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PHP - Hidden Fileds
how would i retrieve a hidden field from this form
Code: [Select] $checkoutBtn .= '<form action="checkout.php" method="POST" id="checkform"> <input type="hidden" name="item_name_' . $x . '" value="' . $eventname . '"> <input type="hidden" name="amount_' . $x . '" value="' . $studentsprice . '"> <input type="hidden" name="quantity_' . $x . '" value="' . $each_item['quantity'] . '">;[ <input type="hidden" name="custom" value="' . $product_id_array . '"> <input type="submit" class="checkoutbtn" name="checkoutbtn" value="CHECKOUT" /> </form>'; /code] Similar TutorialsHi dear freaks i want to create an adressbook with MySQL. At the moment i do not know how many fields i need. i want to be flexible with that - at least in the next days... Untill i am sure how many fields i really would need. i have found a Dump that allready is build for a Adressbook - i found this one in the internet. http://www.apachefriends.org/f/viewtopic.php?f=14&t=26305&start=0&sid=633a3f317b08dc6d8e555a81ed10538f&view=print # phpMyAdmin SQL Dump # version 2.5.7-pl1 # http://www.phpmyadmin.net # # Host: localhost # Erstellungszeit: 04. September 2007 um 16:37 # Server Version: 4.0.20 # PHP-Version: 4.3.7 # # Datenbank: `joels` # # -------------------------------------------------------- # # Tabellenstruktur f�r Tabelle `address_book` # CREATE TABLE `address_book` ( `address_book_id` int(11) NOT NULL auto_increment, `customers_id` int(11) NOT NULL default '0', `entry_gender` char(1) NOT NULL default '', `entry_company` varchar(32) default NULL, `entry_firstname` varchar(32) NOT NULL default '', `entry_lastname` varchar(32) NOT NULL default '', `entry_street_address` varchar(64) NOT NULL default '', `entry_suburb` varchar(32) default NULL, `entry_postcode` varchar(10) NOT NULL default '', `entry_city` varchar(32) NOT NULL default '', `entry_state` varchar(32) default NULL, `entry_country_id` int(11) NOT NULL default '0', `entry_zone_id` int(11) NOT NULL default '0', PRIMARY KEY (`address_book_id`), KEY `idx_address_book_customers_id` (`customers_id`) ) TYPE=MyISAM AUTO_INCREMENT=2 ; can i use this - and can i easily add more fields... ? lookforward to hear from you Regards db1 Ok so standard query can be written as: SELECT * FROM my_table WHERE specific_field = 'some_term' Is there some query that I can search for 'some_term' in all the fields at once in my_table without defining them in the query? SELECT * FROM my_table WHERE any_field = 'some_term' This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=317025.0 Code: [Select] <td > <form action="" method="post"> <b> <?php echo $likes_count; ?> </b> <b> | </b> <b> <?php echo $dislikes_count; ?> </b> <button class="LikeButton" type="submit" name="likes" value="+1">Likes</button> <button class="DislikeButton" type="submit" name="dislikes" value="-1">Dislikes</button> <input type="hidden" name="hidden_con_id" value="<?php echo $con_id; ?>" /> </form> <?php echo $con_id; ?> </td> I have a table with a voting system and the problem I am experiencing is that the hidden id, which I call the hidden contribution id is not set thus the numeric array changes. I know that it is not best practice to use a numeric array for this, though I learned that afterwards. This is the array: Code: [Select] // POST BUTTONS inside the table if (isset($_POST['likes'])) { $likes = $_POST['likes']; } if (isset($_POST['dislikes'])) { $dislikes = $_POST['dislikes']; } if (isset($_POST['likes']) || isset($_POST['dislikes'])) { $hidden_con_id = $_POST['hidden_con_id']; } // $array = array ($likes, $dislikes, $con_id, $user_id); if (isset($likes)) { $array[] = $likes; } if (isset($dislikes)) { $array[] = $dislikes; } if (isset($hidden_con_id)) { $array[] = $hidden_con_id; } if (isset($dnuser_id)) { $array[] = $dnuser_id; } As said the problem I have is that the hidden_con_id variable is not set and that consequently array[2] becomes the user_id variable. Any suggestions why it is not becoming set? hi , when I use hidden input tag and save there information to send with the form , is that secure? I mean , if the user or hacker or anything can change the value of the hidden tag? thanks , Mor. Hey all, i have a little problem. I have a form, and when submitting, i need to use the ID that i put in the $_GET array earlier. When you're entering my site, and clicks a certain link, the $_GET will store show=1, and when you're submitting the form on the page, the value of 'show' is needed on the redirect page.. I thought that it would be smart to transfer it with a hidden textfield, but somehow it fails? <form id="comment-form" action="comment_profile.php" method="POST"> <fieldset> <div class="field"> <textarea name="comment-field" rows="2" cols="66"></textarea> <input type="hidden" name="pofileid-field" value="<?php echo $_GET['show']; ?