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PHP - Convert All Images To Jpeg?
I am using PHP's GD to resize uploaded images and create new ones for security purposes.
Should I leave the converted files in their native format (e.g. PNG ---> PNG) or should I convert all images to JPG (i.e. PNG ---> JPEG)?? Thanks, Debbie P.S. Should it be ".jpg" or ".jpeg" Similar Tutorialsfunction create_image($ext, $filepath, $newfilepath, $jpegquality){ switch ($ext){ case "jpg" OR "jpeg": $im = @imagecreatefromjpeg($filepath); if($im){ imagejpeg($im, $newfilepath, $jpegquality); } break; case "gif": $im = @imagecreatefromgif($filepath); if($im){ imagegif($im, $newfilepath); } break; case "png": $im = @imagecreatefrompng($filepath); if($im){ imagepng($im, $newfilepath, 7); } break; } if(!$im){ return FALSE; } } $ext is my file extention. The rest is pretty self explanitory. It's working for JPEG, but somehow not PNG or GIF. Not sure why, help appreciated. Thanks. Hi all, I am currently making a website that has e-custom functions and a back end for the client. I want them to be able to upload images - but they need to be transparent. I do not want to leave this in the hands of the client, so I am looking at ways of using the GD library to make the change I got no issue with the png/gif type for upload/resize function since this type already transparent background but my major problems is how to deal with jpeg/jpg image type which is their background was not a transparent...so is it possible I can change/ convert to png/gif type upon successful of uploading image...so the new final image will be png/gif type with transparent background...is it doable...I am not even sure it is possible...? Thanks for any help.. the idea on what im doing is like a converter, like showing what your name would look like with certain images per letter, when you input text (your name for example) and when you press the submit button you would get a series of images in a row that represent each character that you typed.
here is the example that i did...
<html> <?php this is the code <?php $image = imagecreatefromjpeg("9t4i_200xX.jpg"); $new_image = imagecreatetruecolor(120,90); imagecopyresampled($new_image, $image, 0, 0, 0, 0, 120, 90, imagesx($image), imagesy($image)); $image = $new_image; imagejpeg($image,"images/test.jpg"); ?> result is black jpeg image of size 120,90 I dont understand where could be the problem SimpleImage.php script doesnt work either hi evry bdy i m new to php here is my big problem im trying to display images and resize but header tag in php not working here is my code <?php header('Content-type: image/jpeg'); $new_width = 200; $new_height = 200; $files = glob("images/*.*"); //print_r($files); //for ($i=0; $i<count($files); $i++) { $filename= $files[0]; print $filename."<br />"; list($width, $height) = getimagesize($filename); echo "width is".$width." and height is ".$height; echo '<img src="'.$filename.'" alt="random image" />'."<br /><br />"; $image_p = imagecreatetruecolor($new_width, $new_height); $image = imagecreatefromjpeg($filename); imagecopyresampled($image_p, $image, 0, 0, 0, 0, $new_width, $new_height, $width, $height); imagejpeg($image_p, null, 100); //} ?> if i m commenting header in line 3 then it is displaying garbage value if i m not commenting then it is displaying filename as string ... i wanna resize image please help me..... Weird question. I am using a captcha class which creates the code/image simply by doing this: Code: [Select] <img src="captcha.php"> The captcha.php file has lots of code of course, but this being key to my question: Code: [Select] header("Content-Type: image/jpeg"); ImageJpeg($image); Can I do it so I can create the image in the PHP of the actual script executing, so I don't have to call captcha.php in the image? - So it would look like this: (well no, but I think this explains what I want) Code: [Select] <img src="<?php echo $captchaCreated; ?>"> I am using a MVC design and don't see why the captcha should try and change this. Hi Coders,
any body can convert the following code into codeigniter.
if($_GET['type'] == 'country'){
$result = mysql_query("SELECT name FROM country where name LIKE '".strtoupper($_GET['name_startsWith'])."%'");
$data = array();
while ($row = mysql_fetch_array($result)) {
array_push($data, $row['name']);
}
echo json_encode($data);
}
Thanks
I have the following code in javascript, I would like to rewrite it in PHP, if someone can help thank you very much. my code: http://pastebin.com/Jnt8RiYj How can I echo this as seconds? $date_at_timezone = new DateTimeZone('Asia/Shanghai'); $date = new DateTime(); $date->setTimezone($date_at_timezone); echo $date->format('l dS F Y h:i:s A') . "Asia/Shanghai<br>"; I have come across a little feature I need to create to be able to upload .doc files and convert them to .pdf using PHP. I was wondering if anyone had any idea how I would go about achieving this, I am not asking for the code, I'm just asking on how it could be accomplished...I've searched Google and other PHP related forums but none have the answer to which I am looking for. Any ideas or suggestions are greatly appreciated. Regards, PaulRyan. Olá,
I have this codE:
$cb = 'str_replace("' . $this->LE . '", "", "<$1>");';
$encoded_value[$key] = preg_replace("/<([^>]+)>/e", $cb, $encoded_value[$key]);
error:
"PHP message: PHP Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead
How can i transform this code to preg_replace_callback ?
thanks
I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
Hi In sql we have dates like this 134238 In php it shows - 19:10:11 . we can make it by using date('d.m.y', $date); where $date=134238 ; my question is how can we turn 19:10:11 in to 134238 using PHP I'm having trouble with a few pages on xcart with the charsets. The problem we're having is that we need to have both utf-8 and iso type charsets as we're getting garbled code on some pages. What I can do is set the utf-8 on all pages and then encode the garbled code into utf-8. Is there a function that does this in PHP or any modules I can use? Thanks I have some words are written by UTF-8. I want to use PHP to convert them to NCR DECIMAL. This is my words. After Convert: Sorry my bad English. Thanks advance This is TEXT FILE my Source. (attach File) [attachment deleted by admin] Hello all, I'm having a problem with people uploading News Articles into my news database. Right now, some of them must be using a weird font to type up their stories, because when they copy/paste their story from Word to the PHP form, it makes the ' turn into the little empty boxes. Also, the same thing is happening to bullets. Any idea how to make ther ' show up correctly, and the bullets to either show, or to convert their bullets to dashes. thanks. how to convert php pages to api Hi, I was wondering if anyone has experience with using php to convert a powerpoint presentation on a Linux OS with Apache web server. The idea would be that a user uploads a powerpoint file that is converted server-side to individual png/jpg files for each slide so that a subset of these slides can be shown as a preview in an image slider. Does anyone know if this can be done on a Linux OS with Apache web server? I came across some solutions for windows versions of php (http://www.php.net/manual/en/com.requirements.php). Hope anyone can help me. Hi, I want to place the following HTML statement inside an echo statement, i.e. in PHP I want to output an image that is also a link. <a href="#"><img src="Somefolder/animage.jpg" width="125" height="156" alt="some image" /></a> All ideas will be greatly appreciated. |
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