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PHP - Execute By Dropdown
Not sure if this is possible I am trying to do a multi delete:
Code: [Select] <form name="form1" method="post" action=""> <table> while($rows=mysql_fetch_array($result)){ ?> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<? echo $rows['id']; ?>"></td> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['name']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['lastname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> </tr> <?php } ?> // Check if delete button active, start this if($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysql_query($sql); } <tr><td> <select name="dropdown"> <option value="option1">Choose an action...</option> <option value="edit">Edit</option> <option value="delete">Delete</option> </select> <a class="button" href="#">Apply to selected</a> if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=nameslist.php\">"; } } mysql_close(); Similar TutorialsI have a form with dropdown list that is populated with values from Sql Server table. Now i would like to use this selected item in SQL query. The results of this query should be shown in label or text field. So when a user selects item from dropdown menu, results from SQL query are shown at the same time. I have two dropdown list at the moment in my form. First one gets all values from a column in table in SQL Server. And the second one should get a value from the same table based on a selection in first dropdown list.
When i load ajax.php i get 2 error mesages: This is my code so far. I have tried to do it with this Ajax script. But i can only get first dropdown to work. The second dropdown(sub_machinery) does not show values, when first dropdown item is selected. The second dropdown should show values from databse table with this query( *$machineryID* is first dropdown selected item): SELECT MachineID FROM T013 WHERE Machinery=".$machineryID. Index.php
<!doctype html>
<?PHP
$server = "server";
$options = array( "UID" => "user", "PWD" => "pass", "Database" =>
"database");
$conn2 = sqlsrv_connect($server, $options);
if ($conn2 === false) die("<pre>".print_r(sqlsrv_errors(), true));
echo " ";
?>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<section id="formaT2" class="formaT2 formContent">
<div class="row">
<div class="col-md-2 col-3 row-color remove-mob"></div>
<div class="col-md-5 col-9 bg-img" style="padding-left: 0;
padding-right: 0;">
<h1>Form</h1>
<div class="rest-text">
<div class="contactFrm">
<p class="statusMsg <?php echo
!empty($msgClass)?$msgClass:''; ?>"><?php echo $statusMsg; ?></p>
<form action="connection.php" method="post">
<div>machinery</div>
<select id="machinery">
<option value="0">--Please Select Machinery--</option>
<?php
// Fetch Department
$sql = "SELECT Machinery FROM T013";
$machanery_data = sqlsrv_query($conn2,$sql);
while($row = sqlsrv_fetch_array($machanery_data) ){
$id = $row['Id'];
$machinery = $row['Machinery'];
// Option
echo "<option value='".$id."' >".$machinery."</option>";
}
?>
</select>
<div class="clear"></div>
<div>Sub Machinery</div>
<select id="sub_machinery">
<option value="0">- Select -</option>
</select>
<input type="submit" name="submit"
id="submit" class="strelka-send" value="Insert">
<div class="clear"> </div>
</form>
</div>
</div>
</div>
</div>
</section>
</script>
<script type="text/javascript">
$(document).ready(function(){
$("#machinery").change(function(){
var machinery_id = $(this).val();
$.ajax({
url:'ajaxfile.php',
type: 'post',
data: {machinery:machinery_id},
dataType: 'json',
success:function(response){
var len = response.length;
$("#sub_machinery").empty();
for( var i = 0; i<len; i++){
var machinery_id = response[i]['machinery_id'];
var machinery = response[i]['machinery'];
$("#sub_machinery").append("<option
value='"+machinery_id+"'>"+machinery+"</option>");
}
}
});
});
});
</script>
</body>
</html>
Ajaxfile.php
<?php
$server = "server";
$options = array( "UID" => "user", "PWD" => "pass",
"Database" => "database");
$conn2 = sqlsrv_connect($server, $options);
if ($conn2 === false) die("<pre>".print_r(sqlsrv_errors(), true));
echo " ";
$machineryID = $_POST['machinery']; // department id
$sql = "SELECT MachineID FROM T013 WHERE Machinery=".$machineryID;
$result = sqlsrv_query($conn2,$sql);
$machinery_arr = array();
while( $row = sqlsrv_fetch_array($result) ){
$machinery_id = $row['ID'];
$machinery = $row['MachineID'];
$machinery_arr[] = array("ID" => $machinery_id, "MachineID" =>
$machinery);
}
// encoding array to json format
echo json_encode($machinery_arr);
?>
Edited May 6, 2019 by davidd
