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PHP - Need To Avoid Redirect To Webhost Homepage
Hello, I never really gave a serious thought to the above question until now that I'm trying to actually launch a live site. Well I'm sure most of you are familiar with this situation, where a user my enter a wrong, non existent url, whose root happens to be your domain name. For example, instead of entering domain.com/greetings, the user may wrongly type domain.com/grewtings . How can I make my site to redirect such erroneous urls to my homepage, instead of to my webhost's homepage with an error message?
Appreciate all answers. Similar TutorialsThis topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=357107.0 Ok first of all i have this code at the final of my insert and update code.
if (!mysql_query($sql,$conn))
{
die('Error: ' . mysql_error($conn));
}
else{
header("Location: finalmsj.php?finalmsj=".$hiwu."");
}
mysql_close($conn);
}
Do any of you know how to override the php.ini file on a webhost to allow uploads using php to be set for 2gig mx file size? .htaccess is not working and my host says it supports changing the php.ini but nothing seems to be working. Hi all, I have the following code to check whether the client has javascript enabled in their browser: page.php: Code: [Select] <?php session_start(); if(isset($_SESSION['gocheck'])) {$gocheck = $_SESSION['gocheck'];} else {$gocheck = 'no';} //echo $gocheck; if($gocheck=='no'){header ("Location: ./gocheck.php"); exit;} //----Execution only reaches this line if gocheck.php has been run and Javascript is enabled.-------- unset($_SESSION['gocheck']); //rest of page ?> gocheck.php: Code: [Select] <?php session_start(); $_SESSION['gocheck'] = 'yes'; echo" <!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\"> <html xmlns=\"http://www.w3.org/1999/xhtml\" xml:lang=\"en\" lang=\"en\"> <head> <script type=\"text/javascript\" language=\"JavaScript\"> window.location.replace('page.php'); </script> </head> <body> This website requires Javascript to be enabled in your browser. <br /> Please enable Javascript and try again. </body> </html> "; ?> So what should happen is the user is always redirected from page.php to gocheck.php, which sets the session variable $gocheck to 'yes' and directs back to page.php via Javascript. Because $gocheck is then equal to 'yes', page.php shouldn't direct back again tio gocheck.php. This worked fine on my PC (using WAMP), but when I upload the files to the webhost, it seems to get stuck in an infinite redirect loop between page.php and gocheck.php. Also, if I echo $gocheck in page.php, it returns 'no', so it seems as if for some reason the session variable $gocheck is not being set properly by gocheck.php. Could somebody please shed some light on this? Is there an error in my code? Is there something I need to change in php.ini on the webhost's server? Thanks! P.S. WAMP on my PC uses PHP v.5.3.0, but the webhost uses PHP v.5.2.12 - don't think this can be the problem though. Is there a reason why on my local machine with php, my login system works, but then when I upload my files and test it on my web host, the login system doesn't work properly. I'm using the same php version on my local machine and on my webhost, so I don't understand why it wouldn't work the same. When I try logging in on my webhost, everything processes as normal when a correct user/pass combo is found in the database, however, my session just doesn't seem to be saved, and therefore I won't be logged in. It'll end up refreshing to the home page (as I have it setup), but it won't show me as logged in. Is there something special I need to do in order for the session to be stored correctly? (I realize I haven't pasted any code, but I'm not sure exactly how much code would be needed for me to show in order to resolve the issue). Hi, I have these variables for pages I navigate to because I pass them in the query string. However, I need a variable for the homepage (index.php), before any query string is created. I cant declare a vari $_GET['intro'] ; $_GET['about'] ; $_GET['contact'] ; However, I need a variable for the homepage (index.php), before any query string is created. I cant declare a variable in index.php because it will be used throughout the entire website. I also cant declare the variable in home.php (the bulk content of the homepage) because I need to use the variable before home.php is included. Is their a trick for this? Thanks! Hello everyone, i have this page in my website called "index.php": <?php include("include/open_conn.php");?