PHP - Array In Mysql Query

I have these two tables... schedule (gameid, homeid, awayid, weekno, seasonno) teams (teamid, location, nickname) This mysql query below gets me schedule info for ALL 32 teams in an array...

$sql = "SELECT
h.nickname AS home,
a.nickname AS away,
h.teamid AS homeid,
a.teamid AS awayid,
s.weekno
FROM schedule s
INNER JOIN teams h ON s.homeid = h.teamid
LEFT JOIN teams a ON s.awayid = a.teamid
WHERE s.seasonno =2014";
$schedule= mysqli_query($connection, $sql);
if (!$schedule) {
die("Database query failed: " . mysqli_error($connection));
} else { 
// Placeholder for data
$data = array();
while($row = mysqli_fetch_assoc($schedule)) {
if ($row['away'] == "") {$row['away']="BYE";}
$data[$row['homeid']][$row['weekno']] = $row['away'];
$data[$row['awayid']][$row['weekno']] = '@ '.$row['home'];
}
}

However, I only want to get info for one specific team, which is stored in the $teamid variable. This should be very easy, right? I have tried multiple things, including this one below (where I added an AND statement of "AND (h.teamid=$teamid OR a.teamid=$teamid)"), but this one still outputs too much...

$sql = "SELECT
h.nickname AS home,
a.nickname AS away,
h.teamid AS homeid,
a.teamid AS awayid,
s.weekno
FROM schedule s
INNER JOIN teams h ON s.homeid = h.teamid
LEFT JOIN teams a ON s.awayid = a.teamid
WHERE s.seasonno =2014
AND (h.teamid=$teamid OR a.teamid=$teamid)";
$schedule= mysqli_query($connection, $sql);
if (!$schedule) {
die("Database query failed: " . mysqli_error($connection));
} else { 
// Placeholder for data
$data = array();
while($row = mysqli_fetch_assoc($schedule)) {
if ($row['away'] == "") {$row['away']="BYE";}
$data[$row['homeid']][$row['weekno']] = $row['away'];
$data[$row['awayid']][$row['weekno']] = '@ '.$row['home'];
}
}

Below is the array that the above outputs. In a nutshell, all I want is that 1st array ([1]) which has, in this example, the Eagles full schedule. It's not giving me too much else and I guess I could live with it and just ignore the other stuff, but I'd rather be as efficient as possible and only get what I need...

Array
(
[1] => Array
(
[1] => Jaguars
[2] => @ Colts
[3] => Redskins
[4] => @ 49ers
[5] => Rams
[6] => Giants
[7] => BYE
[8] => @ Cardinals
[9] => @ Texans
[10] => Panthers
[11] => @ Packers
[12] => Titans
[13] => @ Cowboys
[14] => Seahawks
[15] => Cowboys
[16] => @ Redskins
[17] => @ Giants
)

[27] => Array
(
[1] => @ Eagles
)

[28] => Array
(
[2] => Eagles
)

[4] => Array
(
[3] => @ Eagles
[16] => Eagles
)

[14] => Array
(
[4] => Eagles
)

[15] => Array
(
[5] => @ Eagles
)

[3] => Array
(
[6] => @ Eagles
[17] => Eagles
)

[] => Array
(
[7] => @ Eagles
)

[16] => Array
(
[8] => Eagles
)

[25] => Array
(
[9] => Eagles
)

[11] => Array
(
[10] => @ Eagles
)

[7] => Array
(
[11] => Eagles
)

[26] => Array
(
[12] => @ Eagles
)

[2] => Array
(
[13] => Eagles
[15] => @ Eagles
)

[13] => Array
(
[14] => @ Eagles
)

)

I have a MySQL table with a list of albums and there is a field called "views" with the number of views each album has received. I'm looking to generate an array of all the albums in the table and sort the array by the number of views (descending). I have a list of functions defined in a ContentController.php file. I created a new function called build_albumlist, which I've pasted below. The function "get_ip_log" already exists and works, and I used it as a template to create the "build_albumlist" function:





   public function build_albumlist(){
      return $this->select_raw("SELECT * FROM albums WHERE deleted = '0' ORDER BY views DESC",array(),'all');
   }

public function get_ip_log(){
      return $this->select_raw("SELECT * FROM sessions ORDER BY ID DESC",array(),'all');
   }


When I use the function, I get this warning:


Warning: mysql_real_escape_string() expects parameter 1 to be string, array given inC:\xampp\htdocs\Controllers\DBController.php on line 10

