PHP - Delete Only The Entry With The Specified Id
I have a code where i can edit or delete certain details from the database. Right now, if the user clicks on the edit button it takes him edit page where he can edit the details. But, I am not able to Incorporate a Delete button such that, when the user clicks on a delete button, it should ask for a confirmation box. If the user clicks YES, then do the following:
Code: [Select] DELETE from emp WHERE emp_id='$emp_id'; When there are multiple entries and I click on delete it deletes everything from the database. how can i make it to delete only the entry that is besides the delete button? Code: [Select] if(mysql_num_rows($emp_query) > 0){ echo "<table border='1'>"; echo "<th>Employee Id </th>"; echo "<th>Employee Name </th>"; while($get_emp = mysql_fetch_assoc($emp_query)){ $emp_id = $get_emp['emp_id']; $emp_name = $get_emp['first_name']." ".$get_emp['last_name']; echo "<tr>"; echo "<td width='100'>"; echo $emp_id; echo "</td>"; echo "<td width='400'>"; echo $emp_name; $edit_path = 'edit_employee.php?id='.$emp_id; ?> <INPUT TYPE="button" style="display:inline;" value="VIEW / EDIT" onClick="location.href='<?php echo $edit_path; ?>'"> <form style='margin: 0; padding: 0; display:inline;' method="post" action="<?php echo $_SERVER['PHP_SELF'];?>" onSubmit="return confirm('Are you sure this is correct?');"> <input style='display:inline;' name="delbutton" type="submit" value="DELETE"> <?php if(isset($_POST['delbutton'])){ $del_emp = mysql_query("DELETE from employee WHERE emp_id = '$emp_id'") or die(mysql_error()); //header('Location:view_employee.php'); } echo '</form>'; echo "</td>"; echo "</tr>"; } } Similar TutorialsHey guys I have trouble picking the specific id of an entry i want to delete so please take a look at the codes first Here's the function for making the form: Code: [Select] function am_query_display_quick($page,$order ='DATE DESC'){ global $email; $conn = db_connect_2(); $color1 = "tableRowOdd"; $color2 = "tableRowEven"; $RowCount = 0; $result = $conn->query("SELECT pro,pro_update,ana,ana_update,cell,cell_update,cellother,cellother_update,gen,gen_update,genother,genother_update,author,author_update,other,other_update,id FROM mailing_list WHERE email = '$email' ORDER BY $order LIMIT $start_row, $max_per_page;"); echo "<form method = \"post\" action=\".{$_SERVER['PHP_SELF']}.\">"; echo "<table class=\"sortable\" id=\"query_quick2\" width=\"100%\" >\r\n"; echo "\t<tr><th></th><th>Promoter Locus</th><th>Update?</th><th>Anatomical Area</th><th>Update?</th><th>Cell Type</th><th>Update?</th><th>Other Cell Type</th><th>Update?</th><th>Genetic Background</th><th>Update?</th><th>Other Gen. Back.</th><th>Update?</th><th>Author</th><th>Update?</th><th>Other</th><th>Update?</th><th></th>\r\n"; if($result->num_rows){ while ($row = $result->fetch_array()){ $RowCount ++; $row_color = ($RowCount % 2) ? $color1 : $color2; echo "\t<tr class=\"$row_color\" ><td><input type=\"submit\" name=\"edit_mail\" value = \"Edit\"/></td> <td>{$row['pro']}</td><td>{$row['pro_update']}</td><td>{$row['ana']}</td> <td>{$row['ana_update']}</td><td>{$row['cell']}</td><td>{$row['cell_update']}</td><td>{$row['cellother']}</td> <td>{$row['cellother_update']}</td><td>{$row['gen']}</td><td>{$row['gen_update']}</td><td>{$row['genother']}</td> <td>{$row['genother_update']}</td><td>{$row['author']}</td><td>{$row['author_update']}</td><td>{$row['other']}</td><td>{$row['other_update']}</td> <td><input type=\"submit\" name=\"delete_mail\" value =\"Delete\"/></td> <td><input type =\"hidden\" name = \"id\" value=\"{$row['id']}\"/></td> </tr>"; } } echo "</table>"; echo "</form>"; And this is where the delete command comes into place (excerpt): Code: [Select] } elseif(isset($_SESSION['user_id']) AND isset($_POST['delete_mail'])){ //user is deleting existing queries $conn=db_connect_2(); $id = mysqli_real_escape_string($conn, $_POST['id']); echo $id; $sql2 = "DELETE FROM mailing_list WHERE id='$id'"; $result = mysqli_query($conn, $sql2) or mysqli_error($conn); $msgs[] = "Query deleted successfully."; $body = "account.php"; } yes it can delete entries all right but it doesn't delete a specific entry when i click the "delete" button near it somehow, it ALWAYS deletes the last row of entry at the table as you can see, i echoed out $id as it's referring to the LAST entry as well So my question is, how to delete a particular entry when i click the corresponding "delete" button?? Thanks I'm trying to be able to delete a specific post from a forum. How do I make it so that my function knows which post to delete? I know it needs to pull the id from the boards table, but how do I do that? In the readboard function, I've added a link to try and pull the ID of that specific post, but I don't think I have it right... Readboard function: <? $command = 1; if (getlevel(get("plane"),coords(),"board") == "") echo "There is no bulletin board here.<br>\n"; else{ $board = getlevel(get("plane"),coords(),"board"); if ($admin == "Y+" || $admin == "Y"){ $x = " --- <a href=main.php?username=$username&password=$password&action=delpost>Delete Post</a>";} $dbh=dbconnect() or die ("Userlist read error: " . mysql_error()."<br>"); mysql_select_db("XX"); $result = mysql_query("SELECT * FROM boards WHERE boardname='$board' ORDER BY id LIMIT 10"); $post = mysql_fetch_assoc($result); while ($row = mysql_fetch_array($result)){ echo stripslashes($row['message']) . "$x<br>" . " --- ".stripslashes($row['username']). " on ".stripslashes($row['time']) ."<hr width=90%>"; } } ?> Here's my current delpost function: function delpost() { if (getlevel(get("plane"),coords(),"board") == "" && ( get("admin") == "Y+" || get("admin") == "Y")) echo "There is no bulletin board here.<br>\n"; else{ $board = getlevel(get("plane"),coords(),"board"); $dbh=dbconnect() or die ("Userlist read error: " . mysql_error()."<br>"); mysql_select_db("XX"); $result = mysql_query("DELETE * FROM `boards` WHERE `boardname`='$board', `id`='$id'"); echo "Message deleted.<br>\n"; }} I'm working on an old cms I built a few years ago and for some reason my Delete page isn't working. It has to be something simple I'm overlooking. The database connection is made just above this code and is pulling the thumb and title listed by id. When I push delete I'm getting the cmd=delete&id=2 passed on so something is up with my last if statement (I think). Here is the code: if(!isset($cmd)) { //display all the news $result = mysql_query("select * from verizon order by id"); //run the while loop that grabs all the news scripts while($r=mysql_fetch_array($result)) { //grab the title and the ID of the enws $title=$r["title"];//take out the title $id=$r["id"];//take out the id $thumb=$r["thumb"]; echo "<div id='delete'> <table> <tr> <td width='350px'><strong>$title</strong></td><td><a href='verizondelete.php?cmd=delete&id=$id'> Delete</a></td> </tr> <td colspan='2' align='center'><img src='../upload/verizon/$thumb'></td> </table> </div><br />"; } } if($cmd=="delete") { $sql = "DELETE FROM verizon WHERE id='$id'"; $result = mysql_query($sql); echo "<h1 style='text-align:center;'>deleted!</h1>"; } } ?> No errors come up when I run this but it just doesn't delete the entry. <? $rec = $_POST['stock']; if (!$rec){ die ('Please eneter a stock number'); } $link = mysql_connect("xxxx","xxx","xxx"); mysql_select_db('wadkin', $link) or die( "Unable to select database"); mysql_query("DELETE FROM 'wadkin'.'stocklist' WHERE 'stocklist'.'Stock Number' = $rec") or die ('Query failed'); mysql_close($link); ?> Can someone please correct, (btw I have also tried... "DELETE FROM stocklist WHERE 'Stock Number' = $rec") Alright, wasn't quite sure how to summarize this in the title, but I want to: Check if a user status is "active" or not based on the UserName input. I have a table witch holds: Code: [Select] VarChar Username Var CharPassWord int Active Ted TedsPW 1 something like the above(assuming it formatted correctly. In my php script I will want to input a variable for Username to check for: inputUN in this example would be "Ted". $UserNameToCheck = $_GET['inputUN']; Then I want to check for that UserName in the database, if it exists, I want pull the value for the "Active" field for just that UserName and echo it. Thanks for any help. I am using php to upload a file to my server, and at the same time inserting the files name and url into my mysql database.
