PHP - Column And Variable Names Using Php And Mysql
Hello,
I'm having some issues with PHP thinking that the variables that I send it are the actual columns in my database. First, I pull off Quadratic_Functions and introductory_problem from http://localhost:8888/algebra_book/Chapters/Quadratic_Functions/introductory_problem.php using the code below: Code: [Select] $chapter_page = $_SERVER['PHP_SELF']; $chapter_page_array = explode('/',$chapter_page); $size =count($chapter_page_array); $chapter = $chapter_page_array[$size-2]; $page = $chapter_page_array[$size-1]; $page_array = explode('.', $page); $page = $page_array[0]; Based on my printing of the variables $chapter and $page I think that it's doing what I want it to do. I then use the following function: Code: [Select] $supplemental_id = getSupplementalId($dbRead,$chapter,$page); to check out if the there's a supplemental_id for the Quadratic_Function chapter and introductory_problem page name via: Code: [Select] function getSupplementalId($read,$user_id,$chapter,$page) { $sql = "SELECT supplemental_id FROM instructors_supplemental WHERE page_name = $page AND chapter_name='$chapter"; return $read->fetchRow($sql); } If I stick in actual values, as seen below, the thing runs fine. Code: [Select] $sql = "SELECT supplemental_id FROM instructors_supplemental WHERE page_name = 'introductory_problem' AND chapter_name='Quadratic_Functions'"; But if I run it in the abstract version, with variables for page and chapter name (the first version), I get Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42S22]: Column not found: 1054 Unknown column 'introductory_problem' in 'where clause'' in... It's almost as if it thinks that my variables are the names of the columns. Any thoughts would be appreciated.... Similar TutorialsMy Php Buddies, I have mysql tbl columns these:
id: Now, I want to display their row data by excluded a few columns. Want to exclude these columns: date_&_time account_activation_code account_activation_status id_verification_video_file_url password
So, the User's (eg. your's) homepage inside his account should display labels like these where labels match the column names but the underscores are removed and each words' first chars CAPITALISED:
Id: 1
For your convenience only PART 1 works. Need help on Part 2 My attempted code:
PART 1 <?php // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } // Query to get columns from table $query = $conn->query("SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = 'members' AND TABLE_NAME = 'users'"); while($row = $query->fetch_assoc()){ $result[] = $row; } // Array of all column names $columnArr = array_column($result, 'COLUMN_NAME'); foreach ($columnArr as $value) { echo "<b>$value</b>: ";?><br><?php } ?> PART 2 <?php //Display User Account Details echo "<h3>User: <a href=\"user.php?user=$user\">$user</a> Details</h3>";?><br> <?php $excluded_columns = array("date_&_time","account_activation_code","account_activation_status","id_verification_video_file_url","password"); foreach ($excluded_columns as $value2) { echo "Excluded Column: <b>$value2</b><br>"; } foreach ($columnArr as $value) { if($value != "$value2") { $label = str_replace("_"," ","$value"); $label = ucwords("$label"); //echo "<b>$label</b>: "; echo "$_SESSION[$value]";?><br><?php echo "<b>$label</b>: "; echo "${$value}";?><br><?php } } ?> PROBLEM: Columns from the excluded list still get displayed. Edited November 19, 2018 by phpsaneThe Code Below is for my Colony Building page for my game. That particular code is supposed to display the number of buildings built, which it does, and also allow me to change the number of buildings built, which it doesn't. The code is part of a loop that displays all the possible buildings of a given type, in this case Iron Mines, that can be built on the colony. Basically what I need to know is, how do I change the name of the column that is being updated as the code loops. Currently it is setting all the forms to alter the number of Basic iron mines on a colony. I am hoping I can somehow call the names of all the columns into an array and use the same code that picks which column value i am selecting, the $?(an array)[$b](an incrementing number to call the correct array value): $?[$b]. Then I would replace Basic, in the column part of the UPDATE code with the array and result selector so that the first time i include() the code it creates the form and sets it to alter Basic, but the second time it sets the code to alter the value in the next column. Code: [Select] <?php $dbhost = 'localhost:3306'; $dbuser = 'root'; $dbpass = 'root'; $dbname = 'aosdb'; $conn = mysql_connect($dbhost,$dbuser,$dbpass) or die ('Error connecting to mysql'); mysql_select_db($dbname); $b=1; $queryp = "SELECT * FROM IMBuilt WHERE idcol = $idcol"; $resultp = mysql_query($queryp); $Base = mysql_fetch_row($resultp); if(isset($_POST["built"])) { if($_POST) { $Badd = $Base[$b]+$_POST["built"]; $queryi="UPDATE IMBuilt SET Basic=$Badd WHERE idcol = $idcol"; mysql_query($queryi); } } $queryf = "SELECT * FROM IMBuilt WHERE idcol = $idcol"; $resultf = mysql_query($queryf); $Basic = mysql_fetch_row($resultf); ?> <p class="bd" id="built">| Built: <?php echo $Basic[$b] ?> |</p> <form class="bd" method="post" action="IronMineList.php"><input type="varchar" name="built"><input type="submit" value="Build"></form> </div> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=344739.0 I have data similar to below. I am doing a MySQL query and doing a JOIN based on instructor name. I am echoing classes and linking the instructor name to another page with their BIO. All is working great, however I want to use the ID's for something else. How do I differentiate the ID between the Instructors table and the Classes Table without changing the column name in the database?
