PHP - Column Count Doesn't Match Value Count At Row 1 (prolly Easy, Im Just A Total No
Similar TutorialsHi guys, I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this: Code: [Select] www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp However i have got a error which i don't know how to fix it. Error: Column count doesn't match value count at row 1 <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbusername'); define('DB_PASSWORD', 'mydbpassword'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $adduser = clean($_GET['user1']); $email = clean($_GET['email']); $IP = clean($_GET['ip']); if($username == '') { $errmsg_arr[] = 'username is missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'PASSWORD is missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "The information have been updated."; } ?> Here's the name of the columns i have got in my database: Code: [Select] username IP I have input the correct columns names, so I can't correct the problem I am getting. Please can you help? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331562.0 Why am I getting this error when there are 3 Fields with 3 values? Column count doesn't match value count at row 1 Code: [Select] $sql5="INSERT INTO participants (participant_name, team_no, sport) VALUES ('".implode("','$_POST[team]'),('",$_POST['participant_name'])."','$_POST[team]','$sport')"; How to write this in a shorter way? I've got a set of results and I need to check them against another database results. If they both are similar then I want to make it as "1" (points). The questions and the answers are in the same order (Question1, Question2, Question3 = Answer1, Answer2, Answer3). sa I guess the maching could be done using a set of arrays. E.g. get records from db1 get records from db2 get records from dbY get records from dbX COUNT the matching data from db1 against dbY = echo TOTAL_SCORE1 COUNT the matching data from db2 against dbX = echo TOTAL_SCORE2 I've managed to get the data from the databases in order. But i need to get the COUNT of the MATCHING records. php \\Assume this is db1 $SomeVar = $_POST['sitting2']; $queryU = "SELECT * FROM adxone WHERE username = '".$SomeVar."'"; $resultU = mysql_query($queryU); $scoreU = mysql_fetch_assoc($resultU); $userRa1 = $scoreU['roundzAa']; $userRa2 = $scoreU['roundzAb']; $userRa3 = $scoreU['roundzAc']; $userRa4 = $scoreU['roundzAd']; $userRa5 = $scoreU['roundzAe']; $userRa6 = $scoreU['roundzAf']; $userRa7 = $scoreU['roundzAg']; $userRa8 = $scoreU['roundzAh']; \\ Assume this is dbY $WinVar = 'examinationA'; $query = "SELECT * FROM markacs WHERE roundx = '".$WinVar."'"; $result = mysql_query($query); $scoreM = mysql_fetch_assoc($result); $winRa1 = $scoreM['markwinxa']; $winRa2 = $scoreM['markwinxb']; $winRa3 = $scoreM['markwinxc']; $winRa4 = $scoreM['markwinxd']; $winRa5 = $scoreM['markwinxe']; $winRa6 = $scoreM['markwinxf']; $winRa7 = $scoreM['markwinxg']; $winRa8 = $scoreM['markwinxh']; /*need to match if $winRa1 = $userRa1, $winRa2 = $userRa2, etc.. then get the COUNT of the matching results*/ Hi, I want to let users upload multiple images to my online picture book, so after they press submit, HOW do I count the total $_FILES[someName]['name'] uploaded. I want to allow users to type in html form the total uploads they want and this will then display that many desired upload forms. I'm going to try count($_FILES[][]) and go from there first... Any help much appreciated! I can't get the COUNT of the matching results? Please help. $SomeVar = myname; $queryU = "SELECT * FROM adxone WHERE username = '".$SomeVar."'"; $resultU = mysql_query($queryU); while($scoreP = mysql_fetch_array($resultU)) { $scoreP['roundzAa']; $scoreP['roundzAb']; $scoreP['roundzAc']; $scoreP['roundzAd']; $scoreP['roundzAe']; $scoreP['roundzAf']; $scoreP['roundzAg']; $scoreP['roundzAh']; } $WinV = 'resultA'; $query = "SELECT * FROM acs WHERE resultx = '".$WinV."'"; $result = mysql_query($query); while($scoreUsr = mysql_fetch_array($result)) { $scoreUsr = $scoreM1['winxa']; $scoreUsr = $scoreM1['winxb']; $scoreUsr = $scoreM1['winxc']; $scoreUsr = $scoreM1['winxd']; $scoreUsr = $scoreM1['winxe']; $scoreUsr = $scoreM1['winxf']; $scoreUsr = $scoreM1['winxg']; $scoreUsr = $scoreM1['winxh']; } $count1 = count( array_intersect($resultU, $result) ); echo($count1); mysql_query("UPDATE comp SET id=$count1 WHERE username = '".