Hi freaks, I'm new to php first of all. I'm dynamically binding a dropdownlist with mysql database . After the user selects an item from it , I want to match that item with another table so as to populate another database. The code I'm using to populate dropdown: Code: [Select] <?php $con = mysql_connect("localhost","root",""); if(!$con) { die ('Can not connect to : '.mysql_error()); } mysql_select_db("ims",$con); $result=mysql_query("select cat_id,cat_name from category"); echo "<select name=cat>"; while($nt=mysql_fetch_array($result)) { echo "<option value=$nt[cat_id]> $nt[cat_name] </option>"; } echo "</select>"; mysql_close($con); ?> Now after the user selects any one of the item , I want to bind another dropdown on the same page using such query like $result=mysql_query("select subcategory.sc_id,subactegory.sc_name from subcategory,category where subcategory.sc_id=$nt[cat_id]"); Please anyone tell me the logic and code to do it. Also tell me do I need an intermediate page to post the 1st dropdown value and then continue with 2nd dropdown. I couldn't figure out the concept anyhow. Help on this will be highly appreiable . (Tell me if I'm not clear with my question) hi, I am having problems setting a session from a SQL query, please help... here is my code: Code: [Select] $query1 = "SELECT * FROM members_copy WHERE rsUser = '$username' AND rsPass = '$password'"; $result1 = mysql_query($query1); echo "<br>".$result1['USERID']; $_SESSION['s_logged_n'] = 'true'; $_SESSION['s_username'] = $username; $_SESSION['USERID']=$result1['USERID']; $_SESSION['RSTOWN']=$result1['RSTOWN']; $_SESSION['RSEMAIL']=$result1['RSEMAIL']; $_SESSION['RSUSER']=$result1['RSUSER']; no sessions are currently being set?! I have written a Validation class that checks to see if a file being uploaded to the server meets certain conditions. That works a treat. The next step is to actually upload it to the server and I have an Upload class that can do that. Again, that works perfectly fine. Once the file uploads, I am passing the $location of that of that file to my DB class. The DB class is full of methods that prepare and then execute strings that are SQL queries that are required in other areas of my application. Nothing I have at the moment is suitable for just running an SQL file so I don't know what to do now.. My procedural code, that works, looks like this;
$dbh2 = new PDO("mysql:host=localhost;dbname=DB360transfer", $login_user,
$login_password);
$sql =
file_get_contents($path.$new_file_name);
$qr = $dbh2->exec($sql);
I'm not sure how to replicate this up in a PDO/OOP application.My DB Class script is attached. The run_from_file code starts on line 98. I've left in the other stuff as I suspect the answer has something to do with using the $this or the self:: - but really I have no idea. So my question is, what is the correct syntax for executing a file in OOP? Attached Files DB.php 2.92KB 6 downloads Hi Guys, I have the following script which works fine for GoogleMaps Code: [Select] <?php require'EasyGoogleMap.class.php'; $gm = & new EasyGoogleMap("rYvyXhRFPYW5tkV_IE5hWxecUidHAYjJhBSp59xzQuNZcoxNYCiaum4_Xb66Fw"); $gm->SetMarkerIconStyle('STAR'); $gm->SetMapZoom(10); $gm->SetAddress("10 market st, san francisco"); $gm->SetInfoWindowText("This is the address # 1."); $gm->SetAddress("Manila, Philippines"); $gm->SetInfoWindowText("This is Philippine Country."); $gm->SetSideClick('Philippines'); ?> <html> <head> <title>EasyGoogleMap</title> <?php echo $gm->GmapsKey(); ?> </head> <body> <?php echo $gm->MapHolder(); ?> <?php echo $gm->InitJs(); ?> <?php echo $gm->GetSideClick(); ?> <?php echo $gm->UnloadMap(); ?> </body> </html> I've now coded that static page to take the following, and within the GoogleMaps database field entered in exactly the following $gm->SetAddress("10 market st, san francisco"); $gm->SetInfoWindowText("This is the address # 1."); $gm->SetAddress("Manila, Philippines"); $gm->SetInfoWindowText("This is Philippine Country."); $gm->SetSideClick('Philippines'); Code: [Select] <?php $maps_find = $OO_Open->newFindCommand('Maps'); $maps_find->AddFindCriterion('AccountName','xx'); $maps_result = $maps_find->execute(); $maps_row = current($maps_result->getRecords()); $Gdata = $maps_row->getField('GoogleMaps'); //echo $Gdata; //exit; ?> <?php require'EasyGoogleMap.class.php'; $gm = & new EasyGoogleMap("my key"); $gm->SetMarkerIconStyle('GT_FLAT'); $gm->SetMapZoom(10); $gm->SetMapWidth(1080); # default = 300 $gm->SetMapHeight(550); # default = 300 echo $maps_row->getField('GoogleMaps'); //eval("\$Gdata = \"$Gdata\";"); ?> <html> <head> <title>EasyGoogleMap</title> <?php echo $gm->GmapsKey(); ?> </head> <body> <?php echo $gm->MapHolder(); ?> <?php echo $gm->InitJs(); ?> <?php echo $gm->GetSideClick(); ?> <?php echo $gm->UnloadMap(); ?