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PHP - $_post Not Working.it Aint Producing Any Values
Code: [Select]
<?php $query = "Select * from users where username = '$user' "; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result); $test = $_POST['test1']; $ques = "Select * from questions where testname = '$test' "; $qres = mysql_query($ques) or die(mysql_error()); $qdetails = mysql_fetch_array($qres); $id = $qdetails['id']; $testname = $qdetails['testname']; $ans = "Select * from answers where qid = $id"; $ares = mysql_query($ans) or die(mysql_error()); if($qdetails) { ?> <div class="padding"> <form name="answerform" action="answer.php" method="POST"> <h3> </h3> <input name="test2" id="test2" type="text" value="<?php echo $qdetails['testname'];?>" /><h3><?php echo $qdetails['text'];?></h3> <input name="test3" id="test3" type="text" value="<?php echo $qdetails['testseries'];?>" /><h3><?php echo $qdetails['text'];?></h3> <br /> <br /> <br /> <?php while($opdetails = mysql_fetch_assoc($ares)) { ?> <input class="text" id="opt2" name="correctans" type="radio" value="<?php echo $opdetails['text']; ?>" /><br /><?php echo $opdetails['text']; ?> <?php }?> <div class="two-fields clearfix". <p class="confirm"> </p> </div> <input type="submit" value="SUBMIT ANSWER" /> </form> </div> </div> </div> <?php } this is the code for the program where i am creating the fields i want to fetch the data from the input fields with the name test 2 and test 3 in answer.php Code: [Select] $query = "Select score from users where username = '$user' "; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result); $user_score = $row['score']; print_r($_REQUEST); $tester = $_POST['test3']; $test = $_POST['test2']; print_r($_POST); var_dump($_POST); $ques = "Select * from questions where testname = '$test' And testseries = '$tester' "; $result = mysql_query($ques) or die(mysql_error()); $row = mysql_fetch_array($result); $qid = $row['id']; $score = $row['score']; if(isset($_POST['correctans'])) { $answer = $_POST['correctans']; } else { $answer = ''; } $fetch_ans = "Select * from answers where correct = 1 AND qid = $qid"; $result = mysql_query($fetch_ans) or die(mysql_error()); $row = mysql_fetch_array($result); $id = $row['id']; $correctans = $row['text']; if('$correctans' == '$answer') { $user_score += $score; $qid++; $query = "Update users set score = $user_score where username = '$user'"; $res = mysql_query($query) or die(mysql_error()); if($res) { header("Location: answer.php"); } }else { header("Location: answer.php"); } ?> THIS IS answer.php and here i try to post information from test2 and test3 fields but i am not getting any output the output shows blank array() and unidentified index test2 and unidentified index test3 i am not able to figure out the error any help will be highly appreciated and forgive me if i have made any mistakes in posting the question since i am a newbie at PHPFREAKS Similar TutorialsI am trying to produce a thresholded image with only an rgb value of zero or 255. As you can see, although I only output 0 and 255, I am finding that if I output as jpg file, I get other values in there as well. If I output as gif, I also get other values in there too. I am sure I am doing something stupid as there must be a way to do this. My test file is this attached jpg greyscale file. Is there a way to process this test file so that only 0 or 255 appears in the output image please? Thanks. Here is my program <?php $url = 'greyscale_image.jpg'; $outfile = 'greyscaleout'; $src = imagecreatefromjpeg($url); $w = imagesx($src);$h = imagesy($src); $loband = 80;$hiband = 255; $im_r = imagecreatetruecolor($w,$h); imagefill($im_r,0,0,imagecolorallocate($im_r,255,0,0)); $im_j = imagecreatetruecolor($w,$h); imagefill($im_j,0,0,imagecolorallocate($im_j,255,0,0)); for ($x=0;$x<$w;$x++) { for ($y=0;$y<$h;$y++) { $idx = imagecolorat($src,$x,$y); $rgb = imagecolorsforindex($src,$idx); // this is safest (for gifs) rather than some calculation - apparently $r =$rgb['red']; $g = $rgb['green']; $b = $rgb['blue']; $gryout = $r; if ($r <= $loband) { $gryout = 0; // everything less than= loband is black } if ($r > $loband) { $gryout = 255; // everything else is white } if ( ($gryout == 0) || ($gryout == 255) ) { // only zero or 255 allowed $idx = imagecolorallocate($im_r,$gryout,$gryout,$gryout); imagesetpixel($im_r,$x,$y,$idx); // imagesetpixel($im_j,$x,$y,$idx); // $idx2 = imagecolorat($im_r,$x,$y);// if ($idx != $idx2) { die($idx2." at x,y ".