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PHP - Mysql Insert Skipping Over Field
I have a script that uploads and images, creates 2 versions of it, re-sizes the images and inserts all the info into a DB.
The odd thing is that if I don't have an image to upload, it will still run the script but it will completely skip over the description. If I upload an image, it works fine. Not too sure what the issue is. Is it because my variable of $desc causing a conflict? Here's my code: Code: [Select] <?php ini_set("display_errors",1); include 'dbconn.php'; $change=""; $abc=""; define ("MAX_SIZE"," 10000"); function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } $errors=0; if($_SERVER["REQUEST_METHOD"] == "POST") { $image =$_FILES["file"]["name"]; $uploadedfile = $_FILES['file']['tmp_name']; if ($image) { $filename = stripslashes($_FILES['file']['name']); $extension = getExtension($filename); $extension = strtolower($extension); if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { $change='<div class="msgdiv">Unknown Image extension </div> '; $errors=1; } else { $size=filesize($_FILES['file']['tmp_name']); if ($size > MAX_SIZE*1024) { $change='<div class="msgdiv">You have exceeded the size limit!</div> '; $errors=1; } if($extension=="jpg" || $extension=="jpeg" ) { $uploadedfile = $_FILES['file']['tmp_name']; $src = imagecreatefromjpeg($uploadedfile); } else if($extension=="png") { $uploadedfile = $_FILES['file']['tmp_name']; $src = imagecreatefrompng($uploadedfile); } else { $src = imagecreatefromgif($uploadedfile); } echo $scr; list($width,$height)=getimagesize($uploadedfile); $newwidth=150; $newheight=($height/$width)*$newwidth; $tmp=imagecreatetruecolor($newwidth,$newheight); $newwidth1=50; $newheight1=($height/$width)*$newwidth1; $tmp1=imagecreatetruecolor($newwidth1,$newheight1); imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height); imagecopyresampled($tmp1,$src,0,0,0,0,$newwidth1,$newheight1,$width,$height); $famname = $_POST['famname']; $desc = $_POST['description']; $petname = $_POST['petname']; $letter = $_POST['letter']; $filename = "images/". $_FILES['file']['name']; $filename1 = "images/small". $_FILES['file']['name']; imagejpeg($tmp,$filename,100); imagejpeg($tmp1,$filename1,100); imagedestroy($src); imagedestroy($tmp); imagedestroy($tmp1); }} } //If no errors registred, print the success message if(isset($_POST['Submit']) && !$errors) { $insert="insert ignore into tbl_tribue (petname,familyname,letter,description,imgpath,thumbpath) values ('$petname','$famname','$letter','$desc','$filename','$filename1')"; mysql_query($insert); //mysql_query("update gallery set imgpath='$filename'"); $change=' <div class="msgdiv">Pet Added Successfully!</div>'; print $insert; } ?> I had turned on the error and the print to see the output. Anyone have any ideas? Thanks! Similar TutorialsWe have a php application that is just a form, that takes in data to a mysql database and then displays that data in queue(php web page) for the client. It has been working for the past 5 or more years. Six weeks ago, the client noticed that the numbering started skipping a number each time a request was entered. It then seemed to stop, now it has started again. See attached image. Some detail he after user has completed web form and hits submit, three fields are populated in the mysql "REQUEST" table, then the actually data from the submitted web form is sent to the ANSWER table. The REQUEST table is in sync and is always populated, and numbering is in sequence but upon submit, the actual data from the request does NOT always go to the ANSWER table hence the "skipping of numbers." What do I even begin looking at/for to determine what happened? Reminder: this is a 5+ year old app that worked fine until maybe 6 weeks ago. No changes have been made to the database or the code base since 2008. The code that adds the data to the ANSWER table [the one that appears to skip] is below. The applicate is in php 4.3.1, mysql 5, linux server. Hi: I'm going crazy trying to do the following: I'm making a job registration process where the user registers on one php page to the website, must acknowlege and email receipt using an activate php page, then is directed to upload their C.V. (resume) based on the email address they enter in the active page output. I then run an upload page to store the resume in teh MySQL db based on the users email address in the same record. If I isolate the process of the user registering to the db, it works perfectly. If I isolate the file upload process into the db, it works perfect. I simply cannot upload teh file to the existing record based on teh email form field matching the user_email field in the db. With the processes together, teh user is activated, but teh file is not uploaded. Maybe I've simply been at this too long today, but am compeled to get through it by end day. If anyone can help sugest a better way or help me fix this, I will soo greatly appreciate it. My code is as follows for the 2 pages. ---------activate.php------- <?php session_start(); include ('reg_dbc.php'); if (!isset($_GET['usr']) && !isset($_GET['code']) ) { $msg = "ERROR: The code does not match.."; exit(); } $rsCode = mysql_query("SELECT activation_code from subscribers where user_email='$_GET[usr]'") or die(mysql_error()); list($acode) = mysql_fetch_array($rsCode); if ($_GET['code'] == $acode) { mysql_query("update subscribers set user_activated=1 where user_email='$_GET[usr]'") or die(mysql_error()); echo "<h3><center>Thank You! This is step 2 of 3. </h3>Your email is confirmed. Please upload your C.V. now to complete step 3.