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PHP - Adding A Number Every Visit
Good day:
Im trying to add a number every time a person visits the page. here is the code Im using. Any help will be appreciated. Code: [Select] <?php $aid = $_GET['aid']; $connection = mysql_connect("localhost", "username", "password"); mysql_select_db("articles", $connection); $query="SELECT visits FROM articles_description WHERE id=$aid"; $result=mysql_query($query); $num=mysql_numrows($result); <?php while ($j < $num) { $visits = $num[0] + 1; } $query = "UPDATE articles_description SET visits = $visits WHERE id = $aid"; if(mysql_query($sql_query)) { echo "Record updated successfully"; $j++; } mysql_close(); ?> Similar TutorialsHi all. I am trying to add 1 to a number. The problem I have is that the number is 4 digits long. So for example the number could be 0007. I add one and it returns 8. I need it to return 0008. Code: [Select] <?php $next = 0007 + 1; echo $next; ?> Can anyone show me how I can get the number to be 4 digits? Thank you I made a function which displays the left and right children of the root. However i need to add serial numbers to them. Due to Recursive functions i'm not quite able to to do so . Can someone please help me? Code: [Select] function side_display($root) { $sql = "SELECT lchild,rchild FROM tree WHERE parent='".$root."'"; $sqlexec = mysql_query($sql); $array = mysql_fetch_array($sqlexec); if(!empty($array['lchild']) && $array['lchild'] != '0') { echo "<tr>"; echo "<td>".($array['lchild'])."</td>"; $get = "SELECT * FROM member WHERE member_id='".$array['lchild']."'"; $execget = mysql_query($get); $getarray = mysql_fetch_array($execget); echo "<td>".$getarray['fname']." ".$getarray['lname']."</td>"; echo "<td>".$getarray['id_sponsor']."</td>" ; echo "<td>Left</td>"; echo "<td>".$getarray['doj']."</td>" ; echo "</tr>"; side_display($array['lchild']); } if(!empty($array['rchild']) && $array['rchild'] != '0') { echo "<tr>"; echo "<td>".($array['rchild'])."</td>"; $get = "SELECT * FROM member WHERE member_id='".$array['rchild']."'"; $execget = mysql_query($get); $getarray = mysql_fetch_array($execget); echo "<td>".$getarray['fname']." ".$getarray['lname']."</td>"; echo "<td>".$getarray['id_sponsor']."</td>" ; echo "<td>Right</td>"; echo "<td>".$getarray['doj']."</td>" ; echo "</tr>"; side_display($array['rchild']); } } I have 3 columns in my DB: email (primary), unique_code, timestamp Users enter their email address and it is added to the DB, including an alphanumeric 5 digit unique code in the 'unique_code' column and a timestamp in the 'timestamp' column. 1. The email address is being added, but not the unique code? What is the issue here and what can I should I specifically do to fix it? 2. The next thing is that I need to display that code to the user in where it says <?php echo $unique_code;?>. How can I do that? DB is as follows: Field Type Collation Attributes Null Default Extra Action email varchar(64) utf8_unicode_ci No None unique_code varchar(64) utf8_unicode_ci No None timestamp timestamp on update CURRENT_TIMESTAMP No CURRENT_TIMESTAMP INDEXES PRIMARY BTREE Yes No email 7 A Full code Code: [Select] <?php require "includes/connect.php"; $msg = ''; if($_POST['email']){ // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('This email already exists in the database.'); } if($ajax){ die('{"status":1}'); } $msg = "Thank you!"; $mysqli->query("INSERT INTO coming_soon_emails VALUES('email', SUBSTRING(MD5(UUID()),FLOOR(RAND()*25),5), UNIX_TIMESTAMP())"); echo "Something went wrong:" . $mysqli->error; } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } ?> <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>example</title> <link rel="stylesheet" type="text/css" href="css/styles.css" /> </head> <body> <div id="container"> <form id="form" method="post" action=""> <input type="text" id="email" name="email" value="<?php echo $msg?>" /> <input type="submit" value="Submit" id="submitButton" /> </form> <div id="thankyou"> Thank you! <?php echo $unique_code;?></p> </div> </div> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script> <script src="js/script.js"></script> </body> </html> Thank you! Hi, I'm just starting PHP and I ran into a simple problem (that I can fix), but I just want to understand why my first approach doesn't work. I was testing multiplications and additions and the result I got was unexpected. Here is the code that doesn't work: Code: [Select] <?php $number1 = 5; $number2 = 10; print $number1." multiplied by ".$number2." + 1000 = ".$number1*$number2+1000; ?> Obviously, what I want as a result when I'm displaying the page is: "5 multiplied by 10 + 1000 = 1050" What I get: "1005". That's right, nothing else. On top of getting an erroneous answer, the sentence that's supposed to display right before the equation doesn't display at all. It's even worse if I switch it around like that: Code: [Select] print $number1." multiplied by ".