|
PHP - Saving Pictures/photo's On The Server??
Hi everyone!
I'm trying to create a form with an upload photo bit in it. The photo i know, has to be saved on the server somewhere. Iv'e created an images folder both in my host's control pannel and in my dreamwever files and FTP'd it to the server. I've tried both ways of sending the test .jpg to each folder but i'm getting the desgined mySQL error. What's going worng here? Code: [Select] <?php //This is the directory where images will be saved $target = "/images/COMPANIES"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $company_name=$_POST['company_name']; $basicpackage_description=$_POST['basicpackage_description']; $location=$_POST['location']; $postcode=$_POST['postcode']; $upload=($_FILES['photo']['name']); // Connects to your Database mysql_connect("******host", "****username", "****password") or die(mysql_error()) ; mysql_select_db("****DB") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO `Companies` VALUES ('$company_name', '$basicpackage_description', '$location', '$postcode', '$upload')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } ?> Thanks Similar TutorialsIs it possible to do this? fpdf just opens a dialog box asking the user to save the pdf instead of saving it on the server. Also, is it possible to create a pdf from the data in a mysql table with PHP? Thanks! Hello Guys, I want to extract the attachment from an email. I searched and I found the following link below and many similar ones useful. http://garrettstjohn.com/entry/extracting-attachments-from-emails-with-php/ I am able to get the name of the attachments too.. but.. what after getting the file names? .. How do i actually access the file and move it to a location to my server?.. that part is unclear to me.. Please share me your views on this.. or point me in some direction as to how to accomplish this task. Thank you, Rakesh.
try {
echo "<br>";
foreach($dbh->query("SELECT * FROM test_shot WHERE sold=1 ORDER BY year ASC") as $row) {
if($row['picture'] != "" && $row['picture'] != null)
{
echo "<div class='image-holder'><img src ='".$row['picture']."' width=300px /><br>";
}
if($row['year'] != "" && $row['year'] != null)
{
echo $row['year'];
}
if($row['description'] != "" && $row['description'] != null)
{
echo $row['description'];
}
if($row['sold'] == 1) {
echo "<img src='images/sold1.png'><br>";//Add your image code here
}
elseif ($row['sold'] == 0) {
echo "</div><br>";
}
}
}
catch (PDOException $e) {
print $e->getMessage();
}
?>
I have a PHP web system that store in a windows server. In the system, there is a function for user to upload files to another server (Shared server in Unix). When i try to upload a file, it gives warning: Warning: move_uploaded_file(\\unixserver/sharedfolder/upload/test.txt) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\wamp\www\upload\index.php on line 40 For your information, my username has been assigned in xxx's group that has access to read and write on that folder. Besides, i'm able to open,create and delete files on that folder's server manually (samba). The safe mode setting is off. Does anybody has any idea why this thing happen? Hi, I am not a PHP programmer. I took on a new client with a simple PHP site, without any databases. The site is up and running on the web. I would like to get it running on my local machine for further development. I have latest version of WAMP installed, running Apache version 2.2.11 and PHP version 5.3.0 I created a directory in the WAMP "www" project directory and it shows up there like it's supposed to when I browse to "localhost" Problem: The home page of website displays text but no, images, styles, footer, header, nav links, etc. Here is the code for the home page: <? define("NAV","home"); require_once('local/local.php'); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>TITLE</title> <meta name="keywords" content=""> <meta name="Description" content=""> <? include("common/dochead.php"); ?> </head> <body onLoad="<? include('common/preloads.php'); ?>"> <!-- ============================ main ============================= --> <div id="main-frame"><div id="main" class="noCollapse"> <? include("common/sign.php"); ?> <div id="right-frame"> <? include("common/navigation.php"); ?> <div id="content-frame"> <div id="content"> <h1>Welcome</h1> <p>This is the content area. This is the content area. This is the content area. </p> </div><!-- end content --> </div><!-- end content-frame --> </div><!-- end right-frame --> <div class="clearFloats"></div> </div><!-- end main --></div><!-- end main-frame --> <? include("common/footer.php"); ?> </body> </html> Any help would be greatly appreciated. I have spent many hours on this. Regards I'm trying to make a simple website where people register to my website. When the user doesn't fill anything inside the boxes they get a message "Please fill all required fields" on the register.php page On my local host require_once works good. It shows up.
