PHP - Arranging Images
I am designing a web site which will dynamically generate labels which will be printed out by the end user. I have coded the part which generates each label into an image, but sometimes a user will want to print multiple copies of the same label on a page. I am working on the basis of an A4 page initially and depending on the design of the label, they will be different sizes (but they wont be mixing different designs on a single page so for each a4 sheet, every label will be the same size).
I have no idea how to go about the dynamic arranging of images onto the page without them being half chopped off. Ideally they will just be arranged onto a HTML page which I can just add a print button to. Any suggestions are most welcome Similar TutorialsHi, Im looking for a way of re-arranging my script(s) around to prevent headersalreadysent errors. I know i have a poor script design but since re-designing the site the script does not work where it previously had... im not sure whats gone wrong i just know that it needs to be changed somehow for it to work.. The error messages are coming from my login/check-login scripts: Login.php: Contains the form Code: [Select] <form method="post" action="check_login.php"> <p> <input type="submit" name="Submit2" value="go" /> </fieldset> </form> Check_login.php: Proccess form data Code: [Select] <?php // Connects to your Database mysql_connect("server", "user", "password") or die(mysql_error()); mysql_select_db("DB") or die(mysql_error()); //Checks if there is a login cookie if(isset($_COOKIE['ID_my_site'])) //if there is, it logs you in and directes you to the members page { $username = $_COOKIE['ID_my_site']; $pass = $_COOKIE['Key_my_site']; $check = mysql_query("SELECT * FROM users WHERE username = '$username'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if ($pass != $info['upassword']) { } else { header("Location: members_area.php"); } } } //if the login form is submitted if (isset($_POST['submit'])) { // if form has been submitted // makes sure they filled it in if(!$_POST['username'] | !$_POST['upassword']) { die('You did not fill in a required field.'); } // checks it against the database if (!get_magic_quotes_gpc()) { $_POST['email'] = addslashes($_POST['email']); } $check = mysql_query("SELECT * FROM users WHERE username = '".$_POST['username']."'")or die(mysql_error()); //Gives error if user dosen't exist $check2 = mysql_num_rows($check); if ($check2 == 0) { die('That user does not exist in our database. <a href=register.php>Click Here to Register</a>'); } while($info = mysql_fetch_array( $check )) { $_POST['upassword'] = stripslashes($_POST['upassword']); $info['upassword'] = stripslashes($info['upassword']); $_POST['upassword'] = md5($_POST['upassword']); //gives error if the password is wrong if ($_POST['upassword'] != $info['upassword']) { die('Incorrect password, please try again.'); } else { // if login is ok then we add a cookie $_POST['username'] = stripslashes($_POST['username']); $hour = time() + 3600; setcookie(ID_my_site, $_POST['username'], $hour); setcookie(Key_my_site, $_POST['upassword'], $hour); //then redirect them to the members area header("Location: members_area.php"); } } } else { // if they are not logged in ?> <form action="<?php echo $_SERVER['PHP_SELF']?>" method="post"> <table width="316" height="120" border="0"> <tr><td colspan=2><h1>Login</h1></td></tr> <tr><td>Username:</td><td> <input type="text" name="username" maxlength="40"> </td></tr> <tr><td>Password:</td><td> <input type="password" name="upassword" maxlength="50"> </td></tr> <tr><td colspan="2" align="right"> <input type="submit" name="submit" value="Login"> </td></tr> </table> </form> <?php } ?> Exact error messges read: Warning: Cannot modify header information - headers already sent by (output started at /hermes/bosweb25a/b109/ipg.removalspacecom/check_login.php:11) in /hermes/bosweb25a/b109/ipg.removalspacecom/check_login.php on line 81 Warning: Cannot modify header information - headers already sent by (output started at /hermes/bosweb25a/b109/ipg.removalspacecom/check_login.php:11) in /hermes/bosweb25a/b109/ipg.removalspacecom/check_login.php on line 82 Warning: Cannot modify header information - headers already sent by (output started at /hermes/bosweb25a/b109/ipg.removalspacecom/check_login.php:11) in /hermes/bosweb25a/b109/ipg.removalspacecom/check_login.php on line 85 What do i have to do to change the script check_login around and make it work correctly? Thank you in advance Is there anyway to arrange an array like: Monday 12.00 14.00 16.00 Tuesday 12.00 14.00 16.00 etc instead of Monday 12.00 Monday 14.00 Monday 16.00 Tuesday 12.00 Tuesday 14.00 Tuesday 16.00 etc $sql4 = "select * from time_list where loc_id = $location_id and film_id = $film_id order by day asc"; $result4=mysql_query($sql4); while($rows4=mysql_fetch_array($result4)){ $time_id = $rows4['time_id']; <?php echo $rows4['day']; ?