PHP - Transmit Xml Or Json From One Site To Another With Php4
Do any one have an Idea on how to transmit xml or json from one site to another with php4.........
any help please.. Thanks in advance Similar TutorialsI have 2 servers I use for hosting, both Linux and Apache. I am executing the same php script on both, the one server the information is sent to me as it is processed, the other it only sends when it is finished processing the script. How can I change it so that it sends me the stuff as it processes it, and not right at the end? Thanks Hello guys, I am new to PHP programming. I am trying to figure out how to use PHP language to transmit/write characters to a USB port device at 9600 baud rate 8-N-1. Basically I just need the PHP coding to allow me to send stuff to the USB device but I have no idea how I can interface this. I did some researching but most were for RS-232 COM Port. I can't find the proper one for USB. If someone can help me out, that would be awesome. Thank you! Hi... I could really do with some help, I have some form code I have been using for a very long time. how every my server company will not install php4 anymore Can someone have a look at this code and let me know why its not php5 compatible. Thanks <?php /* $sendto is the email where form results are sent to */ $sendto = "........"; /* $ccto is the email where form results can be carbon copied to */ $ccto = "..........."; /* O P T I O N A L V A R I A B L E S */ /* TO POST PHP ERRORS TO PAGE FOR DEBUGING SET: $report_errors = "ALL"; TO REMOVE PHP ERRORS FROM POSTING TO THE PAGE FOR USE SET: $report_errors = "NONE"; */ $report_errors = "NONE"; $setokurl = "1"; $okurls = "http://www.dwcontractors.com"; if ($report_errors == "NONE") { error_reporting(0); }else{ error_reporting(E_ALL); } /* --- I F S E T O K U R L = 1 ----- */ if ($setokurl == "1"){ $found_url = "0"; $referer =$_SERVER["HTTP_REFERER"]; $referer = str_replace("://", "[CS]", $referer); $referer_sp = explode("/", $referer); $referer = "$referer_sp[0]"; $referer .= "/"; $referer = str_replace("[CS]", "://", $referer); $referer = strtolower($referer); $okurls = split(",", $okurls); foreach ($okurls as $myokurls) { $myokurls = strtolower($myokurls); if ($referer == strtolower($myokurls)) { $found_url = "1"; } } if ($found_url == "0") { $ERROR_action = "bad_okurl"; include("$PATH_error$PAGE_error"); } } /* --- E N D I F S E T O K U R L = 1 --- */ /* check to see if posted */ if ($HTTP_GET_VARS || ! $HTTP_POST_VARS || $_GET || ! $_POST) { include("nverror.php4"); no_pst(); }else{ /* IF OLDER VERSION OF PHP CONVERT TO NEWER VARIABLES */ if (! $_POST) { $_POST = "$HTTP_POST_VARS"; } if (! $_SERVER) { $_SERVER = "$HTTP_SERVER_VARS"; } $year = date("Y"); $month = date("m"); $day = date("d"); $hour = date("h"); $min = date("i"); $tod = date("a"); $ip=$_SERVER["REMOTE_ADDR"]; $SEND_prnt = "The form below was submited by " . $_POST{"email"} . " from Ip address: $ip on $monthnameactual $month/$day/$year at $hour:$min $tod \n"; $SEND_prnt .= "--- DW Contractors ---\n\n"; /* CHECK TO SEE IF $_POST{"required"} IS SET */ if ($_POST{"required"}){ $post_required = $_POST{"required"}; $required = split(",", $post_required); $reqnum = count($required); for ($req=0; $req < $reqnum; $req++) { $REQ_name = $required[$req]; $REQ_value = $POST{"$REQ_name"}; if ($REQ_name == "email") { $goodem = ereg("^[^@ ]+@[^@ ]+\.[^@ \.]+$", $_POST{"email"}, $trashed); if (! $goodem) { include("nverror.php4"); msng_email(); } /* end ! $goodem */ } elseif (! $_POST{"$REQ_name"}) { $isreqe = "1"; $REQ_error .