PHP - Table Background Row Using Php Function
Hi,
I have This Function For Two backgrounds row of table : Code: [Select] function background() { $bg = ''; // odd $bg2 = 'F3F3F3'; // even if ( $i%2 == 0 ) $bgs = "$bg"; else $bgs = "$bg2"; return $bgs; } PHP CODE IS : Code: [Select] echo "<TABLE>"; $i = 0; while ($f = $db->fetcharray( $r )) // for fetch { background(); // function echo "<tr> <td bgcolor=\"{$bgs}\">$id</td> <td bgcolor=\"{$bgs}\">$name</td> <td bgcolor=\"{$bgs}\">$date</td> </tr> "; $i++; } echo "</table>"; But This Not Worked. What's Problem ? Thanks Similar TutorialsOK, so I have a mail function code: Code: [Select] $to = "$email"; // Change this to your site admin email $from = "events@final.net46.net"; $subject = "Thank You for Registering for $event. "; //Begin HTML Email Message where you need to change the activation URL inside $message = "<html> <head> <style type='text/css'> #apDiv1 { position:absolute; left:338px; top:278px; width:311px; height:129px; z-index:1; } #pic { position:relative; left:0px; top:0px; } #apDiv2 { position:absolute; left:50px; top:207px; width:181px; height:149px; z-index:2; } #apDiv2 { text-align: center; } </style> </head> <body><div id='apDiv1'> <table width='408' border='1' cellspacing='2' cellpadding='2'> <tr> <th width='90' scope='col'>Event(s):</th> <th width='298' scope='col'>"; $sql = ("SELECT * FROM Events WHERE eventid='$eventid'"); $result = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_array($result)){ $event = $row['event']; $startdate = $row['startdate']; $enddate = $row['enddate']; $description = $row['description']; $location = $row['location']; $subevent1 = $row['subevent1']; $subevent2 = $row['subevent2']; $subevent3 = $row['subevent3']; $subevent4 = $row['subevent4']; $subevent5 = $row['subevent5']; $subevent6 = $row['subevent6']; $subevent7 = $row['subevent7']; $subevent8 = $row['subevent8']; } if (!empty($title1)) { $message .= "<br/>$title1"; } if (!empty($title2)) { $message .= "<hr><br/>$title2" ; } if (!empty($title3)) { $message .= "<hr><br/>$title3"; } if (!empty($title4)) { $message .= "<hr><br/>$title4"; } if (!empty($title5)) { $message .= "<hr><br/>$title5"; } if (!empty($title6)) { $message .= "<hr> <br/>$title6"; } if (!empty($title7)) { $message .= "<hr><br/>$title7"; } if (!empty($title8)) { $message .= "<hr><br/>$title8"; } echo "</div>"; ?> <?php $message .=" </th> </tr> <tr> <th>Price:</th> <th> $ $total </th> </tr>"; ?> <?php $message .=" <tr> <th>Registrant:</th> <th> $name </th> </tr> </table>"; ?> <?php $message .=" <div id='pic'> <img src=\"http://final.net46.net/button/boyscout.jpg\"> <div id='apDiv2'>$name <p> </p> <p> </p> <p><a href='final.net46.net' target='_new'><strong>Troop 78 Home</strong></a></p> <p> </p> <p> </p> <p><strong><a href='http://www.cornhuskercouncil.org'>Cornhusker Council</a></strong></p> <p> </p> <p> </p> <p> </p> <p> </p> <p> </p> <p> </p> </div> </div> </body> </html>"; ?> <?php // end of message $headers = "From: $from\r\n"; $headers .= "Content-Type: text/html\r\n"; $to = "$to"; // Finally send the activation email to the member mail($to, $subject, $message, $headers);I would like this image <img src=\"http://final.net46.net/button/boyscout.jpg\"> to be the background.............and everything else is layered on top of that.........how can I do this? Well here is the original code in my script file, and it has a background color Green now: [/php]$article_content = "<center><table style='color: #FFFF31; background: Green; width: 400px; border: 1px solid #9BDDFF;'><tr><td><i><b><u>Welcome to Mysidia City's fishing pool</b></u></i><br><br><br> Before you actually begin your fishing career, I'd strongly recommend you to doublecheck if you have a fishing rod already since it is apparently required for every fisherman here. <br><br><br><a href='fishing.php?act=1'>Enter</a> the fishing pool now if you have a fishing rod already or <br>Visit this <a href='fishingquiz.php'>Page</a> to take the fishing quiz and earn yourself an old rod to begin with. <td></tr></table><br><center><img src='picuploads/other/lakeofrage.png'></center>";[/php] Now I wish to replace the background color with a background image, what should I do? The image url is provided below: http://www.pokemansion.net/picuploads/other/seadrabg.png Hi, I've making a script that's almost a todo list, and i want to have 3 colors to the posts. Post under 7 days old should be green, and thoose older then 7 days yellow and over 14 days should be red. How could i do that? Every post i timestamp when stored in my MYSQL table. Here is my code: Code: [Select] <?php $servername='localhost'; $dbusername='root'; $dbpassword=''; $dbname='store'; connecttodb($servername,$dbname,$dbusername,$dbpassword); function connecttodb($servername,$dbname,$dbuser,$dbpassword) { global $link; $link=mysql_connect ("$servername","$dbuser","$dbpassword"); if(!