PHP - Insert Random Pic Into This Script
i have got this script which displays all folders within a folder but what i want to do now is get it to display a random picture for each of the folders that it is showing in the grid. i know how to display a random image using array_rand() but i don't know how i would implement it.
Code: [Select] <form name="Gallery" method="post"> <?php $path = "gallery_files/gallery/"; $dir_handle = @opendir($path) or die("Unable to open folder"); echo "<table cellspacing='15'>"; echo "<tr>"; while (false !== ($folder = readdir($dir_handle))) { if($folder == "pictures.php") continue; if($folder == ".") continue; if($folder == "..") continue; echo ($x % 6 == 0) ? "</tr><tr>" : ""; echo "<td><a href='pictures/?folder=$folder'><img src='path/to/random/image' style='height:auto;width:110px;' alt='$folder'></a><br /><a href='pictures/?folder=$folder'>$folder</a></td>"; $x++; } echo "</tr>"; echo "</table>"; closedir($dir_handle); ?> </form> Similar TutorialsHi all, I have an issue with an image upload script. So far the script will upload the image to the server and rename it with a random 5 digit number on the end. I then INSERT this data into a table for sourcing the image later on. the only problem is that the data in the table is the image's original name not the new one. how do I get it to change that name too? Thanks. Code: [Select] <?php $idir = "uploads/"; // Path To Images Directory if (isset ($_FILES['fupload'])){ //upload the image to tmp directory $url = $_FILES['fupload']['name']; // Set $url To Equal The Filename For Later Use if ($_FILES['fupload']['type'] == "image/jpg" || $_FILES['fupload']['type'] == "image/jpeg" || $_FILES['fupload']['type'] == "image/pjpeg") { $file_ext = strrchr($_FILES['fupload']['name'], '.'); // Get The File Extention In The Format Of , For Instance, .jpg, .gif or .php $copy = copy($_FILES['fupload']['tmp_name'], $idir. basename($_FILES['fupload']['name'], $file_ext).rand(10000 , 99999).$file_ext); // Move Image From Temporary Location To Perm } } error_reporting (E_ALL ^ E_NOTICE); $usr = "user"; $pwd = "pword"; $db = "db"; $host = "host"; # connect to database $cid = mysql_connect($host,$usr,$pwd); if (!$cid) { echo("ERROR: " . mysql_error() . "\n"); } if ($_POST['submit']) { $logo = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); $SQL = " INSERT INTO mhhire "; $SQL .= " (logo) VALUES "; $SQL .= " ('$logo') "; $result = mysql_db_query($db,$SQL,$cid); $last=mysql_insert_id(); if (!$result) { echo("ERROR: " . mysql_error() . "\n$SQL\n"); } header("location:thanks.php"); exit(); } ?> Hi, I'm a researcher (and complete coding noob), and am planning a longitudinal study that requires e-mail follow-up with subjects taking an initial survey. For purposes of ethics/anonymity due to sensitive survey data, I'd like the acquired e-mails to be saved uncoupled from the survey responses; this is simple to deal with, and I use a basic PHP e-mail form, which injects the email address in a table in MySQL in a different server than the one used for the survey. The issue is that the e-mails are saved in the MySQL database in order of injection, thus it is still theoretically possible for me to link the e-mails back to the survey responses (which have a time stamp that I cannot remove). Ideally I would like not to be able (at all) to link the e-mails to the survey responses, and one way to do that (since I don't save the e-mail injection timestamps in MySQL) might be to have the e-mails saved in MySQL in a random order. Not sure if this is possible, and not even sure if this would be via PHP or MySQL side of things. The server is on godaddy and uses Starfield interface for MySQL but I cannot find an option for random insert/saving of table items (emails). They are saved in order of injection. Any solution for this? Thanks, Hi i have this upload script which works fine it uploads image to a specified folder and sends the the details to the database. but now i am trying to instead make a modify script which is Update set so i tried to change insert to update but didnt work can someone help me out please this my insert image script which works fine but want to change to modify instead Code: [Select] <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("upload") or die(mysql_error()) ; // my file the name of the input area on the form type is the extension of the file //echo $_FILES["myfile"]["type"]; //myfile is the name of the input area on the form $name = $_FILES["image"] ["name"]; // name of the file $type = $_FILES["image"]["type"]; //type of the file $size = $_FILES["image"]["size"]; //the size of the file $temp = $_FILES["image"]["tmp_name"];//temporary file location when click upload it temporary stores on the computer and gives it a temporary name $error =array(); // this an empty array where you can then call on all of the error messages $allowed_exts = array('jpg', 'jpeg', 'png', 'gif'); // array with the following extension name values $image_type = array('image/jpg', 'image/jpeg', 'image/png', 'image/gif'); // array with the following image type values $location = 'images/'; //location of the file or directory where the file will be stored $appendic_name = "news".