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PHP - How Can I Put This Code Into A Variable?
I have a option in my profile settings for users to beable to "hide" there friends list
this si my code to show there friends on there profile Code: [Select] $this->to_print .= <<< LOL <fieldset><legend>$Friends</legend> <div class="padding4"> $Friends2 LOL; while( $r = $DB->fetch_row() ){ if ( $r['last_activity'] > (time() - 900) ) $r['status'] = "<span style=float:right;><span class=desc4><b>Online</b></span></span>"; else $r['status'] = "<span style=float:right;><span class=desc4>Offline</span></span>"; $column++; if ($ibforums->member['settings']['2'] or (!$ibforums->member['id'])){ $color = "{$r['color']}"; $colors = explode(",", $color); if ( strpos($_SERVER['HTTP_USER_AGENT'], 'MSIE') ){ { $r['color'] = ($r['color']) ? "style=\"padding:1px 1px 1px 2px;color:#{$colors[0]};filter:Glow(color=#{$colors[1]},strength=3)\"":""; } }else{ $r['color'] = ($r['color']) ? "style=\"color:#{$colors[0]};text-shadow:#{$colors[1]} 2px 1px 1px\"":""; } } $test = explode(";", $info['pdata']); $r['avatar'] = ($r['avatar']) ? "<img src={$r['avatar']} width=64 height=64>" : ""; $r['star'] = ($r['star']) ? "<img class=top3 src=style_images/1/icons/{$r['star']}.png>":""; $r['name'] = "<a href=?i={$r['friendid']}>{$r['name']}{$r['star']}</a>"; $this->to_print .= <<< LOL <dl class="LOL LEFT flm" style="margin-right:5px"><dt2>{$r['name']}</dt2><dd class=padding4>{$r['avatar']}<div class="RIGHT">{$r['status']}</div></dd></dl> LOL; } $this->to_print .= <<< LOL </div> </fieldset> now I will be using this code to make it hidden based on a variable (they set in there settings) Code: [Select] //Hide Friends if ($display[0] == "1"){ $friend = ""; }else{ $friend = 'show that function here above code'; } how can I pull all that info into my $friend variable to make it easy? See then I could just echo out $friend and it will show that code above, or not (if they hidden it in settings)? Help ty Similar TutorialsHey Everyone, I writing on here because I am taking a course on PHP and learning it by using the textbook PHP 6 Fast & Easy Web Development by Julie Meloni and came across a problem on an assignment that I dont know how to fix. Any who, in the assignment I was working on I wrote a script that shows data I have in a table in my broswer (which btw works) BUT it always gives me the following message: Notice: Undefined variable: display_block in 127.0.0.1\sel_byid.php on line 29. I have checked my code over and and am sure I copied it right but still get the notice. Here's the code: Code: [Select] <?php $db_name = "testDB"; $table_name = "my_music"; $connection = @mysql_connect("localhost", "brenda", "mouse") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT * FROM $table_name ORDER BY title"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while($row = mysql_fetch_array($result)) { $id = $row['id']; $format = $row['format']; $title = stripslashes($row['title']); $artist_fn = stripslashes($row['artist_fn']); $artist_ln = stripslashes($row['artist_ln']); $rec_label = stripslashes($row['rec_label']); $my_notes = stripslashes($row['my_notes']); $date_acq = $row['date_acq']; if($artist_fn != "") { $artist_fullname = trim("$artist_fn $artist_ln"); }else{ $artist_fullname = trim("$artist_ln"); } if($date_acq == "0000-00-00") { $date_acq = "[unknown]"; } $display_block .= "<P><strong>$id. $title</strong>on $rec_label, by $artist_fullname<br>$my_notes<em>(acquired: $date_acq, format: $format)</em></P>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>My Music (Ordered by Title)</title> </head> <body> <H1>My Music: Ordered by Title</H1> <?php echo "$display_block"; ?> <P><a href="my_menu.html">Return to Menu</a></P> </body> </html> I've been trying to fix it for like a week now and the only thing I understand from the notice is that this line: Code: [Select] $display_block .= "<P><strong>$id. $title</strong>on $rec_label, by $artist_fullname<br>$my_notes<em>(acquired: $date_acq, format: $format)</em></P>"; is trying to concatentate to a variable which does not exist ($display_block) and I dont know how to fix it... Can anyone help me? Hey guys im making a PHP page using PHP So i have this ##################################################### # Make the PHP page # ##################################################### $PHPCode = " <?php //Title of page used to select the correct record from the database $Title = '".