$sql = "UPDATE uploads SET name = '$name', url='$target_path'"; $statement = $dbh->prepare($sql); $statement->execute();This is working, however, when I upload a new file, rather than making a new entry in my database, it just overwrites the first one. I'm quite new at mysql so was wondering how I would make it add new entrys instead of overwriting the current one? Hi all. Here is my scripts which allow user to check multiple rows of data and delete it , but it require select data and click for twice to delete the rows , what should be the error? Code: [Select] <form name="frmSearch" method="post" action="insert-add.php"> <table width="600" border="1"> <tr> <th width="50"> <div align="center">#</div></th> <th width="91"> <div align="center">ID </div></th> <th width="198"> <div align="center">First Name </div></th> <th width="198"> <div align="center">Last Name </div></th> <th width="250"> <div align="center">Mobile Company </div></th> <th width="100"> <div align="center">Cell </div></th> <th width="100"> <div align="center">Workphone </div></th> <th width="100"> <div align="center">Group </div></th> </tr> </form> <? echo "<form name='form1' method='post' action=''>"; while($objResult = mysql_fetch_array($objQuery)) { echo "<tr>"; echo "<td align='center'><input name=\"checkbox[]\" type=\"checkbox\" id=\"checkbox[]\" value=\"$objResult[addedrec_ID]\"></td>"; echo "<td>$objResult[addedrec_ID] </td>"; echo "<td>$objResult[FirstName]</td>"; echo "<td>$objResult[LastName] </td>"; echo "<td>$objResult[MobileCompany] </td>"; echo "<td>$objResult[Cell] </td>"; echo "<td>$objResult[WorkPhone] </td>"; echo "<td>$objResult[Custgroup] </td>"; echo "</tr>"; } echo "<td colspan='7' align='center'><input name=\"delete\" type=\"submit\" id=\"delete\" value=\"Delete\">"; if (isset($_POST['delete']) && isset($_POST['checkbox'])) // from button name="delete" { $checkbox = ($_POST['checkbox']); //from name="checkbox[]" $countCheck = count($_POST['checkbox']); for($d=0;$d<$countCheck;$d++) { $del_id = $checkbox[$d]; $sql = "DELETE from UserAddedRecord where addedrec_ID = $del_id"; $result2=mysql_query($sql) or trigger_error(mysql_error());;; } if($result2) { $fgmembersite->GetSelfScript(); } else { echo "Error: ".mysql_error(); } } echo "</form>"; Thanks for every reply. <body> <?php include 'sql.php'; $query = "SELECT * FROM validation"; $result = mysqli_query($con , $query); $rows = mysqli_fetch_assoc($result) ; $totals = mysqli_num_rows($result) ; ?> <div id="css"> <form > <table width="80%" border="0" cellpadding="2" cellspacing="2" > <caption><h2>Personal Details of Customers</h2></caption> <tr class="white"> <td bgcolor="#330033"> </td> <td bgcolor="#330033"> Id Number </td> <td bgcolor="#330033"> Full Name </td> <td bgcolor="#330033"> Email Address </td> <td bgcolor="#330033"> Website </td> <td bgcolor="#330033"> Comment </td> <td bgcolor="#330033"> Time </td> </tr> <?php while($rows=mysqli_fetch_assoc($result) { <tr> <input type="raido" name="ID" value="<?php echo $rows['ID']; ?>" /> <td bgcolor="#FFFFCC"><?php echo $rows['ID'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Name'];?> </td> <td bgcolor="#FFFFCC"><?php echo $rows['Email'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Website'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Comment'];?></td> <td bgcolor="#FFFFCC"><?php echo $rows['Time'];?></td> <td> </td> <td> <a href="delete.php? ID= "$rows[ID]" /"> <input type="submit" name="del" value="Delete" /> </a> <input type="button" name= "edit" value="Edit" /> </td> </tr> }?> </table> </form> </div> </body> Hi,
I wish to find out is there any possible that I can delete some data inside my php website but inside my sql database, the record will still at there?
