PHP - How To Check The Data In Mysql?

Hi Guys,

Im using the code below to display the value of checked checkboxes on form submission, however im also trying to pull the price from the database for each checked value.

foreach ($_POST['check'] as $product)

{

echo $row['price'] . " " . $row['currency'] . " for " . $product . "<br />";

}


Please could somebody point me in the right direction as to what id need to do. As iv only been able to get it to display the price of the first checked value.

Thanks

Hi I am trying to select and order data/numbers from a colum in a mysql data base however i run the code and it returns no value just a blank page no errors or any thing so i think the code is working right but then it returns no result? Please help thanks

Here is the code:

<?php
$host= "XXXXXX";
$mysql_user = "XXXXXX";
$mysql_password = "XXXXXX";
$mysql_database = "XXXXXXX";

$connection = mysql_connect("$host","$mysql_user","$mysql_password") or die ("Unable to connect to MySQL server.");
mysql_select_db($mysql_database) or die ("Unable to select requested database.");

$row = mysql_fetch_assoc( mysql_query( "SELECT XP FROM Game ORDER BY number DESC LIMIT 1" ) );
$number = mysql_result(mysql_query("SELECT XP FROM Game ORDER BY number DESC LIMIT 1"), 0);

echo "The the highest XP is $number";

?>

hi guys, im new to this forum

I'm new also to php, I need help from you guys:

I want to display personal information from a certain person (the data is on the mysql database) using his name as a link:

example:
               (index.php)
               names
                          1. Bill Gates
                          2. Mr. nice Guy
           
i want to click Bill Gates
 
   (output.php)
     Name: Bill Gates
     Country:xxxx
     Age: xx   
                 etc.

How can i make this or how to learn this?
   
                 

             
               

   
       

hi guys,  in my form i need to insert an ID which is 5 digits number only. can anyone please tell me how can i check this before i insert? and also i need to check existing ID in my database.

Hey Guys,

I have got 3 chained select boxes working. Basically what you do is check for a region with the country, then once you pick a region, you select a club within that region. Once you have selected the club, you can then choose a team from within that club.

Screenshot: Attchment


As part of this chained select boxes's, a user can register. Although, the user has to FIRST check if the TEAM has already been registered in the database.

I have taken a screenshot of my database, which shows the regions, clubs, and teams from the chained select boxes. What i want to do now is be able to check if a TEAM is already registered in the database. So as you can see in the database, the team 'NPOB, Senior As' has already been taken.

Database Screenshot: Attachment


*** How do i check if a user has been registered to one of the teams? And if there is not a registered user to that team, they can then register it.

Here is my code:


<?php
include"database.php";
?>

<script type="text/javascript">

/*
Triple Combo Script Credit
By Philip M: http://www.codingforums.com/member.php?u=186
Visit http://javascriptkit.com for this and over 400+ other scripts
*/

var categories = [];
categories["startList"] = ["Taranaki","Auckland"]
// Regions + Clubs
categories["Taranaki"] = ["NPOB","Tukapa"];
categories["Auckland"] = ["Marist","Takapuna"];
// Clubs + Teams within that Club
categories["NPOB"] = ["Senior As","Senior Bs","Colts U21s"];
categories["Tukapa"] = ["Senior As","Senior Bs","Colts U21s"];
categories["Marist"] = ["Senior As","Senior Bs","Colts U21s"];
categories["Takapuna"] = ["Senior As","Senior Bs","Colts U21s"];

var nLists = 3; // number of select lists in the set

function fillSelect(currCat,currList){
var step = Number(currList.name.replace(/\D/g,""));
for (i=step; i<nLists+1; i++) {
document.forms['tripleplay']['List'+i].length = 1;
document.forms['tripleplay']['List'+i].selectedIndex = 0;
}
var nCat = categories[currCat];
for (each in nCat) {
var nOption = document.createElement('option'); 
var nData = document.createTextNode(nCat[each]); 
nOption.setAttribute('value',nCat[each]); 
nOption.appendChild(nData); 
currList.appendChild(nOption); 
} 
}