= "<li> $REQ_name "; } /* end ! req val */ } /* end REQ for loop */ /* IF THERE ARE ANY REQUIRED FIELDS NOT FILLED IN */ if ($isreqe == "1") { include("nverror.php4"); msng_required(); } } /* END CHECK TO SEE IF $_POST{"required"} IS SET */ /* END IF THERE ARE ANY REQUIRED FIELDS NOT FILLED IN */ /* GET POSTED VARIABLES */ foreach ($_POST as $NVPOST_name => $NVPOST_value) { $NVPOST_value = str_replace("\n", "", $NVPOST_value); $NVPOST_value = str_replace("\r", "", $NVPOST_value); $NVPOST_value = preg_replace("'\cc:'si", "Cc ", $NVPOST_value); $NVPOST_value = preg_replace("'\bcc:'si", "bcc ", $NVPOST_value); $NVPOST_value = preg_replace("'\to:'si", "to ", $NVPOST_value); $NVPOST_value = preg_replace("'\bc:'si", "bc ", $NVPOST_value); if (strtolower($NVPOST_name) == "subject") { $NVPOST_value = str_replace(":", ";", $NVPOST_value); } /* G E T E M A I L */ if (strtolower($NVPOST_name) == "email") { $SEND_email = "$NVPOST_value"; $SEND_email = str_replace(":", "", $SEND_email); $SEND_email = str_replace(" ", "", $SEND_email); } /* END GET LEADS EMAIL */ if (! $_POST{"sort"}) { /* CHECK TO SEE IF CONFIG FIELD */ if ($NVPOST_name == "subject" || $NVPOST_name == "sort" || $NVPOST_name == "required" || $NVPOST_name == "success_page"){}else{ $SEND_prnt .= "$NVPOST_name: $NVPOST_value \n\n"; } } /* end ! sort */ } /* end foreach */ /* END GET POSTED VARIABLES */ if ($_POST{"sort"}) { /* SORT VARIABLES */ $sortvars = split(",", $_POST{"sort"}); $sortnum = count($sortvars); for ($num=0; $num < $sortnum; $num++) { $SEND_prnt .= "$sortvars[$num]: " . $_POST{"$sortvars[$num]"} . " \n\n"; } } /* END SORT VARIABLES */ /* send mail */ if (! $ccto) { $header = "From: $SEND_email\r\nReply-to: $SEND_email"; }else{ $header = "From: $SEND_email\r\nReply-to: $SEND_email\r\nCc: $ccto"; } mail($sendto, $_POST{"subject"}, $SEND_prnt, $header); /* END sendmail */ /* CHECK TO SEE IF FORM SPECIFYS A SUCCESS PAGE */ if (! $_POST{"success_page"}) { include("nverror.php4"); default_success(); }else{ $successpage=$_POST{"success_page"}; header("Location: $successpage"); /* redirect */ exit; } } /* END IF POSTED */ ?> A while back my webhost upgraded to PHP5 and broke a few of my simple scripts - primarily forms using a text box for entry. I renamed and relinked the forms to .php4 and it "solved" the problem. I've decided to fix them correctly and use proper PHP 5 code. What's the easiest way to actually retrieve the value of a text input in PHP5? My old reference tricks return null. When I started reading up I saw only PHP4 examples and then in over my head with global variables, httaccess and php.ini. I don't want to mess about with the default settings. I'm sure I zoomed right past a simple answer on my way to that mess. A simple example script: Code: [Select] <FORM NAME="form1" ID="form1" METHOD="POST" ACTION="simple.php"> <INPUT Type='Text' Name="i1Text" ID="i1Text" Value="Default"> <INPUT Type="Submit" Name="Submit1" Value="Read the Text"> </FORM> <?PHP if (isset($_POST['Submit1'])) { $RefText=$i1Text; print "Text: $RefText"; <!-- Returns blanks unless .php4 --> } ?>So, how do I actually get to that text value? Thanks in advance! I just finished (or so I thought) a project. But my client's server runs PHP4, so I need to adapt my code. Here's what stopped working: Code: [Select] $localClasses = new DOMDocument; $localClasses -> load("file.xml"); $localClasses -> get_elements_by_tagname('Title') -> item(0) -> firstChild -> nodeValue Here's my petty attempt at trying to adapt this code to run in PHP4: Code: [Select] $file = file_get_contents("localClasses.xml"); $localClasses = new DOMDocument($file); $test = $localClasses -> get_elements_by_tagname('Title'); $testText = $test -> item[0] -> firstChild -> nodeValue; print $testText; This doesn't give me any errors, but nothing shows up. Any help would be appreciated. Thanks for reading! I am trying to convert a php4 app to php5 and am getting this error (Fatal error: Cannot re-assign $this in ) when I call this class. $this = $this->createUnique($new); is the line that generates the error. I try to rename $this to $_this but it does not help. I think I lose the reference to the object later on in the code. Then I will get an error like (Fatal error: Call to a member function createUnique() on a non-object in) Is there another way to reference the current instance of an object in php5? Any help appreciated... Code Example: Code: [Select] class imageobject{ var $handle; var $height=0; var $width=0; var $directory; var $filename; //constructor function imageobject($directory,$filename,$width=0,$height=0,$color="FFFFFF") { $this->directory = $directory; $this->filename = $filename; if ($filename=="" && $width>0 && $height>0){ $new = $this->createImage($width,$height); $this = $this->createUnique($new); }elseif (file_exists($directory.$filename)){ $size = GetImageSize($directory.$filename); if ($size) $this->handle = $this->getHandle($directory.$filename,$size[2]); $this->width = $size[0]; $this->height = $size[1]; } function createUnique($imgnew) { $this->type = substr($this->output,0,3); $unique_str = $this->uniqueName(); switch ($this->type){ case "png": imagepng($imgnew,RES_DIR.$unique_str); break; default: imagejpeg($imgnew,RES_DIR.$unique_str,$this->quality); break; } $this->handle && imagedestroy($this->handle); $newobject = new imageobject(RES_DIR,$unique_str,$this->type); return $newobject; } )//end class I have had a problem with some scripts I wrote (Screenscrapers) that worked great in PHP4, but stopped working the minute I upgraded to PHP5. I can change all of my filenames to have the .PHP4 extension and this solves the problem, but since this encompasses a number of sites, internal links and hundreds of files, this is not my first choice solution. Here is the scraper, what it does, is it takes items from the zazzle Results Page by category, strips out the formatting, adds my affiliate ID and then I can present these items on my page. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Test of scrape</title> <link rel="stylesheet" type="text/css" href="/css/scraper.css" /> <script type='text/javascript' src='http://www.zazzle.com/js/logging/omniture/s_code.zjs/r-52.78223/site-zazzle.js'></script> </head> <body> <div class="gridCell " id="page_productsGrid_assetCell1"> <?php $page = file_get_contents("http://www.zazzle.com/cool+smiley+gifts"); //comment out the <span> tags completely $page = preg_replace('/<span/', "<!-- <span", $page); $page = preg_replace('/<\/span>/', "<\/span> -->", $page); $page = preg_replace('/<a /', "<a rel=\"nofollow\" ", $page); $rf_id="238219236805025733"; // Regular expression to parse "&rf=" and the $rf_id into the existing link $page=preg_replace("/(.*?)(href\s*=+\s*[\"\'])(.*?)([\"\'])(.*?)/is","$1$2$3?rf=$rf_id$4$5",$page); $test = explode('<div style="position:relative" class="clearfix">',$page); for($t=1;$t<=count($test)-2;$t++){ print "<div class=\"gridCellInfo\" id=\"page_products\">"; print $test[$t]; } ?