|
PHP - Help With Php Menu
Hi,
I realise there is likely a very simple solution to this, but I'm pulling my hair out on it. I have a menu.php file on my Intranet that (funnily enough) holds the site menu and is inserted via an include. This works fine. My question is, how can I make it pick up what page I am on in the site, and change the menu accordingly? At the moment, with HTML (and before I changed the site to hold just one menu file), the menu looked like this: Code: [Select] <li class="link"> <a class="link levela" title="The drive formally known as "P""> <span>Company Documents</span></a> <ul> <li class="link"> <a class="link levelb" href="http://hhnet/company_documents/comm_forms.php" title="Forms... for Commission"> <span>Commission Forms</span></a></li> <li class="link"> <a class="link levelb" href="http://hhnet/company_documents/complaint_documentation.php" title="Documents documenting complaints."> <span>Complaint Documentation</span></a></li> and when the page was the current one, it looked like this: Code: [Select] <li class="current"> <a class="current levela" title="The drive formally known as "P""> <span>Company Documents</span></a> <ul> <li class="current"> <a class="current levelb" href="http://hhnet/company_documents/comm_forms.php" title="Forms... for Commission"> <span>Commission Forms</span></a></li> <li class="link"> <a class="link levelb" href="http://hhnet/company_documents/complaint_documentation.php" title="Documents documenting complaints."> <span>Complaint Documentation</span></a></li> As you can see, the class changes to "current". I want to be able to do it so that the central menu file can pick up what page the user is on, and mark the class as current. Any suggestions? Dave Similar TutorialsSo i have a <drop down> menu, and a <nav> menu on my left side of the page. I have a problem when i click at the first column of my drop down menu and it explores submenu, the submenu mixes with the nav menu that is under the drop down menu on the left. i could solve it with margin-top of the nav menu but i don't like the empty space beetwen them. I tried with putting overflow:visible; in CSS of my dropdown menu but it is still the same. drop down menu is seen but there is stil seen nav menu under and they are mixed. So basicly i want my dropdown menu to be priority, so when i clicks on my first column (only first column is problem because there under is nav menu the other are open nice) it will explore submenu and the part of nav menu that covers the submenu will be hidden.
Here is the screen shot:
Here is the code of head <dropdown> menu if someone finds the problem.
#menu, #menu ul {
margin: 0;
padding: 0;
list-style: none;
}
#menu {
width: 900px;
margin-top:20px;
margin-left:auto;
margin-right:auto;
border: 1px solid #222;
background-color: #111;
background-image: linear-gradient(#444, #111);
border-radius: 6px;
box-shadow: 0 1px 1px #777;
}
#menu:before,
#menu:after {
content: "";
display: table;
}
#menu:after {
clear: both;
}
#menu {
zoom:1;
}
#menu li {
float: left;
border-right: 1px solid #222;
box-shadow: 1px 0 0 #444;
position: relative;
}
#menu a {
float: left;
padding: 12px 30px;
color: #999;
text-transform: uppercase;
font: bold 12px Arial, Helvetica;
text-decoration: none;
text-shadow: 0 1px 0 #000;
}
#menu li:hover > a {
color: #fafafa;
}
*html #menu li a:hover { /* IE6 only */
color: #fafafa;
}
#menu ul {
margin: 20px 0 0 0;
_margin: 0; /*IE6 only*/
opacity: 0;
visibility: hidden;
position: absolute;
top: 38px;
left: 0;
z-index: 1;
background: #444;
background: linear-gradient(#444, #111);
box-shadow: 0 -1px 0 rgba(255,255,255,.3);
border-radius: 3px;
transition: all .2s ease-in-out;
}
#menu li:hover > ul {
opacity: 1;
visibility: visible;
margin: 0;
}
#menu ul ul {
top: 0;
left: 150px;
margin: 0 0 0 20px;
_margin: 0; /*IE6 only*/
box-shadow: -1px 0 0 rgba(255,255,255,.3);
}
#menu ul li {
float: none;
display: block;
border: 0;
_line-height: 0; /*IE6 only*/
box-shadow: 0 1px 0 #111, 0 2px 0 #666;
}
#menu ul li:last-child {
box-shadow: none;
}
#menu ul a {
padding: 10px;
width: 130px;
_height: 10px; /*IE6 only*/
display: block;
white-space: nowrap;
float: none;
text-transform: none;
}
#menu ul a:hover {
background-color: #0186ba;
background-image: linear-gradient(#04acec, #0186ba);
}
#menu ul li:first-child > a {
border-radius: 3px 3px 0 0;
}
#menu ul li:first-child > a:after {
content: '';
position: absolute;
left: 40px;
top: -6px;
border-left: 6px solid transparent;
border-right: 6px solid transparent;
border-bottom: 6px solid #444;
}
#menu ul ul li:first-child a:after {
left: -6px;
top: 50%;
margin-top: -6px;
border-left: 0;
border-bottom: 6px solid transparent;
border-top: 6px solid transparent;
border-right: 6px solid #3b3b3b;
}
#menu ul li:first-child a:hover:after {
border-bottom-color: #04acec;
}
#menu ul ul li:first-child a:hover:after {
border-right-color: #0299d3;
border-bottom-color: transparent;
}
#menu ul li:last-child > a {
border-radius: 0 0 3px 3px;
}
Here is the code of <nav> menu if someone finds the problem.
