PHP - Using Variable From Class In Function

I have a method that is returning a funny variable, it should be returning what is below and when I echo the return from inside the method it is right.
Code: [Select]
Software/Section

but when I goto echo the from outside the class I get the following. It adds a back slash
Code: [Select]
Software//Section


this is the method code and it works fine when I echo the returnValue the value is right
Code: [Select]
    // Creates a  dymamic case statement for making a the choice
    // inside and array
        foreach (scandir($dir) as $folderItem) {
            if ($folderItem != "." AND $folderItem != "..") {
                if (is_dir($dir.$folderItem.DIRECTORY_SEPARATOR)) {

                    $folderItem = $folderItem  ; // this allows the the dir to be placed if statements below
                    $folderContents = $this->showPage( $dir.$folderItem ,$getPageGlobal  , $subdir);
                    $subdir = ""; // this resets so that ithe value does not get added to main links;
                }
                else {
                // put into if into array
                    if($getPageGlobal== $folderItem) {
                        $pageReturn = $dir . $folderItem;
                       
                    }
                }
            }
        }
        echo $pageReturn.'<br>';
        return $pageReturn;

This is the way I am echoing the class. This is when it decides to add the back slash
Code: [Select]
echo $dynamicMenu->getShowPage();

I am working on a site that was made a while ago and on a custom page I am making I am needing to call up variables and my brain is too fried to think up the solution for this.  The standing code is this:

class site{
var $name = 'Site';
var $data = 'on';
{

What I need to do is callup the variables, such as $name, as simple as possible.  How would I do this?

If i declare protected variable in a class how can i access those variable in other class inheriting that class?

Can anyone post example code?

Hi,
I have following code :
Code: [Select]
<?php
class CategoryWork {
    
    public $form = "";
    public $error = "";
    public $add_form = "<br /><br /><p><strong>Add New Category</strong></p><br /><form id=\"form1\" name=\"form1\" method=\"post\" action=\"category.php?action=add\">
  <table width=\"550\" height=\"170\" border=\"0\">
    <tr>
      <td width=\"153\">Name :</td>
      <td colspan=\"2\"><label for=\"cat_name\"></label>
      <input name=\"cat_name\" type=\"text\" id=\"cat_name\" size=\"50\" maxlength=\"50\" /></td>
    </tr>
    <tr>
      <td>Slug :</td>
      <td colspan=\"2\"><label for=\"cat_slug\"></label>
      <input name=\"cat_slug\" type=\"text\" id=\"cat_slug\" size=\"50\" maxlength=\"50\" /></td>
    </tr>
    <tr>
      <td>Description</td>
      <td colspan=\"2\"><label for=\"cat_desc\"></label>
      <textarea name=\"cat_desc\" id=\"cat_desc\" cols=\"48\" rows=\"10\"></textarea></td>
    </tr>
    <tr>
      <td>&nbsp;</td>
      <td width=\"97\"><input type=\"submit\" name=\"button\" id=\"button\" value=\"Submit\" /></td>
      <td width=\"286\"><input type=\"reset\" name=\"button2\" id=\"button2\" value=\"Reset\" /></td>
    </tr>
     <tr>
      <td>&nbsp;</td>
      <td colspan=\"2\">error</td>
    </tr>
  </table>
</form>";
}
?>

At the line of <td colspan=\"2\">error</td>
I want to insert $error, hence I made the line as
<td colspan=\"2\">".$error."</td> and also tried <td colspan=\"2\">".$this->error."</td>

After executing with this, php says syntax error at the line of public $add_form

I am going to declare an error at the $error

When I do <td colspan=\"2\">$error</td>
it says : Parse error:  syntax error, unexpected '"' at line of public $add_form

When I do  <td colspan=\"2\">".$error."</td>
it says : Parse error:  syntax error, unexpected '.', expecting ',' or ';' at the above line i.e. of <td>

I am damn confused, I googled but nothing found any helpful material.
Anybody please help me..

