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PHP - Moved: Problem With Updating A Mysql Field To 0
This topic has been moved to MySQL Help.
http://www.phpfreaks.com/forums/index.php?topic=351353.0 Similar TutorialsHi: I'm going crazy trying to do the following: I'm making a job registration process where the user registers on one php page to the website, must acknowlege and email receipt using an activate php page, then is directed to upload their C.V. (resume) based on the email address they enter in the active page output. I then run an upload page to store the resume in teh MySQL db based on the users email address in the same record. If I isolate the process of the user registering to the db, it works perfectly. If I isolate the file upload process into the db, it works perfect. I simply cannot upload teh file to the existing record based on teh email form field matching the user_email field in the db. With the processes together, teh user is activated, but teh file is not uploaded. Maybe I've simply been at this too long today, but am compeled to get through it by end day. If anyone can help sugest a better way or help me fix this, I will soo greatly appreciate it. My code is as follows for the 2 pages. ---------activate.php------- <?php session_start(); include ('reg_dbc.php'); if (!isset($_GET['usr']) && !isset($_GET['code']) ) { $msg = "ERROR: The code does not match.."; exit(); } $rsCode = mysql_query("SELECT activation_code from subscribers where user_email='$_GET[usr]'") or die(mysql_error()); list($acode) = mysql_fetch_array($rsCode); if ($_GET['code'] == $acode) { mysql_query("update subscribers set user_activated=1 where user_email='$_GET[usr]'") or die(mysql_error()); echo "<h3><center>Thank You! This is step 2 of 3. </h3>Your email is confirmed. Please upload your C.V. now to complete step 3.</center>"; } else { echo "ERROR: Incorrect activation code... not valid"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Job application activation</title> </head> <body> <center> <br/><br/><br/> <p align="center"> <form name="form1" method="post" action="upload.php" style="padding:5px;"> <p>Re-enter you Email : <input name="email" type="text" id="email"/></p></form> <form enctype="multipart/form-data" action="upload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="4000000"> Upload your C.V.: <input name="userfile" type="file" id="userfile"> <input name="upload" type="submit" id="upload" value="Upload your C.V."/></form> </p> </center> </body> </html> --------upload.php---------- <?php session_start(); if (!isset($_GET['usr']) && !isset($_GET['code']) ) { $msg = "ERROR: The code does not match.."; exit(); } if(isset($_POST['upload']) && $_FILES['userfile']['size'] > 0) { $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $email = $_POST['email']['user_email']; $fp = fopen($tmpName, 'r'); $content = fread($fp, filesize($tmpName)); $content = addslashes($content); fclose($fp); if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } include 'reg_dbc.php'; $query = "UPDATE subscribers WHERE $email = user_email (name, size, type, content ) ". "VALUES ('$fileName', '$fileSize', '$fileType', '$content')"; mysql_query($query) or die('Error, query failed'); mysql_close($dbname); } ?> <center> <br/> <br/> <br/> <br/> Thank you for uploading your <?php echo "$fileName"; ?> file, completing your registration, and providing us your C.V. for this position. <br/> <br/> <br/> We will contact you if your canditature qualifies. </center> Hi All, Please can someone help me with this bit of code. I have a mysql database with a table called 'events'. I have six fields namely 'ID, mxitID, type, message, ts, publish'. I am trying to update the field 'publish' from Yes --> No or if it is already No then back to Yes again. I have two files then main one beacon.php and publish.php Here is the code: beacon.php Code: [Select] <?php // connect to the database include('connect-db.php'); // display data in table // echo "<p><b>View All</b> | <a href='view-paginated.php?page=1'>View by Page</a></p>"; // echo "Select your Carousel: "; // get results from database $result = mysql_query("SELECT * FROM events WHERE type='beacon'") or die(mysql_error()); echo "<table border='1' cellpadding='10'>"; echo "<a href='index.php'>b Back</a><br><br>"; echo "<tr> <th>ID</th> <th>mxitID</th> <th>Type</th> <th>Message</th> <th>Timestamp</th> <th>Published</th> <th>Modify</th></tr>"; // loop through results of database query, displaying them in the table while($row = mysql_fetch_array( $result )) { // echo out the contents of each row into a table echo "<tr>"; echo '<td>' . $row['ID'] . '</td>'; echo '<td>' . $row['mxitID'] . '</td>'; echo '<td>' . $row['type'] . '</td>'; echo '<td>' . $row['message'] . '</td>'; echo '<td>' . $row['ts'] . '</td>'; echo '<td>' . $row['publish'] . '</td>'; echo '<td><a href="publish.php?id=' . $row['ID'] . '"><input name="update" type="submit" id="update" value="Update"></a></td>'; echo "</tr>"; } // close table> echo "</table>"; ?