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PHP - How To Include Specific Column Elements In Mysql Select Clause As Per User Input
I've a simple Inset List (jQuery Mobile) of several items with a Flip switch, Drop down, check box and Slider elements.
I have wrapped this Inset List inside a HTML Form. <code> <div data-role="fieldcontain"> <ul data-role="listview" data-inset="true"> <li data-role="list-divider"> Inhouse capabilities </li> <li> <label for="flip-b">Project Manager</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li> <label for="flip-b">Site Supervisor</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li><label for="flip-b">Architect</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li><label for="flip-b">Builderworks</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li><label for="flip-b">Electrical</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li><label for="flip-b">Mechanical</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li><label for="flip-b">Hydraulics</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li><label for="flip-b">Joinery</label> <select name="slider" id="flip-b" data-role="slider"> <option value="no">No</option> <option value="yes">Yes</option> </select> </li> <li> <label for="select-choice-1" class="select">Main Location:</label> <select name="select-choice-1" id="select-choice-1"> <option value="NSW">NSW</option> <option value="ACT">ACT</option> <option value="VIC">VIC</option> <option value="SA">SA</option> <option value="QLD">QLD</option> <option value="NT">NT</option> <option value="WA">WA</option> <option value="TAS">TAS</option> </select> </li> <!-- Select Menus: Main Location--> <li> <div data-role="fieldcontain"> <fieldset data-role="controlgroup"> <legend>CBA Reference</legend> <input type="checkbox" name="checkbox-1a" id="checkbox-1a" class="custom" /> <label for="checkbox-1a">Commercial</label> <input type="checkbox" name="checkbox-2a" id="checkbox-2a" class="custom" /> <label for="checkbox-2a">Retail</label> </fieldset> </div> </li> </ul> </div> <!-- End of Field Contain div tag --> <a href="#additionalinfo" data-role="button" data-inline="true" data-iconpos="left" data-theme="b">Additional Info</a> <a href="./search2.html" rel="external" data-ajax="false" data-role="button" data-inline="true" data-icon="search" data-iconpos="left" data-theme="e">Search</a> </code> I want to know, how I can include only the elements the user selected in my SQL query. Lets say, User wants to find the Electrical workers in QLD, then he will select Yes for Electrical and QLD as Main Location and the other items he would not touch. Now, how can I include only those two values in the select clause. Say, Select Electrical, Main Location from table where Main location='QLD'. I used POST method to gather users input. I use PHP, MySQL for this project. Any ideas on how to achieve this. Regards Sandeep Similar TutorialsHello. I'm a newbie so sorry if this isn't the best forum to post my problem.
I am using a MySQL and PHP to create a web app. I have authentication, and I can register users. I also have a form that users provide information and it is successfully inserting data into a table in my database.
I will use fictional fields for my database table called meal_info:
username
dateStartedDiet
numberMealsPerDay
costPerMeal
Problem: Select user-specific data from the MySQL database, using Session username to select only the current user's data, then display it and do some calculations.
Here is thecode at the top, and I am fairly sure it's working:
session_start(); //execute commone code
require("common.php"); //includes code to connect to database, etc.
if(empty($_SESSION['user'])) I have searched this forum as well as over 200 other forums and have not found the answer that is specific to my question. I have shortened my code drastically to assist in resolving this quickly -
I have a search form that has criteria for the search criteria with "virtual" "columns" in an array but it's not working. If I search one column at a time it works just fine but when I try to search 8 columns with one select I get the following error: SELECT Error: Unknown column 'achievements' in 'where clause'.
When a user selects search in Achievements, I need it to look at all 8 columns that are associated with achievements and bring back the results that match - the same as if the user selects search in Associations, I need it to look at all 5 columns and bring back the results that match.