$name;//this append the word [news] before the name so the image would be news[nameofimage].gif // substr counts the number of carachters and then you the specify how how many you letters you want to cut off from the beginning of the word example drivers.jpg it would cut off dri, and would display vers.jpg //echo $extension = substr($name, 3); //using both substr and strpos, strpos it will delete anything before the dot in this case it finds the dot on the $name file deletes and + 1 says read after the last letter you delete because you want to display the letters after the dot. if remove the +1 it will display .gif which what we want is just gif $extension = strtolower(substr($name, strpos ($name, '.') +1));//strlower turn the extension non capital in case extension is capital example JPG will strtolower will make jpg // another way of doing is with explode // $image_ext strtolower(end(explode('.',$name))); will explode from where you want in this case from the dot adn end will display from the end after the explode $myfile = $_POST["myfile"]; if (isset($image)) // if you choose a file name do the if bellow { // if extension is not equal to any of the variables in the array $allowed_exts error appears if(in_array($extension, $allowed_exts) === false ) { $error[] = 'Extension not allowed! gif, jpg, jpeg, png only<br />'; // if no errror read next if line } // if file type is not equal to any of the variables in array $image_type error appears if(in_array($type, $image_type) === false) { $error[] = 'Type of file not allowed! only images allowed<br />'; } // if file bigger than the number bellow error message if($size > 2097152) { $error[] = 'File size must be under 2MB!'; } // check if folder exist in the server if(!file_exists ($location)) { $error[] = 'No directory ' . $location. ' on the server Please create a folder ' .$location; } } // if no error found do the move upload function if (empty($error)){ if (move_uploaded_file($temp, $location .$appendic_name)) { // insert data into database first are the field name teh values are the variables you want to insert into those fields appendic is the new name of the image mysql_query("INSERT INTO image (myfile ,image) VALUES ('$myfile', '$appendic_name')") ; exit(); } } else { foreach ($error as $error) { echo $error; } } //echo $type; ?> Hello, I have been using a random text script to display a useful tip to the user when they land on a certain page. This is how the script looks: Code: [Select] <?php $random_text = array("This is an example tip", "This is another example of a tip", "And another...", "And one more"); $sizeof = count($random_text); $random = (rand()%$sizeof); print("$random_text[$random]"); ?> At the moment the tip will display randomly everytime the page is loaded. Is there any way I can add a small button that says "Give me another" or something, so that when they click it another random fact will come out? If possible I would like to avoid them having to reload the page everytime. Any help is greatly appreciated. Hi, I am wanting to create a random fact script for a small website project. The idea is when the user loads a page a random fact will appear at the top ( I guess from an array of strings I will make?) Can anyone recommend the most efficient and easiest way to go about this please? I'm new to PHP/MySQL and have been searching high and low for a solution to this... When using my PHP script to insert a row into the database it errors out but does not give me a specific error. When I use the MySQL command line client I can insert the first, second, third, or any number of rows without a problem. What I don't understand is, once I have inserted a row using the command line client, my PHP script will insert rows without issue. So my question is, what is it about the first row being inserted that makes it so special? One of the columns in the table is an AUTO_INCREMENT field, so i'm guessing that has something to do with it? I've used this on like three other scripts I don't know why it won't insert now <?php date_default_timezone_set('America/Los_Angeles'); $timestamp = date('H:m:s m.d'); $admin = '24.68.214.97'; $visitor_ip = $_SERVER['REMOTE_ADDR']; $host="mysql"; // Host name $username="15557_test"; // Mysql username $password="**********"; // Mysql password $db_name="15557_test"; // Database name $tbl="announce"; // Table name mysql_connect("$host", "$username", "$password")or die("cannot connect to server"); mysql_select_db("$db_name")or die("cannot select DB"); $body = $_POST["body"]; if ($visitor_ip == $admin) { mysql_query("INSERT INTO $tbl (body, date) VALUES ('$body', '$timestamp')"); //right here, i can echo $body and see what I wrote, but I can't insert into $tbl } else { die("no"); } ?