PHP - Some Sort Of Ecommerce System Help Needed
Hey, I am looking for an ecommerce system or just the way how to achieve the following. I am wanting to store some MP3 sound files in a folder called for example 'sounds' on my web server. I then want to be able to stream the files onto my web pages but then I also want people to be able to purchase them. This is where I get confused, how can I achieve this without letting people just be able to download the 'sounds' directory off my web server. I am wanting to do this using PHP obviously. Thanks in advance for help
Similar TutorialsI'm attempting to implement a simple social networking system but at the moment am confused about how to create a multiple query which will display a certain user's friends list. The database contains four tables, the two tables that I'm using at the moment at 'usersTable' and 'friendshipsTable' are detailed below. usersTable | Table that stores all the user data UserID | Default primary key Forename | Surname | Username | Password | Email Address | friendshipTable | Table that stores information about friendships between users FriendshipID | Default primary key userID_1 | UserID userID_2 | UserID Status | Either Pending or Confirmed. The user's id is parsed into the url, and then saved into a variable. blah.com/userprofile.php?id=6 $id = $_GET['id']; I am familiar with creating simple queries, but can't quite work out how to set up multiple table queries. What the query needs to do is to check the userID that is parsed with the url, and then check the friendshipsTable by checking if either the userID_1 or userID_2 field matches the userID to grab the records from the table where there is a match. The next step is to check to see if the friendship is 'Confirmed' or 'Pending' and if it is 'Pending' to ignore it. Once the records have then been chosen I need the query to then check the value in either userID_1 or userID_2 that doesn't match userID and then pull the user's username and name from the usersTable so it can be displayed on a webpage. I've no idea hoe much I may or may not be overcomplicating this, an example of the code that I've got so far for this query can be found below, but that's as far as I've got at the moment. $displayFriends = mysql_query("SELECT * FROM friendshipTable, usersTable WHERE friendshipTable.userID_1='$id' OR friendshipTable.userID_2='$id' "); Cheers for any help. I actually bought an E-Commerce app an the issue with it is the app process is very slow while opening and while jumping from one page to another its an admin panel web based app so i want to know IF there is a way to solve the issue by coding a line or two (Language used in the app and admin panel is "PHP') Here's the problem:
PayPal Payout Problem
1. My problem is on the page where Members Activation is being paid using the website custom currency which is Peso, where 45 Pesos equals to $1.
2. The membership fee is 50 Pesos or $1.06 USD. The page "fees.php" shows correct Peso amount (50 Pesos) with $1.06 USD as equivalent in dollars.
3. When clicked the checkout, it proceeds to the page "process_payment.php", then proceeds to PayPal page
4. The problem is that it does not convert to the correct $1.06 amount, but shows $50 on the PayPal page which is wrong.
*** The Product page, where customers makes a purchase, there's no problem because PayPal converts the money correctly to USD amount. I believe there's something wrong with the "process_payment.php" page but I cannot figure it out.
EDITED BY MODERATOR [code snipped]
Please help me figure out where the problem is. God bless.
Edited by Ch0cu3r, 31 May 2014 - 09:36 AM. I've been working on JSON and have found a way to send variables from the PHP to the JavaScript using AJAX and no JQuery. For an ecommerce site does it make more sense to send the variables : description, title, cost, etc. to the JavaScript page, or would it make more sense to echo the html on the PHP page? The idea, right now, is a product page for editing and deleting product. Thanks, Josh Edited December 22, 2020 by JoshEirHi All i am wanting a column list like this http://extensions.joomla.org/extensions basically the database is set up as (id, category, parent) I want the parent to group the category section and list like the the joomla example in three columns search various threads throughout the internet but none seem to cover this entirely can any one please help????? hello dear PHP-Fans - greetings to you - and a happy new year!! i set up a WAMP-System on my openSuse 11.4 system. In order to learn as much as i can bout PHP i want to do some tests and write some scripts. Well the WAMP is allready up and running. Now i try to give the writing access to the folder mkdir /srv/www/ where the php-scripts should go in... i want to give write permission to all to all files in /srv/www As root I generally: mkdir /srv/www/ chown <webmaster usrername> /srv/www/ /srv/www/ should be readable and traversable by all, but only writeable by it's owner (the user designated as the webmaster.) can i do this like mentioned above,... Love to hear from you greetings db1 Hello, I have a code which displays name and number. It is working now but I want to sort the content on the basis of number... The code is given below: while($rows = mysql_fetch_array($results)){ echo "". $rows['username'] ." ". $rows['COUNT(Completed_Sales)'] .""; echo "<br />"; } The result will look like this Name Prdoducts. Hello!If i have a table let's say ( Name, Age, Date etc ...), how can i do to sort data table DESC or ASC by clicking in Name, Age and then retrive the same page ( index.php let's say ) with sorted data? statez : I need to sort the results from the high score to the low score. $query = "SELECT statez, COUNT(statez)FROM distributors GROUP BY statez"; $results = mysql_query($query); $returnS=""; while($line = mysql_fetch_array($results)) { $returnS.= $line['COUNT(statez)'].",,".$line['statez'].",,,"; } echo $returnS; mysql_close($link); ?> Hello everyone, This is my first post and i have a question that im sure is easy to answer, im a beginner in PHP and i know how to submit a form and so on into mysql, now my question is, for everything i submit i would like for it to organize by date just like www.WorldStarHipHop.com, but not sure on how to do it. Any Clue? how do i get each indivual form i submit to automatically appear with the correct date untop? and how do i make the date appear untop of each section? Thanks for your time! I want to create a sort trigger, group by and order by on a table after insert. Should the trigger be of this nature create trigger triggername after insert on tablename for each row begin insert into table (column1, column2 ) values ( value1, value2) group by column1 order by column1 end; Hi all
Going to try and explain this as best as I can.