$Name."'; //Use the database information stored in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/Lighthouses-Database-Connection-Information.php'); //Take the information from the database using the method in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/Retrieve-Information.php'); //Process the information using the methods in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/Processing.php'); //Use the layout HTML held in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/PageCode-Lighthouse-Information-Page.php'); //Display the page code made. Resulting in the page displayed. echo $pagecode; ?> "; However, i keep getting syntax errors, possibly due to the fullstops. How shall i get round this?! Danny <?php $pageTitle='Edit Profile'; require_once ("header.php"); ?> How can I pass a variable like that through header.php? I know it doesn't work the way I have it. Hi a get a server error with this code, this worked for awhile, now it doesn't work. I use the first part to extract the user name from the url. then parse it to the IF cookie function as a variable for the cookie name. The cookie is placed on another html page and i placed it like this: <script language="javascript"> document.cookie = "{PROFILE_USERNAME}= 1"; </script> // this code works perfectly i used php to parser the variable to the javascript function, when i check the browser for cookies, it is placed correctly. this code i use to check the cookie's name to see if it exists. the variable below is taken from the url, and matches the username above, but when i execute the code i get this error: Illegal variable _files or _env or _get or _post or _cookie or _server or _session or globals passed to script. can anyone see the problem? <?php $url = $_SERVER['SCRIPT_FILENAME']; $newurl = explode("/", $url); $profmanager=$newurl[6]; $cook= $profmanager; if(!isset($_COOKIE['$cook'])) { $url2 = $_SERVER['HTTP_HOST']; $myurls = 'http://'.$url2.'/'; echo "<META HTTP-EQUIV=Refresh CONTENT=\"0;URL=$myurls\">"; } else { my page code here }?> // to note when i echo the $newurl[6] it does equal the username. the first code in on a html page/the javascript above, // the second code piece is AT THE TOP of a php page. // if there is a better way, liike matching values instead of the cookie name, i would be keen to see it in action. So what i mean is if i set a variable to "[" ($some_variable = "[") the rest of my code is now going to go CRAZY because there is an open [. Is there a way I can just make everything inside the first set of "" not relevant to the code? thanks! Hi All, I'm having a major mind blank, and can't find anything in the previous posts resolving what I'm after. I'm setting $searchtext = $_POST['searchtext']; I want to check $seachtext is not null. I've seen isset($searchtext) but it doesn't solve my problem. Basiclaly; I want an if statement to say if(isset($searchtext)) {......} Thoughts? Dear Friends I want to execute a php code when my session has been destroy or demoinshed, I need a help regarding this kindly help me. Best Regards Habib User clicks on a url, ie: example.com/AEQ438J When I perform this in the code below: Code: [Select] $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly as "AEQ438J" if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } // this also updates the database correctly as it should if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK. It should display "AEQ438J"! ..... $referrer displays correctly BEFORE if($_POST['form']), however during the if($_POST['form']) $referrer is empty. How can I fix my code so that $referrer is not empty during the time the user posts their email address in the form? Thank you! Complete PHP and HTML Code: [Select] <?php require "includes/connect.php"; //var_dump($_GET);die; function gen_code($codeLen = 7) { $code = ''; for ($i=0; $i<$codeLen; $i++) { $d=rand(1,30)%2; $code .= $d ? chr(rand(65,90)) : chr(rand(48,57)); } return $code; } function add_code($email_id) { global $mysqli; $code = gen_code(7); $mysqli->query("UPDATE coming_soon_emails SET code='" . $code ."' WHERE email_id='" . $email_id . "'"); if($mysqli->affected_rows != 1) { add_code($email_id); } else return $code; } $msg = ''; $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('This email already exists in the database.'); } else { $email_code = add_code($mysqli->insert_id); } $msg = "http://www.example.com/" . $email_code; //the following doesn't work as referrer is now empty :( if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET signup = signup + 1 WHERE code='" . $referrer ."'"); } if($ajax){ die(json_encode(array('msg' => $msg))); } } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } ?> <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> <link rel="stylesheet" type="text/css" href="css/styles.css" /> </head> <body> <div id="launch"> <form id="form" method="post" action=""> <input type="text" id="email" name="email" value="<?php echo $msg;?>" /> <input type="submit" value="Submit" id="submitButton" /> </form> <div id="invite"> <p style="margin-top:20px;">The ID of who referred you: <?php echo $referrer; //this displays correctly?>)</p> <p style="margin-top:20px;"><span id="code" style="font-weight:bold;"> </span></p> </div> </div> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script> <script src="js/script.js"></script> </body> </html> script.js Code: [Select] $(document).ready(function(){ // Binding event listeners for the form on document ready $('#email').defaultText('Your Email Address'); // 'working' prevents multiple submissions var working = false; $('#form').submit(function(){ if(working){ return false; } working = true; $.post("./index.php",{email:$('#email').val()},function(r){ if(r.error){ $('#email').val(r.error); } else { $('#email').val(r.msg); // not needed but gets hidden anyways... $('#launch form').hide(); $("#code").html(r.msg); $("#invite").fadeIn('slow'); } working = false; },'json'); return false; }); }); // A custom jQuery method for placeholder text: $.fn.defaultText = function(value){ var element = this.eq(0); element.data('defaultText',value); element.focus(function(){ if(element.val() == value){ element.val('').removeClass('defaultText'); } }).blur(function(){ if(element.val() == '' || element.val() == value){ element.addClass('defaultText').val(value); } }); return element.blur(); } htaccess Code: [Select] RewriteEngine on RewriteCond %{HTTP_HOST} ^my-url.com RewriteRule (.*) http://www.my-url.com/$1 [R=301,L] RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^([a-z0-9]+)$ /index.php?_url=$1 [NC,L,QSA] table.sql Code: [Select] CREATE TABLE IF NOT EXISTS `coming_soon_emails` ( `email_id` int(11) NOT NULL auto_increment, `email` varchar(64) collate utf8_unicode_ci NOT NULL, `code` char(7) collate utf8_unicode_ci DEFAULT NULL, `clicks` int(64) collate utf8_unicode_ci DEFAULT 0, `signup` int(64) collate utf8_unicode_ci DEFAULT 0, `ts` timestamp NOT NULL default CURRENT_TIMESTAMP, PRIMARY KEY (`email_id`), UNIQUE KEY `email` (`email`), UNIQUE KEY `code` (`code`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; Dear Friends, I am alot before doing the mixed content of php and HTML in single variable in PHP.. I could not get the data even though there is not SYNTAX error.. please look my code and advise
$htmlcontent .="
<tr>
<td colspan=\"8\">".$details."></td>
</tr>";
for($k=0;$k<count($reg_years[$details]);$k++) {
$year = (int)($reg_years[$details][$k]);
$singlecount[$year] = array_filter($result[$details],function($details1) use ($year){
return ($details1['reg_year'] == $year && $details1['bench_type'] == 1);
});
$divisioncount[$year] = array_filter($result[$details],function($details2) use ($year){
return ($details2['reg_year'] == $year && $details2['bench_type'] == 2);
});
$fullcount[$year] = array_filter($result[$details],function($details3) use ($year){
return ($details3['reg_year'] == $year && $details3['bench_type'] >= 3);
});
$rpcount[$year] = array_filter($result[$details],function($rp) use ($year){
return ($rp['reg_year'] == $year && $rp['bench_type'] == 'RP');
});
$mjccount[$year] = array_filter($result[$details],function($mjc) use ($year){
return ($mjc['reg_year'] == $year && $mjc['bench_type'] == 'MJC');
});
$cocount[$year] = array_filter($result[$details],function($co) use ($year){
return ($co['reg_year'] == $year && $co['bench_type'] == 'X');
});
$total = 0;
$total = (int)(count($singlecount[$year])+count($divisioncount[$year])+count($fullcount[$year])+count($rpcount[$year])+count($mjccount[$year])+count($cocount[$year]));
$htmlcontent .="
<tr>
<td>".$year."</td>
<td align=\"center\">
if(count($singlecount[$year])>0) {
echo (count($singlecount[$year]));
}
else {
echo "-";
}
</td>
<td align=\"center\">
if(count($divisioncount[$year])>0) {
".count($divisioncount[$year])."
