PHP - How To Create An Rss Feed

Hi

I get an error when trying to add a link to my rss feed
Code: [Select]
<link>http://www.jobjar.co.uk/jobdetails.php?keywords=lon0014&page=1</link>Something to do with the last part of the link because when I remove the page=1 it then works. How can I resolve this?

Also, will I have to manually update my xml file for rss feeds or can it be updated automatically? If so how?

Thanks

Hi,

I've written some code to take information from an SQL database and write it out in the RSS format (Although it doesn't validate).

The problem is i'd like the page to have the .rss (or .xml) file extension, I'm not sure if there's any advantages in having this but thought i'd ask.

I've got the following code:

Code: [Select]
<?php 
header('Content-type: text/xml');
print '<?xml version="1.0"?>';
print '<rss version="2.0">';
        print '<channel>';
include("phpfunctions.php");
db_connect();

//select all from users table
$select="SELECT title, link, description FROM news";
$result = mysql_query($select) or die(mysql_error());

//If nothing is returned display error no records
if (mysql_num_rows($result) < 1) {
die("No records");
}

//loop through the results and write each as a new item

while ($row = mysql_fetch_assoc($result)) {
    $item_title = $row["title"];
    $item_link = $row["link"];
    $item_desc = $row["description"];

        print '<item>';
           print '<title>' . $item_title . '</title>';
            print '<link>' . $item_link . '</link>';
            print '<description>' . $item_desc . '</description>';
        print '</item>';


}
print '</channel>';
print '</rss>';

?>


This seems to work fine as i get what i expect and i'm assuming i can do the same to output .xml but is there a way to have it in a proper .rss / .xml file so that an aggregator or someone could read this properly.

Cheers,

Reece

Hi, I have a small piece of code that creates an RSS feed using a mysql database. The issue is the page itself is blank however if I right click and view source I can see all the feed there. I convert the dat time field into a standard RSS date field. The web address is http://vinovote.com/news/feed.php

My code is as follows

Code: [Select]
<?php echo '<?xml version="1.0" encoding="UTF-8"?>'; ?>



<rss version="2.0">
<channel>
<title>Vinovote.com</title>
<description>The Latest News And Views From Around The Web</description>
<link>http://www.vinovote.com/</link>
<copyright>Your copyright information</copyright>

<?php
require_once('../Connections/connection.php');
mysql_select_db($database_vinovotedb, $vinovotedb);
$doGet = mysql_query("SELECT
feed_content.feed_content_id,
feed_content.feed_id,
feed_content.url,
feed_content.title,
feed_content.content,
feed_content.item_time,
Date_FORMAT(feed_content.item_time,'%a, %d %b %Y %T') AS pubDate
FROM feed_content
order by item_time desc
LIMIT 50
", $vinovotedb) or die(mysql_error());

while($result = mysql_fetch_array($doGet)){
?>

     <item>
        <title> <?php echo $result['title']; ?></title>
        <description> <?php echo $result['content'];?></description>
        <link><?php echo $result['url'];?></link>
        <pubDate> <?php echo  $result['pubDate']; ?></pubDate>
     </item> 
<?php } ?> 

</channel>
</rss>

hi i want to add some content to my site using xml rss

i have a feed i want to show, and the only thing i can find to show it on my page or widgets
but they dont look like i want it to look, so i want to make a php script that reads the xml file and then parses it into my website

dont know if this is even possible ...

but if its possible, is it also possible to filter the feed on certain keywords?

I'm not sure you can do this but i would like to grab the image gif from the rss feed of yahoo weather. For instance

http://weather.yahooapis.com/forecastrss?p=77056

I pulled this script from a tutorial online and it works great for displaying the temperature and condition and i realize those values are located within the xml. But i would like to grab the image located between the <description> tags (if you look at the source of the rss feed). I don't know if this is possible or not. Thanks.

Code: [Select]
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Yahoo! Weather API RSS</title>
<?php 
function retrieveYahooWeather($zipCode="92832") {
    $yahooUrl = "http://weather.yahooapis.com/forecastrss";
    $yahooZip = "?p=$zipCode";
    $yahooFullUrl = $yahooUrl . $yahooZip; 
    $curlObject = curl_init();
    curl_setopt($curlObject,CURLOPT_URL,$yahooFullUrl);
    curl_setopt($curlObject,CURLOPT_HEADER,false);
    curl_setopt($curlObject,CURLOPT_RETURNTRANSFER,true);
    $returnYahooWeather = curl_exec($curlObject);
    curl_close($curlObject);
    return $returnYahooWeather;
}
$localZipCode = "77056"; // Houston, Tx
$weatherXmlString = retrieveYahooWeather($localZipCode);
$weatherXmlObject = new SimpleXMLElement($weatherXmlString);
$currentCondition = $weatherXmlObject->xpath("//yweather:condition");
$currentTemperature = $currentCondition[0]["temp"];
$currentDescription = $currentCondition[0]["text"];

?>
</head>
<body>
<h1>Houston, TX</h1>
<ul>
    <li>Current Temperatu <?=$currentTemperature;?>&deg;F</li>
    <li>Current Description: <?=$currentDescription;?></li>
</ul>

</body>
</html>

Hi, I am reading a feed with this code


foreach ($xml->channel->item as $item) { 
echo $item->title;
echo '<br>';
}

and outputs
Code: [Select]
title 1
title 2
title 3
.... and so on until 10
I wants in reverse order to output last rss feed first like:
Code: [Select]
title 10
title 9
title 8
.... and so on until 1, how can i do it? i tried with rsort($xml->channel->item) butt getting this error:
Quote

Warning: rsort() expects parameter 1 to be array, object given in

Thanks for help

Hello!
I'm trying to develop some kind of RSS news aggregator and I want to show only feeds younger than 1day. I figured i could transform RSS pubDate to timestamp (strtotime()), but there are some feeds without timestamp (like: http://izklop.com/xmldata/rsslinks.xml). Is there any other way to do it, so I could find timestamp from those feeds without pubdate?