Thanks

Hello I want to be able to change the class depending on if a variable is 1 or 0.


<html>
<p class="note-general"> This is the general </p>
<p class="note-warning"> And this is the warning </p>
</html> 


I want the variable $adult (that can be 1 or 0) to set if the class should be a note-general or note-warning.
Thank you for support

I have this as my autoloader. All the classes are based off of Class O. I wanted to be able to do something like $dog = new Dog(); even if I hadn't yet created Dog.class.php and made it extend O. (I realize there are plenty of reasons this is a bad idea, this is a temporary part of the project, I am just trying to get a few things set up and thought it would work - now I'm probably going to spend more time trying to do this than it would have saved, but I'm curious. )

( ! ) Parse error: syntax error, unexpected T_VARIABLE, expecting T_STRING in C:\wamp\www\project\index.php on line 22
(line 22 is Class $class_name extends O{

Code: [Select]
<?php
function autoload($class_name) {
if(file_exists($class_name.'.class.php')){
require_once($class_name.'.class.php');
}else{
Class $class_name extends O{
}
}
}
?>
Is it possible to do what I'm trying to do?

I want to define a function instead of repeating query in all my php pages. I call a function by passing an $id value and from that function i have to get all the info related to that id, like name, description and uom.    I am trying to do this, but i dont know how to get these values seperately.   here is my function  

function items($item_id)
{
$details = array(); 
$result = mysql_query("select item_id, name, uom, description from items where item_id=".$item_id."") or die (mysql_error());
while($row = mysql_fetch_array($result))
{
$details[] = array((stripslashes($row['name'])), (stripslashes($row['uom'])), (stripslashes($row['description'])));
}
return $details;
}

and i call my function like this

$info = items($id);

Can somebody guide me in this    

Hello,

I am creating a class which contains one private function that deals with connecting to a SQL Server and executing the sql that is passed in to that function.
I have defined a class variable which is assigned the value of sqlsrv_query like so.

$this->QueryResult = sqlsrv_query($conn,$sql);
I have placed private $QueryResult at the top of my class.

The other public methods call this private function to assign the result set to the class variable, the private method returns and then the public methods loop through the results array like so.

while($row = sqlsrv_fetch_array($this->QueryResult))

.. but the while loop never gets entered.

If I declare everything in the same method then it works, however there are going to be several public methods that will use this private method and I don't want to duplicate all the database coding.

Hope someone can help

Currently, I'm trying to write a contact form, and perhaps I'm overcomplicating it, but I have a public variable called $EquationAnswer that stores the answer to the Captcha method (randomised maths question) and whenever the page reloads, it creates a new instance of the Contact class, which then erases the value that has been stored in that variable.   What I'm trying to achieve is keeping the value stored even after a new instantiation of the class. I remember from a class at University that static was a way to do this, but this was in C#.

<?php

class Contact
{
	public $EquationAnswer;

	public function CaptchaCreation()
	{
		$SignArray = array('+', '&times;', '-');

		$NumberOne = rand(1, 9);
		$NumberTwo = rand(1, 4);

		if($NumberOne < $NumberTwo)
			$SignIndex = rand(0, 1);
		else
			$SignIndex = rand(0, 2);

		$Sign = $SignArray[$SignIndex];

		$EquationString = $NumberOne." ".$Sign." ".$NumberTwo;

		switch($Sign)
		{
			case "+":
				$Answer = $NumberOne + $NumberTwo;
				break;
			case "-":
				$Answer = $NumberOne - $NumberTwo;
				break;
			case "&times;":
				$Answer = $NumberOne * $NumberTwo;
				break;
		}