My shortened code is as follows:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Search</title>
</head>
<body>
<form name="search" action="" method="POST">
<p>Search:</p>
<p>
Achievements/Associations: <input type="text" name="find1" /> in
<Select NAME="field1">
<Option VALUE="achievements">Achievements</option>
<Option VALUE="associations">Associations</option>
</Select>
<br><br>
Secondary Education: <input type="text" name="find2" /> in
<Select NAME="field2">
<Option VALUE="edu1sectype">Highest Certificate Attained</option>
<Option VALUE="edu1secname">Highest Grade Passed</option>
<Option VALUE="edu1secinst">Name of High School</option>
<Option VALUE="edu1secdate">Date Completed</option>
<Option VALUE="edu1secinsttyp">Type of Institution</option>
<Option VALUE="subjects">Subjects</option>
</Select>
<br><br>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</p>
</form>
<?php
$searching = $_POST['searching'];
$find1 = $_POST['find1'];
$field1 = $_POST['field1'];
$find2 = $_POST['find2'];
$field2 = $_POST['field2'];
if ($searching =="yes")
{
echo "<br><b>Searched For:</b> $find1 $find2<br>";
echo "<br><h2>Results</h2><p>";
//If they did not enter a search term we give them an error
// Otherwise we connect to our Database
include_once "connect_to_mysql.php";
mysql_select_db("table_name") or die(mysql_error());
// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim($find);
$find = mysql_real_escape_string($find);
$field = mysql_real_escape_string($field);
$data = mysql_query("SELECT * FROM table_name
WHERE upper(".$field1.") LIKE '%$find1%'
AND upper(".$field2.") LIKE '%$find2%'
") or die("SELECT Error: ".mysql_error());
$result = mysql_query("SELECT * FROM table_name
WHERE upper($field1) LIKE '%$find1%'
AND upper($field2) LIKE '%$find2%'
") or die("SELECT Error: ".mysql_error());
$num_rows = mysql_num_rows($result);
echo "There are $num_rows records:<br>";
echo '<center>';
echo "<table border='1' cellpadding='5' width='990'>";
// set table headers
echo "<tr><th>Reference</th>
<th>First Name</th>
<th>Last Name</th>
</tr>";
//get images and names in two arrays
$name= $row["name"];
$surname= $row["surname"];
$achieve1 = $row["achieve1"];
$achieve2 = $row["achieve2"];
$achieve3 = $row["achieve3"];
$achieve4 = $row["achieve4"];
$achieve5 = $row["achieve5"];
$achieve6 = $row["achieve6"];
$achieve7 = $row["achieve7"];
$achieve8 = $row["achieve8"];
$assoc1 = $row["assoc1"];
$assoc2 = $row["assoc2"];
$assoc3 = $row["assoc3"];
$assoc4 = $row["assoc4"];
$assoc5 = $row["assoc5"];
$edu1sectype = $row["edu1sectype"];
$edu1secinst = $row["edu1secinst"];
$edu1secname = $row["edu1secname"];
$edu1secdate = $row["edu1secdate"];
$edu1secinsttyp = $row["edu1secinsttyp"];
$subject1 = $row["subject1"];
$subject2 = $row["subject2"];
$subject3 = $row["subject3"];
$subject4 = $row["subject4"];
$subject5 = $row["subject5"];
$subject6 = $row["subject6"];
$subject7 = $row["subject7"];
$subject8 = $row["subject8"];
$compsoft1name = $row["compsoft1name"];
$compsoft2name = $row["compsoft2name"];
$compsoft3name = $row["compsoft3name"];
$compsoft4name = $row["compsoft4name"];
$compsoft5name = $row["compsoft5name"];
$compsoft6name = $row["compsoft6name"];
$achievements = array('achieve1', 'achieve2', 'achieve3', 'achieve4', 'achieve5', 'achieve6', 'achieve7', 'achieve8');
$associations = array('assoc1', 'assoc2', 'assoc3', 'assoc4', 'assoc5');
$subjects = array('subject1', 'subject2', 'subject3', 'subject4', 'subject5', 'subject6', 'subject7', 'subject8' );
$compsoft = array('compsoft1name', 'compsoft2name', 'compsoft3name', 'compsoft4name', 'compsoft5name', 'compsoft6name');
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td ALIGN=LEFT>" . $row['id'] . "</td>";
echo "<td ALIGN=LEFT>" . $row['name'] . "</td>";
echo "<td ALIGN=LEFT>" . $row['surname'] . "</td>";
echo "</tr>";
}
echo "</table>";
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0) {
echo "Sorry, but we can not find an entry to match your query";
}
}
?>
</body>
</html>
Any assistance will be greatly appreciated as I have been working on this website for the past 4 months which has totalled over 150 pages and this is one of the last pages left to program and it's taken 6 days to get to this search page to this point.
