|
PHP - Please Help Me With Little Math Usig Php/mysql Read This Post
Once upon a time needed help on March 12, 2008 this community helped me, I am still a learner tried to help back but all the problems posted here beyond my skills to solve them so I kept quiet. and Now I need help once again hope I will get it done.
Its PHPPOS developed in Codeigniter This code below is from application\controllers\inventory_summary.php file Code: [Select] <?php require_once("report.php"); class Inventory_summary extends Report { function __construct() { parent::__construct(); } public function getDataColumns() { return array($this->lang->line('reports_item_name'), $this->lang->line('reports_item_number'), $this->lang->line('reports_description'), $this->lang->line('reports_count'), $this->lang->line('reports_reorder_level')); } public function getData(array $inputs) { $this->db->select('name, item_number, quantity, reorder_level, description'); $this->db->from('items'); $this->db->where('deleted', 0); $this->db->order_by('name'); return $this->db->get()->result_array(); } public function getSummaryData(array $inputs) { return array(); } } ?> And this partial code below is from application\controllers\report.php file Code: [Select] function inventory_summary($export_excel=0) { $this->load->model('reports/Inventory_summary'); $model = $this->Inventory_summary; $tabular_data = array(); $report_data = $model->getData(array()); foreach($report_data as $row) { $tabular_data[] = array($row['name'], $row['item_number'], $row['description'], $row['quantity'], $row['reorder_level']); } $data = array( "title" => $this->lang->line('reports_inventory_summary_report'), "subtitle" => '', "headers" => $model->getDataColumns(), "data" => $tabular_data, "summary_data" => $model->getSummaryData(array()), "export_excel" => $export_excel ); $this->load->view("reports/tabular",$data); } } ?> Together they get the job done as follow: Item Name Item Number Description Count Reorder Level (Count is quantity in stock) Item 1 0002 xyz 5 3 Item 2 0s00 xyz 5 3 Item 3 0005 xyz 5 3 Item 4 0006 xyz 5 3 The output I want need to be like this: Item Name Item Number Description cost price Count Reorder Level Item 1 0002 xyz 250 5 3 Item 2 0s00 xyz 120 5 3 Item 3 0005 xyz 300 5 3 Item 4 0006 xyz 500 5 3 Total Stock Value 5850 Total Count 20 <-- this doesn't require any formation just needs to be at bottom of all the queries like shown here. This is what I want mainly >>>>>>>>>> Total Stock Value (cost price * count foreach and then sum of all results ) and sum of all count cost price table and column is different than one used above in the code which is: databse table is ' receivings_items ' Column is 'item_cost_price' example php code to fetch is : Code: [Select] $sql = "SELECT `item_cost_price` FROM `receivings_items`"; config.php contains all the connection variables to MySQL Please Help me Similar TutorialsTrying to read through this query string to get a list of subjects (sub) and products (pro) sub2=pro73&sub2=pro76&sub2=pro79&sub2=pro90&sub2=pro92&sub3=pro73&sub3=pro74&sub3=pro87&sub3=pro90 so i need 2 -73, 2-76, 2-79, 3-73, 3-74 etc. What am i missing in this code.