> </body> </html> Is there way of getting the $maps_row->getField('GoogleMaps'); command to behave as if it was php (when I echo it, it does display the code as text). I'm not using the FileMaker db to store the code, I thought eval function was the answer but not had much luck. Many Thanks for the advice Jalz Hello, I've been assigned the task of creating an internal site for our office that has links to all the websites we use as well as the applications we use. I'm very comfortable using php with mysql for handling forms and displaying database information but I'm not sure how to go about this. So my question is, is there anyway I can use php to open an exe file? Hi, Below i have some sample code and am confused over execute(), i have the code below in a try and catch block, in the catch block i call a function i created to log any error that is caught in catch block to a .txt file. I then looked online and it seems that i should do an if statement check on execute to ensure it executed the query, the part that confuses me if the execute failed i thought it would be caught in the catch block but it seems that is not the case. To explain better i have commented the code in depth on the area that i am confused about. Any help in making me understand would be great. I have not included all code above try and catch to keep things simple Code: [Select] <?php try { // connect to database $dbh = sql_con(); // checke if username exists on users table or users banlist table $stmt = $dbh->prepare(" SELECT users.user_login FROM users WHERE users.user_login = ? UNION ALL SELECT users_banlist.user_banlist FROM users_banlist WHERE users_banlist.user_banlist = ?"); // this is the part i am confused with, why is it i would use an if statement on execute() ? // i thought using a try and catch block any errors would be caught in the catch block. // using an if statement to check if execute() worked, i thought if execute failed it would // be handled by the catch block, i mean in my exmaple code here, what could cause the execute to fail ? // and why if execute failed it would not be caught by catch block ? // i am looing at exmaple online and i am reading different things and its all confusing me // execute query if(!$stmt->execute(array($username, $username))){ echo 'something went wrong .. '; } else { // execute worked } } // if any errors found log them in my ExceptionErrorHandler() function and display friendly message catch (PDOException $e) { // this function catches an error and logs them to file ExceptionErrorHandler($e); require_once($footer_inc); exit; } } ?> Thanks or any help! Hi,
I have a cron job that executes this script every 2 minutes:
<?php
// LOAD WP-LOAD.PHP
require('/opt/bitnami/apps/wordpress/htdocs/wp-load.php');
// INCLUDE AND EXECUTE SCHEDULER.PHP
include('/opt/bitnami/apps/wordpress/htdocs/wp-content/themes/yeelloe/scheduler.php');
?>
When I try to include; /opt/bitnami/apps/wordpress/htdocs/wp-content/themes/yeelloe/scheduler.php:
<?php // EXPLODE AND PARSE WP-CONTENT; FUNCTIONS.PHP $parse_uri = explode( '/opt/bitnami/apps/wordpress/htdocs/wp-content', $_SERVER['SCRIPT_FILENAME'] ); // LOAD WP-LOAD.PHP require_once( $parse_uri[0] . '/opt/bitnami/apps/wordpress/htdocs/wp-load.php' ); // LOAD TEMPLATE FUNCTION CheckFunction(); ?> How can I get this form to execute? Do I need to use a hidden input or something? Code: [Select] <form action="partnerRequest.php" method="post"> <a href="" title="Become Associates" id="becomeassoc" class="mll"> <span class="f_right">Become Associates</span><img src="../assets/img/becomeassoc.jpg" class="mrs vmiddle" alt="Become Associates" /> </a> </form> Hi, I am trying to create a PHP script ("repair-correct.php") in order to run some CLI commands without using PuTTy - The CLI commands are needed to repair/correct the execution of a web application named Mautic. Shared web host account with PHP 7.0 URL: https://www.myserver.com Mautic directory: https://www.myserver.com/mautic
What I want to do is:
Step1: Change ownership of files and folders To find out which user Apache is running as, I want to execute the following command and take note of the first entry in the line which is returned: ps aux | grep apache2 I want to use this information to find the groups with the following command groups apache_user (where apache_user is the user I identified from the first step above) To reset the ownership of files and folders, I want to use the following command (ensuring that I replace apache_user and apache_group with the values identified in the steps above): sudo chown -R apache_user:apache_group With this command I want to change ownership, using the -R flag which means recursively - including all files/folders within that location.
