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PHP - Add Parameter To Php Class?
I have a pagination class that uses PHP_SELF to display the proper URLs when generating the pagination buttons. I need PHP_SELF to be a class parameter so that if the page is not defined in the parameter, then use PHP_SELF. The reason for this is because I generate the class in an ajax file and it is returning the URL of the ajax file, not of the page I am running the ajax on. I just don't know how to add the parameter to the class.
The class is below: Code: [Select] <?php class Paginator{ var $items_per_page; var $items_total; var $current_page; var $num_pages; var $mid_range; var $low; var $high; var $limit; var $return; var $default_ipp; var $querystring; function Paginator() { $this->current_page = 1; $this->mid_range = 7; $this->items_per_page = (!empty($_GET['ipp'])) ? $_GET['ipp']:$this->default_ipp; } function paginate($default_ipp) { if((isset($_GET['ipp'])) && ($_GET['ipp'] == 'All')) { $this->num_pages = ceil($this->items_total/$default_ipp); $this->items_per_page = $default_ipp; } else { if(!is_numeric($this->items_per_page) OR $this->items_per_page <= 0) $this->items_per_page = $default_ipp; $this->num_pages = ceil($this->items_total/$this->items_per_page); } if(isset($_GET['page'])) { $this->current_page = (int) $_GET['page']; // must be numeric > 0 } if($this->current_page < 1 Or !is_numeric($this->current_page)) $this->current_page = 1; if($this->current_page > $this->num_pages) $this->current_page = $this->num_pages; $prev_page = $this->current_page-1; $next_page = $this->current_page+1; if($_GET) { $args = explode("&",$_SERVER['QUERY_STRING']); foreach($args as $arg) { $keyval = explode("=",$arg); if($keyval[0] != "page" And $keyval[0] != "ipp") $this->querystring .= "&" . $arg; } } if($_POST) { foreach($_POST as $key=>$val) { if($key != "page" And $key != "ipp") $this->querystring .= "&$key=$val"; } } if($this->num_pages > 1) { $this->return = ($this->current_page != 1 And $this->items_total >= 1) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$prev_page&ipp=$this->items_per_page$this->querystring\">« Previous</a> ":"<!--<span class=\"inactive\" href=\"#\">« Previous</span>-->"; $this->start_range = $this->current_page - floor($this->mid_range/2); $this->end_range = $this->current_page + floor($this->mid_range/2); if($this->start_range <= 0) { $this->end_range += abs($this->start_range)+1; $this->start_range = 1; } if($this->end_range > $this->num_pages) { $this->start_range -= $this->end_range-$this->num_pages; $this->end_range = $this->num_pages; } $this->range = range($this->start_range,$this->end_range); for($i=1;$i<=$this->num_pages;$i++) { if($this->range[0] > 2 And $i == $this->range[0]) $this->return .= " ... "; // loop through all pages. if first, last, or in range, display if($i==1 Or $i==$this->num_pages Or in_array($i,$this->range)) { $this->return .= (($i == $this->current_page) And (isset($_GET['page'])) And ($_GET['page'] != 'All')) ? "<a title=\"Go to page $i of $this->num_pages\" class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" title=\"Go to page $i of $this->num_pages\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> "; } if($this->range[$this->mid_range-1] < $this->num_pages-1 And $i == $this->range[$this->mid_range-1]) $this->return .= " ... "; } $this->return .= (($this->current_page != $this->num_pages And $this->items_total >= 1) //And ($_GET['page'] != 'All') ) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$next_page&ipp=$this->items_per_page$this->querystring\">Next »</a>\n":"<!--<span class=\"inactive\" href=\"#\">» Next</span>-->\n"; //$this->return .= ((isset($_GET['page'])) And ($_GET['page'] == 'All')) ? "<a class=\"current\" style=\"margin-left:10px\" href=\"#\">All</a> \n":"<a class=\"paginate\" style=\"margin-left:10px\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n"; } else { for($i=1;$i<=$this->num_pages;$i++) { $this->return .= ($i == $this->current_page) ? "<a class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> "; } $this->return .= "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n"; } $this->low = ($this->current_page-1) * $this->items_per_page; if(isset($_GET['ipp'])) { $this->high = ($_GET['ipp'] == 'All') ? $this->items_total:($this->current_page * $this->items_per_page)-1; $this->limit = ($_GET['ipp'] == 'All') ? "":" LIMIT $this->low,$this->items_per_page"; } else { $this->high = ($this->current_page * $this->items_per_page)-1; $this->limit = " LIMIT $this->low,$this->items_per_page"; } } function display_items_per_page() { $items = ''; $ipp_array = array(10,25,50,100,'All'); foreach($ipp_array as $ipp_opt) $items .