// function getValue(L3, L2, L1) {
// alert("Your selection was:- \n" + L1 + "\n" + L2 + "\n" + L3);
// }

function init() {
fillSelect('startList',document.forms['tripleplay']['List1'])
}

navigator.appName == "Microsoft Internet Explorer" ? attachEvent('onload', init, false) : addEventListener('load', init, false);

</script>


<form name="tripleplay" action="testingdropdown.php" method="post">
<select name='List1' onchange="fillSelect(this.value,this.form['List2'])">
<option selected>Choose Region</option>
</select><br /><br />

<select name='List2' onchange="fillSelect(this.value,this.form['List3'])">
<option selected>Choose Club&nbsp;&nbsp;&nbsp;</option>
</select><br /><br />

<select name='List3' onchange="getValue(this.value, this.form['List2'].value, 
this.form['List1'].value)">
<option selected >Choose Team&nbsp;&nbsp;</option>
</select>
<input type="submit" name="tripleplay" value="Register">
</form>


<?php
     if (isset($_POST['tripleplay'])) {
         
         
     $region = addslashes(strip_tags($_POST['List1']));
     $club = addslashes(strip_tags($_POST['List2']));
     $team = addslashes(strip_tags($_POST['List3']));

    $email = 'email';

$check = mysql_query("SELECT * FROM managers WHERE email='$email'");
           if ($email == '') {
         echo "You can register that club";
         } else {
echo "Sorry that team has already been registered";
}
}

?>

I have two questions regarding $byte_array.

1. Is there a general way to check if a $byte_array contains any data?

2. Is there a way to confirm if the $byte_array contains an actual PNG image?

Hi, 
I have multiple table 
Table -1 
order_no name 
1 raj 

table -2 
order_no name 
1 raj 

table 3 
order_no name 
1 raj 

table 4 
order_no name 
1 raj 

table 5 
order_no name 
1 raj 

I want a query to check if the id (one) is present in all tables or not, 
i create this. 


select order_no from prepress, press, postpress, qc, binding, dispatch where order_no=prepress.order_no AND order_no=press.order_no AND order_no=postpress.order_no AND order_no=qc.order_no AND order_no=binding.order_no AND order_no=dispatch.order_no 
but the ambiguous error for order_no. 

how to achieve this can anyone suggest me? 
thanks

hi all,

I have an array(1,2,3,4) and

i make a form and make checkboxes for this array and user selects 2,3 and 4

when user submit form

then i save it in table by making selected check boxes and converting selected values into bitwise equivalent value

like this
                                       
                                       
foreach($data['meal_types'] as $v){
$mealTypeBits += pow(2,$v-1);
}


Now when i have to show user his selected data how will i compare table bitwise saved record with array(1,2,3,4) to get the values that he checked while saving.

Hello. I want to check if an e-mail address is stored into a database. I've found this type of code:

Code: [Select]
function verifmail($email)
{
    db_connect();
    if (mysql_num_rows(mysql_query("SELECT email FROM users WHERE email='$email';")))
    {
        return 1;
    }
    else
    {
        return 0;
    }
}
Is it correct ? Is there any other way?

Hi guys, im inserting data into the table using drop-down list & multi select list,well it works very well. but i need to make sure i should not insert same StudentID & CourseID twice. here my code for you could anyone tell me pls where should i write code to check existing data?
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }


  mysql_select_db("uni", $con)or trigger_error('MySQL error: ' . mysql_error());
$result  = mysql_query("SELECT * FROM student") or trigger_error('MySQL error: ' . mysql_error());


echo '<select name="sid">';

while($row = mysql_fetch_array($result))
{

    echo '<option value="' . $row['StudentID'] . '">' . $row['StudentName'] . '</option>';
}

echo '</select>';