Thank you.
I'm trying to set it so that it will delete an entire populated directory based upon a value in the database then after finishing that to go back and delete that row in the database. my current code is Code: [Select] <?php $page_title = "Central Valley LLC | Photo Addition" ?> <?php include("header.php"); ?> <?php include("nav.html"); ?> <div id="content"> <form action="delprod.php" method="post" enctype="multipart/form-data"> <label for="which">Choose A Product To Remove:</label> <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT * FROM Products"); echo "<select name=\"which\">"; while($row = mysql_fetch_array($result)) { echo "<option "; echo "value=\"" . $row['id'] . "\">"; echo $row['Name'] . "</option>"; } echo "</select>"; mysql_close($con); ?> <br /> <input type="submit" name="submit" value="Submit" /> </form> </div><!--#content--> <?php include("footer.html") ?> and the delete script Code: [Select] <?php $con = mysql_connect("localhost","phoenixi_cv","centraladmin"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("phoenixi_cvproducts", $con); $result = mysql_query("SELECT id FROM Products WHERE id=$_POST['which']"); $row = mysql_fetch_array($result) chdir('assets'); chdir('images'); $mydir = $row . '/'; $d = dir($mydir); while($entry = $d->read()) { if($entry!="." && $entry!="..") { unlink($_POST['which'] . '/' . $entry); } } rmdir($mydir); $result = mysql_query("DELETE * FROM Producs WHERE id=$_POST['which']"); ?> Thank you in advance for all your help. any easier ways of approaching this will be welcome as well $insertCount=0; foreach($results[1] as $curName) { if($insert){$insertCount++;} echo <<< END $curName<BR> END; } Right now the results would show up as... Bill Fred Jessica James John How do you make them show up like... 1 Bill 2 Fred 3 Jessica 4 James 5 John Hello there, I have some code here which sends a number of variables from flash to SQL... I would simply like to add the functionality to overwrite records which have the same 'name' or 'pseudo'... can anyone help me please ? Thanks in advance Martin <?php $pseudo=$_POST['var1']; $score=$_POST['var2']; $table = $_POST['tab']; $dategame = $_POST['tempjoueur']; //$micro = microtime(); //$dategame = time()."".substr($micro, 2, 6); $_COOKIE['User'] = $_SERVER['REMOTE_ADDR']; $envoie = InsertDatas($table, "name, score, dategame", "'".$pseudo."','".$score."','".$dategame."'"); if ($envoie) { print_r("OK, $pseudo, $score, $dategame,$ipclient"); } else { echo "BAD, $pseudo, $score, $dategame,$ipclient"; } ?> Hey guys! I know, I know this problem is EVERYWHERE but i just dont understand! I have a solid knowlage of php but my SQL skills are low, so i dont know too much about Keys and stuff. But my error is: Duplicate entry '' for key 2. The thing that im working on at this section is logging in with facebook. The code that presents my error is: $sql = "SELECT * FROM users WHERE uid=".$uid; $fbid = mysql_query($sql); $num_rows = mysql_num_rows($fbid); if(mysql_num_rows($fbid) < 1) { echo "You are not logged in. "; mysql_query("INSERT INTO `users` (`uid`) VALUES ('".$uid."')") or die(mysql_error()); } else { mysql_query("UPDATE users SET logged = '1' WHERE uid=".$uid); //mysql_query("UPDATE users SET full_name = $me WHERE uid=".$uid); echo "Your Logged in "; echo $me['name']; ?