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PHP - Return All The Phrases A Word Is Found In
Hey guys i need to find a way to return all the phrases a certain word is found in.
Ex: $str = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. In facilisis faucibus vehicula. Praesent fermentum odio at dolor semper rutrum. Etiam pretium, diam ac mattis vehicula, dui ipsum congue ipsum, in sodales neque libero sit amet lorem. Morbi ac neque nec arcu feugiat convallis. Praesent quis diam a libero varius ipsum elementum."; $phrases = find_phrase($str, "ipsum"); $phrases would then output an array like this: $phrases[0] = Lorem ipsum dolor sit amet, consectetur adipiscing elit. $phrases[1] = Etiam pretium, diam ac mattis vehicula, dui ipsum congue ipsum, in sodales neque libero sit amet lorem. $phrases[2] = Praesent quis diam a libero varius ipsum elementum. How would the find_phrase function be build to achieve that? Similar Tutorialshello. im trying to get some results from a db and all i keep getting is the word ARRAY ?? I want to get all the placeholders that relate to a page. so if pageID=1 has place holder 1, place holder 2 and place holder 3 it will return 1, 2, 3 etc... in the db i have id pageID phNumber 1 1 1 2 1 2 3 1 3 etc.. this is the code i have Code: [Select] public function find_placeholders($pageID=0){ $sql = "SELECT phNumber FROM ".self::$table_name." WHERE pages_id=".$pageID.""; $result_array = self::find_by_sql($sql); return $result_array; } and on the page i have.. Code: [Select] <?php echo Placeholders::find_placeholders($pageID); ?> all i get is Quote Array once i solve this problem i will want to use each number in the array to find the content for each. so if i get 1,2,3 i will try and do some thing like. foreach placeholder number echo elements but 1 step at a time thanks for any help rick I am trying to make a form search through user input, and link it up with existing data in the database. so if in the text field, the person puts " flowers, red roses, white roses, daisies, sunflowers, cars" then they press "submit" the code then runs sql to search the database with matching terms. So that if the terms in the database field row are things->DBentry1->flowers, trucks, cars, red roses, things->DBentry2->dogs, cats, flowers it will echo out " 2 entries have matches "entry 1 has flowers, cars and red roses" "entry 2 has flowers" I want the results to be in order of number of matches returned for that database entry. it will skip "trucks because trucks was not entered and so did not match., Basically I want the search form to let the user put the terms in separated by a comma and a space or without a space, and then php and mysql find the matching terms, then echo out the results in matching order from most to least. I know that is a lot to ask of you all, but I would appreciate any help. Thanks in advance. how should i approach this with preg_match? i have a text: "big red apple" now i want the script to create a href for each keyword apple and link to http://apple.com examples appreciated I am making login system using codeigniter. When I run my code i get this error. Code: [Select] The requested URL /ci_login/user/login was not found on this server. here is my code so far user.php file which is in controller folder Code: [Select] <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class User extends CI_Controller { function __construct() { parent::__construct(); } function index() { } function login() { if($this->form_validation->run() == FALSE) { $this->load->view('view_login'); } else { echo "Successfull"; } } } view_login.php file which is in view folder Code: [Select] <html> <head> <title>Login</title> </head> <body> <h1>Please Login!</h1> <p>Use the login form below to login.</p> <div id="login_form"> <?php echo form_open(base_url(). 'user/login' ) ?> <label>Username:</label> <div> <?php echo form_input(array('id' => 'username', 'name' => 'username')); ?> </div> <label>Password:</label> <div> <?php echo form_password(array('id' => 'password', 'name' => 'password')); ?> </div> <div> <?php echo form_submit(array('name' => 'submit'),'Login'); ?> </div> <?php echo form_close(); ?> </div> </body> </html> help please how can I solve this error? One more problem... I'm sorry if I bother u. I have: echo "Image: ".$json['Poster'].""; and if image exist I get in return URL... but if there's no image get a error: Notice: Undefined index: Poster in C:\xampp\htdocs\file.php on line 48 How can I show a message error for this? Maybe I have too many questions but it's first time when I use PHP and don't understand too much. Help is appreciated, again. Thanks! I readed about if, else... still can't solved. This code works without problems:
<?php
namespace NamespaceA;
class A extends \NamespaceB\B {}
namespace NamespaceB;
class B {}
But why the following code cause Fatal error: Class 'NamespaceB\B' not found in ...file?
<?php
namespace NamespaceA;
class A extends \NamespaceB\B {}
namespace NamespaceB;
class B extends \NamespaceC\C {}
namespace NamespaceC;
class C {}
And this code also works without problems:
<?php
namespace NamespaceA;
class A extends \NamespaceB\B {}
namespace NamespaceC;
class C {}
namespace NamespaceB;
class B extends \NamespaceC\C {}
Without any namespace, also Fatal error: Class 'B' not found in ...file:
<?php
class A extends B {}
class B extends C {}
class C {}
Works without problems:
<?php
class A extends B {}
class B {}
And yes everything is in the same PHP file....