foreach($_POST as $key => $val) {
$sub = substr($key, 3);
$pro = substr($val, 3);
// $links = "SELECT * FROM table WHERE sub='".$sub."' AND pro='".$pro."';";
}
Hi, I am fairly new to PHP and I have built a page which accepts values from dynamically added rows so there is a combination of HTML,Javascript and PHP in the process. I am caught up with a problem HTML section In my form I have a table with a column as below and a dynamic "Add Row" which would increment the row in javascript and assign a new value to the input name as txtRow2,txtRow3,txtRow4 and so on based on the number of iteration " <tr><td><input type="text" name="txtRow1" id="txtRow1" size="40" /></td></tr> <input type="button" value="Add Row" onclick="addRow();" />" Javascript section The below code generates the new row in js var cellRight2 = row.insertCell(1); var e1 = document.createElement('input'); e1.type = 'text'; e1.name = 'txtRow1' + iteration; e1.id = 'txtRow1' + iteration; e1.size = 20; cellRight1.appendChild(e1); I hope you have understood what I have done till above.. Now comes the problematic part PHP section( I love PHP ) I have to insert the column values into mysql and i will do this using a for loop within which I will have my insert statement INSERT INTO test values($txtRow) Lets say I added 4 rows dynamically with values held in $txtRow1,$txtRow2,$txtRow3,$txtRow4(See the java script section) how would I use these values in my PHP insert statement as I don't want to write 4 different insert scripts and the following "$txtRow.i" won't work for ($i = 1; $i <= 10; $i++) { INSERT INTO test values($txtRow.i) } Any suggestions are welcome...If you think you still need to see the whole code i can post it too. Jay hi there, seems like I'm getting a fairly common beginners php error but as I'm using a number of differant files and as I'm not entirley clear on a couple of things I thought I'd tap into the immense php talent on this site here's the error - Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\Epointment\index.php:4) in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\Epointment\ot\views\header.php on line 38 I have an index page that allows a user to log on, the processing go's away and checks the usual stuff then reloads the login page with the user detail or just reloads the login page with the user/password fields blank. This seemed to be working ok until I put my files onto another web server that had output_buffering turned off. here's part of the login page Code: [Select] <html> <head><title></title></head> <body> <?php ini_set("display_errors", "1"); error_reporting(-1); $dir = dirname(__FILE__); require_once "$dir/ot/ot.php"; ot::include_view('header', array('account' => null)) ?> // various stuff <p>Please login below</p> <?php ot::include_view('login_form')?> the ot.php file doesn't have any echo's or print_r's etc if that helps?? here's the header.php file.. <?php Code: [Select] if (ot::get('do_logout', 0) == 1) { ot::destroy_session(); header("Location: http://{$_SERVER['SERVER_NAME']}{$_SERVER['PHP_SELF']}"); exit; } elseif (self::post('do_reset_password')) { ot::do_reset_password($err); echo "$err"; } $adb = ot::db('account'); $account = null; $error = ""; $id = ot::account_id(); if ($id) { $account = ot::account_from('id', $id); $res = ot::do_change_password($account, $err); if ($res) { echo "<p>Password Changed Successfully</p>"; $account = $res; } else if ($err) { echo "<p>Error: $err</p>"; } $res = ot::do_change_email($account, $err); if ($res) { echo "<p>Email Changed Successfully</p>"; $account = $res; } else if ($err) { echo "<p>Error: $res</p>"; } } else { $account = ot::do_login(); if ($account) { header("Location: http://{$_SERVER['SERVER_NAME']}{$_SERVER['PHP_SELF']}"); exit; } } ?> here's the ot::do_login function Code: [Select] public static function do_login(&$err="") { $adb = ot::db('account'); $e = self::post('email'); $p = self::post('pwd', '', false); if (self::post('do_login') && $e && $p) { $ao = self::account_from('email', $e); if ($ao) { if (self::validate_login($e, $p, $ao)) { //echo "\n"."hit2"; $_SESSION['id'] = $ao->id; return $ao; } } $err = "Invalid email or password"; return false; } } and here's the login_form.php, which is called from ot::do_login from header.php ... Code: [Select] <form action='<?php echo $_SERVER['REQUEST_URI']?>' method='post' > <p>Email:<br/><input type='text' name='email' /></p> <p>Password:<br/><input type='password' name='pwd' /></p> <p><input type='submit' name='do_login' value='Login' /> <input type='submit' name='do_reset_password' value='Reset Password' /></p> </form> Any pointers or useful things I've not posted? is this bit of code from above ok? as in I'm doing some php stuff before the header() function gets used? Code: [Select] <html> <head><title></title></head> <body> <?php ini_set("display_errors", "1"); error_reporting(-1); $dir = dirname(__FILE__); require_once "$dir/ot/ot.php"; ot::include_view('header', array('account' => null)) How do forums check if you've read a post or not? Is it through cookies? I'm trying to send some POST data to a page and then get the contents of it. The page is not on my server, so I can't use Sessions or GET. Google hasn't provided me with a definite answer. How would I do this? Hello together, I'm still relatively new with PHP and I'm encountering an error with the error code (Warning: Undefined array key "title" in I:\xampp\htdocs\test\Datenspeichern.php on line 13 to 17.). Normally I wanted that when I enter the data in the fields from the CD_Website page, that it is inserted in my created database and displayed in the table on the page. Does anyone know where my error is? Thanks a lot
