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PHP - Newbie Problems With Date
hi there.
can someone tell me how to get this to print out the real minutes instead of the month? echo date("M-d-Y H:m:s", mktime()); i've read http://www.sqlite.org/lang_datefunc.html but i can't seem to get it to work. Similar Tutorials
I am currently using a product called PhPRunner.
Newbie here and I seek guidance! Listed below is the code I have so far. It was bundled as part of a script. I just had a friend help me clean up some junk that was in it which was of great help. http://pastebin.com/vJZBUdgy Now my problem is that it needs publish dates. I have no experience with this. Can anyone point me in the right direction? Thanks in advance! edit: Here is what we removed - print " <description>\n"; print " <![CDATA["; print $description; print " ]]>\n"; print " </description>\n"; Now one does print the date, but it merely prints it out below the content and feedburner doesn't accept this. I will report back any discoveries. Hi there guys, I am very new to php and mySQL and i am currently working on a new site which I want to create a form where my sit visitors can leave their details so i can send them emails with future promotions... I have uploaded the files and when testing the form there doesnt seem to be any errors messages, but then when i go to my phpMyAdmin to check i it has worked. I can not see any of the information to which i ave entered from the form n the website.. I would be very grateful if somebody can please help me... the code for the php is as below.. Many many thanks in advance.. <?php $username="rdo10000_robin"; $password="mypassword"; $database="rdo10000_email"; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); mysql_query($query); $query = "INSERT INTO data1 VALUES ('$_POST[name]','$_POST[email]','$_POST[phone]','$_POST[country]','$_POST[age]')"; header('Location: fish.html'); mysql_close(); ?> I really hope some one can help, many thanks in advance I'm trying to switch two dates if one is before the other, but I'm getting some very strange output from this code.... I've verified that the variables contain the correct information, HOWEVER when this code is run, the returns a $rangeStart = 2016-03-02 <- This is the return even if I give it a static date! $rangeEnd = 2010-09-19 or blank! What am I doing wrong? For this example: Code: [Select] $selDay = 17; $selMonth = 9; $selYear = 2010; $pDay[0] = 14; //Day $pDay[1] = 9; //Month $pDay[2] = 2010; //Year $errMsg = "selDay: ".$selDay."-".$selMonth."-".$selYear."; pDay: ".$pDay[0]."-".$pDay[1]."-".$pDay[2]."; selRange: ".$selRange."; TEMP: "; if(mktime(1,1,1,$selMonth,$selDay,$selYear)>mktime(1,1,1,$pDay[1],$pDay[0],$pDay[2])) { $reverse = true; $tmp = $pDay[0]; $pDay[0] = $selDay; $selDay = $tmp; $errMsg.="<br />selDay=".$selDay."<br />pDay[0]=".$pDay[0]; $tmp = $pDay[1]; $pDay[1] = $selMonth; $selDay = $tmp; $errMsg.="<br />selMonth=".$selMonth."<br />pDay[1]=".$pDay[1]; $tmp = $pDay[2]; $pDay[2] = $selYear; $selDay = $tmp; $errMsg.="<br />selYear=".$selYear."<br />pDay[2]=".$pDay[2]; } $RangeStart = date("Y-m-d",mktime(1,1,1,$selMonth,$selDay,$selYear)); //Selected Range start in d-m-Y $RangeEnd = date("Y-m-d",mktime(1,1,1,$pDay[1],$pDay[0],$pDay[2])); //Selected Range start in d-m-Y $errMsg.=";<br /> Range Start: ".$pRangeStart."; <br />Range End: ".$pRangeEnd."; echo $errMsg; Returns: Code: [Select] selDay: 17-9-2010; pDay: 14-9-2010; selRange: ; TEMP: selDay=14 pDay[0]=17 selMonth=9 pDay[1]=9 selYear=2010 pDay[2]=2010; Range Start: ; Range End: ; This is getting annoying. Any help would be wonderful. problem showing date posted from a form into MYSQL using the php code. Date shows as 0000-00-00 and not the value submitted from the form. Thank you for any help Code: [Select] $sql="INSERT INTO Results (RunnerID, EventID, Date, FinishTime, Position, CategoryID, AgeGrade, PB) VALUES ('$_POST[RunnerID]','$_POST[EventID]','$_POST[Date]','$_POST[FinishTime]','$_POST[Position]','$_POST[CategoryID]','$_POST[AgeGrade]','$_POST[PB]')"; if (!mysql_query($sql,$connection)) { die('Error: ' . mysql_error()); } echo "<h1> Success! Saving data: </h1>"; mysql_close($connection); ?> <html> <head> <title>Submitted</title> </head> <body> <br /> <?php echo "RunnerID=" . $_POST["RunnerID"]; ?><br /> <?php echo "EventID=" . $_POST["EventID"]; ?><br /> <?php echo "Date=" . $_POST["Date"]; ?><br /> <?php echo "FinishTime=" . $_POST["FinishTime"]; ?><br /> <?php echo "Position=" . $_POST["Position"]; ?><br /> <?php echo "CategoryID=" . $_POST["CategoryID"]; ?><br /> <?php echo "AgeGrade=" . $_POST["AgeGrade"]; ?><br /> <?php echo "Personal best=" . $_POST["PB"]; ?><br /> </body> </html> I'm using microtime to capture $start_time and $finish_time bothing using microtime() function. I then pass both $start_time and $finish_time into date() function to parse a date. The difference between $start_time and $finish_time is also calculated. The problem being the date() function is producing incorrect values. list($total_count, $success_count, $errors_data, $start_time, $finish_time) = $summary_data; $duration_time = $finish_time - $start_time; echo "<b>Started Processing At:</b> ".date('m/d/Y H:i:m', $start_time)."<br/>"; echo "<b>Completed Processing At:</b> ".date('m/d/Y H:i:m', $finish_time)."