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PHP - Displaying Relevant Data
Similar TutorialsI have an array ( $exifdata ) which contains the relevant bits that I require, read from exif data, as in the var_dump below. array 0 => string 'Caption' (length=7) 1 => string 'Copy' (length=4) 2 => string 'Camera' (length=6) 3 => string 'Shutter' (length=7) 4 => string 'fNo' (length=3) 5 => string 'ISO' (length=3) 6 => string 'Date' (length=4) 7 => string 'Time' (length=4) 'copy' => string 'Alf Thomas' (length=10) 'caption' => string 'Blue Sky over Auld Reekie' (length=25) 'camera' => string 'Canon PowerShot G9' (length=18) 'shutter' => string '1/800' (length=5) 'fNo' => string 'f/5.6' (length=5) 'iso' => int 200 'date' => string '07:10:2011' (length=10) 'time' => string '09:05:26' (length=8 What I am trying to do is echo each key followed by its relevant data, and thought something like this would work:- Code: [Select] foreach( $exifdata as $key => $value){ echo "$key :, $value <br />"; } The output I get from the above is as below:- 0 :, Caption 1 :, Copy 2 :, Camera 3 :, Shutter 4 :, fNo 5 :, ISO 6 :, Date 7 :, Time copy :, Foucquet caption :, Blue Sky over Auld Reekie camera :, Canon PowerShot G9 shutter :, 1/800 fNo :, f/5.6 iso :, 200 date :, 07:10:2011 time :, 09:05:26 Which more or less does what I want except that what I actually would like is this:- Copy - Foucquet Caption - Blue Sky over Auld Reekie Camera - Canon PowerShot G9 Shutter - 1/800 fNo - f/5.6 ISO - 200 Date - 07:10:2011 Time - 09:05:26 What I can't quite understand is why I am getting the two lists as an output, which simply seems to be identical to the output of the var_dump. Hi, I want to be able to generate visitor statistics for a blog I'm creating. I'm going to be collecting numerous pieces of data when a post is viewed, including a time stamp of the visit. I need to be able to select timestamps that were within the current day, the previous day, the day before that ect.. So that I can generate the statistics. Show it for the current week (current day and 6 previous days). So it would be the entries where the timestamp was made on the days: 11/1, 10/1, 9/1, 8/1, 7/1, 6/1, 5/1. For example. Not quite sure how I could do this. Thanks. So what i mean is if i set a variable to "[" ($some_variable = "[") the rest of my code is now going to go CRAZY because there is an open [. Is there a way I can just make everything inside the first set of "" not relevant to the code? thanks! Hello im working on a project which involves marking attendance via an RFID tag and saving the time into an sql file. Everything seems to be working fine and the time stamp is successfully punched into the SQL but something is wrong with the php code thats supposed to display this data. Please if any one can take a look and help.
MY CODE for displaying the data (ViewAttendance.php):
<?php
include_once("header.php");
$attData = array();
$totDays = 0;
if(isset($_REQUEST['submit'])){
$totDays = cal_days_in_month(CAL_GREGORIAN,$_REQUEST['month'],$_REQUEST['year']);
$attData = $commonObj->getAttendanceData($_REQUEST['month'],$_REQUEST['year']);
//print_r($attData);
//print_r(date("d",strtotime($attData[0]['punch_time'])));
}
?>
<div class="container">
<div class="row">
<div class="col-sm-12">
<h4>Showing Attendance</h4>
<form name="showAtt" method="post">
<div class="col-sm-4"><label>Select Month</label>
<select name="month" class="form-control">
<?php for($i=1;$i<=12;$i++){?>
<option value="<?php echo $i;?>"><?php echo $i;?></option>
<?php }?>
</select>
</div>
<div class="col-sm-4"><label>Select Year</label>
<select name="year" class="form-control">
<?php for($i=date("Y");$i>=2010;$i--){?>
<option value="<?php echo $i;?>"><?php echo $i;?></option>
<?php }?>
</select>
</div>
<div class="col-sm-4">
<p> </p>
<input type="submit" value="Show" name="submit" class="btn btn-primary">
</div>
</form>
</div>
</div>
<div class="row">
<div class="col-sm-2">
<label class="btn btn-success btn-sm">Month:<?php echo @$_REQUEST['month'];?></label>
</div>
<div class="col-sm-2"><label class="btn btn-info btn-sm">Year: <?php echo @$_REQUEST['year'];?></label></div>
</div>
<div class="row">
<div class="col-sm-12" style="overflow: scroll;">
<?php if($totDays>0){?>
<table class="table table-striped">
<tr>
<th>
Employee Name
</th>