[font=cabin, 'trebuchet ms', helvetica, arial, sans-serif]The "select_raw" function that I used in "build_albumlist" is defined in the DBController.php file, and is defined as below:[/font]
private function clean_array($params){
      $final=array();
      foreach($params as $param){
         $final[]=mysql_real_escape_string($param);
      }
      return $final;
   }
   public function select_raw($query,$params,$type=''){
      $query=str_replace("?","'%s'",$query);
      $final_query= call_user_func_array('sprintf', array_merge((array)$query, $this->clean_array($params)));
      if($type==''){
         $result=mysql_query($final_query) or die(mysql_error());
         return mysql_fetch_assoc($result);
      }
      elseif($type=='all'){
         $result=mysql_query($final_query) or die(mysql_error());
         $final=array();
         while($row=mysql_fetch_assoc($result)){
            $final[]=$row;
         }
         return $final;
      }


Does anyone know why the "build_albumlist" function is generating this warning, while the "get_ip_log" is not? Any help would be great, as I am obviously pretty new to this.

Hi all,

I have the following MySQL insert query:
Code: [Select]
$insert= mysql_query   ("INSERT INTO tablename (column1,`".$EXPfields."`) VALUES ('$something','".$EXPvalues."')");
where $EXPfields is an array of table-field-names and $EXPvalues is an array of table-field-values.

Now I want to write an equivalent query, but using UPDATE instead of INSERT INTO, but I don't want to write out all the field names/values separately, but again want to use $EXPfields and $EXPvalues.

So something like this:
Code: [Select]
$update = mysql_query ("UPDATE tablename
                     SET (column1,`".$EXPfields."`) = ('$something','".$EXPvalues."')
                     WHERE ....
                  ");

Is this possible? If so, what is the proper syntax? Thanks!

Hi All,

First time posting here. I've googled the problem, but can't seem to find a response that's the same.

All I want to do is have a list of id numbers and for each id number in the array, submit a MySQL query to retrieve information relating to the id number.

When I execute the code below however, I end up with only the last item in the array being printed in the echo statement.

Any clues?

Thanks,

Code: [Select]
// get array of ids
$ids = getIDs($ids);

// loop through input list
foreach ($ids as &$id) {
getVarDetails($id);
}

function getVarDetails($local)
{
$con = mysql_connect('localhost:3306', 'root', '********');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

// set database as Ensembl
mysql_select_db("Ensembl", $con);

$result = mysql_query("SELECT * FROM variations WHERE name = '$local' LIMIT 1");
$row = mysql_fetch_array($result)

while($row = mysql_fetch_array($result))
{
echo $row['name'] . " " . $row['id'];
echo "<br />";
}

// close connection
mysql_close($con);
}

Here is my code:
// Start MySQL Query for Records
$query = "SELECT codes_update_no_join_1b" .
"SET orig_code_1 = new_code_1,
       orig_code_2 = new_code_2" .
"WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)";
$results = mysql_query($query) or die(mysql_error());
// End MySQL Query for Records


This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this???

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1

If you also have any feedback on my code, please do tell me. I wish to improve my coding base.

Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference.

Code:

  Code: [Select]
mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
Full code:

Code: [Select]
<?php
include_once("includes/config.php");
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title><? $title; ?></title>
<meta http-equiv="Content-Language" content="English" />
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link rel="stylesheet" type="text/css" href="style.css" media="screen" />
</head>
<body>
 
<div id="wrap">
 
<div id="header">
<h1><? $title; ?></h1>
<h2><? $description; ?></h2>
</div>
 
<? include_once("includes/navigation.php"); ?>
 
<div id="content">
<div id="right">
<h2>Create</h2>
<div id="artlicles">
<?php
 
if(!$_SESSION['user'])
{
 
        $username = mysql_real_escape_string($_POST['username']);
        $password = mysql_real_escape_string($_POST['password']);
        $name = mysql_real_escape_string($_POST['name']);
        $server_type = mysql_real_escape_string($_POST['type']);
        $description = mysql_real_escape_string($_POST['description']);
 
        if(!$username || !$password || !$server_type || !$description || !$name)
        {

        echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>";
        echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'>
       
        <option value='Any'>Any</option>
        <option value='PvP'>PvP</option>
        <option value='Creative'>Creative</option>
        <option value='Survival'>Survival</option>
        <option value='Roleplay'>RolePlay</option>
       
        </select></td></tr>
       
        <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>";
        echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>";
        }
        elseif(strlen($password) < 8)
        {
        echo "Password needs to be higher than 8 characters!";
        }
        elseif(strlen($username) > 13)
        {
                echo "Username can't be greater than 13 characters!";
        }
        else
        {
                $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1");
               
                if(mysql_num_rows($check1) < 0)
                {
                        echo "Sorry, there is already an account with this username and/or server name!";
                }
                else
                {
                        $ip = $_SERVER['REMOTE_ADDR'];

                        mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)");
                        echo "Server has been succesfully created!";
                }
        }
       
}
else
{
        echo "You are currently logged in!";
}
 
?>
</div>
</div>
 
<div style="clear: both;"> </div>
</div>
 
<div id="footer">
<a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop
</div>
</div>
 
</body>
</html>

I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate.