For instance, I want to echo the Instructor ID and then echo the Classes ID, but they are both the same column name in the database and since they are joined, how will that work?
Instructors:
ID | Instructor | Title | Bio |
1 | Bob Smith | Chef | bob smith is a chef with... |
2 | Jane Doe | Professor | Jane doe is an instructor that... |
Classes:
ID | Instructor | Class Title | Class Description |
4 | Bob Smith | Baking | this is a baking class where you learn.... |
5 | Jane Doe | Food Safety | Food safety is very important... |
Hi, I'm trying to edit some database fields, I have text1, text2, text3, text4, text5, text6 etc.. They are displayed on the index.php page, with an edit link so the user can choose which set to edit // Extract details from database $sql = "SELECT * FROM data WHERE id=1"; $stmt = $db->prepare($sql); $stmt->execute(); $e = $stmt->fetch(); <h1><?php echo $e['text1']) ?></h1> <p><?php echo ($e['text2']); ?></p> <p><a href="edit.php">EDIT</a></p> <h1><?php echo $e['text3']) ?></h1> <p><?php echo ($e['text4']); ?></p> <p><a href="edit.php">EDIT</a></p> <h1><?php echo $e['text5']) ?></h1> <p><?php echo ($e['text6']); ?></p> <p><a href="edit.php">EDIT</a></p>
edit.php: // Extract details from database $sql = "SELECT * FROM data WHERE id=1"; $stmt = $db->prepare($sql); $stmt->execute(); $e = $stmt->fetch(); <form method="post" action="process.php" enctype="multipart/form-data"> <label>Page Title <input type="text" name="text1" maxlength="90" value="<?php echo $e['text1'] ?>" /> </label> <br> <label>Title Text</label> <textarea name="text2"><?php echo $e['text2'] ?></textarea> <input id="button" type="submit" name="submit" value="Save Changes" /> and then update them: process.php $sql = "UPDATE data SET text1=?, text2=? WHERE id=1 LIMIT 1"; $stmt = $db->prepare($sql); $stmt->execute( array( $_POST['text1'], $_POST['text2'] ) ); $stmt->closeCursor(); Question: How can I pass the form values dynamically from the index.php page so I don't have to hard code text1, text2 etc into the edit.php and process.php page and have a different update & process page for each set of data?
