PHP - Checking If Timestamp Was X Days Ago

Hello,

I am trying to put together a mysql query that will return the number of visitors for four days ago, what i am trying to do is plot the last seven days visitors on a graph in the format of day seven, day six, etc and need to find away to get a count for each of those days.  At the moment i am thinking about running various queries with each returning the results for a specific day.  The code below is supposed to get the count of visitors four days ago.  Not between now and four days ago but just for the 24 hour period which covers day 4.  The current code just returns a value of 0.   Any help would be appreciated.

Code: [Select]
$result = mysql_query("SELECT ip FROM ip_stats WHERE  date= date_sub(NOW(), interval 4 DAY)");
$num_rows = mysql_num_rows($result);
echo "$num_rows";

I have a SQL row that has a date field: ex: 2010-11-01.
When a car is sold there either is a 30 day warranty, a 60 day warranty, or 0 day warranty.
What I'm trying to do is display when the vehicles warranty expires, based on the date it was sold, or when did it expire based on the same sold date pulled from the database.

Example using last months date: 2010-10-01

60 day: "Expires 11-30-10"
30 day: "Expired 11-01-10"

I can not seem to use the date function properly...
Any help would be greatly appreciated.

Hello. I want to generate the initial of the day of all the days of a chosen month. Meaning, if I choose this month it will give me:

TFSSMTWTFSSMTWTFSSMTWTFSSMTWTF

Is that clear? Can anybody help me? thanks!

Hi,

I have db table that records the days (Sunday, Monday...) when the employee login to the system. Say that the employee logged in on Monday then Logged in on Wednesday so this means he was absent on Tuesday. I calculated the number of days to get the answer 2 (between Wednesday and Monday before logging in on Wednesday) how to get the name of the missing day "Tuesday"?

code:

$curdate = date("Y-m-d");
$currday = date('l');
$lastdate = $row['indate'];
$lastdayin = $row['lastdayin'];
					
if ($lastdate !=Null)
{
						
	$misseddates = strtotime($curdate) - strtotime($lastdate);
	$misseddates = $misseddates / 86400;
	echo $misseddates;
						
	$misseddays = strtotime($lastdayin) - strtotime($currday);
	$misseddays = $misseddays / 86400;
	echo $misseddays;
}

I tried to get the name of day in the last step but it only calculates 5 in numbers how to get the name. I want the answer to be "Tuesday" as of the example.

Thanks.

When I try to add 30 days:
Code: [Select]
$date = date("Y-m-d");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +30 days");
echo $date;
and I echo date I get 1330664400

How do I get it to echo out 3/1/2012?

I know the answer lies in the strtotime but I can't figure it out.  I know it's a simple problem for most of you...

Hi I am trying to add a field to a database that is 4 days from the date the record is added, but it is not adding a value

Code: [Select]
$end_date=strtotime("+ 4 days");

$add_vehicle_sql=mysql_query("INSERT INTO `tbl_auction_lot`(`cust_id`,`reserve`,`make`,`model`,`spec`,`fuel`,`doors`,`mot_date`,`fns`,`fos`,`rns`,`ros`,`condition`,`reg_no`,`service_history`,`sale_type`,`status`,`keepers`,`gearbox`,`emissions`,`colour`,`date_first_reg`,`date_manufacture`,`bhp`,`engine_size`,`end_date`)
VALUES ('$seller_id','$reserve','$make','$model','$body_style','$fuel_type','$no_of_doors','$mot','$fns','$fos','$rns','$ros','$vehicle_condition','$vrm','$service_history','auction','$status','$prev_keepers','$gearbox','$emissions','$colour','$date_reg','$date_man','$bhp','$engine_size','$end_date')") or die(mysql_error());

What am I doing wrong and what is there a better way to achieve the desired result.

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=320501.0

Hello all,
The exact thing that i need is to calculate how much days there is in between two dates.
The only problem is that every thing that i found dont care about leap year
Anyone have a function to do that?

Hi guys, I've hit a brick wall here and am in need of your help.

I'm pretty new to PHP and have limited knowledge to say the least. I'll explain what it is I'm trying to do.

Set start date as 01/01/2004 (dmY) $oFour
Set how many days has it been since then? $today
Set how many days it was from $ofour 30 days ago. $today -30 = $thirtyDaysAgo


But the problem is I don't know how to make date('z'); work from 2004 and not 01/01/2010.

So $today will be how many days it has been since the start of 2004 and $thirtyDaysAgo will be $today -30. I can set up $thirtyDaysAgo no problem but it's just finding out how to get the $today number...


