PHP - Replace Return Value

what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video
after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/

to do this i know that i need something like this to get the URL of the video
http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+)
but how to only return just the URL is something idk how to do

then use str_replace http://www.youtube.com/(?:v|cp)/" with  http://i2.ytimg.com/vi/

so in the end im asking if anyone know how to remove all other codes i dont want  and only keep the URL


this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol

The situation is that I have a large string with some identifiers to say "replace me" with something else. My goal is to replace the values, but if one replacement includes one of the other keys, I don't want to replace it.   For example:

<?php
$str = 'some blob ~abc~ followed by ~def~';

$arr_orig = array(
	'~abc~',
	'~def~'
);

$arr_new  = array(
	'value~def~',
	'blah'
);

echo str_replace( $arr_orig, $arr_new, $str );
?>

This will echo: some blob valueblah followed by blah   But that's not what I'm trying to accomplish. Basically, I want ~abc~ to be replaced with the literal: value~def~ and for the ~def~ that happens to be part of that string to NOT be replaced. I hope what I'm asking is clear. Basically, preg_replace/str_replace with arrays seems no different than just doing a FOR loop and replacing ~abc~ and then ~def~. But that's not what I need.   I'm hoping that if ~abc~ is replaced with text that happens to be another identifier -- ~def~, ~xyz~, whatever -- that this already replaced text is not again replaced. Is there a built-in function to do something like this? If not, should I just parse the whole string and count characters or something? Seems like a pain (and slow!)

Hi
i wrote a find and replace code but my code replace last value of array and skip the first, second.... values in the array.
Please give me an idea because i stack with this code.

Regards


$KeyWord  = explode("\n", $RowGetWords['KEYWORDS']);
$Replace  = explode("\n", $RowGetWords['ReplaceTo']);

for($i=0; $i<count($KeyWord); $i++){
$pattern = $KeyWord[$i];
$replace = "<a href=\"" .$URL. "\" target=\"_blank\" >" .$Replace[$i]. "</a>";
$html = str_replace($pattern, $replace, $Row['MessageBody']);
}

I retrieve urls that have the following path
$url=http://cdn.test1.com
$url=http://cdn.test2.com and so on...
i want to to do a string replace such that it displays http://test.com,http://test2.com and son without the cdn part.
Will the following work for all cases?
Code: [Select]
$url=str_replace("cdn.","",$url);

Hello:

I have a quick question.

I am currently using the following code to replace an apostrophe and quote marks when inserting and updating a database record:
Code: [Select]
$myPageContent = mysql_real_escape_string(str_replace("'", "&#39;", $_POST['myPageContent']));
$myPageContent = mysql_real_escape_string(str_replace("", "&#34;", $_POST['myPageContent']));

My question is - how can I modify it so I only need to use one line.
Like (but this does not work):
Code: [Select]
$myPageContent = mysql_real_escape_string(str_replace("'", "&#39;", "", "&#34;", $_POST['myPageContent']));

It seems to me that the way I am currently doing it might be POSTing the data twice?

Thanks!