$x.",".$y); } $rgb = imagecolorsforindex($im_r,$idx); // this is safest (for gifs) rather than some calculation - apparently $r =$rgb['red']; $g = $rgb['green']; $b = $rgb['blue']; if ($r != 0) { if ($r != 255) { die($r." at x,y ".$x.",".$y); } } } else { die('<br>Grey going out to image is '.$gryout); } } } imagegif($im_r,$outfile.'.gif');imagedestroy($im_r); imagejpeg($im_j,$outfile.'.jpg');imagedestroy($im_j); // ========================== // done the writing, now check it // ========================== // $outfile = 'greyscale_image'; // test using original $src = imagecreatefromjpeg($outfile.'.jpg'); $w = imagesx($src);$h = imagesy($src); $errcount = 0; $x = 0; while($x<$w) { $y = 0; while($y<$h) { $idx = imagecolorat($src,$x,$y);// $rgb = imagecolorsforindex($src,$idx); // this is safest (for gifs) rather than some calculation $r =$rgb['red']; $g = $rgb['green']; $b = $rgb['blue']; if ($r != 0) { if ($r != 255) { echo sprintf('<br>r(%d,%d) r=%d g=%d b=%d',$x,$y,$r,$g,$b);$errcount++; } } if ($g != 0) { if ($g != 255) { echo sprintf('<br>g(%d,%d) r=%d g=%d b=%d',$x,$y,$r,$g,$b);$errcount++; } } if ($b != 0) { if ($b != 255) { echo sprintf('<br>b(%d,%d) r=%d g=%d b=%d',$x,$y,$r,$g,$b);$errcount++; } } if ($errcount > 10) {break 2;} $y++; } $x++; } if ($errcount == 0) {die( ' Checked OK' );} die( ' Checked NOT OK' ); // ================= ?> Hi all I am populating a List menu with values from Mysql table. The values are populated correctly. Once a selection is made and upon submit when I display POST submit values using print_r($_POST) the result is correct only when the value do not contain spaces. For example if the list selection is "One" the $_POST[sel] value is correct. But if the selection is "Two Three" it is only first part before space. How do I get it to give complete value as in the list. Thanks and Regards SKN Greetings folks, I've tried searching on this but couldn't find anything which I think is odd since I'm sure I'm not the first person with this question... I have a project that is basically a big (really big) form. When the user hits submit they get a CSV file. My client will then import the CSV into their database. The CSV is made up of two lines, the first being field names and the second line being the field values. Both the names and values are pulled from $_POST. The CSV looks like this: "Name","Age","Favorite Color" "Bob","12","Purple" The problem I having is if the user skips a question, let's say Age for this example, the CSV will look like this: "Name","Age","Favorite Color" "Bob","Purple" The clients database then freaks when it sees the value for Age is Purple. So my question is, how does one handle null values from from $_POST to avoid such an issue? Thank you! Thank you! Thank you! I have a table that I must be populated based on a check box selection. The maximum selection is 5, however, there are more then 10 choices. For example: Here is a choice of 10 different (checkbox) options that the user can select from: 1. Coke 2. Root Beer 3. Pepsi 4. Dr. Pepper 5. Sprite 6. 