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PHP - Write Information From Many Tables To Page (following Tables Dependent On First)
I am trying to write some data from multiple SQL tables to a page. In the first table is a list of places. I then have more tables that are named after the different places. For example, say my first place in the list is called Place1. I have a table named Place1 with data that corresponds to place1. The data contained in the table named Place1 is a list of things to do in this place. It has 21 columns and each one is something to do in the morning, afternoon, and at night for each day of the week in the place Place1. What I am trying to do is display a sort of weekly calendar as a table on a webpage that lists all of the places in one column and then lists seven days of the week as 7 more columns. Then in each data cell I would want to list the things to do in the morning, afternoon and at night for the certain day of the week and for the place. The problem is that I am creating a CMS to allow other users with no coding knowledge to update events for other places, so I have to display data that could have been altered.
The only solution I know of is to do a while loop that gets all of the place names and while there are still place names, write the place names to the page and set a variable equal to the place name. Inside the while loop I would create another while loop that each time the first while loop is executed uses the variable set in the first while loop to know which table to reference and then make a call to that table pulling out the 21 columns and writing them to the page. Each time the outer while loop executes, it would (hopefully) write the place name, and then set the variable as the current place name so that the inner while loop uses the variable to write the rest of the information about that place. I don't know if that would even work and if it did, I know it cannot be the best way to do this. I am pretty stuck here and don't really have a good solution so if anyone proposes a solution that is radically different to anything I have done, I am open to everything. Thank you! Similar TutorialsHi,
I am wanting to bring information from a number of different tables. For an example I have used two tables.
The tables provide results from motorsport. I am wanting a page to display both sets of data WHERE skill is 'novice' for the novice championship. the novice championship includes events from cautotest and ctrial hence why i need both tables.
I have a table called cautotest and ctrial
They both contain the same structure apart from ctrial has more "rounds".
This is the coding for the page i have;
<?php
$cnovice_results = mysql_query("SELECT * FROM cautotest, ctrial WHERE skill ='N'");
if(mysql_num_rows($novice_results) == 0) { echo "<p>No Results Available."; } else {
echo "<table width=\"800\" border=\"0\" cellpadding=\"2\" cellspacing=\"2\" class=\"greywritinglight\" align=\"center\">
<tr align=\"center\">
<td>Competitor</td>
<td>Vehicle</td>
<td>Class</td>
<td>autotest1</td>
<td>autotest2</td>
<td>trial1</td>
<td>autotest3</td>
<td>trial2</td>
<td>Total</td>
</tr>";
$x=1;
while($results_row = mysql_fetch_array($cnovice_results))
{
if($x%2): $rowbgcolor = "#FFFFFF"; else: $rowbgcolor = "#EEEEEE"; endif;
echo "<tr align=\"center\" bgcolor=\"" .$rowbgcolor. "\">";
echo "<td>" . $results_row['competitor'] . "</td>";
echo "<td>" . $results_row['vehicle'] . "</td>";
echo "<td>" . $results_row['class'] . "</td>";
echo "<td>" . $results_row['autotest1'] . "</td>";
echo "<td>" . $results_row['autotest2'] . "</td>";
echo "<td>" . $results_row['trial1'] . "</td>";
echo "<td>" . $results_row['autotest3'] . "</td>";
echo "<td>" . $results_row['trial2'] . "</td>";
echo "<td>" . $results_row['total'] . "</td>";
echo "</tr>";
$x++;
}
echo "</table>";
}
?>
Any help is appriciated
HI, I have a ms-access file which has linked table. The linked table is connected to a ODBC source (e.g MS-SQL or 3rd Party ODBC Driver). WebPage(php) Apache, connecting to a ODBC DSN of MS-Access, MS-Access is having linked tables. Linked tables as from another ODBC source. On the PHP Page, When I am trying to connect the ms-access odbc dsn , I am able to connect. But when I query any of the linked tables, PHP is not able to query and is failing. Does php has capabilities to read/write to linked tables in ms-access file. Or it is issue with MS-Access Or is it I am missing something. Microsoft says, its an issue of PHP https://social.msdn....forum=accessdev Requesting you to please share your feedback Regards Rajendra Dewani I am trying to make a filter to show posts from mutual friends between you and the persons profile you're on, I have somewhat of an idea on how to write the mysql query (it needs to be just one query, not two(which would be the easy way of doing it)). the "friends" table has: "friend_1" and "friend_2" and the "posts" table: "to_id" and "from_id" The PHP variables would be: "$session" and "$id" id would be the users Id of the profile you're on. Thanks, any help would be appreciated. Im doing a search system and Im having some problems.
