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PHP - Code In Textfield Caesarcode
Hello everyone,
We have written a code to make a translator of the Caesarcode. But we don't know how we put the code working on the textfield. We tried by ourselves but it doesn't work. So we are asking where and which code we have to put in to the html textfield. This is our code: <?php class CaesarCode { private static $alfabetUpper; private static $alfabetLower; private $steps; private function _getNewPosition($originalPosition) { return ($originalPosition + $this->steps) % 26; } private function _getCharFromArray($char, $fromArray) { if (($charKey = array_search($char, $fromArray)) !== false) { return $fromArray[$this->_getNewPosition($charKey)]; } return false; } private function _translateChar($char) { $translatedChar = $this->_getCharFromArray($char, $this->_getAlfabetUpper()); if ($translatedChar === false) { $translatedChar = $this->_getCharFromArray($char, $this->_getAlfabetLower()); } return $translatedChar; } private function _getAlfabetUpper() { if (empty(self::$alfabetUpper)) { self::$alfabetUpper = range('A', 'Z'); } return self::$alfabetUpper; } private function _getAlfabetLower() { if (empty(self::$alfabetLower)) { self::$alfabetLower = range('a', 'z'); } return self::$alfabetLower; } public function __construct($steps) { $this->steps = $steps; } public function translate($string) { $encr = ''; foreach (str_split($string) as $key => $char) { if (($newChar = $this->_translateChar($char)) !== false) $char = $newChar; $encr .= $char; } return $encr; } } ?> And this is the html code: <?php // de class CaesarCode beschikbaar maken in dit bestand include 'caesarcodephp.php'; $caesarCode = new CaesarCode( 1 ); // de uitkomst opslaan in de variabele $result $result = $caesarCode->translate( 'ABC' ); ?> <!doctype html> <html> <head> <title>oefen</title> </head> <body> <table border="1"> <tr> <tr><td>Rotation:</td> <td> <select> <option value ="1"><?php $caesarCode= new CaesarCode( 1 ); ?> 1 </option> <option value ="2"><?php $caesarCode= new CaesarCode( 2 ); ?>2 </option> <option value ="3"><?php $caesarCode= new CaesarCode( 3 ); ?>3</option> <option value ="4"><?php $caesarCode= new CaesarCode( 4 ); ?>4</option> <option value ="5">5</option> <option value ="6">6</option> <option value ="7">7</option> <option value ="8">8</option> <option value ="9">9</option> <option value ="10">10</option> </select> </tr> <tr> <textarea rows="10" cols="20" style="overflow:hidden;"> <?php echo $caesarCode->translate( 'XYZ' ); ?> INPUT TEXT?? </textarea> <p style="font-size:10px;"></p> <textarea rows="10" cols="20" style="overflow:hidden;"> Output text</textarea> <p style="font-size:10px;"></p> </tr> <tr> <td>Result</td> <td><?php echo $result ?></td> </tr> </table> </body> </html> Thank you very much! Similar TutorialsI hope this is a fairly quick one, I've got a form I'm building where i may well have some special characters being inserted (accents mostly) now normally i would just pop in an HTML editor (TinyMCE) and let that deal with it. But i am looking to export this data as a CSV for use in excel, which means i can't afford to have HTML tags within the output. I am sure someone will have come across this before any suggestions? many thanks Matt how do i limit this textfield to three strings? Code: [Select] <input type='text' size='40' name='search' style='font-size:16px; font-family:Arial;font-weight:bold;' /> is this php or javascript? i want only three strings to be allowed entered. I am looking for some info on creating a textfield /dropdown menu that works just like a standard browser: when you type in something in the textfield/dropdown it should show results (this is needed to quickly find a member) eg. I type "use" and dropdown should contain members(results) starting with "use" (user1, user2 ...) Anyone know where I can find info on this? I have a problem with the following code but i really don't see it: I try to populate the city textfield by the zipcode entered on the zipcode textfield function fillcitystate(controlname) { var zipstring = ""; xmlhttp = new XMLHttpRequest(); xmlhttp.open("GET", "postcode.php?postcode=" + controlname.value, true); xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { var zipstring = xmlhttp.responseText; if (zipstring!="Error") { var ziparray = zipstring.split("|"); document.getElementById("test").innerHTML = ziparray[1]; } } } xmlhttp.send(null); } In postcode.php $returnval = "Error"; $postcode = $_GET['postcode']; $query = "SELECT * FROM city WHERE code='$postcode'"; $resultval = mysql_query($query); $rowcount = mysql_num_rows($resultval); if ($rowcount==1) { $row = mysql_fetch_array($resultval); $returnval = $row['code']."|".ucwords(strtolower($row['name']))."|".$row['province']; } else { } echo $returnval; When entering a zipcode, nothing happened so i decided to just echo the name of the city using the innerHTML. Still nothing happened, so i commented out all the php in my postcode.php and decided to just do: $postcode = $_GET['postcode']; echo $postcode; then it printed out: 'undefined' Can somebody point me out? Hey again guys! I'm back already today. XD Okay, so... I'm building a script, right. I have a form that is a simple text field. I do NOT want to use javascript. I want to be able to use PHP to be able to do this. Here is the form exactly as it is now: Code: [Select] <form action="<?php echo "$PHP_SELF"; ?