$link){die("Could not connect to MySQL");} mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error()); } $result = mysql_query("SELECT * FROM henvendelser ORDER by id desc ") or die(mysql_error()); echo "<table cellspacing='12px' cellpaddomg='5px' align='center'>"; echo "<tr> <th>ID</th> <th> Opprettet </th> <th>Navn</th> <th>Telefon</th> <th>Emne</th> </tr>"; while($row = mysql_fetch_array( $result )) { echo "<tr> <td>"; echo $row['id']; echo "</td> <td>"; echo date("d.m.y", strtotime($row["date"])); echo "</td> <td>"; echo "<a href=\"detaljer.php?view=$row[id]\">$row[Navn]</a>"; echo "</td> <td>"; echo $row['Telefon']; echo "</td> <td>"; echo $row['Emne']; echo "</td> </tr>"; } echo "</table>"; ?> This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=347058.0 Hi all! First off, sorry if this question is a completely dumb one but i'm really new to PHP. I'll paste the code to start with... function getReasons ($id) { global $link; $rst = mysql_query('SELECT r.name as reason FROM entries_feedback_comments as f LEFT JOIN reasons as r ON r.id = f.reason_id WHERE f.feedback_id ='. $id, $link); while ($row = mysql_fetch_assoc($rst)) { echo $row['reason']; } } later on in the code.... inside a table structure i do this... echo '<tr class="' . ($y?'even':'odd') . '">'; echo '<td colspan="10" class="freetext">'.getReasons($row['id']).'</td>'; echo '</tr>'; echo '<tr class="' . ($y?'even':'odd') . '">'; echo '<td colspan="10" class="freetext">'.$row["freetype"].'</td>'; echo '</tr>'; (I have left put the "freetype" bit of code in to show you that it works with this row but not with the function). Basically, what I see is the result of the function outside of the table itself rather than in the table row. Is there a reason for this? Does a function have to be put in specific places in the code? Thank you for your help. Sam Im messing around with functions and arrays but cant seem to get this to work. It basically creates a simple table with the parameters you specify. The array however doesnt go into the table properly. function asf_create_table($rows, $cols, $border=1, $padding=5, $td_border=1, $contents) { $table = "<table style=\"border: {$border}px solid; padding:{$padding}px;\">"; for ($t_rows=0; $t_rows<$rows; $t_rows++) { $table .= "<tr>"; } for ($t_cols=0; $t_cols<$cols; $t_cols++) { for ($i=0; $i<$cols; $i++) { $table .= "<td style=\"border: {$td_border}px solid;\">"; $table .= $contents[$i]; $table .= "</td>"; } } for ($t_rows=0; $t_rows<$rows; $t_rows++) { $table .= "</tr>"; } $table .= "</table>"; echo $table; } $t_contents = array("Cell 1", "Cell 2", "Cell 3", "Cell 4"); asf_create_table("4", "4", "1", "5", "1", $t_contents); instead of 4 cells each with Cell # in them i get 16 cells with the cell #. the 4 displayed 4 times.
Looking for help with a small task for my weather station website.
Want to see on my website a table with current temperature or other types of measurements for each hour. A small fee is usually given.
the website:
Examples of desired solutions:
Trying to run this function so it displays the generated image in a table cell - Code: [Select] <?php function imgsecuregen($size = 6){ $width = 11*$size; $height = 25; $string = ""; for($i = 1; $i <= $size; $i++){ $string .= rand (0,9).""; } // for $im = ImageCreate($width, $height); $bg = imagecolorallocate($im, 102, 102, 102); // background $black = imagecolorallocate($im, 0, 255, 0); // text $grey = imagecolorallocate($im, 102, 102, 102); // border imagerectangle($im,0, 0, $width-1, $height-1, $grey); imagestring($im, 5, $size, 5, $string, $black); imagepng($im); imagedestroy($im); } imgsecuregen(8); // string length ?> Works if I load it directly, but not in a <td>. Hi, I'm trying to build a 'simple' page to improve a process where I work.