> <meta http-equiv="REFRESH" content="0;url=http://testchan.dcfilms.org/board-b.php"> Hello, I'm trying to write my first database using SQL and PHP, without much luck, I'm afraid. After inserting a new record (for which I didn't have a problem), I wanted to automatically generate a username which is the person's first name (they'll then be able to change it later). Trying to use Dreamweaver as a model, I've come up with this: $updateSQL = sprintf("UPDATE users SET username=%s", GetSQLValueString($_POST['first_name'], "text")) Well...it does update the username, but it does so on ALL of the records as opposed to the one that was just inserted. Any help would be appreciated... Thank you. Well the subject line is pretty explicit. I found this script that uploads a picture onto a folder on the server called images, then inserts the the path of the image on the images folder onto a VACHAR field in a database table. Code: [Select] <?php //This file inserts the main image into the images table. //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user //Start session session_start(); //Connect to database require ('config.php'); //Check whether the session variable id is present or not. If not, deny access. if(!isset($_SESSION['id']) || (trim($_SESSION['id']) == '')) { header("location: access_denied.php"); exit(); } else{ // Check to see if the type of file uploaded is a valid image type function is_valid_type($file) { // This is an array that holds all the valid image MIME types $valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif"); if (in_array($file['type'], $valid_types)) return 1; return 0; } // Just a short function that prints out the contents of an array in a manner that's easy to read // I used this function during debugging but it serves no purpose at run time for this example function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } // Set some constants // This variable is the path to the image folder where all the images are going to be stored // Note that there is a trailing forward slash $TARGET_PATH = "images/"; // Get our POSTed variable $image = $_FILES['image']; // Sanitize our input $image['name'] = mysql_real_escape_string($image['name']); // Build our target path full string. This is where the file will be moved to // i.e. images/picture.jpg $TARGET_PATH .= $image['name']; // Make sure all the fields from the form have inputs if ( $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: member.php"); exit; } // Check to make sure that our file is actually an image // You check the file type instead of the extension because the extension can easily be faked if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: member.php"); exit; } // Here we check to see if a file with that name already exists // You could get past filename problems by appending a timestamp to the filename and then continuing if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: member.php"); exit; } // Lets attempt to move the file from its temporary directory to its new home if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); header("Location: images.php"); echo "File uploaded"; exit; } else { // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to // Make sure you chmod the directory to be writeable $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: member.php"); exit; } } //End of if session variable id is not present. ?> The script seems to work fine because I managed to upload a picture which was successfully inserted into my images folder and into the database. Now the problem is, I can't figure out exactly how to write the script that displays the image on an html page. I used the following script which didn't work. Code: [Select] //authenticate user //Start session session_start(); //Connect to database require ('config.php'); $sql = mysql_query("SELECT* FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main' "); $row = mysql_fetch_assoc($sql); $imagebytes = $row['image']; header("Content-type: image/jpeg"); print $imagebytes; Seems to me like I need to alter some variables to match the variables used in the insert script, just can't figure out which. Can anyone help?? Hi Guys, having one of them "why wont it work" nightmares whilst doing some updates on a web page someone else has coded, its a simple php and mysql insert string