= ($ipp_opt == $this->items_per_page) ? "<option selected value=\"$ipp_opt\">$ipp_opt</option>\n":"<option value=\"$ipp_opt\">$ipp_opt</option>\n"; return "<span class=\"paginate\">Items per page:</span><select class=\"paginate\" onchange=\"window.location='$_SERVER[PHP_SELF]?page=1&ipp='+this[this.selectedIndex].value+'$this->querystring';return false\">$items</select>\n"; } function display_jump_menu() { for($i=1;$i<=$this->num_pages;$i++) { $option .= ($i==$this->current_page) ? "<option value=\"$i\" selected>$i</option>\n":"<option value=\"$i\">$i</option>\n"; } return "<span class=\"paginate\">Page:</span><select class=\"paginate\" onchange=\"window.location='$_SERVER[PHP_SELF]?page='+this[this.selectedIndex].value+'&ipp=$this->items_per_page$this->querystring';return false\">$option</select>\n"; } function display_pages() { return $this->return; } } Similar TutorialsHello,
I recently posted here about an issue I was having with my database orientated products page.
I have now run into another problem where say if, /db.php was typed or /db.php?p=IDoNotExist was typed, it returns blank.
I have in my code the desired content to be displayed, but it just doesn't seem to want to make a show.
I was also wondering if it is possible to show different content for whatever the URL is, so for no parameter, the content about the products, and a non existent one, maybe "Product not found"?
Here is my code:
<?php
$db=mysql_connect ("localhost", "webwibco_charlie", "Hello123") or die ('I cannot connect to the database because: ' . mysql_error());
$mydb=mysql_select_db("webwibco_products");
include("header.php");
$status = htmlspecialchars( @$_GET ['p'] );
if ($status == "floorpuzzles") {
echo "<h1>Our Floor Puzzles</h1>";
$sql="SELECT ID, Name, Tags, Description, Category FROM products WHERE Category LIKE '%" . FloorPuzzles . "%'";
$result=mysql_query($sql);
while($row=mysql_fetch_array($result)){
$Name =$row['Name'];
$ID =$row['ID'];
$Description =$row['Description'];
echo "<div class=\"box\">";
echo "<h1>$Name</h1>";
echo "<div class=\"floorbox\"><a href=\"?p=$ID\"><img src=\"images/products/catalogue/big/floorpuzzles/$ID.jpg\" class=\"small\"></a></div>";
echo "<h2>$Description</h2>";
echo "</div>";
}
?>
<?
}else{
if ($status == $_GET["p"]) {
$sql="SELECT ID, Name, Tags, Description, Pieces, Size, Barcode, Category FROM products WHERE ID = '" . $_GET['p'] . "'";
$result=mysql_query($sql);
while($row=mysql_fetch_array($result)){
$Name =$row['Name'];
$ID =$row['ID'];
$Description =$row['Description'];
$Pieces =$row['Pieces'];
$Size =$row['Size'];
$Barcode =$row['Barcode'];
echo "<div class=\"1\">";
echo "<h1>$Name</h1>";
echo "<div class=\"bigbox\">";
echo "<div class=\"floorbox\"><img src=\"images/products/catalogue/big/floorpuzzles/$ID.jpg\" class=\"big\"></div>";
echo "</div>";
echo "</div>";
echo "<div class=\"2\">";
echo "<p>Puzzle Pieces: $Pieces</p>
<p>Puzzle Size: $Size</p>
<p>Barcode: $Barcode</p>";
echo "</div>";
}
}else{
?>
<?
echo"<h1>Our Products</h1>
<p>Our jigsaw puzzles are hand cut by skilled craftsmen and therefore each one is unique with self-correcting pieces. There is a strict quality control process at all stages by our highly experienced staff. The puzzles are durable and provide fun and excitement, enhancing learning and a child’s development.<p>
<p>All of our jigsaws are made using materials from sustainable resources grown in managed forests. Where possible we support companies in the UK and source our components locally, most of our suppliers are in the East Midlands, many in Derbyshire and Nottinghamshire. We keep packaging to a minimum and take our environmental and ethical responsibilities very seriously.</p>
<p>Reducing waste and recycling was a way of life for us before it became fashionable. We are constantly searching for new ideas and consult teachers when developing our jigsaws, which are often used within the national curriculum.</p>
<p>As well as making our own range, we manufacture for leading suppliers to the education market. Check for \"Made in Britain\" and it is probably made by us.</p>
<p>We have a wide variety of products available for viewing, from classic floor puzzles to innovative inset trays. You can take a look at all our products on this page, simply use the navigation buttons to your left.</p>";
}}
include("footer.php");
?>
The final echo is what I wish to be displayed on the URL without or with an invalid parameter.