Thanks in advance. Hi There, I would like to place the last for month names into an variable- for example: February 2011 January 2011 December 2010 November 2010 But I would like them to all have the same variable ($date) - so when I use it in a mssql_fetch_assoc - it increments with every instance of $date, as there will be one instance of $date for every row returned, getting older with every row. Hope that is enough info? Cheers Matt As you can see here I have the following code Code: [Select] <?php session_start(); session_register('hazard2'); //INITIALIZE ERROR VARIABLES $errorFound = false; $errorIcon['hazard2'] = ''; if (isset($_POST['submitbutton'])) { //SET SESSION VARIABLES $_SESSION['hazard2'] = $_POST['hazard2']; //TEST FORM INFORMATION if(count($_POST['hazard2']) != 3) { $errorFound = true; $errorIcon['hazard2'] = 'Error Question 2'; } //IF NO ERRORS WERE FOUND, CONTINUE PROCESSING if (!$errorFound) { header( "Location: hazardresult.php" ); } } ?> It's lazy I know, but the script is on a file called hazard2.php, is there anyway to have all of the hazard2's in the code come from the file name. So when I make hazard3, I don't have to change all the hazard2's to hazard3's Thank you I am building a website that uses session variables extensively. The site is getting a little complicated, and I am starting to lose track of which session variables are assigned, and what their values are. Is there some way where I can create a piece of code that will display all of the existing session variables and their values? I'm trying to input the results from a query into html, but I'm just getting the variable names rather than their values. I used single quotes for the echo statement, but I think I must need to switch to double to do that. But then I have problems with the double quotes from the class names (ex. class="SideBoxTitle"). Code: [Select] <?php // get user's videos from database $conn = mysqli_connect($dbhost, $dbuser, $dbpass) or die("MySQL Error: " . mysql_error()); $query = "SELECT * FROM haas12_test.videos"; $result = mysqli_query($conn, $query) or die ("Couldn't execute query."); while($row = mysqli_fetch_assoc($result)) { extract($row); echo ' <div id="topBox" class="mainVideoSideBoxes" > <div class="SideBoxTitle" ><h3> $vidtitle </h3> </div><!-- close SideBoxTitle --> <div class="sideBoxVidContainer"> <div class="SideBoxScreenCast" > $vidurl </div><!-- close SideBoxScreenCast --> <div class="SideBoxDesc" ><p> $viddesc </p> </div><!-- close SideBoxDesc --> </div><!-- close sideBoxVidContainer --> </div><!-- close mainVideoSideBoxes --> </div><!-- close mainVideoSideBoxes --> '; // end echo staement } ?> This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=321230.0 Hi, I want to store files to variable array using glob() like $files[0] = xyz.txt $files[1] = pqr.txt . . . $files[n] = nfile.txt I know how to list files from directory using glob() Code: [Select] <?php foreach (glob("*.txt") as $filename) { echo "$filename size " . filesize($filename) . "\n"; } ?> How can I do that ? I need to update a particular table and there be a whole lot of field names. I'd like to do it without having to use them the same way you can access then like $row[12] after a "select" query. The standard for updating (at least how I write it) goes like this ... Code: [Select] $query = "UPDATE linguistics SET welcome1='$var3', welcome2='$var4' WHERE language = '$lengua'"; Well, I'd like to do it where I don't have to name welcome1 and welcome2, but instead refer to their numerical position within the database. On a "select" query we can do this. Can this be done on an update? Something perhaps like ... Code: [Select] $query = "UPDATE linguistics SET 3='$var3', 4='$var4' WHERE language = '$lengua'"; ... where 3 and 4 represent the 4th and 5th fields respectively. I know that this particular phrasing doesn't work because I've tried it, but surely there has to be something. This will save me LOTS of time. Thanks!! Hi. The idea: I want to pull a client record and simply place all the row columns into editable form field text boxes. Once the user reviews and edits a submit button will update the record. What I have: Code: [Select] $Query01 = "SELECT * FROM `CustomerSignups` WHERE `Id` = '$_GET[Id]'"; $Result01 = mysql_query($Query01) or die("Error 01: " . mysql_error()); while ($get_info = mysql_fetch_row($Result01)) { foreach ($get_info as $field) echo "<p>$field</p>"; It displays as expected, a line for each field. How can I get this to pull the field names also and then I can use those as text box input fields...? I currently have php code that outputs information from my database, but how do i make it also display the name of the fields beside each entry of the database? heres my PHP code: Code: [Select] <?php $server = ""; // Enter your MYSQL server name/address between quotes $username = ""; // Your MYSQL username between quotes $password = ""; // Your MYSQL password between quotes $database = ""; // Your MYSQL database between quotes $con = mysql_connect($server, $username, $password); // Connect to the database if(!