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PHP - Update Multiple Tables
Need help in updating the tables
I have array of data coming from a form which I'm inserting in my DB. I have 5 tables product filter product_filter heater product_heater Im able to put the data in the "product", "filter" & "heater" tables but i dont know how to put data inside the "product_filter" & "product_heater" table. Any help or direction to any tutorails is appreciated. My Tables structu product id int(5) product text cost text details text filter id int(5) filter text imgpath text product_filter id int(5) id_product int(5) id_filter int(5) heater id int(5) heater text imgpath text product_heater id int(5) id_product int(5) id_heater int(5) Code: [Select] // Product data Update $name = mysql_real_escape_string($_POST['product']); $cost = mysql_real_escape_string($_POST['cost']); $details = mysql_real_escape_string($_POST['details']); $sql_title = "INSERT INTO product ( id , product , cost , details , ) VALUES ( NULL , '$name' , '$cost' , '$details')"; if (!mysql_query($sql_title,$con)) { die('Error: ' . mysql_error()); } echo "records for product added<br />"; // Filter update // This is the array which is coming from the form /* Array ( [0] => ehiem [1] => Hagan [2] => Rena [3] => jobo ) Array ( [0] => img1.jpg [1] => img2.jpg [2] => img3.jpg [3] => img4.jpg ) */ $filtername = mysql_real_escape_string($filtername); $filterimgpath = mysql_real_escape_string($filterimg); $combined_array = array_combine($filtername, $filterimgpath); $values = array(); foreach ($combined_array as $filtername => $filterimgpath) { $values[] = "('$filtername', '$filterimgpath')"; } $sql = "INSERT INTO filter (filter , imgpath) VALUES " . implode(', ', $values); //echo $lastid = mysql_insert_id()."<br />"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "records added<br />"; //Product Filter Update table // This is where Im stuck. Not able to even think of anything.... // heater update // This is the array which is coming from the form /* Array ( [0] => ehiem [1] => Dolphin [2] => Rena [3] => jobo ) Array ( [0] => img1.jpg [1] => img2.jpg [2] => img3.jpg [3] => img4.jpg ) */ $heatername = mysql_real_escape_string($heatername); $heaterimgpath = mysql_real_escape_string($heaterimg); $combined_array = array_combine($heatername, $heaterimgpath); $values = array(); foreach ($combined_array as $heatername => $heaterimgpath) { $values[] = "('$heatername', '$heaterimgpath')"; } $sql = "INSERT INTO heater (heater , imgpath) VALUES " . implode(', ', $values); //echo $lastid = mysql_insert_id()."<br />"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "records added<br />"; //Product heater Update table // This is where Im stuck. Not able to even think of anything.... Similar TutorialsAs the title says I need help with multiple update system.. Can't really get it to work at all >.< Here's some code: $selectt = mysql_query("SELECT * FROM exercises WHERE user='" . $_SESSION["user"] . "' AND exname='" . $_GET["edit"] . "'"); echo '<form method="POST" action="exercises.php?edited">'; echo '<div id="newexx">'; while($raw = mysql_fetch_array($selectt)) { echo '<input type="text" name="up[' . $raw["id"] . ']" value="' . $raw["swe"] . '">'; echo '<input type="text" name="up1[' . $raw["id"] . ']" value="' . $raw["eng"] . '"><br>'; echo '<input type="hidden" name="id[' . $raw["id"] . ']">'; } echo '</div>'; echo '<input type="submit" value="Update Exercise">'; echo '</form>'; if(isset($_GET["edited"])) { $swe = $_POST["up"]; $eng = $_POST["up1"]; $id = $_POST["id"]; foreach($id as $value => $index) { $update = "UPDATE exercises SET swe='".$swe."', eng='".$eng."' WHERE id='".$index."'"; mysql_query($update); } Would be thankful for reply! I have a form where a user can duplicate part of a form like below: I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories". $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; The above mysql statement works and returns values..BUT if say, I search "john" and "funny", and a quote is posted by the user "john", but has a category of "funny" it will output the same quote twice. I was wondering if there was a way to see if a quote has either 1 term or both terms, if so display that quote but only display it once. Below is what the query is outputting. [100] => Array ( [id] => 100 [username] => John [quote] => new test quote blah blah [by] => John [voteup] => 0 [votedown] => 0 [servtime] => 2010-12-02 @ 16:27:03 [label] => Array ( [0] => Historic [1] => Serious [2] => Funny ) ) Here is the code in full. //// $sword = explode(" ",$search); foreach($sword as $sterm){ $srch="%".$sterm."