7up 7. Cream Soda 8. Club Soda 9. Water 10. Milk I've already managed to limit the users selection to only 5. My issue is determining which of the checkboxese were actually selected so that I can correctly place them in my database. The first thing to do is create variables from all the checkboxes: $coke = $_POST['coke']; $rootbeer = $_POST['rootbeer']; $pepsi = $_POST['pepsi']; $drpepper = $_POST['drpepper']; etc. etc. Now that I have all 10 selections as variables from a submitted form how can I determine which ones are empty (or which ones have values) so that I can then save them to the database respectively? Hi I would like to generate list of $_POST values using records from database: example: Code: [Select] $amount1=$_POST['amount1']; $amount2=$_POST['amount2']; $amount4=$_POST['amount4']; $amount7=$_POST['amount7']; where number next to amount word is simply id value in the database. $_POST values i get from the form erlier. I tried following way and some other ways too but doesnt seems to work (and im not even sure if possible). Code: [Select] $result2 = mysql_query("SELECT * FROM list") or die(mysql_error()); while($row2=mysql_fetch_array($result2)) { $amo = "amount"; $amount = $row2['id']; $amo1 = $amo.$amount; $amo1 = $_POST['$amo1']; echo "($amo1)"; } Hope is clear what i want to do! Thank you very much in advance. I'm trying firstly to output hidden fields based on the values of the $_POST variable. Then after that I want to output the values again in a unordered list. I'm using the following code: while (list($key, $val) = each($_POST)) { if ($key != 'Submit') { echo '<input type="hidden" name="' . $key . '" value="' . $val . '" />'; } } echo '<ul>'; while (list($key, $val) = each($_POST)) { if ($key != 'Submit') { echo '<li><strong>' . $key . '</strong>: <span class="highlight-219ddb">' . $val . '</span></li>'; } } echo '</ul>'; However the <ul> appears to be blank? Can I only use the list() function once on a particular variable? Hello everyone, I'm trying to code a section of the site which is like an advertising website (i.e, gumtree) where people can post an Ad on the site and have any responses sent to them via email. The thing is that I have a form where they can enter their details and need to POST the information to the following page which is a preview page of their Ad. I have the form action returning to the same page for validation but I need the $_POST vaules to populate the following page without sending information to the database (in an effort to keep the database clean should they decide not to publish their Ad. There are 3 pages in total CREATE AD > PREVIEW AD (where they can go back and edit if they need to) > Publish AD (where they confirm terms and send to database). I do have session variables already set after login in and a seperate table to hold the details after they have confirmed the Ad & terms. Any ideas would be greatly appreciated. Thanks, L-plate Well I have a script file that loads lots of info from a form using $_POST[] method, which is quite tedious: Code: [Select] $act = $_POST["act"]; $page = $_POST["page"]; $id = $_POST["id"]; $category = $_POST["category"]; $itemname = $_POST["itemname"]; $description = $_POST["description"]; $imageurl = $_POST["imageurl"]; $existingimageurl = $_POST["existingimageurl"]; $function = $_POST["function"]; $target = $_POST["target"]; $value = $_POST["value"]; $shop = $_POST["shop"]; $price = $_POST["price"]; $tradable = $_POST["tradable"]; $consumable = $_POST["consumable"]; I was wondering if there is a way to write one or two simple lines of code to load all variables stored in superglobal array $_POST[] efficiently. The point is to store all values within $_POST[] to an array called $item[], what I was thinking about is: Code: [Select] foreach($_POST = $key as $val){ $item['{$key}'] = $val; } Seems that its not gonna work, so I wonder if anyone of you have ideas on how I am able to simplify my code with 10-20 lines of $_POST[] to just 2-3 lines. Please do lemme know if this is possible, thanks. Hi all, I'm looking for some pointers in regards to my form.. How would I firstly trim the $_POST value of the variables that come through via the form (I'm only using one for now)..I know I'm making a right dogs dinner of it. In my head I'm thinking, trim all the posts first before i even assign a variable to it ( i dont know if thats possible), then use an array for when more values start coming through via the form. You know as i make a contact form that requires more data from the user..