#cssmenu {
width:15%;
padding: 0;
margin-top: 50px;
margin-left:auto;
margin right:auto;
float:left;
border: 0;
line-height: 1;
}
#cssmenu ul,
#cssmenu ul li,
#cssmenu ul ul {
list-style: none;
margin: 0;
padding: 0;
}
#cssmenu ul {
position: relative;
z-index: 597;
float: left;
}
#cssmenu ul li {
float: left;
min-height: 1px;
line-height: 1em;
vertical-align: middle;
position: relative;
}
#cssmenu ul li.hover,
#cssmenu ul li:hover {
position: relative;
z-index: 599;
cursor: default;
}
#cssmenu ul ul {
visibility: hidden;
position: absolute;
top: 100%;
left: 0px;
z-index: 598;
width: 100%;
}
#cssmenu ul ul li {
float: none;
}
#cssmenu ul ul ul {
top: -2px;
right: 0;
}
#cssmenu ul li:hover > ul {
visibility: visible;
}
#cssmenu ul ul {
top: 1px;
left: 99%;
}
#cssmenu ul li {
float: none;
}
#cssmenu ul ul {
margin-top: 1px;
}
#cssmenu ul ul li {
font-weight: normal;
}
/* Custom CSS Styles */
#cssmenu {
width: 200px;
background: #333333;
font-family: 'Oxygen Mono', Tahoma, Arial, sans-serif;
zoom: 1;
font-size: 12px;
}
#cssmenu:before {
content: '';
display: block;
}
#cssmenu:after {
content: '';
display: table;
clear: both;
}
#cssmenu a {
display: block;
padding: 15px 20px;
color: #ffffff;
text-decoration: none;
text-transform: uppercase;
}
#cssmenu > ul {
width: 200px;
}
#cssmenu ul ul {
width: 200px;
}
#cssmenu > ul > li > a {
border-right: 4px solid #1b9bff;
color: #ffffff;
}
#cssmenu > ul > li > a:hover {
color: #ffffff;
}
#cssmenu > ul > li.active a {
background: #1b9bff;
}
#cssmenu > ul > li a:hover,
#cssmenu > ul > li:hover a {
background: #1b9bff;
}
#cssmenu li {
position: relative;
}
#cssmenu ul li.has-sub > a:after {
content: '+';
position: absolute;
top: 50%;
right: 15px;
margin-top: -6px;
}
#cssmenu ul ul li.first {
-webkit-border-radius: 0 3px 0 0;
-moz-border-radius: 0 3px 0 0;
border-radius: 0 3px 0 0;
}
#cssmenu ul ul li.last {
-webkit-border-radius: 0 0 3px 0;
-moz-border-radius: 0 0 3px 0;
border-radius: 0 0 3px 0;
border-bottom: 0;
}
#cssmenu ul ul {
-webkit-border-radius: 0 3px 3px 0;
-moz-border-radius: 0 3px 3px 0;
border-radius: 0 3px 3px 0;
}
#cssmenu ul ul {
border: 1px solid #0082e7;
}
#cssmenu ul ul a {
font-size: 12px;
color: #ffffff;
}
#cssmenu ul ul a:hover {
color: #ffffff;
}
#cssmenu ul ul li {
border-bottom: 1px solid #0082e7;
}
#cssmenu ul ul li:hover > a {
background: #4eb1ff;
color: #ffffff;
}
#cssmenu.align-right > ul > li > a {
border-left: 4px solid #1b9bff;
border-right: none;
}
#cssmenu.align-right {
float: right;
}
#cssmenu.align-right li {
text-align: right;
}
#cssmenu.align-right ul li.has-sub > a:before {
content: '+';
position: absolute;
top: 50%;
left: 15px;
margin-top: -6px;
}
#cssmenu.align-right ul li.has-sub > a:after {
content: none;
}
#cssmenu.align-right ul ul {
visibility: hidden;
position: absolute;
top: 0;
left: -100%;
z-index: 598;
width: 100%;
}
#cssmenu.align-right ul ul li.first {
-webkit-border-radius: 3px 0 0 0;
-moz-border-radius: 3px 0 0 0;
border-radius: 3px 0 0 0;
}
#cssmenu.align-right ul ul li.last {
-webkit-border-radius: 0 0 0 3px;
-moz-border-radius: 0 0 0 3px;
border-radius: 0 0 0 3px;
}
#cssmenu.align-right ul ul {
-webkit-border-radius: 3px 0 0 3px;
-moz-border-radius: 3px 0 0 3px;
border-radius: 3px 0 0 3px;
}
Edited by Dorkmind, 26 November 2014 - 05:00 PM. Hi All,
Am sure this is simple but can't work it out. I have the following which creates 3 menus:
<p>Drag items from one menu to another</p> <table> <tr> <td valign="top">Menu 1</td> <td valign="top">Menu 2</td> <td valign="top">Menu 3</td> </tr> <tr> <td valign="top"> <ul class="sortable" id="menu1"> <li id="id_1">Item 1</li> <li id="id_2">Item 2</li> </ul> </td> <td valign="top"> <ul class="sortable" id="menu2"> <li id="id_3">Item 3</li> <li id="id_4">Item 4</li> </ul> </td> <td valign="top"> <ul class="sortable" id="menu3"> <li id="id_5">Item 5</li> <li id="id_6">Item 6</li> </ul> </td> </tr> </table>This uses the following to show an array of each menu:
