PHP - Date Format Mismatch With C
Hi,
I'm working on an application which interacts with an embedded device. Here I'm sending the time in EDT. The following code is used to send the time: Code: [Select] $time = date_format(date_create(null, timezone_open("EDT")), "s,i,H,d,m,Y,w"); Here 'm' is from 01 to 12. But at the receiving end the firmware expects the month to be in the range 0-11 (C-style). Yes I can explode the "$time" and subtract 1 from month. But is there any better way to do that..? Thanks, Girish Similar TutorialsI have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. Hi there, I have a string '12/04/1990', that's in the format dd/mm/yyyy. I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field. The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01. Any ideas? Much appreciated. I have a date field in the database table of this format 2012-02-08. Now I want to select fields from the database where date >= $currentdate. Do I have to do someting like $currentdate=time(); //Then convert it into YYYY-MM-DD format? I'm trying to format a date to use in a mysql query and was wondering about the best way to do it. the form returns: mm/dd/yyyy and I need to format it to yyyy-mm-dd, any help would be greatly appretitaed, thanks in advance! I am trying to get the full date from form field using the date function and post method. $fromdate = $_POST[‘sdate’]; $todate = $_POST[‘edate’]; $fromday = date(‘F j, Y, g:i a’,’$fromdate’); $today1 = date(‘F j, Y, g:i a’,’$todate’); When trying to print i get the right format but i get extra information not sure from where? I am getting the date from the form fields of type date. Code Output: March 19, 2020, 4:16 pm,$31202019pm31Asia/Dubai why i am getting the second part! Hi Guys
In MYSQL the date format seems to be YYYY-MM-DD, when I use a dynamic table in Dreamweaver the date is also displayed this way, is there a simple way to change this to UK format DD-MM-YYYY?
What Date Format is this... Code: [Select] echo '<div class="date">Published: ' . date('F j, Y', strtotime($publishedOn)) . '</div>'; And where can I find a listing of the different Date and Time Formats that will work with this? (I would like to display my date as "2012-02-26 2:40pm" for what it is worth...) Thanks, Debbie Hi Guys, I'm sure i have done this before, is there a way to shorten dates like: December 16, 2010 to Dec 16, 2010 and January 16, 2010 to Jan 16, 2010 etc, i have used $dateFormatted2 = date("F j, Y", strtotime($d2)); to get the date format i have now. any help would be appreciated thansk guys Graham Hi guys I have this date script below which displays like so: 16/09/2011. Its fine but I now like it to display like this: 16 September 2011 Please I need help in twicking the code to do this Thanks! <?php //check to see if passing variable is set i.e. if true get day, month, year. if(isset($_GET['day'])){ $day = $_GET['day']; } else{ //Get today's date and put them in date, month, year $day = date("d"); } if(isset($_GET['month'])){ $month = $_GET['month']; } else{ $month = date("m"); } if(isset($_GET['year'])){ $year = $_GET['year']; } else{ $year = date("Y"); } echo $day."/".$month."/".$year; ?> Code: [Select] $date =date("d F Y"); It will display 18 October 2011. If I need it to display 2011-10-18. How do it go about coding it? I can't seem to get the syntax correct I want my date outputted as January 1st. Code: [Select] <span class="goal_head f_right mrm"><?php echo date($goal['complete_date'], 'F j'); ?></span> Hi Guys Could somebody tell me how i would put a line break into the code below i.e: 1.07 <br /> 2010 <?php echo date('d.m.Y',strtotime($news['created_at']));?> Thanks for your help Anyone know what's up with this? <?php $days = floor($posts['timestamp'] / (60 * 60 * 24)); $remainder = $posts['timestamp'] % (60 * 60 * 24); $hours = floor($remainder / (60 * 60)); $remainder = $remainder % (60 * 60); $minutes = floor($remainder / 60); $seconds = $remainder % 60; if($days > 0) { echo date("d/m/y", $posts['timestamp']); echo " at "; echo date("H:i", $posts['timestamp']); }elseif($days == 0 && $hours == 0 && $minutes == 0) { echo "few seconds ago"; }elseif($days == 0 && $hours == 0) { echo $minutes.' minutes ago'; }elseif($days == 0 && $hours > 0){ echo $hours.' hour ago'; }else{ echo "few seconds ago"; } ?> Hi there, i want to convert whatever a user inputs through and html form to a DATE format which when posted will be entered (using mysql) as that particular Date format , i'm using this: Code: [Select] $date = "12-12-11"; //assume this to be the user input $time = strtotime($date); $new_date = date("d/m/Y",$time); echo $new_date; but this format will give the output as: 11/12/2012.....is there a way to convert whatever the user enters to be: dd/mm/yyyy which gives: 12/12/2011 thanks so much I'm trying to make $time be a variable with the current time and I want it to have the same format as mysql. I can't figure out what I am doing wrong here Wrror: Warning: date_format() expects parameter 1 to be DateTime, integer given Code: [Select] $time = date_format(time(),'Y-m-d H:i:s'); Hey, I have a database with a date field that has the date in this format: August 2, 2010 11:04 pm I was wondering if it was possible to change this so I have the day, month and year in separate variables like this: $day = "2"; $month = "8"; $year = "2010"; Also notice how I have changed August to "8". I was wondering if there was an easy way around getting this done? Thanks in advance
I am currently using a product called PhPRunner.
when trying to get the date
var visitors_time = new Date();i'll being back a result like Mon Oct 27 2014 20:54:55 GMT+0000 (GMT Standard Time)my issue is, is there a way of getting the end part with the brackets to not show up? ie. format the date?...ive googled but doesnt seem no simple solution like php to actually format the date to the way you'd like it thank you guys I need to change the date format to DD-MM-YYYY. Please help. $SomeVar = $_POST['finco']; $query = "SELECT * FROM news_home WHERE code = '".$SomeVar."' ORDER BY timestamp DESC"; $results = mysql_query($query); $returnS=""; while($line = mysql_fetch_array($results)) { $returnS.= $line["subject"].",,".$line["timestamp"].",,".$line["News"].",,".$line["links"].",,,"; } echo $returnS; mysql_close($link); ?> check date is in format of Y-m-d |