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PHP - Php Include In A Tpl File Question
Hi
I'm in a need of help here, I need to inluded this: "http://site.com/products.php?do=groups&groupid=2" in a a tpl file. Any way that this can be done? an example would be greatly appreciate it. cheers Similar TutorialsHow can I use an include file that has a list of links in any directory at my website without breaking those links? You can see it in action here... The links in this directory work... https://www.billelgin.com/primary-directory/ The links in this directory (being created from the same include file) do not work... https://www.billelgin.com/primary-directory/subsection-one/ Obviously the problem is the include file is being called from different directories, so it's breaking the relative path links in the include file, but what can I do to fix it? You can download the example directory structure here... https://www.billelgin.com/EXAMPLE.zip I have a php file that generates a string that I need to use in a .js (javascript)file. Being that php developers sometimes using javascript with php, Im hoping someone can help me with this, cause i dont know any javascript. Code: [Select] //This is the varible inside the .js file var suggestionText = "I need to be able to include my string generated by the php file here..."; Just a quick question about including php files on a page... Let's say I have my index page that is a fully functioning page with all the <html>, <body>, and <head> tags where they should be. Now I want to include another file, which also has <html>, <body>, and <head> tags. Would this cause any problems or is it ok to include the second file as is? I want to include a php file after an succesfully login. Let's suposed that I have a login form on index.php. If the login was ok I want to include a php file with some content instead of the login form. Something like: Code: [Select] <? if($_POST['ok']){ require('content.php'); } else { //login form } ?> It's ok to include in the code the name of the file that you have on server ? From security point of view. Thanks www.desmond-otoole.co.uk/secure/securefunctions.php /bank/admin/index.php what should I do in the index.php file to access securefunctions.php
require("../secure/SecureFunctions.php"); Nothing seems to work
I just get a stupid google chrome page saying Can I include a class file in the same page that I use an instance of the same class with my action attribute with my form. Here's the code Code: [Select] <?php include 'Resources/User.php';?> <html> <head> <title></title> <link href="stylesheets/styles.css" rel="stylesheet" type="text/css"/> </head> <body> <form action = "Resources/testClass.php" method="post" enctype="multipart/form-data"> <label>First Name: </label> <input type="text" name="fname" id="fname" size="25" maxlength="25"/> <label>Last Name: </label> <input type="text" name="lname" id="lname" size="25" maxlength="25"/> <label>Email: </label> <input type="text" name="email" id="email" size="25" maxlength="40"/> <label>Username: </label> <input type="text" name="username" id="username" size="25" maxlength="32"/> <label>Password: </label> <input type="password" name="password" id="password" size="25" maxlength="32"/> <label>Re-enter Password: </label> <input type="password" name="conf_pass" id="conf_pass" size="25" maxlength="32"/> <br /><br /> <input type="submit" name="submit" id="submit" value="Register"/> <input type="reset" name="reset" id="reset" value="Reset"/> </form> </body> </html> Hello, Im trying to pass a variable to a newly created page using GET. Code: [Select] $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title'>" . $nt[$i] . "</a>" . "<br/>"; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); header.php Code: [Select] <head> <?php $title = $_GET['Title']; ?> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <p>HEADER UPDATED!</p> <p>TESTING - the heading below should read (title goes here in capital letters)</p> <?php <h1>$title</h1> ?> //This is line 12 </body> </html> Im getting the error; Parse error: syntax error, unexpected '<' in D:\Hosting\3753557\html\1pw\mexican.php on line 12 I suspect that I have my syntax muddled in header.php? Is there a better way to pass variables to a newly created page? (fopen). Many thanks for any ideas. Any help is much appreciated in advance... I have a master file located along the root path that needs to be included in subdomains. Inside the master file are includes like Code: [Select] <?php include("../bodyCopy/anyfile.php"); ?