>" /> // <--- Here is the hidden field. <input type="submit" name="submit-field" class="submit" value=""/><i> (HTML tags kan bruges)</i> </div> </fieldset> </form> Above you can see a piece of my code, and i marked the hidden field aswell. What i do not understand is, why isn't the hidden fields value return the value of show when i check in comment_profile.php, as that is where it returns? Thanks in advance -Niixie I have a menu that i want to be added to every page of my coding using a hidden variable, but i cannot get it to work. I using this with a few if conditions. the index page should navigate every page. can anyone help? I have attached the files to illustrate the coding i have done so far. [attachment deleted by admin] This is just a snippet of my code. The php script itself is called test.php and so it calls itself once the form is submitted. I keep having problems retrieving the data back correctly; I am testing in retrieving the data on the same script from the same page before retrieving the POST data from another webpage. If $decimalSum is a variable that assigns a value that is hard-coded then I would be able to retrieve the same value. However, if the value is computed I can not retrieve it unless I click on the "Find" button twice. This is such a strange behavior and I don't know why. Does anyone have any suggested solutions to this? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <?php echo '<form enctype="multipart/form-data" method="post" action="test.php">'; echo ' <label for="_firstName">First name : </label>'; echo ' <input type="text" id="_firstName" name ="_firstName">'; echo ' <input type="checkbox" value="1" name="_firstNameChecked"/>'; echo ' <label for="_middleName">Middle name : </label>'; echo ' <input type="text" id="_middleName" name ="_middleName">'; echo ' <input type="checkbox" value="1" name="_middleNameChecked" />'; echo ' <label for="_lastName">Last name : </label>'; echo ' <input type="text" id="_lastName" name ="_lastName">'; echo ' <input type="checkbox" value="1" name="_lastNameChecked" />'; echo '<br />'; echo '<input type="submit" name="Find" value="Find" />'; $firstNameChecked = intval(($_POST['_firstNameChecked'])); $middleNameChecked = intval(($_POST['_middleNameChecked'])); $lastNameChecked = intval(($_POST['_lastNameChecked'])); $decimalSum = (int)((2*2*2)*$firstNameChecked + (2*2)*$middleNameChecked + (2*1)*$lastNameChecked); //$decimalSum = 28; echo '<br />'; echo '$decimalSum = ' . $decimalSum . '<br />'; echo '<input type="hidden" name="_decimalSum" value = "' . $decimalSum . '" />'; $decimalSum2 = ($_POST['_decimalSum']); echo '$decimalSum2 = ' . $decimalSum2 . '<br />'; echo '</form>'; echo '</body>'; echo '</html>'; ?> I have a while loop that fetches data from the database and prints it out organized in a table. Now I want to implement a voting functionality, the problem I'm encountering is, once I've printed out a list of tables one table after other with the while loop I need to figure out a way to tell the query TO WHICH of those tables to ADD or SUBTRACT the vote. I thought of implement a hidden id field into the while loop of contributions, the id field would be fetched from the auto_increment field in the contribution table in the MySQL database. Since the id field is unique there can be no misunderstandings to which table to add the vote. My question how can I do exactly that? How can I add a hidden id field to the while loop with the table WHICH I then can pass along to the voting script. Here's the while loop: while ($row = mysqli_fetch_array($data)) { echo "<table padding='0' margin='0' class='knuffixTable'>"; echo "<tr><td width='65px' height='64px' class='avatar_bg' rowspan='2' colpan='2'><img src='$avatar_path' alt='avatar' /></td><td class='knuffix_username'><strong>" . $user_name; echo "</strong><br />" . $row['category'] . " | " . date('M d, Y', strtotime($row['contributed_date'])) . "</td></tr><tr><td>"; echo "<form action='' method='post'> <input type='submit' name='plusVote' value='Y' /> <input type='submit' name='minusVote' value='N' /> </form></td><td class='votes'>Y[ - ] | N[ - ]</td></tr>"; echo "<tr><td class='knuffix_name' colspan='3'><strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td colspan='2' class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "</table>"; } If I simply add $row['con_id'] it's obviously going to be echo'd out, what is the right practice to have it hidden? I have created a form which allows people to add data to a database. However, I want to replicate the form across several pages and give each page a category. For example, if I have a website based on sport. I have a page which enters information into the baseball category, a page which enters information into the ice hockey category, a page which enters information into the soccer category etc. Can someone advise how I would do this? Hello, My question is how to send values over and over without using forms or even hidden forums. I have tried to use sessions but it didn't work out for me. Any suggestions! Is there anything wrong (or insecure) with using hidden form fields? I am working on a page where the user can choose one of 4 different subscription options. The approach I was going to use is to have a separate form for each plan, and when the user chooses one, submit a hidden form value so my script knows which subscription plan to grab out of the database. Thoughts? Hi I have an index.php with three drop down boxes on, each drop down uses an SQL statement to pull seatNumber from 'seats' each seat number has a UI and a forgein key field called SrideID. I have the buttons on the dorp down boxes going to dd-check.php, here the seat chosen is posted and a simple echo(just testing it works atm) for me to do any queries I also need the SrideID within the dropdown box, i tried adding it within the <option></option> but it only made the drop down duplicate. 1 1 2 2 3 3 ect..... what i would like is for the SrideID field to be included with in the dropdown box but hidden so i can post it to the dd-check.php and then show the time and price of that particular ride. here is the table and the code so far. Thanks for any help. CREATE TABLE `ride` ( `RrideID` tinyint(1) default NULL, `name` varchar(20) default NULL, `time` tinyint(1) default NULL, `price` varchar(4) default NULL ) INSERT INTO `ride` VALUES (1, 'Swinging Ship', 7, '2.50'); INSERT INTO `ride` VALUES (2, 'Roller Coaster', 5, '3.75'); INSERT INTO `ride` VALUES (3, 'Ice Blast', 4, '3.00'); CREATE TABLE `seats` ( `seatID` int(8) NOT NULL default '0', `SrideID` tinyint(1) default NULL, `seatNumber` int(2) default NULL, PRIMARY KEY (`seatID`) ) INSERT INTO `seats` VALUES (1, 1, 1); INSERT INTO `seats` VALUES (2, 1, 2); INSERT INTO `seats` VALUES (3, 1, 3); INSERT INTO `seats` VALUES (4, 1, 4); INSERT INTO `seats` VALUES (5, 1, 5); INSERT INTO `seats` VALUES (49, 2, 1); INSERT INTO `seats` VALUES (50, 2, 2); INSERT INTO `seats` VALUES (51, 2, 3); INSERT INTO `seats` VALUES (52, 2, 4); INSERT INTO `seats` VALUES (53, 2, 5); INSERT INTO `seats` VALUES (69, 3, 1); INSERT INTO `seats` VALUES (70, 3, 2); INSERT INTO `seats` VALUES (71, 3, 3); INSERT INTO `seats` VALUES (72, 3, 4); INSERT INTO `seats` VALUES (73, 3, 5); code for index.php <table width="200" border="1"> <tr> <h1>Swinging Ship</h1> <?php echo '<form method="post" name="f1" action="dd-check.php">'; $query_s = "SELECT * FROM `seats` WHERE SrideID='1' ORDER BY seatID"; $result = mysql_query($query_s); echo"<select name='seatNumber'><option value=''>Select Seat</option>"; while( $row = mysql_fetch_array($result) ) { echo '<option>'.$row['seatNumber'].'</option>'; } echo '</select>'; mysql_free_result( $result ); echo "<input type='submit' value='Submit'>"; echo "</form>"; ?> </tr> <tr> <h1>Roller Coaster</h1> <?php echo '<form method="post" name="f2" action="dd-check.php">'; $query_r = "SELECT * FROM `seats` WHERE SrideID='2' ORDER BY seatID"; $result = mysql_query($query_r); echo"<select name='seatNumber'><option value=''>Select Seat</option>"; while( $row = mysql_fetch_array($result) ) { echo '<option>'.$row['seatNumber'].'</option>'; } echo '</select>'; mysql_free_result( $result ); echo "<input type='submit' value='Submit'>"; echo "</form>"; ?