main Code=
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Unbenanntes Dokument</title>
<style type="text/css">
table {
border-collaps: collapse;
width: 100%;
font-family: serif;
font-size: 35px;
text-align: center;
}
td {
font-size: 25px;
text-align: center;
font-family: serif;
}
</style>
</head>
<body>
<table>
<tr>
<th>CD-Titel</th>
<th>Artist</th>
<th>Songtitel</th>
<th>Musiklänge</th>
<th>Lied Nummer</th>
</tr>
<?php
$host = "localhost";
$user = "root";
$password = "";
$db_name = "cdaufgabe";
$con = mysqli_connect($host, $user, $password, $db_name);
if(mysqli_connect_error()) {
die("Verbindungsabbruch mit der Datenbank: ". mysqli_connect_error());
};
$check = "SELECT * FROM `cd-titel`";
$result = mysqli_query($con, $check);
if ($result > null) {
while ($row = $result->fetch_assoc()){
echo "<tr><td>" . $row['CD-Titel'] . "</td> <td>" . $row['Artist'] . "</td> <td>" . $row['Songtitel'] . "</td> <td>" . $row['Musiklänge'] . "</td> <td>" . $row['Lied-Nummer'] . "</td></tr>";
};
};
/*if (isset($_POST['submitted'])) {
$titel = $_POST['titel'];
$artist = $_POST['artist'];
$songtitel = $_POST['songtitel'];
$musicle = $_POST['musicle'];
$liednr = $_POST['liednr'];
$data_add = "INSERT INTO cd-titel (CD-Titel, Artist, Songtitel, Musiklänge, Lied-Nummer) VALUES ('$titel', '$artist', '$songtitel', '$musicle', '$liednr')";
if (!mysqli_query($db_name, $data_add)) {
die('Fehler beim einfügen von Daten');
}
}
*/
// $data_add = "INSERT INTO `cd-titel` (`CD-Titel`, `Artist`, `Songtitel`, `Musiklänge`, `Lied-Nummer`) VALUES ('$titel', '$artist', '$songtitel', '$musicle', '$liednr')";
// mysqli_query($con, $data_add);
/*mysqli_query($con, $data_add);*/
?>
<form methode="post" action="Datenspeichern.php">
<input type="text" name="titel" placeholder="CD-Titel"/>
<input type="text" name="artist" placeholder="Artist"/>
<input type="text" name="songtitel" placeholder="Songtitel"/>
<input type="text" name="musicle" placeholder="Musiklänge"/>
<input type="text" name="liednr" placeholder="Lied-Nummer"/>
<input type="submit" name="submitted" value="speichern"/>
</form>
</br></br></br>
</table>
</body>
</html>
second code(Datenspeichern.php)=
<?php
$con = mysqli_connect('localhost', 'root', '');
if (!$con) {
echo'Nicht verfügbar';
}
if (!mysqli_select_db($con, 'cdaufgabe')){
echo 'Datenbank nicht ausgewählt';
};
$titel = $_POST['titel'];
$artist = $_POST['artist'];
$songtitel = $_POST['songtitel'];
$musicle = $_POST['musicle'];
$liednr = $_POST['liednr'];
$data_add = "INSERT INTO cd-titel (CD-Titel, Artist, Songtitel, Musiklänge, Lied-Nummer) VALUES ('$titel', '$artist', '$songtitel', '$musicle', '$liednr')";
if (!mysqli_query($con, $data_add)){
echo 'Fehler';
}
else {
echo'Eingefügt';
};
header("url=CD_Webseite.php");
?>
Does anyone knows the mistake i keep doing? Hi On my xampp server's database I get the warning that my database is read-only when I try to insert something into a table. I think I may know what cause this, because I created an export/import app that exports/import important data to the database... How can I remove the read-only from the database, because I am scared that the same thing might happen to my server's database? And is there a mysql query that test if the database is read-only? Thanks in advance Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03. Here is the code: Code: [Select] <?php $sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $title = $row['title']; $date_posted = $row['date_posted']; $summary = $row['summary']; echo "<h3>$title</h3>\n"; echo "<p>$date_posted</p>\n"; echo "<p>$summary</p>\n"; echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n"; } ?> I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work. I am working on a simple web app in which I want to store about 20 variables in a MYSQL table so when I hand off the project the variables can be easily edited by the end user. Is it easy to store variables in a MYSQL table then query those and make them PHP variables? Really I just need to read a MYSQL table and pull two columns; AppOption and AppOptionValue then create PHP variables for each of the results making the AppOption the variable name and the AppOptionValue the value of said varible. Any Ideas? Thanks! Sean MOD: Thanks for moving to the correct forum - much appreciated! OK, I've taken a look around and cannot find a complete tutorial on how to do this. I have created a database with a table and the following fields; id, day, month, year, event, type What I am trying to do is read the data held in the table by referencing the type field (unique data), have it populate data firleds which are user editable and then once all changes are made have it update into the table. I can't imagine that this is that hard at all, but I cannot for the life of me figure it out! Anybody got a tutorial or some code which will do this? I am having trouble trying to save my image file names to mysql after reading a dir. I am trying to use the file below.