I'm a newbie, can you please help? I'm getting a mysql error "Unknown column 'E0000001' in 'where clause'" The id is in the URL: ...user-profile.php?id=E0000001 My Query $query = mysqli_query($con, "SELECT * FROM UserList WHERE UserID=".$id) or die (mysqli_error($con)); Thank you Edited September 18, 2019 by ACBMSEHi, All: I'm trying to figure out what way it's the best way to pull info belonging to a specific user based on whether he's a logged-in "member", and want to make sure he's not able to access any other member's details... would the best way be to try to match the user's "username" stored in a $_SESSION when fetching his info, something like this: Code: [Select] <?php // Assume the login combo is this: $username = $_POST['username']; $password = $_POST['password']; // Assume he has already logged in: $_SESSION['username'] = $username; //EXAMPLE 1: SELECTING user info simply from actual DB username/password match: if ($_SESSION['username']) { $userRecords = mysql_query("SELECT * FROM users WHERE username = '$username' AND password = '$password'"); $userInfo = mysql_fetch_array($userRecords); echo $userInfo['id'] . $userInfo['username'] . $userInfo['first-name'] . $userInfo['last-name'] . $userInfo['date-register']; } // EXAMPLE 2: or SELECTING user info based on $_SESSION['username'] value: if ($_SESSION['username']) { $userRecords = mysql_query("SELECT * FROM users WHERE username = . $_SESSION['username'] . AND password = '$password'"); $userInfo = mysql_fetch_array($userRecords); echo $userInfo['id'] . $userInfo['username'] . $userInfo['first-name'] . $userInfo['last-name'] . $userInfo['date-register']; } ?> So, my question is, are this actually working differently? is one better than the other as far as security, preventing other users from hacking either on purpose or accidenally into other user's details? thank! Appreciate any feedback... The PHP code sends me an email from the server, but the user input is empty or "blank". I only receive: "From: \ Email: \ Subject: \ Message: " and that's it. How do I fix my PHP and/or HTML code to receive user input from the form? Attached is my existing HTML and PHP code that doesn't send me any "user input" from the form. Thanks to anyone who can help!!
So I have an array of IDs that I would only like to select from a database table instead of everything in the table. How might I go about doing that? Hello,
First of all I'd like to say thank you for all the great information on the forums, I've been reading a lot on here lately.
I've started to make a website where users can log in and submit items to a database, which is then displayed on another page.
If Tom and Bill both post 10 items, all 20 items will be displayed on the "listings" page, however on the main log in screen Tom will only see his own 10 items and Bill will see his own 10 items.
This is all working perfectly, however, I now need to add a delete button so that they can delete specific items.
I have loosely followed this tutorial here to get the table to display as I want it (amongst a few other things, such as the user logins) http://www.wickham43...mphptomysql.php
I've added the delete button in the PHP loop for each row, I just can't figure out how to delete the specific row when clicked.
Any help would be really appreciated
Edited by eklem, 22 October 2014 - 08:10 AM. Hi, I have created a session based logon system using php and MYSQL from some tutorials I found online which is working very successfully. I can log on and of and move through different pages with no problems. My query is how do I output or display the information that is specific to the user which is currently logged on and block access to any other users information. I am quite sure there is a simple solution that is escaping me. If you could point me in the right direction it would be greatly appreciated. Thanks in advance I am not sure if the title is correct; I tried my best.
I'm a PHP/MySQL beginner and I really need some help.
I have a small script that I am using for sending SMS. I recently added a phonebook. The problem with the phonebook right now is that it's available to all users, i.e. they can all update and delete all rows. What I would like to do is make it so that each user can update and delete only their own contacts.
I have a table call contacts. Inside that table there is first name, last name, company and phonenumber.
How can I accomplish this with PHP & MySQL?