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>name site</title> </head> <body> <div id="container"> <?php include("include/header.php");?> <?php include("include/content.php");?> <?php include("include/footer.php");?> </div> </body> </html> <?php include("include/close_conn.php");?> The content change dinamically with this code "content.php": $pages_dir = 'pages'; if (!empty($_GET['menu'])) { $pages = scandir($pages_dir, 0); unset($pages[0], $pages[1]); $menu = $_GET['menu']; if (in_array($menu.'.php', $pages)) { include($pages_dir.'/'.$menu.'.php'); } So, when i change the page the url will be " index.php?menu=nameofmypage ". But now i want to put an image only in my index.php page, a sort of welcome to the users, but with this codes the image will appear in all the other page because i change only the content. I know that i could create a page named "home.php" and do all i want, but i want to change the first page that the user see when he types the address of my website. thank you! This topic has been moved to Website Critique. http://www.phpfreaks.com/forums/index.php?topic=346717.0 I have a sorting functionality, the code is he <?php $select_category = $_REQUEST['sort_category']; $sort_date_var = $_REQUEST['sort_date']; $sort_submit = $_POST['sortSubmit']; // Connect to the database $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); if (($select_category == 'All') || (!isset($select_category)) && (!isset($sort_date_var))) { // Retrieve the chosen category from MySQL $query = "SELECT * FROM con"; $data = mysqli_query($dbc, $query); //Loop through the array of data while ($row = mysqli_fetch_array($data)) { echo "<table class='knuffixTable'>"; // Display the score data echo "<tr><td class='knuffix_name'>"; echo "<strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "<tr><td class='knuffix_categoryDate'>" . $row['category'] . " | " . date('M d, Y', strtotime($row['contributed_date'])) . " </td></tr>"; echo "</table>"; } mysqli_close($dbc); } elseif (isset($select_category) && !isset($sort_date_var)) { // Retrieve the chosen category from MySQL $query = "SELECT * FROM con WHERE category = '$select_category'"; $data = mysqli_query($dbc, $query) or die (mysqli_error($dbc)); //Loop through the array of data while ($row = mysqli_fetch_array($data)) { echo "<table class='knuffixTable'>"; // Display the score data echo "<tr><td class='knuffix_name'>"; echo "<strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "<tr><td class='knuffix_categoryDate'>" . htmlentities($row['category']) . " | " . date('M d, Y', strtotime($row['contributed_date'])) . " </td></tr>"; echo "</table>"; } mysqli_close($dbc); } elseif (!isset($select_category) && isset($sort_date_var)) { // Retrieve the chosen category from MySQL $query = "SELECT * FROM con ORDER BY contributed_date $sort_date_var"; $data = mysqli_query($dbc, $query) or die (mysqli_error($dbc)); //Loop through the array of data while ($row = mysqli_fetch_array($data)) { echo "<table class='knuffixTable'>"; // Display the score data echo "<tr><td class='knuffix_name'>"; echo "<strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "<tr><td class='knuffix_categoryDate'>" . htmlentities($row['category']) . " | " . date('M d, Y', strtotime($row['contributed_date'])) . " </td></tr>"; echo "</table>"; } mysqli_close($dbc); } elseif (isset($select_category) && isset($sort_date_var)) { // Retrieve the chosen category from MySQL $query = "SELECT * FROM con WHERE category = '$select_category' ORDER BY contributed_date $sort_date_var"; $data = mysqli_query($dbc, $query) or die (mysqli_error($dbc)); //Loop through the array of data while ($row = mysqli_fetch_array($data)) { echo "<table class='knuffixTable'>"; // Display the score data echo "<tr><td class='knuffix_name'>"; echo "<strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "<tr><td class='knuffix_categoryDate'>" . htmlentities($row['category']) . " | " . date('M d, Y', strtotime($row['contributed_date'])) . " </td></tr>"; echo "</table>"; } mysqli_close($dbc); } ?