PHP - How To Create Easily Mysql Table Edito On My Website For My Visitors?

I am trying to implement this for two days now but stuck with logics ! Please help.
What I can get the due left of every person easily for the following table [image attached] -
table link:  https://ibb.co/xC53Cf4
where
1.inc_due is the column to get total due for specific person like cust_id
2. inctype_id =11 is the type of dues paid for specific person (cust_id)
3. echo only due left by cust_id or person id

Hey yall!
I'm working on a new site idea and I've run across a problem that I know is simple enough but I'm stumped. It's in the signup form
What I want to do is insert the new user into the 'Login' table and get the user id that was just created and use that to create a table with the user id in the name.

Here is what I have:
 // now we insert user into 'Login' table

mysql_real_escape_string($insert = "INSERT INTO `Login` (`UID`, `pass`, `HR`, `mail`, `FullName`) VALUES ('{$_POST['username']}', '{$_POST['pass']}', '{$_POST['pass2']}', '{$_POST['e-mail']}', '{$_POST['FullName']}')");

mysql_query($insert) or die( 'Query string: ' . $insert . '<br />Produced an error: ' . mysql_error() . '<br />' );

 $error="Thank you, you have been registered.";

 setcookie('Errors', $error, time()+20);
 
 // Get user ID

mysql_real_escape_string($checkID = "SELECT * FROM Login WHERE `mail` = '{$_POST['e-mail']}'");

while ($checkIDdata = mysql_fetch_assoc($checkID)) { 

$userID = $checkIDdata;


 // now we create table 'Transactions" for the user
mysql_real_escape_string($create = "CREATE TABLE  `financewatsonn`.`Transactions_{$userID}` (
`ID` INT( 20 ) NOT NULL AUTO_INCREMENT COMMENT  'Transaction ID',
 `name` VARCHAR( 50 ) NOT NULL COMMENT  'Name/Location',
 `amount` VARCHAR( 50 ) NOT NULL COMMENT  'Amount',
 `date` VARCHAR( 50 ) NOT NULL COMMENT  'Date',
 `category` VARCHAR( 50 ) DEFAULT NULL COMMENT  'Category',
 `delete` INT( 1 ) NOT NULL DEFAULT  '0',
UNIQUE KEY  `ID` (  `ID` )
) ENGINE = MYISAM DEFAULT CHARSET = utf8 COMMENT =  'User ID {$userID}'");

mysql_query($create) or die( 'Query string: ' . $create . '<br />Produced an error: ' . mysql_error() . '<br />' );
}

I know in  'Get user ID' that I need to get the ID but I'm not sure how to get that information.

i get the error Quote

Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource

at 166 which is the while line under Get user ID

What I mean by dynamic is say I created a function to generate a random code. I put it in a variable named $key.

I make a form with a hidden input type with the name and value of $key. When the form posts, it generates the table name to whatever $key is.

Because I tried something like this & its not querying. Heres my code:

<?php
$dbc = mysqli_connect('localhost', 'cpacrop_todo', 'pass', 'cpacrop_todo')
or die('Failed to connect to database!');
function make_key($num_chars) {
if ((is_numeric($num_chars)) && 
($num_chars > 0) && 
(! is_null($num_chars))) {
$key = '';
$accepted_chars = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890';
//seed 
srand(((int)((double)microtime()*1000003)) );

for ($i=0; $i<=$num_chars; $i++) {
$random_number = rand(0, (strlen($accepted_chars) -1));
$key .= $accepted_chars[$random_number] ;
}
return $key;
}
}
$key = make_key(6);
?>
<form action="" method="post">
<input type="hidden" name="<?php echo "$key"; ?>" />
<input type="submit" name="submit" value="Submit" />
</form>
<?php
if ($_POST['submit'] == "Submit") {
$query = "CREATE TABLE `$key` (
  `id` INT AUTO_INCREMENT,
  `title` VARCHAR(35),
  `description` VARCHAR(365)
);";
mysqli_query($dbc,$query)
or die('Unable to query database.');
echo "Success";
}
?>


If this is possible, what am I doing wrong?

Thanks!

i want to make virtual money (credits, tokens) whatever you want to call it but make no mistake this is not for profit at this point but i like the concept of visitors having something to do with other members of site for example to kill bordom and create a reason to play games, compete in competetions, it will have to conversion to real money at this point but i wish to do this script using php and mysql and have very basic coding skills in these areas anyone please help me make this script...


reply and let me know if you like this idea


please help me as this is achievable as fb has it and more sites are moving toward these same ideas, even tho fb is real money it is more to do with fun at this point until we do this stage another stage canot proceed it.

How would I create a prepared mysql temp table using PHP?  I currently write my prepared statements like the example below.  How would I create a "TEMP" table? Thanks!

$connection8y = new mysqli("host", "xxx", "xxx", "db");
$result8y = $connection8y->prepare("SELECT ordernum, ordertype, duedate FROM hedord WHERE custnum = ? AND ordertype = ?");
$result8y->bind_param("ss", $custnum, $theordertype);
$result8y->execute();
$bindok8y = $result8y->bind_result($ordernum, $ordertype, $duedate, $yyy, $mmm, $ddd);                                    
while ($bindok8y && $myrow8y = $result8y->fetch()) {
        echo "$custnum $ordernum $ordertype $duedate $yyy-$mmm-$ddd<br>";
  }