PHP - Display Certain Page If No Results From Query?
Hello all. I'm using this code to go through the database and output certain user-defined numbers
Code: [Select] <?php mysql_connect ("pdb1.awardspace.com", "anastasov_db","moscow1945") or die (mysql_error()); mysql_select_db ("anastasov_db"); $term = $_POST['term']; $sql = mysql_query("select * FROM countries WHERE cocode = '$term'"); while ($row = mysql_fetch_array($sql)){ echo '<br/> Code: '.$row['cocode']; echo '<br/> Country: '.$row['coname']; echo '<br/><br/>'; } ?> Now how would I go about making a page that appears if the script can't find any results in the database? Thank you in advance Similar TutorialsHello all, I have made the multi level marketing downline tree, but the problem with it now, it gives only the downline of one result, as the query gives 2 results what I want now is to make it give the downline of both results not just one, and it's always 2 results, not more here is my code Code: [Select] <?php $id = $_GET['id']; $result = mysql_query("SELECT id FROM users WHERE id = '".$id."' ORDER BY id"); $row = mysql_fetch_assoc($result); if ($row['id'] == 0) { echo" <table> <div id=\".piccenter\""; echo "<tr>"; echo "<img src=\"icon.gif\" border=0 align=\"center\">"; echo ""; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row['id']."'"; echo ""; echo "</div>"; } } $result2 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row['id']."'"); $rows2 = mysql_fetch_assoc($result2); foreach ($rows2 as $row2) { if ($row2['id'] == 0) { echo" <div id=\".picleft\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0 >"; echo "<br />"; echo "'".$row2['id']."'"; echo "</div>"; echo " <td>"; echo "</td> "; } } $result3 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows2['id']."'"); $row3 = mysql_fetch_assoc($result3); if ($row3['id'] == 0) { echo"<div id=\".picright\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row3['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result4 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row3['id']."'"); $rows4 = mysql_fetch_assoc($result4); if ($rows4['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows4['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result5 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows4['id']."'"); $rows5 = mysql_fetch_assoc($result5); if ($rows5['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows5['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result6 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows5['id']."'"); $rows6 = mysql_fetch_assoc($result6); if ($rows6['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows6['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result7 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows6['id']."'"); $rows7 = mysql_fetch_assoc($result7); if ($rows7['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows7['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result8 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows7['id']."'"); $rows8 = mysql_fetch_assoc($result8); if ($rows8['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows8['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result9 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows8['id']."'"); $rows9 = mysql_fetch_assoc($result9); if ($rows9['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows9['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> </tbody> </table> "; } ?> Hello, I know this should be pretty simple to figure out, but everything I try is giving me absolutely no results. I have a mysql query selecting columns from my database and returning results. I have the results printing out right now, so I can see that this part is working. All I want to do is take the results and put them into a table to display on my page. Basically, take what's in the database table and copy it to a table I can put on the web. FYI I am using sourcerer so the "connect" code is taken care of for me in the "JFactory" bit of code. Here is the first part of my code, selecting the information from the database. {source} <?php $db = JFactory::getDbo(); $query = $db -> getQuery(true); $query -> SELECT($db -> quoteName(array('first_dept_name', 'last_name', 'dept', 'position', 'phone_num'))); $query -> FROM ($db -> quoteName('#__custom_contacts')); $query -> ORDER ('first_dept_name DESC'); $query -> WHERE ($db -> quoteName('contact_category')."=".$db -> quote('YTown Employees')); $db -> setQuery($query); $results = $db -> loadObjectList(); print_r($results); Here is where I am trying to print the results into a table. I got this code directly from a PHP book, but I am getting nothing at all returned back to me. I get table headers, but no data. <?php echo "<table><tr><th>Name</th><th>Department</th></tr>"; while ($row = mysqli_fetch_array ($result)){ echo "<tr>"; echo "<td>".