} else {
"-"
}
</td>
<td align=\"center\">
if (count($fullcount[$year]) > 0)
{
echo (count($fullcount[$year]));
}
else
{
echo "-";
} </td > < td align =\"center\">
if(count($rpcount[$year])>0) {
echo (count($rpcount[$year]));
} else { echo " - "; }
</td>
<td align=\"center\">
if(count($mjccount[$year])>0) {
echo (count($mjccount[$year]));
} else { echo " - "; }
</td>
<td align=\"center\">
if(count($cocount[$year])>0) {
echo (count($cocount[$year]));
} else { echo " - "; }
</td>
<td align=\"center\">
echo $total;
</td>
</tr>";
}
}
$htmlcontent .= "</tbody></table>";
$mpdf = new \Mpdf\Mpdf();
$mpdf->WriteHTML($htmlcontent);
$mpdf->Output();
Waiting for FAST reply
Thanks Anes I have a Google Adsense code that I am saving to the wp_options table. I can successfully save and retrieve the variable containing the google adsense code but it doesn't do anything except display it as plain text on screen. I have a submit.php file that includes the following jQuery code:
<script> [...] request.done(function( json ) { jQuery('input[name=thumbnail-url]').val(json.thumbnail_url); jQuery('input[name=job_title]').val(json.title); jQuery('textarea[name=htmlcode]').val(json.html); [...] </script>
I need to remove
jQuery('textarea[name=htmlcode]').val(json.html);
and pass the "json.html" value into a PHP variable in another php file (functions.php). The code in the functions.php file is already there. The thing i need to do (and i am seriously struggling with it) is placing the value of json.html into a $phpvariable that i can then call from the function.php file. Do you need any more info for this issue? Thanks. I have a form that users input user name, password, and email... all writes to csv fine. My problem is I need to concatenate a a string with a variable and some html code will preserving the html when written to the csv.. I need the csv to be this username,password,email,user,category,text with http://sub.domain..com/splash/,something,something here's what i have Code: [Select] <?php if($_POST['formSubmit'] == "Submit") $varUserName = $_POST['username']; $varPW = $_POST['PW']; $varEmail = $_POST['email']; { $fs = fopen("testcsv.csv","a"); fputcsv($fs, array($varUserName,$varPW,$varEmail,"user","title",",category","some text '<a href="http://$varUserName.url.com/splash/>site.com</a>',)); fclose($fs); exit; } ?> and of course I'm getting Parse error: syntax error, unexpected T_STRING, expecting ')' on line 9 Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using:
<?php
session_start();
function verify() {
//verify that the user is logged in via the login page. Session_start has already been called.
if (!isset($_SESSION['loggedin'])) {
header('Location: /index.html');
exit;
}
//if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users.