I'm wanting to do this.
Read either the last line, the last 10 lines, or something I decide on from a log and display the output in table rows and columns.
I've done this before with loops and db query's, but don't know how to approach it using php only as this is the first time I'm using it.
So right now I have this in a table but it will only display one row.
<tr><td colspan="5"> Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; Hello all, I have some piece of code that is nested like this $variable = 'This is a global argument'; function parentFunction($variable) { function childFunction() { echo 'Argument of the parent function is '.$GLOBALS['variable']; } childFunction(); } parentFunction(5); What I want to know is - Is there a way to access a variable from the parent function without passing arguments to the child function? (Something like how classes have parent::?). I don't want to use $GLOBALS because it might cause some variable collision, and I didn't want to pass arguments because incase I decide to change the arguments in the parent function I'd have to do it in the child function aswell. From my searching around in the Internet it seems like this is not possible, but if theres a slight chance that there might be something out there, i'm willing to give it a shot . Thanks in advance I have this function completely written in my class file that I am working on. The point to this function is to be able to check the login of a user or administrator for either of the control panels associated with my site. It will check the session intime as well as the page / module referenced. Once it passes all those checks, it will check and ensure the emailaddress/password stored in the current session still holds true and the account is still active... if the account is still active it will update the lastActivity as well as update all of the session variables with what is currently in the database. What I am looking for is basically a look at the function, see if it looks good.. If there is any part to it that could create security holes for the site just off the login function itself... Usage: $q->validUser($_SESSION['user'], $_mod); <?php function validUser($sess, $p) { if ($sess['inTime'] == '' && $p != 'login' && $p != 'logout') { session_destroy(); $login = '0'; $_int = ''; return $login; } else if ($sess['inTime'] < time()-3600 && $p != 'login') { $sess['inTime'] = ''; session_destroy(); $this->check_login($sess, $p); } else { $this->user = $sess['emailAddress']; $this->pass = $sess['password']; $login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' AND status = '1' LIMIT '1'"); if ($login = $this->sql_numrows($login) < 1) { $sess['inTime'] == ''; session_destroy(); $login = '0'; } else { // logged in, lets update the database for last_activity AND the session. $this->sql_query("UDATE users SET lastActivity = '".now()."' WHERE emailAddress = '".$this->user."'"); $login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' AND status = '1' LIMIT '1'"); $login = mysql_fetch_assoc($login); foreach ($login as $key => $value) { $sess[$key] = $value; } $sess['inTime'] = time(); $login = '1'; } return $login; } } ?> That is the main function, sql_query and sql_numrows is: <?php function sql_query($query = "", $transaction = FALSE) { unset($this->query_result); if ($query != "") { $this->num_queries++; if ($transation == BEGIN_TRANSACTION && !$this->in_transation) { $result = mysql_query("BEGIN", $this->db_connect_id); if (!$result) { return false; } $this->in_transaction = TRUE; } $this->query_result = mysql_query($query, $this->db_connect_id); } else { if ($transaction == END_TRANSACTION && $this->in_transaction ) { $result = mysql_query("COMMIT", $this->db_connect_id); } } if ($this->query_result) { unset($this->row[$this->query_result]); unset($this->rowset[$this->query_result]); if ($transaction == END_TRANSACTION && $this->in_transaction ) { $this->in_transaction = FALSE; if (!mysql_query("COMMIT", $this->db_connect_id)) { mysql_query("ROLLBACK", $this->db_connect_id); return false; } } return $this->query_result; } else { if ($this->in_transaction ) { mysql_query("ROLLBACK", $this->db_connect_id); $this->in_transaction = FALSE; } return false; } } function sql_numrows($query_id = 0) { if(!$query_id) { $query_id = $this->query_result; } return ($query_id) ? mysql_num_rows($query_id) : false; } ?> Any insight that can help to benefit these functions would be appreciated. Question 1) Is the only and proper way to call a parent function "parent::function()"? Are there other/better ways from within a child function? Question 2) What are the deciding factors for when to make a function or attribute static? How do you make that decision? Assuming 5.3... Thanks. I need to call usort from a class function, and I'm puzzled about how to define the comparison function. I've tried to define the comparison function in the same class, but I can't get usort to call it. I found one hint that it will work if I make the comparison function static, but I tried that, and it didn't work for me. If I define the comparison function outside the class, it won't have access to object properties that it needs to operate. The only solution I can think of is to define the comparison function outside the class and put the object properties it needs in globals. Is there a cleaner way to do this? I want to define a function instead of repeating query in all my php pages. I call a function by passing an $id value and from that function i have to get all the info related to that id, like name, description and uom.