></td> <td><a href ="seating.php?cine=<?php echo $location_id; ?>&film=<?php echo $film_id; ?>&time=<?php echo $time_id; ?>"><?php echo $rows4['time']; }?> Thank you Hi guys, I have a php script to arrange my data my title, location and date. However, when the data is arranged by date it is arranged with the earliest date first, I want it to arrange it as the latest date first, how do I do this? Regards Code: [Select] // //orderBy if(isset($_GET['orderBy'])){ switch ($_GET['orderBy']){ case "date": $orderBy = " ORDER BY `Date Added` ASC"; break; case "title": $orderBy = " ORDER BY `Title` ASC"; break; case "location": $orderBy = " ORDER BY `Location` ASC"; break; default: break; } } I have a code that outputs a table but right now each result is under the next ex: 1 2 3 1 2 3 I would like them to be horizontal ex: 123 123 the part of the code the controls the table is: Code: [Select] echo "<table border=0 cellspacing=0 cellpadding=0>"; foreach($xml->result->rowset->row AS $name) { echo "<tr>"; echo "<td><img src=/Character/".$name['characterID']."_200.jpg></td></tr>"; echo "<tr><td>".ucwords($name['name'])."</td></tr>"; echo "<tr><td>".ucwords($name['corporationName'])."</td>"; echo "</tr>"; } echo "</table>"; Been using a function I found here a while back for listing categories and sub categories and it works perfect. Code: [Select] function listSubcats ($parent, $level=0){ global $abc; $sql = "SELECT id, title FROM Cat WHERE parent = $parent"; $res = mysqli_query($abc, $sql); while (list($id, $title) = $res->fetch_row()) { $indent = str_repeat('-', $level); echo "<OPTION value='$id'>$indent $title</OPTION>\n"; listSubcats ($id, $level+1); // list its subcats } } But this is the first time I need change the way the results are displayed. And that leads me to realizing I am a bit confused on how list really works. The mysql table has the typical ID, CatName, parent I need to have each Cat with all subcats related to it listed in its own div. But whatever I try I cannot get the placements of the opening and closing divs in the right spots. So can anyone tell if its even possible to do it with this function. I did work it out using multiple queries but then read on alot of forums that queries inside while statements is not good. Just looking for he best (Correct) way of geting the results laid out properly. like this Code: [Select] <div class="one-third column"> Cat1 </div> <div class="one-third column"> Cat 2 </div> <div class="one-third column"> Cat 3 - Subcat 1 - Subcat 2 -- Sub Subcat 1 </div> <div class="one-third column"> Cat 4 </div> Hope that makes sense... Thanks for any guidance. I need help arranging a text blob into a table of where each cell is a letter, and the contents of the text blob must be arranged in the table according to what letter it starts with. This is the query I used: $gibs33 = mysql_query("SELECT name,anime_id,sort FROM anime WHERE popular='1' ORDER BY name ASC"); while ($gib33 = mysql_fetch_assoc($gibs33)) { echo '<a href="http://www.website.com/index.php?anime_id='.$gib33['anime_id'].'">'.$gib33['name'].'</a> | '; } The text blob looks like this: Quote <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=132">Appleseed (2004)</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=133">Appleseed: Ex Machina</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=219">Black Rock Shooter</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=2">Bleach</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=191">Bleach: Diamond Dust Rebellion</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=192">Bleach: Fade to Black</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=190">Bleach: Memories of Nobody</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=175">Brave Story</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=207">Canaan</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=24">Clannad</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=26">Code Geass Lelouch of the Rebellion</a> | <a href="http://www.narutosoul.com/index.php?categoryid=2&task=series&anime_id=206">Code Geass Lelouch of the Rebellion R2</a> | I want to arrange this blob into a table like this: #-9 A B C D E .Hack AppleSeed Bleach Blood+ Basilisk Claymore D Gray Man Eureka 7 Elfen Lied F G H I J K Fairy Tail Gundam Seed K-ON Season 2 etc.... In the Query, anime_id = number example: (189) sort = First letter of the word, example (N) name = Name of the anime, example (Bleach) I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
