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PHP - Help With An "array_sum" Not Adding Correctly
I am making a price sheet for extended warranties that my company sells and am having a problem with the math.
There is a base price of $1380, plus certain surcharges and certain exclusions. The exclusions are working properly, but something funky is happening with the surcharges... This link more clearly explains the problem I am having: http://www.carcityofdanbury.com/New/01/Resources/printable_list_Admin.php Here is the code, then I'll explain the problem Code: [Select] // TMU if ($row['TMU'] == "x") { $extended = 'N/A'; // Salvage Title } elseif ($row['cleantitle'] != "x") { $extended = 'N/A'; // 150,000+ miles } elseif ($row['mileage'] > "150000") { $extended = 'N/A'; // Snowplow } elseif ($row['ftr003'] == "x") { $extended = 'N/A'; // Category 3 } elseif ($row['make'] == "Jaguar" || $row['make'] == "Land Rover") { $extended = 'N/A'; // 10+ cyls } elseif ($row['engine_cylinders'] > "8") { $extended = 'N/A'; // Older than 13 years } elseif ($year < date("Y")-12) { $extended = 'N/A'; // Qualifies for warranty } else { if ($row['mileage'] > "99999" && $row['mileage'] < "125000") {$surcharge[] = 200;} if ($row['mileage'] > "125000" && $row['mileage'] < "150001") {$surcharge[] = 400;} if ($row['drivetrain'] == "AWD" || $row['drivetrain'] == "4x4") {$surcharge[] = 150;} if ($row['fuel'] == "Diesel") {$surcharge[] = 100;} if ($row['make'] == "Audi" || $row['make'] == "BMW" || $row['make'] == "Cadillac" || $row['make'] == "Infiniti" || $row['make'] == "Lexus" || $row['make'] == "Lincoln" || $row['make'] == "Mercedes-Benz" || $row['make'] == "Mini" || $row['make'] == "Saab" || $row['make'] == "Volvo") {$surcharge[] = 550;} if (date("Y")-11 == $year) {$surcharge[] = 50;} if (date("Y")-12 == $year) {$surcharge[] = 100;} if (date("Y")-13 == $year) {$surcharge[] = 200;} if ($surcharge) {$surcharges = array_sum($surcharge);} $extended = '$'.number_format(1380 + $surcharges); } The 9th vehicle on the list: 08 Hyundai Sante Fe SE the warranty price is correct, but the vehicle after, the 08 Honda Accord EX should be 1,380, yet its adding the surcharges from the the Hyundai, and it keeps repeating down the list. Where is the error? Similar TutorialsCan someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! I have the code below to output a list: Code: [Select] while ($row = mysql_fetch_array($rs_teambydate)) { echo "<tr><td width='200'>".$row['team_name']." (".$row['members_count'].")</td><td><input type='submit' name='".$row['team_name']."' value='Plunder'/></td>"; } This is all inside a form so I can use the following to get various includes: Code: [Select] <? if(isset($_POST['".$row['team_name']."'])){ include ('resources.php');} ?> My problem is this part : $_POST['".$row['team_name']."'], as this obviously doesn't work. Anyone know how I can add the "$row['team_name']" inside $_POST[' '] ? Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; This is what I have $eeee = $_POST['forum_reply']; $eeee = strip_tags($eeee, '<p>'); echo $eeee; this is what prints out Quote Untitled document testinggg this is a print_r of $_Post Quote Array ( [forum_reply] => testinggg [form_reply_submit] => Reply ) Please someone tell me what in binary's name is going on! I have a simple form to add details to the database. I want to use the same form layout to call back details for editting and updating. The main page is showroomedit.php which lists (in an array) the records in the database. I have added an edit.php but cant seem to work the code out. Can some one point me in the right direction. here is edit.php: <?PHP include('dbconnect.php') ?