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PHP - Mysql Query Problem
Hope someone can help. i am trying to search between two date ranges but am not sure how to add it to the rest of my query.
this is my original query which works fine .. it does not have the start and end date part Code: [Select] $query = "SELECT * FROM table WHERE hdt1 like '%$hdt1_search%' and hdt2 like '%$hdt2_search%' and hdt3 like '%$hdt3_search%' and dateadd like '$dateadd_search'"; this is the start date to end date search, ...it works ok when it is the only thing in the query Code: [Select] $query = "SELECT * FROM table WHERE dateadd >= '$start_date' AND dateadd <= '$end_date'"; BUT, when i try to put it all together the only two fields that get search are the start date to end date search. ... Code: [Select] $query = "SELECT * FROM table WHERE hdt1 like '%$hdt1_search%' and hdt2 like '%$hdt2_search%' and hdt3 like '%$hdt3_search%' and dateadd like '$dateadd_search' and dateadd >= '$start_date' AND dateadd <= '$end_date' "; what am i doing wrong???? Similar TutorialsHey everyone, i keep having this error: Code: [Select] Could not connect: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc,mg,pg) VALUES ('1','0','Snoozy','teata','1','White','atata','atatata'' at line 1 This was just a example as I've been lately just trying and trying with no luck, The script part is: $appquery = mysql_query("INSERT INTO applications (aid,cid,name,charactername,gender,race,desc,mg,pg) VALUES ('".$_COOKIE['ID']."','$insertid','".$_COOKIE['Username']."','$name','$sex','$race','$description','$mg','$pg')") or die('Could not connect: ' . mysql_error()); Hi all, I have a form for users to input posts into their blog. This works fine with the INSERT INTO query in my code. However, when I test it and check the database the entry is going in fine but there is no id attached to it. I'm not really sure how to use an INNER JOIN with an INSERT. As you will see, I have tried to work around it, but I am getting a parameter error "mysqli_fetch_array() expects parameter 1 to be mysqli_result, object given". I suspect this is because the query is not working. I have echoed out the SESSION['name'] variable $whichuser and it works fine. Any help appreciated. Code: [Select] <?php session_start(); // always on the top of the script when user should be logged in if(isset($_SESSION['loggedin'])){ }else{ header("location: index.php"); } require('connection.php'); $whichuser=$_SESSION['name']; if(empty($_POST['title'])){ $title=NULL; echo "<b>Warning:</b>You haven't given your post a title.</br>"; }else{ $title=mysqli_real_escape_string($connection, trim($_POST['title'])); } if(empty($_POST['content'])){ $content=NULL; echo "<b>Warning:</b>You haven't entered any content.</br>"; }else{ $content=mysqli_real_escape_string($connection, trim($_POST['content'])); } if(($title) && ($content)){ $newentry = "INSERT INTO blogposts (title, content, timeofpost) VALUES ('$title', '$content', NOW())"; if($newentry){ $join= "SELECT * FROM blogposts INNER JOIN users ON blogposts.post_number = users.username WHERE username='$whichuser'"; if($join){ $entry=mysqli_query($connection, $join) or die(mysqli_error($connection)); }else{ echo "THERE'S A PROBLEM WITH THE QUERY."; } while($newpost = mysqli_fetch_array($connection, $entry)){ extract($newpost); echo "<h3>$title</h3></br>"; echo "$content</br>"; echo "$whichuser</br>"; } } } ?