> Continue to <a href="removed :)"> My Settings </a>. <? } Any help is welcome Well this sounds weird, but it happens. I have an itemshop script, and I wanna code a system that automatically delete the database entry once the variable item amount falls to 0. However, this doesnt happen when I check phpmyadmin, and the item remains in the database even after the amount becomes 0. In fact, the amount can become negative at times, which annoys me. The code of deleting sql entry looks like this: if($continue == "yes"){ $query = "SELECT * FROM ".$prefix."user_inventory WHERE item_owner = '$loggedinname' AND item_name = '$item_name'"; $result = mysql_query($query); $num = mysql_numrows($result); $item_data = mysql_fetch_array($result); $item_amount = $item_data['item_amount']; $newquantity = $item_amount - $quantity; $query = "UPDATE ".$prefix."user_inventory SET item_amount = '$newquantity' WHERE item_owner = '$loggedinname' AND item_name = '$item_name'"; $result = mysql_query($query); if($newquantity == "0"){ $query = "DELETE FROM ".$prefix."user_inventory WHERE item_owner = '$loggedinname' AND item_name = '$item_name'"; $result = mysql_query($query); } What part of the codes should I edit to fix this issue? Thanks. Hi.. So im currently working on a script.. My script generates a "oid" based on timestamp. Ive made the "oid" field unique in my db, so if i do a quick refresh i get the message: Duplicate entry '1283195988' for key 'oid' Is there some way i can check if its a dublicate, and if it is + it with 1 or something? Hey folks, Sorry for being a pain in the ass. I am trying to submit data to my database via a form and when I click Submit, I get: Duplicate entry '' for key 1 I understand that it means I have a duplicate entry with the ID of 1 or something like that. I can't find where the issue is. Here is the form: <form actin="" id="settings" name="settings"> <table class="listing form" cellpadding="0" cellspacing="0"> <tr> <th class="full" colspan="2"><?php echo $lang_settings; ?></th> </tr> <tr> <th colspan="2"><?php echo $lang_settings_description; ?></th> </tr> <tr> <td><?php echo $lang_sitename; ?>: </td> <td><input type="text" name="sitename" value="<?php echo $site_name; ?>" width="172" /> <em>Site name for logo</em></td> </tr> <tr> <td><?php echo $lang_email; ?>: </td> <td><input type="text" name="email" value="<?php echo $site_email; ?>" width="172" /> <em>Your email address</em></td> </tr> <tr> <td><?php echo $lang_yourname; ?>: </td> <td><input type="text" name="name" value="<?php echo $your_name; ?>" width="172" /> <em>Your own name</em></td> </tr> <tr> <td><?php echo $lang_meta_description; ?>: </td> <td><input type="text" name="meta-description" value="<?php echo $description; ?>" width="172" /> <em>SEO</em></td> </tr> <tr> <td><?php echo $lang_keywords; ?>: </td> <td><input type="text" name="meta-keywords" value="<?php echo $keywords; ?>" width="172" /> <em>Separate with Commas</em></td> </tr> <tr> <td><input type="submit" class="button" name="submit" value="<?php echo $lang_button_savesettings; ?>"></td> </tr> </table> </form> Here is the Insert code: $insert = "INSERT INTO settings (site_name, description, keywords, email, name) VALUES ('$sitename', '$meta_description', '$meta_keywords', '$site_email', '$your_name')"; mysql_query($insert) or die(mysql_error()); Can anyone please tell me where I am going wrong here? Much appreciated. i'm trying to get the username of the last person to enter something into a database table,and display it an html table. the problem is, the query is failing, and i get the error "Table 'forum.posts' doesn't exist". if in the error message "forum" means the name of the database, and "posts" the name of the table, there is something wrong, as they both exist. the code i'm using is below $list = "SELECT * FROM section_main ORDER BY section_title"; $result = mysql_query($list) or die ("Query failed"); $numofrows = mysql_num_rows($result); for($j = 0; $j < $numofrows; $j++) { $row = mysql_fetch_array($result); echo "<tr><th>". $row['section_title']."