Hi Folks! New to php and introduced into it by a new found friend who is really into php. Been learning and learning and learning but not so much I am afraid. I guess books and youtubes and other tutorials are not enough so here I am, fearlessly venturing into this forum and I hope to learn much more to all ya pros out there err I mean in here. Be gentle to me please. I am not a coder but I do have logical thinking attitude and habit. I am a slow learner and close to the resignation age. But who cares, I wanna learn php, yeah!
Fatal error: Call to undefined function curl_init() in C:\(etc etc...) Now I know the usual causes for a problem like this, but they are not solving anything. Yes, extension=php_curl.dll is uncommented in the php.ini file. Yes, phpinfo() displays the php.ini file I have been editing as the Loaded Configuration File. Yes, extension_dir is set correctly in my php.ini file (other extensions work). Yes, php_curl.dll exists in my ext/ folder. No, phpinfo() does not display anything about cURL, anywhere Where else can I look to possibly fix this? I'm trying to show my friend my website and it's not letting him or me view it. I am using my own IP-address. (dashed out for security, but it is correct) http://--.---.--.---/index-1.php When he and I type this into our browser, we can an error called "Resource Not Found". But, when I use localhost address, it works fine. http://localhost/index-1.php Does anyone know what is wrong? Do I need to open a specific port? USING XAMPP. I think this is a PHP topic rather than Javascript. Can anyone tell me why this code cannot find the page (404 Not Found) Code: [Select] <?php if ("{$row['passState']}" == 0) { ?> <script language="javascript" type="text/javascript" > <-- var newwindow; function popupgo() { newwindow = window.open('check.php?quizTitle=<?php ".urlencode($quizTitle)."; ?>','_blank', 'scrollbars=yes,top=0,left=0,width='+screen.width+',height='+screen.height); if (window.focus) {newwindow.focus()} } //--> </script> <?php echo "<form><input type='button' onClick='popupgo()' value='Popup'></form>"; } ?>when this test code works fine? Both files are PHP. Code: [Select] <?php ?> <head> <script language="javascript" type="text/javascript" > <-- var newwindow; function popupgo() { newwindow = window.open('check/check.php?quizTitle=<?php '.urlencode($quizTitle).'; ?>','_blank', 'scrollbars=yes,top=0,left=0,width='+screen.width+',height='+screen.height); if (window.focus) {newwindow.focus()} } //--> </script> </head> <body> <form> <input type="button" onClick="popupgo()" value="Popup"> </form> </body> <?php ?> Hi every1, I am quite a newbie in php so please bear with ma silly questions.. I use IIS 6.0 . I have a php file named try.php . content is as folows <html> <head>......</head> <body>........som html code here... <?php if (flag==0) { some html code } ?> ...some html code </body> </html> when i open the file it says Error Summary HTTP Error 500.0 - Internal Server Error The page cannot be displayed because an internal server error has occurred. Can anybody tell me what am i doing wrong... It happen with me almost every now and then.. Is there some conceptual mistake am doing? Please clarify.. If the same question has been discussed thousand times before, than do direct me to the proper link... Regards, Dwayne http://bayarearcsociety.com/prototype/index.php When I click the Home link in the nav panel I get these errors Code: [Select] Warning: include(/content/pages/testpage.php) [function.include]: failed to open stream: No such file or directory in /home/bayare27/public_html/prototype/content/maincontent.php on line 7 Warning: include() [function.include]: Failed opening '/content/pages/testpage.php' for inclusion (include_path='.:/usr/lib/php:/usr/local/lib/php:/home/bayare27/php') in /home/bayare27 /public_html/prototype/content/maincontent.php on line 7 index.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" > <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8" /> <meta http-equiv="Content-language" content="en" /> <link type="text/css" rel="stylesheet" href="css/reset.css" /> <link type="text/css" rel="stylesheet" href="css/960.css" /> <link type="text/css" rel="stylesheet" href="css/custom.css" /> <title></title> </head> <body> <div id="wrapper" class="container_12"> <div id="header" class="grid_12"> <div id="left-header" class="grid_5 alpha"></div> <div id="newsflash" class="grid_7 omega"><?php include('content/newsflash.php'); ?></div> </div> <div id="leftmenu" class="grid_3"><?php include('content/menu.php'); ?></div> <div id="maincontent" class="grid_9"><?php include('content/maincontent.php'); ?></div> <div id ="footer" class="grid_12"><?php include('content/footer.php'); ?></div> </div><!-- end wrapper --> </body> </html> menu.php <?php ?> <div class="content"> <ul id="menu"> <li><a href="<?php echo htmlentities($_SERVER['SCRIPT_NAME']); ?>?page=testpage"><span>Home</span></a></li> <!-- Tried both these $_SERVER['PHP_SELF'] and $_SERVER['SCRIPT_NAME']--> <li><a href=""><span>About us</span></a></li> <li><a href=""><span>Schedule</span></a></li> <li><a href=""><span>Media</span></a></li> <li><a href=""><span>Products</span></a></li> <li><a href=""><span>Miscellaneous</span></a></li> </ul> </div> testpage.php <?php ?