$SomeVar."'"); ?> I'm printing some mysql results to a table and sometimes I have rows with no results so they never get counted... which results in an ugly looking parenthesis on my page with nothing it (). For these times, I'd like to print a zero. How can I rewrite the following to achieve this? Code: [Select] if($row['mycount'] does not exist) { $row['mycount'] = '0'; } Hi Everyone, I am working on implementing a blog comment system using the query below to display comments. My question is what is the best way to do a row count for the id column with this query or do I need to do a second db query to accomplish this? The purpose of this is to echo out the number of comments for that post, before displaying them. Any help is appreciated. Thanks in advance, kaiman <?php // get url variables $post_id = mysql_real_escape_string($_GET['id']); include ("../../scripts/includes/nl2p.inc.php"); // connects to server and selects database include ("../../scripts/includes/dbconnect.inc.php"); // table name $tbl_name3="blog_comments"; // select info from comments database $result3 = mysql_query ("SELECT count(*) FROM $table_name3 WHERE id='$post_id' ORDER BY id DESC LIMIT 1") or trigger_error("A mysql error has occurred!"); if (mysql_num_rows($result3) > 0 ) { while($row = mysql_fetch_array($result3)) { extract($row); // display number of comments // display date $row_date = strtotime($row['date']); putenv("TZ=America/Denver"); echo "<p class=\post\">On ".date('F, jS, Y', $row_date)." "; // display commenter name if($row['url'] == "") { echo $row['name']." wrote:</p>\n"; } else { echo "<a href=\"".$row['url']."\" target=\"_blank\">".$row['name']."</a> wrote:</p>\n"; } // display content $comments = $row['comment']; echo nl2p($comments); } } else { echo "<p class=\"large_spacer\">No Comments</p>"; } ?> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=320119.0 Hi everyone, Like the title says I need to count the amount of 1's in a column but I can't figure out how. Gr and thanx already Ryflex Anyone can help me? <?php $tbl_name="menu"; $kategorije = mysql_query("SELECT * FROM $tbl_name WHERE Left(menu_name, 1) BETWEEN 'A' AND 'M' ORDER BY menu_name ASC"); if (!$kategorije) { die("Database query failed: " . mysql_error()); } while ($row=mysql_fetch_array( $kategorije )) { echo "<div id=lista-header><h4>{$row["menu_name"]}</h4></div>"; $id_sub=$row['id_menu']; $podkategorije = mysql_query("SELECT * FROM submenu WHERE id_menu=$id_sub ORDER BY sub_name ASC", $connection); if (!$podkategorije) { die("Database query failed: " . mysql_error()); } echo "<ul class=\"pod\">"; while ($pod=mysql_fetch_array( $podkategorije )) { echo "<li><a href=index.php?=podkate?".$pod["id_sub"]." class=black>{$pod["sub_name"]}</a><hr size=1 align=left width=100px color=#cccccc></li>"; } echo "</ul>"; } ?> In this way, I get list with categories and hes subcategories. How to count how many subcategories have each categories, and count how many articles have each categories? Example (I wanna get this kind of look): Categories name (3) subcategoriesname (2) subcategoriesname (4) subcategoriesname (7) Categories name (5) subcategoriesname (1) subcategoriesname (14) subcategoriesname (9) subcategoriesname (2) subcategoriesname ( Categories name (2) subcategoriesname (28) subcategoriesname (17) Where the numbers represent how many categories and sub-items have articles returns -30. how can i remove the minus so it just returns 30 Code: [Select] $days = (strtotime(date("Y-m-d")) - strtotime($info['expiredate'])) / (60 * 60 * 24) echo $days Hello, I'm using the following code to count the amount of SQL results and divide it. Works great as is but I want to alter it so it works with categories. $amount = mysql_query('SELECT COUNT(`car_id`) AS num FROM `tbl_cars`') or die(mysql_error()); $amount_row = mysql_fetch_assoc($amount); I tried adding... WHERE car_cat = '".$cat."' which causes an error. Why doesn't this work, and how can I get the amount of results as a variable? Hello,
I am trying to get the report of my sales table. I want to get total number of leads for each month. And then i have to use this data to create graph using google graph.