<?php
require_once '../connection/dbconfig.php';
include_once('../connection/connectionz.php');
//get the values
//Get the request method from the $_SERVER
$requestType = $_SERVER['REQUEST_METHOD'];
//this is what type
//echo $requestType ;
if($requestType == 'POST') {
//now trim all $_POSTS
$search_products = trim($_POST['search_products']);
//
if(empty($search_products)){
echo '<h4>You must type a word to search!</h4>';
}else{
$make = '<h4>No match found!</h4>';
$new_search_products = "%" . $search_products . "%";
$sql = "SELECT * FROM product WHERE name LIKE ?";
//prepared statement
$stmt = mysqli_stmt_init($conDB);
//prepare prepared statements
if(!mysqli_stmt_prepare($stmt,$sql)) {
echo "SQL Statement failed";
}else{
//bind parameters to the placeholder
mysqli_stmt_bind_param($stmt, "s", $new_search_products );
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
echo'<h2> Search Result</h2>';
echo 'You searched for <strong><em>'. $search_products.'</em></strong>';
while($row = mysqli_fetch_assoc($result)){
echo '<h4> (ID : '.$row['pid'];
echo ') Book Title : '.$row['name'];
echo '</h4>';
}
}
}
}
;?>
If any one can shed some light on this, or some pointers..that would be very nice... Thanks Darren
So, i need this. Hello pros. I've been working on a website, and i just figured out that a thing is completely wrong. I am entering the website with: "website.com/something.php?name='Hello/system/root/advance.exe'" but somehow the $_POST['name'] is null... My current php code which just prints that post data: Spoiler <?php $postedFileName = $_POST["name"]; echo $postedFileName; /*#-- Here it doesnt echo anything --#*/ ?> I am having problems storing a $_POST variable from a form into a $_SESSION. When I go to the next page and echo out the $_SESSION variable its blank Page 1 code (page with self submitting form action) <?php session_start(); $email = $_POST['email]; $_SESSION['email'] = $email; ?> Page 2 (page which should be echoing out the value of the session variable) <?php session_start(); echo "Your Email Address which you submitted was: " . $_SESSION['email']; ?> When I echo that out on page 2 its blank Why is the variable value not carrying over to the 2nd page? Chad So ive created a forum that I got handling several different approvals. (it is used to approve or decline all submitted notes) it works fine and it even submits fine im at the part know where i process the information and do something with it, below is my form: <form action="course_proccess.php?action=approve" method="post"> <table align="left" border="1" cellspacing="0" cellpadding="3"> <tr> <td><b>Author</b></td> <td><b>File name</b></td> <td><b>Download</b></td> <td><b>Suggested catagory</b></td> <td><b>Select Catagory</b></td> <td>Approve</td> </tr> <td><input type="text " disabled="disabled" name="tr1_author" value="MikeH" </td> <td><input typee="text " disabled="disabled" name="tr1_name" value="A lot of my skills set back"</td> <td><a href= /uzEr%20Upl0ds/cache.zip > Download</a></td> <td>1001 Laws - Polceing </td> <td><select name="tr1_scatagory"> <option value="1"> Intro To Law </option> <option value="2"> 1001 Laws - Police Foundations </option> </select></td> <td><select name = "tr1_approve"> <option value = "1"> Yes</option> <option value = "2"> no</option> </select></td> </tr> <td><input type="text " disabled="disabled" name="tr2_author" value="MikeH" </td> <td><input typee="text " disabled="disabled" name="tr2_name" value="MM"</td> <td><a href= /uzEr%20Upl0ds/Michael Heintzman.doc > Download</a></td> <td>1001 Laws - Polceing </td> <td><select name="tr2_scatagory"> <option value="1"> Intro To Law </option> <option value="2"> 1001 Laws - Police Foundations </option> </select></td> <td><select name = "tr2_approve"> <option value = "1"> Yes</option> <option value = "2"> no</option> </select></td> </tr> <input type="hidden" name="rowCount" value="2"> <tr> <td><input type="submit" name="sendData" value="send"/></td> </tr> </table> </form> so what I do in my process file is I have a for loop for all of the "TR's" in the table and if it is approved I have an if statment and then I want to add db stuff my problem is my $_POST's are returning blank and I have no idea why. Can someone please assit me with this? (p.s i have debugged and it does get into the if approve == 1 statment. if(isset($_GET['action'])){ if ($_GET['action'] == "approve"){ if(isset($_POST['sendData'])) { $dataArray = array(); $row_count = $_POST['rowCount']; for($i=1;$i<$row_count;$i++) { $approven = "tr".