Any help would be appreciated. I was originallly getting the files to list but they we not showing up in the database.
Now the page shows up blank.
<?php
require("config_0.php");
// Connect to server and select database.
mysql_connect($dbhost, $dbuser, $dbpass)or die("cannot connect");
mysql_select_db("test")or die("cannot select DB");
$files = glob("images/*.jpg");
for ($i=1; $i<count($files); $i++)
{
$num = $files[$i];
$sql="INSERT INTO images (url) VALUES ('$num')";
if (!mysql_query($sql))
{
die('Error: ' . mysql_error());
}
echo '<img src="'.$num.'" alt="random image">'." ";
}
?>
I have a MySQL database with each record of a person who has registered for an event, I am displaying the information on a web page for a user, but he wants to be able to print out all the records in alphabetical order by last name, first name later on so he will have a hard copy of each person who has registered at the table when they arrive. How can I write each record to a Txt file that he can print out later that will be formated with the record contents along with each fields definition (Ex. Last Name - Smith, First Name - John, etc)? Hi again, i'm wondering how can i make Sort (for example a-z) an column in php reading mysql informations. Here's the script: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title></title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" href="table.css" type="text/css"> </head> <body style="margin: 0 0 0 0;"> <? include("passwd.php"); @$start = $_GET["start"]; if($start =='') $start =0; include("lib.php"); $link = mysql_connect($host,$username,$password); if (!$link) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db($db, $link); if (!$db_selected) { die ("Can't use $db : " . mysql_error()); } //total number of records in the table $res = mysql_query("SELECT * from `$table`"); @$rows = mysql_num_rows ($res); $result = mysql_query("SELECT * from `$table` limit $start,10"); if (!$result) { die('Invalid query: ' . mysql_error()); } echo "<p align=center class = 'menu'> Ocitana tabela: $table </p>"; $cols = mysql_num_fields($result); $records = mysql_num_rows ($result); echo "<table align='center' width='1200' >"; echo "<tr bgcolor='BBCCDD' class='menu'>"; for ($i = 0; $i < $cols;$i++) { echo "<td align='center'>".mysql_field_name($result,$i)."</td>"; } echo "</tr>"; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "<tr bgcolor='F6F6F6' class='normal'>"; foreach ($row as $value) { echo "<td align='center'>".$value ."</td>"; } echo "</tr>"; } $end = $start + $records; echo "<tr align = 'center' bgcolor = 'BBCCDD' class='menu'><td colspan=$cols> Prijema $start do $end od $rows </td></tr>"; echo "<tr align = 'center' class='mylink'><td colspan=$cols> "; if($start != 0) { $prev = $start - 10; echo "<a href='tabela.php?start=$prev'> Prethodna </a> "; } if($start<$rows-10) { $next = $start + 10; echo "<a href = 'tabela.php?start=$next'>Sledeca</a> "; } echo "</td></tr>"; echo "</table>"; ?> </body> </html> Hello,
I try to get website speed of some website, but i can read only ''domain.com'' i can't read website files like css , js ... why ? i use proxies for this job.
here is the php code:
$options = array(
'useragent' => "Firefox (+http://www.firefox.org)", // who am i
'connecttimeout' => 120, // timeout on connect
'timeout' => 120, // timeout on response
'redirect' => 10, // stop after 10 redirects
'referer' => "http://www.google.com",
'proxyhost' =>'85.25.8.14:80'
);
$response = http_get("http://solve-ict.com/wp-content/themes/ict%20theme/js/jquery-1.7.1.min.js", $options , $info);
but it works fine with http://domain.com/ , but with files css or js it gives 404, using some free proxy servers available
?