> With this code I'm able to: - showcase every category by DEFAULT when someone comes to the page. - sort only by category, - sort only by date, - sort by category AND date, The problem is as you can see I have a lot of duplicate code, if I for example want to change the table that is being printed out, I have to change it on all of them. I'd like to ask how I could avoid this duplicate code. Can I for example just have the table ONE TIME at a separate place and then insert the REFERENCE _after_ the query in each if statement? Like this: if (($select_category == 'All') || (!isset($select_category)) && (!isset($sort_date_var))) { // Retrieve the chosen category from MySQL $query = "SELECT * FROM con"; $data = mysqli_query($dbc, $query); table_here(); } elseif (isset($select_category) && !isset($sort_date_var)) { // Retrieve the chosen category from MySQL $query = "SELECT * FROM con WHERE category = '$select_category'"; $data = mysqli_query($dbc, $query) or die (mysqli_error($dbc)); table_here(); } I'm just coding since 2 month so I don't know how do it, maybe I can do it with functions? I've tried doing it with functions, but I got an error since the function doesn't contain any query statement and only the table because it was trying to fetch. it looked like this: function table_here () { //Loop through the array of data while ($row = mysqli_fetch_array($data)) { echo "<table class='knuffixTable'>"; // Display the score data echo "<tr><td class='knuffix_name'>"; echo "<strong>" . htmlentities($row['name']) . "</strong><br /></td></tr>"; echo "<tr><td class='knuffix_contribution'><pre>" . $row['contribution'] . "</pre><br /></td></tr>"; echo "<tr><td class='knuffix_categoryDate'>" . $row['category'] . " | " . date('M d, Y', strtotime($row['contributed_date'])) . " </td></tr>"; echo "</table>"; } mysqli_close($dbc); } I'm learning functions and I'm working on a rating script. This is a small test script that works, you can try it out yourself: <?php // Rating System function while_test (){ $a = 1; $b = 4; $t_id = 1; global $likes; global $dislikes; global $con_id; while ($a++ <= $b){ echo "<center>"; echo "<table><tr><td>Table: </td></tr>"; echo "<tr><td>This is a table test </td></tr>"; echo "<tr><td><form action='' method='post'>"; echo "<button type='submit' name='likes' value='Y'>likes</button>"; echo "<button type='submit' name='dislikes' value='N'>dislikes</button>"; echo "<input type='hidden' name='hidden_id' value='" . $t_id . "' /></form></td></tr></table>"; echo "</center><br /><br />"; $t_id++; $likes = $_POST['likes']; $dislikes = $_POST['dislikes']; $con_id = $_POST['hidden_id']; } } while_test(); if ($likes) { echo "likes it: " . $likes . " con_id: " . $con_id; } elseif ($dislikes) { echo "dislikes it: " . $dislikes . " con_id: " . $con_id; } ?> I've gotten recommended before not use globals, because the projects would become unmanageable, and I'm wondering how would I be able to avoid using globals in this example? I'm able to in-ject variables through the parenthesis, but I'm not able to out-ject variables, if that makes sense. (?) At least it doesn't work for me. How would I use those three variables $likes, $dislikes and $con_id outside the function without setting them as globals, what would be good practice? Array ( [0] => Virender Sehwag|||http://abc.xyz.com/Virender-Sehwag [1] => Sachin Tendulkar|||http://abc.xyz.com/Sachin-Tendulkar ) foreach($array as $arr) { $topics=explode ('|||', $array); echo '<li>' .'<a rel="nofollow" target="_new" href="'.$topics[1].'"><span class="title">'.html_entity_decode($topics[0], ENT_NOQUOTES, "UTF-8").'</span></a>|</li>'; How to avoid '|' for the last element of any aaray. Also if array contains only 1 element '|' should not appear. For eample, In the browser it should display as "Virender Sehwag | Sachin Tendulkar". If the array contains only 1 element then, In the browser it should display as Virender Sehwag if array contains 3 elements, Virender Sehwag | Sachin Tendulkar | someword I'm just looking for some tips here. I am developing and selling an eccommerce shopping cart software package, and it has been received very well from the early adopters. There's just one small problem that prevents the software from being a truly out-of-the-box solution: the include path. Not all users have access to their php.ini file, and it's not always a php.ini file anyway. So this is something the installation is unable to set for the customer. I'm using object-oriented PHP5 stuff, so I have a folder named "classes" with all the relevant stuff in there. I am unable to search for paths to the folder and hard-code those into source files (there are ajax calls and other fun stuff; hard to know the exact relation to the path). I guess I could use set_include_path on the top of a bunch of files, but that is a small performance hit (and totally inelegant code). I could put the folder path in the database somewhere and query for it (and cache it so it's not a performance hit). None of this stuff seems good. The path seems like the best solution. Unless you have better ideas.... 