</center>"; } else { echo "ERROR: Incorrect activation code... not valid"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Job application activation</title> </head> <body> <center> <br/><br/><br/> <p align="center"> <form name="form1" method="post" action="upload.php" style="padding:5px;"> <p>Re-enter you Email : <input name="email" type="text" id="email"/></p></form> <form enctype="multipart/form-data" action="upload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="4000000"> Upload your C.V.: <input name="userfile" type="file" id="userfile"> <input name="upload" type="submit" id="upload" value="Upload your C.V."/></form> </p> </center> </body> </html> --------upload.php---------- <?php session_start(); if (!isset($_GET['usr']) && !isset($_GET['code']) ) { $msg = "ERROR: The code does not match.."; exit(); } if(isset($_POST['upload']) && $_FILES['userfile']['size'] > 0) { $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $email = $_POST['email']['user_email']; $fp = fopen($tmpName, 'r'); $content = fread($fp, filesize($tmpName)); $content = addslashes($content); fclose($fp); if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } include 'reg_dbc.php'; $query = "UPDATE subscribers WHERE $email = user_email (name, size, type, content ) ". "VALUES ('$fileName', '$fileSize', '$fileType', '$content')"; mysql_query($query) or die('Error, query failed'); mysql_close($dbname); } ?> <center> <br/> <br/> <br/> <br/> Thank you for uploading your <?php echo "$fileName"; ?> file, completing your registration, and providing us your C.V. for this position. <br/> <br/> <br/> We will contact you if your canditature qualifies. </center> Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Hi, I have a field called experience in mysql and I want to add +7 to said field, is it possible using UPDATE or insert? If so, what's the syntax? Here's what I have that doesn't work, it sets experience to 7, but won't add another 7 when clicked again. if(isset($_POST['submit'])){ $query = "UPDATE account_info SET experience = +7 WHERE username = $name"; $result = mysql_query($query) or die(mysql_error()); } don't ask for the whole script, because you won't need it to answer that o.0 - I am inserting a new record into a table called "parts". The key field is "partid", which is autoincremented. - After I do the insert, how do I get the value for partid for the new record? I cannot select the record because there are no unique combinations of fields to select on. Here is my code to insert the new record into table "parts". //Insert new part. $query="INSERT INTO parts (modelnum, prodcat, ". "prodname, prodsubname, createuser, createdate) " . "VALUES ( ". "'".$modelvar."', " . "'".$prodcatvar."', ". "'".$prodnamevar."', ". "'".$prodsubnamevar."', ". "'".$_SESSION['username']."', ". "NOW() ". ");"; $result=mysqli_query($dbc,$query); if (!$result) { $msg=mysql_error().'<br/>Could not run SELECT. '; //There was an error. crError($_SERVER['PHP_SELF'].' line '.__LINE__,$msg,true); } else { $s='Inserted new product cat='.$prodcatvar.', model='.$modelvar; crInfomsg($s); } } Thank you. Hi i have a form that logins at a mail. I have installed an SSL at this domain and i would like to add an option at the form for the user to login using https or not the form is above. How can i add an option with check-box from user to login using https ???? IF this is checked when the user clicks "login" he will redirected to https and will login. If i have not describe well please ask for details. Thanks <form class="login-form" action="<?php echo $this->moduleBaseUrl; ?>/XXX/XXXXXX" name="loginPage" id="loginPage" method="post"> <input type='hidden' name='emailName' value=''/> <input type='hidden' name='emailDomain' value=''/> <input type='hidden' name='cssStyle' value='<?php echo $this->cssStyle ?>'/> <table class="login"> <tbody> <tr> <td> <label class="user"><?php print $this->translate('Email') ?>:</label> <input id="email" class="input-email" type="text" name="email" tabindex="1" /> </td> </tr> <tr> <td> <label class="pass"><?php print $this->translate('Password') ?