CREATE TABLE IF NOT EXISTS `contacts` ( `contact_id` int(10) NOT NULL AUTO_INCREMENT, `firstname` varchar(255) NOT NULL, `lastname` varchar(255) NOT NULL, `company` varchar(255) NOT NULL, `cell_no` text NOT NULL, PRIMARY KEY (`contact_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; CREATE TABLE IF NOT EXISTS `users` ( `user_id` int(11) NOT NULL AUTO_INCREMENT, `users_name` varchar(30) NOT NULL, `uname` varchar(30) NOT NULL, `u_pass` varchar(60) NOT NULL, `utype` varchar(30) NOT NULL, `timezone` varchar(30) NOT NULL, `uapi_user` varchar(30) NOT NULL, `uapi_pass` varchar(60) NOT NULL, PRIMARY KEY (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;
<?php
if (isset($_POST['submit'])){
//form has been submitted1
$firstname = trim($_POST['firstname']);
$lastname = trim($_POST['lastname']);
$company = trim($_POST['company']);
$cellno = trim($_POST['cell_no']);
if($firstname == ''){
echo '<div class="alert alert-danger">First Name is not Valid!</div>';
exit;
}elseif($lastname == ''){
echo '<div class="alert alert-danger">Last Name is not Valid!</div>';
exit;
}elseif($company == ''){
echo '<div class="alert alert-danger">Company is not Valid!</div>';
exit;
}elseif($cellno == ''){
echo '<div class="alert alert-danger">Cellphone Number is not Valid!</div>';
exit;
}else{
$query = "Select cell_no from contacts where cell_no = '".$cellno."' ";
$result = mysql_query($query);
if (!mysql_num_rows($result)) {
$sql = "INSERT INTO contacts(firstname, lastname, company, cell_no)
values('{$firstname}','{$lastname}', '{$company}', '{$cellno}')";
$result = mysql_query($sql);
confirm_query($result);
//echo '<div class="alert alert-success">Successfully added.</div>';
//exit;
?>
<script type="text/javascript">
window.location = "contact_list.php";
</script>
<?php
}
else{
echo '<div class="alert alert-danger">Username. already exist!.</div>';
echo '<p><a href="new_contact.php" class="btn btn-success"> Back </a></p>';
exit;
}}
}else{
$firstname = "";
$lastname = "";
$company = "";
$cellno = "";
}
?>
I have a family site with a member list and a forum that both run on MySql. One of the items in the member list is the birthday. What I like to achieve is that a day or 2 before a member's birthday, a post wil be automaticly inserted in the forum, (a post that contains that this persons birthday is comming up in a few days) without any user input. I like to have this done automaticly because I don't feel like setting up a cron job for every member seperatly. There are just too many members. What I need is a script that will create a cron job or something simular the moment a new member registers and updates his profile and sets his birthday. So I'm trying to basically trying to make an "advanced search" function in PHP/mysql that will allow users to search by a number of different options like search by zipcode, username, gender, etc. Now my question is how do I vary my mysql query so that it searches for all these things based on whatever the user inputs? For example, the user might need to search zipcode and username but not gender, but in another case, might need to search username and gender, but not zipcode. Obviously I could just do some if/else statements, but that would be increasingly more difficult as there are more fields. What can I do? Hi, I have a SQL statement: $sql='SELECT PROPID, ADDRESS_1, ADDRESS_2, TOWN, POSTCODE1, POSTCODE2, BEDROOMS, BATHROOMS, RECEPTIONS, PRICE, TRANS_TYPE_ID FROM properties WHERE TRANS_TYPE_ID=2 AND BEDROOMS =3 AND PROP_SUB_ID IN (1,2,3,4,5,6,21,22,23,24,27,30,95,128,131) ORDER BY DATE_ADDED, PROPID DESC'; I want to be able to get the fields and their corresponding values as such: $result['TRANS_TYPE_ID']=2; $result['BEDROOMS']=3; And then capture the values in PROB_SUB_IN IN(*) How can I do this? Any help will be greatly appreciated. Thanks I am brand new to mysql and php but I have created a database and loaded two tables using cPanel and phpMyAdmin. Now I need some programs to access my data. I have a couple of simple ones that work, but I can't figure out what I really need, I am trying to Select a table Where the Value is a $variable, not a fixed value. Of course the end result will be to pass the value from a Form, but I have to get this to work first. <?php // Connect to database============================= include("connect_db.php"); $table='airplanes'; $amano='123456' $iden='1' // Send query =========================================================== // $result = mysql_query("SELECT * FROM {$table} where ama='123456'"); == this works // $result = mysql_query("SELECT * FROM {$table} where ama='940276'"); == this works // $result = mysql_query("SELECT * FROM {$table} where id='1'"); // this works // $result = mysql_query("SELECT * FROM {$table} where id = '{$iden}'"); == doesnt work // $result = mysql_query("SELECT * FROM {$table} where id = $iden"); == doesnt work // $result = mysql_query("SELECT * FROM {$table} where id = ($iden)"); // == doesnt work // $result = mysql_query("SELECT * FROM {$table} where id = $iden"); // == doesnt work // $result = mysql_query("SELECT * FROM {$table} where ama='$amano'"); // == doesnt work $result = mysql_query("SELECT * FROM {$table} where ama=($amano)"); // == doesnt work Thanks Hi,
Im having a problem and I can't seem to figure it out or find anything on the net.