Thanks.
I need to check post values with existing database values and my check isn't working for the values below. Code: [Select] //This one works if ((isset($_POST['companystageas'])) && ($_POST['companystageas'] != $info['stage'])) { $details = ''; update_company_actions($info['companyid'], 10, $details); } //These all fail if ((!isset($_POST['companystateas'])) && (($_POST['companycountryas'] != $info['country']) || ($_POST['city'] != $info['city']))) { $details = $_POST['companycityas'].', '.$_POST['companycountryas']; update_company_actions($info['companyid'], 11, $details); } else if ((isset($_POST['companystateas'], $_POST['companycityas'])) && (($_POST['companystateas'] != $info['state']) || ($_POST['companycityas'] != $info['city']))) { $details = $_POST['companycityas'].', '.$_POST['companystateas']; update_company_actions($info['companyid'], 11, $details); } if ((isset($_POST['capitalrequestedas'])) && ($_POST['capitalrequestedas'] != $info['capitalrequested'])) { $details = ''; update_company_actions($info['companyid'], 12, $details); } Hey y'all, I'm trying to write a PHP script for a login function. There are three elements, two text fields (username and password) and a button which calls the script. Segment from index.php file: <form action = "login.php" method = "POST"> Admin Login: <br> Username: <input type = "text" name = "usernameField"/><br> <!-- Password field--> Password: <input type = "password" name = "passwordField"/><br> <!-- Username field --> <input type = "button" value = "Login" name = "submitButton"/> <!-- Login button --> </form> Segment from login.php file: <?php $connect = mysql_connect("localhost", "root", "root"); if(!$connect){//If user can't connect to database die('Could not connect: ' . mysql_error()); //Throw an error } mysql_select_db("colin_db", $connect); //Get given username and password from username field and password field $givenUsername = $_POST["usernameField"]; $givenPassword = $_POST["passwordField"]; $myQuery = "SELECT * FROM ADMINS WHERE USERNAME = '$givenUsername' AND PASSWORD = '$givenPassword'"; $queryResult = mysql_query($myQuery); $numRows = mysql_num_rows($queryResult); if($numRows == 1){ //If the details are correct... //Reload the page and login echo "<script type = 'text/javascript'> window.location.reload() </script>"; } elseif($numRows == 0){ //Else if the details are not found //Display error accordingly echo "Details not correct!"; } mysql_close($connect); ?> The problem is, when I click the login button, it doesn't do anything. What am I missing? (The information in the database is correct) Thanks, Jake original sql Code: [Select] -- -------------------------------------------------------- -- -- Table structure for table `countries` -- CREATE TABLE `countries` ( `id` int(6) NOT NULL auto_increment, `value` varchar(250) NOT NULL default '', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=243 ; -- -- Dumping data for table `countries` -- INSERT INTO `countries` VALUES (1, 'Vancouver'); New Sql Code: [Select] -- -------------------------------------------------------- -- -- Table structure for table `countries` -- CREATE TABLE `countries` ( `id` int(6) NOT NULL auto_increment, `value` varchar(250) NOT NULL default '', `code` varchar(12) NOT NULL default '', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=243 ; -- -- Dumping data for table `countries` -- INSERT INTO `countries` VALUES (1, 'Vancouver', 'BC-50'); PHP code for the job Code: [Select] <?php // PHP5 Implementation - uses MySQLi. // mysqli('localhost', 'yourUsername', 'yourPassword', 'yourDatabase'); $db = new mysqli('localhost', 'root' ,'password', 'weather'); if(!$db) { // Show error if we cannot connect. echo 'ERROR: Could not connect to the database.'; } else { // Is there a posted query string? if(isset($_POST['queryString'])) { $queryString = $db->real_escape_string($_POST['queryString']); // Is the string length greater than 0? if(strlen($queryString) >0) { // Run the query: We use LIKE '$queryString%' // The percentage sign is a wild-card, in my example of countries it works like this... // $queryString = 'Uni'; // Returned data = 'United States, United Kindom'; // YOU NEED TO ALTER THE QUERY TO MATCH YOUR DATABASE. // eg: SELECT yourColumnName FROM yourTable WHERE yourColumnName LIKE '$queryString%' LIMIT 10 $query = $db->query("SELECT your_column FROM your_db_table WHERE your_column LIKE '$queryString%' LIMIT 10"); if($query) { // While there are results loop through them - fetching an Object (i like PHP5 btw!). while ($result = $query ->fetch_object()) { // Format the results, im using <li> for the list, you can change it. // The onClick function fills the textbox with the result. // YOU MUST CHANGE: $result->value to $result->your_colum echo '<li onClick="fill(\''.