PHP - Need Help With Adding A Css Class
I had this working before, but my coding structure has changed a bit and need help with syntax.
My function I have down ok. function cssfrommvp($mvp) { $class = array('MVP' => 'MVP'); return $class[$mvp]; } this is how I would add the class to a <td> with $row. Code: [Select] echo "<td class=\"".cssfrommvp($row['mvp'])."\">".$row['mvp']."</td>\n"; now using $array <td> . $MVP .</td>\n</tr> how would I do the same thing as done before with $row? Similar TutorialsHi, I am adding "active_filter", "passive_filter" classes to links based on regex pattern coming from the URL: Line 46: https://github.com/laanes/product_filtering/blob/master/APF_URL.php The function gets called on line 89 in he https://github.com/laanes/product_filtering/blob/master/boxes/advanced_product_filtering_box.inc.php You can see it in action he http://www.swanseatimber.co.uk/shop/hafele/brand_281.html by clicking on a category on the left, under the heading "Filter Your Results". The clicked category gets a green background because of the added "active_filter" class. When you click again, it will get "passive_filter" class and the products are not filtered any more. The problem: When moving to other pages by using the pagination at the top of the product results, the class doesn't get added. Therefore, you can't remove the filter because function creating the href on line 72 in he https://github.com/laanes/product_filtering/blob/master/APF_URL.php and the function clearing all filters on line 100 in he https://github.com/laanes/product_filtering/blob/master/APF_URL.php both fail. What's interesting - when selecting a filter, moving to the next page, clicking in the browser url bar and hiting enter(hard reload i think?), the problem disappears and you can play with the filters again. I really hope you find a minute to look into it and help me. I have mysqli object in Database class base: [color=]database class:[/color] class Database { private $dbLink = null; public function __construct() { if (is_null($this->dbLink)) { // load db information to connect $init_array = parse_ini_file("../init.ini.inc", true); $this->dbLink = new mysqli($init_array['database']['host'], $init_array['database']['usr'], $init_array['database']['pwd'], $init_array['database']['db']); if (mysqli_connect_errno()) { $this->dbLink = null; } } } public function __destruct() { $this->dbLink->close(); } } Class derived is Articles where I use object dBLink in base (or parent) class and I can't access to mysqli methods (dbLink member of base class): Articles class: require_once ('./includes/db.inc'); class Articles extends Database{ private $id, .... .... $visible = null; public function __construct() { // Set date as 2009-07-08 07:35:00 $this->lastUpdDate = date('Y-m-d H:i:s'); $this->creationDate = date('Y-m-d H:i:s'); } // Setter .... .... // Getter .... .... public function getArticlesByPosition($numArticles) { if ($result = $this->dbLink->query('SELECT * FROM articles ORDER BY position LIMIT '.$numArticles)) { $i = 0; while ($ret = $result->fetch_array(MYSQLI_ASSOC)) { $arts[$i] = $ret; } $result->close(); return $arts; } } } In my front page php I use article class: include_once('./includes/articles.inc'); $articlesObj = new articles(); $articles = $articlesObj->getArticlesByPosition(1); var_dump($articles); [color=]Error that go out is follow[/color] Notice: Undefined property: Articles::$dbLink in articles.inc on line 89 Fatal error: Call to a member function query() on a non-object in articles.inc on line 89 If I remove constructor on derived class Articles result don't change Please help me I have an existing instance of my class Database, now I want to call that instance in my Session class, how would I go about doing this? If a class has a constructor but also has a static method, if I call the static method does the constructor run so that I can use an output from the constructor in my static method? --Kenoli Hi Can you call Class A's methods or properties from Class B's methods? Thanks. Ok. I know you can pass the object of a class as an argument. Example: class A { function test() { echo "This is TEST from class A"; } } class B { function __construct( $obj ) { $this->a = $obj; } function test() { $this->a->test(); } } Then you could do: $a = new A(); $b = new B($a); Ok so that's one way i know of. I also thought that you could make a method static, and do this: (assuming class A's test is 'static') class B { function test() { A::test(); } } But that is not working. I'd like to know all possible ways of accomplishing this. Any hints are appreciated. thanks Hi, I need to be able to call a class based on variables. E.G. I would normally do: Code: [Select] $action = new pattern1() but i would like to be able to do it dynamicaly: Code: [Select] $patNum = 1; $action = new pattern.$patNum.() Im wondering if that's possible? If so what would the correct syntax be? Many Thanks. I have two classes: ## Admin.php <?php class Admin { public function __construct() { include("Config.php"); } /** * deletes a client * @returns true or false */ function deleteClient($id) { return mysql_query("DELETE FROM usernames WHERE id = '$id'"); } } ?