PHP - Taking Screenshot Of Currently Open Webpage
Hi all...
I am facing problems in taking screenshot for the currently open page. What I want is by clicking on a link like "Click for taking Screenshot" the screenshot of that page gets generated, which can be saved further. I have tried by using "imagegrabscreen" & "imagegrabwindow" but both of them results as a big black png image, also searched forums but not able to get the perfect match. If any expert there...then plzzzzz do help me out.... Thank You Similar TutorialsHi Guys, Yet again, I was wondering if one of you genious's could help me. I want to be able to take a screenshot of an entire webpage (From the header to footer) using a PHP script. So If I crawled the webpage URL = http://www.google.co.uk/search?q=php+sc ... =en&num=10 I would like to take a screenshot of that entire page from the GOOGLE header to the GOOGLE footer and store it into a TEMPORARY folder on my server and then be able to call it back. Is this possible? I've been searching everywhere for a solution to this but the closest thing I came to was http://mistonline.in/wp/get-youtube-vid ... avascript/ I would be really grateful if one of you could please help me, thank you in advance. M Well I am using easy php and I need to make a script that will open up a script in easy php in the web browser.. so like a script to open http://127.0.0.1:8888/script.php then sleep for x amount of time then open another script in the browser http://127.0.0.1:8888/script2.php Any help is appreciated Hello there! I'm looking for a script that generates website screenshots. I want to use a script on my server bcz, i think, it will work faster than use services like webshotspro.com or any other, and have no restriction on size. I need a script that can cache the screenshot and refresh it every 2 weeks for example. Hope that you can help me on this. Thank you in advance! I have the content of an email in a database, and I need to generate a screenshot of the email based on that.. I'm thinking this won't be possible in PHP and I'll have to use some service? Anyone know where to begin? Without using FFMPEG that is, since my host refuses to allow it. I really don't want to change hosts just for this one thing, I'm happy otherwise, but I need this work. I just need to grab a frame from a video when the user uploads the video. I can't use FFMPEG like I said, but I saw a suggestion someone had that said "have PHP open the video in fullscreen and take a screencap". That would work perfectly, I just have not a CLUE how to do it. Does anyone have experience doing this? I just want it to grab a screenshot and have it saved as a jpg with the same filename as the video, for obvious reasons...call the video player and pass it the filename with a .jpg attached for the screenshot param. Any help is appreciated! Thanks. try { echo "<br>"; foreach($dbh->query("SELECT * FROM test_shot WHERE sold=1 ORDER BY year ASC") as $row) { if($row['picture'] != "" && $row['picture'] != null) { echo "<div class='image-holder'><img src ='".$row['picture']."' width=300px /><br>"; } if($row['year'] != "" && $row['year'] != null) { echo $row['year']; } if($row['description'] != "" && $row['description'] != null) { echo $row['description']; } if($row['sold'] == 1) { echo "<img src='images/sold1.png'><br>";//Add your image code here } elseif ($row['sold'] == 0) { echo "</div><br>"; } } } catch (PDOException $e) { print $e->getMessage(); } ?>
I'm trying to open a URL using fopen() and I keep getting this error: Code: [Select] Failed to open stream: Permission deniedI can not work out what is wrong, it's not a firewall as far as I can tell. Hello, Is there any way to capture a screenshot of a full length view of a website using php on a shared hosting linux server? After many, many years of struggling, I would like to finally learn how to separate my website's PRESENTATION from its LOGIC. I have been working on a startup business for over a decade now. And one of the reasons it is taking me so long to build my website from scratch is because I am a horribly INEFFICIENT PROGRAMMER!! On one hand, I think I write solid business logic. But considering that each of my scripts averages between 1,000-2,000 lines of code, that is a monster to manage. (My website is over 50,000 lines of code at this point. All home-grown and hand-coded.) While it is hard to manage things while I am actively coding, what kills me even more, is when I get pulled away for months (or recently for 2 years), and then later on when I come back, it is a nightmare to load all of that code into my brain?! I mean if you read any of my scripts starting at line 1 and going through line 1,500 I think it reads pretty well. But who in the hell can keep track of all of that in one reading? It's certainly a struggle for me!! I definitely wantto strive for more of a "component archtecture" approach. (On a side note, I have heard "good" Object-Oriented programmers claim that if a class is more than 100 lines of code then it is too long?!) So anyways.... My #1 priority for v2.0 is to learn and master separating my website's PRESENTATION from its LOGIC using something like MVC. (And after that, my goal is to finally learn and master Object-Oriented Programming, but one thing at a time!!) I want to finally learn how to program like a *professional* coder. (A very successful and RICH professional programmer!!!) ? So, can all of you gurus out there, please help me get started with a solid Model-View-Controller introduction and/or resources and/or advice?? I know the Internet is littered with this topic, but like anything done well, you need to find good learning materials and at least one or two good mentors. After all, if MVC and OOP and whatever were so easy, then everyone would be doing it, and doing it well. (And of course you realize that very few people actually do things like MVC and OOP well!!) So my goal is to become a "jedi", but I will need some good teachers to get there...