Step 2: Reset the file and folder permissions
find . -type f -not -perm 644 -exec chmod 644 {} +
Thanks so much for your help in solving this problem!
Best, Tony
I need to execute a program in the command prompt in windows using php, which php functions would be best to do this? and would i need to set any type of permissions to be able to use them? Hi. I have a query that determines if user is online/offline. Works perfectly when page loads. I want to change to auto run query every X seconds. NOTES: - The query is on a .php page with multiple other queries. -IF it is possible to still run the query with-in this page? or make a separate file and include in an iframe? i would like to avoid the iframe and just $output the result of query every X seconds. Here is my $query code: $query = "SELECT `manager_id` FROM #__profiles_xref WHERE profileid = '$profid'"; $onofflineid=doSelectSql($query,1); foreach ($onofflineid as $isonoffline){ $profmanagerid=$isonoffline->manager_id; } $query = "SELECT `session_id` FROM table_session WHERE userid = '$propmanagerid'"; $onofflinestatus=doSelectSql($query,1); if (count($onofflinestatus)>0) { $output['PROPSTATUS']='Online'; } else { $output['PROPSTATUS']='Offline'; } <?php error_reporting(E_ALL); $psPath = "powershell.exe"; $psDir = "C:\\wamp\\www\\ps\\"; $psScript = "SampleHTML.ps1"; $runScript = $psDir. $psScript; $prem = "-Action enable"; $runCMD = $psPath. " " .$runScript. " " .$prem; //var_dump($runCMD); $output = exec($runCMD); echo $output; ?>Hello, I am working on a small project to get results from powershell script by using PHP. For some reason in PHP logs I get Exec unable to fork. Above is the script I wrote to execute powershell script within php. My webserver is IIS 7, and app pool is using a domain user that has full rights for Powershell to execute and get remote server results. I am running Apache with the PHP module installed on Debian Linux. My goal is to launch a binary in a background process and then feed it commands via fifo. The binary I need to launch has a config file which lives in the home directory of the apache user (in my case the user name apache is started with is www-data). www-data's home dir was the web root so I changed it to /home/www-data. I also change the shell from /bin/sh to /bin/bash for www-data. Neither of these changes are present when I load a php file from a browser. This script: Code: [Select] <?php echo "User: " . exec('whoami') . "<br>"; echo "Shell: " . exec('ps -p $$ | grep sh') . "<br>"; ?> Outputs this: Code: [Select] User: www-data Shell: 9179 ? 00:00:00 sh Also if I execute the binary it does seem to read the config file which is in the www-data users directory. I have set the home dir and the web root to be owned by www-data and it's read and writeable. How do I get php to execute the binary so it has access to the users home directory and uses the bash shell? Are there any other ways to launch and control a binary on a unix system via php? I'm looking to get php to write to file when someone visits one of my sites without javascript.
From the research I've done, it seems that an css hidden, iframe within the noscript tag would work, and the php file would then write to a log.
I just want a simple tick log that increments by 1, but perhaps also lists the user-agent.
My one concern is that I want to include this same code on multiple sites, all of which could be trying to access, and write a tick to the same "no JS log". Is that going to cause problems the way php writes to files?
Can someone help me create the code that will write to this log file, that won't cause errors or problems when multiple sites/visitors could be making writes to the log?