Ok, I have a GD image that is then rewrote as a png. My question is, is it possible to find out what site is requesting the image and then use it on the php image. Example, if I didn't want a domain to use my images, could I somehow me able to restirict that site? Hi guys I just want to know something. With php you can handle excel files by saving them as .csv files. Then the php script reads it line by line, and commas separating the fields. But is it possible that I can insert an image (small jpg or png) file in one of these fields...and then handle the image in the php script? Just for intrest I inserted an image in excel worksheet and it did not insert it into a cell, it float. Is there maybe another to insert it in the cell and then control it with php?? Thanx in advance Hey every i'm just trying to change my 'Read More' text after a blog post on my site into am image. Got some code that lets me change the actual text to something else, just can't find how to change the text into an image. Code: [Select] add_filter( 'the_content_more_link', 'child_content_more_link', 10, 2 ); function child_content_more_link( $more_link, $more_link_text ) { return str_replace( $more_link_text, 'my new read more text', $more_link ); } Thanks, Matty44m Hi, There are 10 images in a folder called "Images". All images are named like 1.jpg, 2.jpg, 3.gif, 4.png, and so on... I am using these images on my website with this link: MyDomain.com/Images/1.jpg Now what i want to do is change the image every minute. from 1... to ...10 all images one by one, every minute... Link should remain same, but it should give different image every time. and if someone copies my link of image, it still gets changed every minute. i hope to get some help, better with some example code... Thanks! Hello... I have some simple code but no ideas for upload another image?? PHP stores image name in database but there is no second picture uploaded in the images/ folder. Pls help. Thanks if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/png") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 2000000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "<strong>Slika:</strong> " . $_FILES["file"]["name"] . "<br />"; echo "<strong>Format slike:</strong> " . $_FILES["file"]["type"] . "<br />"; echo "<strong>Velicina:</strong> " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "<strong>Temp file:</strong> " . $_FILES["file"]["tmp_name"] . "<br />"; // here is mistake??? move_uploaded_file($_FILES["file"]["tmp_name"], "images/" . $_FILES["file"]["name"]); // $sql="INSERT INTO test (name, something, slika, slika2) VALUES ('".$_POST['name']."', '".$_POST['something']."', '".$_FILES['file']['name']."', '".$_FILES['slika1']['name']."')"; if (mysql_query($sql)) { echo "Sucess"; } else { echo "Error" . mysql_error(); } } } else { echo "Invalid file"; } ?> Hi all, while I was coding a script for my website something struck me which ive not really got an idea how to code it, but anyway, in my Database ive got a table which holds image URL's but how could I echo them out in PHP which will show the image? Not just the writing. Thanks for your help. I am absolutley stumped with this: im trying to have PHP get the size of an image that has been uploaded to mySQL, and return it to a certain size, lets say 200X200px. The problems im having to finding an existing script to help me understand - and then fit it into a table? All the help from google searches seem to suggest using software, but i would like to learn how to do this properly. First off the upload script: Code: [Select] <?php error_reporting(E_ALL); ini_set("display_errors", 1); echo '<pre>' . print_r($_FILES, true) . '</pre>'; //This is the directory where images will be saved $target = "/home/users/web/b109/ipg.removalspacecom/images/COMPANIES"; $target = $target . basename( $_FILES['upload']['name']); //This gets all the other information from the form $company_name=$_POST['company_name']; $basicpackage_description=$_POST['basicpackage_description']; $location=$_POST['location']; $postcode=$_POST['postcode']; $upload=($_FILES['upload']['name']); // Connects to your Database mysql_connect("server", "user", "password") or die(mysql_error()) ; mysql_select_db("removalspacelogin") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO `Companies` (company_name, basicpackage_description, location, postcode, upload) VALUES ('$company_name', '$basicpackage_description', '$location', '$postcode', '$upload')") ; echo mysql_error(); //Writes the photo to the server if(move_uploaded_file($_FILES['upload']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['upload']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } ?> this works great, it uploads the users pictures. This displays them out: Code: [Select] <?php $database="removalspacelogin"; mysql_connect ("server", "user", "password"); @mysql_select_db($database) or die( "Unable to select database"); $result = mysql_query( "SELECT company_name, location, postcode, basicpackage_description, premiumuser_description, upload FROM Companies" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); print "\n\n\nThere are $num_rows records.<P>"; echo "<table><tr><th>Comppany Name</th><th>Location</th><th>Postcode</th><th>Basic Members</th><th>Upgraded Users</th><th>Company Logo</th></tr><tr><td></td><td></td><td></td><td></td><td></td><td></td></tr>";// store the records into $row array and loop through while ( $row = mysql_fetch_array( $result, MYSQL_ASSOC ) ) { // Print out the contents of the entry echo "<tr><td>{$row['company_name']}</td>"; echo "<td>{$row['location']}</td>"; echo "<td>{$row['postcode']}</td>"; echo "<td>{$row['basicpackage_description']}</td>"; echo "<td>{$row['premiumuser_description']}</td>"; echo "<td><img src=\"http://www.removalspace.com/images/COMPANIES{$row['upload']}\" alt=\"logo\" /></td></tr>";} echo "</table>"; ?> Right now all the information in my table is fine except the image coloumn, the images are all the same size as they went in, i'd like them to all be one size so there in a uniformed fashion. But need all the rest of the mySQL table displayed, so how does it fit into my script to display the table? Many thanks!??? This topic has been moved to Application Design. http://www.phpfreaks.com/forums/index.php?topic=346417.0 I have a site where I need to have lets call it image1 displayed, then I want to change this image based on a php if statement, for instance: if $var == $var2 change the image ....blah blah so I was also going to have the names of my images stored in my database, i.e. image1.jpg and image2.jpg in my database. the image is in its own div tag set as the background image of the div tag if that makes any diference. Thanks Ok I have finally got rid of my syntax errors with this upload script. Now im getting the error uploading your image. My folders are called project_files and project_thumbs. This is my script <?php $results = ""; error_reporting(E_ALL); ini_set("display_errors", 1); //Auto Thumbnail Function function create_thumbnail($source,$destination, $thumb_width) { $size = getimagesize($source); $width = $size[0]; $height = $size[1]; $x = 0; $y = 0; if($width> $height) { $x = ceil(($width - $height) / 2 ); $width = $height; } elseif($height> $width) { $y = ceil(($height - $width) / 2); $height = $width; } $new_image = imagecreatetruecolor($thumb_width,$thumb_width) or die('Cannot initialize new GD image stream'); $extension = get_image_extension($source); if($extension=='jpg' || $extension=='jpeg') $image = imagecreatefromjpeg($source); if($extension=='gif') $image = imagecreatefromgif($source); if($extension=='png') $image = imagecreatefrompng($source); imagecopyresampled($new_image,$image,0,0,$x,$y,$thumb_width, $thumb_width,$width,$height); if($extension=='jpg' || $extension=='jpeg') imagejpeg($new_image,$destination); if($extension=='gif') imagegif($new_image,$destination); if($extension=='png') imagepng($new_image,$destination); } //Get Extension Function function get_image_extension($name) { $name = strtolower($name); $i = strrpos($name,"."); if (!$i) { return ""; } $l = strlen($name) - $i; $extension = substr($name,$i+1,$l); return $extension; } //Random Name Function function random_name($length) { $characters = "abcdefghijklmnopqrstuvwxyz01234567890"; $name = ""; for ($i = 0; $i < $length; $i++) { $name .= $characters[mt_rand(0, strlen($characters) - 1)]; } return "image-".$name; } $images_location = "/project_files/"; $thumbs_location = "/project_thumbs/"; $thumb_width = "100"; $maximum_size = "5000000"; //Check And Save Image if($_POST) { if($_FILES['image']['name'] == ""){ $results = "Please select the image you would like to upload by clicking browse"; } else{ $size=filesize($_FILES['image']['tmp_name']); $filename = stripslashes($_FILES['image']['name']); $extension = get_image_extension($filename); if($size > $maximum_size) { $results = "Your file size exceeds the maximum file size!"; } else if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { $results = "Only the following extensions are allowed. 