>" method="POST"> <input type="text" name="price"> How would I only allow a number, and up to 5 digits long, like, for example, a zip code. I know I can always limit the char space, but they might be able to "inject" it? On another note for forms, what would I have to do to get rid of people being able to run a script through a form; is it the strip_tags(); function? Thanks for your help in advance guys! Hello, I want to create an order form where people can order shirts with sizes and quantities. So in 1 form you have a column where people can check the size and after that the quantities. (see below the form) As result i want after pressing submit and selecting for example 3 shirts Large and 1 small: S=1, M=0, L=3, XL=0, XXL=0 Code: [Select] echo "<form method=\"post\" action=".$PHP_SELF."> <label>aantal <input name=\"textfield[]\" type=\"text\" size=\"4\" maxlength=\"3\"> <input class=\"option2\" id=\"option2\" name=\"maat[]\" type=\"checkbox\" value=\"S\">S<br /> <input name=\"textfield[]\" type=\"text\" size=\"4\" maxlength=\"3\"> <input class=\"option2\" id=\"option2\" name=\"maat[]\" type=\"checkbox\" value=\"m\">m<br /> <input name=\"textfield[]\" type=\"text\" size=\"4\" maxlength=\"3\"> <input class=\"option2\" id=\"option2\" name=\"maat[]\" type=\"checkbox\" value=\"l\">l<br /> <input name=\"textfield[]\" type=\"text\" size=\"4\" maxlength=\"3\"> <input class=\"option2\" id=\"option2\" name=\"maat[]\" type=\"checkbox\" value=\"XL\">XL<br /> <input name=\"textfield[]\" type=\"text\" size=\"4\" maxlength=\"3\"> <input class=\"option2\" id=\"option2\" name=\"maat[]\" type=\"checkbox\" value=\"XXL\">XXL<br /> </label> <input type=submit value=Select></form>"; i hope you can help me with it. thanks in regard! Hello, I'm writing a PHP program in which textfields are printed (in a loop) into an HTML table. On a button click, another column is added to the table, and another textfield added. The problem is that when a new textfield is printed, it is slightly above the height of the other textfields (see attached picture if unclear). The code for this is below: Code: [Select] <table border = '1' cellspacing = '4' style = "color: white"> <?php include "connectToDatabase.php"; //Initial script call to generate table from database ?> </table> //Code in connectToDatabase.php... $query = mysql_query("SELECT * FROM colin_table"); while($row = mysql_fetch_array($query)){ //$row represents each row in an array for($i = 0; $i < $limit; $i++){ //Print every element in the array if($row[$i] == null) echo "<td align = 'center'><input type = 'text' style = 'text-align: center; vertical-align: middle' align = 'center'>"; else echo "<td align = 'center'>" . $row[$i]; } echo "<td align = 'center'>"; echo "<tr align = 'center'>"; //Then move to the next row } //Loop that prints text boxes for every column in the HTML table $textBoxQuery = mysql_query("SELECT * FROM allColumnFields"); while($row = mysql_fetch_array($textBoxQuery)){ echo <<<END <td align = 'center'> <input type = 'text' style="margin-left:auto; text-align:center; vertical-align: middle; margin-right:auto;" name = "rowField"/> END; //THIS IS THE PART THAT NEEDS WORK. FOR SOME REASON NEW TEXTBOX IS HIGHER THAN THE OTHER BOXES } It's more of an aesthetic problem, but it's nonetheless something I'd like to get fixed. Any ideas? Jake I have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this? <?php include ("includes/includes.php"); $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo "<p class='postnote'>" . $post->post . "</p"; echo "<span class='footer'>Posted By: " . $post->author . "</span>"; echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>"; echo "<span class='footer'>Tags: " . $post->tags . "</span>"; echo ' <div class="addthis_toolbox addthis_default_style "> <a class="addthis_button_facebook_like" fb:like:layout="button_count"></a> <a class="addthis_button_tweet"></a> <a class="addthis_counter addthis_pill_style"></a> </div> <script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script> <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>'; echo "</div>"; } ?> Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code. $sql="select * from Profile where username = '$username'; $result = mysql_query( $sql, $conn ) or die( "ERR: SQL 1" ); if(mysql_num_rows($result)!=0) { process form } else { echo "That username already exist!"; } the current code of the form <?PHP //session_start(); require_once "formvalidator.php"; $show_form=true; if (!isset($_POST['Submit'])) { $human_number1 = rand(1, 12); $human_number2 = rand(1, 38); $human_answer = $human_number1 + $human_number2; $_SESSION['check_answer'] = $human_answer; } if(isset($_POST['Submit'])) { if (!isset($_SESSION['check_answer'])) { echo "<p>Error: Answer session not set</p>"; } if($_POST['math'] != $_SESSION['check_answer']) { echo "<p>You did not pass the human check.