PHP - Trouble Posting

I have this code with clears the input box onclick...
Code: [Select]
<input type="text" name="username" value="Username" onclick="value=''"/>

however is there any way to use php to get the value of username, before its posted?

that way i can make it so it only clears if the value of username is "username"

can anyone help me as to whay I get this error: Problem with the query: INSERT INTO options (item_id, option ) VALUES('1', 'hi' )
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'option ) VALUES('1', 'hi' )' at line 1

with this code: Code: [Select]
foreach($_POST["user"] AS $key => $val) {
$user = $val;
$id1 = $_POST['id1'][$key];


$sql = "INSERT INTO options (item_id, option )





VALUES('$id1', '$user' )";
$rs = mysql_query($sql) or die ("Problem with the query: $sql <br />" . mysql_error());


} Code: [Select]
<input type="checkbox" name="yes" id="checkme" /><div id = "extra"> <div id="user"> Enter User Names:<br> <input type="text" name="user[]"/><br></div>
<div id="add_user" style="display: none;"><input type="text" name="user[]"/>

the code is in a form whose method = "post".
i have failed to echo $r_in. i eed help on this.

$lowest_time = 30 - 14;
$adder = 2*5*9;

echo   '<table width="526" border="0"><tr>
      <td width="169">
      <input type="text" name="$r_in" value="'.$lowest_time.'"  style="width:169px" readonly="readonly" class="text_non_color"/></td>
      <td width="169">
      <input type="text" name="$r_out" value="'.$adder.'"  style="width:169px" readonly="readonly" class="text_non_color"/></td>
      </tr></table>';

Hi, i have written a form that uses 3 dropdown boxes, one of them being populated from a database.

The form code is as follows;

Code: [Select]
<form id="pointsForm" name="pointsForm" method="post" action="points-engine.php">

<select name="car" id="car">
<?php
        // result of car name collection
        $result = mysql_query ($query);
        
        //Array stored in $cars
        while($cars=mysql_fetch_array($result)){
            
        //option values added by looping through array
        echo "<option value=$cars[id]>$cars[carName]</option>";
        }
?>
</select>

<select name="season" id="season">
<option value="low">Low season</option>
<option value="mid">Mid season</option>
<option value="high">High season</option>
    <option value="peak">Peak season</option>
</select>
   
    <select name="period" id="period">
<option value="day">One day</option>
<option value="weekend">Weekend</option>
<option value="week">One week</option>
</select>

<input type="submit" name="Submit" value="Submit" /> 

</form>
which posts to;

Code: [Select]
<?php

$car=$_POST['car'];
echo $car;

$season=$_POST['season']; 
echo $season;

$period=$_POST['period'];
echo $period;

?>
The initial form code is working fine, the car field is being populated from the database. My problem is the post value for car isn't working...

points-engine.php is echoing $season & $period fine but not $car

can anyone tell me why?

many thanks
Richard

Hi guys,

I have a list box.

say the code is
Code: [Select]
<select name="drop1" id="Select1" size="4" multiple="multiple">

    <option value="1">item 1</option>

    <option value="2">item 2</option>

    <option value="3">item 3</option>

    <option value="4">item 4</option>

    <option value="0">All</option>

</select>

The user will select few items.
How do i capture the data through the "POST" method.

Code: [Select]
$data = $_POST['drop'];
would not work coz there is an array if data.

Can any one help or point me in the right direction?

Thanks in advance

You guys helped me create a function to gather information for my database. Now I need some help with posting that information.

Function code and Form:
<?php include("opendatabase.php"); ?>

<?php
function createMatchup($week, $game)
{
$query1 = "SELECT team_name 
FROM schedule, teams 
WHERE schedule.week_id = $week 
AND schedule.game_id = $game 
AND schedule.A_team = teams.team_id";

$query2 = "SELECT team_name 
FROM schedule, teams 
WHERE schedule.week_id = $week 
AND schedule.game_id = $game 
AND schedule.H_team = teams.team_id";

$result1 = mysql_fetch_assoc(mysql_query($query1));
$result2 = mysql_fetch_assoc(mysql_query($query2));

$output = "
<input type=\"text\" size = \"3\" name=\"w$weekg$gameA\"> {$result1['team_name']} vs. {$result2['team_name']} 
<input type=\"text\" size = \"3\" name=\"w$weekg$gameH\">";

return $output;