<?php for($i=1;$i<=$totDays;$i++){?>
<th>
<?php echo $i;?>
</th>
<?php }?>
<?php foreach($attData as $attk=>$attv){
$punchin = $commonObj->getTimeOfDate($attData[$attk]['punchin']);
$punchout = $commonObj->getTimeOfDate($attData[$attk]['punchout']);
?>
<tr>
<th class="danger">
<?php echo $attv['name'];?>
</th>
<?php for($i=1;$i<=$totDays;$i++){?>
<?php if($commonObj->getDayOfDate($attData[$attk]['punch_time']) == $i){
echo "<td class='success' id='att_$i'>".$punchin.'-'.$punchout;?>
<table class="table table-responsive"style="display: none; position:relative;min-width:100px;max-width:200px; margin-top: -40px;" id="<?php echo "det_att_".$i;?>">
<tr>
<td>Total hours:</td>
<td><?php echo $commonObj->getHoursBetweenDates($attData[$attk]['punchin'],$attData[$attk]['punchout']);?>
</td></tr>
<tr>
<td>UID:</td>
<td><?php echo $attData[$attk]['rfid_uid'];?></td>
</tr>
</table>
<?php
}else {echo "<td class='info'>#na";}?>
</td>
<?php }?>
</tr>
<?php }?>
</tr>
</table>
<?php }?>
</div>
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$("td").hover(
function () {
var id = "#det_"+this.id;
$(id).css({"display":"block"});
},
function () {
var id = "#det_"+this.id;
$(id).css({"display":"none"});
//console.log(id);
//$(id).css("display","block");
});
});
</script>
Display of (ViewAttendance.php):
MY SQL TABLE :
I have page1.php which has a post form and page2.php which display data/results. I have a seperate php script file which queries a database. Having completed the query and assuming a result, I would end up with something like Code: [Select] while($result = mysql_fetch_assoc($query)) how do I get the data onto the display page. Looking at example approaches I found this using a go-between file Code: [Select] <?PHP include_once(process.php; process($_POST); display_results; ?> would display_results be a form of redirect? If not? Any help appreciated. So i pull some records out of a mysql table and i want to display them in 5 even columns. I'm not entirely sure how to do the math & logic to accomplish this. The pull is simple $qry = "SELECT DIST_PART_NUM FROM $tablename"; $sql = mysql_query($qry) or die(mysql_error()); while($res = mysql_fetch_assoc($sql)) { // CREATE 5 even columns here. } so let's say i just retrieved 5,000 part numbers, i'd like to display then in a table of 5 columns with 1000 records per column. This is easy math, but i need the script to automatically figure out the #'s. Also the tricky part is that i dont want to display the part numbers like so 11111 22222 33333 44444 55555 66666 77777 88888 99999 00000 but rather 11111 44444 77777 22222 55555 88888 33333 66666 99999 00000 the remainder if there is one can go in the last column or whatever is easier. I'd tried googling this, but it's not easy to phrase what i'm looking for. Thanks for the help. PS: I'm not looking to copy and paste code, if possible please explain your way so that i can learn the logic. Hi, I'm trying to joing two tables together, in the resulting PHP coding (See below) the issue I'm having the coding saying select the colour from the colour table where the model of car is the same as the model in the cars table. For example, if the car model is KA and in the table it is KA show the colours. I know this manual fix does the trick. [ $test = "KA"; $query_cols = "SELECT * FROM colours WHERE colours.model = '$test' "; ] But not the soultion any help would be much appericated thank you. [ include "connections/dbconnect.php"; $manfactures = "Ford"; $car_query = "SELECT * FROM cars WHERE make = '$manfactures'"; $car_result = mysql_query($car_query) or die ("Error in query: $car_query. ".mysql_error()); setlocale(LC_MONETARY, 'en_GB'); $fmt = '%i'; if (mysql_num_rows($car_result) > 0) { while ($car_row = @ mysql_fetch_array($car_result)) { $test = "KA"; $query_cols = "SELECT * FROM colours WHERE colours.model = cars.model"; $cols_result = mysql_query($query_cols) or die ("Error in query: $query_cols. ".mysql_error()); print " <table class='details'> <tr> <td rowspan='2'> <img src=\"". $car_row["image"] ."\" alt='" . $car_row["image_alt"] . "' /> </td> <td colspan='2'> <a href='" . $car_row["what_link"] . "'> " . $car_row["model"]." ".