		$this->EquationAnswer = $Answer;

		return $EquationString;
	}

	public function EchoContactForm()
	{
		$CaptchaMessage = $this->CaptchaCreation();

		echo "<form method='POST' action=''>\n\n";
		echo "\t\t\t\t\t<table>\n\n";
		echo "\t\t\t\t\t\t<tr><td>Name: </td><td><input type='text' name='name' /></td></tr>\n";
		echo "\t\t\t\t\t\t<tr><td>Email: </td><td><input type='text' name='email' /></td></tr>\n";
		echo "\t\t\t\t\t\t<tr><td>Subject: </td><td><input type='text' name='subject' /></td></tr>\n";
		echo "\t\t\t\t\t\t<tr><td>Message: </td><td><textarea rows=5 name='message'></textarea></td></tr>\n";
		echo "\t\t\t\t\t\t<tr><td>What is: ".$CaptchaMessage."?</td><td><input type='text' name='captcha' /></td><td></td></tr>\n";
		echo "\t\t\t\t\t\t<tr><td colspan=2 style='text-align: right'><input type='submit' name='submit' value='Send' /></td></tr>\n\n";
		echo "\t\t\t\t\t</table>\n\n";
		echo "\t\t\t\t</form>\n";
	}

	public function ContactFormValidation($Name, $Email, $Subject, $Message, $CaptchaInput, $CaptchaAnswer)
	{
		echo $CaptchaAnswer;

		$ErrorsArray = array();

		if(strlen($Name) == 0)
			array_push($ErrorsArray, "You must provide a name.");
		if(strlen($Email) == 0)
			array_push($ErrorsArray, "You must provide an email.");
		if(strlen($Message) == 0)
			array_push($ErrorsArray, "You must provide a message.");
		if(strlen($CaptchaInput) == 0)
			array_push($ErrorsArray, "You must provide an answer to the maths question.");
		if($CaptchaInput != $CaptchaAnswer)
			array_push($ErrorsArray, "Incorrect captcha answer.");

		if(count($ErrorsArray) > 0)
		{
			echo "There are ".count($ErrorsArray)." Errors: <br />";

			foreach($ErrorsArray as $E)
				echo $E."<br />";
		}
		else
		{
			return true;
		}
	}
}

?>

^ That's the Contact class, and the main function that I want to focus on is the last one, "ContactFormValidation()".   From the contact form page (which is within a template), I want it to send the EquationAnswer variable to that function so that it can compare what the user has input.

<?php

//Instantiate the contact class
include './inc/PHP/classes/ContactClass.php';
$ContactClass = new Contact;

if(!isset($_POST['submit']))
{
	$ContactClass->EchoContactForm();
}
else
{
	$NameInput = $_POST['name'];
	$EmailInput = $_POST['email'];
	$SubjectInput = $_POST['subject'];
	$MessageInput = $_POST['message'];
	$CaptchaInput = $_POST['captcha'];
	$CaptchaAnswer = $ContactClass->EquationAnswer;

        //Tried echoing out what is in the variable but it produces nothing because the contact class is a new instance.
	//echo $CaptchaAnswer;

	if($ContactClass->ContactFormValidation($NameInput, $EmailInput, $SubjectInput, $MessageInput, $CaptchaInput, $CaptchaAnswer) == true)
	{
		//Mail function
	}
}

?>

Any help would be appreciated.   Cheers.

Hi,
when i extend a class containing a private variable and then access the variable in the extended class it doesn't produce any error and works fine and when i access the variable using the object of the extended class it works even then, i think private variable should not be accessable in an extended class neither by object of that extended class
here is the code


<?php

class textbox{

var $body_text, $body_text1;

private $body_private="this is private value";

protected $body_protect="this is protected value";

function __construct($text_in, $text_out){

$this->body_text=$text_in;

$this->body_text1=$text_out;

}

function display(){

echo "$this->body_text<br>";

echo "<i>";

echo "$this->body_text1</i><br>";

echo "$this->body_private<br/>";

echo "$this->body_protect<br/>";

}

function test_new(){

echo "see if this private echo works";

}

}

$box=new textbox("any new value","any old value" );

$box->display();

$box->body_text="this is public thats why i can access it";

$box->body_text1="this is public thats why i can access it";

/*$box->body_private="this is private value changed";   //you will see we can't access the private and protected memebers from outside