Edited February 24, 2019 by SaranacLake Type-o's and added some more stuff... I'm trying to get details of family members to display in a grouped fashion under their family, but for some reason the cell phone (mobile phone) number comes through from the query but not into the variable assignment!? I've used FirePHP to track the variable assignments and I can see that the value pulls into the query variable $per_Cellphone but not through into the array as it outputs a NULL value!? The Email works fine, just not CellPhone? $aCellPhone[$iCount] = $per_Cellphone; $aEmail[$iCount] = $per_Email; I have just recently began learning PHP. I have a pretty solid foundation in general programming and PHP. As my first major PHP project I am trying to make myself an autobuyer for Fifa 15 using curt2008 Fifa API. He basically has everything there for me to use and I know that I have enough knowkledge to get a basic autobuyer going if I could just figure out how to log in. I have come to realize that the problem is that I have no idea what he is doing when he connects to the Fifa Web App. He has the code there for me, but I don't know what it is actually doing. I was hoping someone can point me to some documentation, a tutorial, or even exercises so that I may learn more about... logining into a web application? I don't even know what to call it.
Looking at connect.php he has a bunch of functions. Login, getSessionID, Phishing, getNucleusID, getShards, and all of them do a bunch a requests and use a bunch of headers. I don't know what this terminology is or how it all works together, but I would like to learn about it. Thats why I wanted to start learning PHP, for stuff like this. I just don't know where to look.
Thank You
I am trying to adapt a database search form from a tutorial I saw, and it's not working. I just get a blank white slate despite having error_reporting(E_ALL); at the top of the page. I was hoping someone might be able to spot anything obvious I might be missing. Here is my code <?php error_reporting(E_ALL); // include MySQL-processing classes require_once 'mysql.php'; try{ // connect to MySQL $db=new MySQL(array ('host'=>'localhost','user'=>'username','password'=>'password', 'database'=>'DBName')); $searchterm=$db->escapeString($_GET['searchterm']); $result=$db->query("SELECT last_name, first_name,employee_id,title,territory,districts FROM Scores WHERE MATCH(last_name,first_name,employee_id,title,territory,districts) AGAINST ('$searchterm')"); if(!$result->countRows()){ echo '<div class="maincontainer"><h2>No results were found. Go back and try a new search.</h2></div>'."n"; } else{ // display search results echo '<div class="maincontainer"><h2>Your search criteria returned '.$result->countRows().' results.</h2>'."n"; while($row=$result->fetchRow()){ echo '<div class="rowcontainer"><p><strong>First Name: </strong>'.$row['first_name'].'<p><p><strong>Last Name: </strong>'.$row['last_name'].'</p><p><strong>Employee ID: </strong>'.$row['employee_id'].'</p> <p><strong>Title: </strong>'.$row['title'].'</p> <p><strong>Territory: </strong>'.$row['territory'].'</p> <p><strong>Districts: </strong>'.$row['districts'].'</p> </div>'."n"; } } echo '</div>'; } catch(Exception $e){ echo $e->getMessage(); exit(); } ?> and here is the included file mysql.php code <?php // define 'MySQL' class class MySQL{ private $conId; private $host; private $user; private $password; private $database; private $result; const OPTIONS=4; public function __construct($options=array()){ if(count($options)!=self::OPTIONS){ throw new Exception('Invalid number of connection parameters'); } foreach($options as $parameter=>$value){ if(!$value){ throw new Exception('Invalid parameter '.$parameter); } $this->{$parameter}=$value; } $this->connectDB(); } // connect to MySQL private function connectDB(){ if(!$this->conId=mysql_connect($this->host,$this->user,$this- >password)){ throw new Exception('Error connecting to the server'); } if(!mysql_select_db($this->database,$this->conId)){ throw new Exception('Error selecting database'); } } // run query public function query($query){ if(!