}

$game1 = createMatchup(1, 1);
$game2 = createMatchup(1, 2);
$game3 = createMatchup(1, 3);
$game4 = createMatchup(1, 4);
$game5 = createMatchup(1, 5);
$game6 = createMatchup(1, 6);
$game7 = createMatchup(1, 7);
$game8 = createMatchup(1, 8);
$game9 = createMatchup(1, 9);
$game10 = createMatchup(1, 10);
$game11 = createMatchup(1, 11);
$game12 = createMatchup(1, 12);
$game13 = createMatchup(1, 13);
$game14 = createMatchup(1, 14);
$game15 = createMatchup(1, 15);
$game16 = createMatchup(1, 16);

mysql_close($con);

?>

<form action="insert_spreads.php" method="post">
<?php echo $game1; ?>
<br>
<?php echo $game2; ?>
<br>
<?php echo $game3; ?>
<br>
<?php echo $game4; ?>
<br>
<?php echo $game5; ?>
<br>
<?php echo $game6; ?>
<br>
<?php echo $game7; ?>
<br>
<?php echo $game8; ?>
<br>
<?php echo $game9; ?>
<br>
<?php echo $game10; ?>
<br>
<?php echo $game11; ?>
<br>
<?php echo $game12; ?>
<br>
<?php echo $game13; ?>
<br>
<?php echo $game14; ?>
<br>
<?php echo $game15; ?>
<br>
<?php echo $game16; ?>
<br /><br />
<input type="Submit" value="Submit Spreads">
</form>
I'm wondering if I can use this code for posting to the database (insert_spreads.php):
<?php

header("Location: admin_schedule.php");

include("opendatabase.php");

$w$weekg$gameA=("$_POST['w$weekg$gameA']");
$w$weekg$gameH=("$_POST['w$weekg$gameH']");

$sql="
UPDATE schedule 
SET A_pt_spread= '$w$weekg$gameA',H_pt_spread= '$w$weekg$gameH'
WHERE week_id = '$week'
AND game_id = '$game';

$result = mysql_query($sql) or die(mysql_error().$sql);

mysql_close($con)

?>



Thanks for helping.

i am basically trying to retrieve the response of a chatbot from mysql database with query below. As i run script i don't get any error from the server but it seems the post doesn't take $data2 which is an array that includes the keys "user_id" and "text" that are normally accepted (eg: $dmessage->post('direct_messages/new/wrap_links=true', 'text'->'example', '12345');

As result of the above i can't post to Twitter the chatobot response as the recipient (my other twitter account) doesn't get the answer...what do you think?

Code: [Select]

include_once ('connect.php');

connect_to_database();

$query2 = mysql_query ("SELECT response FROM conversation_log WHERE id = (SELECT MAX(id) FROM conversation_log)") or die (mysql_error());

$row = mysql_fetch_row($query2);

$response = $row[0];

//this is the array with the parameters to be used to send bot responses via Twitter API. It normally takes
$data2 = array("text"=>"$response" , "user_id"=> "$userid");

//this modifies the array values with response e userid fields
$data2["text"] = "$response";
$data2["user_id"] = "$userid";

require_once('config_oauth.php'); // includes the applications Oauth keys

require_once($_SERVER['DOCUMENT_ROOT'].'Program-O/gui/xml/oauth/twitteroauth.php'); //Full path to twitteroauth.php library

$dmessage = new TwitterOAuth($consumer_key,$consumer_secret, $oAuthToken, $oAuthSecret); // create new instance with the credentials

//sends the bot response via Twitter API by going through the array $data2
$dmessage->post('direct_messages/new/wrap_links=true', $data2);

I am working on a PHP/MySQL authorization script.
The script seems to work initially, but when I try to Login and post the Form (
        echo '<form method="post" action=authorize_1.php">';
   echo '<table>';
   echo '<tr><td>Userid:</td>';
   echo '<td><input type="text" name="userid"></td></tr>';
   echo '<tr><td>Password:</td>';
   echo '<td><input type="password" name="password"></td></tr>';
   echo '<tr><td colspan="2" align="center">';
   echo '<input type="submit" value="Log in"></td></tr>';
   echo '</table></form>';
)
Internet Explorer returns the error that the page is not found.... but I am using one .php file for the authorization so I am sure the page is found because i can see the Login portion.

Any ideas as to what is going wrong?

How can I post this variable $healspell when I already have an echo within a php?

Here's what I have:



echo '<p>You cast Nature\'s Cure (Recovered <?=$healspell?>)</p>';


It's not printing anything out at the moment, obviously, and if I just put $healspell, it just echos out: $healspell.

Thanks!

might have it nevermind.

I've tried this:
<?php
$xsblock = $_SERVER['HTTP_REFERER'];
$url = "testchan";
$pos = strpos($xsblock, $url);
if ($pos == false) {
die();
} else {
echo "content content content content content content content content";
}
?>

How can I do this correctly?
Thanks in advance! 