> Senseis, I give nothing error. But mysql query dont put in to the table. I am using variables... $ara = '/Public Game - /'; $degistir = ''; $seo_var=preg_replace( $ara, $degistir, $yeni_title ); $ara2 = '/\s+/'; $degistir2 = ''; $seo_var2=preg_replace( $ara2, $degistir2, $seo_var ); $seo_link = tr_converter($seo_var); $makalequery = "INSERT INTO `jos_content` (`id`, `title`) VALUES (NULL, '$seo_link')"; $makaleekle = mysql_query($makalequery) or die("Problem with the query: $q<br>" . mysql_error()); Thank you for help... Note: I'm dealing with this problem for three days.. Best Regards... Hi guys, Im just after a little help here because i cant seem to get my script to work correctly. Basically i have a table full of data and i want to be able to extract a months worth of data but split that data into weeks from within the month. This is my database structu Code: [Select] -- phpMyAdmin SQL Dump -- version 3.4.5 -- http://www.phpmyadmin.net -- -- Host: localhost -- Generation Time: Dec 13, 2011 at 09:13 AM -- Server version: 5.5.16 -- PHP Version: 5.3.8 SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO"; SET time_zone = "+00:00"; /*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */; /*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */; /*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */; /*!40101 SET NAMES utf8 */; -- -- Database: `time_man` -- -- -------------------------------------------------------- -- -- Table structure for table `clock_status` -- CREATE TABLE IF NOT EXISTS `clock_status` ( `id` int(11) NOT NULL AUTO_INCREMENT, `user_id` varchar(24) NOT NULL DEFAULT '0', `location` int(4) NOT NULL DEFAULT '0', `date_time` datetime NOT NULL DEFAULT '0000-00-00 00:00:00', `status` tinyint(1) NOT NULL DEFAULT '0', `amend_time` datetime NOT NULL DEFAULT '0000-00-00 00:00:00', `hours_worked` varchar(25) NOT NULL DEFAULT '', `lunch` int(11) NOT NULL DEFAULT '0', `break` int(11) NOT NULL DEFAULT '0', `sick` char(3) NOT NULL DEFAULT 'NO', `holiday` char(3) NOT NULL DEFAULT 'NO', `comments` text NOT NULL, `auth` tinyint(1) NOT NULL DEFAULT '0', `auth_date` date NOT NULL, `paid` tinyint(1) NOT NULL DEFAULT '0', `pay_rate` text NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=734 ; -- -- Dumping data for table `clock_status` -- INSERT INTO `clock_status` (`id`, `user_id`, `location`, `date_time`, `status`, `amend_time`, `hours_worked`, `lunch`, `break`, `sick`, `holiday`, `comments`, `auth`, `auth_date`, `paid`, `pay_rate`) VALUES (720, '653467435', 3301, '2011-10-12 04:00:00', 0, '2011-10-12 06:35:00', '9300', 0, 0, 'NO', 'NO', '', 1, '2011-10-13', 0, 'L'), (721, '653467435', 3301, '2011-10-12 06:30:00', 0, '2011-10-12 11:25:00', '17700', 0, 0, 'NO', 'NO', '', 1, '2011-10-13', 0, 'L'), (722, '5030341511007', 3301, '2011-10-13 17:45:00', 0, '2011-10-30 22:10:00', '15900', 0, 0, 'NO', 'NO', '', 1, '2011-10-13', 0, 'H'), (723, '653467435', 3301, '2011-10-13 01:15:00', 0, '2011-10-13 07:15:00', '21600', 0, 0, 'NO', 'NO', '', 1, '2011-10-13', 0, 'L'), (724, '653467435', 3301, '2011-10-13 03:15:00', 0, '2011-10-13 05:15:00', '7200', 0, 0, 'NO', 'NO', '', 1, '2011-10-13', 0, 'L'), (725, '653467435', 3301, '2011-11-11 05:45:00', 0, '2011-11-11 13:20:00', '27300', 0, 0, 'NO', 'NO', '', 1, '2011-11-11', 0, 'L'), (726, '653467435', 3301, '2011-11-11 01:15:00', 0, '2011-11-11 08:25:00', '3663', 0, 0, 'NO', 'NO', '', 1, '2011-11-22', 0, 'L'), (727, '12345678954565456', 3301, '2011-11-11 05:45:00', 0, '2011-11-11 16:25:00', '3662', 0, 0, 'NO', 'NO', '', 1, '2011-11-22', 0, 'L'), (728, '50226900', 3301, '2011-11-21 09:30:00', 0, '2011-11-21 17:00:00', '27000', 0, 0, 'NO', 'NO', '', 1, '2011-11-22', 0, 'H'), (729, '5030341511007', 3301, '2011-11-22 09:30:00', 0, '2011-11-11 15:30:00', '21600', 0, 0, 'NO', 'NO', '', 1, '2011-11-22', 0, 'H'), (730, '5030341511007', 3301, '2011-11-22 06:00:00', 0, '2011-11-17 09:20:00', '12000', 0, 0, 'NO', 'NO', '', 1, '2011-11-22', 0, 'H'), (731, '653467435', 3301, '2011-11-22 06:45:00', 0, '2011-11-22 12:30:00', '20700', 0, 0, 'NO', 'NO', '', 1, '0000-00-00', 0, 'L'), (732, '5030341511007', 3301, '2011-11-22 07:45:00', 0, '2011-11-22 15:15:00', '3661', 0, 0, 'NO', 'NO', '', 1, '0000-00-00', 0, 'H'), (733, '653467435', 3301, '2011-11-22 04:45:00', 0, '2011-11-22 14:05:00', '33600', 0, 0, 'NO', 'NO', '', 1, '0000-00-00', 0, 'L'); -- -------------------------------------------------------- -- -- Table structure