PHP - How To Get The Cookie Values.
How to get the cookie value,when we login for a website,also how to access the site by using the cookie values?
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Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
hello, i have a cookie which contains ids, like: 123,33,45,67,89, i then have a little ajax script and interface where the user can delete id's. i can post these ids, which might look like this: 45,123, how can i delete the posted id's from the cookie? i would just grab the cookie, then reset it with the new values, but dont know the function that would strip the id's. trim()? strSOMETHING()? CURRENT CODE: JS: Code: [Select] <script> function close_box(id){ $('span.close').click(function() { $(this).parent().fadeOut(400); $.post("<?php echo $html_dir . $scripts_dir . 'ajax/contact_ids_delete.php'; ?>",{idsToDelete:id}); }); } </script>(generated) HTML Code: [Select] echo "<div class=\"info-box\">".$i++.") ".$displayEmail['business_name']."<span onclick=\"close_box('".$displayEmail['ID'].",')\" class=\"close\">x</span></div>"; PHP Code: [Select] <?php session_start(); if(isset($_POST['idsToDelete'])){ $_SESSION['contact_id_del'] .= $_POST['idsToDelete']; } else { $contact_id_trimmed = implode(',', array_unique(explode(',', $_SESSION['contact_id_del']))); echo $contact_id_trimmed; //setcookie("contact_ids", $contacts_trimmed, time()+1000, "/", ""); } ?> thanks for your help, Joe Hi here is my problem, i have a link like : index.php?id=1 When user click on it, a cookie array is set with a value of 1 when user clicks on another link with an id of 2, the same cookie is set with another value of 2, at the end , the cookie should read: Code: [Select] array( [0] => 1 [1] => 2 ) Can someone please explain how to do this? im struggling :S Dear All Members here is my table data.. (4 Columns/1row in mysql table)
id order_no order_date miles How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.
(5 Columns in mysql table) id order_no order_date state miles 310 001 02-15-2020 MI 108.53 310 001 02-15-2020 Oh 194.57 310 001 02-15-2020 PA 182.22
310 001 02-15-2020 WA 238.57 ------------------my php code -----------
<?php
if(isset($_POST["add"]))
$miles = explode("\r\n", $_POST["miles"]);
$query = $dbh->prepare($sql);
$lastInsertId = $dbh->lastInsertId(); if($query->execute()) {
$sql = "update tis_invoice set flag='1' where order_no=:order_no"; $query->execute();
} ----------------- my form code ------------------
<?php -- Can any one help how to correct my code..present nothing inserted on table
Thank You Edited February 8, 2020 by karthicbabuHi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
Hi all, I'm a first time poster here and I would really appreciate some guidance with my latest php challenge! I've spent the entire day googling and reading and to be honest I think I'm really over my head and need the assistance of someone experienced to advise the best way to go! I have a multi dimensional array that looks like (see below); the array is created by CodeIgniter's database library (the rows returned from a select query) but I think this is a generic PHP question as opposed to having anything to do with CI because it related to working with arrays. I'm wondering how I might go about searching the array below for the key problem_id and a value equal to a variable which I would provide. Then, when it finds an array with a the matching key and variable, it outputs the other values in that part of the array too. For example, using the sample data below. How would you recommend that I search the array for all the arrays that have the key problem_id and the value 3 and then have it output the value of the key problem_update_date and the value of the key problem_update_text. Then keep searching to find the next occurrence? Thanks in advance, as above, I've been searching really hard for the answer and believe i'm over my head! Output of print_r($updates); CI_DB_mysql_result Object ( [conn_id] => Resource id #30 [result_id] => Resource id #35 [result_array] => Array ( ) [result_object] => Array ( ) [current_row] => 0 [num_rows] => 5 [row_data] => ) Output of print_r($updates->result_array()); Array ( [0] => Array ( [problem_update_id] => 1 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Some details about a paricular issue [problem_update_active] => 1 ) [1] => Array ( [problem_update_id] => 4 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Another update about the problem with an ID of 3 [problem_update_active] => 1 ) [2] => Array ( [problem_update_id] => 5 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of four [problem_update_active] => 1 ) [3] => Array ( [problem_update_id] => 6 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of 6 [problem_update_active] => 1 ) [4] => Array ( [problem_update_id] => 7 [problem_id] => 3 [problem_update_date] => 2010-10-12 [problem_update_text] => Some new update about the problem with the ID of 3 [problem_update_active] => 1 ) ) Hi all, Just curious why this works: Code: [Select] while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]')"; } And this does not: $headdata_1 = "'$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]'"; while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values($headdata_1)"; }it puts $data[#'s] in the database fields instead of the actual data that '$data[0]','$data[1]'... relates to. I wrote a script to create the values in $headdata_1 based on the number of headers in $csvheaders1 but can't seem to get it working in the sql statement. Thanks I have a question about cookies I want the cookie to work on all the paths / folders / directorys located in a root path. So say like.. http://www.site.com/members/login.php is the folder which sets the cookie, then this cookie will also work on like.. http://www.site.com/bla/boo/works.php I'm trying to do: setcookie(Data1, 'valueofthecookie', '/', '.site.com', 1); But its not working... Hi all, I'm struggling with a program I'm trying to write with cookies, so any help would be very much appreciated!! What I'm wanting to do is when someone visits my site, I want to display content until the end of the day, and once the days up it disappears forever/until the cookies are deleted. Could someone help me with this? Thanks lots in advance, Jake Hey PHPFreaks! I have a problem with my login script, because when i login it sets a cookie and it all works. But when i got redirected and refresh the page, my script turns an error which says i'm not logged in? how come? This is what finds the cookie and redirects me Code: [Select] if(!isset($_SESSION['auth']) && !isset($_COOKIE['authcookie'])) { $_SESSION['ERROR'] = 7; header('location: index.php?login'); } Hi, I was trying to use setcookie on my website but when I try to use, it wasn't setting anything and then I tried to make sure if it's setting something, I added Code: [Select] echo $_COOKIE;But it shows Array (just the word) instead of tblogvalue. This is the code I'm using; Code: [Select] $Month = 2592000 + time(); setcookie(tblog, tblogvalue, $Month); echo $_COOKIE; if a user clicks ?hide=1 or ?hide=2 it does Code: [Select] if (isset($_GET['hide'])){ $id = intval($_GET['hide']); setcookie('hide', ''.$id.'',time()+32000000); header('Location: index.php'); exit; } How do I make it so if they click ?hide=1 it ad's 1, but what if they do ?hide=2 also? it would need to be 1,2 not just 2. how can i set cookie like a*dm*n@**t*r*c**.*c** ?? Code: [Select] $cookkiee = $islem_1['mail'] ; $sayisi = strlen($cookkiee)-1 ; $cok = $islem_1['mail'] ; for($i=0;$i<=$sayisi;$i++) { $sifr = rand(0,2); if($sifr ==0) { $cok[$i]= '*'; } $dizik = $cok[$i]; setrawcookie("kayip",$dizik,time()+(60*30),"/"); $_COOKIE['kayip'] = $dizik; echo $dizi // etc . a*dm*n@**t*r*c**.*c** } echo $_COOKIE['kayip']; // etc. just one char being like random a Ok I have my login form and previously I was using $_SESSION untill I learned this removes data when browser is closed. Someone said to me to use cookies but I have no clue where to begin on setting a cookie or reading information from it. Can anyone point me to a tutorial on cookies? I have part of my script that I have used many times in many diffrent applications that works just fine. But in this use it refuses to set the cookie or do anything besides the redirect for that matter. // if login is ok then we add a cookie $ip = $_SERVER['REMOTE_ADDR']; $datem = date("j F Y, g:i a"); mysql_query("UPDATE YBK_Login SET date = '$datem' AND ip = '$ip' WHERE ID = '{{$info['ID']}'")or die(mysql_error()); $_POST['username'] = stripslashes($_POST['username']); $hour = time() + 3600; setcookie('ID_WatsonN', $_POST['username'], 0); setcookie('Key_WatsonN', $_POST['pass'], 0); setcookie('UID_WatsonN', $info['ID'], 0); setcookie('LOGIN', $info['ID'], time()+3); //then redirect them to the members area Header("Location: dashboard.php"); i want to store the nickname of the user as a cookie.. somthing like set cookie name=nickname,value=smarty,expires after 1 week i know cookies are stored against domain names. what happens when another person logs in the same computer, with different login, and his nickname is diff how does the cookie get handled, and how does the right nickname flash against the right persons login id... Hi All, I have a secure website which always checks the cookies is not expired and the