I have an issue with my script, the date for some reason stopped posting after I changed the format in the date() section, I wanted it to post so it shows month-day-year, and it seems for some reason all it accepts is Y-m-d...

Can someone help me out here please?

Code: [Select]
<?php
require_once('connectvars.php');

  if (isset($_POST['submit'])) {
    // Connect to the database
    $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$PO_Date = date('MM "/" DD "/" YY',strtotime($_POST['PO_Date']));
$query = "INSERT INTO ncmr (PO_Date) VALUES ('$PO_Date')";
            mysqli_query($dbc, $query);



// Confirm success with the user
        echo '<p>The date have been successfully entered</p>';
mysqli_close($dbc);

// Clear the score data to clear the form
            $PO_Date = "";
}
echo'<form form id="all" method="post">';
echo '<div id="abd"><span class="b">On:&nbsp;&nbsp;</span><input type="text" name="Added_By_Date" value="" /></div>';
echo '<div id="button"><input type="submit" value="Submit Edits" name="submit" /></div>';
echo '</form>'
?>

hello, i have a while loop that displays multiple tables of data depending on how many are in the database... i have a link if you click it will redirect to another page that prompts you to save an xls file with the table data... this was all working for me before when i had the while loop display rows of data in one table...well i decided that i would like the while loop to display a separate table each time... when i changed it... the xls file only shows one table of data... how can i set up so it will export all tables of data... is there some kind of loop i can set up for it to append the tables??

i have the table data all in a variable $table which i put into a hidden form field that redirects to the xls export page.... any help is appreciated...   

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>

<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Admin</title>



</head>

<body>

<?php





$sql= mysql_query("SELECT * FROM programs")
           or die (mysql_error());

while($row = mysql_fetch_array($sql)){

$table =

"<table border='1' width='600' style='border-collapse:collapse;'>" .
"<th colspan='4'>Programs</th>" .
"<tr>" .
"<td>ID</td>" . 
"<td>Views</td>" .
"<td>Enabled</td>" .

"</tr>";




$prog_titles = $row['titles'];


$prog_titles = explode(',' , $prog_titles);








$table .=

 "<tr>" .
 "<td>".$row['id']. "</td>" .
 "<td>".$row['views']. "</td>" .
 "<td>".$row['enabled']. "</td>" .  
 "<td></td>" .
 "</tr>" .







 "<tr>" .
 "<td>Title ID</td>" .
 "<td>Name</td>" .
 "<td>Description</td>" .
 "<td>Image</td>" .
 "</tr>" ;
 






foreach ( $prog_titles as $title ) {

$sql2= mysql_query("SELECT * FROM titles WHERE title = '$title' ");
$row2 = mysql_fetch_array($sql2);


$table .=

 "<tr>" .
 "<td>" . $row2['id'] . "</td>" .
 "<td>" . $row2['title'] . "</td>" .
 "<td>" . $row2['description'] . "</td>" .
 "<td>". "<img width='50px' src='images/" . $row2['img'] . "'/></td>" .
 "</tr>" ;



} // close foreach

$table .=
 "</table>";
 
 
 
 echo $table;
 echo "<br /><br /><br />";
 
  
 
 
} // close while


 
?>

<br />
<br />

<FORM action="export.php">
<INPUT type="submit" value="Export to XLS"> 
<INPUT type="hidden" value="<?php print $table;?>" name="export">
</FORM>


</body>
</html>

i am making a website where i can submit films but i am confuse to understand the structure of that where people can also submit their views and i can diferent link of diffrent companiess for example i have some example

http://tv.desitvforum.net/index.php?option=com_content&task=view&id=77865&Itemid=86

http://www.funbolo.com/more.asp?itemCode=1916


this type of page that i can easily insert links and their title
and images
on that page
there is also one problem every time become different links of different sites in different  counting
so that's why m more confuse ho to set data base structure for that
and how add these all details from panel  and people can also post comment on that well thats simple but my bug problem is structure for this
aNy Body in structure

I have a database in which i store articles that contain all type of special characters including slashes, single quotes, double quote etc.

Previously it was working fine, but now after the updating the xampp, things are not going as usual.

I insert are articles using following code

$query = "INSERT INTO `articles` (`source`, `heading`, `description`, `catagory`, `detail`, `date`, `timestamp`)
          values ('$source', '$heading', '$desc', '$catagory', '$detail', '$date', '$timestamp')";

Error I am getting is

Error Running query 1You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's economy and emphasized that international community should provide its complet' at line 2

Can anybody tell me whats wrong with my script?