for table `staff` -- CREATE TABLE IF NOT EXISTS `staff` ( `person_id` int(4) NOT NULL AUTO_INCREMENT, `name` varchar(60) NOT NULL DEFAULT '', `staff_number` varchar(20) NOT NULL DEFAULT '0', `dob` date NOT NULL DEFAULT '0000-00-00', `pay_rate` char(1) NOT NULL DEFAULT '', `date_amended` datetime NOT NULL DEFAULT '0000-00-00 00:00:00', `expiry` text NOT NULL, PRIMARY KEY (`person_id`), UNIQUE KEY `staff_number` (`staff_number`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=53 ; -- -- Dumping data for table `staff` -- INSERT INTO `staff` (`person_id`, `name`, `staff_number`, `dob`, `pay_rate`, `date_amended`, `expiry`) VALUES (16, 'Person Two', '3456', '1990-06-23', 'H', '2011-06-23 07:40:38', ''), (17, 'Person Three', '5678', '1986-05-29', 'H', '2011-01-24 12:18:03', ''), (15, 'Person One', '1234', '1995-11-29', 'L', '2011-01-18 16:59:53', ''), (47, 'Person four', '50226900', '1980-04-23', 'H', '2011-06-17 10:50:50', ''), (48, 'Person Two', '653467435', '1980-01-13', 'L', '0000-00-00 00:00:00', '01/02/1982'), (50, 'Person One', '5030341511007', '1983-07-13', 'H', '0000-00-00 00:00:00', ''), (52, 'Person Three', '12345678954565456', '2000-02-01', 'L', '0000-00-00 00:00:00', '01/03/2019'); -- -------------------------------------------------------- /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */; /*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */; /*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */; This is the script so far... Code: [Select] <?php require_once("../includes/connection.php"); ?> <?php $date1 = '2011-10-28'; $date2 = '2011-11-27'; $ident = '3301'; $sql10 = "SELECT WEEK(date_time) as Week, staff.name, clock_status.user_id, sum( clock_status.hours_worked ) AS sum_hours, clock_status.hours_worked, clock_status.amend_time FROM clock_status, staff WHERE amend_time >= '$date1' AND amend_time < '$date2' AND clock_status.auth =1 AND clock_status.user_id = staff.staff_number AND clock_status.location = '3301' GROUP BY user_id ORDER BY Week, user_id"; $query10 = mysql_query($sql10) or die(mysql_error()); ?> <table style="border: 1 solid black;"> <tr> <th>Staff No</th> <th>Name</th> <th>Sum hours</th> <th>Week 1</th> <th>Week 2</th> <th>Week 3</th> <th>Week 4</th> <th>Week 5</th> </tr> <?php while ($row = mysql_fetch_assoc($query10)) { ?> <tr> <td><?php echo $row['user_id'] ;?></td> <td><?php echo $row['name'] ;?></td> <td><?php echo $row['sum_hours'] ;?></td> <td>Week 1 hours here</td> <td>Week 2 hours here</td> <td>Week 3 hours here</td> <td>Week 4 hours here</td> <td>Week 5 hours here</td> </tr> <?php } ?> </table> <?php require("../includes/footer.php"); ?>The table should list each person once, with the total hours, then the amount of hours in each week in a different column. As represented in my table. If someone could help me on this issue i would be eternally grateful... thanks in advance. Hi there I am using a query to find what user made a comment. The problem I am having is I get the wrong user from the query. Everything seems fine in the database and I just can't seem to track the problem $query = "SELECT * FROM messages"; $result=mysql_query($query) or die("Invalid Query : ".mysql_error()); while ($row = mysql_fetch_assoc($result)){ $pid=($row["pid"]); $id=($row["id"]); $query = "SELECT * FROM users WHERE id='$pid'"; $rresult=mysql_query($query) or die("Invalid Query : ".mysql_error()); while ($row = mysql_fetch_assoc($rresult)){ $user=($row["user"]); } } The query is working in reverse I.E when I search for what messages are from the user. Can anyone see my problem. How can I get this query to work? I am having problems with the HAVING section of it. Code: [Select] SELECT id,price, ( 6371 * acos( cos( radians($lat) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians($lng) ) + sin( radians($lat) ) * sin( radians( lat ) ) ) ) AS distance FROM fuelstations HAVING distance < 250 , price > 0 ORDER BY price LIMIT 