%"; echo"$srch<br />"; $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; $result=mysql_query($sql); while($row=mysql_fetch_object($result)){ $quote[$row->id]['id'] = $row->id; $quote[$row->id]['username'] = $row->username; $quote[$row->id]['quote'] = $row->quote; $quote[$row->id]['by'] = $row->by; $quote[$row->id]['voteup'] = $row->voteup; $quote[$row->id]['votedown'] = $row->votedown; $quote[$row->id]['servtime'] = $row->servtime; $quote[$row->id]['label'][] = $row->label; } echo"<pre>"; print_r($quote); echo"</pre>"; I don't think this is the fastest way of doing this, as it loops for each item in the db, per each keyword that is search. Any help would be great!! -BaSk I am trying to export multiple csv files to download from 2 separate tables in my database. Some background: I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization. The fields in my tables a location, firstname, lastname, username, extension, mac, type What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each. For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now: <form action="exportexiting.php" method="POST" style="width: 456px; height: 157px"> <div> <fieldset> <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend> <input name="Export" type="submit" id="Export" value="Export"> </fieldset><br/> </div> </form> This links to my exportexiting.php file: <?php $host = 'localhost'; $user = 'root'; $pass = 'xxxx'; $db = 'PhoneInventory'; $table = 'exiting'; // Connect to the database $link = mysql_connect($host, $user, $pass); mysql_select_db($db); require 'exportcsv.inc.php'; exportMysqlToCsv($table); ?> Then to exportcsv.inc.php: <?php function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = ''; $csv_escaped = "\\"; $sql_query = "select * from $table"; // Gets the data from the database $result = mysql_query($sql_query); $fields_cnt = mysql_num_fields($result); $schema_insert = ''; for ($i = 0; $i < $fields_cnt; $i++) { $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, stripslashes(mysql_field_name($result, $i))) . $csv_enclosed; $schema_insert .= $l; $schema_insert .= $csv_separator; } // end for $out = trim(substr($schema_insert, 0, -1)); $out .= $csv_terminated; // Format the data while ($row = mysql_fetch_array($result)) { $schema_insert = ''; for ($j = 0; $j < $fields_cnt; $j++) { if ($row[$j] == '0' || $row[$j] != '') { if ($csv_enclosed == '') { $schema_insert .= $row[$j]; } else { $schema_insert .= $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed; } } else { $schema_insert .= ''; } if ($j < $fields_cnt - 1) { $schema_insert .= $csv_separator; } } // end for $out .= $schema_insert; $out .= $csv_terminated; } // end while header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Length: " . strlen($out)); // Output to browser with appropriate mime type, you choose header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=$filename"); echo $out; exit; } ?> Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need? Thanks for the help... i have:
if( $stmt = $db_connect->prepare('UPDATE '.C_T_DRAGONS.' AS d, '.C_T_USERS.' AS u SET d.'.$prop.' = d.'.$prop.'+'.$val.', u.ap=u.ap-1 WHERE d.id = ? AND (SELECT u2.ap FROM '.C_T_USERS.' as u2 WHERE u2.id = ?) > 100') )
which echoes out as:
UPDATE dragons AS d, users AS u SET d.claws_dam = d.claws_dam+1, u.ap=u.ap-1 WHERE d.id = ? AND (SELECT u2.ap FROM users as u2 WHERE u2.id = ?) > 100and am getting the following response: Error : (1093) Table 'd' is specified twice, both as a target for 'UPDATE' and as a separate source for datawill this have to be done in 2 queries? did a little searching and im thinking maybe the subquery is being refused? Edited by BuildMyWeb, 04 December 2014 - 04:35 PM. Hi all I have 2 tables: 1. is a tables full of images that have an id, a src and a title (images_table). 2. table is a list of records with an id, a description and an images_id (records_table) What I'm looking to do is: Loop through the records in the records_table and find the description, the description is something like this 'Welcome to Kansas'. Then, I want to loop through the images_table and find the associated image of Kansas, based on a MySQL LIKE statement. This is because the images_table has a title of 'Kansas', for example. Once this has been done, I then need to insert the id of Kansas into the images_id in the records_table a possible MySQL UPDATE. Has anyone got an idea how I could do this? Thanks Hi coders,
im trying to update multiple rows of record using check-box and have a default value "RCV" and now im getting difficulties since im new in CI and any body can help and solve or can improve this code below.