> that need to reference the /bodyCopy directory IN THE SUBDOMAIN and NOT along the root. The problem that I'm having is that the master file resides OUTSIDE of the subdomain on the root (in a '/bodyCopy' directory. How do I write the PHP include so that files included in a subdomain from outside of the subdomain (on root) search directories INSIDE the subdomain and NOT relative to the root path? Here's what I mean. I have this file sitting on the root: /home/xxxx/public_html/constructfiles/filetoinclude.php It needs to be included he /home/xxxx/public_html/SUBDOMAIN/publicfile.php Then, 'filetoinclude.php' needs to include other files that are he /home/xxxx/public_html/SUBDOMAIN/bodyCopy/otherfilestoinclude.php ...but, 'filetoinclude.php' is searching along the root path for '/home/xxxx/public_html/bodyCopy/otherfilestoinclude.php' (which does not exist), and NOT within the SUBDOMAIN for the '/home/xxxx/public_html/SUBDOMAIN/bodyCopy/otherfilestoinclude.php' like I need it to. It appears that PHP will only search along the root path of the included file and NOT the root path of the file in which an include is included. I'm confusing myself now, but I hope someone can help. Thanks, Jet - Hello person who reads this now I work a lot with <?php include("..."); ?> and I never thought beyond the html I put in there. In 1 of the include files I have the set-up of a simple vertical html/css menu and on the right next to it I have an image. However, not every page on my website needs the same image and I probably will change a lot of them frequently. Now I was wondering if (and how) I could include a piece of PHP code which does the following: If the web-url is "page1.php" show "image1.png" If the web-url is "page2.php" show "image2.png" If the web-url is "page3.php" show "image3.png" etc. This way I only have to change the "imageX.png" in 1 file. I hope you can help me. Best regards and thanks in advance! Ferdri3 I'm really embarrassed asking this.. I have two files. config.php & program.php config.php<php $max_columns = 3; ?> program.php<?php include ('config.php'); echo $max_columns; ?> I can't get the script to echo anything. I have tried... $max_columns = '3'; $max_columns = "3"; include_once include ("config.php"); include ('/path/to/file/config.php'); require .....etc. etc. Any thoughts? PLEASE, I'm going nuts here. Thanks for you patience with what must be a very trivial question for you guys In my code include_once "http://myserver.com/someFile.php" does not work but include_once "/someFile.php" works I NEED to be able to full URL. Anyone know what PHP setting I need to change to get this working for me? Thanks
I am using an inclue file on my layout.php page. Hi peeps iv been trying to figure out this but i cant see it....its probably obvious!!! in the $header variable the include files dont show... any ideas here the php code <? session_start(); ?> <link href="/styles/main.css" rel="stylesheet" type="text/css" /> <? //get data $button = $_GET['submit']; $search = $_GET['search']; $search = strtoupper($search); $header = ("<table width='100%' border='0' height='80' cellpadding='4' bgcolor='#000000' > <tr> <td width='39%' height='76' valign='top'><p><span class='stigrosheadfont'><strong>www.StigRos.com</strong></span><strong><span class='headnocrap'><br /> ( No Crap - Just Quality Movie & Music Downloads )</span></span><br /> <a href='http://mysite' class='headerlinkcolor'>Home</a> | <a href='register.php' class='headerlinkcolor'>Register</a> | <a href='#' class='headerlinkcolor'>Contact us</a></strong></td> <td width='47%' valign='bottom'><p class='normalblacktext'>You are currently logged in, <b>$_SESSION[username]</b></td> <td width='14%' valign='top'><div align='center'> <div align='center'><span class='headfont'><strong>Disclaimer</strong></span></div> <div align='center'> <? include_once 'countertest.php'; ?> <? date('F d, Y'); ?></div></td> </tr> </table>"); $s = $_GET['s']; if (!$s) $s = 0; $e = 10; // Just change to how many results you want per page $next = $s + $e; $prev = $s - $e; if (strlen($search)<=2) echo "Must be greater then 3 chars $user"; else { echo $header; echo " <form action='search.php' method='GET'> <center> <br> <input name='search' type='text' class='blacktext' size='50'> <input name='submit' type='submit' class='blacktext' value='Search Film'></font></p> </center> </form> "; //connect to db include('db.php'); //explode out search term $search_exploded = explode(" ",$search); foreach($search_exploded as $search_each) { //construct query $x++; if ($x==1) $construct .= "keyword LIKE '%$search_each%'"; else $construct .= " OR keyword LIKE '%$search_each%'"; } //echo outconstruct $constructx = "SELECT * FROM movies WHERE $construct"; $construct = "SELECT * FROM movies WHERE $construct LIMIT $s,$e"; $run = mysql_query($constructx); $foundnum = mysql_num_rows($run); $run_two = mysql_query("$construct"); if ($foundnum==0) echo "No results found for <b>$search</b>"; else { echo "<table bgcolor='#000000' width='80%' height='1px' align='center'><br /></table><table bgcolor='#000000' width='80%' height='10px' align='center'><tr><td><div align='right'><font color='#E6E6E6'>Showing 1-10 of <b>$foundnum</b> results found for <b>$search.</b></font></div></td></tr></table><p>"; echo "<br>"; while ($runrows = mysql_fetch_assoc($run_two)) { //get data $title = $runrows['film']; $desc = $runrows['description']; $url = $runrows['dl_link']; $imdb = $runrows['imdb']; $pic = $runrows['pic']; $film = $runrows['film']; echo "<table width='900' border='1' align='center'> <tr> <td width='229' align='center'><IMG SRC='$pic'></td> <td class='blacktext' width='655' align='center'><b>$film</b><br /><br />$desc<br /><br /><a href='$url' target='_blank'><b>Download Now</b></a> | <a href='$imdb' target='_blank'><b>IMDb</b></a></td> </tr> </table> "; } ?