> publish.php <?php // connect to the database include('connect-db.php'); // get id value $id = $_GET['id']; echo "$id"; $sql="SELECT * FROM events WHERE type='beacon'"; $result=mysql_query($sql); $active=($result['publish']=='')?'Yes':'No'; echo "$active"; if ($active='Yes') { $active='No'; } else { $active='Yes'; } $sql = "UPDATE events SET publish='$active' WHERE ID='$id'"; $result = mysql_query($sql); // header("Location: beacon.php"); ?> I cant seem to change the value...any help would be much appreciated. Thank you in advance. MOD EDIT: code tags added. Hey, Im needing some help with an update form that I have created using PHP/MySQL. Basically the form is working great (updating records, retrieving records and showing errors) but there is a problem with the errors. If there are no errors and I edit the existing text input values, the database updates fine. However if I edit the existing text input values and there is an error, the edited input values dont save, they revert back to the values of the database. I understand why this is happening, its because the text inputs are set to show the values of the database so if i edit the existing values and an error occurs or the page is refreshed, the values revert back to the database values. However id like it so that if any text in the text field have been edited and an error occurs, the text stays to how it is until the user by passes any errors and then the database is updated. Hopefully this makes sense. I have attached the php page just incase anybody wants to look into it but any help would be much appreciated! Also, im not looking for someone to just to fix this for me but if someone knows my problem and can guide me in the right direction, that would be great. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321735.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=334042.0 i have a with my script I made a basic messaging service for my website. I have a form with a textarea as an input variable. It inserts the textarea value to a database using a php script upon form submission. The SQL field is set as longtext so the user can insert a large text string. There's a few things i need to do to perfect it. I need to make it so the user can only insert text characters, so not to allow script manipulation; and I need to figure out why it's deleting my intro message when changing the `read` field from `unread` to `read`. The `messages` SQL table is separated into 6 fields: to, from, message, read, subject, and number. when the user reads a message, i have a php script that reads as follows: <?php include("include/session.php"); function curPageName() { return substr($_SERVER["SCRIPT_NAME"],strrpos($_SERVER["SCRIPT_NAME"],"/")+1); } $pagename = curPageName(); $replaced2 = eregi_replace("message", "", $pagename); $number = eregi_replace(".php", "", $replaced2); mysql_select_db("******_starcraft") or die(mysql_error()) ; $query = " SELECT * FROM `messages` WHERE number='$number' "; $result = mysql_query($query); $info = mysql_fetch_array ( $result ); $to = $info['to']; $from = $info['from']; $subject = $info['subject']; $message = $info['message']; $read = $info['read']; mysql_query("DELETE FROM `messages` WHERE `number`='$number'") ; mysql_query("INSERT INTO `messages` VALUES ('$to', '$from', '$message', 'read', '$subject', '$number')") ; ?> Now, after trouble shooting, i found that the problem is occuring when it tries to insert the $message string into the third field of the `messages` table. I find this strange because when you send the message to this user using the "compose message" script, the input variable is inserted into the database table without a stitch. Is there something i'm missing? i feel like it's on the tip of my tounge... thanks in advance, -dan this is my 3 files which is i am using to show data of customer but i am not able to see them their logo image please see them & help me guys i dont know whats wrong in this. these files i uploaded please find attachment to see them. thnx in advanced [attachment deleted by admin] Okay, I have a useredit page in where a user can manage their account info. All the text field and SQL connections work fine, and they all update perfectly. But when I go ahead and add my own text field (first name) and hit submit, it says success - but in my SQL it hasn't actually updated ... What the Ef? Here are my snippets of my codes: --useredit.php-- <form action="process.php" method="POST"> <input type"text" name"firstname" value="<? if($form->value("firstname") == ""){ echo $session->userinfo['firstname']; }else{ echo $form->value("firstname"); } ?