Here is my site URL: http://www.webwib.co...saws/search.php (note that only the "Floor Puzzles" category has content within it).
Thank you in advance for assistance.
I have the following code just to insert a username and hashed password into the database but somehow I am getting this error and I couldn't find out where I am doing it wrong...can someone please give me a hand?
I tried it in two ways and both errors...
the first few lines are just connecting database which worked fine and a password.php so I can use password_hash() with my php version
$hash = password_hash('xx', PASSWORD_BCRYPT, array('cost' => 10));
$username = 'xx';
$insertQuery = $db->prepare("
INSERT INTO et_todo (username, password)
VALUES (:username, :hash)
");
$insertQuery->execute(array(
'username' => $username,
'password' => $hash
));
also tried
$hash = password_hash('xx', PASSWORD_BCRYPT, array('cost' => 10));
$insertQuery = $db->prepare("
INSERT INTO et_todo (username, password)
VALUES ('xx', :hash)
");
$insertQuery->execute(array(
'username' => 'xx',
'password' => $hash
));
I have mysqli object in Database class base: [color=]database class:[/color] class Database { private $dbLink = null; public function __construct() { if (is_null($this->dbLink)) { // load db information to connect $init_array = parse_ini_file("../init.ini.inc", true); $this->dbLink = new mysqli($init_array['database']['host'], $init_array['database']['usr'], $init_array['database']['pwd'], $init_array['database']['db']); if (mysqli_connect_errno()) { $this->dbLink = null; } } } public function __destruct() { $this->dbLink->close(); } } Class derived is Articles where I use object dBLink in base (or parent) class and I can't access to mysqli methods (dbLink member of base class): Articles class: require_once ('./includes/db.inc'); class Articles extends Database{ private $id, .... .... $visible = null; public function __construct() { // Set date as 2009-07-08 07:35:00 $this->lastUpdDate = date('Y-m-d H:i:s'); $this->creationDate = date('Y-m-d H:i:s'); } // Setter .... .... // Getter .... .... public function getArticlesByPosition($numArticles) { if ($result = $this->dbLink->query('SELECT * FROM articles ORDER BY position LIMIT '.$numArticles)) { $i = 0; while ($ret = $result->fetch_array(MYSQLI_ASSOC)) { $arts[$i] = $ret; } $result->close(); return $arts; } } } In my front page php I use article class: include_once('./includes/articles.inc'); $articlesObj = new articles(); $articles = $articlesObj->getArticlesByPosition(1); var_dump($articles); [color=]Error that go out is follow[/color] Notice: Undefined property: Articles::$dbLink in articles.inc on line 89 Fatal error: Call to a member function query() on a non-object in articles.inc on line 89 If I remove constructor on derived class Articles result don't change Please help me If a class has a constructor but also has a static method, if I call the static method does the constructor run so that I can use an output from the constructor in my static method? --Kenoli I have an existing instance of my class Database, now I want to call that instance in my Session class, how would I go about doing this? Hi Can you call Class A's methods or properties from Class B's methods? Thanks. Ok. I know you can pass the object of a class as an argument. Example: class A { function test() { echo "This is TEST from class A"; } } class B { function __construct( $obj ) { $this->a = $obj; } function test() { $this->a->test(); } } Then you could do: $a = new A(); $b = new B($a); Ok so that's one way i know of. I also thought that you could make a method static, and do this: (assuming class A's test is 'static') class B { function test() { A::test(); } } But that is not working. I'd like to know all possible ways of accomplishing this. Any hints are appreciated. thanks Hi, I need to be able to call a class based on variables. E.G. I would normally do: Code: [Select] $action = new pattern1() but i would like to be able to do it dynamicaly: Code: [Select] $patNum = 1; $action = new pattern.