0 , 60; Here is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate. What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop. It doesn't matter if I get to the next page using a header redirect or a form submit. I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. Any ideas? I have 2 tables (see code below) (1) "tbl_users" has all users info, including "user_alias" (VARCHAR) and "user_id" (INT and PRIMARY KEY) (2) "tbl_projects" has all project info, including "project_client" (INT) which i linked to "user_id" from "tbl_users" and displays "user_alias" Code: [Select] CREATE TABLE `tbl_users` ( `user_id` int(11) NOT NULL auto_increment, `user_first` varchar(25) NOT NULL, `user_last` varchar(25) NOT NULL, `user_email` varchar(35) NOT NULL, `user_pw` varchar(12) NOT NULL, `user_role` int(1) NOT NULL, `user_alias` varchar(35) NOT NULL, PRIMARY KEY (`user_id`) ) CREATE TABLE `tbl_projects` ( `project_id` int(11) NOT NULL auto_increment, `project_client` int(1) NOT NULL, PRIMARY KEY (`project_id`) ) So... I managed to display all users and all projects but I want to show all users with ONLY their projects assigned. I mean, when I click on a user, I want to see his or hers contact info and all the projects that specific user is linked to. For instance, i might have project 1, project 2, project 3 and project 4. Project 1, 2 and 4 are linked to user 1 so when i click on user 1 i see projects 1, 2 and 3 (not 4). Code: [Select] <?php require_once('config.php'); mysql_select_db($database, $makeconnection); //this displays all projects $sql_get_projects="SELECT * FROM tbl_projects ORDER BY project_id ASC"; $get_projects = mysql_query($sql_get_projects, $makeconnection) or die(mysql_error()); $row_get_roles = mysql_fetch_assoc($get_projects); $totalRows_get_projects = mysql_num_rows($get_projects); //this displays all users $sql_find_users = "SELECT * FROM tbl_users WHERE user_id = $user_id"; $find_users = mysql_query($sql_find_users, $makeconnection) or die(mysql_error()); $row_get_users = mysql_fetch_assoc($find_users); $totalRows = mysql_num_rows($find_users); ?> Any help would be great!! Hello! Please help... I am trying to use the script below to get results from a mysql database based on a query of the form fields (the names of which are displayed near the top of the script as POST items) When a location or age etc. is entered into the form, I want the script to search for records which meet those criteria. At the moment the script works but only does so if all the values are entered to match what is in the database. e.g. if the location england and the age 22 was entered into the form, and that matched the value in the database, then at the moment, the script will display the result, but if only the location is entered in the form without any value for age/genre etc. then no results are displayed. Any help would be very welcome as I have search high and low for a solution on google... which doesn't seem to exist... I'm not that experienced with php/mysql but am learning on the job so any helpful prompts as to terms etc. would help! Thanks! Lewis <?php if($_POST) { $searchage = $_POST['searchage']; $searchlocation = $_POST['searchlocation']; $searchgenre = $_POST['searchgenre']; $searchinstrument = $_POST['searchinstrument']; $searchexperience = $_POST['searchexperience']; // Connects to your Database mysql_connect("localhost", "user", "pass") or die(mysql_error()); mysql_select_db("DB") or die(mysql_error()); $query = mysql_query("SELECT * FROM table_user WHERE userage = '".$searchage."' AND userlocation = '".$searchlocation."' AND usergenre = '".$searchgenre."' AND userinstrument = '".$searchinstrument."' AND userexperience = '".$searchexperience."'") or die(mysql_error()); $num = mysql_num_rows($query); echo "$num results found!