> </body> </html> This works find in PHP4; not at all in PHP5. My ideal solution would be an .htaccess file that I could put in any directory under PHP5 to make it default to php4. I have tried this, to no avail (.htaccess): Code: [Select] <IfModule mod_rewrite.c> RewriteEngine On AddType text/html .php4 AddHandler php4-script .php .html php5 </IfModule> I have also tried a few alternatives... this appears to be a common problem and I have scoured the web and found no solution. Here are the two pages in PHP4 and PHP5: php4: http://www.killersmiley.com/test/cool-smiley.php4 php5: http://www.killersmiley.com/test/cool-smiley.php So this script did work in previous versions oh php but in php5 I get the error, "Sorry, uploaded images must be of type jpg or jpeg, (not )." So it looks like it's not recognizing my file as a jpeg?? Any contributions towards a fix are GREATLY appreciated!!! If there are clean, nice (EASY) php5 scripts available for this simple image uploading and thumbnail creation I would consider starting this over. //Listing page code: echo "<form name=\"addCat\" enctype=\"multipart/form-data\" action=\"preview.php\" method=\"post\">"; <INPUT type="file" name="pic1" size="50" value=""> <INPUT type="file" name="pic2" size="50" value=""> <INPUT type="file" name="pic3" size="50" value=""> <INPUT type="file" name="pic4" size="50" value=""> <input type="submit" value="Upload Images"> //preview.php page code: $pic1 = $_FILES['pic1']; $pic2 = $_FILES['pic2']; $pic3 = $_FILES['pic3']; $pic4 = $_FILES['pic4']; function ResizeImage($im,$maxwidth,$maxheight,$name){ $width = imagesx($im); $height = imagesy($im); if(($maxwidth && $width > $maxwidth) || ($maxheight && $height > $maxheight)){ if($maxwidth && $width > $maxwidth){ $widthratio = $maxwidth/$width; $RESIZEWIDTH=true; } if($maxheight && $height > $maxheight){ $heightratio = $maxheight/$height; $RESIZEHEIGHT=true; } if($RESIZEWIDTH && $RESIZEHEIGHT){ if($widthratio < $heightratio){ $ratio = $widthratio; }else{ $ratio = $heightratio; } }elseif($RESIZEWIDTH){ $ratio = $widthratio; }elseif($RESIZEHEIGHT){ $ratio = $heightratio; } $newwidth = $width * $ratio; $newheight = $height * $ratio; if(function_exists("imagecopyresampled")){ $newim = imagecreatetruecolor($newwidth, $newheight); imagecopyresampled($newim, $im, 0, 0, 0, 0, $newwidth, $newheight, $width, $height); }else{ $newim = imagecreate($newwidth, $newheight); imagecopyresized($newim, $im, 0, 0, 0, 0, $newwidth, $newheight, $width, $height); } ImageJpeg (($newim),$name . ".jpg"); ImageDestroy ($newim); }else{ ImageJpeg ($im,$name . ".jpg"); } } // Set up some variables flush(); set_time_limit(210); // set process page limit to 3.5 minutes $maxfilesize = "102400"; //# individual file size limit - in bytes (102400 bytes = 100KB) $path="2012images"; $thumbpath="thumbs"; // two data pulls to rename images - would be easier to have a permanent counter...fix later $mysql[getpicname] = mysql_query("select pic from picname"); $z = mysql_fetch_array($mysql[getpicname]); $new_filename=$z[pic]; $new_z[pic]=$z[pic]+$total_pics; if(@mysql_query("UPDATE picname SET pic = '$new_z[pic]' ")) echo ""; // Create thumbnail from imgurl and store in thumbs // Height to reszie image to (in pixels) $RESIZEHEIGHT=200; // Width to reszie image to (in pixels) $RESIZEWIDTH=200; //thumbnail to thumbs folder, named same as 1st image $FILENAME=$thumbpath."/".$new_filename; $thumb_name=$thumbpath."/".$new_filename.".jpg"; // create a thumbnail from the first image only $im = imagecreatefromjpeg($_FILES['pic1']['tmp_name']); if($im) { if(file_exists("$pic_1.jpg")) { unlink("$pic_1.jpg"); } if (ResizeImage($im,$RESIZEWIDTH,$RESIZEHEIGHT,$FILENAME)) ImageDestroy ($im); } //now upload the images..... for ($i=1;$i<5;$i++) { //check if blank or image $xpic="pic".$i; if (($$xpic<>"none") and ($$xpic<>"")) { // check if jpg $cert1 = "image/pjpeg"; //jpg $cert2 = "image/jpeg"; //jpg (for MAC) $xtype =$HTTP_POST_FILES[$xpic]['type']; $xsize =$HTTP_POST_FILES[$xpic]['size']; if (($xtype <> $cert1) AND ($xtype <> $cert2)) { echo "<DIV class=\"errorsubheading\"><br><br>Alert - Missing or Invalid Information</DIV><br>"; echo "<DIV class=\"requiredtext\">Sorry, uploaded images must be of type jpg or jpeg, (not $xtype).