$row['last_name']."</td>"; echo "<td>".$row['dept']."</td>"; echo "</tr>"; } echo "</table>"; ?> {/source} Hey all. I have a query that selects data from a datbase based on a criteria. Easy enough. But now I am growing and the amount displaying is too much. How can you, via php, have a queries result be displayed only so many at a time and auto create links that show the rest? Like if query returns 82 results, I want it to display 25 immediately and create 3 links at the bottom. The next link would show 26-50. The next 51-75. And the final 76-82. etc Example: Code: [Select] $result = mysql_query("SELECT * FROM pay"); $num_rows = mysql_num_rows($result); while($row = mysql_fetch_array($result)) { echo $row['first_name']; echo $row['last_name']; echo $row['item_name']; echo $row['option_selection1']; echo $row['payment_date']; echo $row['stat']; } This is simple. But what happens when the results are 125? I want to limit it to displaying 25 at a time. Is the only way to manually create seperate pages and have each one show 1-25, then 26-50, etc? Or is there a way to have the script do it, itself? Any tutorials out there on this specifically? Hopefully I am making sense. Thanks! I have no clue about to go abt this one: I have form which has some: Code: [Select] <table> <tr> <td> <form> Title display info </form> </td> </tr> </table> I need to add an additional link next to title such that when someone clicks on the link the table expands and displays rsult of a query. Code: [Select] <table> <tr> <td> <form> Title LINK if( link is clicked ) { $query=select display query results } else { dont display query results display info } </form> </td> </tr> </table> Say a user puts in a support request, and for every request it generates a unqiue string, and enters it into the database. Ok, now say there is a text field, when the user enters their unique string and it finds a match, it displays the data along with it. How can I accomplish this? Im kind of new to mysql, but I know basic SQL. Would be great if somebody could point me in the right direction! Thanks In an .html, before : <!-- BEGIN myquery --> I need to stop output and check the content of "myquery" Is there a command for that ? Thank You. I have the following code that searches my database and displays results in a table: $fields = array("field1", "field2", "field3") $cols = implode (', ', $fields); $result= mysql_query (" SELECT $cols FROM tablename WHERE ................... "); if (!$result) {die('Could not search database: ' . mysql_error());} if($result) { if(mysql_num_rows($result) == 0) { return "Sorry. No records found in the database"; } else { $table = "<table border='1' cellpadding='5' cellspacing='5'>"; while($arr = mysql_fetch_array($result, MYSQL_ASSOC)) { $table .= "\t\t<tr>\n"; foreach ($arr as $val_col) { $table .= "\t\t\t".'<td>'.$val_col.'</td>'."\n"; } $table .= "\t\t</tr>\n"; } $table .= "</table>"; echo $table; } mysql_free_result($result); } As you can see each of the MySQL table fields specified by $fields is displayed in a new column in the html table. I want to change this so that e.g. "field3" is displayed in a new row instead. So, instead of the html table looking like: | "field1-result1" | "field2-result1" | "field3-result1" | | "field1-result2" | "field2-result2" | "field3-result2" | | "field1-result3" | "field2-result3" | "field3-result3" | I want it to look like: | "field1-result1" | "field2-result1" | | "field3-result1" | | | "field1-result2" | "field2-result2" | | "field3-result2" | | | "field1-result3" | "field2-result3" | | "field3-result3" | | I guess this is quite straightforward, but I can't work it out! Pls help! Thanks. First off, let me say that this will not be a public use site. We want to create a site that allows us to run queries in our database; this way we don't need to log into the MySQL server when ever we want to run a query. Basically, I am trying to create something as simple as a form with a text-input and a submit button. In this text-input, we will write a query (such as SELECT * FROM xxxx). When we hit submit, we would like to have the MySQL table printed out in a large textbox below. Our database has multiple tables, so something that works across the entire database seamlessly is key. Has anyone ever made anything like this? Is there another way to go about this? We really just want an easy way to run queries on the go. Thanks in advance to anyone who replies! Code: [Select] The form below is meant to retrieve the named attribute of a form input called "limitedtextfield" , along side the current date and store those values in a database. The form contains some javascript which can be disregarded for this particular problem. [code] <form name="mymind" style= "position:relative;left:40px;" action="insert_status.php" method="post"> <input name="limitedtextfield" type="text" onKeyDown="limitText(this.form.limitedtextfield,this.form.countdown,55);" onKeyUp="limitText(this.form.limitedtextfield,this.form.countdown,55);" maxlength="55"><br> <font size="1">(Maximum characters: 55)<br> You have <input readonly type="text" name="countdown" size="3" value="55"> characters left.