>:</label> <input id="password" class="input-pass" type="password" name="password" tabindex="2" /> </td> </tr> <tr id="LoginBtn" style="display: none;"> <td> <input class="loginbtn <?php echo $this->cssStyle ?>" type="submit" value="<?php print $this->translate('Login') ?>" /> <span class="remember"><?php print $this->translate('Remember Me') ?></span> <input class="check" type="checkbox" value="1" name="RememberMe" /> </td> </tr> </tbody> </table> </form> can someone tell me why this won't work? I just want to key in the amtpaid and have fields inserted. I get no errors but the only field inserted is the datepaid . <html><head> <script> function $_(IDS) { return document.getElementById(IDS); } function calculate_paid() { var amtpaid = parseInt($_("amtpaid").value); var rentdue = parseInt($_("rentdue").value); var prevbal = parseInt($_("prevbal").value); var secdep = parseInt($_("secdep").value); var latechg = parseInt($_("latechg").value); var damage = parseInt($_("damage").value); var courtcost = parseInt($_("courtcost").value); var nsf = parseInt($_("nsf").value); var hudpay = parseInt($_("hudpay").value); var late = ($_("late").value); var paidsum = parseInt($_("paidsum").value); var dateNow = new Date(); var dayNow = dateNow.getDate(); var datePaid = (dateNow.getMonth()+1)+"/"+dateNow.getDate()+"/"+dateNow.getFullYear(); $_('datePaid').value = datePaid; if(dayNow > 5) { late = "L"; prevbal = prevbal + 10; } paidsum = paidsum + amtpaid var tentpay = amtpaid - hudpay; var totOwed = rentdue + prevbal - hudpay; var left = totOwed - amtpaid; if (amtpaid <= totOwed) { prevbal = left; } left = amtpaid - totOwed; if (left <= secdep) { secdep = secdep - left; } left = left - secdep; if (left <= damage) { damage = damage - left; } left = left - damage; if (left <= latechg) { latechg = latechg - left; } left = left - latechg; if (left <= courtcost) { courtcost = courtcost - left; } left = left - courtcost; if (left <= nsf) { nsf = nsf - left; } prevbal = left - nsf; } </script> </head><body> <?php mysql_connect(localhost,root,""); mysql_select_db(test) or die( "Unable to select database"); if(!empty($_POST["submit"])) { $apt = $_POST['apt']; $query="SELECT * FROM testdata Where apt='$apt'"; $result=mysql_query($query); if(mysql_num_rows($result)) { echo "<form action='#' method='post'><b>Rent Payment :<br /><br /> <table cellspacing=0 cellpadding=0 border=1> <tr> <th>Name</th> <th>Apt</th> <th>Paid</th> <th>Due</th> <th>Prev Bal</th> <th>Sec Dep</th> <th>Late Chg</th> <th>Dmg</th> <th>Court Cost</th> <th>NSF</th> <th>Tent Pay</th> <th>Hud Pay</th> <th>Date Paid</th> <th>Late</th> <th>Comments</th> <th>Paidsum</th> </tr>"; while($row = mysql_fetch_assoc($result)) { echo "<tr> <td><input type='text' size=25 name='name' value='" . $row['name'] . "'></td> <td><input type='text' size=2 name='apt' value='" . $row['apt'] . "' ></td> <td><input type='text' size=4 id='amtpaid' name='amtpaid' value='" . $row['amtpaid'] ."' onBlur='calculate_paid(this)'></td> <td><input type='text' size=4 id='rentdue' name='rentdue' value='" . $row['rentdue'] . "'></td> <td><input type='text' size=4 id='prevbal' name='prevbal' value='" . $row['prevbal'] ."'></td> <td><input type='text' size=4 id='secdep' name='secdep' value='" . $row['secdep'] ."'></td> <td><input type='text' size=4 id='latechg' name='latechg' value='" . $row['latechg'] ."'></td> <td><input type='text' size=4 id='damage' name='damage' value='" . $row['damage'] ."'></td> <td><input type='text' size=4 id='courtcost' name='courtcost' value='" . $row['courtcost'] ."'></td> <td><input type='text' size=4 id='nsf' name='nsf' value='" . $row['nsf'] ."'></td> <td><input type='text' size=4 id='tentpay' name='tentpay' value='" . $row['tentpay'] . "'></td> <td><input type='text' size=4 id='hudpay' name='hudpay' value='" . $row['hudpay'] ."'></td> <td><input type='text' size=10 id='datepaid' name='datepaid' value='" . $row['datepaid'] . "'></td> <td><input type='text' size=1 id='late' name='late' value='" . $row['late'] . "'></td> <td><input type='text' size=25 name='comments' value='" . $row['comments'] . "'></td> <td><input type='text' size=4 id='paidsum' name='paidsum' value='" . $row['paidsum'] . "'></td> </tr>"; } echo "</table> <input type='submit' name='update' value='Make Payment' /> </form>"; } else{echo "No listing for apartment $apt.<br />Please select another.<br />";} } if(!empty($_POST["update"])) { $sql = "UPDATE testdata SET name = '" . mysql_real_escape_string($_POST['name']) . "', amtpaid = '" . mysql_real_escape_string($_POST['amtpaid']) . "', rentdue = '" . mysql_real_escape_string($_POST['rentdue']) . "', prevbal = '" . mysql_real_escape_string($_POST['prevbal']) . "', secdep = '" . mysql_real_escape_string($_POST['secdep']) . "', latechg = '" . mysql_real_escape_string($_POST['latechg']) . "', nsf = '" . mysql_real_escape_string($_POST['nsf']) . "', damage = '" . mysql_real_escape_string($_POST['damage']) . "', courtcost = '" . mysql_real_escape_string($_POST['costcost']) . "', tentpay = '" . mysql_real_escape_string($_POST['tentpay']) . "', hudpay = '" . mysql_real_escape_string($_POST['hudpay']) . "', datepaid = '" . mysql_real_escape_string($_POST['datepaid']) . "', late = '" . mysql_real_escape_string($_POST['late']) . "', comments = '" . mysql_real_escape_string($_POST['comments']) . "', paidsum = '" . mysql_real_escape_string($_POST['paidsum']) . "' WHERE apt='".