$i."_approve"; $approve = $_POST[$approven]; if($approve == 1) { //Move the info over to "approved files" and delete it out of newnotes $author = "tr".$i."_author"; $location = "tr".$i."_location"; $catagory ="tr".$i."_scatagory"; $filename = "tr".$i."_name"; $submitedby = $_POST['author']; die($submitedby); $dataArray[]=array('author'=>$author,'fileName'=>$fileName,'Catagory'=>$catagory,'location'=>$location); var_dump($dataArray); }else{ //Email user saying they did not recive credits AND delete the entry } } if(!empty($dataArray)) { //now do what you want with the dataArray... var_dumb($dataArray); } } } I have a simple log in form. By debugging I found that isset post submit function is not responding. It remains on the same page after submitting form. I have googled all the possible solutions to this problem but none worked. Any help is greatly appreciated. The form is in multiplelogin.php file and the code is in multi.php file. After login redirection is to teachers.php file. <?php session_start(); $conn = mysqli_connect("localhost", "root", "", "signup");
if(isset($_SESSION['username'])) {
?>
<head> <link rel="stylesheet" type="text/css" href="bootstrap.css"> <title> Teachers Students Login </title> </head> <body class="bg-secondary"> <div class="container"> <div class="row justify-content-center"> <div class="col-log-5 bg-light mt-5 px-0"> <h3 class="text-center text-light bg-primary py-3 px-5"> Log In </h3>
<div class="form-group px-5"> <input type="email" name="email" class="form-control form-control-lg" placeholder="Email" required> </div> <div class="form-group px-5"> <input type="password" name="password" class="form-control form-control-lg" placeholder="Password" required> </div> <div class="form-group px-5"> <input type="submit" name="submit" value="Submit" class="btn btn-primary btn-block"> </div> </form> </div> </div> </div>
<?php
ini_set( 'display_errors', 1 );
$password = $_POST['password'];
$stmt = mysqli_stmt_init($conn); header("Location: multilogin.php?error=sqlerror"); exit();
} else { mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
if ($pwdCheck == false) {
exit(); $_SESSION['username'] = $row['username']; $_SESSION['email'] = $row['email']; header("Location: teachers.php?login=success");
exit ();
exit();
exit();
else {
exit(); Hi, I have set up 2 php pages page 1 - add_entry2.php In this page I have a invoice table created where I can dynamically add/delete rows. This has a View Bill button which takes me to page 2- add_entry3.php In this page it shows up the rows added in page 1 in read only format, so if the user wants to modify the data that he/she entered then he must Click on <back> that i have provided in the page 2 which will direct him to page 1 Now the problem starts here on click of Back the dynamically added rows dissappear..which is frustrating..I know its something to do with my code..but can anyone help me fix it. One more thing is that i dont want to store the data into DB till the finalise button is clicked on page 2 so that means till page 2 is submitted nothing goes to DB from Page 1. I am able to retain values if I use the code Code: [Select] <form action="add_entry2.php" name="eval_edit" method="post" format="html"> i,e if I submit back to the same page and retrieve values form $_POST but If I use the code Code: [Select] <input type="button" value="Back" onClick="history.go(-1);return true;">to get back to add_entry2.ph it looses all the values. Is there any other way to code the BACK link retaining my $_POST values(Do you think $_SESSION would work in this case?) When I echo the POST, it echoes the correct value. The MySQL portion seems to just ignore it all together. I've tried changing the dropdown option to just a text field, same thing occurred. I have text fields right above this particular one that update just fine with the SAME exactly scripting. if POST, update query, done. Works. This one for some reason will not. MySQL portion: if ($_POST['bUpdate']){ mysql_query("UPDATE `Patients` SET `b` = '$_POST[bUpdate]' WHERE `id` = '".