</DIV><BR>"; echo "<BR><br><br>"; include ("footer.php"); exit(); } if ($xsize > $maxfilesize) { echo "<DIV class=\"errorsubheading\"><br><br>Alert - Missing or Invalid Information</DIV><br>"; echo "<DIV class=\"requiredtext\">Sorry, uploaded images must be under the maximum size requirements.</DIV><BR>"; echo "<BR><br><br>"; include ("footer.php"); exit(); } else { // upload to server $dest=$path."/".$new_filename.".jpg"; If (move_uploaded_file($$xpic, $dest)) { $photo[$i]=$dest; $new_filename+=1; } else { echo "<DIV class=\"errorsubheading\"><br><br>Alert - Upload Failed!</DIV><br>"; echo "<BR><br><br>"; include ("footer.php"); exit(); } // upload sucessful } // end type check } // end check if blank } I have an application that was written back in PHP4 days and has ceased development ever since. PHP 4 is basically gone, i can't get it to install on any of my machines now and what i use on my windows boxes (XAMPP) doesn't include PHP4 anymore. When i set everything up, i get ~50 of these: Deprecated: Assigning the return value of new by reference is deprecated in.... and on every line it looks like: $var =& _____ or $var = &something... yada-yada and removing the & symbol removes the error message. Using editplus i removed all the "=&" and "= &" and just replaced the & with space, i had read on google PHP5 doesn't need it anymore so that should've worked. But as my luck would have it, the server errors out with 500 code until i replace all the &'s back, and then the errors show up yet again. Is there anyway to force php5 to run this program despite having php4 things in it? I have several "sites" located in my html directory, and each has a "general" access point and an "administrator" access point:
/var/www/html/site1/index.php /var/www/html/site1/administrator/index.php /var/www/html/site2/index.php /var/www/html/site2/administrator/index.php /var/www/html/site3/index.php /var/www/html/site3/administrator/index.phpAll sites are similar except that data will be specific to site1, site2, or site3, etc. Users who log onto /var/www/html/siteX/index.php are totally unrelated to those who logon to /var/www/html/siteX/administrator/index.php, will have different logon credentials, are stored in different DB tables, and each should have their own session. If a user logs off of either the general or administrator site, it should not effect the other site even if they were previously logged on to both on the same PC (and of course not effect other sites). When a user logs off, I would like to destroy their previous cookie and associated session. Users for either will only use https. I am using Apache to rewrite https://www.mysite.com/ to https://mysite.com/. While I named the administrator site "administrator" above, the administrator user has the ability to change the directory name. I am thinking I need to use session_set_cookie_params to specify where I wish the session cookie to be stored since /var/www/html/siteX/administrator/index.php is a sub-directory to /var/www/html/siteX/index.php, but am not really sure. Sorry for the cryptic post, but I am not very well versed in this subject. How would you recommend setting up cookies/sessions for this scenario? Thank you Not sure if I'm trying to achieve something totally crazy here, or if this is something pretty standard. Didn't have much luck with searching as I'm not fully down with all the terms. (A) I have one site providing an RSS feed. (B) I