> <HTML> <HEAD> <TITLE>Barry Ottley Motor Co - Quality Used Motors - Stanford-Le-Hope, Essex</TITLE> </HEAD> <BODY LINK="#000000" ALINK="#000000" VLINK="#000000"> <CENTER><IMG SRC="logo.jpg"></CENTER> <CENTER> <TABLE WIDTH="840" CELLPADDING="0" CELLSPACING="0" BORDER="0"> <TR> <TD WIDTH="186" valign="top"> <BR> <CENTER><A HREF="index.html"><IMG SRC="homepage.jpg" alt="Homepage" border="0"></A></CENTER> <CENTER><A HREF="showroom.php"><IMG SRC="showroom.jpg" alt="Our Online Showroom" border="0"></A></CENTER> <CENTER><A HREF="location.html"><IMG SRC="ourlocation.jpg" alt="Our location" border="0"></A></CENTER> <CENTER><A HREF="aboutus.html"><IMG SRC="aboutus.jpg" alt="About Us" border="0"></A></CENTER> <CENTER><A HREF="contactus.php"><IMG SRC="contactus.jpg" alt="Contact Us" border="0"></A></CENTER> </TD> <TD WIDTH="30" valign="top"> </TD> <TD valign="top"> <FONT SIZE="2" FACE="ARIAL"> <CENTER><A HREF="addcar.html"><IMG SRC="vehicleadd.jpg" border="0"></A><A HREF="showroomconfig.php"><IMG SRC="vehicleedit.jpg" border="0"></A><A HREF="showroomconfig.php"><IMG SRC="vehicledelete.jpg" border="0"></A></CENTER> <CENTER><B>Update a Vehicle</B></CENTER> <BR> <?php $query1="SELECT cars FROM CarName='$carname', CarTitle='$CarTitle', CarPrice='$carprice', CarMiles='$carmiles', CarDescription='$cardesc'"; mysql_query($query1); mysql_close(); ?> <form action="editvehicle.php" method="post"> <CENTER>Vehicle Name:</CENTER> <CENTER><input type="text" name="CarName" value="<?php echo $carname; ?>"></CENTER> <br> <CENTER>Vehicle Type:</CENTER> <CENTER><input type="text" name="CarTitle" value="<?php echo $cartitle; ?>"></CENTER> <br> <CENTER>Vehicle Price:</CENTER> <CENTER><input type="text" name="CarPrice" value="<?php echo $carprice; ?>"></CENTER> <br> <CENTER>Vehicle Mileage:</CENTER> <CENTER><input type="text" name="CarMiles" value="<?php echo $carprice; ?>"></CENTER> <br> <CENTER>Vehicle Description:</CENTER> <CENTER><textarea name="CarDescription" rows="10" cols="30" value="<?php echo $cardesc; ?>"></textarea></CENTER> <br> <CENTER><input type="Submit"></CENTER> </form> </TD> </TR> </TABLE> <BR><BR><BR><BR> <CENTER><FONT FACE="VERDANA" SIZE="1"> This website was designed and is hosted by <A HREF="http://www.IRCDirect.co.uk">IRC Direct Website Design™</A> 2010 </CENTER> <BR> <CENTER><A HREF="admin.php">Employee Area</A> </BODY> </HTML> That is not even showing me the table details at all. Im lost . There is an "Update" link in each array in showroom.php in which when the user clicks it opens edit.php . They update the form as they wish... then click update and it updates the database and sends them back to showroomedit.php Much help would be appreciated ! Cheers paul if your out there still I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? I have a this piece of code, and simply need to make the last piece work: Code: [Select] $amount = $_POST['amount']; ......... $query = mysql_query("SELECT * FROM teams WHERE team_id='$te' ") or die(mysql_error()); $result = mysql_fetch_array( $query ); if($result['team_treasure'] <= '$amount'){ echo "<br><br><div align='center'>Transfer Failed: Not enough credits</div> ";} else { echo "<br><br><div align='center'>Transfer Completed!</div>";} It returns Transfer Completed!, no matter if team_treasure is higher or lower than $amount Hi all, Using a form with check boxes divided into different categories, I collect data selected by the user. I now want to combine each choice in each category with each choice in the other categories and list the combinations to the user. If the user chooses one or more options in each category, it is relatively easy to nest foreach loops, since the number of categories will always be the same. For example, if the form contains three categories of options, the code will be: Code: [Select] foreach ($form['cat_1'] as $k1 => $val1) { foreach ($form['cat_2'] as $k2 => $val2) { foreach ($form['cat_3'] as $k3 => $val3) { echo $val1.' _ '.