$box->body_protect="this is protected value changed"; */

$box->display();

$box->test_new();



class textboxbold extends textbox{

function __construct($text_on, $text_off, $text_get, $text_go)

{$this->body_text=$text_on;

$this->body_text1=$text_off;

$this->body_protect=$text_get;

$this->body_private=$text_go;

}

function display(){

echo "<b>$this->body_text</b><br>";

echo "<b>$this->body_text1</b><br>";

echo "<b>$this->body_protect</b><br>";

echo "<i>$this->body_private</i><br>";

}

}

$boxnew=new textboxbold("new Bold text", "text in bold","protected member","private");

$boxnew->display();

$boxnew->body_private="this is simple text taken from outside";

$boxnew->display();

$boxnew->test_new();

?>


please recommend, is it working as it should be

hello all, i have ran into another issue i get this message when i go onto my homepage

Notice: Undefined variable: layout in

i have the following includes on the main index page:

Code: [Select]
<?php
// Include Main Core File.
include '_class/core.php';

// Include Config File
include 'config/config.php';
include 'config/db.php';

// Use Database
$obj->connect();

// Include library
include '_class/library.php';

// Include layout
include 'layout/index.php';
?>

on the config file i have the varible it is refering too:

Code: [Select]
<?php
$layout = $url . "layout/";
?>

the actual file i get the error on (library.php)
Code: [Select]
<?php

class library extends core {

function advert() {

/* 
* Name your images 1.jpg, 2.jpg etc. 
* 
* Add this line to your page where you want the images to 
* appear: <?php include "randomimage.php"; ?>
*/

// Change this to the total number of images in the folder
$total = "2";

// Change to the type of files to use eg. .jpg or .gif
$file_type = ".png";

// Change to the location of the folder containing the images
$image_folder = $layout . "layout/images/adverts";

// You do not need to edit below this line

$start = "1";

$random = mt_rand($start, $total);

$image_name = $random . $file_type;

echo "<img src=\"$image_folder/$image_name\" alt=\"$image_name\" />";
}
}

$obj = new library;


?>

is there a way to make it so it $layout works on any page or file as long as its in the includes?

thanks again.

I have the following simple class:

Code: [Select]
class Settings {
  public static $mysql_datetime_format = "%c/%e/%Y %l:%i %p " . date("[T]");
}

And referencing like:

Code: [Select]
echo Settings::$mysql_datetime_format;

But, I am getting the error: Parse error: syntax error, unexpected '.', expecting ',' or ';'.

Why is this invalid?

I have a class that I created, halfway down my page I call a function from the class which prints some code and also changes a variable inside the class.

It's a search class basically it prints out the search results and saves the total amount of results into the variable.

I want to display the amount of results above the results like so:-

echo $Search->results;

$Search->GetResults('foo');

The problem is that $Search->results will be equal to NULL until the variable is updated in the function GetResults.

Hope that makes sense, am I going about this wrong?

I have a function that get's a quick single item from a query:

function gimme($sql) { 
global $mysqli; 
global $mytable; 
global $sid; 
$query = "SELECT ".$sql." FROM ".$mytable." WHERE sid = ".$sid; $result = $mysqli->query($query); 
$value = $result->fetch_array(MYSQLI_NUM); 
$$sql = is_array($value) ? $value[0] : ""; 
return $$sql; // this is what I've tried so far 
$result->close(); 
}

It works great as:

echo(gimme("name"));

Then I realized that I could use that as a variable ('$name' in this case) elsewhere. However, I can't figure out how get that new, variable variable 'outside' of the function.  As such,

echo($name);

isn't working outside the function.  Is there a way to return a variable variable?  In other words, is there a way to make a function that creates a variable variable that will available outside of the function?

 

Thanks

 

In c++ class we can declare function inside a class and then we can describe that function at bottom.
Can i do this in PHP class?

In C++ class:

class Myclass{
    void doall();
}
void Myclass::doall(){
    .............
    .............
}