Hope anyone can offer a little light to my situation :/

Mav

Hi,

I need to calculate absent percentage but not sure how. working days from Sunday to Thursday every week so 5 working days a week. i will calculate the absent days from joining date until current date. Example if joining date is 24-3-2020 and today's date is 7-4-2020 i should get the number of absent days to 11 days since both Friday and Saturday are excluded. How to do that?

here is what I have:

$workingdays = $curdate - $joindate;
$workingdays = $workingdays - 				
$absent = ($counter / $workingdays) * 100;

the second line i missing the number of days for (Fridays and Saturdays) that should be excluded from calculations. The third line i did calculate the actual working days ($counter) for the employee so then i can get percentage of absent days. How to exclude the weekend days from calculations?

Edited April 1, 2020 by ramiwahdan
mistake in dates

I have this block of code that was written by someone years ago :-

 

<?php

	class BoDelivery {
		
		public function EstimatedDays($off, $standard_days, $saturday, $delay) {
            
            $today = date("N"); // Weekday - number 1-7
            $now = strtotime("now"); // Unix
            
            $off_array = explode(":", str_replace(".", ":", $off));
            
            $off_unix = mktime($off_array[0], $off_array[1], "00", date("n"), date("j"), date("Y"));

            $sending_days_from_now = 0;
            if ($now > $off_unix) {
                $sending_days_from_now++;
            }
            $sending_day = $today + $sending_days_from_now;
            switch ($sending_day) {
                case 6:
                    $sending_days_from_now++;
                    $sending_days_from_now++;
                    break;
                case 7:
                    $sending_days_from_now++;
                    break;
            }
            $sending_day = $today + $sending_days_from_now;

            // Estimated delivery time
            $delivery_days = $standard_days;
            $over_weekends = 0;

            // Add Delay
            if ($delay) {
                $delivery_days = $delivery_days + $delay;
            }
			            
            if ($sending_day == 5 && !$saturday) {
                $delivery_days++;
                $delivery_days++;
                $over_weekends++;
            }
            
            $delivery_day = $sending_day + $delivery_days;

            switch ($delivery_day) {
                case 6:
                    if (!$saturday) {
                        $delivery_days++;
                        $delivery_days++;
                        $over_weekends++;
                    }
                    break;
                case 7:
                    $delivery_days++;
                    $over_weekends++;
                    break;
            }
            
            if ($over_weekends == 0 && $delivery_days > 5) {
                $delivery_days++;
                $delivery_days++;
            }
            
            $delivery_day = $sending_day + $delivery_days;
            
            switch ($delivery_day) {
                case 13:
                    $delivery_days++;
                    $delivery_days++;
                    $over_weekends++;
                    break;
                case 14:
                    $delivery_days++;
                    $over_weekends++;
                    break;
            }
            
            $delivery_day = $sending_day + $delivery_days;
            
            $delivery_days = $delivery_day - $today;
            			
			return $delivery_days;
			
		}
		
	}
	
?>

 

Which is supposed to calculate the number of days for delivery, taking into account weekends & with a delay variable that we can set.

It isn't working as expected, may never have worked(??) or maybe down to PHP upgrades.

For example, if today (18th)I set the delay to 2 days the delivery estimate is the 21st (which is correct), if I change the delay to 3 OR 4 it becomes the 24th, 5 then becomes the 26th!

I can't get my head around the code at all, I wonder if someone could assist in what may be going on or add comments to the code snippets so I can maybe work it out?

 

Thanks for any help.

Hi fellas, this is really kicking my arse and i know its so simple!

I retrieve a date from the database, done!
I am manipulating it to display as i want, done!
How the hell do i add 365 days to this date?

$date= ($row['date']);
$subscription = strtotime($date);
echo
"<p>Subscription renewal date: ". date('l jS F Y', $subscription) . "</p>";

please could some one help me i need to limit the query by timestamp for the last 7 days here is my code on the php side

Code: [Select]
<?php
 
             $db = @mysql_connect("localhost", "8conv", "*****") or die("Connection Error: " . mysql_error());
             mysql_select_db("tempmonitor") or die("Error connecting to db.");
             $sql = "SELECT *, UNIX_TIMESTAMP(datetime) AS datetime FROM 8conv";
             $result = mysql_query($sql);
             $data = array();
             while ($row = mysql_fetch_array($result)) {
                $temp1[] = array($row['datetime'] * 1000, (int)$row['temp1']);;

             }
            
 $temp1 = json_encode($temp1);

I have a update query that should be updating the timestamp when a "month" field is changed.    I have the following code:   $month_update->bindParam(':timestamp', strtotime (date("Y-m-d H:i:s")), PDO::PARAM_INT);   The result that is returned is 1403198033.  I need it to look like this 2014-03-26 07:09:06.    I know I am missing something and I would greatly appreciate your help.   Thank you so much!  

   I have this date in database I must convert it to Unix Timestamp How ?      
   2010-11-11 09:04:44
   
   I try this
   echo mktime($mydate);
   
   but its not work its return wrong Timestamp becase if I convert back it I have wrong date 2011-02-16 21:01:33