$val2.' _ '.$val3.'<br/>'; } } } Things get complicated if the user does not select options within a given category. More generally, I want to be able to generate the list regardless of the number of categories in which the user selects options. Thank you in advance for your advice. hello, I was wondering what is the point of writing for a dropdown: <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> or for a checkbox/ radio button: <?php if ($_POST['cb/radioID'] == "value") { echo "checked"; } ?> I guess it's for after submit, if there is any error, the values filled will still be echoed in the inputfield, or am i wrong? But then if that is true, i have a php search box where i use AJAX object to to send all the input they filled in after submit. But after pushing submit the inputted values remain. I guess when using AJAX to send the information i don't need <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> in my html forms? Little confused Can maybe somebody bring clearness Hey guys! I have the following doubt: I have a php file that does the following alongside with other code not displayed he $fp = fopen("emails.txt", "w"); It opens a txt file called emails.txt that is in the same folder where the php is saved but how do I tell $fp = fopen("/folderbefore/emails.txt", "w"); ?? In other words, how do I write the path on the script that the emails.txt is located in a previous folder where the php file is located?? Thanks in advance for your help Cheers! Hi all, I am making a newsletter sign up system and needing a little help with the PHP side of things. The HTML code I am about to quote is a stripped back version of what I am trying to do (keeping it simple for the thread). HTML code: Quote <FORM action="confirmation.html" method="post"> <DIV> <SPAN> Action: <SELECT name="action"> <OPTION>Register</OPTION> <OPTION>Unregister</OPTION> </SELECT> E-mail: <INPUT name="e-mail" type="text"></INPUT> <BR> Newsletter: <SELECT name="newsletter"> <OPTION>Mens</OPTION> <OPTION>Womens</OPTION> </SELECT> <BR> <INPUT type="submit" value="Submit"> </SPAN> </DIV> </FORM> PHP code: Quote <?php $link = mysql_connect('localhost', 'testuser', 'testpw'); if (!$link) { die('Could not connect: ' . mysql_error()); } echo 'Connected successfully'; mysql_select_db('testdb', $link); if $_POST['action'] == ('register') { if $_POST['newsletter'] == ('mens') { $sql = "INSERT INTO newsletters(mens) VALUES('{$_POST['e-mail']}')" } if $_POST['newsletter'] == ('womens') { $sql = "INSERT INTO newsletters(womens) VALUES('{$_POST['e-mail']}')" }; } if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo 'Done!'; mysql_close($link); ?> I know the HTML part is fine, but its the PHP code where I am making the mistakes. I think I am treating it too much like Python. What am I doing wrong? I'm a very new PHP user (as in, I just started today) and need to make a set of navigation buttons which will take the user to "next" or "previous" pages. I assume that the $_GET function is involved, but I don't know how to do it. It needs to work like this: If the URL looks like "http://website.com/page1.php" I need the "next" button (a href image) to change it to "/page2.php", and while on page 2, for the "previous" button to take the user to "/page1.php" and so forth. How can I cause the page number to increment or decrease respective to the href image being clicked? In the following code the sign "\" is used before "/index.php?....". What does this sign mean in a link statement? Does it mean it automatically adds the url of the webfolder or phpfile? Code: [Select] <?php echo "<a href=\"/index.php?sid=".$name."&question=".$nextquest."\">next</a>"; ?> |
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