that has some validation on but no matter what I do it wont add a new property, it updates fine, i have only added three new fields to the original source files, property_county, property_size, property_status, it should have been a simple job but has got me stumped, anyone got any suggestions? The script uses three files, properties.php - which is the page which holds the form class.properties.php - which contains the functions - this is where i think the problem is.... and property_form.php - which is just the form, this is fine, just the above two that seem to be causing the problem!! any suggestions would be greatly appreciated. Thanks Matt Hello, I am very new to both PHP and MYSQL but I am eager to learn. What I want to do is write a PHP script that will parse an XML file and insert the results into a MYSQL database. I've read a bunch of guides online and I think I have the parser structure down. I created a parser using xml_parser_create(). As I understand it, I need to create functions to handle each of the three events, startTag, endTag, and contents. This is where I am not sure what to do. What do I need to tell these functions to do when these events are triggered? I know I need to connect to the MYSQL database at some point but I do not know when. If anyone could point me in the right direction, I'd appreciate it. Hi all, I am managing a social network and am creating a script to allow the admin to private message all users on the site. Even setting the max execution time to unlimited within the file does not allow us to insert all 40,000 rows into the 'message' table, it stops after several thousand rows. Our hosts tell us setting this globally is a bad idea/unstable. Does anyone have some advice on the best to do this? No email notifications need to be sent so it is purely allowing the script to run it's full course without stopping. I did consider a cron job but without emails doing in 'batches' seems a bit unecessary so I'm clearly missing something. ANy and all advice would be most welcome! Richard The code.... very simple: $punc_body = explode(". ", $body); foreach ($punc_body as $k => $v) { $v = ucfirst($v); echo $v . "<br>"; // this is only here for testing purposes. } $body = implode(". ", $punc_body); Why doesn't this work? I threw in the echo $v in which it shows that it is doing everything properly, however when I implode the array everything that was capitalized is reverted back to lower-case. Can someone tell me whats wrong or what I'm missing here please. I have a php script that I've been running that seems to have been working but now I'm wondering if some of my logic is potentially off. I select records from a db table within a date range which I put into an array called ```$validCount``` If that array is not empty, that means I have valid records to update with my values, and if it's empty I just insert. The trick with the insert is that if the ```STORES``` is less than the ```Quantity``` then it only inserts as many as the ```STORES``` otherwise it inserts as many as ```Quantity```. So if a record being inserted with had Stores: 14 Quantity:12
Then it would only insert 12 records but if it had It would only insert 1 record. In short, for each customer I should only ever have as many valid records (within a valid date range) as they have stores. If they have 20 stores, I can have 1 or 2 records but should never have 30. It seems like updating works fine but I'm not sure if it's updating the proper records, though it seems like in some instances it's just inserting too many and not accounting for past updated records. This is the logic I have been working with:
if(!empty($validCount)){ for($i=0; $i<$row2['QUANTITY']; $i++){ try{ $updateRslt = $update->execute($updateParams); }catch(PDOException $ex){ $out[] = $failedUpdate; } } }else{ if($row2["QUANTITY"] >= $row2["STORES"]){ for($i=0; $i<$row2["STORES"]; $i++){ try{ $insertRslt = $insert->execute($insertParams); }catch(PDOException $ex){ $out[] = $failedInsertStore; } } }elseif($row2["QUANTITY"] < $row2["STORES"]){ for($i=0; $i<$row2["QUANTITY"]; $i++){ try{ $insertRslt = $insert->execute($insertParams); }catch(PDOException $ex){ $out[] = $failedInsertQuantity; } } } }
Let's say customer 123 bought 4 of product A and they have 10 locations
customerNumber | product | category | startDate | expireDate | stores Because they purchased less than their store count, I insert 4 records. Now if my ```$validCheck``` query selects all 4 of those records (since they fall in a valid date range) and my loop sees that the array isn't empty, it knows it needs to update those or insert. Let's say they bought 15 this time. Then I would need to insert 6 records, and then update the expiration date of the other 9 records.