$(function() {
$("ul.sortable").sortable({
connectWith: '.sortable',
update: function(event, ui) {
$('#menu_choice').empty().html( $('.sortable').serial() );
}
});
});
(function($) {
$.fn.serial = function() {
var array = [];
var $elem = $(this);
$elem.each(function(i) {
var menu = this.id;
$('li', this).each(function(e) {
array.push( menu + '['+e+']=' + this.id );
});
});
return array.join('&');
}
})(jQuery);
What I'd like is to simply grab the values of menu 1 only, as the array shows all menus. What am I doing wrong as can't seem to just return menu1.
Going forward, I then want to store the returned array into a PHP cookie if this is possible?
Many thanks
I am close to pulling my hair out! I cannot seem to fix it. I am trying to make a HTML dropdown menu, this is what it looks like at the minute. im fairly new to php so tend to do trial and error..... more error than trial tbh. im wondering if it is possible to get a drop down menu to fill from a mysql database and to arrange it alphabetically. i have created the menu just dont know how to arrange it better. also how can i use the items id in drop menu to load other info from that row on the database. hope you can help me. Code: [Select] <FORM> <?php $result = mysql_query( "SELECT * FROM movie_info" ) ; echo "<select name= film onChange='submit()' >film name</option>"; while ($nt=mysql_fetch_array($result)){ ?> <?php echo "<option value='$nt[id]'>$nt[title] </option>"; } ?> </select> </FORM> Hi I want to add student from a dropdown list to database but I have some problem. This is my select dropdown menu code <form name ="student" method = "POST" action ="confirmation.php"> <select name="name"> <option selected>Select Student</option> <?php $arrStudent = executeSelectQuery("select * FROM user "); for ($i = 0; $i < count($arrStudent); $i++) { $student_result = $arrStudent[$i]['student_id']; $name_result = $arrStudent[$i]['student_name']; ?> <option value="<?php echo $id_result; ?>"><?php echo $id_result; ?>, <?php echo $name_result; ?></option> <?php } ?> </select> </form> The output in the dropdown menu look something like this: 1, Alvin 2, Benny 3, Charles 4, Daniel 5, Eva and so on... After submitting the form, it will proceed to confirmation.php page. At the confirmation page, I have the following variable: $student_result = $_REQUEST['student_id']; $name_result = $_REQUEST['student_name']; I want to insert to database with the following insert query $sql = "INSERT INTO student(student_id, student_name) VALUES ('". $student_result . "', '". $name_result ."')"; $insert = executeInsertQuery($sql); It can insert successfully but, it will not insert the student_name. May I know where I did wrongly? Thanks Ben Chew helo i a newbie in php. i need some help regarding my system. i want my data from database to display in drop down menu form.anyone have idea how to do that? i really need some help. i have search all over and couldn't find any solution. any suggestions would be helpful Hello, I am running into a problem. I am trying to convert : Code: [Select] $queryyp = "SELECT YEAR(date) as year, MONTHNAME(date) as month, title FROM post ORDER BY date DESC"; // query to get the rows you want in the order that you want them, with the year and monthname specifically selected as well $resultyp = mysql_query($queryyp); $last_heading = null; // remember the last heading (initialize to null) while($rowyp = mysql_fetch_assoc($resultyp)){ $new_heading = $rowyp['year']; // get the column in the data that represents the heading $new_subheading = $rowyp['month']; // get the column in the data that represents the subheading if($last_heading != $new_heading){ // heading changed or is the first one $last_heading = $new_heading; // remember the new heading $last_subheading = null; // (re)initialize the subheading // start a new section, output the heading here... echo "{$rowyp['year']}<br />"; } // subheading