<br>"; while($result = mysql_fetch_assoc($query)) { $username = $result['username']; $useremail = $result['useremail']; $userage = $result['userage']; $userlocation = $result['userlocation']; $usergenre = $result['usergenre']; $userinstrument = $result['userinstrument']; $userexperience = $result['userexperience']; $userbiography = $result['userbiography']; echo " Name: $username<br> Email: $useremail<br> Age: $userage<br> Location: $userlocation<br> Gen $usergenre<br> Instrument: $userinstrument<br> Experience: $userexperience<br> Biography: $userbiography<br><br> "; } } ?> Hello... First I should explain what is wrong. I have a database with a table called subs... Within this table I have a unique field called ID, then a fields called member, date(unix timestamp) amount, month, year... HOWEVER for each month and year there is several entries all with different date stamps. How can I extract the entry with the most recent date??? However there is a catch. I want to view payments made since a certain date but only one per month... Below is my code... I thnk I need to add or change something slightly but i am fairly new to PHP and am totally stuck... MANY THANKS IN ADVANCE!!! Code: [Select] [php]$query="SELECT * FROM records WHERE section='B' OR section='C' OR section='S' order by section, surname"; $result=mysql_query($query); for ($row=0;$row<mysql_num_rows($result);$row++){ $forename=mysql_result($result,$row,'forename'); $surname=mysql_result($result,$row,'surname'); $id=mysql_result($result,$row,'id'); $ref="19nx".$id.substr($forename,0,2).substr($surname,0,2); $section=mysql_result($result,$row,'section'); $giftAid=mysql_result($result,$row,'giftAid'); if ($giftAid>1){$day=date('d',$giftAid);$month=date('m',$giftAid);$year=date('y',$giftAid);}else{$day="";$month="";$year="";} $giftAidName=mysql_result($result,$row,'giftAidName'); $giftAidComment=mysql_result($result,$row,'giftAidComment'); $subdate=mktime(0,0,0,$submonth,$subday,$subyear); $query="SELECT * FROM subs WHERE member='$id' AND date>$subdate Order BY id DESC"; $subResult=mysql_query($query); $subs=""; for($ss=0;$ss<mysql_num_rows($subResult);$ss++){ $amount=mysql_result($subResult,$ss,'amount'); if ($amount==""){$amount='25';} $date=date("M/Y",mysql_result($subResult,$ss,'date')); $subs=$subs."<a title='$date' alt='$date'>$amount</a>,"; }[/php] This outputs a line of results which is right except it shows 2 or 3 for april, 3 or 4 for may anthoer 2 or 3 for june etc... I hope someone gets my drift! I have a query which when I run in phpmyadmin it returns the results I want. When I put it into PHP I get no results can someone tell me what I'm doing wrong? Code: [Select] <?php include("config.php"); ?> <?php // sending query $sql = mysql_query("SELECT dayname((date(FROM_UNIXTIME(dateline)))) as 'Day Of Week', date((date(FROM_UNIXTIME(dateline)))) as 'Date', count(*) as 'Number of Opened Tickets', ( select count(ticketmaskid) from swtickets where date(FROM_UNIXTIME(swtickets.lastactivity)) = Date and isresolved=1 ) as 'Number of Closed Tickets' from swtickets where ((date(FROM_UNIXTIME(dateline)) between (DATE_SUB(CURDATE(), INTERVAL (IF(DAYOFWEEK(CURDATE())=1, 9, DAYOFWEEK(CURDATE()))) DAY)) and (DATE_ADD(CURDATE(), INTERVAL (6 - IF(DAYOFWEEK(CURDATE())=1, 8, DAYOFWEEK(CURDATE()))) DAY)) )) group by date(FROM_UNIXTIME(dateline))"); ?> <?php echo $sql; ?> All it returns is: Resource id #4 When in phpmyadmin I get: I have the following MYSQL Query: Basically, the query will not work when i add quotes to the string. I want it to select from e-mails database where subject LIKE '%"$stringservername"%' If I do just '%$SERVERNAME%' it works :S - And the mysql data includes the quotes. I use the $strongservername to add the quotes. $stringservername = ""$servername""; $stringjobname = ""$vjobname""; $queryemails = mysql_query("SELECT * FROM `emails` WHERE `subject` like '$searchstatus' AND `subject` like '%$stringservername%' AND `subject` like '%$stringjobname%' AND `fromemail` = '$matchfrom'"); Any suggestions? Thankyou