I need to search in two tables (news and pages), I already had sucess doing my search system for just one table, but for two tables its not easy to do.
I already use a select statment with two tables using UNION because I want to show number of search results, that is number of returned rows of my first sql statment.
But now I need to do a select statment that allows me to acess all fields of my news table and all fields of my pages table.
I need to acess in my news table this fields: id, title, content, link, date, nViews
I need to acess in my pages table this fields: id, title, content, link
Im trying to do this also with UNION, but in this case Im not having any row returning.
Do you see what I have wrong in my code?
<?php //first I get my $search keyword $search = $url[1]; $pdo = connecting(); //then I want to show number of returned rows for keyword searched $readALL = $pdo->prepare("SELECT title,content FROM news WHERE title LIKE ? OR content LIKE ? UNION SELECT title,content FROM pages WHERE title LIKE ? OR content like ?"); $readALL->bindValue(1,"%$search%", PDO::PARAM_STR); $readALL->bindValue(2,"%$search%", PDO::PARAM_STR); $readALL->bindValue(3,"%$search%", PDO::PARAM_STR); $readALL->bindValue(4,"%$search%", PDO::PARAM_STR); $readALL->execute(); //I show number of returned rows echo '<p>Your search keyword returned <strong>'.$readALL->rowCount().'</strong> results!</p>'; //If dont return any rows I show a error message if($readALL->rowCount() <=0){ echo 'Sorry but we didnt found any result for your keyword search.'; } else{ //If return rows I want to show, if it is a page result I want to show title and link that I have in my page table //if it is a news result I want to show title and link that I have in my news table and also date of news echo '<ul class="searchlist">'; $readALL2 = $pdo->prepare("SELECT * FROM news WHERE status = ? AND title LIKE ? OR content LIKE ? LIMIT 0,4 UNION SELECT * FROM pages where title LIKE ? OR content LIKE ? LIMIT 0,4"); $readALL2->bindValue(1, '1'); $readALL2->bindValue(2, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(3, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(4, "%$search%", PDO::PARAM_STR); $readALL2->execute(); while ($result = $readALL2->fetch(PDO::FETCH_ASSOC)){ echo '<li>'; echo '<img src="'.BASE.'/uploads/news/'.$result['thumb'].'"/>'; echo '<a href="'.BASE.'/news/'.$result['id_news'].'">'.$result['title'].'</a>'; //if it is a news result I also want to show date on my list //echo '<span id="date">'.$result['date'].'</span>'; echo '</li>'; } echo ' </ul>'; //but how can I do my select statement to have access to my news table fields and my page table fields?? } ?> This portion is kind of stumping me. Basically, I have a two tables in this DB: users and users_access_level (Separated for DB normalization) users: id / username / password / realname / access_level users_access_level: access_level / access_name What I'm trying to do, is echo the data onto an HTML table that displays users.username in one table data and then uses the users.access_level to find users_access_level.access_name and echo into the following table data, I would prefer not to use multiple queries if possible or nested queries. Example row for users: 1234 / tmac / password / tmac / 99 Example row for users_access_level: 99 / Admin Using the examples above, I would want the output to appear as such: Username: Access Name: Tmac Admin I am not 100% sure where to start with this, but I pick up quickly, I just need a nudge in the right direction. The code I attempted to create just shows my lack of knowledge of joining tables, but I'll post it if you want to see that I did at least make an effort to code this myself. Thanks for reading! I have been playing around with this. Thought I had it nailed, and then found that It was fubar when I started to add more entries to the database. I basically want to display 2 tables from my database on the page. One is called "players" the other is called "editlog". The output with my current script came out as this: and here is the dreaded code: <html> <body> <u><h3>Performance Point Monitor (PPM): Knights of Shadow WoW Officers.