</font> <input type="hidden" name="submitted" value="TRUE"/> <input style="position:relative;left:0px;bottom:0px;" type="submit" name="submit" value="Submit!" /> </form> Here is the php script that processes the form. What it is meant to do is search the database and if no record is found for the authenticated member, input the relevant values into the database. If a record is found, it should update the record. Well every time I hit the submit button, all I get is a blank page. Any clue as to what is going wrong? PS: I checked the database and no values got inserted. Code: [Select] <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user require('auth.php'); //Connect to database require ('config.php'); if (isset($_POST['submitted'])) { $query = "SELECT* FROM publications WHERE member_id ='".$_SESSION['id']."' AND cartegory='status'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { $update = mysql_query("UPDATE publications SET publication = '{$_POST['limitedtextfield']}' WHERE member_id = '".$_SESSION['id']."' AND cartegory = 'status'"); header("Location: member.php"); } else { $query = "INSERT INTO publications ( member_id, publication, cartegory, pub_date) VALUES ( '{$_SESSION['id']}','{$_POST['limitedtextfield']}', 'status', NOW() )"; header("Location: member.php"); } } ?> I have a search page and everything works fine but I would like to add the latest 10 rows to the page so there is something to look at or click on before the user searches. The page is at: www.giantstridedives.com/locations. You can see that it's pretty boring. Hit submit and you'll see the entries so far (only 3 right now). I'd like to have the latest 10 display there by default but then when a user searches they are replaced by the search results. Make sense? Here's the code I'm using for the search: Code: [Select] <?php if (isset($_POST['submit'])) { require_once('dbconnection.php'); mysqli_select_db($conn, $dbname); $searchterm = $_POST['search']; $searchterm = strip_tags($searchterm); $searchterm = trim ($searchterm); $q ="SELECT * FROM locations WHERE loc_name LIKE '%" . $searchterm . "%' AND loc_approved != '0'"; $r = mysqli_query($conn, $q) or die(mysql_error($q)); $row = mysqli_fetch_assoc($r); $rowcount = mysqli_num_rows($r); } ?> <h1>Search for Scuba Dive Locations</h1> <form id="searchform" name="searchform" method="post" action="index.php"> <input type="text" name="search" id="search_bar" /> <input type="submit" name="submit" id="submit" value="Submit" /> </form> <span style="color: #333;">Search for the name of the location, ie: Devils Den or USS Oriskany.</span><br /> <?php if (isset($_POST['submit'])) { if ($rowcount == 0) { echo "Sorry, but we can not find an entry to match your query: <strong>$searchterm</strong>"; } else { //this tells the table below to display since $totalRows_Products_res is not 0 ?> <table style="font-size: 14px;" border="0" width="650"> <tr> <td colspan="6"><p>You searched for <strong><?php echo $searchterm; ?></strong>. Results are displayed below.</p></td> </tr> <tr> <td><strong>Location Name</strong></td> <td><strong>City</strong></td> <td><strong>State</strong></td> <td><strong>Depth (ft)</strong></td> <td><strong>Fees</strong></td> <td><strong>Gear Rentals</strong></td> <td><strong>Map</strong></td> </tr> <?php do { ?> <tr> <td><a href="loc_details.php?loc_id=<?php echo $row ['loc_id']; ?>"> <?php echo $row ['loc_name']; ?> </a></td> <td><?php echo $row ['loc_city']; ?></td> <td><?php echo $row ['loc_state']; ?></td> <td><?php echo $row ['loc_depth']; ?></td> <td>$<?php echo $row ['loc_fee']; ?></td> <td><?php if($row['loc_gear'] == 1) { echo 'Yes'; } else { echo 'No'; } ?></td> <td><a href="http://maps.google.com/maps?q=<?php echo $row ['loc_lat'];?>,<?php echo $row ['loc_lon'];?>" target="_blank">View Map</a></td> </tr> <?php } while ($row = mysqli_fetch_assoc($r)); ?> </table> <?php mysqli_free_result($r); } // this closes out results else } ?