$car_row["model_details"] . " </a> </tr> <tr> <td> <p class='info'> RRP:<br/> What Price:<br/> Our Price:<br/> Savings of:<br/> Delivery Time: </p> </td> <td> <p class='info1'> "; echo money_format($fmt, $car_row["rrp"] ); print "<br/>"; echo money_format($fmt, $car_row["what_price"] ); print "<br/>"; echo money_format($fmt, $car_row["our_price"] ); $savings = $car_row["rrp"] - $car_row["our_price"]; print " <br/> <font color=\"red\">"; echo money_format($fmt, $savings ); print " </font><br/> " . $car_row["delivery_time"] . " </p> </td> </tr> <tr> <td> "; while ($cols_row = @ mysql_fetch_array($cols_result)) { ?> <a href='#' onmouseout='hideTooltip()' onmouseover='showTooltip(event,"<?php print "" . $cols_row["colour"] . ""; ?>");return false'> <?php print " <img src=\"". $cols_row["colour_img"] ."\" alt='" . $cols_row["colour_img_alt"] . "' /> "; } print " </td> </tr> "; } } else { echo "Aids!"; } print "</table>"; ?>] Hi all! I've been recently messing with PHP and MySQL to attempt to create a search function for my tables (too advanced, so I toned it down to learning to just display data from my table). Anyways, I'm watching a YouTube video on how to do it, and I'm copying his code exactly, but I'm still getting an error. Can anyone help? Thanks. Edit: Sorry, my error was snuggled down below the code. Anyways, my error is just my while echo appearing in and out of my tables on the page. My code:
<?php
//Make connection
mysql_connect('localhost', 'root', 'test');
// select db
mysql_select_db('testdatabase');
$sql="SELECT * FROM employees";
$records=mysql_query($sql);
?>
<html>
<head>
<title>Employee Data</title>
</head>
<body>
<table width="600" border="1" cellpadding="1" cellspacing="1">
<tr>
<th>ID</th>
<th>First name</th>
<th>Surname</th>
<th>Age</th>
</tr>
<?php
while($employees=mysql_fetch_assoc($records)){
echo "<tr>";
echo "<td>".$Employee['ID']."</td>";
echo "<td>".$Employee['First name']."</td>";
echo "<td>".$Employee['Surname']."</td>";
echo "<td>".$Employee['Age']."</td>";
echo "</tr>";
}
// end while
?>
</table>
</body>
</html>
Edited by thwikehu1990, 19 January 2015 - 01:33 PM. hello, i have a table in a database that stores information on powerpoint presentations like so: id, title, filename, presenter, program, session I want to query the data so that all entries are grouped by session (which is a date) and each presentation is displayed under its respective session in a table like so: [session] (i want to display each session once) [title] - [program] (then i want to display this information for each presentation in each session) [presenter] [session] [title] - [program] [presenter] etc... i am thinking of using group_concat for this but am not sure exactly how to pull it off. any help is greatly appreciated. thank you! So I have an simple account centre up, and i'm wanting to display their 'Name' 'Username' and 'Email' as part of their details. But I have one problem... My code doesn't seem to be getting the data from my database... It may be messy to some people, just warning you! Code: [Select] <?php session_start(); if($_SESSION['username']){ $connect = mysql_connect("****","****","****") or die("Could not connect to database."); mysql_select_db("****") or die ("Could not find database!"); $sql = mysql_query("SELECT * FROM login"); $username = $rows['username']; $email = $rows['email']; $rows = mysql_fetch_assoc($sql); echo "<p>"; } else header("location: suggestion.html"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <link href="css/style.css" rel="stylesheet" type="text/css" /> <style type="text/css"> body { background-color: #CCC; } body,td,th { color: #000; font-family: "MS Serif", "New York", serif; } </style> </head> <body> <div id="wrap"> <!--Header--> <div id="header_member"> </div> <!--Log out and time--> <div id="info"> <div id="date"><script type="text/javascript"> var currentDate = new Date() var day = currentDate.getDate() var month = currentDate.getMonth() + 1 var year = currentDate.getFullYear() document.write("<b>" + day + "/" + month + "/" + year + "</b>") var currentTime = new Date() var hours = currentTime.getHours() var minutes = currentTime.getMinutes()</script> </div> <div id="time"><script type="text/javascript"> var suffix = "AM"; if (hours >= 12) { suffix = "PM"; hours = hours - 12; } if (hours == 0) { hours = 12; } if (minutes < 10) minutes = "0" + minutes document.write("<b>" + hours + ":" + minutes + " " + suffix + "</b>")</script> </div> </div> <div id="logout"><center><?php echo "<a href='logout.php'>Log out.