$number2." + 1000 = ".1000+$number1*$number2; I get an error message and nothing displays. The obvious solution works: using a parenthesis at the beginning and at the end of the equation, which I should do regardless, but still, it's bugging me and since I just started learning PHP today, I want to understand how the code is compiled / interpreted so I don't make stupid mistakes like this one. Thanks in advance for the replies. I'm getting the dreaded " Invalid parameter number: number of bound variables does not match number of tokens" error and I've looked at this for days. Here is what my table looks like:
| id | int(4) | NO | PRI | NULL | auto_increment | | user_id | int(4) | NO | | NULL | | | recipient | varchar(30) | NO | | NULL | | | subject | varchar(25) | YES | | NULL | | | cc_email | varchar(30) | YES | | NULL | | | reply | varchar(20) | YES | | NULL | | | location | varchar(50) | YES | | NULL | | | stationery | varchar(40) | YES | | NULL | | | ink_color | varchar(12) | YES | | NULL | | | fontchosen | varchar(30) | YES | | NULL | | | message | varchar(500) | NO | | NULL | | | attachment | varchar(40) | YES | | NULL | | | messageDate | datetime | YES | | NULL |Here are my params:
$params = array(
':user_id' => $userid,
':recipient' => $this->message_vars['recipient'],
':subject' => $this->message_vars['subject'],
':cc_email' => $this->message_vars['cc_email'],
':reply' => $this->message_vars['reply'],
':location' => $this->message_vars['location'],
':stationery' => $this->message_vars['stationery'],
':ink_color' => $this->message_vars['ink_color'],
':fontchosen' => $this->message_vars['fontchosen'],
':message' => $messageInput,
':attachment' => $this->message_vars['attachment'],
':messageDate' => $date );
Here is my sql:
$sql = "INSERT INTO messages (user_id,recipient, subject, cc_email, reply, location,stationery, ink_color, fontchosen, message,attachment) VALUES( $userid, :recipient, :subject, :cc_email, :reply, :location, :stationery, :ink_color, :fontchosen, $messageInput, :attachment, $date);";
And lastly, here is how I am calling it:
$dbh = parent::$dbh;
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);
if (empty($dbh)) return false;
$stmt = $dbh->prepare($sql);
$stmt->execute($params) or die(print_r($stmt->errorInfo(), true));
if (!$stmt) { print_r($dbh->errorInfo()); }
I know my userid is valid and and the date is set above (I've echo'd these out to make sure). Since the id is auto_increment, I do not put that in my sql (though I've tried that too), nor in my params (tried that too). What am I missing? I feel certain it is something small, but I have spent days checking commas, semi-colons and spelling. Can anyone see what I'm doing wrong?
hi guys, I'm trying to use a very basic PHP script and i think I've got everything right but I'm not getting any records inserted into my table. here is my script:
$dbHost = "ip address";
$dbName= "rptDatabase";
$dbUsername = "username";
$dbPassword = "password";
$ip = $_SERVER['REMOTE_ADDR'];
$page = $_SERVER['PHP_SELF'];
$referrer = $_SERVER['HTTP_REFERER'];
$date = date("m/d/y");
$time = date("h:i:a");
$db = mysql_connect($dbHost, $dbUsername,
$dbPassword) or trigger_error(mysql_error(),E_USER_ERROR);
mysql_select_db($dbName, $db);
$sql = "INSERT INTO tblTraffic (ip, page, referrer, date, time)
VALUES ($ip, $page, $referrer, $date, $time)";
$result = mysql_query($sql) or trigger_error(mysql_error(),E_USER_ERROR);
mysql_close($db);
can someone tell me what I'm doing wrong? thanks. Edited October 13, 2019 by ajetrumpetHi I'm trying to figure out how to calculate how long since a datevariable I have stored is from whenever the page is loaded.. I currently have a stored datevariable in the format: YYYY-MM-DD H:m:s ... So basically what I wish to accomplish is figuring out whenever i load the page which has stored this variable, how much time has passed. I want it to show up as for example : '10 minutes ago'.. '1 hour 25minutes ago' if it's the same day.. if its more than 1 day old it's enough to show only the number of days.....'1week 3 days ago' etc etc This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=322423.0 Hello,
I have problem durring binding update query. I can't find what is causing problem.
public function Update(Entry $e)
{
try
{
$query = "update entry set string = $e->string,delimiter=$e->delimiter where entryid= $e->id";
$stmt = $this->db->mysqli->prepare($query);
$stmt->bind_param('ssi',$e->string,$e->delimiter,$e->id);
$stmt->close();
}
catch(Exception $ex)
{
print 'Error: ' .$ex->getMessage();
}
}
When I run function update I'm getting next error:Warning: mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement
Can you help me to solve this problem ?