I currently have a query that sorts a list of records by number of points, then wins, 2nd places, 3rd places etc, the query is as follows
SELECT COUNT( `points` ) AS `rides`, SUM( `points` ) AS `pts`, SUM(IF(`points`=3,1,0)) AS `wins`, SUM(IF(`points`=2,1,0)) AS `2`, SUM(IF(`points`=1,1,0)) AS `1`, SUM(IF(`points`=0,1,0)) AS `0`, rider_name FROM tbl_heat WHERE card_id = 38 GROUP BY `rider_name` ORDER BY pts DESC, wins desc, `2` desc, `1` desc, `0` desc LIMIT 8this query has resulted in this result '5','15','5','0','0','0','Jaroslaw Hampel' SELECT domains_url, SUBSTRING(domains_url, 1, 1) AS letter FROM a INNER JOIN domains ON a_domain=domains_id ORDER BY letter ASC, domains_url ASCwhen I use this it will sort like hello-world.co.uk hello-zulu.co.uk hello.co.uk but I am hoping to get the hello first, any ideas please? Hello, i have a user entering dates in the format DD-MM-YYYY --> 11-12-02 when i try to sort by DESC [nearest date first] i am getting sort problems for example i'll get this.. 11-12-02 12-07-02 13-08-02 whats the best way to sort this to get the dates correct? Hey guys, I have got some events, and got it sorted by date, although at the moment the oldest date is showing first, and I would like to turn that around(new first old last), any simple suggestions? Also another little question how would I turn a date row (for example 2009/5/31) into Tuesday - May 2009 or something similar, anyone can point me into the right direction? ok so my problem is i need my data to be sorted by date which comes first.. how do i do it..can someone help me..if possible elaborate some codes? thxx.. so this is my program Code: [Select] <? $b=$_GET['b']; $m=$_GET['m']; $y=$_GET['y']; if ($b <> '' && $m <> '' && $y <> '') { $branch=$b; $leavemonth=$m; $leaveyear=$y; } else { $branch=$_POST['branch']; $leavemonth=$_POST['leavemonth']; $leaveyear=$_POST['leaveyear']; } $connection=mysql_connect("$server", "$username", "$password") or die("Could not establish connection"); mysql_select_db($database_name, $connection) or die ("Could not select database"); $query="SELECT * from tblworkgroup"; $result=mysql_query($query);?> Branch <select name="branch" > <option value="all">ALL Branches</option> <? while($row=mysql_fetch_array($result)) { ?> <option value= "<?=$row['WorkGroupID']?>" <? if ($branch==$row['WorkGroupID']){ echo 'selected'; } ?> ><?=$row['WorkGroupName']?></option> <? } ?> </select> </td> </tr> <br><br><br> Month <select name="leavemonth" > <option value = "1" <? if ($leavemonth==1){ echo 'selected'; } ?>>January</option> <option value = "2" <? if ($leavemonth==2){ echo 'selected'; } ?>>February</option> <option value = "3" <? if ($leavemonth==3){ echo 'selected'; } ?>>March</option> <option value = "4" <? if ($leavemonth==4){ echo 'selected'; } ?>>April</option> <option value = "5" <? if ($leavemonth==5){ echo 'selected'; } ?>>May</option> <option value = "6" <? if ($leavemonth==6){ echo 'selected'; } ?>>June</option> <option value = "7" <? if ($leavemonth==7){ echo 'selected'; } ?>>July</option> <option value = "8" <? if ($leavemonth==8){ echo 'selected'; } ?>>August</option> <option value = "9" <? if ($leavemonth==9){ echo 'selected'; } ?>>September</option> <option value = "10" <? if ($leavemonth==10){ echo 'selected'; } ?>>October</option> <option value = "11" <? if ($leavemonth==11){ echo 'selected'; } ?>>November</option> <option value = "12" <? if ($leavemonth==12){ echo 'selected'; } ?>>December</option> </select> Year <select name="leaveyear" > <option value = "2010" <? if ($leaveyear==2010) { echo 'selected';} ?>>2010</option> <option value = "2011" <? if ($leaveyear==2011) { echo 'selected';} ?>>2011</option> <option value = "2012" <? if ($leaveyear==2012) { echo 'selected';} ?>>2012</option> <option value = "2013" <? if ($leaveyear==2013) { echo 'selected';} ?>>2013</option> <option value = "2014" <? if ($leaveyear==2014) { echo 'selected';} ?>>2014</option> <option value = "2015" <? if ($leaveyear==2015) { echo 'selected';} ?>>2015</option> <option value = "2016" <? if ($leaveyear==2016) { echo 'selected';} ?