$patNum.() Im wondering if that's possible? If so what would the correct syntax be? Many Thanks. Hi people! class FirstOne{ public function FunctionOne($FirstInput){ //do stuff and output value return $value1; } } Then:- class SecondOne{ public function FunctionTwo($AnotherInput){ //do stuff and output value return $value2; } } What I want to know is this, if I want to use FunctionOne() in Class SecondOne do I do it like this:- (Assume as I have instantiated the first class using $Test = new FirstOne(); ) class SecondOne{ function SecondedFunction(){ global $Test; return $Test->FunctionOne(); } public function FunctionTwo($AnotherInput){ //do stuff and output value return $value2; } public function FunctionThree(){ //some code here $this->Test->SecondedFunction();<--I think as I can omit the $this-> reference } } My point is: Do I have to do it this way or is there way of having this done through __construct() that would negate the need for a third party function? I have a version working, I just think that it is a little convoluted in the way as I have done it, so I thought I would ask you guys. Any help/advice is appreciated. Cheers Rw I have two classes: ## Admin.php <?php class Admin { public function __construct() { include("Config.php"); } /** * deletes a client * @returns true or false */ function deleteClient($id) { return mysql_query("DELETE FROM usernames WHERE id = '$id'"); } } ?> ## Projects.php <?php class Projects { public function __construct() { include("Config.php"); $this->admin = $admin; $this->dataFolder = $dataFolder; } /** * Deletes a project * @returns true or false */ function deleteProject($id) { $root = $_SERVER['DOCUMENT_ROOT']; $theDir = $root . $this->dataFolder; $sql = mysql_query("SELECT * FROM projectData WHERE proj_id = '$id'"); while ($row = mysql_fetch_array($sql)) { $mainFile = $row['path']; $thumb = $row['thumbnail']; if ($thumb != 'null') { unlink($theDir . "/" . substr($thumb,13)); } unlink($theDir . "/" . substr($mainFile,13)); } $delete = mysql_query("DELETE FROM projectData WHERE proj_id = '$id'"); $getDir = mysql_query("SELECT proj_path FROM projects WHERE id = '$id'"); $res = mysql_fetch_array($getDir); rmdir($theDir . "/" . $res['proj_path']); return mysql_query("DELETE FROM projects WHERE id = '$id'"); } } ?> How can I call deleteProject() from within Admin.php? Hi! Code: [Select] $url = "http://www.youtube.com/watch?feature=player_embedded&v=IwPHy17Iu6E"; I have code Code: [Select] if (preg_match("/http:\/\/www.youtube.com\/watch\?v=([0-9a-zA-Z-_]*)(.*)/i", $url, $matches)) { return '<object height="'.$embed_height.'" width="'.$embed_width.'">'. '<param name="movie" value="http://www.youtube.com/v/'.$matches[1].'" />'. '<param name="wmode" value="transparent" />'. '<embed src="http://www.youtube.com/v/'.$matches[1].'&autoplay=1" type="application/x-shockwave-flash" wmode="transparent" height="'.$embed_height.'" width="'.$embed_width.'" />'. '</object>'; }How to remove feature=player_embedded& from $url ? Hi guys, please help me to solve my problem. i want to get the url parameter using /
for now i use index.php?category_id=14
how can i change the ?category_id=14 to index.php/14
thank you so much.