under each heading if($last_subheading != $new_subheading){ // subheading changed or is the first one $last_subheading = $new_subheading; // remember the new subheading // start a new section, output the subheading here... echo " {$rowyp['month']}<br />"; } // output each piece of data under a heading here... echo " {$rowyp['title']}<br />"; } And be able to put it in a javascript tree with very little luck: Code: [Select] <ul id="yeartree" class="tree"> <li>{$rowyp['year']} <ul> <li>{$rowyp['month']} <ul> <li>{$rowyp['title']}</li> </ul> </li> </ul> </li> Yes I know the phpcode in the tree is not correct. That is just an example of what I am attempting to do. I can get the tree to display without the js but I need to add it to js due to the amount of entries and need to beable to collapse it. Hi, I am using php dynamic listing from database. it is working but I wanna integrate to a horizontal css menu how can i integrate my codes to any css horizantal dropdown menu. thans. here my dynamic list. <?php function sinirsiz_kategori($parent) { $sql = mysql_query("SELECT * FROM kategoriler ORDER BY id DESC"); while($row = mysql_fetch_array($sql)) { $diziler[$row['id']] = array('baslik' => $row['baslik'],'parent' => $row['parent']); } $has_childs = false; foreach($diziler as $key => $value) { if ($value['parent'] == $parent) { if ($has_childs === false){ $has_childs = true; echo "\t<ul>"; } echo "<li><a href=\"".$value['baslik'].".php\">".$value['baslik']."</a>"; sinirsiz_kategori($key); echo "</li>\n"; } } if ($has_childs === true) echo "</ul>"; } ?> <?=sinirsiz_kategori(0)?> Hi, i know this is probably very basic but i have been banging my head and looking for tuts. i have built a mysql php dropdown menu. all displays fine. now, how do i get the menu to actualy take me to a new url? the new url should be www.mysite.com/"menu selection" Code: [Select] <? include_once 'includes/db.php'; $result = mysql_query("select * from crimerate WHERE DISTRICT = 'Limpopo'", $con); if (!$result) { die('Invalid query: ' . mysql_error()); } $options=""; while ($row=mysql_fetch_array($result)) { $id=$row["id"]; $crime=$row["CRIME"]; $options.="<OPTION VALUE=\"$id\">$crime</option>"; } ?> <SELECT NAME=crime> <OPTION VALUE=0>Choose <?=$options?> </SELECT> Hi all, I was wondering if someone knows a clean way to make a dropdown menu using just php and html with the following functionality. If someone selects a value from the dropdown options it should be visible on refresh. So in case a have a dropdown menu with: oranges, apples, grapes and someone selects grapes and submits it, grapes should be selected. I have made someonthing but it looks redundant. I think there should be something with a foreach loop or something but i can't figure it out yet. Thanks in advance, cheers!! i have a menu home id1 about id2 gallery id3 and so on with drop downs sub menu home and about are normal text pages but gallery is were the drop down is when i select gallery it shows empty connent page how do i make it do nothing just an id for the sub menu any help would be great First of all I am very new to php. I have coded in asp for years but have made the switch so I kinda know what I want to do but I am unsure on how to achieve it. I have a css menu that I am trying to populate through a database. The parent tabs are in a standard list. The first child submenu is in sepearate unordered list and anymore child tabs are within that list. Like this. Code: [Select] <div id="ddtopmenubar" style="width: 960px"> <ul> <li><a href="?page=">HOME </a></li> <li><a href="?page=About" rel="">ABOUT </a></li> <li><a href="?page=Services" rel="SERVICES">SERVICES </a></li> <li><a href="?page=Governance" rel="GOVERNANCE">GOVERNANCE </a></li> <li><a href="?page=Events">EVENTS </a></li> <li><a href="?page=Contact">CONTACT </a></li> </ul> <ul id="SERVICES" class="ddsubmenustyle"> <li><a href="?page=Health">Health/Dental</a></li> <li><a