</h3></u> <?php include('/home/a3269923/public_html/ppm/admin/config.php'); include('/home/a3269923/public_html/ppm/admin/dbopen.php'); $query="SELECT * FROM players"; $result=mysql_query($query); $num=mysql_numrows($result); ?> <table border="1" style="position:absolute;width:500;height:10;left:0;top:70"> <tr> <th><font face="Arial, Helvetica, sans-serif">PLAYER</font></th> <th><font face="Arial, Helvetica, sans-serif">POINTS</font></th> <th><font face="Arial, Helvetica, sans-serif">DATE</font></th> </tr> <?php $i=0; while ($i < $num) { $f2=mysql_result($result,$i,"PLAYER_NAME"); $f3=mysql_result($result,$i,"ND_POINTS"); $f4=mysql_result($result,$i,"DATE ADDED"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> </tr> </table> <?php $i++; } ?> <?php include('/home/a3269923/public_html/ppm/admin/config.php'); include('/home/a3269923/public_html/ppm/admin/dbopen.php'); //USER LOG $query="SELECT * FROM editlog"; $result=mysql_query($query); $num=mysql_numrows($result); ?> <table border="1" style="position:absolute;width:600;height:10;left:510;top:70"> <tr> <th><font face="Arial, Helvetica, sans-serif">USER</font></th> <th><font face="Arial, Helvetica, sans-serif">TYPE</font></th> <th><font face="Arial, Helvetica, sans-serif">POINTS</font></th> <th><font face="Arial, Helvetica, sans-serif">NOTES</font></th> <th><font face="Arial, Helvetica, sans-serif">DATE</font></th> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"USER"); $f2=mysql_result($result,$i,"TYPE"); $f3=mysql_result($result,$i,"POINTS"); $f4=mysql_result($result,$i,"NOTE"); $f5=mysql_result($result,$i,"TIMESTAMP"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> </tr> </table> <?php $i++; } ?> What am I doing wrong? Halp! hello all, i want to display each row from mysql table in a different page using this code: Code: [Select] <? require_once('config.php'); //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die("can't connect: " . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("can't select database"); } mysql_query("SET NAMES 'hebrew'"); //mysql_set_charset('utf8',$link); if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = $page-1; $qry='SELECT * FROM ordering limit 0, 1'; $result = mysql_query($qry); while($row = mysql_fetch_array($result)){ echo "<div dir='rtl' charset='utf8'><h2>"," hover cam: ",$row['hover_camera'], "<br> stills: ",$row['stills'], "<br> video_photographers: ",$row['video_photographers'], "<br> increase: ",$row['increase'], "<br> video_edit: ",$row['video_edit'], "<br> digital_album: ",$row['digital_album'], "<br> photo_album: ",$row['photo_album'], "<br> small_digital_album: ",$row['small_digital_album'], "<br> video_clip: ",$row['video_clip'], "<br> magnets: ",$row['magnets'], "<br> comments: ",$row['comments'], "<br> date: ",$row['date'], "<br><br></h2></div>"; } $sql = "SELECT COUNT(userid) FROM ordering"; $result = mysql_query($sql,$link); $row2 = mysql_fetch_row($result); $total_records = $row2[0]; $total_pages = $total_records ; for ($i=1; $i<=$total_pages; $i++) { echo "<a href='table.php?page=".$i."'>".$i."</a> "; }; ?> this is the table: Code: [Select] CREATE TABLE IF NOT EXISTS `ordering` ( `userid` int(11) unsigned NOT NULL AUTO_INCREMENT, `hover_camera` varchar(10) DEFAULT NULL, `stills` int(5) NOT NULL, `video_photographers` int(5) NOT NULL, `increase` int(5) NOT NULL, `video_edit` varchar(10) NOT NULL, `digital_album` varchar(10) DEFAULT NULL, `photo_album` varchar(10) DEFAULT NULL, `small_digital_album` varchar(20) DEFAULT NULL, `video_clip` varchar(10) DEFAULT NULL, `magnets` int(10) NOT NULL, `comments` text NOT NULL, `date` date NOT NULL, PRIMARY KEY (`userid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 ; the problem is that only the first row is displayed no matter which page i choose and i want each page to display the row assigned to it (page 15 = row 15 etc...) any