I do know how to do this but I am curious about whether or not there is a "preferred" way to do this. I know there are a couple ways to use a class (I'll call Alpha_Class) within another class (I'll class Beta_Class) Let's say we have this simple class (Beta_Class): class beta { function foo(){ } } If I wanted to use the Alpha Class within the Beta Class, I could any number of things. For example: class beta { function foo(){ $this->alpha = new alpha; //$this->alpha->bar(); } } Or you could simply use the $GLOBALS array to store instantiated objects in: $GLOBALS['alpha'] = new alpha; class beta { function foo(){ //GLOBALS['alpha']->bar(); } } You could even declare Alpha_Class as a static class and thus would not need to be instantiated: static class alpha { static function bar(){} } class beta { function foo(){ //alpha::bar(); } } Those are the only ways I can think of right now. Are there any other ways to accomplish this? I was wondering which way is the best in terms of readability and maintainability. Hi all, I have two classes. Registration and Connection. Inside a registration.php I include my header.php, which then includes my connection.php... So all the classes should be declared when the page is loaded. This is my code: registration.php: <?php include ('assets/header.php'); ?> <?php class registration{ public $fields = array("username", "email", "password"); public $data = array(); public $table = "users"; public $dateTime = ""; public $datePos = 0; public $dateEntryName = "date"; function timeStamp(){ return($this->dateTime = date("Y-m-d H:i:s")); } function insertRow($data, $table){ foreach($this->fields as $key => $value){ mysql_query("INSERT INTO graphs ($this->fields) VALUES ('$data[$key]')"); } mysql_close($connection->connect); } function validateFields(){ $connection = new connection(); $connection->connect(); foreach($this->fields as $key => $value){ array_push($this->data, $_POST[$this->fields[$key]]); } $this->dateTime = $this->timeStamp(); array_unshift($this->data, $this->dateTime); array_unshift($this->fields, $this->dateEntryName); foreach($this->data as $value){ echo "$value"; } $this->insertRow($this->data, $this->table); } } $registration = new registration(); $registration->validateFields(); ?> <?php include ('assets/footer.php'); ?> At this point I cannot find my connection class defined on another included/included page. $connection = new connection(); $connection->connect; config.php (included within header.php) <? class connection{ public $dbname = '**'; public $dbHost = '**'; public $dbUser = '**'; public $dbPass = '**'; public $connect; function connect(){ $this->connect = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass) or die ('Error connecting to mysql'); mysql_select_db($this->dbname, $this->connect); } } ?> Any ideas how to call it properly? I have a class in which I have a function called connection. I am now trying to call this function from another class, but it will not work. It works if I put the code in from the other function rather than calling it but that defeats the purpous. class locationbox { function location() { $databaseconnect = new databaseconnect(); $databaseconnect -> connection();{ $result = mysql_query("SELECT * FROM locations"); while($row = mysql_fetch_array($result)) // line that now gets the error, mysql_fetch_array() expects parameter 1 to be resource, boolean given //in { echo "<option>" . $row['location'] . "</option>"; } } }} How does one go about using one class inside another? For example, building a class that does some series of functions, and uses a db abstraction layer class in the process? Hey guys, I'm dealing a url that is similar to hxxp://domain/directory/?#{$id}. What I'm trying to do is extract $id from that. Its not available as a $_GET variable and $_SERVER['REQUEST_URI'] comes up as "/directory/?". Does anyone know how I could retrieve $id ? Thanks Hello I am experiencing some issues with a function and I cannot identify the problem. The function is not receiving any parameter. The URL values are passed correctly. I used echo to display the parameters outside the function and that worked. I also used echo to display the parameters inside the function and no parameter were displayed. So the function is not receiving parameters. Code: [Select] <?php $find = $_REQUEST['u_find']; $field = $_REQUEST['u_field']; $searching = $_REQUEST['u_search']; echo"(1a)$find, (1b)$field, (1c)$searching";//outside function function test_display($searching, $field, $find) { echo"(2a)$find, (2b)$field, (2c)$searching";//inside function } ?> Hi all
Is it possible to have a function with two parameters but and then check if one is passed before using it.
In this code here I want to remove spaces and change to lowercase.
If the $extra parameter is set I want to add that to the end of the string.
function className($nametoUse, $extra){ I am trying to create a simple voting form. Everything goes well until I submit and then I get a Warning: mysqli_error() expects exactly 1 parameter, 0 given on line 79 error. I am assuming it is not pulling the ID correctly but as I am new to php and mysqli I cannot exactly say if it the way the code is written or if I am calling the parameter incorrectly in the query. Again I am new to to this so please be gentle. Below is my code. It pulls the drop down list correctly and echo's correctly but I believe my post query to be a little out of wack. Could someone point me in the correct direction? It would be very appreciated.
<form action="businesstype_update.php" method="post">
<?php
if(isset($_POST['voteall'])){
$vote_lg = "update membertest where id={$row_lg['id']} set vote=vote+1";
$run_lg = mysqli_query($con, $vote_lg) or die(mysqli_error());
}
$result_lg = mysqli_query($con, "SELECT id, business FROM membertest WHERE businesstype='large'");
echo "Vote for large business of the year! <SELECT name='business'>\n";
echo "<option>Select a large business</option>";
while($row_lg = $result_lg->fetch_assoc()) {
echo "<option value='{$row_lg['id']}'>{$row_lg['business']}</option>\n";
}
echo "</select></br></br>\n";
echo "<input type='submit' name='voteall' value='voteall'>";
$result_lg->close();
$con->close();
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