$con) { die('Could not connect: ' . mysql_error()); } // If connection failed, stop and display error mysql_select_db($database, $con); // Select database to use // Query database $result = mysql_query("SELECT * FROM Properties"); if (!$result) { echo "Error running query:<br>"; trigger_error(mysql_error()); } elseif(!mysql_num_rows($result)) { // no records found by query. echo "No records found"; } else { $i = 0; echo '<div style="font-family:helvetica; font-size:15px; padding-left:15px; padding-top:20px;">'; while($row = mysql_fetch_array($result)) { // Loop through results $i++; echo '<img class="image1" src="'. $row['images'] .'" />'; //image echo "Displaying record $i<br>\n"; echo "<b>" . $row['id'] . "</b><br>\n"; // Where 'id' is the column/field title in the database echo $row['Location'] . "<br>\n"; // Where 'location' is the column/field title in the database echo $row['Property_type'] . "<br>\n"; // as above echo $row['Number_of_bedrooms'] . "<br>\n"; // .. echo $row['Purchase_type'] . "<br>\n"; // .. echo $row['Price_range'] . "<br>\n"; // .. } echo '</div>'; } mysql_close($con); // Close the connection to the database after results, not before. ?> thanks in advance I can get files to upload to folder and add a new row for each in to a mysql db using the code below, how do I get all the filles in one row with multiple uploads Code: [Select] //Check if the form was submitted. if(isset($_POST['uploadButton'])) { //Specify folder path where the file is going. $path = 'uploads/'; //Upload file one by one. foreach($_FILES['file']['name'] as $key => $val) { if($val != '') { $file_name = $_FILES['file']['name'][$key]; //Get file name. $file_tmp = $_FILES['file']['tmp_name'][$key]; //Get temporary file name. $file = $path . $file_name; mysql_query("INSERT INTO images (img1) VALUES('$file');") or trigger_error('Unable to INsert: ' . mysql_error()); //Move uploaded file if(move_uploaded_file($file_tmp, $file)) { echo 'File was succesfully uploaded to: ' . $file . '<br />'; } else { //Display error message if there was a problem uploading file. echo 'Error uploading file "' . $key . '."<br />'; } echo $target_path; } } } ?> Hi all, I have the following MySQL insert query: Code: [Select] $insert= mysql_query ("INSERT INTO tablename (column1,`".$EXPfields."`) VALUES ('$something','".$EXPvalues."')"); where $EXPfields is an array of table-field-names and $EXPvalues is an array of table-field-values. Now I want to write an equivalent query, but using UPDATE instead of INSERT INTO, but I don't want to write out all the field names/values separately, but again want to use $EXPfields and $EXPvalues. So something like this: Code: [Select] $update = mysql_query ("UPDATE tablename SET (column1,`".$EXPfields."`) = ('$something','".$EXPvalues."') WHERE .... "); Is this possible? If so, what is the proper syntax? Thanks! In querying my database, I'm Selecting nameFirst and nameLast, and it produces a name like Joe Smith. I'm trying to match a photo with the name. Right now I'm uploading photos into a folder naming the file (e.g. SmithJoe.jpg). For reasons that involve writers being able to upload and access photos, I'm trying to use an image plugin. When uploading photos, it strips capital letters, so SmithJoe,jpg goes in as smithjoe.jpg, and it's not matching my database query. Here is the code I'm working with that works quite well with this one exception: $query = 'SELECT * FROM wp_playerRank'; $results = mysql_query($query); while($line = mysql_fetch_assoc($results)) { if ($line['wpID'] == $wp_tagID) { echo '<div class="player">'; // Here is the code that produces the image. I need to get rid of capital letters for ease of use echo '<div><img src="/wp-content/uploads/' . $line['nameLast'] . $line['nameFirst'] . '.jpg"></div>'; echo '<div class="playerData">' . $line['height'] . ' '; if ($line['position'] == 'PG') {echo 'Point Guard';} elseif ($line['position'] == 'SG') {echo 'Shooting Guard';} elseif ($line['position'] == 'SF') {echo 'Small Forward';} elseif ($line['position'] == 'PF') {echo 'Power Forward';} elseif ($line['position'] == 'C') {echo 'Center';} echo '</div>'; echo '<div class="playerData">' . $line['hschool'] . '</div>'; echo '<div class="playerData">' . $line['summer'] . '</div>'; echo '<div class="playerData">Class of ' .$line['year'] . '</div>'; if ($line['committed'] == 'y') { echo '<div> <br>Committed to <strong>'. $line['college'] . '</strong></div> ';} } } I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> This is a continuation of my previous post. I would like to be able to read the second column of a tab delimited txt file into a variable as a string. let's say i have: Code: [Select] somegarbage_here readthisinto$file I'm looking for this but all tuts seem to be about importing it to arrays and what not. I just want to import the second column. There is always one line. |