$user === $_SESSION['name'];
//Connect to Databse
$link = mysqli_connect("127.0.0.1", "database user", "password", "database");
if (!$link) {
echo "Error: Unable to connect to MySQL." . PHP_EOL;
echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
exit;
}
//SQL Statement to lookup privlege information.
if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) {
//LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv.
while ($row = $result->fetch_assoc()) {
$priv === $row["su"];
}
}
// close SQL connection.
mysqli_close($link);
// Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special
//accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators.
if ($priv !== 1) {
echo $_SESSION['name'];
echo "you have privlege level of $priv";
echo "<br>";
echo 'Your account does not have the privleges necessary to view this page';
exit;
}
}
verify();
?>
I have a script that adds points together based upon the placing. This is the actual script: Code: [Select] <? $points = 0; if($place === '1st') {$points = $points + 50;} elseif($place === '2nd') {$points = $points + 45;} elseif($place === '3rd') {$points = $points + 40;} elseif($place === '4th') {$points = $points + 35;} elseif($place === '5th') {$points = $points + 30;} elseif($place === '6th') {$points = $points + 25;} elseif($place === '7th') {$points = $points + 20;} elseif($place === '8th') {$points = $points + 10;} elseif($place === '9th') {$points = $points + 10;} elseif($place === '10th') {$points = $points + 10;} elseif($place === 'CH') {$points = $points + 50;} elseif($place === 'RCH') {$points = $points + 40;} elseif($place === 'TT') {$points = $points + 30;} elseif($place === 'T5') {$points = $points + 30;} elseif($place === 'Champion') {$points = $points + 50;} elseif($place === 'Reserve Champion') {$points = $points + 40;} echo "Total HF Points: $points"; ?>What it *should* do (my friend's script works the same way and it works) it starts at points = 0, than if there is a first place, it adds 50, and so forth until it reaches the end. It is included into a file, in this area: Code: [Select] <div class="tabbertab"> <h2>Records</h2> <? $query92 = "SELECT * FROM THISTABLE WHERE VARIABLE='$id' OR VARIABLE = '$name' ORDER BY ABS(VARIABLE), VARIABLE"; $result92 = mysql_query($query92) or die (mysql_error()); echo "<table class='record'> <tr><th>Show</th> <th>Class</th> <th>Place</th></tr> "; while($row92 = mysql_fetch_array($result92)) { $class = $row92['class']; $place = $row92['place']; $entries = $row92['entries']; $race = $row92['show']; $purse = number_format($row92['purse'],2); echo "<tr><td>$race</td> <td>$class</td> <td>$place</td></tr>"; } ?> <tr><td colspan='3'><div align='right'><? include('includes/points.php'); ?></div></td></tr> </table> </div> This is the code that is relevant. When ended here, it echoes the last place that appears in the results (such as a 5th place echoing 30 points). When I move it to be included in the while loop, it shows Total Points: 50 Total Points: 25 Total Points: 10 (depending on the results displayed on that page). What am I doing wrong? I have a form that creates rows of data input textboxes depending on a user input number of things. I have a naming convention for all these textboxes that basically just keeps incrementing a number suffix for each row. All this is working fine. My problem is I need to get the data inserted into this table of textboxes into an array. Here's my code where I attempt to to this (it does not work): Code: [Select] $temp = $_SESSION['Num_Part']; $count = 1; while ($count <= $temp){ $temp2[$count] = "'Participant_P".$count."'"; //echo $temp2[$count]."<br/>"; $temp3[$count]=$_POST[$temp2[$count]]; //here's the problem $temp4[$count] = "'Result_P".$count."'"; $temp5[$count]=$_POST[$temp4[$count]]; //here's the problem //echo $temp4[$count]."<br/>"; $count++; } The problem is that the $_POST does not work with the variable in the argument position - even though the argument is formatted with single quotes. Can a variable be used in a POST argument and if so what is the correct syntax? If not, is there some other simple solution to harvest the data into an array. I understand I can harvest by explicitly accessing each key in the post assoc array. But this could be dozens of rows of input fields. Thanks in advance for your help here. I couldn't find anything online re this topic. Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu Probably something simple but I have searched high and low and can't figure this one out. I have a variable that is of the datetime format. I have another variable that is of the time format. I need to add them together. Example: $var1 = 2012-02-24 06:38:22 $var2 = 02:00:00 $var3 = $var1 + $var2 = 2012-02-24 08:38:22 Thanks for the help! |
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