suggestions? hello i have a mysql table and i want to display each row in a different page with an added condition, the code: Code: [Select] if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = $page-1; $qry="SELECT * FROM ordering WHERE userid='$page' AND email='$email' LIMIT 0,1"; $result = mysql_query($qry); while($row = mysql_fetch_array($result)){ echo "<div dir='rtl' charset='utf8'><h2>"," hover cam: ",$row['hover_camera'], "<br> stills: ",$row['stills'], "<br> video_photographers: ",$row['video_photographers'], "<br> increase: ",$row['increase'], "<br> video_edit: ",$row['video_edit'], "<br> digital_album: ",$row['digital_album'], "<br> photo_album: ",$row['photo_album'], "<br> small_digital_album: ",$row['small_digital_album'], "<br> video_clip: ",$row['video_clip'], "<br> magnets: ",$row['magnets'], "<br> comments: ",$row['comments'], "<br> date: ",$row['date'], "<br><br></h2></div>"; } $sql = "SELECT COUNT(userid) FROM ordering"; $result = mysql_query($sql,$link); $row2 = mysql_fetch_row($result); $total_records = $row2[0]; $total_pages = $total_records ; for ($i=1; $i<=$total_pages; $i++) { echo "<a href='myorders.php?page=".$i."'>".$i."</a> "; }; the table is as so: Code: [Select] CREATE TABLE IF NOT EXISTS `ordering` ( `userid` int(11) unsigned NOT NULL AUTO_INCREMENT, `hover_camera` varchar(10) DEFAULT NULL, `stills` int(5) NOT NULL, `video_photographers` int(5) NOT NULL, `increase` int(5) NOT NULL, `video_edit` varchar(10) NOT NULL, `digital_album` varchar(10) DEFAULT NULL, `photo_album` varchar(10) DEFAULT NULL, `small_digital_album` varchar(20) DEFAULT NULL, `video_clip` varchar(10) DEFAULT NULL, `magnets` int(10) NOT NULL, `comments` text NOT NULL, `date` date NOT NULL, `fname` varchar(100) NOT NULL, `email` varchar(100) NOT NULL, PRIMARY KEY (`userid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; now to the problem: this code displays all the userid as page numbers however, the email condition is good only for part of the rows it's a little hard to explain, i'll try an example: suppose the email '1@1.com' is at rows 22,25 and 30 my code displays 30 page numbers and page 22 is user 22, page 25 is user 25 etc. what i want is to display only the page numbers of the pages with the conditional email, and if possible to display them as 1,2,3 instead of 22,25,30 Hi, I wonder if I somebody can help me I have three drop down lists which are populated from data thats stored in my sql database. I also have a table which is echoed from the database all on the same page. What i want to do is allow users to select values in the drop down lists which will then echo different results below in the table. Is this possible. So on page load it will show all of the info in the html table. Then when the user changes the drop downs and clicks submit it will change the query to something SELECT dropdown1 value FROM users where Dropdown2 = 1 AND Dropdown3 = 2 etc. Is this possible to display this information on the same page using the dropdown list or does it need to load a different page as the client side is trying to edit a server side script? If its possible please can someone give me an example. Thanks in advance Edd This is more than a question than anything else: I am looking for a tutorial or something that will allow me to make tables with php and mysql for example what I need is: mysql data: table = links lid = 1 lname = Page 1 linkid = page.php lid = 2 lname = Page 2 linkid = page2.php etc and i am try to get it so if there is 2 pages then the table would do Page 1 Page 2 if 3 Page 1 Page 2 Page 3 so there are 2 lname(s)s per row and 1 in each column and it would keep building the table and rows as more lname(s) are added. Does anybody know where to find a tutorial on doing something like this. Thanks in advance hi everyone, Whats the best way to put my displayed php into my table? I already have gotten to the point where it is displayed, but it looks basic, so i want it to look like the table below it.... i just havent quite figured out how