If there isn't any other way, do You think it is ok, to just show last 5 feeds?

I hope I made my self clear, and please forgive me for my English

Does anybody have any recommendations for PHP scripts to pull in a Twitter feed? I've tried several but each seem to just give me error messages!

I basically just need a PHP alternative so that the tweets can be read by search engines.

Thanks.

I have tried sitemap.org and a few others but have not found anything that will give the results I am after.

I have a blog site that has a URL and a Description for the URL and wish to have the description show as the anchor text which is linked to the URL, all data is taken from MySQL.

Does anyone have a code that will generate something like this ?

hi all,

i am trying to just get a couple things from this RSS feed: http://www.sierraavalanchecenter.org/bottomline-rss.php

I would like to grab the danger rose image on the left, the text that tells of the Avalanche danger ie... "Avalanche Danger Remains LOW..." and the date.

I have tried using a few things like:
$html = 'http://www.sierraavalanchecenter.org/bottomline-rss.php';$dom = new DOMDocument;$dom->loadHTML($html);$xpath = new DOMXPath($dom);$res = $xpath->query('//div[@id="dangericon"]');if ($res->item(0) !== NULL) {  $test = $res->item(0)->nodeValue;}()

...without any luck. Anyone have some advice for me?

thanks!

I'm been searching and can't seem to figure this out.

I want to take an RSS feed from a news site and display it on my site.

any help?

I have a php script that saves some data as a .xml document.  When I view this in my browser I can subscribe to the feed (I am using firefox).  However I asked someone else to see if they could subscribe (they were using IE) but the couldn't.  Therefore how can users subscribe to my feed?  Will only some be able to subscribe?

Thanks for any help. 

I'm creating an RSS feed that can be read through an Android app.  I've pulled in RSS feeds from CNN and other places and they all seem to have the same setup.  They have
Title1|||Description1|||Link1
Title2|||Description2|||Link2
ect.

How do I create the 3 | (Shift + Backslash) and not have them show up in the feed when viewed through a browser?  It's been a while since I've done PHP and I don't remember doing anything like this.

I am trying to troubleshoot a problem with a php script that incorporates an RSS feed (with Magpie 0.72.)  I did not code the site, and am trying to retrace the original logic.  Tech support at my web hosting firm said that the problem was in line 4 of INDEX.PHP:
1.   <?php
2.   require ("\\\\(HOSTING SITE NAME)\\config.inc.php");
3.   require ($CONFIG['admin_dir'].'page.class.php');
4.   require ($CONFIG['admin_dir'].'function.inc.php');
5.   $currentFile = $_SERVER["SCRIPT_NAME"];
6.   $parts = explode('/', $currentFile);
7.   $currentFile = $parts[count($parts) - 1];
8.   $currentFile = preg_replace("/\.\w+$/", "", $currentFile);
9.   $page = new page($currentFile, $CONFIG);
10.   if ( !$page->isActive() ) {
a.   $currentFile = $CONFIG['404_page'];
b.   $page = new page($currentFile, $CONFIG);
11.   }
12.   require ($CONFIG['include_dir'].$page->getTemplate().'.php');
13.   ?>

The RSS feed is in an INCLUDES directory that is defined by CONFIG.INC.PHP:

<?php
    # URL to the RSS feed
    // CIO.com
    $FEED_URL = "http://feeds.cio.com/cio/feed/articles?format=rss";
    $NUM_ITEMS = 5;
   
    require($CONFIG['include_dir'].'magpierss-0.72\rss_fetch.inc');
   
    # Fetch the feed
    error_reporting(E_ERROR);
    $rss = fetch_rss($FEED_URL);
    if($rss) {
        # Split array with our amount of items
        $items = array_slice($rss->items, 0, $NUM_ITEMS);
       
        $rssChannelTitle = $rss->channel['title'];
        $rssChannelLink = $rss->channel['link'];
        // $rssChannelDesc = $rss->channel['description'];
        $output = "";
        $output .= "";
        foreach ( $items as $item ) {
            $output .= '<li class="item">';
                $output .= '<a class="itemLink" target="blank" href="';
                    $output .= $item['link'] . '">';
                    $output .= $item['title'];
                $output .= '</a>';
                /* CIO's feed contains ads.
                  $output .= '<p class="description">' . $item['description'] . '</p>';
                 */
            $output .= "</li>";
        }
        $output .= "";
    }
?>
<?php if($rss) { ?>
    <div class="rssFeed <?php echo $rssChannelTitle ?>">
        <h1>
            <a href="<?php echo $rssChannelLink ?>">
                <?php echo $rssChannelTitle ?>
            </a>
        </h1>
        <!-- <h2><?php echo $rssChannelDesc ?></h2> -->
        <ul class="itemList">
            <?php echo $output ?>
        </ul>
    </div>
<?php } ?>

What am I missing?