> ## Projects.php <?php class Projects { public function __construct() { include("Config.php"); $this->admin = $admin; $this->dataFolder = $dataFolder; } /** * Deletes a project * @returns true or false */ function deleteProject($id) { $root = $_SERVER['DOCUMENT_ROOT']; $theDir = $root . $this->dataFolder; $sql = mysql_query("SELECT * FROM projectData WHERE proj_id = '$id'"); while ($row = mysql_fetch_array($sql)) { $mainFile = $row['path']; $thumb = $row['thumbnail']; if ($thumb != 'null') { unlink($theDir . "/" . substr($thumb,13)); } unlink($theDir . "/" . substr($mainFile,13)); } $delete = mysql_query("DELETE FROM projectData WHERE proj_id = '$id'"); $getDir = mysql_query("SELECT proj_path FROM projects WHERE id = '$id'"); $res = mysql_fetch_array($getDir); rmdir($theDir . "/" . $res['proj_path']); return mysql_query("DELETE FROM projects WHERE id = '$id'"); } } ?> How can I call deleteProject() from within Admin.php? Hi people! class FirstOne{ public function FunctionOne($FirstInput){ //do stuff and output value return $value1; } } Then:- class SecondOne{ public function FunctionTwo($AnotherInput){ //do stuff and output value return $value2; } } What I want to know is this, if I want to use FunctionOne() in Class SecondOne do I do it like this:- (Assume as I have instantiated the first class using $Test = new FirstOne(); ) class SecondOne{ function SecondedFunction(){ global $Test; return $Test->FunctionOne(); } public function FunctionTwo($AnotherInput){ //do stuff and output value return $value2; } public function FunctionThree(){ //some code here $this->Test->SecondedFunction();<--I think as I can omit the $this-> reference } } My point is: Do I have to do it this way or is there way of having this done through __construct() that would negate the need for a third party function? I have a version working, I just think that it is a little convoluted in the way as I have done it, so I thought I would ask you guys. Any help/advice is appreciated. Cheers Rw I do know how to do this but I am curious about whether or not there is a "preferred" way to do this. I know there are a couple ways to use a class (I'll call Alpha_Class) within another class (I'll class Beta_Class) Let's say we have this simple class (Beta_Class): class beta { function foo(){ } } If I wanted to use the Alpha Class within the Beta Class, I could any number of things. For example: class beta { function foo(){ $this->alpha = new alpha; //$this->alpha->bar(); } } Or you could simply use the $GLOBALS array to store instantiated objects in: $GLOBALS['alpha'] = new alpha; class beta { function foo(){ //GLOBALS['alpha']->bar(); } } You could even declare Alpha_Class as a static class and thus would not need to be instantiated: static class alpha { static function bar(){} } class beta { function foo(){ //alpha::bar(); } } Those are the only ways I can think of right now. Are there any other ways to accomplish this? I was wondering which way is the best in terms of readability and maintainability. How does one go about using one class inside another? For example, building a class that does some series of functions, and uses a db abstraction layer class in the process? I have a class in which I have a function called connection. I am now trying to call this function from another class, but it will not work. It works if I put the code in from the other function rather than calling it but that defeats the purpous. class locationbox { function location() { $databaseconnect = new databaseconnect(); $databaseconnect -> connection();{ $result = mysql_query("SELECT * FROM locations"); while($row = mysql_fetch_array($result)) // line that now gets the error, mysql_fetch_array() expects parameter 1 to be resource, boolean given //in { echo "<option>" . $row['location'] . "</option>"; } } }} Hi all, I have two classes. Registration and Connection. Inside a registration.php I include my header.php, which then includes my connection.php... So all the classes should be declared when the page is loaded. This is my code: registration.php: <?php include ('assets/header.php'); ?> <?php class registration{ public $fields = array("username", "email", "password"); public $data = array(); public $table = "users"; public $dateTime = ""; public $datePos = 0; public $dateEntryName = "date"; function timeStamp(){ return($this->dateTime = date("Y-m-d H:i:s")); } function insertRow($data, $table){ foreach($this->fields as $key => $value){ mysql_query("INSERT INTO graphs ($this->fields) VALUES ('$data[$key]')"); } mysql_close($connection->connect); } function validateFields(){ $connection = new connection(); $connection->connect(); foreach($this->fields as $key => $value){ array_push($this->data, $_POST[$this->fields[$key]]); } $this->dateTime = $this->timeStamp(); array_unshift($this->data, $this->dateTime); array_unshift($this->fields, $this->dateEntryName); foreach($this->data as $value){ echo "$value"; } $this->insertRow($this->data, $this->table); } } $registration = new registration(); $registration->validateFields(); ?> <?php include ('assets/footer.php'); ?> At this point I cannot find my connection class defined on another included/included page. $connection = new connection(); $connection->connect; config.php (included within header.php) <? class connection{ public $dbname = '**'; public $dbHost = '**'; public $dbUser = '**'; public $dbPass = '**'; public $connect; function connect(){ $this->connect = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass) or die ('Error connecting to mysql'); mysql_select_db($this->dbname, $this->connect); } } ?