href="?page=Identification">International Student Identification Card</a></li> <li><a href="?page=Employment">Student Employment</a></li> <li><a href="?page=Saver">Student Saver</a></li> <li><a href="#">Other Services</a> <ul> <li><a href="#">Emergency Student Loan Fund</a></li> <li><a href="#">Legal Services</a></li> <li><a href="#">Parking Permits</a></li> <li><a href="#">Homes4Students</a></li> </ul> </li> </ul> <ul id="GOVERNANCE" class="ddsubmenustyle"> <li><a href="?page=Council">Your Council</a></li> <li><a href="?page=Executive">Executive</a></li> <li><a href="?page=Committees">Committees</a></li> <li><a href="?page=Constitution">Constitution/By-Laws</a></li> <li><a href="?page=Minutes">Minutes</a></li> <li><a href="?page=Elections">Elections</a></li> </ul> </div> I am trying to populate this from a database list the results come ordered like this Code: [Select] 1.0 2.0 3.0 3.1 3.2 3.3 3.4 3.4-1 3.4-2 3.4-3 3.4-4 4.0 4.1 4.2 4.3 4.4 4.5 4.6 5.0 6.0 where the "." show the 1st childs and the "-" show the 2nd child I tried to do this by splting each line and determining if it is a zero or not if it was a zero i put that paticular one into an array to be used in the sub menu however this did not work out. Any ideas? Hi everybody. I'm pretty new in PHP programmation and really new on this forum. So, I'll try to explain my situation the best I can. I have created a modification page where the user can modify certain data of the database. To avoid spelling mistakes, I have created a scroll down menu that includes all the options they have. My problem is that I what the "actual Selection" of the database to be the "selected" option right from the start. Now, my scroll0-down menu shows the first option of my list and not the actual value contained in the database. Here is my partial code: <td><select name="equipe" value="<?php echo($result->equipe) ;?>"> <option <?php if (($result->equipe) == 'Colorado') echo "selected" ?>value='Colorado'>Colorado</option> <option <?php if (($result->equipe) == 'St-Louis') echo "selected" ?>value='St-Louis'>St-Louis</option> <option <?php if (($result->equipe) == 'Montreal') echo "selected" ?>value='Montreal'>Colorado</option> <option <?php if (($result->equipe) == 'Washington') echo "selected" ?>value='Washington'>Washington</option> <option <?php if (($result->equipe) == 'Islanders') echo "selected" ?>value='Islanders'>Islanders</option> <option <?php if (($result->equipe) == 'Edmonton') echo "selected" ?>value='Edmonton'>Edmonton</option> <option <?php if (($result->equipe) == 'Floride') echo "selected" ?>value='Floride'>Floride</option> <option <?php if (($result->equipe) == 'Pittsburgh') echo "selected" ?>value='Pittsburgh'>Pittsburgh</option> <option <?php if (($result->equipe) == 'Anaheim') echo "selected" ?>value='Anaheim'>Anaheim</option> </select> Hi, i wonder whether someone may be able to help me please. I am using a combination of PHP and AJAX to create two drop down menus on a HTML form. The data is being pulled from a mySQL database with the options available in the second drop down dependent on the value selected in the first. The initial drop down menu called 'detectors' and the behaviours for the second drop down menu, 'searchheads' are created with the following AJAX code: Code: [Select] Function AjaxFunction(detectorid) { var httpxml; try { // Firefox, Opera 8.0+, Safari httpxml=new XMLHttpRequest(); } catch (e) { // Internet Explorer try { httpxml=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { httpxml=new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) { alert("Your browser does not support AJAX!"); return false; } } } function stateck() { if(httpxml.readyState==4) { var myarray=eval(httpxml.responseText); // Before adding new we must remove previously loaded elements for(j=document.addfindstolocation.searchheads.options.length-1;j>=0;j--) { document.addfindstolocation.searchheads.remove(j); } for (i=0;i<myarray.length;i++) { var optn = document.createElement("OPTION"); optn.text = myarray[i]; optn.value = myarray[i]; document.addfindstolocation.searchheads.options.add(optn); } } } var url="searchheaddetails.php"; url=url+"?detectorid="+detectorid; url=url+"&sid="+Math.random(); httpxml.onreadystatechange=stateck; httpxml.open("GET",url,true); httpxml.send(null); } The following code is the file 'searchheaddetails.php' (as highlighted above) which populates the second drop down menu. Code: [Select] <? $detectorid=$_GET['detectorid']; require "config.php"; $q=mysql_query("SELECT * FROM searchheads WHERE detectorid='$detectorid' ORDER BY 'searchheadname' ASC"); echo mysql_error(); $myarray=array(); $str=""; while($nt=mysql_fetch_array($q)){ $str=$str . "\"$nt[searchheadname]\","; } $str=substr($str,0,(strLen($str)-1)); // Removing the last char , from the string echo "new Array($str)"; ?> And this is the section of my form that pulls together the two drop down menus. Code: [Select] <form name="addfindstolocation" method="post" id="addfindstolocation"> <div align="left"> <select name=detectors id="detectorid" onchange="AjaxFunction(this.value);"> <option value=''>Select One</option> <? require "phpfile.php";// connection to database $q=mysql_query("SELECT * from detectors WHERE userid='1'ORDER BY 'detectorname' ASC"); while($n=mysql_fetch_array($q)){ echo "<option value=$n[detectorid]>$n[detectorname]</option>"; } ?> </select> </div> </div> <p align="left"> <label></label> <label>Search Head Used</label></p> <div> <div align="left"> <select name=searchheads id="searchheadid"> </select> </div> The drop down menus work fine, but I'm having a little difficulty with the data that is being saved. For the 'detectors' drop down menu the data being saved upon a selection being made is the 'id' pertient to the relevant detector e.g. 'Detector1' is selected and the 'id' value of '1' is saved which is exactly what I want. However when it comes to the second drop down menu, the value saved is the text value that the user selects, rather than the 'id'. e.g. 'Deep Search Head ' rather than an 'id' of '1'. Could someone perhaps tell me please what I need to change so that the 'id' value is saved rather than the text value. If it helps, the coding is taken from the following http://www.plus2net.com/php_tutorial/ajax_drop_down_list.php. Many thanks and kind regards. Chris this is my nav menu code Code: [Select] <ul> <li><a href='fountains_page.php?id=all'>all fountains</a></li> <li><a href='fountains_page.php?id=garden'>garden fountains</a></li> <li><a href='fountains_page.php?id=wall'>wall fountains</a></li> </ul> this is my script Code: [Select] require('dbconnect.php'); $id = $_GET['id']; if($id = all){ $records = "SELECT * FROM (fountains)"; }else{ if ($id = garden){ $records = "SELECT * FROM (fountains) WHERE wall='no'"; }else{ if($id = wall){ $records = "SELECT * FROM (fountains) WHERE wall='yes'"; } } } $query_records = mysql_query($records); $num_records = mysql_num_rows($query_records); if ($num_records == 0) { echo "The menu is closed for now."; } else{ $i=1; } echo 'We have'.' '.$num_records.' '.'fountains for your consideration<br />Please visit our store to view hundreds of styles.<br />'; echo $id; $errors = array(); // initialize error array Here is the link http://www.mywebsitepaid.com/stonemans/fountains_page.php I can't get the 'id' to pass. What am I doing wrong? I did another site fine, but here I messed something up. Can somebody please have a look at this. The Problem I am having is that only 1 entry for each month goes into the tree and for the life of me I can't figure out why. Code: [Select] $queryyp = "SELECT YEAR(date) as year, MONTHNAME(date) as month, title FROM monsterpost ORDER BY date DESC"; // query to get the rows you want in the order that you want them, with the year and monthname specifically selected as well $resultyp = mysql_query($queryyp); $last_heading = null; // remember the last heading (initialize to null) while($rowyp = mysql_fetch_assoc($resultyp)){ $new_heading = $rowyp['year']; // get the column in the data that represents the heading $new_subheading = $rowyp['month']; // get the column in the data that represents the subheading if($last_heading != $new_heading){ // heading changed or is the first one $last_heading = $new_heading; // remember the new heading $last_subheading = null; // (re)initialize the subheading // start a new section, output the heading here... echo "<ol class=\"tree\"><li><label for=\"folder1\">{$rowyp['year']}</label> <input type=\"checkbox\" id=\"folder1\" /></li></ol>"; } // subheading under each heading if($last_subheading != $new_subheading){ // subheading changed or is the first one $last_subheading = $new_subheading; // remember the new subheading // start a new section, output the subheading here... echo "<ol><li><label for=\"subfolder1\">{$rowyp['month']}</label> <input type=\"checkbox\" id=\"subfolder1\" />"; } // output each piece of data under a heading here... echo "<ol><li class=\"file\">{$rowyp['title']}</li></ol></li></ol></li></ol>"; } Hi, I have some code that I think worked at one point, but now it doesn't. I have a side navigation menu which I have set as an include. I want to change CSS styling to a current state to whatever page you are current on. For instance the portfolio link would look like this. Code: [Select] <li><a id="current" href="../Portfolio/" title="Visit my Portfolio">Portfolio</a></li> Both the page I am trying to set this on and my includes are in separate directories, so I am not sure if that is messing things up, but the id="current is not being set with what I currently have as my code. Here is my current code. <?php $menu = <<< MENU <div id="SideMenu"> <div id="button"> <img src="../images/NavButton.png" width="184" height="32" class="menu_class" /> <ul class="the_menu"> <li><a href="../index.php" title="take me home">Home</a></li> <li><a href="../Portfolio/" title="Visit my Portfolio">Portfolio</a></li> <li><a href="../blog/" title="See what I have to say">Blog</a></li> <li><a href="../Contact/" title="Get in Touch with me">Contact</a></li> </ul> </div><!--end button div--> </div><!--end SideMenu div--> MENU; $lines = split("\n", $menu); foreach ($lines as $line) { $current = false; preg_match('/href="([^"]+)"/', $line, $url); if (substr($_SERVER["REQUEST_URI"], 0, 5) == substr($url[1], 0, 5)) { $line = str_replace('<a h', '<a id="current" h', $line); } echo $line."\n"; } ?> any ideas? Hi i currenlty have adrop box filled with companies so the user can select which company they woudl like services from but the default is currently 0 and is to selecvt all firms but im unsure how to do this. Current code: Code: [Select] <td>Taxi Firm</td><td> <select name="taxifirm"> <option value="0" selected>All Taxi Firms</option> <?php $sql = mysql_query("SELECT * FROM taxi_Firms"); while($row = mysql_fetch_array($sql)){ $uid = $row["Firm_ID"]; $username = $row["Firm_Name"]; echo '<option value="'.$uid.'">'.$username.'</option>' ; } ?> amny help is welcomed thanx I'm trying to code a drop-down menu that has four options; one for pie,exp, root 3, and the golden ratio.(all math values) Beside the drop-down menu, there is an option for user-inputted data, they must input only positive numbers. I must take there selected drop-down menu option and times it by the user inputted number. I'm not sure how to check which option the user chose.
<form id="s" method="post"> </select> <input type="submit" name="Submit" value="Send"> Everything That ive tried has failed I did search this up but all of them were lists.
I want to make a menu drop down like so....
Non-clicked...
Clicked...
The grey boxes would be images (unless it is easier to code them).
I am a complete noob so please don't use technical terms
Thanks
|
|||||||