But when i upload the files to my sever the require_once does not show up on the register.php It just refreshes and i dont get the message "Please fill all required fields"
This is the code that works in local host but not in a live server <?php require_once 'messages.php'; ?>
Here is my full code
Register page: <html> <?php require_once 'messages.php'; ?> <br><br> <form action="register-clicked.php" method="POST"> Username:<br> <input type="text" name="usernamebox" placeholder="Enter Username Here"> <br><br> Email:<br> <input type="text" name="emailbox" placeholder="Enter email here"> <br><br> Password:<br> <input type="password" name="passwordbox" placeholder="Enter password here"> <br><br> Confirm Password:<br> <input type="password" name="passwordconfirmbox" placeholder="Re-enter password here"> <br><br> <input type="submit" name="submitbox" value="Press to submit"> <br><br> </form> </html>
Register clicked <?php
session_start();
$data = $_POST;
if( empty($data['usernamebox']) ||
empty($data['emailbox']) ||
empty($data['passwordbox']) ||
empty($data['passwordconfirmbox'])) {
$_SESSION['messages'][] = 'Please fill all required fields';
header('Location: register.php');
exit;
}
if ($data['passwordbox'] !== $data['passwordconfirmbox']) {
$_SESSION['messages'][] = 'Passwords do not match';
header('Location: register.php');
exit;
}
$dsn = 'mysql:dbname=mydatabase;host=localhost';
$dbUser='myuser';
$dbPassword= 'password';
try{
$connection = new PDO($dsn, $dbUser, $dbPassword);
} catch (PDOException $exception){
$_SESSION['messages'][] = 'Connection failed: ' . $exception->getMessage();
header('Location: register.php');
exit;
}
messages.php <?php
session_start();
if (empty($_SESSION['messages'])){
return;
}
$messages = $_SESSION['messages'];
unset($_SESSION['messages']);
?>
<ul>
<?php foreach ($messages as $message): ?>
<li><?php echo $message; ?></li>
<?php endforeach; ?>
</ul>
Edited Wednesday at 12:49 AM by bee65 Hi folks, I'm curious if I can for example, save a file from my server and it will save to all other servers - obviously if they accepted the connection first. It's for a software I developed and is almost complete and know there will be frequent updates to it. Instead of users downloading upates, I want the update files from my server to somehow synchronize to their server automatically? Anything called this?? Thanks for info. Following a tutorial on udemy, i tried to learn the very basics of mvc structure. I built the same project on my local server and it worked without giving me any error. but when i tried it on live server. its not working as it should. not showing any error. I tried to figure out the problem and found that for every page loading, it stops at the same line in my main.php file. <?php require($view); ?> starting from the above line. it stops. i came here to share my problem but i am unable to upload my files here. if there is a way to upload and share my files, please guide. zip file size of the whole project is 31.6 kb This isn't exactly an application design question, but rather a system design one.
I am about to install an Inventory Control System inside this store I work in.
The store itself also owns a Linode VPS running Centos 6.4 which hosts our website.
This new Inventory System will come built in with a Microsoft SQL Server, and supposedly it is a SQL Anywhere database, but I'm not too sure what that means.
I need to make this database publicly accessible, but only via the Linode VPS. Surely, setting restrictions is easy enough to address that issue. That isn't my question.
My first idea is to put this server into the DMZ, easy. But it doesn't exactly sound safe. So my next idea was to put a middleman server in the DMZ, this way the Linode can send queries to that middleman server and it will send that data to the SQL Server and back. This is very vaguely described I know, but I don't want to get too much into details, but rather, understand how I can create that middleman server, and what could Install onto it that would allow me to securely process queries?
My first thought was to install a webservice, that accepts an XML/JSON request and returns an XML/JSON response.
Then, I realized directly afterwards that I don't have any experience setting up a webservice like that.