>"> <input type="hidden" name="subedit" value="1"> <input type="submit" value="Edit Account"> --process.php-- function procEditAccount(){ global $session, $form; /* Account edit attempt */ $retval = $session->editAccount($_POST['curpass'], $_POST['newpass'], $_POST['email'], $_POST['firstname']); /* Account edit successful */ if($retval){ $_SESSION['useredit'] = true; header("Location: ".$session->referrer); } --session.php-- function editAccount($subcurpass, $subnewpass, $subemail, $subfirstname){ global $database, $form; if($subfirstname){ $database->updateUserField($this->username,"firstname",$subfirstname); } --database.php-- function updateUserField($username, $field, $value){ $q = "UPDATE ".TBL_USERS." SET ".$field." = '$value' WHERE username = '$username'"; return mysql_query($q, $this->connection); } If you need to see more code, let me know. Would appreciate the help, thanks! Ollie! Hey, im trying to fix a line of code that should update a field in the database when filled in. The code i think handles this is below. <input type="text" id="uuser_address" name="uuser_address" value="<?php echo("$slide[address]"); ?>"><br /><input type="text" id="uuser_town" name="uuser_town" value="<?php echo("$slide[town]"); ?>"><br /><input type="text" id="uuser_county" name="uuser_county" value="<?php echo("$slide[county]"); ?>"><br /><input type="text" id="uuser_postcode" name="uuser_postcode" value="<?php echo("$slide[postcode]"); ?>"></div> can anyone tell me why this is updating all the address fields other than the postcode? thanks, gavin I must be using the wrong search terms in google cause I cant find out how to update a field to a blank spot. trying to make name blank. I thought it was just " " hope someone can please help me with this Code: [Select] mysql_query("UPDATE users SET name = '".mysql_real_escape_string "."' WHERE id = '".mysql_real_escape_string($_SESSION['user_id']))."'"; Hi there. I'm totally new (about a week!) with php and mysql and am encountering a problem that perhaps someone can help me with?
I've looked through to see if a similar problem has appeared or been solved, but without success, so apologies if I am repeating something.
In php I am trying to update 7 fields from a form from which a user has edited/modified any of the fields in a chosen record (except id).
Here is the code:
$id=$_GET['id']; I need some help with updating the database table with the correct selection from that box. I have a dropdown box. This is actually a list from the images in a curtain directory. here the code I used: <?php $dhandle = opendir('../images/Vessels/'); $files = array(); if ($dhandle) { // loop through all of the files while (false !== ($fname = readdir($dhandle))) { if (($fname != '.') && ($fname != '..') && ($fname != basename($_SERVER['PHP_SELF']))) { $files[] = (is_dir( "./$fname" )) ? "(Dir) {$fname}" : $fname; } } closedir($dhandle); } So when inserting a new record I can use the dropdownbox to populate the correct field. Database: Id, Vesselname, Image, more, andmore There is a section where an authorized user can upload an image to the directory. This image will then be available in dropdown when the need to add a new vessel (in this case) The problem that I have is, when I later what to update the vessel, I want that same dropdownbox to be showing the correct imagename as "selected". How can I do that? This is what I have been expirementing with sofar: <?php require_once('../Connections/bgf_db.php'); ?> <?php $dhandle = opendir('../images/Vessels/'); $files = array(); $selectedFile = "mare.jpg"; if ($dhandle) { // loop through all of the files while (false !== ($fname = readdir($dhandle))) { if (($fname != '.') && ($fname != '..') && ($fname != basename($_SERVER['PHP_SELF']))) { $files[] = (is_dir( "./$fname" )) ? "(Dir) {$fname}" : $fname; } } closedir($dhandle); } if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $MyFile_Recordset1 = "no-picture.jpg"; if (isset($selectedFile)) { $MyFile_Recordset1 = $selectedFile; } mysql_select_db($database_bgf_db, $bgf_db); $query_Recordset1 = sprintf("SELECT vessels.Name, vessels.Image FROM vessels WHERE vessels.Image = %s", GetSQLValueString($MyFile_Recordset1, "text")); $Recordset1 = mysql_query($query_Recordset1, $bgf_db) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); $selectedFile = $row_Recordset1['Image']; ?> <select name="NameHere"> <option value="<?php echo $selectedFile?>" <?php if (!