If I use the following code the script successfully updates every row in the table:
mysqli_query($con,"UPDATE Ads SET Ads_LocalArea='Stroud'");However if I try updating the table using the WHERE clause in any of the combinations below nothing happens. mysqli_query($con,"UPDATE Ads SET Ads_LocalArea='Stroud' WHERE Ads_ID=$DBROWID");---------------------------------------------------------------------- My Script:
mysqli_query($con,"INSERT INTO Ads (Ads_ID, Ads_AID, Ads_Title)
VALUES ('', '$Polished_AdRef', '$Polished_AdTitle')");
$DBROWID = mysqli_insert_id($con);
mysqli_query($con,"UPDATE Ads SET Ads_AID='Stroud' WHERE Ads_ID=$DBROWID");
// TRIED THESE TOO
// mysqli_query($con,"UPDATE Ads SET Ads_AID='Stroud' WHERE Ads_ID='$DBROWID'");
// mysqli_query($con,"UPDATE Ads SET Ads_AID='Stroud' WHERE Ads_ID='5'");
Does any one know where I am going wrong?
This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=342695.0 Hi all, I have an array of data. I am looping through this data to generate a CSV file. However, if there are commas in any of the elements then this will throw out the structure of the CSV file. My question is, how do I loop through the array before I use it to strip out any commas and replace with a space? Thanks for your help. I've been searching around for this for a while and nothing seems to be working properly. On my website I track who is online at the time (within the past 15 minutes). My database contains important information like ip addresses and page views during the visit. It also contains a column for two digit country codes (US, NL, CA, GB, etc.) It works great. But I'd like to display to my visitors how many countries people are visiting from at the time. I might have ten people from the US, three from England, and one from Canada. I'd like it to say we have visitors from 3 countries. My hope this could be accomplished with a simple query. Here's the code I have ended up with. But it's not working. Each visitor has one row in the table. "cCode" is the column name and "onlinenow" is the table name. I would have changed the names in my code below but I wanted to post my code exactly as is. Code: [Select] $cDiff = mysql_query("SELECT cCode, COUNT(cCode) AS number FROM onlinenow"); I also tried.... Code: [Select] $cDiff = mysql_query("SELECT cCode, COUNT(DISTINCT cCode) AS number FROM onlinenow"); It results in returning "Resource id#30" for the value of cDiff. What am I doing wrong. I am self taught and please forgive me if I didn't use the correct lingo. Thank You In Advance. I have this code that will get the absent dates for all employees, how can i make it for one specific employee using oracle id? code:
$res = $conn->query("SELECT s.oracleid
, s.staffname
, date_format(date, '%W %d/%m/%Y') as absent
FROM staff s
CROSS JOIN
date d
LEFT JOIN
attendance_records a ON s.oracleid = a.oracleid
AND d.date = DATE(a.clockingindate)
WHERE a.oracleid IS NULL
ORDER BY s.oracleid, d.date
");
the records i am concerned about is for the attendance records table, I have oracle id in that table. Hi Guys, I am fairly new to mySQL/PHP and I have an issue. I have a login/registration system for a website and it works. However in the registration the user enters info such as their phone and email. How can I access these two fields of info from the user who is currently logged in. For example someone makes an account with: Username: Person Password: hello Email: person@gmail.com Phone: 111-111-1111 Name: Hello Person When they log into the site using their username and password, how can I detect their email/phone/name? Thanks in advance! |
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