What kind of options are there out there? Ultimately, my question is, should I just put the Server in the DMZ or should I create the middleman, and if so, can someone point me in the right direction as to getting a webservice set up? Edited by Zane, 15 July 2014 - 11:28 PM. (This might be the wrong forum; it might be server-side configuration, but alas it is the code that *calls* fwrite, so I'll start here.) I have written a script, and one thing it does is generate a file to disk using fwrite. No big deal. Here's what interests me: On most servers, the file is written successfully when the folder's permissions are 755 with recursive permissions. On some servers, 755 fails. Only 777 works. How could this be? Are permissions=permissions=permissions? Why will 755 work on one machine but not another? I'm just a logic guy; I know very little of server-side configuration and/or why there would be a difference here. Just trying to learn. Hey. I am wanting to move a couple of files from my current server to another. If i am uploading the file this is fine but if it is already on the server then im not sure how to move it. When uploading I can just use ftp_put($conn_id, $destination_file, $myFile, FTP_BINARY); What i need to do is figure out how to get a hold of the file and store it in $myFile then this would work fine. Is this possible? Cheers What I'm trying to do is copy all files from one server to another folder on another server. Here is what I have have so far.. <?PHP //connection settings $ftp_server = "server"; $ftp_user_name = "user"; $ftp_user_pass = "pass"; $dir = "/var/test/"; $destination_file = "/test/"; // set up basic connection $conn_id = ftp_connect($ftp_server); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); // check connection if ((!$conn_id) || (!$login_result)) { echo "FTP connection has failed!"; echo "Attempted to connect to $ftp_server for user $ftp_user_name"; exit; } else { echo "Connected to $ftp_server, for user $ftp_user_name"; } if (ftp_chdir($conn_id, $dir)) { echo " <br/>Current directory is now: " . ftp_pwd($conn_id) . "\n<p/>"; } else { echo "Couldn't change directory\n<p/>"; } $buff = ftp_rawlist($conn_id, $dir); foreach($buff as $files) { echo $files. "<br/>"; if (ftp_get($conn_id, $destination_file."test.file", $dir."test.txt", FTP_BINARY)) { echo "<br/>Successfully written to $destination_file\n"; } else { echo "There was a problem\n"; } ?> That doesn't work. Any ideas? Thanks, Sean I have two servers: WebServer and FaxServer. WebServer needs to send a fax. Is my approach shown below fairly secure? Before sending a fax, ServerWeb needs to store a record in a table representing the message, and I am using a pseudo random value for the PK which is generated as 2147483648+mt_rand(-2147483647,2147483647). WebServer then generates a hash equal to hash('sha256',$pk.'secretCodeWhichOnlyWebServerAndFaxServerKnow'). WebServer then sends curl request to FaxServer using POST which includes $pk, the hash, the fax number, some text to include in the fax, and an optional array of document to include (array(array('id'=>321,'name')=>'fileName.pdf')). FaxServer verifies that the hash is correct given $pk, that the minimum information has been received, and that the fax number is a valid phone number, and quickly responds to WebServer by echoing 0 or 1 so the code in the WebServer could continue and inform the user. If all looks okay, a new instance of PHP is started.
if(missingInformation) {echo(0);}
else {
session_start();
$_SESSION['_xfr']=$_POST;
exec('/usr/bin/php -q /path/to/send_fax.php '.session_id().' >/dev/null &');
echo(1);
}
New instance of PHP send_fax.php then does the following:
session_id($argv[1]);//Set by parent
session_start();
$data=$_SESSION['_xfr'];
$doc_list=null;
foreach ($data['documents'] AS $doc)
{
if(ctype_alnum($doc['id']))
{
$file='/some/tmp/directory/'.$doc['id'];
if(!file_exists($file))
{
$url='http://machine.WebServer.com/index.php?task=displayDocument&id='.$doc['id'].'&x='.hash('sha256','displayDocument'.$doc['id'].'secretCodeWhichOnlyWebServerAndFaxServerKnow');
$cmd='wget -O '.$file.' '.escapeshellarg($url);
exec($cmd);
}
$doc_list.=' '.$file;
}
exit('invalid document');
}
//Send the fax...
//Send another CURL request to the WebServer similar to the wget giving the fax status.
exit;
When WebServer receives the wget request for a document, it confirms the hash and sends the document to the FaxServer using X-Sendfile.When WebServer receives the CURL request regarding status, it updates the database for the applicable message. Seem reasonably secure? i have made 2 classes. the first "point" has an array of 3 floats and some functions to help manipulate the values the second "triangle" has an array of 3 points. in this way if i want to make a tetrahedron i can make 4 points and assign them to 4 triangles. problem is for some reason each triangle point group seems to use 1k. any idea why? I have a .php code that gets data from a database and saves it in a variables as xml. However how can I then save all of the data in this variable as a .xml file somewhere? Thanks for any help. Hello, like I promised, I'm back with another problem. This one will be harder xD so squeeze your brain
Now I've got a webpage, with a database shown into a table, under that I've got page numbers. So I got my 20 rows for each page.
https://www.dropbox..../stillnotok.jpg
Great/awesome so far
Now I've got a new problem and it's hard for me to explain this too.
In my database I got allot of tables, in my webpage I'm using 2 of them, called 'artikel' and 'images".
Everything from my artikel table is ok. So we don't need to look at that.
But my problem is with the table 'images'.
In that table I got 2 items.