</a>";?></center></div> <!--Main section which will contain everything else--> <div id="member_main"> <div id="member_right"><center> <p><img src="images/accountinf.png" width="175" height="30" /></p> <p>Name: <?php echo $username;?></p> <p>Email: <?php echo $email;?></p> </center> </div> <div id="member_top"><center><?php echo "Welcome, ".$_SESSION['username'];?></center></div> <div id="member_left" align="center"><img src="images/navigation.png" width="105" height="30" /><img src="images/home_member.png" width="105" height="30" /><img src="images/account.png" width="105" height="30" /></div> </div> <!--Footer--> <div id="footer_member"></div> </div> </body> </html> I have a field in my table that gets populated with a custom value from a subscription form, but when the data gets inserted into the table, it adds some text I do not want to output. The field is for the user's name, but when the form saves it, it saves the name, plus the text #2# (this is from a Wordpress plugin and I can't figure out how to remove the #2# when I insert the value there either). Is there a way to remove this #2# text when I display the field's value in MySQL and PHP? Hey guys have been trying to get this script to work for a while now, i am new to php and mysql so i am sure i am missing something simple. I have DB setup and need to pull data based on the key item code and get the following I want to get the fields item_code description allergy_statement useable_units region_availability order_lead_time ingredients for item_code 12-100 LITERALLY 12-100, no range, but like i said before i am really new to php and mysql. I have 1187 items that when a user clicks a link in search results it takes them to the product details page for that item code All that data is in my database just can't figure out how to get it out of the database. Is this even the right script to achieve that result. here is the code to get the data from database Code: [Select] <?php require_once('includes/mysql_connect_nfacts_ro.php'); $query = "SELECT item_code, description, allergy_statement, useable_units, region_availability, order_lead_time, ingredients " . "FROM products " . "WHERE item_code = '12-100' "; $resuts = mysql_query($query) or die(mysql_error()); ?> And need to display the data like so : Code: [Select] <td width="715" align="center" valign="top"> <h1>Product Details</h1> <h3>DISPLAY description HERE</h3> <table width="420" border="0"> <td class="ingreg"> </td> </table> <h5>Item Number</h5> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY ITEM_CODE HERE</td> </tr> </table> <h3>Ingredients:</h3> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY INGREDIENTS HERE</td> </tr> </table> <h4>Allergy Statement:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Allergy Statement HERE</td> </tr> </table> <h4>Useable Units Per Package:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Useable Units Per Package HERE</td> </tr> </table> <h4>Region Availability: </h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY ITEM_CODE HERE</td> </tr> </table> <h4>Order Lead Time:</h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY order lead time HERE</td> </tr> </table> <p> </p> <div align="right"></div></td> </tr> </table> how do i get data in database to display where i need it to? Can any one shine some light on this I am trying to display data from a database from a form entry here is the php <?php include('dbconnect.php'); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM child_info"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); echo "<b><center>Database Output</center></b><br><br>"; $i=0; while ($i < $num) { $field1-name=mysql_result($result,$i,"file_number"); $field2-name=mysql_result($result,$i,"first_name"); $field3-name=mysql_result($result,$i,"middle_name"); $field4-name=mysql_result($result,$i,"last_name"); $field5-name=mysql_result($result,$i,"birthdate"); $field6-name=mysql_result($result,$i,"gender"); $field7-name=mysql_result($result,$i,"features"); $field8-name=mysql_result($result,$i,"diagnosis"); $field9-name=mysql_result($result,$i,"description"); echo "<b>$field1-name $field2-name2</b><br>$field3-name<br>$field4-name<br>$field5-name<hr><br>"; $i++; } ?