(strcmp($selectedFile, $row_Recordset1['Image']))) {echo "selected=\"selected\"";} ?>><?php echo $selectedFile ?> </option> <?php // Now loop through the files, echoing out a new select option for each one foreach( $files as $fname ) { echo "<option value=\"$fname\">{$fname}</option>\n"; } echo "</select>\n"; ?> I have a form that allows my client to update some products. Now the products are simple just basic info and 1 picture. I have set this up so they can edit the products and change the information, having done this many times in the past, but now hit a puzzling block that I am baffled. The client when editing is presented with the form with the information pulled from the database and the form fields loaded with that data ready to edit. The image can either be left alone or they can choose to upload a new image. They are shown the image they currently have stored in the database. The problem I have is EVEN if they decide not to upload an image and change other information, when the submit the form it must be sending a blank value for the image somewhere as it is updating the database and removing the image reference as if it has been removed. I have an if/else statement based on the form to perform 2 different queries for the update in mysql. Here is the code for the form update, as you can see the image should not update?? Please help?? if ($_SERVER['REQUEST_METHOD'] =='POST') { //This stops SQL Injection in POST vars foreach ($_POST as $key => $value) { $_POST[$key] = mysql_real_escape_string($value); } // **************************** THIS IS FOR NO NEW IMAGE ******************************** if ($_SERVER['REQUEST_METHOD'] =='POST' && empty($_FILES['product_image']['name'])) { # setup SQL statement for no new image $SQL = " UPDATE products SET product_title = '{$_POST['product_title']}', product_description = '{$_POST['product_description']}', standard_price = '{$_POST['standard_price']}', deluxe_price = '{$_POST['deluxe_price']}' WHERE product_id = '{$_REQUEST['product_id']}' "; } // **************************** THIS IS FOR A NEW IMAGE ******************************** else { // Check the image type is a jpeg or gif for the image. if (($_FILES['product_image']['type'] != "image/gif") && ($_FILES['product_image']['type'] != "image/jpeg") && ($_FILES['product_image']['type'] != "image/pjpeg")) { echo "<FONT FACE=\"Verdana\"><SPAN CLASS=\"content\">You have chosen not to upload a <b>Product Image</b>.<BR></SPAN>" ; } elseif ($_FILES['product_image']['size'] > 100000) { echo "<FONT FACE=\"Verdana\"><SPAN CLASS=\"content\">The file size is bigger than 300kb.<BR></SPAN>" ; } else { move_uploaded_file($_FILES['product_image']['tmp_name'], "/httpdocs/product_images/".$_FILES['product_image']['name']) ; echo "<FONT FACE=\"Verdana\"><SPAN CLASS=\"content\"><B>Your front image has successfully uploaded.</B><BR></SPAN>" ; } } # setup SQL statement for update $SQL = " UPDATE products SET product_title = '{$_POST['product_title']}', product_description = '{$_POST['product_description']}', standard_price = '{$_POST['standard_price']}', deluxe_price = '{$_POST['deluxe_price']}', product_image = '{$_FILES['product_image']['name']}' WHERE product_id = '{$_REQUEST['product_id']}' "; } #execute SQL statement $result = mysql_db_query( *****,"$SQL",$connection ); # check for error if (!$result) { echo("ERROR: " . mysql_error() . "\n$SQL\n"); } This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=306058.0 This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=326455.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=334445.0 Hi, Does anyone have any experience of using PHP to transfer data from an XML file to a MySQL database? For the last 5 weeks I have been trying to get the following code to work but I am still unable to do it. The code does copy the file from my root folder into another (I eventually plan to use external download onto my server). However, it comes up with the following error: "Cannot instantiate non-existent class: xmlreader in" which refers to this: $xmlReader = new XMLReader(); Does anyone have any experience of transferring data from an XML file to a database? I am using PHP 5 so I dont know why this doesn't work. <?php ini_set('display_errors', 1); error_reporting(-1); $host="hostname"; // $username="username"; // $password="password"; // $db_name="db"; // $tbl_name="productfeed"; // // Connect to server and select database. mysql_connect("$host", "$username", "$password")or ("no connection"); mysql_select_db("$db_name")or die("Database Connection Error"); $xmlReader = new XMLReader(); $filename = "datafeed_98057.xml"; $url = "[url=http://www.ukhomefurniture.co.uk/datafeed.xml]http://www.ukhomefurniture.co.uk/datafeed.xml[/url]"; file_put_contents($filename, file_get_contents($url)); $xmlReader->open($filename); while ($xmlReader->read()) { switch ($xmlReader->name) { case'prod': $dom = new DOMDocument(); $domNode = $xmlReader->expand(); $element = $dom->appendChild($domNode); $domString = utf8_encode($dom->saveXML($element)); $product = new SimpleXMLElement($domString); $product_code = $product->prod['id']; $image = $product->awImage; //insert query if(strlen($product) > 0) { $query = mysql_query("REPLACE INTO productfeed (image) VALUES ('$awImage')"); echo $awImage . "has been inserted </br>"; die('yes it works'); error_reporting(E_ALL); if (ini_get('display_errors')) { ini_set('display_errors', 1); } } break; } } ?> MOD EDIT: DB credentials removed. Hi, Apologies to keep going on about this but I have hit a brick wall over updating my database with XML. I have spent around 100 hours on this and so far I can only copy the file, I am unable so far to update my database with the information from the XML file. I would be very grateful for any help you can offer to fix this. Code: [Select] ----Code so far----> $xmlReader = new XMLReader(); $filename = "datafeed_98057.xml"; $url = "http://www.domain.co.uk/datafeed.xml"; file_put_contents($filename, file_get_contents($url)); $xmlReader->open($filename); while ($xmlReader->read()) { switch ($xmlReader->name) { case'prod': $dom = new DOMDocument(); $domNode = $xmlReader->expand(); $element = $dom->appendChild($domNode); $domString = utf8_encode($dom->saveXML($element)); $prod = new SimpleXMLElement($domString); $id = $prod->prod['id']; $description = $prod->name; $image = $prod->awImage; $fulldescription = $prod->desc; //insert query if(strlen($prod) > 0) { $query = mysql_query("REPLACE INTO productfeed (id, description, fulldescription, image) VALUES ('$id','$description','$image','$fulldescription') "); echo $id . "has been inserted </br>"; } else{echo ("This does not work </br>");} } This is an outline of the XML feed I am using, it only includes one item which I am using as a test: Code: [Select] - <merchant id="1829" name="Pinesolutions.co.uk"> - <prod id="39920873" pre_order="no" web_offer="no" in_stock="yes" hotPick="no" adult="no"> - <text lang="EN"> <name>Oakleigh Wall Mirror 60x90</name> <desc>Mirrors are useful anywhere in the house. Not only are they functional allowing you to see your reflection in order to look your best, they also add elegance to any room theyre placed in. We offer a variety of mirrors to fit your decorating tastes as well as wall space. The Oakleigh Wall Mirror radiates an elegant simplistic style, while offering a generous size glass. The Oakleigh Wall Mirror s frame is crafted from solid hardwood and is lacquered with a protective finish to guard against dust and unexpected stains. The Oakleigh Wall Mirror is versatile and can be hung portrait style at the top of a staircase or landscape. The Oakleigh Wall Mirrors light colour means it also complements all of the furniture in our Camden Painted Range because the range has ash tops. The Oakleigh Wall Mirror has fewer knots than traditional oak wood, but is built just as sturdy so you can be certain it will last you through the generations to come.</desc> </text> - <uri lang="EN"> <awTrack>http://www.awin1.com/pclick.php?p=39920873&a=98057&m=1829</awTrack> <awImage>http://images.productserve.com/preview/1829/39920873.jpg</awImage> <mLink>http://www.pinesolutions.co.uk/bedroom-furniture/mirrors/wall-mirrors/oakleigh-wall-mirror-60x90/</mLink> <mImage>http://media.pinesolutions.co.uk/images/products/903.333.3.4.jpg</mImage> </uri> - <price curr="GBP"> <buynow>40.00</buynow> </price> - <cat> <awCatId>424</awCatId> </cat> <brand /> </prod> </merchant> Hi, when someone logs in to my page, i have a form displayed with names, address, etc...what i need to do is when i hit the update button for that information to go into the MYSQL table I have created and over write that information if a user updates...so how do i do that? Hi All, Whenever I try to update any piece of PHP code to update a MySQL database, nothing happens. I have tried copying in some of the working codes of a website and tried the same, but no success. I recently installed XAMPP. I am connecting using the correct user id and pass to the database. The scripts are not giving me any error, but just not connecting, that's all. While making such a usage as noted below <FORM name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" > I get the following error Firefox can't find the file at /C:/xampp/htdocs/="<?php.. so on Why does this happen? I am pretty new to this, so please do help. Thanks, Satheesh P R |
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