</p>"; exit(); } $validator = new FormValidator(); $validator->addValidation("FirstName","req","Please fill in FirstName"); $validator->addValidation("LastName","req","Please fill in LastName"); $validator->addValidation("UserName","req","Please fill in UserName"); $validator->addValidation("Password","req","Please fill in a Password"); $validator->addValidation("Password2","req","Please re-enter your password"); $validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!"); $validator->addValidation("email","email","The input for Email should be a valid email value"); $validator->addValidation("email","req","Please fill in Email"); $validator->addValidation("Zip","req","Please fill in your Zip Code"); $validator->addValidation("Security","req","Please fill in your Security Question"); $validator->addValidation("Security2","req","Please fill in your Security Answer"); if($validator->ValidateForm()) { $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error()); mysql_select_db("beatthis_beatthis") or die(mysql_error()); $FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file $LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file $UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file $Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file $Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file $email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file $Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file $Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file $Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file $Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file $sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; //echo $sql; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } else{ mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body); echo "<h3>Your profile information has been submitted successfully.</h3>"; } mysql_close($con); $show_form=false; } else { echo "<h3 class='ErrorTitle'>Validation Errors:</h3>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<p class='errors'>$inpname : $inp_err</p>\n"; } } } if(true == $show_form) { ?> Advance thank you. Can you help please. The error..... Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24 code. Code: [Select] <?php //database connection. $DB = mysql_connect("localhost","root") or die(mysql_error()); if($DB){ //database name. $DB_NAME="mysql"; //select database and name. $CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name"); // if connection. }if($CON){ //show tables. $mysql_show="SHOW TABLES"; //select show and show. $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())"; } //if allowed to show. if($mysql_select2){ //while it and while($data=mysql_fetch_assoc($mysql_select2)){ //show it. echo $data; } } ?> hey gurus, i am a newbie php coder.. i am learning by example. what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage) ---------------------------------------------------------------- the table structure that will be used is as follows: user.bonus_credit user.ID bonus_credit.bonusCode bonus_credit.qty bonus_credit.value bonus_credit_usage.bonusCode bonus_credit_usage.usedBy ---------------------------------------------------------------- so lets say, in bonus_credit i have the following bonusCode = 'facebook' (this is the code they have to type to redeem the bonus qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once) value = '5' (this is the amount of bonus_credit for each qty) Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit ----------------------- i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code. if(isset($_REQUEST['btnBonus'])) { $bonus_credit = addslashes($_REQUEST['bonusCode']); $query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'"; echo "<script>window.location='myreferrals.php?msgs=2';</script>"; mysql_query($query) or die(mysql_error()); } Hi, Look at this code below: Code: [Select] <?php function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ""; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n"; $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = round($markTotal / $weightSession * 100); if ($markGrade >= 70) { $grade = "A"; } else if ($markGrade >= 60 && $markGrade <= 69) { $grade = "B"; } else if ($markGrade >= 50 && $markGrade <= 59) { $grade = "C"; } else if ($markGrade >= 40 && $markGrade <= 49) { $grade = "D"; } else if ($markGrade >= 30 && $markGrade <= 39) { $grade = "E"; } else if ($markGrade >= 0 && $markGrade <= 29) { $grade = "F"; } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n"; return $moduleHTML . $sessionsHTML; } $output = ""; $studentId = false; $courseId = false; $moduleId = false; while ($row = mysql_fetch_array($result)) { if($studentId != $row['StudentUsername']) { //Student has changed $studentId = $row['StudentUsername']; $output .= "<p><strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']})\n"; } if($courseId != $row['CourseId']) { //Course has changed $courseId = $row['CourseId']; $output .= "<br><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Course Mark</strong> <strong>Grade</strong> <br><strong>Year:</strong> {$row['Year']} </p>\n"; } if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } //Get output for last module $output .= outputModule($moduleId, $moduleName, $sessionsAry); //Display the output echo $output; } } } ?> This code allallows me to make calculations and display a student's course and linked with it the course the modules in the course and linked with modules are all the sessions. It is able to display what marks each student have got for each module and session. Now look at code below, it is able to display modules and in those modules the sessions that link to those modules: Code: [Select] <?php if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } What I want to know is how can I do something similar for course so that it picks out the right modules depending on the course it displays. There maybe some code that needs to be added in the function. Can you help me integrate this code :