Hi all, I have a database with 2 tables, 'users' and 'battles'. The site pulls 2 random peoples pictures and lets the user choose who they think would win the battle. So if user1 is using the site it might show pictures for user5 and user3. If the user1 chooses that user5 wins then an entry is made into the 'battles' table like this : voter win lose user1 user5 user3 Any ideas what query I can use so it only shows 2 people that the user hasnt compared before ? As if its doing this : choose 2 id's from 'users' that user1 hasnt compared before Hope that makes sense. Many thanks, Scott Hi Guys, I have been having problems with a piece of PHP and mysql. I was wondering if you could help me out? The error is = Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /customers/klueless.net/klueless.net/httpd.www/daisysite/home.php on line 120 Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /customers/klueless.net/klueless.net/httpd.www/daisysite/home.php on line 122 And this is the code which goes with these errors = Code: [Select] $msgquery = "SELECT * FROM spotty_messages WHERE (id_receiver = '" . $userid . "') AND read = '0'"; $messageres = mysql_query($msgquery); $messrow = mysql_fetch_array($messageres); $messagecount = mysql_num_rows($messageres); I am creating a site that has to display 36 images on the screen. The image name is stored in the database. My problem is if I have less than 36 images stored I need to display a default image. here is my current query $sql="SELECT col_image, col_url from tbl_images WHERE col_active='1' and col_bigimage='0' ORDER BY RAND() limit 36"; so If I only have 20 active images. I need to display 16 default images. I hope this makes sense. Bill Hi there, I am executing this query in the code below, it executes as I want it except when it gets the title, it doesnt get the title for that row it just gets it from the first row in the table... if that makes sense... what is going on? Code: [Select] <?php require'styles/top.php'; ?> <br> <center><table border='0' width='100%' style='text-align:center; font-weight:bold;'> <tr> <td width='33%'>Subject</td> <td width='33%'>From</td> <td width='33%'>Date</td> </tr> </table></center> <br> <?php $query = mysql_query("SELECT * FROM messages WHERE to_user='$username' ORDER BY message_id DESC") or trigger_error('Error: ' . mysql_error()); $numrows = mysql_num_rows($query); if ($numrows > 0){ while ($row = mysql_fetch_assoc($query)){ $id = $row['message_id']; $from = $row['from_user']; $to = $row['to_user']; $title - $row['message_title']; $content = nl2br($row['message_content']); $date = $row['date']; echo"<center><table border='0' width='100%' style='text-align:center; font-weight:bold;'> <tr> <td width='33%'>$title</td> <td width='33%'>$from</td> <td width='33%'>$date</td> </tr> </table></center> <br>"; } } else echo ''; ?> </div> <div id='left'> </div> <div id='right'> </div> Hi
I need a sql query help from you guys.
It is a sql query for get all upline referrer details from database for particular person
when new person register his details are storing in wp_members_tbl with uername, password, firstname, lastname, email, phone, address, referrer etc.
Below the query is for user
$wp_aff_members_db = $wpdb->get_row("SELECT * FROM $members_table_name WHERE refid = '".$_SESSION['user_id']."'", OBJECT);
And below the query is for this user's upline referrer
$wp_aff_members_db = $wpdb->get_row("SELECT * FROM $members_table_name WHERE refid = '$referrer'", OBJECT);
Now i need the query for find and get this referrer's upline referrer.
Please help me with a solution
Regards
Edited by rajasekaran1965, 23 October 2014 - 10:09 AM. $loc="SELECT * FROM table WHERE username='a', id='1' AND uin='123'"; $get=myspl_query($loc) or die(mysql_error()); Please somone tell me the right command as how to use multiple AND in mysql query. Thanks |
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