Edited by danchi, 17 October 2014 - 10:25 AM. I need to display a number(the number is retrieved from the db) in the form input field such that only the last 4 digits is visbile, the remaining can be masked as * or X or whatever is applicable. I know the last 4 can be obtained as follows: Code: [Select] $number=substr($number,-4,4); But when i hit the submit button the form validates the input field and checks if the number is a valid number of a specific format. Therefore when I click on the submit button then I should still be able to unmask the masked numbers or do something similar that would help me validate the whole number. Code: [Select] <input type="text" name="no" value="<?php if(!empty($number)){ echo $number;} ?>"> I just had a question for you guys. I am building a forum script and I'm currently stumped on the "show unread posts since last visit" feature. Not sure as to how to code it. Should I be using a mysql database to keep track of them or use cookies some how? Thanks in advanced! Hey I have a string that looks like the following: Quote top-php-tutorials-2.html I have a script that cycles through each page. The 2 in the quote above is the page number. How can I extract the number between the - and the .html and replace it with another number? I've tried Code: [Select] substr($engine->selectedcaturl, 0,-6).$v.".html"But then I realised this only works for numbers that are 1 digit long Any input would be appreciated hello, i have a start time and an end time (no dates). the following works great, except for when the start time is at night, and the end time is in the morning. im thinking if i can do an if the number is negative, add 24, that it will resolve my issue. any ideas? Code: [Select] $tbilled = $tfinish - $tstart; Suppose I have a series of numbers being stored in an SQL table, which are not uniform and constantly growing. Once the numbers in the table (in sql) hit 99,999,999, they start back at 1, and do it all over again continuously until the end of time.
If I am performing calculations in PHP on these numbers (stop date-start date), is there a function that can take a look at the next cell after 99,999,999 and acknowledge that the 1 is really 100,000,000.
In the below example, instead of using 99,999,999, we used 4 as the last number before numerical reset. Once the numbers hit 4, they reset to 1. continuously.
Example1. If I were to subtract Jan 1(start) from jan 4(stop) I would have Stopdate -Startdate = 4-1 =3.
Example2. If I were to subtract Jan 4(start) from jan 7(stop) I would have Stopdate-Startdate = 3-4 =-1 but should be 7-4 for the sake of the calculation only.
Example3. If I were to subtract Jan 8(start) from jan 11(stop), I would have Stopdate-Startdate = 3-4=-1 but should be 11-8=3 but for ease of not having to be a continuous repeating thing, can be represented at 7-4. There is no need to keep a running memory towards infinity. It just needs to know that any number after some number ending in 4 is 5, instead of reseting to 1.
jan 1 2014.......1
jan 2 2014.......2
jan 3 2014.......3
jan 4 2014.......4
jan 5 2014.......1
jan 6 2014.......2
jan 7 2014.......3
jan 8 2014.......4
jan 9 2014.......1
jan10 2014......2
jan11 2014......3
Hope this is not that confusing.
Long story short, I can't do a stopdate-startdate = somenumber, if that some number keeps resetting to 1 once it reached 99,999,999. As a result, my code will work perfectly until I reach 99,999,999, then I am in trouble because 1-99,999,999 is not equal to 1, where 100,000,000 -99,999,999 = 1
thanks.
Edited by Butterbean, 24 October 2014 - 02:24 PM. <?php echo "How much money do you want landed on the account?!\n"; $landed = fgets(STDIN); $calc = ($landed * .25); $total = ($landed + $calc); echo "\nYou need to list the dummy for $".$total."...\n\n"; echo "Press enter to close this script..."; $exit = fgets(STDIN); ?> so say I enter 12000000000 which would make the $total .. $15000000000 how so I make the total have commas in it, like $15,000,000,000 $insertCount=0; foreach($results[1] as $curName) { if($insert){$insertCount++;} echo <<< END $curName<BR> END; } Right now the results would show up as... Bill Fred Jessica James John How do you make them show up like... 1 Bill 2 Fred 3 Jessica 4 James 5 John Hi Guys I have a code what inserts very simple queries to database, im trying to add a random reference number for each enrty using $reference = rand(111111111111,999999999999); but each time I add an entry it gives me the same random number previously generated for previous entry can you help pleasE? One more question to ask. I'm trying to do a count of total logins that have happened in the last 5 months including the current one so far. My users_logins table has the following structu users_id, session_id, login_date(datetime), last_activity(datetime). What the end result is going to be is: <tr> <td></td> <th scope="col"><?php echo date("M", strtotime("-4 month")); ?></th> <th scope="col"><?php echo date("M", strtotime("-3 month")); ?></th> <th scope="col"><?php echo date("M", strtotime("-2 month")); ?></th> <th scope="col"><?php echo date("M", strtotime("-1 month")); ?></th> <th scope="col"><?php echo date("M"); ?></th> </tr> <tr> <th scope="row">Logins</th> <td>94</td> <td>53</td> <td>124</td> <td>92</td> <td>105</td> </tr> Where the first td would be May and the last td would be September. Do I have to do this in 4 separate queries. If so here's what I have for the first query. I'm not sure what woudl go for the WHERE. $four_months_ago_query = "SELCT COUNT(date_login) FROM users_logins WHERE ? "; I have these numbers in an array: 14042 11130 10100 10100 9506 How can I add them all together? Was thinking about a while loop. Derp. >array_sum solved! i wanted to choose 5 random numbers from 0-20. each number represents an index in an array. is there a way to pick out 5 random items from the array. say if random number generator piked a number 22, the last item in the array is at index 20, it wud then have to go to index 0. thanks! |
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