session id is set. When someone doesn't browse for the period of the cookie it will expire however the session id stays valid until he logout. A lot of people don't logout so the pages will still be accessable for them or others who use their pc. Is there a way to destroy the session id when the cookies expires? Marco Hey guys, first i have to say im from germany my english is not so good, i hope you understand the most things okay lets start, i have a cookie from site XY, i see the cookie in my browser, and now i want to save the cookie if someone goes to my website, the cookie is not on my website, i only want that the cookies displayed on my website or saved into the log.txt Code: [Select] <?php $jsi = $_COOKIES['JSESSIONID']; $current = file_get_contents('log,txt'); $current .= "\n$jsi"; file_put_contents('log.txt', $current); ?> but this code saves only the cookies on my own website, but i want a cookie from another website, all cookies are in my browser saved i want to read and save them. i hope you can help and understand me Hello, I am new to this forum and joined in hope I could get some help in relation to some PHP problems I have stumbled across within my work. I am currently working on an online store I am building from scratch. I have already built the basic system behind it and am now starting to implement a more user friendly design to it with JS validation, stylesheets and imaging layout. I have however come across a COOKIE problem with my login script. The purpose behind it is to only allow users into an area if they have logged in and declared cookies. I declare the cookies with 'setcookie()' then try and retrieve them with '$_COOKIE['firstname'];'. However since implementing my new design layout it has stopped being able to retrieve the cookies. Here is some of the script. I would greatly appreciate any help given ... Login.php Code: [Select] <?php //Validating input details and executing mysql query if ($username && $pass) { mysql_connect("$dhost","$dname","$dpass"); //Connection to mysql server @mysql_select_db("$dbase") or die ("Unable To Select Database!"); //Connection to stated database $query = "SELECT firstname, lastname, username FROM userdata WHERE password=SHA('$pass')"; //Retrieves firstname and lastname for username and password combination $result = @mysql_query ($query); $row = mysql_fetch_array ($result,MYSQL_NUM); //Return a record, if applicable if ($row) { setcookie('firstname', $row[0], time()+3600); setcookie('lastname', $row[1], time()+3600); setcookie('username', $row[2], time()+3600); //Set the cookies echo "<p class='Body-error-P'><span class='Body-text-T'>Login successful. If you are not redirected in 15 seconds click <A HREF='./index.php'>here</A></span></p>"; print "<meta HTTP-EQUIV='REFRESH' content='5 url=./index.php'>"; } else { //no record matched the query echo "<p class='Body-error-P'><span class='Body-text-T'>The username and password you entered are not valid.</span></p>"; } mysql_close(); //close database connection } } Index.php Code: [Select] <?php include_once ("config.php"); if(isset($_COOKIE['firstname'])) //if not cookie present, redirect the user { echo "<p class='Body-text-P'><span class='Body-text2-T'>You are now logged in, <b>".$_COOKIE['firstname'].' '.$_COOKIE['firstname']."</b></span</p>"; } else { echo '<p class="Body-text-P"><span class="Body-text-T">You are not logged in at this current time. Please login or register.</span</p>'; } ?> Let me know if you need anymore coding... I'm not really sure if this is a cookie problem but that's all I could think of. I have a web site that users have to log into. I have seen that when I log out of my account and log into my test account my main user name will still show on the welcome page unless I let the computer sit for a bit or if I clear recent history. This happens in all the main browsers. I have also started having a problem where if I update something in my database it shows up in MySQL right away but can take a while to show up on the web page unless i clear the history. Not sure what code to post to give you an idea so if you want to see something let me know and I will put it up. Thank you I was told that my login page could easily be manipulated to set themselves as my username (Mod Justin), giving them powers. How can I further secure my website's use of cookies? Quote I just visited your site as you - Mod Justin, simply by setting a 'user' cookie for your domain with your username in it. Your login code is NOT effective at stopping anyone or any bot script from impersonating any of the users, even impersonating you. My login code: http://pastebin.com/cBLybGKq Any possible solution to this? |