// ----------------

?>
</div>
<div class="style41" id="Layer7">

<?php
$result  = mysql_query("SELECT * FROM course") or trigger_error('MySQL error: ' . mysql_error());


echo '<select name ="cid[]" multiple="multiple" size="10">';

while($row = mysql_fetch_array($result))
{
    echo '<option value="' . $row['CourseID'] . '">' . $row['CourseName'] . '</option>';
}

echo '</select>';
mysql_close($con);
?>


------------------------------------
<?php

$con = mysql_connect("localhost","root","");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
 
  mysql_select_db("uni", $con)or trigger_error('MySQL error: ' . mysql_error());
   
 if (!empty($_POST['sid']) && !empty($_POST['cid'])) 
{
    $ct = 0;
    $student = $_POST['sid'];
    foreach ($_POST['cid'] as $key => $course)
    {
     $sql = "INSERT INTO take (StudentID, CourseID) VALUES('".mysql_real_escape_string($student)."',
 '".mysql_real_escape_string($course)."')";
     $query = mysql_query($sql) or trigger_error('MySQL error: ' . mysql_error());
     if (mysql_affected_rows() > 0){$ct++;}
     }
    echo $ct . ' rows added.';
 }  

mysql_close($con);

?>

//database
create table mydata (
	id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT,
	fname varchar(20),	
    phoneno int(12) NOT NULL
    /*......*/
);
//class my data php

<?php

include('connect.php');
class InsertMydata {
    public function insertnow($fname, $phoneno) {
        $connect = new Connect;
        $insrt = $db -> prepare('INSERT INTO mydata (fname, phoneno) VALUES (?,?)');
		$insrt -> execute(array($fname, $phoneno));		
	}
}
?>


//insernow validate form

<?php
include('../classs/mydata.php');
//Declare data and error arrays
$errors = [];
$mydara = [];
if(!preg_match('/^[a-zA-Z]{4,15}$/', $_POST['fname'])) {
	$errors['fname'] = 'Enter full name!';
}
//this block not working even the phone exist
$connect = new Connect;
$phoneno = $_POST['phoneno'];
$checkiexist = $connect -> prepare('SELECT * FROM mydata WHERE phoneno = ?');
$checkiexist -> execute([$phoneno]);
if($checkiexist->rowCount() > 0) {
      $errors['phonenoexist'] = 'Try another phone number!';
 }
if(!empty($errors)){
      $data['success'] = false;
      $data['errors'] = $errors;
}else{
      $data['success'] = true;
      $data['message'] = 'success message!';  
      $mydata = new InsertMydata;
      $mydata -> insertnow($fname, $phoneno);
}
echo json_encode($data);

?>

//my ajax

$("#insertbtn").click( function(e) {
     var fname = $('#fname').val(),
         phoneno = $('#phoneno').val(),
           
       $.ajax({
           url: 'insertnow.php',
           type: 'POST',
           data: {fname:fname, phoneno:phoneno},
           dataType: "JSON",
           encode: true,
        }).done( function (data) {
         
         if (data.success == false) {
           if (data.errors.fname) {
                 $('#fname').append('<p class="text-danger">' + data.errors.fname + '</p>');
            } 
            if (data.errors.phonenoexist) {
              $('.card-header').append('<div class="alert alert-info alert-dismissible" role="alert">
                <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.errors.phonenoexist+'</div>');
            }
            } else {
             $('.card-header').append('<div class="alert alert-success alert-dismissible" role="alert"><button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.message+'</div>');
        }
    });
       e.preventDefault();
    });


//the problem is, the code insert data even if the phone exist why?

the problem is, the code insert data even if the phone exist why?

Edited April 8 by mahenda

Hi guys
Can someone help me about this:
The php code can be revise username and password with CURL then check database and if username & password is correct return true else false.

Thanks

Hi guys,

I need your help. I am checking on a database as I want to see if I have the same value in the url and in the database.