> <p> lalalaa </p> The file structure on the server is: prototype content - I know these are ok pages - testpage.php is in this file css - I know these are ok images - I know this one is ok Just don't know what to do next. Thanks I apologize, I thought I was posting in php. I assume you will move it. Hello. I have a system worked out where I have 2 columes for friends in my database (login_info). One of these is requests and the other is friends. Each request/friend is seperated with a underscore (_). I use the explode() function to seperate the friends/requests into a array. My only problem is I want to display the a different text if the user has sent a requests or is already friends with the user. I tried to do this using the array_search() function and converting it into a boolean (with the boolean cast). It doesn't seem to be working. Code: [Select] <?php $query = mysql_query('SELECT friends, requests FROM login_info WHERE user = \' ' .$userget .'\''); $friend = mysql_fetch_assoc($query); $req = explode('_', $friend['requests']); $friends = explode('_', $friend['friends']); if((bool)array_search($userget, $friends) && (bool)checkarray($userget, $req)) { echo '<a href="?p=add&user='.$userget .'"> Add As Friend </a>'; } if((bool)array_search($userget, $req)) { echo 'Friend Request Pending'; } if((bool)array_search($userget, $friends)) { echo $userget .'Is Your Friend' .$user_log .'!'; } ?> Any help? I'm having trouble with a role in a wordpress site that I made I think the script was that I installed another version, so I some adjustments in it, among those changes have modified this function Quote if (@$_GET['src'] && !@$PHPTHUMB_CONFIG['allow_local_http_src'] && eregi('^http://'.@$_SERVER['HTTP_HOST'].'(.+)', @$_GET['src'], $matches)) { $phpThumb->ErrorImage('It is MUCH better to specify the "src" parameter as "'.$matches[1].'" instead of "'.$matches[0].'".'."\n\n".'If you really must do it this way, enable "allow_local_http_src" in phpThumb.config.php'); } for this: Quote (@$_GET['src'] && !@$PHPTHUMB_CONFIG['allow_local_http_src'] && preg_match('^http://'.@$_SERVER['HTTP_HOST'].'(.+)', @$_GET['src'], $matches)) { $phpThumb->ErrorImage('It is MUCH better to specify the "src" parameter as "'.$matches[1].'" instead of "'.$matches[0].'".'."\n\n".'If you really must do it this way, enable "allow_local_http_src" in phpThumb.config.php'); } It was supposed to make some images appear as thumbnails on the home page my site, but they do not appear and I got the following error: Quote Warning: preg_match() [function.preg-match]: No ending delimiter '^' found in /home/pontocom/public_html/wp-content/themes/Comfy/scripts/phpThumb/phpThumb.php on line 160 Is there some way that I can take to fix this error? My Project: Online school note sharing for my university. How: You upload your note(s) get credits and with those credits buy other notes to download. Problem: Whats to stop someone from uploading a note they have downloaded. Security: Currently I have all notes go through an approval system where a staff member views the note sees if it is a legit note then approves it granting the user credits and making the note downloadable. So does anyone have any theories about how I could stop someone from uploading a file that they have uploaded before or have downloaded? timestamps on files md5checksums anything I need to find a way to fix this error and I have no idea. I am following a tutorial on how to make a simple PHP shopping cart at: http://v3.thewatchmakerproject.com/journal/276/ I have discovered a problem with the code where a } is not closed. Quote $cart = $_SESSION['cart']; if ($cart) { $items = explode(',',$cart); $contents = array(); foreach ($items as $item) { $contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1; } Should the } go on the end of the code or is it suppose to go else where within it? Hello, I am trying to implement a simple script that ZIPs up a text file. The problem is that I don't think the ZIPArchive is available on my server. Here is an example of my code: Code: [Select] <?php $zip = new ZipArchive(); $filename = "./PJR.v2.zip"; if ($zip->open($filename, ZIPARCHIVE::CREATE)!==TRUE) { exit("cannot open <$filename>\n"); } if ($handle = opendir('WORKDIR')) { while (false !== ($entry = readdir($handle))) { if ($entry != "." && $entry != "..") { $zip->addFile($entry); } } closedir($handle); } $zip->close(); ?> When I run it from the command line, I get Code: [Select] PHP Fatal error: Class 'ZipArchive' not found in /users/albert/zip_POC.v2.php on line 2 This is the version info on my server: Code: [Select] php -v PHP 5.1.6 (cli) (built: Nov 12 2008 11:22:53) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies Is there a way that I can install that class even though I am not the 'root' user?? I am using the code below for my webpage. When no or non existant querystring is passed the user is directed to the homepage. I want to change this so that if a user goes uses an invalid query string (?page=oldcontent) they are directed to a 'not found page'. Can this be done with the way I hae set this up? switch ($page) { case 'about': include 'about.php'; break; case 'contact': include 'contact.php'; break; default: include 'homepage.php'; } This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=318218.0 Hi New to php code, been trown in at the deep end. Keep getting error message Warning: preg_replace(): No ending delimiter it is to do with these 3 lines only $is_sera = preg_replace("'","\"", $is_sera); $is_sera = preg_replace("%","", $is_sera); $is_sera = preg_replace("\?","", $is_sera); can any one tell me what the ending delimiter error means/is thanks in advance |
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