> <table width='100%'> <tr> <td> <div align="center"> <?php if (!$s<=0) echo "<a href='search.php?search=$search&s=$prev'>Prev</a>"; $i =1; for ($x=0;$x<$foundnum;$x=$x+$e) { echo " <a href='search.php?search=$search&s=$x'>$i</a> "; $i++; } if ($s<$foundnum-$e) echo "<a href='search.php?search=$search&s=$next'>Next</a>"; } } ?> </div> </td> </tr> </table> hi php freaks, Is there a way to parse an include file through the php engine and then place the contents into a variable? Code: [Select] $x = include ($myfile); Hello, I have a simply query that will if a simple two different things: Code: [Select] $cssyn = mysql_query("SELECT `12` FROM `12345` WHERE `abc` = '$_SESSION[number]'"); $cssy = mysql_fetch_row($cssyn); if($cssy[0] == "YES") { echo "Yes"; } else { echo "No"; } The YES or NO result is stipulated earlier on so thats not the problem. But basically before I added the if statement simply would have echoed a table with all the rows etc from another query. However I would like to give the user a choice between echoeing the results into one table or a neater two. I have separated the code for the table and the queries into two separate files but say if I use: file_get_contents then it just prints the HTML and doesnt actually populate it will the queried parts. Nor if I use something like include() then it wont echo anything, which it wouldnt unless called so what I am asking is: Is there a way to get EVERYTHING from the file if the answer is YES or the other file if NO. How do I include a file that is located two directories above the file that I want to include the file into? My absolute hosting path is /home/content/52/8840652/html if this would be of any use. I'm not quite sure about the PHP include functions. Any help would be greatly appreciated, Thanks! My catalog uses a template file to list product details. One part of it is responsible for putting these details into nifty little tabs: <?php $template = '{magictabs style=black_rounded, tabwidth=110px}'; $template .= 'Technical Specifications'; $template .= '::'; $template .= '<table colspan="3"><tr><td>'; $template .= $details; $template .= '</td></tr></table>'; $template .= '||||'; ?> I don't want it to output $details, I want it to output a separate script instead. How do I include this separate file as a variable? I want this: <?php include('specs.php'); ?> to replace the $details variable. Hi all, I'm at a dead-end here. I have a php file that I can query to return an array containing a bunch of data about a job listing. I include and query it by calling it like so within another file on my site. Quick Notes: The original file is in a different directory on my site than the page it's being included in. I have tried returning the array at the end of the script. I can print_r the array on the page I'm including the script on (so the URL path is correct). If I go to this URL directly and print_r on the array, I see the entire array as expected. Also, if I include the file on page 2 like I did above with print_r on the array in the original file, I see the array printed out on page 2. Code: [Select] include 'http://www.example.com/php/job-details.php?job=jobname&city=thecity'; However, if I do not print_r on the array in the original file and just include it on page 2, I cannot do anything with it and the array variable isn't found. Is this a case of variable scope? I'm so frustrated... Here is the code I have in my original file: Code: [Select] <? include('functions.php'); $jobtitlematch = $_GET["job"]; $jobcitymatch = $_GET["city"]; //echo $jobtitlematch; //echo $jobcitymatch; $url = 'http://somesite.com/something'; $xml = simplexml_load_file($url); foreach($xml->job as $job) { $jobtitle = makeURL((string)$job->title); $jobcity = makeURL((string)$job->region); if ($jobtitle == $jobtitlematch && $jobcity == $jobcitymatch) { $jobdata[] = array( Title => ((string)$job->title), URL_Title => makeURL((string)$job->title), Location => ((string)$job->region), URL_Location => makeURL((string)$job->region), Department => ((string)$job->department), URL_Department => makeURL((string)$job->department), Overview => ((string)$job->joboverview), Responsibilities => ((string)$job->responsibilities), Qualifications => ((string)$job->qualifications), Keywords => ((string)$job->metakeywords) ); } return $jobdata; //I have also tried return global $jobdata; } print_r($jobdata); ?> Thanks in advance for any help you can provide... Here is a section of php file A include_once(dirname(__FILE__) . '/PhpfileB.php') $VALID_RATING_IDS = $Ratethese Here is all of php file B $Ratethese = "array("1", "2",);" I need the var $VALID_RATING_IDS to = $Ratethese from file B I am trying to include an array from php file B in php file A. Is this possible? How can i accomplish this? |
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