I'm a php noob, so while I can research how to get php to write to a file and save, most of the tutorials don't mention if it would be a safe method to use, if multiple domains were trying to write to that same file, at the same time, and trying to add their own "tick" to increment the number within the flat file.
Extended help that I'm looking for is getting ticks per user-agent/search bot, so bots/web users that visit my pages, that don't run JS, could have ticks by them. eg:
Google Bot: 3
Mozilla Firefox 31.0: 15
Any help on this would be appreciated, or any flaws that you see in this type of tracking, thanks!
private function _authenticate() { // if there's already an auth error if ( $this->_checkForMessageType('auth') ) { $this->_addMessage('auth', 3); self::__destruct(); return false; } $stmt = $this->_dbh->prepare("SELECT shopID FROM api_users WHERE shopID = ? AND API_key = ? LIMIT 1"); var_dump($stmt->execute(array($this->_shopID, $this->_key))); echo $stmt->rowCount(); // authenticate key / shop id if ( !$stmt->rowCount() ) { $this->_addMessage('auth', 3); self::__destruct(); return false; } $this->_addMessage('auth', 4); } I am using PDO with MySQL driver and ATTR_EMULATE_PREPARES => true, however, when I run this code I get the output: Code: [Select] bool(false) 0{"auth":{"3":""}} Any ideas why PDOStatement::execute is returning false? I get no connection errors, no PDOExceptions, the db structure is correct, and there is valid data in the database. Any help appreciated, thanks. Hi, I have a strange problem using the exec command. I have the following php code : <?php error_reporting(E_ALL); ini_set('display_errors','On'); $accountBase = "HORAIREMOBILE"; $primaryUser = "DUM"; $secondaryUser = "DUM"; $result = exec(escapeshellcmd("/home/evidian/utils/getAccount ".escapeshellarg($accountBase)." ".escapeshellarg($primaryUser)." ".escapeshellarg($secondaryUser)),$output,$return_val); echo $result; ?> When I execute the command from the CLI, with any user, it just works fine, and shows my the result (basically a JSON formated output). However, when I call the code frome the apache server, it simply returns nothing. Could anybody help me with this issue ? i need this code to execute faster, is there a faster way? function all_word_combinations($all_words_unknown,$previous_string=''){ $all_words_2=array(); if(is_array($all_words_unknown)){ $all_words_array=$all_words_unknown; }else{ $all_words_array=explode(' ',trim($all_words_unknown)); } $item2remove='the'; $all_words_array=explode(' ',trim(str_replace($item2remove.' ','',str_replace(' '.$item2remove,'',(implode(' ',$all_words_array)))))); if(count($all_words_array)>1){ $previous_array=explode(' ',$previous_string); foreach($all_words_array as $one_word){ if(!in_array($previous_string.$one_word,$all_words_2) && !in_array($one_word,$previous_array)){ $all_words_2[$previous_string.$one_word]=$previous_string.$one_word; $all_words_2=array_merge($all_words_2,all_word_combinations($all_words_array,$previous_string.$one_word.' ')); } } return $all_words_2; }else{return $all_words_array;} } $one_word_combination=''; foreach(all_word_combinations('cat dog mouse turtle shark whale elephant giraffe lion tiger fish monkey') as $one_word_combination){echo str_replace(' ','-',$one_word_combination).'<br />';} Hello, I am mounting google drive to my raspberry pi with this command from command line; sudo gdfs -o allow_other /var/www/html/gdfs.creds /media/pi/gdrives İt is working from command line, but it is not work when i execute it from web browser. Here php content;
shell_exec("sudo gdfs -o allow_other /var/www/html/gdfs.creds /media/pi/gdrives");
and i changed my sudoers file giving permission www-data. here is my sudoers file content # This file MUST be edited with the 'visudo' command as root. # # Please consider adding local content in /etc/sudoers.d/ instead of # directly modifying this file. # # See the man page for details on how to write a sudoers file. # Defaults env_reset Defaults mail_badpass Defaults secure_path="/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin" # Host alias specification # User alias specification # Cmnd alias specification # User privilege specification root ALL=(ALL:ALL) ALL # Allow members of group sudo to execute any command %sudo ALL=(ALL:ALL) ALL www-data ALL=NOPASSWD: ALL # See sudoers(5) for more information on "#include" directives: #includedir /etc/sudoers.d Can anyone tell me what i am doing wrong ? |
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