to "space" the data out so it looks better? Is it just a case of printing out what i want where in the table? or is it something more complex? http://www.removalspace.com/indextwo.php Hi everyone! I am trying to figure out how to put echoed php results from mySQL database into a table ready for styling to look how i want it too. So far i have got to the point where the results are echoed out but they are not in a good table layout. (under "latest removalspace user's) I want it more structured in my table. I have found out how to create the table but just not been able to work out how to fit the echo's in without snytax errors??? the "new" table that i want to use is near the end of the script. Code: [Select] <?php // Make a MySQL Connection mysql_connect("***", "***", "***") or die(mysql_error()); mysql_select_db("***") or die(mysql_error()); // Retrieve all the data from the "example" table $result = mysql_query("SELECT company_name, location, postcode, basicpackage_description, premiumuser_description, upload FROM Companies") or die(mysql_error()); // store the records into $row array and loop through while ( $row = mysql_fetch_array( $result, MYSQL_ASSOC ) ) { // Print out the contents of the entry echo "Name:\r".$row['company_name']; echo "\r\rLocation:\r".$row['location']; echo "\r\rPostcode:\r".$row['postcode']; echo "\r\nBasic Users:\r".$row['basicpackage_description']; echo "\r\nPremium Users:\r".$row['premiumuser_description']; echo "\r\nlogo:\r".$row['upload']; echo "<img src=\"http://www.removalspace.com/images/COMPANIES" . $row['upload'] . "\" alt=\"logo\" />"; echo "<table> <tr><th>Comppany Name</th><th>Location</th><th>Postcode</th><th>Basic Members</th><th>Upgraded Users</th><th>Company Logo</th></tr> <tr><td></td><td></td><td></td><td></td><td></td><td></td></tr>"; } ?> Hi everyone... I have a thumbnail page that is putting out tables that are skewed and I am not able to use CSS properly because of that. Is there anyways I can change the PHP output? This is my code... I think the highlighted area is responsible for my tables? But it is mismatching the <tr> and <td> tags.... I really want it to show a structured table.. like <table> <tr> <td> </td> </tr> </table> // Thumbnail Listing else if( $cid && empty( $pid ) ) { $number_of_thumbs_in_row = 4; // If current page number, use it // if not, set one! if(!isset($_GET['page'])){ $page = 1; } else { $page = $_GET['page']; } // Define the number of results per page $max_results = 400; // Figure out the limit for the query based // on the current page number. $from = (($page * $max_results) - $max_results); $result = mysql_query(" SELECT photo_id , photo_caption , photo_filename , photo_category FROM gallery_photos WHERE photo_category='".addslashes($cid)."' LIMIT $from, $max_results "); $nr = mysql_num_rows( $result ); if( empty( $nr ) ) { $result_final = "\t<tr><td>No Photos found</td></tr>\n"; } else { while( $row = mysql_fetch_array( $result ) ) { $result_array[]= "<a href='viewgallery.php?cid=$cid&pid=".$row[0]."'><img src='".$images_dir."/tb_".$row[2]."' border='0' alt='".$row[1]."' class='img'/></a>"; } $result = mysql_query( "SELECT category_name FROM gallery_category WHERE category_id='".addslashes($cid)."'" ); list($category_name) = mysql_fetch_array( $result ); mysql_free_result( $result ); $result_final = "<tr>\n\t<td> <span class='navlinks'><a href=viewgallery.php>Albums</a></span><font color=#ff0000> >> </font> <span class='navlinks'><a href=viewgallery.php?cid=$cid>$category_name</a></span><br><br/><br/><br/></td>\n</tr>\n"; foreach($result_array as $thumbnail_link) { if($counter == $number_of_thumbs_in_row) { $counter = 1; [b][size=24pt][size=18pt][b]$result_final .= "\n</tr>\n<tr>\n";[/b][/size][/size][/b] } else $counter++; [b][size=18pt] $result_final .= "\t<td>".$thumbnail_link."