<br/>"; echo "<b>Processing Duration:</b> $duration_time seconds<br/><br/>"; The output: Started Processing At: 11/22/2010 18:45:11 Completed Processing At: 11/22/2010 18:45:11 Processing Duration: 8.0499620437622 seconds OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time. All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results... Thanks. Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03. Here is the code: Code: [Select] <?php $sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $title = $row['title']; $date_posted = $row['date_posted']; $summary = $row['summary']; echo "<h3>$title</h3>\n"; echo "<p>$date_posted</p>\n"; echo "<p>$summary</p>\n"; echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n"; } ?> I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work. Alright, I have a Datetime field in my database which I'm trying to store information in. Here is my code to get my Datetime, however it's returning to me the wrong date. It's returning: 1969-12-31 19:00:00 $mysqldate = date( 'Y-m-d H:i:s', $phpdate ); $phpdate = strtotime( $mysqldate ); echo $mysqldate; Is there something wrong with it? I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. Hi, I have a job listing website which displays the closing date of applications using: $expired_date (This displays a date such as 31st December 2019) I am trying to show a countdown/number of days left until the closing date. I have put this together, but I can't get it to show the number of days.
<?php
$expired_date = get_post_meta( $post->ID, '_job_expires', true );
$hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
if(empty($hide_expiration )) {
if(!empty($expired_date)) { ?>
<span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
<?php
$datetime1 = new DateTime($expired_date);
$datetime2 = date('d');
$interval = $datetime1->diff($datetime2);
echo $interval->d;
?>
<?php }
}
?>
Can anyone help me with what I have wrong? Many thanks (continuing from topic title) So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date. How could I go about doing this easily? I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after. Cheers Denno Hi there, I have a string '12/04/1990', that's in the format dd/mm/yyyy. I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field. The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01. Any ideas? Much appreciated. I'm getting this Time Zone error. Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one. Here is the error message Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /blocked.php on line 41 12/02/12 Here is the code. Line 41 is near the bottom, the one with the d,m,y. Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help! Code: [Select] <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red"> <tr> <td width="176"> <p align="center"><?php // shows IP Number on Page echo $ip; ?> </p> </td> </tr> </table> <p align="center"><?php // Show the user agent echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p> [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b] </td> </tr> </table [,code] Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week. Any one know how to write this code? Here is what I have got, but not working. <?php $todays_date = date("Y-m-d"); $result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7"); while($row = mysql_fetch_array($result)) { echo "$todays_date - $row[title]"; } ?> Hi, I am trying to convert a String date into numeric date using PHP function's, but haven't found such function. Had a look at date(), strtotime(), getdate(); e.g. Apr 1 2011 -> 04-01-2011 Could someone please shed some light on this? Regards, Abhishek i have a table that shows payments made but want to the payments only showing from a set date(06/12/14) and before this date i dont want to show
this is my sql that doesnt seem to work and is showing dates before the specified date.
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"SELECT * FROM payments2014, signup2014, editprop2014 WHERE signup2014.userid = payments2014.payment_userid AND editprop2014.prop_id = signup2014.prop_id AND signup2014.userid !='page1' AND signup2014.userid !='page6' AND signup2014.userid !='page4' AND payments2014.payment_transaction_status !='none' AND payments2014.payment_transaction_status !='CANCELLEDa' AND payments2014.payment_type !='deposit' AND payments2014.payment_paid_timestamp NOT LIKE '%2012%' AND payments2014.payment_paid_timestamp NOT LIKE '%2011%' AND payments2014.payment_paid_timestamp >= '06/12/14' ORDER BY payments2014.payment_id DESC"i have some other parts in the statment but this one that should be filtering is host_payments2014.payment_paid_timestamp >= '06/12/14'thanks in advance Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later). This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date. Here's the code I have right now: Code: [Select] $result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC"); echo "<br />"; echo mysql_result($result, $i, 'eventvenue'); echo ", "; $dt = new DateTime($eventdate); echo $dt->format("jS F Y"); In my mysql table eventdate is set up as follows: field - eventdate type - timestamp length/values - blank default - current_timestamp collation - blank attributes - on update CURRENT_TIMESTAMP null - blank auto_increment - blank Any help as to why this could be happening would be much appreciated, thanks. |
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