> Any ideas how to call it properly? Well the title may seem a bit confusing, but heres an example: Code: [Select] <?php class User{ public $uid; public $username; protected $password; protected $email; public $usergroup; public $profile; public function __construct($id){ // constructor code inside } public function getemail(){ return $this->email; } public function getusergroup(){ return $this->usergroup; } public function getprofile(){ $this->profile = new UserProfile($this->uid); } } class UserProfile(){ protected $avatar; protected $bio; protected $gender; protected $favcolor; public function __construct($id){ // constructor code inside } public function formatavatar(){ // avatar formatting code inside } public function formatusername(){ // format username? } } ?> As you can see, the User class(an outer class) has a property called Profile, which can be instantiated as a UserProfile object(an inner class). The two objects have distinct functionalities, but there are times when the UserProfile object needs to access property and methods from the user object. I know its easy for outer class to access methods from inner class by using the single arrow access operator twice, but how about the other way around? Lets say from the above example the userprofile can format the username displayed to the screen by adding a sun to the left of the username if the usergroup is admin, a moon if the usergroup is mod, and nothing if its just a member. The usergroup property is stored in the outer class, and can be accessed with this $user->getusergroup() method only. I know I can always do the hard way by passing a user object to the method's argument, but is there an easier way for the inner class UserProfile to access properties/methods for outerclass User? If so, how can I achieve that? i have: Code: [Select] class Host { public $hostname; public $foundResults; public function __construct($hostname) { $this->$hostname = $hostname; $foundResults = array(); } } but when i create a object the hostname doesn't get set, instand a new propert get's created What do i do wrong? Quote Host Object ( [hostname] => [foundResults] => [www.google.nl] => www.google.nl ) Need some help whit the following code: The problem is when i try to insert into database it appears only the first letter in the name column and in the text column it appears exact letter like in the name column. Code: [Select] newArticle(); function newArticle() { $article = new Article; $article->storeFormValues("SOMENAME","SOMETEXT"); $article->insert(); echo $article->id." ".$article->name." "; } Code: [Select] class Article{ public $id = null; public $name = null; public $text = null; public function __construct($data=array() ) { if( isset($data['id']) ) $this->id= $data['id']; if( isset($data['name']) ) $this->name= preg_replace ( "/[^\.\,\-\_\'\"\@\?\!\:\$ a-zA-Z0-9()]/", "", $data['name'] ); if( isset($data['text']) ) $this->text= preg_replace ( "/[^\.\,\-\_\'\"\@\?\!\:\$ a-zA-Z0-9()]/", "", $data['text'] ); } public function storeFormValues ( $params ) { // Store all the parameters $this->__construct( $params ); } public function insert() { $con = new PDO(DBN,DB_USER,DB_PASS); $sql = "INSERT INTO articles (name,text) VALUES (:name, :text) "; $st = $con->prepare($sql); $st->bindValue(":name", $this->name, PDO::PARAM_STR); $st->bindValue(":text", $this->text, PDO::PARAM_STR); $st->execute(); $this->id = $con->lastInsertId(); $con=null; } } I have a simple class like this: <?php class packet { private $SERVER = "192.168.1.100"; } ?> This works fine on localhost but on the server the $SERVER variable needs to be "72.20.32.58" instead. It's a pain having to keep changing this manually and using "localhost" doesn't work for some reason. I wanted to use $_SERVER['SERVER_ADDR'] but it errors when I use it. I have an issue with PHP/Apache which means I can't see the error that it returns. Can anyone tell me how I could set the $SERVER variable to $_SERVER['SERVER_ADDR'] in the class? im trying to learn more on OOP so decided to try this code: class asf { public $_template; public function __construct() { $this->_template = new newTemplate; } } class newTemplate { public function setTemplate($template) { global $asf; $asf->_template = $template; } public function getTemplate() { global $asf; return $asf->_template; } } $asf = new asf; $asf->_template->setTemplate('default'); echo $asf->_template->getTemplate(); setTemplate() works but i get the following error on getTemplate(): Code: [Select] Call to a member function getTemplate() on a non-object can anyone explain why and let me know how to fix it? Thanks. I need to add a class to the div at the end of my for each. How do I say if the function breaks, add in class="lastmessage" <?php $counter = 0; foreach ($conversations as $conversation) { if(++$counter == 5) break; ?> <div class="(add class here)"> <a href="blah"><?php echo blah; ?></a> </div> <?php } ?> Okay, so I want to take a stab at my first PHP class. Here is what I want it to do, but I'm not sure where to begin?! I have an HTML form in my index.php file, and when the user clicks "Register", I'd like to have registration.php which will contain the class Registration take what was entered in the form and print it out on the user's screen. This is an academic example, but it will get my feet wet! So, some questions... 1.) If registration.php is basically my Registration class, then where do I "instantiate" the class to create a "registration object"? 2.) How do I pass what was entered into the form to my registration class? Can you pass arguments to a class while you are instantiating it? Or do I instantiate the class, and then pass values to the object? Or do I let the object somehow get the values? 3.) I assume if I make it this far, then I can display the values by just having echo statements in the class/object, maybe as a method? Thanks, TomTees |