> I figure I can use the below query to get the results. Code: [Select] select * from table WHERE id > ((SELECT MAX(id) from table) - 10);I'm just not sure how I can display them by default and then have them be replaced by the search results. Anyone have any ideas for me? As always I appreciate the help as I continue to learn this beast. Good day and Merry Christmas to all, I just spent a good time of my christmas eve trying to figure out this problem. I hope one of you santas would be so kind as to help me with it. First off I have two tables; employee and employee_works both connected via employee_id key. Basically I have a parent window we'll call parent.php. inside the parent page is a search button that once clicked will open a child window we'll call child.php inside the child page is a list, lets say employees with name, employee_id, etc. My main concern is this: How do I populate parent.php based off the employee selection I made in the child window. Example: -Access parent.php -Click on search -Click on [ID: 004] [NAME: JOHN SMITH] [PHONE: 1233456] [DATE HIRED: JULY 16, 1992] <---format of a row in child.php -child.php automatically closes and parent.php now shows all data from employee_works with the employee_id = 004 Is this even possible? I know this is vary vague and would be willing to explain more if needed. My website is built mostly on javascript and php. I wrote the page below to display a member's area of a website. The page is a mix of html and php code. the first part of is a block of php, which authenticates the user and displays the header. The middle part is a block of html which contains the bulk of the page. Embedded in this block of html are two sections of php, the first of which is supposed to display a user uploaded picture, enclosed in div tags, and the second of which, prints out the user's first name, from the database. The end of the script is a line of php that displays the footer. Now the page displays correctly when the section of php that contains the select query for displaying the picture(starting line 104) is omitted. But once I include that section, all i see is a blank page. Why is that section of php problematic? What can be done to fix it? Here is the data for the full page. Thanks for any help. <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user require('auth.php'); //define title define('TITLE' , 'Members'); require ('header.html'); //need the header ?> <div id="main" style="background-color: #FFFFFF; height:71%; width:101%; border:0px none none; margin:auto; "> <!-- --> <div id="main_left" style="float:left; height:100%; width:20%; border:0px none none;"> <!--opens main left--> <div id="main_left_top" style="float:left; position:relative;bottom:5px;right:5px; height:31.25%; width:100%; background-color: #FFFFFF; border:1px solid #c0c0c0; margin:1px;"> <!--opens main left top--> </div> <!-- closes main left top--> <div id="main_left_center" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left center--> <div id="main_left_bottom" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left bottom--> </div> <!-- closes main left--> <div id="main_center" class="content_text" style="float:left; height:100%; width:58%; background-color: #FFFFFF; border:1px solid #c0c0c0;"> <!--opens main center--> <div id="image_box" style="float:left; background-color: #c0c0c0; height:150px; width:140px; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); $query = "SELECT* FROM images WHERE member_id ='{$_SESSION['id']}' AND cartegoty 'main' "; $result = mysql_query($query); $result_data = mysql_fetch_array($result); header("Content-type: image/jpeg") ; echo $result_data['image']; ?> </div> <a href="upload_image_page.php">click here to uplaod a picture</a> <h1>Welcome <?php echo ucfirst($_SESSION['firstname']);?></h1> <a href="member_profile.php">My Profile</a> | <a href="logout.php">Logout</a> <p>This is a password protected area only accessible to members. </p> <a href="blog_entries.php">Add to Hahap Tok Library</a> </div> <!-- closes main center--> <div id="main_right" style="float:left; background-color: #FFFFFF; height:100%; width:20%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> <div id="main_right_top" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left top--> <div id="main_right_center" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left center--> <div id="main_right_bottom" style="float:left; background-color: #FFFFFF; height:34%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left bottom--> </div> <!-- closes main right--> </div> <!-- closes main--> <?php require('footer.html'); ?> Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete": if(isset($_POST['highlight-purchased'])) { // ****** Setup customized query to obtain only items that are checked ****** $sql = "SELECT * FROM shoplist WHERE"; for($i=0; $i < count($_POST['checkboxes']); $i++) { $sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or"; } $sql= rtrim($sql, "or"); $statement = $conn->prepare($sql); $statement->execute(); // *** fetch results for all checked items (1st query) *** // $result = $statement->fetchAll(); $statement->closeCursor(); // Setup query that will change the purchased flag to "N", if it's currently set to "Y" $sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'"; // Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL $sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL"; $statementSetToN = $conn->prepare($sqlSetToN); $statementSetToY = $conn->prepare($sqlSetToY); /*** loop through the results/collection of checked items ***/ foreach($result as $row) { if ($row["purchased"] != "Y") { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToY = $statementSetToY->fetch(); foreach($resultSetToY as $row) { $statementSetToY->execute(); } } else { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToN = $statementSetToN->fetch(); foreach($resultSetToN as $row) { $statementSetToN->execute(); } } } break; }CRUD Queston.png 20.68KB 0 downloads What would be the correct way to close a mysql query? At current the second query below returns results from the 1st query AND the 2nd query The 3rd query returns results from the 1st, 2nd and 3rd query. etc etc. At the moment I get somthing returned along the lines of... QUERY 1 RESULTS Accommodation 1 Accommodation 2 Accommodation 3 QUERY 2 RESULTS Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 QUERY 3 RESULTS Takeaways 1 Takeaways 2 Takeaways 3 Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php include($_SERVER['DOCUMENT_ROOT'].'/include/db.php'); ?> <title>Untitled Document</title> <style type="text/css"> <!-- --> </style> <link href="a.css" rel="stylesheet" type="text/css" /> </head><body> <div id="listhold"> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Placestostay.html">Places To Stay</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingout.html">Eating Out</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingin.html">Eating In</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------SKILLED TRADES BELOW---------------------------------------------------> <div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> Can someone please give me some ideas as to what might be wrong with this query...I keep getting no result and am echoing $count for debugging (and usernames and passwords) but get nothing for $count (expecting a 0 or a 1) or $dbusername or $dbpassword $sql="SELECT * FROM `users` WHERE `User name` = '$fusername' and `Password` = '$fpassword'"; $result=mysql_query($sql); $dbusername=mysql_result($result,0,"User name"); $dbpassword=mysql_result($result,0,"Password"); echo $dbusername; echo $dbpassword; // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $fusername and $fpassword, table row must be 1 row echo $fusername; echo $fpassword; echo $count; if($count==1){ (This is where I keep going to the else) quick question, I have this code that returns over 100 buttons: Code: [Select] <?php // Query member data from the database and ready it for display $sql = mysql_query("SELECT * FROM products"); while($row = mysql_fetch_array($sql)){ $product = $row["product"]; $id =$row["id"]; $price =$row["price"]; ?> <div id="products"> <form action="" method="POST" name="myform<?php echo $id; ?>" class="myform<?php echo $id; ?>"> <input type="hidden" name="hiddenField" class="hiddenField" value="<?php echo $product; ?>" /> <input type="hidden" name="hiddenField2" class="hiddenField2" value="<?php echo $id; ?>" /> <input type="hidden" name="hiddenField1" class="hiddenField1" value="<?php echo $price; ?>" /> <input type="submit" name="submit" class="submit" value="<?php echo $product; ?>" style="background-color:lightgreen; height:50px; width:100px;"> </form> </div> <?php } ?> What I would like is for the buttons to form columns of nine. ie 9 buttons in a column then a new column form.... how do I do this? this is my query code Code: [Select] <?php $wsi_query = "(SELECT * FROM (SELECT a.no_Yards AS 'yards', a.Day_Swam AS 'date', a.Season AS 'season', (SELECT sum(no_yards) FROM swimming WHERE Season = '$ws') AS 'totalyards', (SELECT AVG(no_Yards) FROM swimming WHERE Season = '$ws') AS 'avg', (SELECT count(*) FROM swimming WHERE Season ='$ws') AS 'timelaps', (SELECT 1 + count(*) FROM swimming b WHERE b.no_Yards > a.no_Yards AND Season = '$ws') AS hrank, (SELECT 1 + count(*) FROM swimming b WHERE b.no_Yards < a.no_Yards AND Season = '$ws') AS lrank FROM swimming AS a) AS x WHERE Season = '$ws' )"; $wsi_result = mysql_query($wsi_query) or die("Query failed ($wsi_query) - " . mysql_error()); $wsi_row = mysql_fetch_assoc($wsi_result); ?