view
<tr> <td><input type = "hidden" value = "<?php echo $row->pull_out_id ?>" name = "po_id"></td> <td><input type="checkbox" class="case" name="case" value="rcv"/></td> </tr>controller
public function update_po_receive()
{
$po_id = $this->input->post('po_id');
$this->public_base_model->update_po_receive($po_id);
redirect('public_base/search_stocks', 'refresh');
}
model
public function update_po_receive($po_id)
{
$data = array('temp' => $this->input->post('case'));
$this->db->where('pull_out_id', $po_id);
$this->db->update('pull_out', $data);
}
I am using multiple levels of JSON data coming into php from a C# application, as in:
return new RootObject() { ID_Project = 4, Name_Project = "Test", Receiver_ID = 4, Receiver_Name = "ABCDE", UserID = 20, UserRole = new User_Role() { ID_User = 20, Role_User = "level 3", User_Role_Description = "U", UserGroup = new List<user_group>() { new User_Group() { ID_UserGroup = 30, Name_UserGroup = "usergroup8", UserID = 20 }, new User_Group() { ID_UserGroup = 31, Name_UserGroup = "usergroup9", UserID = 21 }, new User_Group() { ID_UserGroup = 32, Name_UserGroup = "usergroup10", UserID = 22 } } } }; i am having troubles accessing the second level: UserRole and 3rd level: User_Group in my php script. im currently trying like this: foreach ($phpArray as $key => $value) { echo "<h2>$key</h2>"; foreach ($value as $k => $v) { echo "$k | $v "; foreach ($v as $key1) { echo "$key1 "; } } } does anyone have an idea? Thanks, Revathy hey can someone advice me on how to make my update script update multiple rows. here's what i've got so far: update.php <?php require('connect.php'); $update = mysql_query("SELECT DISTINCT rideName FROM ride ORDER BY rideName DESC" ); $numrows = mysql_num_rows($update); echo "<form action='mysql_update.php' method='POST'> <select name='updateRide' >"; while ($row=mysql_fetch_assoc($update)) { #$rideID = $row ['rideID']; $rideName = $row ['rideName']; #$seatNumber = $row ['seatNumber']; #$time = $row ['time']; #$price = $row ['price']; echo "<option value='$id'> $rideName </option>"; } echo "</select> <input type='text' name='tochange'> <input type='submit' name='submit' value='change'> </form>"; ?> and now the handler script: mysql_update.php <?php require ('connect.php'); $updateRide=$_POST['updateRide']; $tochange=$_POST['tochange']; if ($updateRide&&$tochange) { $change = mysql_query("UPDATE ride SET rideName='$tochange' WHERE $id='updateRide'"); } ?> When I try this I get nothing, no changes. In the table there is 3 distinct rideNames each have more than 20 rows. Is there a way using the drop down box and ext field like i Have to update all of the distinct rideNames in the table? Thanks. I have a code that I am using to update multiple products at one time instead of one at a time. It works great except that my processing page is not updating the very last product. My process page is receiving all of my products as I know how many products that I am updating and I have my process page tell me how many products are updated as well as listing the name of each product updated. It is always the last product that is not updated. Here is my process update code. Code: [Select] <?php $size = count($_POST['casketid']); //$size = 306; $i = 1; while ($i < $size) { $product=$_POST['productid'][$i];//getting case # $price=$_POST['price'][$i]; $model=$_POST['model'][$i]; $active=$_POST['active'][$i]; //Getting pricerange if(($price > "0") && ($price <= "1000.00")) $pricerange = "1"; elseif(($price >= "1001.00") && ($price <= "1500.00")) $pricerange = "2"; elseif(($price >= "1501.00") && ($price <= "2000.00")) $pricerange = "3"; elseif(($price <= "2001.00") && ($price <= "2500.00")) $pricerange = "4"; elseif(($price <= "2501.00") && ($price <= "3000.00")) $pricerange = "5"; elseif(($price >= "3001.00") && ($price <= "3500.00")) $pricerange = "6"; elseif(($price >= "3501.00") && ($price <= "4000.00")) $pricerange = "7"; elseif(($price >= "4001.00") && ($price <= "4500.00")) $pricerange = "8"; elseif(($price >= "4501.00") && ($price <= "4500.00")) $pricerange = "9"; elseif($price >= "5001.00") $pricerange = "10"; $query = "UPDATE products SET price='$price', pricerange='$pricerange', active='$active' WHERE productid='$product'"; mysql_query($query) or die ("Error in query: $query"); echo "$model = $price & active = $active</em><br />$size<br />"; ++$i; } ?