have one site I want to search, once for each of the items in the feed A. (C) I want the results of the search in (B) to be displayed on page (C). So for example, the feed on (A) says; apples bananas oranges cheese I want site (B) to search for each of those terms (by passing the item in the feed (A) to the ?search= part of the URL of that page) and then show the results from THAT search on page C. Bit of a complex one, let me know if you need me to clarify. Thanks for any help! now i use this code to show where the visitors came from to my site. <?php $referer=$_SERVER['HTTP_REFERER']; echo $referer; ?> now, i want to show the 5 latest vistors referer's site url on my site ? Hi, My first post here is a cry for help I have a Windows 2003 server running IIS6/PHP5, the server hosts multiple web sites. The problem is include files that are for site A are showing on site B (each site having its own includes as part of the site files in its own site folder), though not every time, its very random, sometimes the correct includes show, sometimes ones from another site on the same server. This only occurs where the include files for both sites have the same name, such as 'inc-header.php' for example. I can only assume PHP is caching includes and because they have the same name is showing the wrong one on other sites sometimes, if I rename them to something unique then the problem goes away, but its not a practical solution to rename all include files to unique names so I find myself looking for a 'real' fix. I have a feeling its to do with the include_path in the php.ini, but right now its disabled with a semi-colon, and I don't want to set one as I have no global includes, all includes are site specific. Any help would be very much appreciated! Phil Transferring data from sub-domain.site.com Reading sub-domain.site.com What is this all about? I'm going to put all .. images into a separate sub-domain eg: images.site.com. This would create a folder inside my public_HTML called "images" Now when sites have that Transferring data, and Reading... is this .. something relating to what I want. Facebook also does it, and they get their images for the site from a sub domain, how is it all done? I'm not sure if its entirely PHP, but I hope someone can help. Thanks I'm currently running a classified ads site and planning to display my own content from database combined with and external site rss. So here is what i got right now after the db query for the jobs ads (procedural php),
while ($row = mysqli_fetch_array($results, MYSQLI_ASSOC)){ echo '<div class="media margin-none"> <a class="pull-left bg-inverse innerAll text-center" href="#"><img src="'.$foto.'" share_alt="" width="100" height="100"></a> <div class="media-body innerAll"> <h4 class="media-heading innerT"> <a href="' . $row['title'] .'-da' . $row['id_ad'] . '" class="text-inverse">'. $remuneracion .' ' . substr(ucfirst(strtolower($row['title'])), 0, 53) . '</a> <small class="pull-right label label-default"><i class="fa fa-fw fa-calendar-o"></i> ' . $row['date_created'] . '</small></h4> <p>' . substr(ucfirst(strtolower($row['description'])), 0, 80) . ' ...</p>'; echo '</div> </div> <div class="col-separator-h"></div>'; } echo pagination($statement,$per_page,$page, $url_filtros, $filtros); ?