> what it should do is output both the min and the max values like this Code: [Select] <?php while ($mm_wsi_row = mysql_fetch_assoc($wsi_result)){ if ($mm_wsi_row['hrank'] == 1){ if ($mm_wsi_row['date'] == "0000-00-00"){$dayswam = "";}else{$dayswam = $mm_wsi_row['date'];} echo "<tr>"; echo "<td style='background-color:#F90'>Max Length:</td>"; echo "<td>" . number_format($mm_wsi_row['yards']) . "</td>"; echo "<td>" . $dayswam . "</td>"; echo "</tr>"; } if($mm_wsi_row['lrank'] == 1){ if ($mm_wsi_row['date'] == "0000-00-00"){$dayswam = "";}else{$dayswam = $mm_wsi_row['date'];} echo"<tr>"; echo "<td style='background-color:#F90'>Min Length:</td>"; echo "<td style='background-color:#FF9'>". number_format($mm_wsi_row['yards']) . "</td>"; echo "<td style='background-color:#FF9'>" . $dayswam . "</td>"; echo "</tr>"; } ?> the problem is that it doesn't work right all the time for some it just shows the min while others it just shows max I've tested the query in MySQL workbench so i know that that is working right but idk why it works right for some and doesn't work for others Hi, say I have a query like so: foreach($_REQUEST['r'] as $position => $row) { $row = implode("', '",$row); $result = mysql_query("Insert into player_stats (position,shirt_number,player_id,goals,cards,substituted,used_sub,injury,season,report_id) values('$position','$row','$currentSeason','$report_id')"); } How do I print the results of that query to my Browser for each time? Thanks If ($_GET['CODE'] == '1') { $ThreadID = mysql_escape_string($_GET['threadid']); $ForumID = mysql_result(mysql_query("SELECT forum_id FROM ".FORUM_THREADS." WHERE thread_id='{$ThreadID}'", $db), 0, 'forum_id'); $PostText = mysql_escape_string($_POST['replytext']); $IP = $_SERVER['REMOTE_ADDR']; $PostQuery = "INSERT INTO ".FORUM_POSTS." (`user_id`, `thread_id`, `post_text`, `forum_id`, `ip_address`, `timestamp`) VALUES ('{$memid}', '{$ThreadID}', '{$PostText}', '{$ForumID}', '{$IP}' , CURRENT_TIMESTAMP)"; $PostRes = mysql_query($PostQuery, $db); For some reason whenever this query goes through, it also adds a blank result using all the same information but without any $PostTest so essentially it does query: Code: [Select] INSERT INTO ".FORUM_POSTS." (`user_id`, `thread_id`, `post_text`, `forum_id`, `ip_address`, `timestamp`) VALUES ('{$memid}', '{$ThreadID}', '', '{$ForumID}', '{$IP}' , CURRENT_TIMESTAMP) This is the only query that does this part of the code and I can't see why it is adding 2 queries. FORUM_POSTS = constant containing table name. Below is my query which works fine: $query = " SELECT st.CourseId, c.CourseName, st.Year, st.StudentUsername, st.StudentForename, st.StudentSurname, s.ModuleId, m.ModuleName, m.Credits, s.SessionId, s.SessionWeight, gr.Mark, gr.Grade FROM Course c INNER JOIN Student st ON c.CourseId = st.CourseId JOIN Grade_Report gr ON st.StudentId = gr.StudentId JOIN Session s ON gr.SessionId = s.SessionId JOIN Module m ON s.ModuleId = m.ModuleId WHERE (st.StudentUsername = '".mysql_real_escape_string($studentid)."') "; Below is my results outputted by using php: Course: INFO101 - Bsc Information Communication Technology Year: 3 Student: Mayur Patel (u0867587) Module: CHI2550 - Modern Database Applications Session: AAB 72 (A) Course: INFO101 - Bsc Information Communication Technology Year: 3 Student: Mayur Patel (u0867587) Module: CHI2513 - Systems Strategy Session: AAD 61 (B) Course: INFO101 - Bsc Information Communication Technology Year: 3 Student: Mayur Patel (u0867587) Module: CHI2550 - Modern Database Applications Session: AAE 67 (B) How do I display it using php so that it only shows Course details and Student details only once, it will show each module in the course only once and shows each session being below each module it belongs to: The output from above should look like this in other words: Course: INFO101 - Bsc Information Communication Technology Year: 3 Student: Mayur Patel (u0867587) Module: CHI2550 - Modern Database Applications Session: AAB 72 (A) Session: AAE 67 (B) Module: CHI2513 - Systems Strategy Session: AAD 61 (B) PHP code to output the results: $output1 = ""; while ($row = mysql_fetch_array($result)) { //$result is the query $output1 .= " <p><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Year:</strong> {$row['Year']}<br/> <strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']}) </p>"; $output1 .= " <p><strong>Module:</strong> {$row['ModuleId']} - {$row['ModuleName']} <br/> <strong>Session:</strong> {$row['SessionId']} {$row['Mark']} ({$row['Grade']}) </p>"; } echo $output1; Thank You |