customerNumber | product | category | startDate | expireDate | stores There can only ever be a maximum of 10 (store count) records for that customer and product within the valid date range. As soon as the row count for that customer/product reaches the equivalent of stores, it needs to now go through and update equal to the quantity so now I'm running this but it's not running and no errors, but it just returns back to the command line $total = $row2['QUANTITY'] + $validCheck; if ($total < $row2['STORES']) { $insert_count = $row2['QUANTITY']; $update_count = 0; } else { $insert_count = $row2['STORES'] - $validCheck; // insert enough to fill all stores $update_count = ($total - $insert_count); // update remainder } for($i=0; $i<$row2['QUANTITY']; $i++){ try{ $updateRslt = $update->execute($updateParams); }catch(PDOException $ex){ $failedUpdate = "UPDATE_FAILED"; print_r($failedUpdate); $out[] = $failedUpdate; } } for($i=0; $i<$insert_count; $i++){ try{ $insertRslt = $insert->execute($insertParams); }catch(PDOException $ex){ $failedInsertStore = "INSERT_STORE_FAILED!!!: " . $ex->getMessage(); print_r($failedInsertStore); $out[] = $failedInsertStore; } }```
As above, I have a lottery style site that picks a random number between 1-8 but my users complain for some reason that this is not enough. So i was told to look into using fopen and random.org to generate a random number. Anyone have experience of this and perhaps a code snippet for me to look at and possibly use? help will be appreciated. Hello. I am working on a php script for searching a database table. I am really new to this, so I used the this tutorial http://www.phpfreaks.com/tutorial/simple-sql-search I managed to get all the things working the way I wanted, except one important and crucial thing. Let me explain. My table consist of three columns, like this: ID(bigint20) title(text) link (varchar255) ============================= ID1 title1 link-1 ID2 title2 link-2 etc... Like I said, I managed to make the script display results for a search query based on the title. Want I want it to do more, but I can't seem to find the right resource to learn how, is to place a "Download" button under each search result with its corresponding link from the table. Here is the code I used. <?php $dbHost = 'localhost'; // localhost will be used in most cases // set these to your mysql database username and password. $dbUser = 'user'; $dbPass = 'pass'; $dbDatabase = 'db'; // the database you put the table into. $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error()); mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error()); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 3) { $error[] = "Search terms must be longer than 3 characters."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT title, link FROM db WHERE title LIKE '%{$searchTermDB}%'"; $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } ?> <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?> <form method="GET" action="search?" name="searchForm"> Search for title: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" /> <input type="submit" name="submit" value="Search" /> </form> <?php echo (count($results) > 0)?"Rezultate lucrari de licenta sau disertatie pentru {$searchTerms} :<br /><br />" . implode("", $results):""; ?> $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; I would like the results to be displayed like this Results for SearchItem: Result 1 Download | Other link Result 2 Download | Other link etc.... or something like this. So, how do I add the data from the link row into a text(Dowload), within an <a href> tag (well, at least I guess it would go this way) ? My first tries (fueled by my lack of knowledge) where things like $results[] = "{$row['title']}<br /> <a href="{$row['link']}">Download</a> <br /> "; but I keep getting lots of errors, and then I don't know much about arrays and stuff (except basic notions); So there it is. I am really stuck and can't seem to find any workaround for this. Any suggestions? (examples, documentation, anything would do, really) Thanks, Radu Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; I'm missing something here. I have a form, and when the submit is pressed, the relevant post data inserts into table one, then I want the last insert id to insert along with other form data into a second table. The first table's still inserting fine, but I can't get that second one to do anything. It leapfrogs over the query and doesn't give an error. EDIT: I forgot to add an error: I get: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'usage, why VALUES ('14', '', '123', '','1234', '', '')' at line 1 query:INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('test 14', 'asdfa', 'asdf', 'adf','asdf', '', '', '', '123', '', '') Code: [Select] if (empty($errors)) { require_once ('dbconnectionfile.php'); $query = "INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('$description12', '$sn', '$description4', '$cne','$description5', '$description6', '$description7', '$description8', '$description9', '$description10', '$description11')"; $result = @mysql_query ($query); if ($result) { $who_donated=mysql_insert_id(); $query2 = "INSERT INTO tbl_donation (donor_id, donor_expyear, donor_cvv, donor_cardtype, donor_authorization, amount, usage, why) VALUES ('$who_donated', '$donate2', '$donate3', '$donate4','$donate5', '$donate6', '$donate7')"; $result2 = @mysql_query ($query2); if ($result2) {echo "Info was added to both tables! yay!";} echo "table one filled. Table two was not."; echo $who_donated; //header ("Location: http://www.twigzy.com/add_plant.php?var1=$plant_id"); exit(); } else { echo 'system error. No donation added'; Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks I know this is not coding.. However... How tolerant is PHP from generating a random output from 1000s of entry columns in a mysql database. I would like to make a script that would potentially pick one of a 1000 results at random. is this a problem with being ran multiple times? |