$this->result=mysql_query($query,$this->conId)){ throw new Exception('Error performing query '.$query); } return new Result($this,$this->result); } public function escapeString($value){ return mysql_escape_string($value); } } // define 'Result' class class Result { private $mysql; private $result; public function __construct(&$mysql,$result){ $this->mysql=&$mysql; $this->result=$result; } // fetch row public function fetchRow(){ return mysql_fetch_assoc($this->result); } // count rows public function countRows(){ if(!$rows=mysql_num_rows($this->result)){ return false; } return $rows; } // count affected rows public function countAffectedRows(){ if(!$rows=mysql_affected_rows($this->mysql->conId)){ throw new Exception('Error counting affected rows'); } return $rows; } // get ID form last-inserted row public function getInsertID(){ if(!$id=mysql_insert_id($this->mysql->conId)){ throw new Exception('Error getting ID'); } return $id; } // seek row public function seekRow($row=0){ if(!is_int($row)||$row<0){ throw new Exception('Invalid result set offset'); } if(!mysql_data_seek($this->result,$row)){ throw new Exception('Error seeking data'); } } } ?> Hi all, first of all sorry if this is in the wrong board, im currently building a site which will charge an annual fee of X amount. I've never build something like this before so Ill be using paypal for ease of use and security, but how would you usually go about constructing the tables etc? Hi i have the following code Code: [Select] $orderFetch->order="3"; mysql_query("UPDATE `categories` SET order=order-1 WHERE `order` > $orderFetch->order"); i wish to minus -1 from all the "order" fields in categories that are over a certain value i.e 3. But however this code is not working can anyone tell me where i'm going wrong? thank you I am using this code in my "create_account.php" script... Code: [Select] mail($trimmed['email'], ' Please Activate Your Account', $body, 'From: admin@mywebsite.com <admin@mywebsite.com>'); It is taking anywhere from one to several hours to receive this e-mail in my inbox?! It used to take seconds, and now takes forever. I thought it was a Gmail or SPAM issue, but I just did a test on my AT&T paid account and the same issue so far... It's awfully hard to do development and testing if I have to wait a half-a-day to get these e-mails?! Debbie This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321088.0 Hi, I have a searchbar which looks for a value in my tables, it works great but i want to know how i can make the results of the search clickable; go to a page relevent to that search, let me explain in more depth. User searches for a postcode, script finds and displays the postcode on the next page, user clicks the result postcode to goto the next page. What im stuck with is how to take that result and automatically display it on the clicked "final" page? Search script: Code: [Select] <?php // Get the search variable from URL $var = @$_GET['q'] ; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=10; // check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } //connect to your database ** EDIT REQUIRED HERE ** mysql_connect("xxxxx","xxxx","xxxx"); //(host, username, password) //specify database ** EDIT REQUIRED HERE ** mysql_select_db("removalspacelogin") or die("Unable to select database"); //select which database we're using // Build SQL Query $query = "(SELECT postcode FROM freelistings WHERE postcode like '%$trimmed%') UNION (SELECT postcode FROM basicpackage WHERE postcode like '%$trimmed%') UNION (SELECT postcode FROM premiumuser WHERE postcode like '%$trimmed%') ORDER BY postcode"; // EDIT HERE and specify your table and field names for the SQL query $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); $result = mysql_query($query) or die("<b>Query:</b> $query<br><b>Error</b>: " . mysql_error()); // If we have no results, offer a google search as an alternative if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>"; echo "<p><a href=\"http://www.google.com/search?q=" . $trimmed . "\" target=\"_blank\" title=\"Look up " . $trimmed . " on Google\">Click here</a> to try the search on google</p>"; } // next determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; } // get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); // display what the person searched for echo "<p>You searched for: "" . $var . ""</p>"; // begin to show results set echo "Results for $q"; $count = 1 + $s ; // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row['postcode']; echo " $title" ; $count++ ; } $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> <form method="post" action="localarea.php"> <a href="localarea.php"><?php echo """ .$var. ""</p>";?></a> </form> [\code] The form at the bottom im guessing is where i should take the $var from but how exactly? or if not where should it be pulled from to display on the next page? I want this "next" page because ideally there would be lots of results in postcode, so the user can choose which one is more relevant to them and go to that specific page with all the companies within that postcode. Hope this helps for a better understanding of what im trying to achieve, its just implementing it in? I have a small issue here which I can't quite figure out. I have three containers on one page all below each other. One for buttons, a JS image slideshow and a description box. The image slider seems to take up unnecessary space when the browser is resized activating media queries:
http://gyazo.com/333...d5668e240fae788
CSS desktop view (without media queries):
body { background: #141414 url('../images/background1.png'); background-repeat: repeat-y; background-attachment:fixed; background-position:center; } #container{ height:450px; width:840px; margin:120px auto 2% auto; position:relative; } #container2{ height:60px; width:840px; margin:0 auto 50px auto; position:relative; -moz-box-shadow:0 0 5px 5px black; -webkit-box-shadow:0 0 5px 5px black; box-shadow:0 0 5px 5px black; } #container2 p{ color:white; font-size:15px; padding-left:5px; } #container2 h2{ color:white; font-size: 18px; text-decoration:none; padding-left:5px; padding-top:2px; } #img{ height:450px; width:840px; position:absolute; -moz-box-shadow: 0 0 5px 5px black; -webkit-box-shadow: 0 0 5px 5px black; box-shadow: 0 0 5px 5px black; } #l_holder{ height:450px; width:100px; position:absolute; left:0px; top:0px; cursor:pointer; } #r_holder{ height:450px; width:100px; position:absolute; right:0px; top:0px; cursor:pointer; } .left{ height:50px; width:50px; position:absolute; top:45%; left:0px; } .right{ height:50px; width:50px; position:absolute; top:45%; right:0px; } .clear{ clear:bottom; }CSS with media queries, this is where the container is causing a problem: @media all and (min-width: 3.5in) and (max-width: 10in) { body { background: #141414; } #container{ height:30%; width:100%; margin:5% auto; padding:0 0 0px 0; } #container2{ width:100%; margin: 0; padding: 0; } #container2 p{ padding-left:3px; } #container2 h2{ padding:5px 0 0 3px; } #container2 .body_black_box{ } #img{ height:80%; width:100%; } #l_holder{ height:80%; } #r_holder{ height:80%; } .left{ } .right{ } .clear{ } }Any help is greatly appreciated. Hi all
we have an ajax query which queries a MySQL database for cities around the world for our hotel search. We are running on a Linux web hosted server.
The problem we are having is when you first visit out site and type in Brisbane or Sydney it takes around 15 seconds maybe to return. After that what ever city you query is lightening fast. I have had a few friends try this and when they first visit our site they experience the same then second time around it is fast.
Could this be some sort of caching issue or setting somewhere that I am missing?
I have attached a file so you can see what I mean
Thanks in advance
Attached Files
ajaxqry.jpg 169.31KB
0 downloads Hi, I am creating a date string using the following: $curDate = date("Y-m-d H:i:s"); However, what I want to do is take one hour off this so that $curDate now becomes the current date and time minus one hour. Thanks for your help. |