$_POST["apt"]."'"; mysql_query($sql) or die("Update query failed."); echo "Record for apartment ".$_POST["apt"]." has been updated"; } ?><form method="post" action="#"> <br /> <input type="text" name="apt"/> <p> <input type="submit" name="submit" value="select apartment"/> </form> </body></html> Hello I though this code would work Code: [Select] mysql_query("UPDATE cart SET totprice = quantity * price WHERE ID='{$id}'")or die(mysql_error());because this is working fine Code: [Select] mysql_query("UPDATE products SET rating = rating + 1 WHERE ID='{$id}'")or die(mysql_error()); Anything wrong with it, or how should i do it? I have a register script, and I am wanting to make it so that if the username field contains, lets say "mod", "ass", and more, then it'll return an error and wont let them register. Hi guys I have the code below and have 4 text fields, the issue is i'd like to prevent insert query if textfield is empty, do u know how? if (isset($_POST['register']) && $_POST['register']) { $reference = rand(11111111,99999999); $name1 = addslashes(strip_tags($_POST['name1'])); $name2 = addslashes(strip_tags($_POST['name2'])); $name3 = addslashes(strip_tags($_POST['name3'])); $name4 = addslashes(strip_tags($_POST['name4'])); $addname4=mysql_query("INSERT INTO nearest (stref, name) VALUES('$reference','$name4')"); $addname3=mysql_query("INSERT INTO nearest (stref, name) VALUES('$reference','$name3')"); $addname2=mysql_query("INSERT INTO nearest (stref, name) VALUES('$reference','$name2')"); $addname1=mysql_query("INSERT INTO nearest (stref, name) VALUES('$reference','$name1')"); } thanks For instance if i set the following 2x variables; "$varOne = $_GET[first_name]" "$varTwo = $_GET[last_name]" "$varThree = $_GET[userid]" how do i insert them both together into a DB field for example: $full = $varOne,$varTwo,$varThree (without the , ) this would then be echo as : joebloggs66985 i have the INSERT in there atm but i wanted to insert first name and last name together with there userid to generate a sort of username possibility. sorry if i didnt explain correcly Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks Hi guys I have a registration form working fine, my database is as below: userid username password repeatpassword I have added another column which is "name", users can update their profile once they have logged in so I have created updateprofile.php and when I login-->go to update profile and insert my name nothing adds to mysql name column this is my code below: <?php include ("global.php"); //username session $_SESSION['username']=='$username'; $username=$_SESSION['username']; //welcome messaage echo "Welcome, " .$_SESSION['username']."!<p>"; if ($_POST['register']) { //get form data $name = addslashes(strip_tags($_POST['name'])); $update = mysql_query("INSERT INTO users (name) VALUES ('$_POST[name]') WHERE username='$username'"); } ?> <form action='updateprofile.php' method='POST'> Company Name:<br /> <input type='text' name='name'><p /> <input type='submit' name='register' value='Register'> </form> can you please tell me where in this code is wrong? Im new in php so please excuse me if I have silly mistakes. thanks in advance I don't understand where the empty value is. I've substituted the variables for text and still have the same problem. Code: Code: [Select] $sql = "INSERT INTO courses (course#, name, subject, semester, ap)VALUES('$courseNum', '$courseName', '$subject', '$semester', '$ap')"; Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 I have this code: <?php $con = mysql_connect("localhost","hhh","hhh"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("hhh", $con); // -------------------- // Avatar insert check // -------------------- session_start(); $name = $_POST[name]; $group = $_POST[group]; $age = $_POST[age]; $usernameid = $_SESSION[id]; $result = mysql_query("SELECT * FROM avatars WHERE name='$_POST[name]'"); $num = mysql_numrows($result); if ($num == 0) { mysql_query("INSERT INTO avatars (id, usernameid, name, group, age, xp) VALUES ('', '$usernameid', '$name', '$group', '$age', '0')"); header( 'Location: me/' ) ; } else echo 'Sorry, please pick a new name'; ?> And it does everything but put the data into the datebase. If I add a session befor and after '$request' they both run, but the sql doesn't. No error returns, if just redirects to the other page. Any help? well this is truely embarrising...i have a insert statement which works within phpmyadmin but when using mysqli_query it returns a error.