</td>\n";[/size][/b] } if($counter) { And my HTML output shows the tables like this... Code: [Select] <body> <table width='100%' border='0' align='center' style='width: 80%;'> <tr> <td> <span class='navlinks'><a href=viewgallery.php>Albums</a></span><font color=#ff0000> >> </font> <span class='navlinks'><a href=viewgallery.php?cid=1>Abstract</a></span><br><br/><br/><br/></td> </tr> <td><a href='viewgallery.php?cid=1&pid=240'><img src='photos/tb_240.jpg' border='0' alt='End Of Day' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=239'><img src='photos/tb_239.jpg' border='0' alt='A Photographer's Dream' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=238'><img src='photos/tb_238.jpg' border='0' alt='Heaven's View' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=237'><img src='photos/tb_237.jpg' border='0' alt='Colorful World ' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=241'><img src='photos/tb_241.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=242'><img src='photos/tb_242.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=243'><img src='photos/tb_243.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=244'><img src='photos/tb_244.jpg' border='0' alt='' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=245'><img src='photos/tb_245.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=246'><img src='photos/tb_246.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=247'><img src='photos/tb_247.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=248'><img src='photos/tb_248.jpg' border='0' alt='' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=249'><img src='photos/tb_249.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=250'><img src='photos/tb_250.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=251'><img src='photos/tb_251.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=252'><img src='photos/tb_252.jpg' border='0' alt='' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=253'><img src='photos/tb_253.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=254'><img src='photos/tb_254.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=255'><img src='photos/tb_255.jpg' border='0' alt='' class='img'/></a></td> </table> </body> I want to read records from the database and print out in this table and I need help with the code. Code: [Select] <?php mysql_connect(localhost,root,""); mysql_select_db(oodb) or die( "Unable to select database"); $query=" SELECT * FROM oocust"; $result=mysql_query($query); $num=mysql_numrows($result); ?> <HTML><HEAD> <script type="text/javascript"> var monthNames = [ "January","February","March","April","May","June","July", "August","September","October","November","December" ]; var today = new Date(); var mmyy = monthNames[today.getMonth()] + " / " + today.getFullYear(); </script> </HEAD><BODY bgcolor="#CCCC99" background="oldorchard.jpg"><b><center> <font size=+2><b> Old Orchard Invoice </font>Date: <script type="text/javascript">document.write(mmyy);</script></center> echo "<TABLE BORDER="0" CELLPADDING="5" CELLSPACING="5" background="oldorchard.jpg"> <TD> <TABLE BORDER="0" CELLPADDING="10" CELLSPACING="10" background="oldorchard.jpg"> <TD> <TABLE BORDER="0" CELLPADDING="1" CELLSPACING="1" background="oldorchard.jpg"> <TD> <input type=text size=25 value="Old Orchard Plumbing"><br> <input type=text size=25 value="2210 E. Hogan Hollow Road"><br> <input type=text size=25 value="Margate, Fl 33063"><br></TD> <TR> <td> <input type=text size=3 value="Bill To:"><br> <input type=text size=25 value="$bname"><br> <input type=text size=25 value="$bstreet:">><br> <input type=text size=25 value="$bcity"><br> <input type=text size=25 value="$contact"><br></TD> <tr> <td> <input type=text size=5 value="Ship To:"><br> <input type=text size=25 value="$sname:"><br> <input type=text size=25 value="$street"><br> <input type=text size=25 value="$scity"></td> </TR> </TABLE> </TD> <TD> <input type=text size=25 value="Invoice No: $invnum"><br> <input type=text size=25 value="Date: $mm/dd/yyyy"><br> <input type=text size=25 value="Terms: $terms"><br> <input type=text size=25 value="Due Date: $duedate"><br> <input type=text size=25 value="Order No: $ordernum"><br> <input type=text size=25 value="Territory:"><br> <input type=text size=25 value="Salesperson:"><br> </TD> </TABLE> </TD> <TD align=center><img src="dave pic.jpg" width=250 height=350></td> </TABLE> echo "</tr>"; <hr> echo "</table>";mysql_close(); ?