I am trying to do this, but i dont know how to get these values seperately.
here is my function
function items($item_id) { $details = array(); $result = mysql_query("select item_id, name, uom, description from items where item_id=".$item_id."") or die (mysql_error()); while($row = mysql_fetch_array($result)) { $details[] = array((stripslashes($row['name'])), (stripslashes($row['uom'])), (stripslashes($row['description']))); } return $details; }and i call my function like this $info = items($id);Can somebody guide me in this When I put this chunk of code into it's own function: function fetch_all ($dbc, $query) { include ('knuffix_list_func.php'); pagination_start ($dbc, $query); $offset = $pag_array[0]; $rows_per_page = $pag_array[1]; $query = $query . " LIMIT $offset, $rows_per_page"; echo "test query: " . $query; knuffix_list ($query, $dbc); pagination_end ($pag_array); } And when I echo out the query as you can see in the example, then I notice that the variables $offset and $rows_per_page never get appended. I set the variable $pag_array to a global inside the function pagination_start(). It usually works when I DON'T wrap a function around this chunk of code, but if I do wrap a function around everything then the global suddenly won't work anymore. Btw, this also won't work if I wrap a function around the function DECLARATIONS. Any ideas, how I could make it work? Hi all, I want to call a javascript function from a php function like this: public function Buscar() { $HoraInicio = $_POST['edtHoraInicio']; $HoraFin = $_POST['edtHoraFin']; $FechaInicio = $_POST['edtFec1']; $FechaFin = $_POST['edtFec2']; $FechaMax = $FechaFin." ".$HoraFin.":00"; $FechaMin = $FechaInicio." ".$HoraInicio.":00"; $_GET["FechaMax"] = $FechaMax; $_GET["FechaMin"] = $FechaMin; echo $FechaMin; echo "<script language=javascript>alert('Hi.')</script>"; } but the function Buscar never show the alert but shows the $FechaMin I hopu u guys can help me out with this probem Thanks, Siddhartha Hi I have a table class and functions I want to call in another function but can't get it working. Some help will be very welcome. It seesm that the new table class is not working in this function if I pass the values to it, I have tested the class, it does get the post values I post to it so $_POST['id'] are being received as well as all the other $_POST's but the table class and find function is not working, it works fine if I don't put it in a function.. function edit() { if (isset($error)){ $error.="Please fix the error(s) above";} else { if ($_POST['id'] <> "") { $update =& new table($db, 'publisher'); $update->find($_POST['id']); $update->name = $_POST['name']; $update->url = $_POST['url']; $update->contact = $_POST['contact']; $update->address = $_POST['address']; $update->phone = $_POST['phone']; $update->email = $_POST['email']; $update->save(); $error = "The Publisher has been edited"; } } } im using a function which connects to a db called 'comments' and then inside that function i again called another function that will connect to the db 'main' to get avatars.... but as i put Code: [Select] mysql_select_db("main") or die(mysql_error()); on the new function, the original function stops to fetch rows. i tried to remove "mysql_select_db("main") or die(mysql_error());" and used the new function to return some text only and it worked, so i guess the connection to the db was the problem... i tried doing Code: [Select] mysql_query("SELECT * FROM main.avatar INNER JOIN main.list ON main.avatar.title=main.list.id WHERE main.avatar.page_id='$id'"); but it also didnt work I've followed the PHP Freaks pagination tutorial which you can find here. And I also got it to work, the only problem is that the script won't work when I use the query outside of the function. Here's the function: <?php function knuffix_list ($query, $dbc) { // find out how many rows are in the table: $query_row = "SELECT COUNT(*) FROM con"; $query_run = mysqli_query ($dbc, $query_row); $row = mysqli_fetch_row($query_run); $num_rows = $row[0]; // number of rows to show per page $rows_per_page = 5; // find total pages -> ceil for rounding up $total_pages = ceil($num_rows / $rows_per_page); // get the current page or set a default if (isset($_GET['current_page']) && is_numeric($_GET['current_page'])) { // make it an INT if it isn't $current_page = (int) $_GET['current_page']; } else { // default page number $current_page = 1; } // if current page is greater than total pages then set current