>>2016</option> <option value = "2017" <? if ($leaveyear==2017) { echo 'selected';} ?>>2017</option> </select> <input type='submit' name='submit' value='Preview' Class="button" onclick='return validate()'> </div> </form> <br /><br /> <div id="box" valign="top"> <h3> <strong>Leave Application Details</strong>  </h3> <br><br> <table width="80%" align="center" > <thead> <tr> <th width="700px" align="left">Name</a></th> <th width="800px" align="center"></a>Application Date</th> <th width="500x" align="right"></a>Reason</th> </tr> </thead> <tbody> <? /*echo "branch:".$branch.'<br />'; echo "leavemonth:".$leavemonth.'<br />'; echo "leaveyear:".$leaveyear.'<br />';*/ //-------------------------------------------------- if ($leavemonth =='' || $leaveyear =='' || $branch == '') { // one value missing, so don't display } else { // start display data $branchtracker = ''; if ($branch=='all'){ $branch = '%'; } $rs = mysql_query( " call vwleavereport('$leavemonth', '$leaveyear', $branch, 0);"); $query="SELECT *, MONTH(tblleaveapplication.DateFrom) as DFMonth, MONTH(tblleaveapplication.DateTo) as DTMonth, YEAR(tblleaveapplication.DateFrom) as DFYear FROM `tblleaveapplication` LEFT JOIN `tblemployee` ON tblleaveapplication.employeeid = tblemployee.id WHERE WorkGroupID LIKE '".$branch."' AND ( (MONTH(tblleaveapplication.DateFrom)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.") OR (MONTH(tblleaveapplication.DateTo)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.") ) ORDER BY WorkGroupID "; $result = mysql_query($query); if ((mysql_num_rows($result))>0){ ?> <FORM name="printbutton" method="post" align="left" action="report_print.php" target="_blank"> <input type="hidden" name="leavemonth" value="<?php echo $leavemonth; ?>"> <input type="hidden" name="leaveyear" value="<?php echo $leaveyear; ?>"> <input type="hidden" name="branch" value="<?php echo $branch;?>"> <Input type = "Submit" Name = "Submit1" Class="button" VALUE = "Print Leave Details"> </form> <? while($row=mysql_fetch_array($result)) { if ($branchtracker<>$row['WorkGroupID']){ echo '<tr><td colspan=4 style="background-color: #e8e8e8; font-weight: bold;">'.$row['WorkGroupID'].'</td></tr>'; $branchtracker = $row['WorkGroupID']; } echo '<tr>'; echo '<td>'.$row['EmployeeName'].'</td>'; echo '<td>'.$row['DateFrom'].' - '.$row['DateTo'].'</td>'; echo '<td>'.$row['Purpose'].'</td>'; echo '</tr>'; } } } ?> Hi, I am reading a feed with this code foreach ($xml->channel->item as $item) { echo $item->title; echo '<br>'; } and outputs Code: [Select] title 1 title 2 title 3 .... and so on until 10 I wants in reverse order to output last rss feed first like: Code: [Select] title 10 title 9 title 8 .... and so on until 1, how can i do it? i tried with rsort($xml->channel->item) butt getting this error: Quote Warning: rsort() expects parameter 1 to be array, object given in Thanks for help Is there a simple way of sorting data like this? $string = " 50|1|0|15|1|1~ 13|2|0|15|1|1~ 50|3|0|15|1|0~ 19|1|2|10|0|0~ 19|2|2|10|0|0~ 22|4|2|10|0|0~ 22|3|2|10|0|0~ 19|5|2|10|0|0~ 1|6|2|10|1|0~ 19|6|1|10|1|1 "; I treat this data as a string, and create an array out of it as follows: $individuals = explode("~", $string); Then I can divide up each individual as follows: foreach ($individuals as $individual) { $individual = explode("|", $individual); } How can I write something that sorts this data by $individual[0], $individual[1], and $individual[2], respectively and in that order?? After sorting I should get the following: $string = " 1|2|10|0|0~ 13|2|0|15|1|1~ 19|2|1|10|0|0~ 19|5|2|10|0|0~ 19|6|1|10|1|0~| 19|6|2|10|1|1~ 22|3|2|10|0|0~ 22|4|2|10|0|0~ 50|1|0|15|1|1~ 50|3|0|15|1|0 "; Help? I have no idea how to write such a function. Thank you guys. hi, is there a way to sort by column a, then by column b? Hello. I have an object like this: object->object_id object->object_name object->object_number I have an array with many instances of the object, with different values. I want to sort that array to put first the object that the value of object->object_number is higher, and then descending. Please let me know if its not clear! thank you! |