'jpg', 'jpeg', 'png', 'gif'."; } else { $image_random_name=random_name(15).".".$extension; $copy = @copy($_FILES['image']['tmp_name'], $images_location.$image_random_name); if (!$copy) { $results = "Error while uploadin your image! Please try again!"; } else{ create_thumbnail($images_location.$image_random_name,$thumbs_location.$image_random_name, $thumb_width); $results = "Your image has been uploaded!"; } } } } ?> and the form Code: [Select] <html> <head> <title>test</title> </head> <body> <?php echo $results; ?> <form action="#" method="post" enctype="multipart/form-data"> <input type="hidden" name="MAX_FILE_SIZE" value="5000000" /> <input type="file" name="image" /> <input type="submit" value="Upload Image" /> </form> </body> </html> Hello all , I am facing a problem when trying to to show image files generated from php code in IE8 . it is working fine on firefox and IE9 . but in IE8 its showing the famous red X instead of the image ; belw is the code: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html dir="RTL" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:v="urn:schemas-microsoft-com:vml" lang="en-us" > <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <head> <title>header </title> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <?php mb_internal_encoding('UTF-8'); /** * @author IT Department * @copyright 2011 */ INCLUDE ("header.php"); INCLUDE ("connect.php"); if (isset($_GET['id'])) { $ID=$_GET['id']; $sql="select employees.USER_ID, employees.NAME_ARAB, employees.NAME_ENG, employees.TITLE_ARAB, employees.TITLE_ENG, department.DEP_NAME_ENG, department.DEP_NAME_ARAB, location.LOC_DESC_ENG, location.LOC_DESC_ARAB, employees.MOBILE, employees.EMAIL, employees.DEP, employees.LOC FROM employees,location,department WHERE employees.DEP=department.DEP_ID AND employees.LOC=location.LOC_ID and employees.USER_ID=$ID "; //echo $sql; $result=mysql_query($sql,$link); mysql_query("SET NAMES 'utf8'"); ECHO '<html DIR="RTL">'; echo "<table width=100% border='1' cellpadding='8' align='center' bgcolor='white'>"; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { //$row = mysql_fetch_assoc($result); echo"<tr align='center'>"; echo"<td>"; ECHO " الرقم الوظيفي :"; echo"</td>"; echo"<td colspan='2'>"; ECHO "<strong>$row[0]</strong>"; echo"</td>"; echo"<td>"; ECHO " : User ID "; echo"</td>"; echo"<td rowspan='7'>"; ECHO "<img src='IMAGE.php?id=".$row[0]."' width='225' height='300'/>"; //the image echo"</td>"; echo "</tr>"; the php image file is : Code: [Select] <?php INCLUDE ("connect.php"); $ID = "'".$_GET['id']."'"; $sql="SELECT PHOTO FROM employees WHERE USER_ID=$ID"; $result=mysql_query($sql,$link); $row = mysql_fetch_array($result); header("Content-type: image/pjpeg"); print ( $row[0]); ?> Thanks in advance for your help Ok, so i've managed to upload images, but now i'm trying to rename them to avoid replacement and i've done something like this: mysql_query( "INSERT INTO `softmarket`.`internet_securitate` (`internet_securitateID`, `nume_produs`, `descriere`, `versiune`,`poza`, `pret`, `disponibilitate_produs`) VALUES ('', '$_POST[titlu]', '$_POST[descriere]', '$_POST[versiune]', '$foto', '$_POST[pret]', '$_POST[disponibilitate]');"); Code: [Select] function findexts ($filename) { $filename = strtolower($filename) ; $exts = split("[/\\.]", $filename) ; $n = count($exts)-1; $exts = $exts[$n]; return $exts; } $ext = findexts ($_FILES['foto']['name']) ; $ran2 = $foto."."; $target = "../images/"; $target = $target . $ran2.$ext; while (file_exists($target)) { $ran2 = 'copyof'.$ran2; $target = $target . $ran2.$ext; } if(move_uploaded_file($_FILES['foto']['tmp_name'], $target)) { echo "The file has been uploaded as ".$ran2.$ext; } else { echo "Sorry, there was a problem uploading your file."; } header('Location: succes.php'); but it renames them in a wierd way...what is wrong? Hi, I have this upload script that uploads a file and writes path to DB: Code: [Select] <?php $uploadDir = '../uploads/'; if(isset($_POST['upload'])) { foreach ($_FILES as $file) { $fileName = $file['name']; $tmpName = $file['tmp_name']; $fileSize = $file['size']; $fileType = $file['type']; if($fileName==""){ $filePath = '../img/none.jpg'; } else{ $filePath = $uploadDir . $fileName; } if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); $filePath = addslashes($filePath); } $fileinsert[]=$filePath; } ?> this works fine for a single image, but I eed to upload 2 images with a single submission....any ideas how to do this? Thanks |