> here is the form I am using <form name="child_info" action="selectdata.php" method="post" id="child_info"> <table width="444" align="center" > <tr> <td> Search by Name: </td> <td> First Name:<input type="text" class="form-textbox " id="first_name" name="first_name" size="20" /><br /> Last Name:<input type="text" class="form-textbox " id="last_name" name="last_name" size="20" /> </td> </tr> <tr> <td width="208"> Choose Male or Female: </td> <td width="224"> <input type="radio" name="gender" value="male" /> Male <input type="radio" name="gender" value="Female" /> Female </td> </tr> <tr> <td> Choose age range: </td> <td> <select name="first_age" id="first_age"> <option value="00">From</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> </select> <select name="second_age" id="second_age"> <option value="00">To</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> </select> </td> </tr> <tr> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> <div align="right"> <input type="submit" name="submit" id="submit" value="submit" /> <input type="reset" name="reset" id="reset" value="reset" /> </div></td> </tr> </table> </form> first problem is getting the form to use the php second problem is when i try to use the php alone is I get this error Parse error: syntax error, unexpected '=' in /home/fathersh/public_html/selectdata.php on line 17 17 is highlighted above in the php Ok... I need some help - I want to show a players balance in a game beside there name (Balance is in mysql database)I can do that but... - I also want to show if there online or offline at the same time( This is stored in a different database) I have the code which says whether they are online or offline <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> Here is the page: www.scswc.com/Offline_Users.php displaying that But I want to Create something like this: Nocvacraft Players |Online| Name:Player Balance:$20 |Offline| Name:Player Balance:$15 Here is what I have tried: <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); $query2 =mysql_query("SELECT * FROM iBalances WHERE player = $users"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query) $rows2 = mysql_fetch_array($query2)): $users = $rows['name']; $balance = $rows2['balance']; echo "<font color='black'>|Online|<br><font color='green'>Name:$usersBalance:$balance</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> I know I am trying to use a variable before it is been set - but if I don't how I have tried this as well... <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>Name:$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; $query = mysql_query("SELECT * FROM iBalances WHERE player = $users"); WHILE($rows = mysql_fetch_array($query)): $balance = $rows['balance']; echo "<font color='red'>$users $balance</font><br>"; endwhile; // ?> Can you use variables in mysql_query()?Is that why it isn't working? This is my first php script so if I need to give you more information for you to help me just tell me Thanks Here is database pictures iBalances users_online PHP Code Code: [Select] <?php $username=""; $password=""; $database=""; mysql_connect("","",""); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM tablename"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); echo "<b><center>Database Output</center></b><br><br>"; $i=0; while ($i < $num) { $field1-name=mysql_result($result,$i,"id"); $field2-name=mysql_result($result,$i,"Location"); $field3-name=mysql_result($result,$i,"Property type"); $field4-name=mysql_result($result,$i,"Number of bedrooms"); $field5-name=mysql_result($result,$i,"Purchase type"); $field6-name=mysql_result($result,$i,"Price range"); echo "<b>$field1-name $field2-name2</b><br>$field3-name<br>$field4-name<br>$field5-name<hr><br>"; $i++; } ?