PHP - Select By Count

Hello there,

Having a nightmare here.  It feels like what I need to do is really easy but I just can't get it to work.  I have a table called "groups2" that holds a unique id and the name of an activity.

I already have a query that finds the users selected groups using a while loop but I also want to show how many other members are in that group by counting the number of times the activity comes up or the id comes up.  I don't know whether I need 2 while loops nested or what but I get the error

Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource on line 32 which is highlighted.

Can anyone help.  I am no expert at php and still learning so some advice or example code would be great.


$result = mysql_query("SELECT * FROM groups2 WHERE L_ID = ". $_SESSION['member_ID'] .";");
$data = mysql_query("SELECT COUNT('name') AS num FROM groups2 WHERE name = " . $row['name'] . "");
$count = mysql_fetch_assoc($data);
$numbers = $count['num'];
while ( $row = mysql_fetch_assoc($result) ) {
echo("<tr>
<td><font face='Arial, Helvetica, sans-serif' size='3'><strong>" . $row["name"] . "</strong></font></td>
</tr><tr>
<td><font face='Arial, Helvetica, sans-serif' size='1' color='#0000FF'><strong>Members (" . $numbers . ")</strong></font></td>
</tr><tr>
<td><hr width=95%><br></td>
</tr>");
}

 $result = mysql_query("SELECT *  FROM `friend_system` WHERE `friend_system_accepter` = '$myusername' ");
echo mysql_num_rows($result);

This displays the total rows in the table.

$result = mysql_query("SELECT COUNT(friend_system_accepter)  FROM `friend_system` WHERE `friend_system_accepter` = '$myusername' ");
echo mysql_num_rows($result);

This displays '1', which is incorrect.   I want to echo out the number of rows where 'friend_system_accepter' = $myusername   Thanks

The code below is part of some validation code that I have, it is supposed to count the number of entries in the table 'test_selections' where 'userid' equals the user that is logged in and where the 'transfer_in' date is a date within the current month. I am getting an error saying "Error running query Unknown column '10' in 'where clause' ". Does anybody know why this could be? I am hoping that it is something to do with the snippet of code below so I don't need to post the whole lot!!

Any help would be much appreciated.

Code: [Select]
$current_month = date("m");
$query = "SELECT COUNT(`userid`) as `transfers_count`
          FROM `test_selections`
          WHERE `userid` = '{$_SESSION['userid']}' AND Month(`transfer_in`) = `$current_month`
          GROUP BY `userid`";

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=312721.0

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=305934.0

Hi guys,

I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this:

Code: [Select]
www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp

However i have got a error which i don't know how to fix it.


Error: Column count doesn't match value count at row 1


<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbusername');
    define('DB_PASSWORD', 'mydbpassword');
    define('DB_DATABASE', 'mydbname');

$errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {

die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
  $username = clean($_GET['user']);
    $password = clean($_GET['pass']);
    $adduser = clean($_GET['user1']);
    $email = clean($_GET['email']);
    $IP = clean($_GET['ip']);
    if($username == '') {
  $errmsg_arr[] = 'username is missing';
  $errflag = true;
    }
    if($password == '') {
  $errmsg_arr[] = 'PASSWORD is missing';
  $errflag = true;
    }
    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
   $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')";

if (!mysql_query($sql,$link))
  {
  die('Error: ' . mysql_error());
  }
echo "The information have been updated.";
  }
?>


Here's the name of the columns i have got in my database:

Code: [Select]
username
email
IP


I have input the correct columns names, so I can't correct the problem I am getting.

Please can you help?

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=331562.0

Why am I getting this error when there are 3 Fields with 3 values?

Column count doesn't match value count at row 1

Code: [Select]
$sql5="INSERT INTO participants (participant_name, team_no, sport)
VALUES ('".implode("','$_POST[team]'),('",$_POST['participant_name'])."','$_POST[team]','$sport')";

Anyone can help me?

<?php
$tbl_name="menu";
$kategorije = mysql_query("SELECT * FROM $tbl_name WHERE Left(menu_name, 1) BETWEEN 'A' AND 'M' ORDER BY menu_name ASC");
if (!$kategorije) {
die("Database query failed: " . mysql_error());
}

while ($row=mysql_fetch_array( $kategorije )) {
echo "<div id=lista-header><h4>{$row["menu_name"]}</h4></div>";
$id_sub=$row['id_menu'];
$podkategorije = mysql_query("SELECT * FROM submenu WHERE id_menu=$id_sub ORDER BY sub_name ASC", $connection);
if (!$podkategorije) {
die("Database query failed: " . mysql_error());
}
echo "<ul class=\"pod\">";
while ($pod=mysql_fetch_array( $podkategorije )) {
echo "<li><a href=index.php?=podkate?".$pod["id_sub"]." class=black>{$pod["sub_name"]}</a><hr size=1 align=left width=100px color=#cccccc></li>";
}
echo "</ul>";
}


?>

In this way, I get list with categories and hes subcategories. How to count how many subcategories have each categories, and count how many articles have each categories?

Example (I wanna get this kind of look):

Categories name (3)
subcategoriesname (2)
subcategoriesname (4)
subcategoriesname (7)

Categories name (5)
subcategoriesname (1)
subcategoriesname (14)
subcategoriesname (9)
subcategoriesname (2)
subcategoriesname (


Categories name (2)
subcategoriesname (28)
subcategoriesname (17)

Where the numbers represent how many categories and sub-items have articles

hirealimo.com.au/code1.php

this works as i want it:
Quote

SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1



but apparelty selecting * is not a good thing????

but if I do this:
Quote

SELECT priceID, price FROM price INNER JOIN vehicle....etc


it works but i lose the info from the vehicle table.

but how do i make this work:
Quote

SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc


so that i am specifiying which colums from which tables to query??

thanks

I have 2 queries that I want to join together to make one row  

hey i'm just woundering how i would go abouts on echoing unread messages sent to a user
i want to beable to see how many unread messages i have

Hello, I'm using the following code to count the amount of SQL results and divide it. Works great as is but I want to alter it so it works with categories.

$amount = mysql_query('SELECT COUNT(`car_id`) AS num FROM `tbl_cars`') or die(mysql_error());
$amount_row = mysql_fetch_assoc($amount);

I tried adding...

WHERE car_cat = '".$cat."'

which causes an error.

Why doesn't this work, and how can I get the amount of results as a variable?

Hey All,

I need to count and display the number of rows I have.


<?php

//declare the SQL statement that will query the database
$query = "
SELECT COUNT(id) FROM connectvisits
WHERE staffid = '$staffid'
 ";

//execute the SQL query and return records
$result = mssql_query($query);

$thismonth = mssql_num_rows($result);

echo "Total Meetings This Month: ";
echo $thismonth;
echo "<br />";

?>


For some reason I keep getting a result of 1. Everything else I try gives me a "Resource ID" number. Any help would be apprecaited. Maybe I have the completely wrong code. Thanks!