> </tr> <tr> <h1>Ice Blast</h1> <?php echo '<form method="post" name="f3" action="dd-check.php">'; $query_i = "SELECT * FROM `seats` WHERE SrideID='3' ORDER BY seatID"; $result = mysql_query($query_i); echo"<select name='seatNumber'><option value=''>Select Seat</option>"; while( $row = mysql_fetch_array($result) ) { echo '<option>'.$row['seatNumber'].'</option>'; } echo '</select>'; mysql_free_result( $result ); echo "<input type='submit' value='Submit'>"; echo "</form>"; ?> </tr> </table> code for dd-check.php <?php $result=$_POST['seatNumber']; echo " <p> the seat choosen is : $result <p> "; //TEST PULL ALL QUERY $testPullAll = mysql_query("SELECT * FROM ride"); echo "<table border='1'> <tr> <th>Name</th> <th>Duration</th> <th>Price</th> </tr>"; while($row = mysql_fetch_array($testPullAll)) { echo "<tr>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['time'] . "</td>"; echo "<td>" . $row['price'] . "</td>"; echo "</tr>"; } echo "</table>"; ?> the end result will be a query in dd-check.php that says something like if [hidden SrideID = 1] echo 'the name, time and price of the ride' if [hidden SrideID =2 echo name, time and price if number 3 then echo the rest of the row. any help would be great, i've been using trial and error so far (since yesterday afternoon) with no success =( ps sorry for the long post, i wanted to try and explain everything the best i can. =) Hi Guys, Appreciate any help here please... Basically I want to hide some inputs on my registration page and populate them will default values. Everything works okay, apart from the input below: Code: [Select] <input type="hidden" name="seek_location" value="Anywhere"> When I use the above, the MYSQL database field for seek_location is left empty... I've noticed that the code below pulls the location into a dropdown list. You know the kind of thing, Australia, UK, USA etc etc: Code: [Select] $seek_location = $wcr[$seek_location]; Code: [Select] <? $p=0;asort($wcr);reset($wcr); while (list ($p, $val) = each ($wcr)) { echo '<option value="'.$p.'">'.$val; } ?> So, all I want to do is have: Code: [Select] <input type="hidden" name="seek_location" value="Anywhere"> Populate seek_location with Anywhere Any help appreciated Thanks Rob Hello everyone, I have a question. I'm trying to figure out a way to make it so that when a user visits a page for a certain file, they are given the file to download but can't see the link to that file. Example: There is a file on http://serverB.com/file.rar A person goes to http://serverA.com/?file=file.rar They can download http://serverB.com/file.rar without seeing the link to that file. Is there any way to do this? Thanks. This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=342456.0 If I store a value in a hidden form control, and then use that as a means to pass the value to another PHP script, could that cause any security issues?
so I have this code: Code: [Select] <input type='checkbox' name='title8' value='$title8' /></td><td><strong>$title8</strong> <br /> $date8 <br />$ $price8<input type='hidden' name='price8' value='$price8'> how do I make is so that the hidden field is only going to submit if the checkbox is checked........
Customers visit a "select merchandise page." Question: Is using 2 forms and hidden inputs the secure and accepted way to do this?
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<form method="post" action="<?=$SERVER['PHP_SELF']?>"> When finished, click here to create Packing Slip:
<form method="post" action="finished.php"> Thank you!!
i have the following code: <li>Have you read the <?php echo link_to('FAQ','util/faq') ?> ? <select id="yesnolist" onChange="getChoice(this.value)"> <option value="yes" selected="selected">Yes</option> <option value="no">No</option> </select> </li> <input type="hidden" name="text" size=30 id="yesandno"> <?php if ($_GET['yesandno'] == "no") { echo "anything!!!!!!!!!!!!!!!!!!!"; } ?> then my java script for getCoice(): function getChoice(val) { yesNo = new Array("Yes", "No"); var getsel = document.contactus.yesnolist.value; var e = document.getElementById("yesnolist"); var strUser = e.options[e.selectedIndex].value; document.contactus.yesandno.value = strUser; alert(document.contactus.yesandno.value); return strUser; } my alert will gove yes or no depending on what i chose in the dropdown but HOWCOME it does not go into the if ($_GET['yesandno'] == "no") ???? please help??? |
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