</th></tr>"; $query2 = "SELECT * FROM section_sub WHERE section_id = '".$row['section_id']."' ORDER BY section_sub_title"; $result2 = mysql_query($query2) or die("Select Error :" . mysql_error()); $numofrows2 = mysql_num_rows($result2); for($i = 0; $i<$numofrows2; $i++){ $row2 = mysql_fetch_array($result2); echo "<tr><td><a href='display_forum.php?id={$row2[section_sub_id]}'>".stripslashes($row2[section_sub_title])."</a></td><td>"; $new = mysql_query("Select * FROM posts WHERE section_sub_id = '".$row2['section_sub_id'] . " ' ") or die ("Select Error :" . mysql_error()); //this is where the error message is from $lastpost = mysql_fetch_assoc($new); echo $lastpost['username']; echo"</td></tr>"; } } i've checked that the names of the tables and fields in the queries are correct, but i cant think of anything else that might be wrong. any help would be great. My query is not finding the last recieptnum entry, it is finding the number 9 everytime for some odd reason. Im trying to incrementally increase this each time a reciept is created. $getreceiptnum = mysql_query("SELECT receiptnum FROM accounting WHERE agency = '$agency' ORDER BY receiptnum DESC LIMIT 1") or die(mysql_error()); $recieptarray = mysql_fetch_array($getreceiptnum); $recieptnum = $recieptarray['receiptnum']; echo $recieptnum; For some reason this only allows one SQL to be added... // SQL Connection $username="monstert_admin"; $password="admin"; $database="monstert_admin"; $connection = mysql_connect("localhost", $username, $password) or die("Connection Failure to Database"); // Select Database mysql_select_db($database, $connection) or die ($database . "No Database" . $username); //Select everything from the the table $MyQuery = "SELECT * FROM photos"; $retrieve = mysql_query($MyQuery) or die(mysql_error()); if(mysql_num_rows($retrieve) != 0): $row = mysql_fetch_assoc($retrieve); else: echo ''; endif; if(isset($_POST['Submit']) && !$errors) { $url = $newname; include('img.php'); $image = new SimpleImage(); $image->load($url); $image->resize(500,315); $image->save($newname); mysql_query("INSERT INTO photos (url) VALUES ('$url')"); echo "File Uploaded Successfully as <i> "; echo $newname; echo "</i>"; } What would the issue be? I only have two columns - ID and url Thanks in advance! Hi I am getting this error message and don't know why. please help this is the message " Error: Duplicate entry '' for key 1 " Here is the code Code: [Select] <?php include'../DB-connection.php'; $sql="INSERT INTO Company(CompanyName,Address,Logo,PhoneNumber,ContactPerson) VALUES('".mysql_real_escape_string($_POST[CompanyName])."', '".mysql_real_escape_string($_POST[Address])."', '".mysql_real_escape_string($_POST[Logo])."', '".mysql_real_escape_string($_POST[PhoneNumber])."', '".mysql_real_escape_string($_POST[ContactPerson])."')"; if(!mysql_query($sql,$con)) { die(' Error: '. mysql_error()); } echo " <center>your compnay info added       <a href='User-Login.php'>Login to Post a job</a> </center>" ; mysql_close($con) ?> |