$_GET['id']."'"); } echo $_POST['bUpdate']; Form Portion: Code: [Select] <tr onmouseover="color(this, '#baecff');" onmouseout="uncolor(this);"> <td width="310" colspan="2" align="center"><span class="fontoptions">Postcard Status </span><br /> <? if ($data['b'] == 1){ echo '<select name="bUpdate"><option value="1" selected>Yes</option><option value="0">No</option></select>'; } else { echo '<select name="bUpdate"><option value="1">Yes</option><option value="0" selected>No</option></select>'; } ?> </td> </tr> base64_encode is a perfect standard php encoding, but this produces = most of times. Is there an alternative making the encode by alphanumeric only? I've used this before and it worked fine but the mt_rand is not working properly. It keeps producing the same number. I've tested it on with the $_GET to the next page and it produces a unique code but it doesn't want to insert that number into the table, just the other same, repetitive number. $transaction_id = mt_rand() . mt_rand(); $item_email = mysql_real_escape_string($_POST[email]); $item_first_name = mysql_real_escape_string($_POST[first_name]); $item_last_name = mysql_real_escape_string($_POST[last_name]); $item_street = mysql_real_escape_string($_POST[street]); $item_street2 = mysql_real_escape_string($_POST[street_2]); $item_city = mysql_real_escape_string($_POST[city]); $item_state = mysql_real_escape_string($_POST[state]); $item_zip_code = mysql_real_escape_string($_POST[zip_code]); $item_country = mysql_real_escape_string($_POST[country]); $username = $_SESSION['username']; $item_id = $_GET['id']; $item_title = mysql_real_escape_string($_POST[title]); $item_price = mysql_real_escape_string($_POST[price]); $item_shipping_cost = mysql_real_escape_string($_POST[shipping_cost]); $item_in_shipping = mysql_real_escape_string($_POST[in_shipping]); $okay = TRUE; if ($item_country == 'United States'){ $shipping = "$item_shipping_cost"; } else { $shipping = "$item_in_shipping - <span class=\"submissionfont\">International Rate</span>"; } $sql="INSERT INTO buyer (username, email, first_name, last_name, street, street_2, city, state, zip_code, country, transaction_id, date) VALUES ('$username', '$item_email', '$item_first_name', '$item_last_name', '$item_street', '$item_street2', '$item_city', '$item_state', '$item_zip_code', '$item_country', '$transaction_id', CURDATE())"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } $sql2="UPDATE product SET transaction_id='$transaction_id', sold='1', sold_date=CURDATE() WHERE id = '$item_id'"; if (!mysql_query($sql2)) { die('Error: ' . mysql_error()); } I am trying to join two tables but I am producing no results. I'm convinced that I have entered everything correctly, but clearly I haven't? Can anyone spot my mistake?
<?php
require 'core/memberinit.php';
$member = new Member();
include 'timeago.php';
$memberid = $member->data() ->id;
if(isset($_GET['q'])) {
$q = html_entity_decode($_GET['q']);
$query2 = DB::getInstance()->query("SELECT c.id c.time as time, c.message as message, c.removed1, c.removed2,
m1.member_first_name as firstname1, m1.member_last_name as lastname1, m1.username as username1,
m2.member_first_name as firstname2, m2.member_last_name as lastname2, m2.username as username2
FROM conversation c
LEFT JOIN members m1 ON c.member1=m1.id
LEFT JOIN members m2 ON c.member2=m2.id
WHERE (c.id=$q OR c.originalid=$q)
AND ((c.member1=$memberid AND c.removed1='No')
OR (c.member2=$memberid AND c.removed2='No'))
ORDER BY c.id");
foreach ($query2->results() as $result2)
{
echo $result2->firstname1;
echo $result2->lastname1;
echo $result2->username1;
echo timeAgo(strtotime($result2->time));
echo $result2->message;
echo $result2->firstname2;
echo $result2->lastname2;
echo $result2->username2;
}
?>
Edited by MartynLearnsPHP, 23 November 2014 - 12:55 PM. |
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