> HTML code for the form Code: [Select] <table id="tb1"> <tr> <td><p class="LOC">Location:</p></td> <td><div id="LC"> <form action="insert.php" method="post"> <select multiple="multiple" size="5" style="width: 150px;" > <option>Armley</option> <option>Chapel Allerton</option> <option>Harehills</option> <option>Headingley</option> <option>Hyde Park</option> <option>Moortown</option> <option>Roundhay</option> </select> </form> </div> </td> <td><p class="PT">Property type:</p></td> <td><div id="PS"> <form action="insert.php" method="post"> <select name="property type" style="width: 170px;"> <option value="none" selected="selected">Any</option> <option value="Houses">Houses</option> <option value="Flats / Apartments">Flats / Apartments</option> </select> </form> </div> </td><td> <div id="ptype"> <form action="insert.php" method="post"> <input type="radio" class="styled" name="ptype" value="forsale"/> For Sale <p class="increase"> <input type="radio" class="styled" name="ptype" value="forrent"/> To Rent </p> <p class="increase"> <input type="radio" class="styled" name="ptype" value="any"/> Any </p> </form> </div> </td> </tr> </table> <div id="table2"> <table id="NBtable"> <tr> <td><p class="NBS">Number of bedrooms:</p></td> <td><div id="NB"> <form action="insert.php" method="post"> <select name="number of bedrooms"> <option value="none" selected="selected">No Min</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> </select> to <select name="number of bedrooms"> <option value="none" selected="selected">No Max</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> </select> </form> </div> </td> <td><p class="PR">Price range:</p></td> <td><div id="PR"> <form action="insert.php" method="post"> <select name="price range"> <option value="none" selected="selected">No Min</option> <option value="50,000">50,000</option> <option value="60,000">60,000</option> <option value="70,000">70,000</option> <option value="80,000">80,000</option> <option value="90,000">90,000</option> <option value="100,000">100,000</option> <option value="110,000">110,000</option> <option value="120,000">120,000</option> <option value="130,000">130,000</option> <option value="140,000">140,000</option> <option value="150,000">150,000</option> <option value="160,000">160,000</option> <option value="170,000">170,000</option> <option value="180,000">180,000</option> <option value="190,000">190,000</option> <option value="200,000">200,000</option> <option value="210,000">210,000</option> <option value="220,000">220,000</option> <option value="230,000">230,000</option> <option value="240,000">240,000</option> <option value="250,000">250,000</option> <option value="260,000">260,000</option> <option value="270,000">270,000</option> <option value="280,000">280,000</option> <option value="290,000">290,000</option> <option value="300,000">300,000</option> <option value="310,000">310,000</option> <option value="320,000">320,000</option> <option value="330,000">330,000</option> <option value="340,000">340,000</option> <option value="350,000">350,000</option> </select> to <select name="price range"> <option value="none" selected="selected">No Max</option> <option value="50,000">50,000</option> <option value="60,000">60,000</option> <option value="70,000">70,000</option> <option value="80,000">80,000</option> <option value="90,000">90,000</option> <option value="100,000">100,000</option> <option value="110,000">110,000</option> <option value="120,000">120,000</option> <option value="130,000">130,000</option> <option value="140,000">140,000</option> <option value="150,000">150,000</option> <option value="160,000">160,000</option> <option value="170,000">170,000</option> <option value="180,000">180,000</option> <option value="190,000">190,000</option> <option value="200,000">200,000</option> <option value="210,000">210,000</option> <option value="220,000">220,000</option> <option value="230,000">230,000</option> <option value="240,000">240,000</option> <option value="250,000">250,000</option> <option value="260,000">260,000</option> <option value="270,000">270,000</option> <option value="280,000">280,000</option> <option value="290,000">290,000</option> <option value="300,000">300,000</option> <option value="310,000">310,000</option> <option value="320,000">320,000</option> <option value="330,000">330,000</option> <option value="340,000">340,000</option> <option value="350,000">350,000</option> </select> </form> </div> </td> </tr> </table> </div> <form id="submit" action=""> <input type="submit" value="search" /> </form> I am querying my database to show the visit statistics for a particular week and it shows the number of visits for the countries, but does not display the country name.
I have proved that the MySQL works by going into phpMyAdmin and pasting the query into SQL query tab, replacing the POST with 1, for week 1.
I can't see why it is not displying the country.