1 - I am using phpmailer to send an email to a people without defining the $headers = 'From:" , so the From section of the email is showing default server aekcom@xenon.sfdns.net , the email didn't go to Junk box, I am so happy. 2 - Then I apply $headers .= 'From: Pflik <admin@pflik.com>'; on the php mailer now. The email go to Junk box now. I am sad. My question : How do I change the default email server of my hosting aekcom@xenon.sfdns.net into admin@pflik.com ? If I can change it, then the email won't go to junk box anymore. Hello Everyone, I m making an attendance application. I have an issue with following code, Code: [Select] <?php session_start(); require_once("conf.php"); mysql_select_db('site'); $subjects=$_GET['sublen']; $username=$_SESSION['user']; for($i=1;$i<=$subjects;$i++) { $subject=$_GET[',Sub'.$i]; $query="INSERT INTO Subjects(id,Subjects,User,Classs) VALUES($i,'$subject','$username','F.Y.B.Sc')"; $true=mysql_query($query) or die("Cannot Store subjects".mysql_error()); } ?> <html> <head> <link href="../css/style.css" type="text/css" rel="stylesheet" /> <script type="text/javascript" src="../js/jquery.js"></script> </head> <body> <div id="main"> <div id="logo"> KiMi... </div> <div id="header"> <ul> <li><a href="index.html">Home</a></li> <li><a href="php/subjectsTable.php">Create Subjects</a></li> <li><a href="html/form.html">Contact Us</a></li> <li><a href="html/register.php">Register!</a></li> </ul> </div> <div id="nav"> </div> <div id="content"> <?php if($true) { echo "<div id='dynamicDiv'>"; echo "<div> Subjects stored Successfully!</div></br></br>"; $query="SELECT * FROM Subjects Where User='$username'"; $result=mysql_query($query) or die("Cannot Fetch Data"); echo "<table id='table'>"; echo "<tr><td> </td><td>Subjects</td><td>Class</td></tr>"; while($row=mysql_fetch_array($result)) { echo "<tr><td><input type='checkbox' name='box[]'/> </td>"; echo "<td>"; echo $row['Subjects']; echo "</td>"; echo "<td>"; echo $row['Classs']; echo "</td>"; echo "</tr>"; } echo "</table>"; echo "</div>"; } ?> </div> <div id="footer"> © Copyright Amit K. Goda 2011-2012 </div> </div> </body> </html> In the above code i m storing data into database which has been passed into $_GET array. The Code is this Quote <?php session_start(); require_once("conf.php"); mysql_select_db('site'); $subjects=$_GET['sublen']; $username=$_SESSION['user']; for($i=1;$i<=$subjects;$i++) { $subject=$_GET[',Sub'.$i]; $query="INSERT INTO Subjects(id,Subjects,User,Classs) VALUES($i,'$subject','$username','F.Y.B.Sc')"; $true=mysql_query($query) or die("Cannot Store subjects".mysql_error()); } ?> the data is stored but the issue is, since i have data coming in $_GET array when i reload my page the same data is stored again inmy database. So any suggesstions how can i avoid that??? Any Help will be highly appreciated Trying to make my code more secure. This is what I currently have, which is not secure by any means: Code: [Select] $query1 = "SELECT COLUMN_NAME, DATA_TYPE, ORDINAL_POSITION, COLUMN_DEFAULT, CHARACTER_MAXIMUM_LENGTH, IS_NULLABLE FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='$table'"; // Run PRO query $qresult1 = sqlsrv_query($dbPRO, $query1); if ($qresult1 === false) { exitWithSQLError('Retrieving schema failed.'); } This is how I changed it, Code: [Select] $query1 = "SELECT COLUMN_NAME, DATA_TYPE, ORDINAL_POSITION, COLUMN_DEFAULT, CHARACTER_MAXIMUM_LENGTH, IS_NULLABLE FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME=?"; $params = array(1, $table); // Run PRO query $qresult1 = sqlsrv_query($dbPRO, $query1, $params); if ($qresult1 === false) { exitWithSQLError('Retrieving schema failed.'); } but I'm getting this error: Code: [Select] SQL-Status: 22018 Code: 245 Message: [Microsoft][SQL Server Native Client 10.0][SQL Server]Conversion failed when converting the nvarchar value 'sysrscols' to data type int Please notice I am using sqlsrv_query function because my database engine is MS-SQL 2008. That's why I'm a bit confused. Most documentation online is pointed to MySQL. exitWithSQLError is a customized function of mine, so please ignore. Any help or hints is appreciated, Thanks, Hello, I