What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop.

It doesn't matter if I get to the next page using a header redirect or a form submit.  I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. 

I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. 

Any ideas?

How can i save array from inputs, witch is $igraci and it have 5 values, to mysql base, i tryed but in mysql it shows Array.
This is form:
        <form action="dodaj_klan.php" method="post" >
            <p>
            <label>Naziv klana:</label>
            <input name="naziv" type="text" size="20%" />
            <label>Web Sajt:</label>
            <input name="website" type="text" size="20%" />
            <label>E-Mail:</label>
            <input name="email" type="text" size="20%" />
            <br /><br />
            <label>Igraci klana(5):</label>
            <input name="lider" type="radio" value="1" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="2" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="3" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="4" />
            <input name="igraci[]" type="text" size="20%" /><br />
            <input name="lider" type="radio" value="5" />
            <input name="igraci[]" type="text" size="20%" />
            <label><i>(obelezi lidera klana)</i></label>
            <br /><br />
            <input class="button" type="submit" name="submit" value="Dodaj" />&nbsp;&nbsp;
            </p>
        </form>
Now i wonna save this igraci[] array in mysql, i tried like this but it doesn't work:
$igraci = $_POST['igraci'];
$query = "INSERT INTO klanovi (naziv, website, email, igraci) VALUES ('{$naziv}', '{$website}', '{$email}', '{$igraci}')";
$result = mysql_query($query, $connection);

How can i do this?
Thanks..

Hello everyone,

Sorry if this has been answered but if it has I can't find it anywhere. So, from the begining then.  Lets say I had a member table and in it I wanted to store what their top 3 interests are.  Their$ row has all the usual things to identify them userID and password etc.. and I had a further 3 columns which were labled top3_1 top3_2 & top3_3 to put each of their interests in from a post form.

If instead I wanted to store this data as a PHP Array instead (using 1 column instead of 3) is there a way to store it as readable data when you open the PHPmyadmin?

At the moment all it says is array and when I call it back to the browser (say on a page where they could review and update their interests) it displays 'a' as top3_01 'r' as top3_02 and 'r' as top3_03 (in each putting what would be 'array' as it appears in the table if there were 5 results. Does anyone know what I mean?

For example -

If we had a form which collected the top 3 interests to put in a table called users,

Code: [Select]
<form action="back_to_same_page_for_processing.php" method="post" enctype="multipart/form-data">
   
    <input name="top3_01" type="text" value="enter interest number 1 here" />
    <input name="top3_02" type="text" value="enter interest number 2 here" />
    <input name="top3_03" type="text" value="enter interest number 3 here" />
    <input type="submit" name="update_button" value=" Save and Update! " />

   
    </form> // If my quick code example for this form is not correct dont worry its not the point im getting at :)
And they put 'bowling' in top3_01, 'running' in top3_02 and 'diving' in top3_03 and we catch that on the same page with some PHP at the top -->

Code: [Select]
        if (isset($_POST)['update_button']) {
   
    $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars
    $top3_02 = $_POST['top3_02']; // i.e, 'running'
    $top3_03 = $_POST['top3_03']; // i.e, 'diving'

With me so far? If I had a table which had 3 columns (1 for each interest) I could put something like -

  Code: [Select]
   include('connect_msql.php');
   
    mysql_query("Select * FROM users WHERE id='$id' AND blah blah blah");
   
    mysql_query("UPDATE users SET top3_01='$top3_01', top3_02='$top3_02', top3_03='$top3_03' WHERE id='$id'");


And hopefully if ive got it right, it will put them each in their own little column. Easy enough huh? But heres the thing, I want to put all these into an array to be stored in the 1 column (say called 'top3') and whats more have them clearly readable in PHPmyadmin and editable from there yet still be able to be called back an rendered on page when requested.

Continuing the example then, assuming ive changed the table for the 'top3' column instead of individual colums,  I could put something like this -


Code: [Select]
            if (isset($_POST)['update_button']) {
       
        $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars
        $top3_02 = $_POST['top3_02']; // i.e, 'running'
        $top3_03 = $_POST['top3_03']; // i.e, 'diving'
   
    $top3_array = array($top3_01,$top3_02,$top3_03);
   
    include('connect_msql.php');
   
    mysql_query("UPDATE members SET top3='$top3_array' WHERE id='$id' AND blah blah blah");
But it will appear in the column as 'Array' and when its called for using a query it will render the literal string. a r r in each field instead.  Now I know you can use the 'serialize()' & 'unserialize()' funtcions but it makes the entry in the database practically unreadable. Is there a way to make it readable and editable without having to create a content management system?