Here is the code:
<?php
include('connect_visits.php');
doDB7();
$WVisit_data="SELECT WeekNo15.WNo, WeekNo15.WCom, Countries.Country, Countries.CID, ctryvisits15.CVisits
FROM ctryvisits15
LEFT JOIN Countries
ON ctryvisits15.country = Countries.CID
LEFT JOIN WeekNo15
ON ctryvisits15.WNo = WeekNo15.WNo
WHERE ctryvisits15.WNo = '{$_POST['WeekNo']}'
ORDER BY ctryvisits15.CVisits DESC";
$WVisit_data_res = mysqli_query($mysqli, $WVisit_data) or die(mysqli_error($mysqli));
$display_block ="
<table width=\"20%\" cellpadding=\"3\" cellspacing=\"1\" border=\"1\" BGCOLOR=\"white\" >
<tr>
<th>Country</th>
<th>Visits</>
</tr>";
while ($WV_info = mysqli_fetch_array($WVisit_data_res)){
$Ctry = $WV_info['country'];
$Visits = $WV_info['CVisits'];
//add to display
$display_block .="
<tr>
<td width=\"10%\" valign=\"top\">".$Ctry."<br/></td>
<td width=\"5%\" valign=\"top\">".$Visits."<br/></td>
";
}
mysqli_free_result($WVisit_data_res);
mysqli_close($mysqli);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<!--
Design by Free CSS Templates
http://www.freecsstemplates.org
Released for free under a Creative Commons Attribution 2.5 License
Name : Yosemite
Description: A two-column, fixed-width design with dark color scheme.
Version : 1.0
Released : 20091106
-->
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="keywords" content="" />
<meta name="description" content="" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>1066 Cards 4U - Stats for country</title>
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />
</head>
<body>
<div id="wrapper">
<div id="menu">
<ul>
<li class="current_page_item"><a href="index.php">Home</a></li>
<li><a href="Links.html">Links</a></li>
<li><a href="Verse_Menu.html">Verses</a></li>
<li><a href="Techniques.html">Techniques</a></li>
<li><a href="blog.php">Blog</a></li>
<li><a href="Gallery.html">Gallery</a></li>
<li><a href="contact.html">Contact</a></li>
<li><a href="AboutUs.html">About Us</a></li>
<li><a href="stats1.html">Stats</a></li>
</ul>
</div><!-- end #menu -->
<div id="header">
<div id="logo">
<h1><a href="http://www.1066cards4u.co.uk">1066 Cards 4U</a></h1>
</div><!-- end #wrapper -->
</div><!-- end #header -->
<div id="page">
<div id="page-bgtop">
<div id="page-bgbtm">
<div id="content">
<h3>Statistics for Week Commencing <? echo $WkCom; ?> in 2015</h3>
<div id="table">
<?php echo $display_block; ?></div>
</div><!-- end #content -->
</body>
</html>
Can you help please?
Edited by rocky48, 07 January 2015 - 07:33 AM. After several attempts, I now have data displayed on my index.php page, but the data is from all rows. Luckily I have two rows. The page also has a menu - with two links. What I would like help with is: How to display index.php with just the data for it - i.e. home page data. How to display data if either the ‘home’ or ‘copyright’ links are clicked. I understand you can use $_GET[‘id’], and isset(), but I don’t know how to do that. I include the full html page code:
<?php
// database connection
require_once('admin/databasecon.php');
?>
<!DOCTYPE html>
<html>
<?php include 'includes/headsection.php'; ?>
<body>
<?php
// displaying data
$table = "pages"; // table
$sqli = "SELECT * FROM $table ORDER BY id ASC";
$result = $conn->query($sqli);
?>
<!-- topMenu -->
<table id="topMenu">
<tr>
<td><h1 class="siteName">Scarab Beetle</h1></td>
<?php
if ($result = mysqli_query($conn, $sqli)) {
while($row = $result->fetch_assoc()) {
echo "<td class='navItem'>" . "<a href=index.php>" . $row["menuheader"] . "</a>" . "</td>";
}
}
?>
</tr>
</table>
<!-- topMenu end -->
<!-- timeline menu -->
Menu goes here
<!-- timeline menu end -->
<!-- page title -->
<?php
if ($result = mysqli_query($conn, $sqli)) {
while($row = $result->fetch_assoc()) {
echo "<h1 class='centered'>" . $row["pageheader"] . "</h1>";
}
}
?>
<hr>
<!-- page content -->
<?php
if ($result = mysqli_query($conn, $sqli)) {