Code: [Select]
<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbuser');
    define('DB_PASSWORD', 'mydbpass');
    define('DB_DATABASE', 'mydbtable');
       
    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {
  die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
  
    $username = clean($_GET['user']);
    $password = clean($_GET['pass']);
    $test = clean($_GET['test']);
    $public = clean($_GET['public']);
   
   
   if (isset($_GET['user']) && (isset($_GET['pass']))) {
    if($username == '' || $password == '') {
  $errmsg_arr[] = 'username or password are missing';
  $errflag = true;
    }
} elseif (isset($_GET['user']) || (isset($_GET['test'])) || (isset($_GET['public']))) {
    if($username == '' || $test == '' || $public == '') {
  $errmsg_arr[] = 'user or others are missing';
  $errflag = true;
    }
  }

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
  $qry="SELECT * FROM members WHERE username='$username' AND passwd='$password'";
  $result=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error());


if ($username && $password) {
  if(mysql_num_rows($result) > 0) {
     $qrytable1="SELECT images, id, test, links, Public FROM user_list WHERE username='$username'";
    $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error());

    while ($row = mysql_fetch_array($result1)) {
        echo "<p id='test'>";
        echo $row['test'] . "</p>";
        echo '<p id="images"> <a href="images.php?test=test&id='.$row['id'].'">Images</a></td> | <a href="http://' .  $row["links"] . '">Link</a> </td> | <a href="delete.php?test=test&id='.$row['id'].'">Delete</a> </td> | <span id="test">'.$row['Public'].'</td>';
     }
   } else {
    echo "user not found";
  }
} elseif($username && $test && $public) {
    $qry="SELECT * FROM members WHERE username='$username'";
    $result1=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error());
    
    if(mysql_num_rows($result1) > 0) {     
      $qrytable1="SELECT Public FROM user_list WHERE username='$username' && test='$test'";
      $result2=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error());
      
      if(mysql_num_rows($result2) > 0) {
        $row = mysql_fetch_row($result2);
        mysql_query("UPDATE user_list SET Public=('$_GET[public]') WHERE username='$username' AND test='$test'");
        echo "update!";
      } else {
        echo "already updated!";
      }
    } else {
      echo "user not found";
    }
  }
} 
?>
This is the function I use to check the value in the database:

Code: [Select]
if (mysql_affected_rows($result2) > 0) {
         mysql_query("UPDATE user_list SET Public=('$_GET[public]') WHERE username='$username' AND test='$test'");
         echo "you have update it!";
       } else if (mysql_affected_rows($result2) < 0) {
         echo "it is not on the database";
       } else {
         echo "you have already updated!";
       }

When i input the different value in a url bar while the records are not the same as the value in the url and in the database, i can't get passed and I am keep getting "you have already updated!!" when the value in a database are different than I have input in a url.

Do you know how i can get pass it when I have input the different value in the url while it is not the same in the database?

Any advice would be much appreicated.

Thanks,
Mark

Hello All,

I am new to PHP and I am trying to modify a already written script since I want to add a checkbox to my site.
In the front end I have
Code: [Select]
<input type="checkbox" name="privateurlcheck" id="privateurlcheck" value="0">
in the php I have
var privateurlcheck = document.getElementById( "privateurlcheck" ).value

Then in the mysql data insert php page,
$records[channel_protected] = $postData[privateurlcheck] ;

In MySQL "channel_protected" field is "ENUM" with Values '0','1'

When I run the code I see 0 in the MySQL channel_protected field even when I check the checkbox. All other values that are passed on to mysql such as name, age are posted correctly without any issues.


Can you please let me know how can I get 0 or 1 in the mysql depening on the checkbox status?

It is 5AM and I am trying to figure this for 2nd consecutive day! Greatly appreciate if any one can help me out.

I have this script running:


<?php
$query = mysql_query("SELECT * FROM jobs WHERE event = 'Yes' ORDER BY title");
while ($row = mysql_fetch_array($query)) {
?>


How do I check if a field is empty and NOT display it...?

For instance it has a 'applied' field, if that is empty I dont want it to display, however I still  need the event = 'Yes' part.