<form method="post" action="submit.php"> <input type="checkbox" class="required" /> Click to check <br /> <input disabled="disabled" type='submit' id="submitBtn" value="Submit"> </form>In to this Contact Form code, please? <form action="../page.php?page=1" method="post" name="contact_us" onSubmit="return capCheck(this);"> <table cellpadding="5" width="100%"> <tr> <td width="10" class="required_field">*</td> <td width="80">Your Name</td> <td><input type="text" name="name" maxlength="40" style="width:400px;/></td> </tr> <tr> <td class="required_field">*</td> <td>Email Address</td> <td><input type="text" name="email" maxlength="40" style="width:400px;/></td> </tr> <tr> <td></td> <td>Comments:</td> <td><textarea name="comments" style="width: 400px; height: 250px;"></textarea></td> </tr> </table> </form I use this type of a code to send automatic emails from my website: Code: [Select] $headers = ; $headers .= ; $to = ; Click here to go to Google. ", $headers); I am having hard time figuring out how to do hyperlink on words (like here). If I do something like this: Code: [Select] <a href='http://www.google.com'>here</a> it spits out that exact thing out. Thanks you for your input Can I combine also HTML code in PHP function? For example, can a PHP function include HTML form and the PHP code to handle this form? If yes, this will make my main code much more smaller and readable. If not, is there a way to define an "external macro" like, which allow me to replace pre-defined lines of code with short alias? Hello Everyone I am new to php and indeed Web Development. After testing and Playing a bit, I can get the following code to work as two files, the form calling the *.php file to insert into the database, however, I am trying to create one html/php file that displays the form and then executes the php code to insert into the database once user clickes the button. Please can you assist me with the code? I have something horribly wrong and I cannot find it. Code: [Select] <?php> <html> <head> <title>Personal Details</title> </head> <body> <form method="post" action="contactdetails.html"><font face="Arial"> Call Sign:<br> <input name="callsign" size="5" type="text"><br> Surame:<br> <input name="surname" size="30" type="text"><br> First Name:<br> <input name="firstnames" size="30" type="text"><br> Known as:<br> <input name="knownas" size="30" type="text"><br> RSA ID No.:<br> <input name="rsaid" size="13" type="text"><br> Birth Date:<br> <input name="birthdate" size="12" type="text"><br> <input name="Insert" value="Next" type="submit"></form> </font><br> </body> </html> //php to insert data into table $callsign = $_POST['callsign']; $surname = $_POST['surname']; $firstnames = $_POST['firstnames']; $knownas = $_POST['knownas']; $rsaid = $_POST['rsaid']; $birthdate = $_POST['birthdate']; mysql_connect ("localhost", "jredpixm_testuse", "PHPDevelopment") or die ('I cannot connect to the database because: ' .mysql_error()); mysql_select_db ("jredpixm_test"); $query="INSERT INTO personal_details (callsign, surname, firstnames, knownas, rsaid, birthdate)Values ('$callsign', '$surname', '$firstnames', '$knownas', '$rsaid', '$birthdate')"; mysql_query($query) or die ('Error updating Database'); echo "<p>Thanks, your information has been added to the database.</p>"; ?> Regards Allen Alright so I'm attempting to save config data via php. Bellow is the code I currently have, however I'm afraid that when I "flip the switch" and use it that it will error out because of the <?php and ?> tags inside of it... Ideas, suggestions? $config = '../includes/config.php'; $fh = fopen($config, 'w'); $data = ' <?php $dbhost = "'.$database_host.'"; $dbuser = "'.$database_username.'"; $dbpass = "'.$database_password.'"; $dbname = "'.$database_name.'"; $key = "'.$site_key.'"; $cron_key = "'.$database_cron_key.'"; ?> '; fwrite($fh, $data); fclose($fh); Hi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Michael Feathers coined the term Legacy Code as being code without automated tests.
Still however Legacy Code evokes a vision in me that it is code that is ugly, old, runs on mainframes, and is probably 3000 lines long, uses globals and questionable code practices.
But say we take this ugly nasty code, and put it very nicely under test, but without doing any refactoring, other than that necessary to be able to put it under test in the first place.
Now that code is under test. But it it still ugly. How would you call ugly code under test?
Would you make a differentiation between old & ugly and modern & pretty code if both are under test?
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