>it is the while loop that i use to display ads from my database, what could be the best way to display (in this same loop?) other site's rss feed so i can show my content combined with the external rss? Thanks Hi, I have two select boxes on my site like this: Language - Level and the user can keep adding more sets of select boxes. I need the data posted to be JSON encoded like this: {"LANG1":["German","Beginner"],"LANG2":["Polish","Advanced"]} etc How can i make this happen? Okay so i know this is going to sound really stupid i just got out of school and now im in the real world here is the problem I dont know very much about how to work with JSON via PHP all i am trying to do is have the Script read data into an array from some text boxes then from the array into a JSON file the reading and the listing is all fine and dandy but only if i want the entire file how do i read data from a JSON file and only have it display data according to what i want so for example if i wanted to return data that matched an ID like you would do in MySQL like this ("SELECT * FROM catagories WHERE ID = '$id'") so how do i do that without a Database using a JSON File as a source for the data My script is not acting like it should. I believe its because of the recent change in the api, (the new error array)? Before there was only one.... <?php $gamertag = 'l RaH l'; $url = "http://api.xboxleaders.com/user_api.php?gamertag=".str_replace(' ', '%20', $gamertag); $output = file_get_contents($url); // try to convert the response into a PHP object $obj = json_decode($output); if(!is_object($obj)) die("Error parsing JSON response\n"); //define variables $avatar = ($obj->user->avatar); $gold = ($obj->user->gold); print $avatar; print $gold; ?> if you print_r $object; it displays this {"error":{"code":200,"desc":"OK"}},{"user":{"gold":1,"gamertag":"l RaH l","avatar":"http:\/\/avatar.xboxlive.com\/avatar\/l%20RaH%20l\/avatarpic-l.png","gamerscore":12508,"reputation":20},"recent_games":[{"recent_game":{"title":"Halo: Reach","link":"http:\/\/gamercard.xbox.com\/en-US\/GameCenter\/Achievements?titleId=1297287259&compareTo=l%20RaH%20l","image":"http:\/\/tiles.xbox.com\/tiles\/ih\/ew\/0Wdsb2JhbA9ECgR8GgMfVlohL2ljb24vMC84MDAwIAAAAAAAAP6fF5U=.jpg"}},{"recent_game":{"title":"Halo 3","link":"http:\/\/gamercard.xbox.com\/en-US\/GameCenter\/Achievements?titleId=1297287142&compareTo=l%20RaH%20l","image":"http:\/\/tiles.xbox.com\/tiles\/Us\/3e\/1Wdsb2JhbA9ECgR8GgMfWSpVL2ljb24vMC84MDAwIAAAAAAAAPrxzU0=.jpg"}},{"recent_game":{"title":"AC Brotherhood","link":"http:\/\/gamercard.xbox.com\/en-US\/GameCenter\/Achievements?titleId=1431504989&compareTo=l%20RaH%20l","image":"http:\/\/tiles.xbox.com\/tiles\/oK\/tp\/1Wdsb2JhbA9ECgUNGgMfVlonL2ljb24vMC84MDAwIAAAAAAAAPpGq78=.jpg"}},{"recent_game":{"title":"Fighters Uncaged","link":"http:\/\/gamercard.xbox.com\/en-US\/GameCenter\/Achievements?titleId=1431504974&compareTo=l%20RaH%20l","image":"http:\/\/tiles.xbox.com\/tiles\/v+\/Au\/0Wdsb2JhbA9ECgUNGgMfVlsmL2ljb24vMC84MDAwIAAAAAAAAP4B4KA=.jpg"}},{"recent_game":{"title":"Assassin's Creed","link":"http:\/\/gamercard.xbox.com\/en-US\/GameCenter\/Achievements?titleId=1431504852&compareTo=l%20RaH%20l","image":"http:\/\/tiles.xbox.com\/tiles\/L3\/mu\/0Wdsb2JhbA9ECgUNGgMfWStXL2ljb24vMC84MDAwIAAAAAAAAP6BeTA=.jpg"}}]} Hey guys I am Posting data over to a server file in Json and I need to know how I can add to the XML file. here is both codes.
function validate() { $xml = simplexml_load_file("stock.xml"); $sxe = new SimpleXMLElement($xml->asXML()); for($i = 1; $i < 801; $i++) { $newItem->addChild("name" , "null"); } $sxe->asXML("stock.xml"); echo $sxe->asXML(); $response = $_POST; $response["items"] = "Test output"; $response["description"] = "test 42 "; $response["json"] = json_encode($response); echo json_encode($response); }The red text is what I want this json script to do. Do I have to return back to my form to add to the XML file? Can json add to a xml file on its own? Thanks for your time! have a good day! |