But i am not getting how eactly i can get this.
Here is my code
<?php if(isset($_POST['submit'])) { $type = $_POST['type']; $sql="select * from leads where lead_customer='".$type."'"; $query=mysql_query($sql); while ($row = mysql_fetch_array($query)) { list($year,$month,$day)=explode("-", $row['last_modified']); $l = $row['last_modified']; $count=mysql_num_rows($month); echo $count; $myurl[] = "['".$month."', ".$count."]"; } print_r($myurl); echo implode(",", $myurl); } ?>But for $count, it doesn't show any values. below is my database. Capture.PNG 18.16KB 0 downloads Please suggest me hey i'm just woundering how i would go abouts on echoing unread messages sent to a user i want to beable to see how many unread messages i have Hey All, I need to count and display the number of rows I have. <?php //declare the SQL statement that will query the database $query = " SELECT COUNT(id) FROM connectvisits WHERE staffid = '$staffid' "; //execute the SQL query and return records $result = mssql_query($query); $thismonth = mssql_num_rows($result); echo "Total Meetings This Month: "; echo $thismonth; echo "<br />"; ?> For some reason I keep getting a result of 1. Everything else I try gives me a "Resource ID" number. Any help would be apprecaited. Maybe I have the completely wrong code. Thanks! Hi, I want the user to be able to go to one page and hit a button, once he hits the butten I want a count down to start from 10 minutes. When the user goes to the page within those 10 minutes, I want it to show him a live countdown until those ten minutes run out. Any ideas how I would go about doing this? I am printing question id and corect answers and incorrect one. Example: Questionid =8 Incorrect Incorrect Incorrect Correct Correct Incorrect This will be repeated for other question id. Now I would like to count total answers. In my example it will be 6. I would like to count the correct one so that will be 2. And print 2 as outcome. So far I have Code: [Select] $sqlll=questionid(); while($infoo = mysql_fetch_array( $sqlll)) { echo "<hr><br><strong>{$infoo['Que_ID']}</strong><br />\n"; $_Session1=$infoo['Que_ID']; $que=question($_Session1); while($infooo = mysql_fetch_array( $que)) { $answer1 = $infooo['Que_Answer1'] == $infooo['Ans_Answer1']; $answer2 = $infooo['Que_Answer2'] == $infooo['Ans_Answer2']; $answer3 = $infooo['Que_Answer3'] == $infooo['Ans_Answer3']; $answer4 = $infooo['Que_Answer4'] == $infooo['Ans_Answer4']; if ( $answer1 && $answer2 && $answer3 && $answer4) { echo ('<b><p style="color: green; text-align: left"> Correct </p></b>'); $scoree = $scoree + 1; } else { echo ('<br><b><p style="color: red; text-align: left"> Incorrect </p></b></br>'); $intt= $intt +1; } } Hey, having an odd issue, looking to show players whos within 25 ranks of them lower and higher, i'm unsure as to why the following code doesn't actually do it... would anyone care to explain... Code: [Select] <?php $score = $playerdata['score']; $sql = "SELECT * FROM `players` WHERE '$score' BETWEEN 25 AND 75 ORDER BY `score` DESC"; $query = mysql_query($sql) or die(mysql_error()); $i=0; while($players = mysql_fetch_array($query)) { $i++; ?> |