> </b></BODY></HTML> Hi everyone. I am a newbie to mysql php and have a question. I can display records in a loop from one table but i want to display the records from another table as well that has the same quoteid and where approved is "n" This is what have so far, but there is also only 3 fields from the quotes table i want to display in the loop. $sql = mysql_query("SELECT * FROM comments WHERE approved LIKE 'n%'"); while ($row = mysql_fetch_array($sql)) { $count = mysql_num_rows ( $sql ); foreach($row as $key=>$value){ $$key = htmlentities(stripslashes($value)); } echo ' Hope i make sense. <?php $con = database_connect(); $sql = "SELECT * FROM anime1, episode1 WHERE animeid='$animeid'"; $result = mysql_query($sql); while ($row = mysql_fetch_assoc($result)) { $title = $row['title']; $ep = $row['ep']; } ?> keep giving me back error Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\wamp\www\studying\take 2\addin12.php on line 45 Hello all! So I am working on screen scraping a site for my son's rec league. I seem to be having problem with the pre_match_all syntax. Here is my code Code: [Select] <?php $url = "http://www.mywebsite.com"; $raw = file_get_contents($url); $newlines = array("\t","\n","\r","\x20\x20","\0","\x0B"); $content = str_replace($newlines, "", html_entity_decode($raw)); $start = strpos($content,'table border="1" cellpadding="1" cellspacing="0"'); $end = strpos($content,'</table>',$start) + 8; $table = substr($content,$start,$end-$start); preg_match_all("|<tr(.*)</tr>|U",$table,$rows); foreach ($rows[0] as $row){ if ((strpos($row,'<th')===false)){ preg_match_all("|<td(.*)</td>|U",$row,$cells); $game_date = strip_tags($cells[0][0]); $game_time = strip_tags($cells[0][1]); $rink = strip_tags($cells[0][2]); $home_team = strip_tags($cells[0][3]); $home_score = strip_tags($cells[0][4]); $visiting_team = strip_tags($cells[0][5]); $visiting_score = strip_tags($cells[0][6]); echo "{$game_date} @ {$game_time} : [{$home_team}] - {$home_score} vs. [{$visiting_team}] - {$visiting_score} <br>\n"; } } ?> My issue is that I am trying to get it to only display the data if the team name = x. I tried to replace the preg_match_all("|<td(.*)</td>|U",$row,$cells); with preg_match_all("|Posse|U",$row,$cells); (Posse is one of the team names). No luck. Any input/thoughts?! Thank you!! hi i created a page where users can reply to a post and i saved there reply in a table i called comment.when new visitors click on a topic they can see the topic and the people that comment on the topic..Now my problem is this when i click on any topic it display the comment on that topic whch is good but also display comments from other topics wchich is not supposed to be.i have tried joining the tables but i keep getting syntax errors.is joining the comment table to the topics table the solution?? if so can anyone give me the proper way of joining a table but if there is another way kindly tell me.Thanks this is the problem i have 2 tables table named ZAMJENE with fields id_event_1, id_event_2 table named EVENTS with fields id_event and event_date and i need echo $id_event_1 on date(EXTRACT FROM TABLE EVENTS FIELD event_date) can be replaced with $id_event_2 on date(EXTRACT FROM TABLE EVENTS FIELD event_date) structure must remains because i have half site build already and i have 3rd table where i just need use JOIN hope you understand problem just trying to see if i have this right in my head here.. if i have a page that has a topic on it and many replies, the tables would look like this.. would this be the right code to pull out the topic AND all responses for say. www.mysite.com/view?id=1 $topic = 'SELECT * from topics where id = $id' $replies = 'SELECT * from replies where replies.topic_id = $id' |
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