$result->value.'\');">'.$result->value.'</li>'; } } else { echo 'ERROR: There was a problem with the query.'; } } else { // Dont do anything. } // There is a queryString. } else { echo 'There should be no direct access to this script!'; } } ?> What the original code does 1) you start typing your city (eg. Van) 2) when you type the first letter (eg. V), it looks into mysql and auto fills a dropdown menu with all possible cities What i need it to do 1) you start typing your city (eg. Van) 2) when you type the first letter (eg. V), it looks into mysql and auto fills a dropdown menu with all possible cities 3) when you find your city you click it or press enter, and it POST's the city code as well now how do i munipulate the script to do that... another thing, when i put the extra sql entry in "code", the auto fill stopped working, why? Thanks I have a post.php that is suposted to run a mysql query, and it used to, but it won't anymore and I don't have the old file. Can someone just look see if there is something i'm missing? <?php //header("Location: ./?p=UCP"); setcookie("Errors", 0, time()-3600); // Connects to your Database mysql_connect("SERVER", "USER", "PASS") or die(mysql_error()); mysql_select_db("DB") or die(mysql_error()); if (isset($_POST['remove'])) { $id=$_POST['ID']; if($_POST['initals'] == "NLW") { if (is_numeric ($id)) { mysql_query("DELETE FROM `users` WHERE `users`.`ID` = $id LIMIT 1"); $error="<span style="; $error .="color:green"; $error .=">"; $error .= "User Removed."; $error .="</span>"; setcookie(Errors, $error, time()+20); } else { $error="<span style="; $error .="color:red"; $error .=">"; $error .= "Please enter a valid ID"; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } } else { $error="<span style="; $error .="color:red"; $error .=">"; $error .="Initials are not correct"; $error .="<span/>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } } elseif (isset($_POST['submit'])) { //This makes sure they did not leave any fields blank if (!$_POST['username'] | !$_POST['pass'] | !$_POST['pass2'] ) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= "You did not complete all of the required fields"; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } // checks if the username is in use if (!get_magic_quotes_gpc()) { $_POST['username'] = addslashes($_POST['username']); } $usercheck = $_POST['username']; $check = mysql_query("SELECT username FROM users WHERE username = '$usercheck'") or die(mysql_error()); $check2 = mysql_num_rows($check); //if the name exists it gives an error if ($check2 != 0) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= "Sorry, the username is already in use."; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location ./?p=UPC'); } // this makes sure both passwords entered match if ($_POST['pass'] != $_POST['pass2']) { $error="<span style="; $error .="color:red"; $error .=">"; $error .= 'Your passwords did not match.'; $error .="</span>"; setcookie(Errors, $error, time()+20); echo $error; } // here we encrypt the password and add slashes if needed $_POST['pass'] = md5($_POST['pass']); if (!get_magic_quotes_gpc()) { $_POST['pass'] = addslashes($_POST['pass']); $_POST['username'] = addslashes($_POST['username']); $_POST['pass2'] = $_POST['pass2']; } // now we insert it into the database $insert = "INSERT INTO users (username, password, Human-Readable) VALUES ('".$_POST['username']."', '".$_POST['pass']."', '".$_POST['pass2']."')"; mysql_query("INSERT INTO users (username, password, Human-Readable) VALUES ('".$_POST['username']."', '".$_POST['pass']."', '".$_POST['pass2']."')"); $error="<span style="; $error .="color:green"; $error .=">"; $error .= "<h1>User Registered</h1> <p><h2>Thank you, the user has been registered - he/she may now login</a>.</h2></p>"; $error .="</span>"; setcookie(Errors, $error, time()+20); header('Location: ./?p=UCP'); } else { header('Location: ./?p=UCP'); echo $error; } ?> The remove function works but its the submit. Thanks in advanced |
|||||||