have a form that has a preview, before user can preview the form inputs he must login. If he is logedin, he can see preview and continue to editing form, but after user is finished with editing his values he is redirected to "preview" page for which he must be logged in. But the problem is that variables are "empty" after redirecting back to preview. $_POST['email'] is received from login.php $_SESSION['code'] is 5 digit code generated at start, it isn't important in this issue. Here's the code: preview.php Code: [Select] $id_user= 0; $code = $_SESSION['code']; $email = $_POST['email']; $_SESSION['email_login'] = $email; So now you can see that $email and $_SESSION['email_login'] are empty because when redirecting from "editing" to preview $_POST['email'] can't be found... I Have a protected members section on my site for staff. I would like it so that information specific to that member of staff would appear on their homepage straight after login. Just basic information that is stored on a MySQL database so they can login and check appointments and clients etc for the week etc. is this something that is possible to do in PHP and MySQL? or am I going mad? At the moment I have the entire table on the members homepage and the only way I've figured out to specify a member to only show one users information is to use - (SELECT * FROM Tutors WHERE name = 'XXX'. I don't like this method as it would mean i would have to have a separate files for each member. I was hoping I could do something along the lines of - WHERE name = ' relative to the login name used'. but I am sure I am flogging a dead horse here. So many websites do this kind of thing and I'm surprised after scouring the net for hours and hours that I haven't found any useful information or tutorials on the subject. I am fairly new to programming in PHP and MySQL and am only just getting to grips with the lingo. Maybe I've just been seacrhing the wrong thing, I don't Know. Any help at all would be amazing and much appreciated, a nudge in the right direction would be a start as I'm getting nowhere on my own THANKS Hi guys, first of all, sorry for my bad english I have a question, As title, how can i avoid html tags in a text passed by $_POST method? htmlentities() is one way, i think, but... there's another way to avoid me to use that? I don't like to decode again every text! Edit: is strip_tags(); good for this purpose? Hi, Does anyone know why session variables might disappear after a form submits data to a third party site (salesforce), which then redirects to the ThankYou page on the original site? Both the form page and the thankyou page have session_start(); at the top. It works fine if I process the form locally, but now I'm supposed to have Salesforce's site process the form, but my thankyou page still needs to read the cookies from the form page in order to display some dynamic links in the text. But now when the thankyou page appears, the session variables seem to have been destroyed. The Script:
<h1>Do Add a Message to the MySQL Database</h1>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<textarea name="message"></textarea>
<br/>
<input type="submit" name="submit"/>
</form>
<?php
// The Connection to the Database
// Taken Out
?>
<?php
// To insert the text data into the MySQL database.
if(isset($_POST['submit'])){
$tqs = "INSERT INTO messages (`message`) VALUES ('{$_POST['message']}')";
$tqr = mysqli_query($dbc, $tqs) or die(mysqli_error($dbc));
}
?>
<?php
// To select the text data from the MySQL database.
$tqs = "SELECT * FROM messages";
$tqr = mysqli_query($dbc, $tqs);
// To print out the text data inside of table on the page.
echo "<h1>This Is Where the Messages Gets Printed on Screen</h1>";
echo "<table><tr><td>ID</td><td>The Message</td></tr>";
while($row = mysqli_fetch_assoc($tqr)){
echo "<tr><td>" . $row['id'] . "</td><td>" . $row['message'] . "</td></tr>";
}
echo "</table>";
?>
1. When I have added text with the form to the MySQL database...
2. ... and I have clicked on "page reload" in Firefox to reload the page...
3. ... then the before submitted text gets submitted again to the MySQL database.
So basically, add text with the form to the MySQL database, reload the page in Firefox, and the before added text will get submitted to the MySQL database again.
My Question Is:
What is the proper way to avoid this?
Edited by glassfish, 06 October 2014 - 10:18 AM. |
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