page to last page if ($current_page > $total_pages) { $current_page = $total_pages; } // if current page is less than first page then set current page to first page if ($current_page < 1) { $current_page = 1; } // the offset of the list, based on current page $offset = (($current_page - 1) * $rows_per_page); echo "test " . $query; // SCRIPT ONLY WORKS IF I INSERT QUERY HERE $query = "SELECT * FROM con, user WHERE con.user_id = user.user_id ORDER BY contributed_date DESC LIMIT $offset, $rows_per_page"; $data = mysqli_query ($dbc, $query) or die (mysqli_error ($dbc)); // Loop through the array of data while ($row = mysqli_fetch_array ($data)) { global $array; // Variables for the table $con_id = $row['con_id']; $likes_count = $row['likes']; $dislikes_count = $row['dislikes']; $dbuser_name = $row['nickname']; $dbuser_avatar = $row['avatar']; $user_id = $row['user_id']; // The TABLE echo "<table padding='0' margin='0' class='knuffixTable'>"; echo "<tr><td width='65px' height='64px' class='avatar_bg' rowspan='2' colpan='2'><img src='avatar/$dbuser_avatar' alt='avatar' /></td>"; echo "<td class='knuffix_username'><strong><a href='profile.php?user=$dbuser_name' title='Profile of $dbuser_name'>" . $dbuser_name . "</a> ___ " . $user_id . "____ <form action='' method='POST'><button type='submit' name='favorite' value='fav'>Favorite</button></form>"; echo "</strong><br />" . $row['category'] . " | " . date('M d, Y', strtotime($row['contributed_date'])) . "</td></tr><tr><td>"; echo "<form action='' method='post'> <button class='LikeButton' type='submit' name='likes' value='+1'>Likes</button> <button class='DislikeButton' type='submit' name='dislikes' value='-1'>Dislikes</button> <input type='hidden' name='hidden_con_id' value='" . $con_id . "' /> </form></td><td class='votes'>Y[" . $likes_count . "] | N[" . $dislikes_count . "]</td></tr>"; echo "<tr><td class='knuffix_name' colspan='3'><strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td colspan='2' class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "</table>"; // POST BUTTONS inside the table $likes = $_POST['likes']; $dislikes = $_POST['dislikes']; $con_id = $_POST['hidden_con_id']; $favorite = $_POST['favorite']; $array = array ($likes, $dislikes, $con_id, $user_id, $favorite); } /********* build the pagination links *********/ // BACKWARD // if not on page 1, show back links and show << link to go back to the very first page if ($current_page > 1) { echo " <a href='{$_SERVER['PHP_SELF']}?current_page=1'><<</a> "; // get previous page number and show < link to go to previous $prev_page = $current_page - 1; echo " <a href='{$_SERVER['PHP_SELF']}?current_page=$prev_page'><</a> "; } // CURRENT // range of number of links to show $range = 3; // loop to show links in the range of pages around current page for ($x = ($current_page - $range); $x < (($current_page + $range) + 1); $x++) { // if it's a valid page number... if (($x > 0) && ($x <= $total_pages)) { // if we're on current page if ($x == $current_page) { // highlight it but don't make a link out of it echo "[<b>$x</b>]"; // if it's not the current page then make it a link } else { echo "<a href='{$_SERVER['PHP_SELF']}?current_page=$x'>$x</a>"; } } } // FORWARD // if not on the last page, show forward and last page links if ($current_page != $total_pages) { // get next page $next_page = $current_page + 1; // echo forward link for next page echo " <a href='{$_SERVER['PHP_SELF']}?current_page=$next_page'>></a> "; // echo forward link for last page echo " <a href='{$_SERVER['PHP_SELF']}?current_page=$total_pages'>>></a> "; } /***** end building pagination links ****/ mysqli_close($dbc); } ?> As you can see above, the script will only work if I put the query right below the $offset variable and above the $data variable. I put the test echo above the query to see how the query looks like when I induce the query from the outside through the function parenthesis into the function, and this is what I get printed out: test SELECT * FROM con, user WHERE con.user_id = user.user_id ORDER BY contributed_date DESC LIMIT , Obviously the $offset and the $rows_per_page variables are not set, when I induce the query from the outside into the function. So in that sense my question is: How can I induce the query from the outside into the function SO THAT the $offset and the $rows_per_page variables are set as well and NOT empty? p.s. I need the query outside of the function because I'm using a sort by category functionality. |