while($row = $result->fetch_assoc()) {
echo $row["pagetext"];
}
}
?>
<hr>
<div class="clear"></div>
<!-- footer content -->
<?php include 'includes/footersection.php'; ?>
<!-- footer content end -->
</body>
</html>
Any help to achieve what I want will be appreciated. Thank you. ok so im sure this is only a small problem but still here it is: im making a shopping list app where users can create a list...when they view the list they can populate it with categories such as frozen food, fruit, veg etc etc...they can then populate categories with items such as apples, potatoes or ice cream etc etc. now i have some data in the database already...and i wanted to display it on the page like this. ASDA SHOPPING LIST fruit apples bananas plums veg potatoes carrots frozen burgers chips ice cream however at the moment with my code it displays like this: ASDA SHOPPING LIST fruit apples bananas plums potatoes carrots burgers chips ice cream veg frozen here is my code: include_once("config_class.php"); $db = new db(); // open up the database object $db->connect(); // connect to the database //getting id of the data from url $id = $_GET['id']; $sql=mysql_query("SELECT listname FROM list WHERE listid=$id") or die("cannot select: ".mysql_error()); $sql2=mysql_query("SELECT catid, category FROM cat WHERE listid=$id") or die("cannot select: ".mysql_error()); $sql3=mysql_query("SELECT items.itemname, items.itemid, cat.catid FROM items, cat WHERE cat.catid=items.catid") or die("cannot select: ".mysql_error()); $temp_cat = ""; $res=mysql_fetch_array($sql); echo "<b>" . $res['listname'] . "</b>" . "<br><br>"; echo "<form action='addcat.php?id=$id' method='post'>"; echo "<input type='text' id='addcat' name='addcat'>"; echo "<input type='submit' value='Add Category'>"; echo "</form>"; while($res2=mysql_fetch_array($sql2)) { echo "<table cellpadding='2' cellspacing='2' width='800'>"; echo "<tr>"; if($res2['category'] != $temp_cat ) { echo "<td width='20%'>"; echo "<b>" . $res2['category'] . "</b>" . "</td>"; echo "<td width='20%'><a href='delcat.php?id=$res2[catid]&id2=$id'>Delete Category</a></td>"; echo "<form action='additem.php?id=$res2[catid]&id2=$id' method='post' name='form1'>"; echo "<td width='20%'>"; echo "<input type='text' name='itemname'></td>"; echo "<td width='20%'>"; echo "<input type='submit' name='Submit' value='Add Item'></td>"; echo "</form>"; echo "</tr>"; $temp_cat=$res2['category']; } while($res3=mysql_fetch_array($sql3)) { echo "<tr>"; echo "<td width='20%'>"; echo "$res3[itemname]" . "</td>"; echo "<td width='20%'>"; echo "<a href='delitem.php'>Delete Item</a>" . "</td>"; echo "</tr>"; } echo "</table>"; } could someone please help me display this correctly? thanks in advance I am retrieving data from a third party's API using AJAX method. I would like to do two things. 1. Display the data records on a page. 2. Create a pagination on the page to display records more efficiently. I am expecting to retrieve possibly hundreds of records. I can normally do this using PHP but since I am retrieving the records using AJAX, the pagination is gonna be a challenge. First things first is to display the records. Here is my AJAX code. It displays the log data fine. But it doesn't display any data in the "output" div. And it gives this error in the console. Uncaught SyntaxError: Unexpected token o in JSON at position 1 at JSON.parse (<anonymous>) at Object.success
<div class="output"></div>
<script>
$.ajax ({
type: 'GET',
url: "https://3rdpartywebsite.com/api/GetCustomers",
dataType: 'json',
processData: false,
contentType: false,
success: function(data) {
console.log(data)
$newData = JSON.parse(data);
$.each($newData, function(i, v) {
$('.output').append(v.LastName);
$('.output').append(v.FirstName);
});
}
});
</script>
What am I doing wrong? Edited November 14, 2020 by imgrooot |
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