INSERT INTO users (username, timestamp) VALUES ('test', UTC_TIMESTAMP())
Unknown column 'timestamp' in 'field list'
i've been playing about with this for a few hours now ...tried changing the column name (timestamp), adding ` around column names as well as table name.
the column exists which is the strangest part, and ive even checked there is no space after the column name in the db.
whats going on please?
I need help badly! What I want to do is insert into database the value from the selected radio group buttons.. All of them. There are 10 radio groups total (they can be less, but not more). Thanks! Code: [Select] <?php require_once('Connections/strana.php'); mysql_select_db($database_strana, $strana); ?> <link href="css/styles.css" rel="stylesheet" type="text/css" /> <table width="100%" height="100%" style="margin-left:auto;margin-right:auto;" border="0"> <tr> <td align="center"> <form action="" method="post" enctype="multipart/form-data" name="form1"> <table> <?php $tema = mysql_query("SELECT * from prasanja where tip=2")or die(mysql_error()); function odgovor1($string) { $string1 = explode("/", $string); echo $string1[0]; } function odgovor2($string) { $string1 = explode("/", $string); echo $string1[1]; } while ($row=mysql_fetch_array($tema)) { $id=$row['prasanje_id']; $prasanje=$row['prasanje_tekst']; $tekst=$row['odgovor']; ?> <tr> <td> </td> </tr> <tr> <td class="formaP"> <?php echo $prasanje?> </td> </tr> <tr> <td class="formaO"> <p> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor1($tekst) ?>" /> <?php odgovor1($tekst) ?></label> <br /> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor2($tekst) ?>" /> <?php odgovor2($tekst) ?></label> <br /> </p></td> </tr> <tr> <td> <br /> </td> </tr> <?php } ?> </table> <input align="left"type="submit" name="submit" value="Внеси" > </form> </td> </tr> </table> prasanje = question tekst/odgovor = answer The answer table: id - primary question_id - the questions ID whose answer is selected in the radio group user_id - cookie takes care of this answer - the value from radio group date - automatic Hey guys for some reason this code is not working i can't see a problem myself could someone please have a look and point the issue out to me. what i mean by it not working is it won't insert into the database or show a mysql_error. thanks in advance Code: [Select] $guestip = $_SERVER['REMOTE_ADDR']; $time = date('G:i'); $date = date("y-m-d"); $query = mysql_query("SELECT * FROM IP_Address") or die(mysql_error()); while($row = mysql_fetch_assoc($query)){ if($guestip != $row['ip']){ //insert into db. mysql_query("INSERT INTO IP_Address(id, ip, date, time) VALUES(NULL,'$questip','$date','$time')") or die(mysql_error()); echo "inserted in to database"; echo mysql_error(); }else{ // add hit count and update time and date. echo "already in db"; } } I've got Code: [Select] for ($i=1; $i<=5; $i++) { if(isset($_POST['partsusedqty'.$i]) && $_POST['partsusedqty'.$i] != "" && $_POST['partsusedqty'.$i] != "0.00") { mysql_query("INSERT INTO partsused (ptnumber, partqty, partdesc, partprice) VALUES ($ticket, '$partsusedqty'.$i, '$partsuseddesc'.$i, '$partsusedprice'.$i)") or die(mysql_error()); } } I need to know the correct formatting to put these variable variables as values in the mysql query. With this particular code, I get the error "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.1, ''.1, ''.1)' at line 2" I've tried formatting this an endless number of ways, but I used this particular example because its the one I really thought should work. Everything I've tried that doesn't throw an error put the $partsusedqty in the partqty, partdesc, and partprice fields. Thanks for any help! |
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