If so please let me know and I'll be your friend forever, lol, ok maybe not but I'd really appreciate the help anyways.  The other thing is, If you can do this or something like it, how am I to add entries to that array to go back into the data base?

I hope ive explained myself enough here, but if not say so and I'll have another go.  Thanks very much people,  L-PLate (P.s if I sort this out on my own ill post it all here)

I'm trying to delete items from a table by selecting them via checkboxes. I managed to post all the ids of the checkboxes I filled in the url like this,

check_box=154,153,152    etc...

and turned that into an array

Array
(
    [0] => 154
    [1] => 153
    [2] => 152
)
Array

using

$delete_selected = $connection->real_escape_string($_POST['check_box']);
$check_box_array = explode(",", $delete_selected);

Now I can't figure out how to put that into

$sql = "DELETE FROM categories WHERE cat_id = '$delete_selected'";

it only deletes one. Any ideas?

Hi there i need to make an array with the result from a query (numbers 1-4) I need to calculate how many occurances of each 1-4 number is in the table. Im new to this and havent much experience with arrays but ive managed to create an array and echo the results:

2 Class
3 Class
1 Class
3 Class
3 Class
2 Class
2 Class
2 Class

So i need to somehow Add the occurance of them and echo the results e.g. 4 Class 2, 1 Class 1, 3 Class 3.

If someone could please point me in the right direct that would be great.

Code: [Select]
$colname_Recordset1 = "-1";
if (isset($_SESSION['MM_Username'])) {
  $colname_Recordset1 = (get_magic_quotes_gpc()) ? $_SESSION['MM_Username'] : addslashes($_SESSION['MM_Username']);
}

mysql_select_db($database_swb, $swb);
$query = sprintf("SELECT Class FROM ships WHERE PlayerName = %s", GetSQLValueString($colname_Recordset1, "text"));
$result = mysql_query($query, $swb) or die(mysql_error());

while($row = mysql_fetch_array($result)){
echo $row['Class']. " Class ";
echo "<br />";
}
mysql_free_result($result);?>;

Thank You

I'm using a web service call, my response comes back as an array:
stdClass Object ( [contractVehicle] => Array ( [0] => ITSchedule70 [1] => ITCommodityProgram ) )
I then need to hand this response off to anther developer who needs to know that "ITSchedule70" is the selected Contract Vehicle (actually there could be more than one, this only returns one for now), so he can insert it into a SQL query against a MySQL database (to match "Products" with the right "Contract Vehicle".   So basically how do I do that? How to wrap it up and send it off, and how to insert a query?

Hi

I am trying to store the results of a mysql query into a php array. Here is the code i am using

$test = implode(",",$_GET['checkbox']);
        $query = mysql_query("SELECT categoryTitle FROM `category` where categoryid in ($test)");
        $test2 = array();
        while ($result = mysql_fetch_assoc($query))
        {
            $test2[] = $result;
       
        }   
        $test3 = implode(", ",$test2);       
        print_r($test3);

Everything works fine until implode the array. When i try to print after the implode the result is "Array, Array". if i remove the implode it prints "Array ( => Array ( [categoryTitle] => Escalators & Lifts ) [1] => Array ( [categoryTitle] => Human Resource/Payroll/ Training ) )"
The values here are ture. Im thinking that its storing an array inside another array so cannot implode. Is there something i can do to solve this

I am trying to compare a teams average attendance compared to the average across all teams. The query that show the average by team (column 'atte') is
Code: [Select]
$att_table = mysql_query("
SELECT
t.team_name as Tm
, ROUND(AVG(g.attendance))atte
, SUM(g.attendance) tot
, MAX(g.attendance) max
, MIN(g.attendance) min
from teams t
left join all_games g
on t.team_id = g.home_team
WHERE comp = '1'
AND home_goals IS NOT NULL
AND date BETWEEN '2010-07-01' AND '2011-06-31' 
GROUP BY t.team_id
ORDER BY atte DESC
");A simple query to show the total average is
Code: [Select]
$lgeav = mysql_query("
(AVG(g.attendance))atte2
from all_games g
WHERE comp = '1'
AND home_goals IS NOT NULL
AND date BETWEEN '2010-07-01' AND '2011-06-31' 
");I am hoping to put the second query into an array and use the two to show the teams whose own average attendance is higher than the total average attendance in bold, with something along the lines of
while ($row_att_table = mysql_fetch_assoc($att_table)){
if ($row_att_table['atte'] > $lgeav['atte2'])   

 echo '<tr  style="font-weight:bold">';

 else

 echo '<tr>';

I know that this can be done with views but in an attempt to broaden my knowledge (and also in case I ever have to do something similar on MySQL4) I wondered if there was a simple way to do this through PHP?

Thanks in advance
Steve