Like you will see in my code, I need the I_ARTCODE and I_FILE
in I_ARTCODE stands: 14 and for the other image 15
in I_FILE stands: 5.jpg and for the other image 6.jpg
With the code I've got now, I display the word 5.jpg and 6.jpg.
But I need to display the picture behind that, the person who gave me this task sayed, I normally can do this with the pad but it's not a real url, I'll give you guys a picture how my database looks like:
https://www.dropbox....uqplxd/path.jpg
Over here the pad is this: 000000-001000
It doesn't seems normal to me and I can't find a sollution for this on the internet.
Can someone plz help me?
Ooh ya, almost forgot, this is my code:
<?php
include('connect-mysql.php');
if (!empty($_GET["page"])) {
$page = $_GET["page"];
} else {
$page=1;
};
$start_from = ($page-1) * 20;
$sqlget = "SELECT *
FROM artikel, images
LIMIT $start_from, 20
";
$sqldata = mysqli_query($dbcon, $sqlget) or die('error getting');
echo "<table>";
echo "<tr><th>A_ARTCODE</th><th>A_NUMMER</th><th>A_OMSCHRN</th><th>A_REFLEV</th><th>A_WINKEL</th><th>I_ARTCODE</th><th>I_FILE</th></tr>";
while($row = mysqli_fetch_array($sqldata)){
echo "<tr><td align='right'>";
echo $row['A_ARTCODE'];
echo "</td><td align='left'>";
echo $row['A_NUMMER'];
echo "</td><td align='left'>";
echo $row['A_OMSCHRN'];
echo "</td><td align='left'>";
echo $row['A_REFLEV'];
echo "</td><td align='right'>";
echo $row['A_WINKEL'];
echo "</td><td align='right'>";
echo $row['I_ARTCODE'];
echo "</td><td align='right'>";
echo $row['I_FILE'];
//echo "<img src='000000-001000".$row['I_ID']."' />";
echo "</td></tr>";
}
echo "</table>";
$sql = "SELECT COUNT(A_ARTCODE) FROM artikel";
$rs_result = mysqli_query($dbcon, $sql) or die ("mysqli query dies");
$row = mysqli_fetch_row($rs_result) or die ("mysqli fetch row dies");
$total_records = $row[0];
$total_pages = ceil($total_records / 20);
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='index.php?page=".$i."'>".$i."</a> ";
};
?>
if you have the urls to pictures in a database how would you display the actual pictures on a webpage? Here 's the code. Code: [Select] <?php require_once("functions.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <style type="text/css"> td { border-top-style: solid; border-right-style: solid; border-bottom-style: solid; border-left-style: solid; border-top-color: #30C; border-right-color: #30C; border-bottom-color: #30C; border-left-color: #30C; } </style> </head> <body> <?php navBar(); echo "<form action=\"\" method=\"post\" name=\"catalog\">"; DatabaseConnection(); $query = "SELECT * FROM treats"; $result_set = mysql_query($query) or die(mysql_error()); $i = 0; echo "<table>"; while ($row = mysql_fetch_array($result_set)) { echo"<tr><td width=\"400px\">($row['product_pic']). <br />{$row['product_id']}.<br />{$row['product_title']}.<br /> {$row['product_Description']}.<br />{$row['product_price']}</td></tr>"; } echo "</table>"; ?> </form> </body> </html> Hi, i would like to know what is the best method to store a picture. Currently what happens, is each user has a different avatar, which when uploaded comes in a folder called Avatar, in my website folder and is also stored as a BLOB in mysql. I would like to know is this ok to store all avatars in one folder or some other step should be used and if so could some one guide me to a good tutorial. As I would also like to make an option, where people could upload their pictures, is it safe to store pictures in the same folder for all users or some how create a different folder for each user. Hi,
I have a crwal engine and every time when I try to take a picture from a specific website, it also take some bullshit from superfish, creating iframe and div class, that I can`t deleted using jquery after my page is load.
I was looking in my code and I found out that the only thing that trigger that is the <img src="<?php h(getPicture($itemRow['site'], if I remove 'site', I don`t see any other superfish code but also don`t see the picture. What can I do to take only the .jpg picture , without any of the other crap?
<?php for ($i = 0; $i < count($itemRow['pics']); $i++) { ?> Hi, I'm completely new to anything that is not html but I'm wondering if in something like php I can get a checkbox to permanently save through reloads and different machines. My idea was just to have a page with only a checkbox on it, and then load that through and iframe in html. If anybody could give me the code for that checkbox page (complete if possible as I don't really know anything about that type of programming) I would be very grateful. Thank You |
|||||||