> Ok, so I need to know how I can get these codes to interact and work to update multiple rows/columns in a database. this code is what pulls the query and displays info(it displays fine): Code: [Select] <?php if (isset($_POST['submitted'])) { include('connect1.php'); $category = $_POST['category']; $criteria = $_POST['criteria'] ; $query = ("SELECT name, badges, rank, userid FROM members WHERE $category LIKE '%".$criteria."%'"); $result = mysqli_query($dbcon, $query) or die('error getting data'); $num_rows = mysqli_num_rows($result); echo "$num_rows results found"; echo "<table width=\"896\" border=\"0\" cellspacing=\"0\" cellpadding=\"0\">"; echo "<tr bgcolor=\"#F7E496\"><td bgcolor=\"#F7E496\"><strong>name</strong></td><td bgcolor=\"#F7E496\" ><strong>Merit Badges</strong></td><td bgcolor=\"#F7E496\"><strong>Rank</strong></td><td bgclor=\"#F7E496\"></td></tr>"; while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {$color = ($color == 'white')?'#fffccc':'white'; echo "<tr bgcolor='$color'><td> "; echo $row['name']; echo " </td><td> <form action=\"scout.php\" method=\"post\"> <input type=\"text\" name=\"userid\" id=\"userid\" value='".$row['userid']."'> <textarea name=\"badges[]\" id=\"badges\" cols=\"40\" rows=\"3\" type=\"textarea\">".$row['badges']."</textarea></td><td> <span class=\"adfa\"> </span> <select name=\"rank[]\" id=\"rank\"> <option value=\"Scout\">Scout</option> <option value=\"Tenderfoot\">Tenderfoot</option> <option value=\"Second Class Scout\">Second Class Scout</option> <option value=\"First Class Scout\">First Class Scout</option> <option value=\"Star Scout\">Star Scout</option> <option value=\"Life Scout\">Life Scout</option> <option value=\"Eagle Scout\">Eagle Scout</option> <option value=\"\" selected=\"selected\">".$row['rank']."</option> </td><td>"; } echo "</td></tr>"; echo "</table>"; echo "<input type=\"submit\" name='submit[]' id=\"submit\" value=\"Save\" /> </form>"; } ?> and this code is what is supposed to update the database: Code: [Select] if ($_POST[submit]){ foreach ($_POST[rank] as $key => $value) { $badges = $_POST['email1'][$key]; $userid1 = $_POST['userid'][$key]; $q = "UPDATE members SET badges='$badges', rank='$rank' where userid='$userid1'"; $sql = mysql_query($q) or die("Problem with the query: $q<br>" . mysql_error()); printf("Records updated: %d\n", mysql_affected_rows());} exit(); } // close if post again, I am really new to arrays and don't know If i am using them right here......... I have ran this code before and it worked but not it won't update. Can anyone see what I am doing wrong? Code: [Select] <? if(isset($_POST[sort_invest])) { // if form was submitted $id = $_POST['sel_record']; $sort = $_POST['sort']; for($i=0;$i<$count;$i++){ $sql = "UPDATE invest SET id='$id[$i]', sort='$sort[$i]' WHERE id='$id[$i]'"; $sql_result = mysql_query($sql,$con) or die (mysql_error()); } } // if form was submitted or if it came from another page if (isset($_POST['order_invest']) || isset($_POST['sort_invest'])) { ?> <p><strong>Order Invest</strong></p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <? $sql = "SELECT id, sort, title FROM invest ORDER BY sort ASC"; $sql_result = mysql_query($sql,$con) or die(mysql_error()); while ($row = mysql_fetch_array($sql_result)) { $id = $row["id"]; $title = $row["title"]; $sort = $row["sort"]; ?> <input type="hidden" name="sel_record[]" value="<? echo "$row[id]"; ?>"> <table width="545" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="69"><input type="text" name="sort[]" value="<? echo "$row[sort]"; ?>" size="3"></td> <td width="476"><? echo "$row[title]"; ?></td> </tr> </table> <br> <? } } ?> <input name="sort_invest" type="submit" value="Sort"> </form> Only the last row will update when I submit. I have this form (and one nerve left): <form action="" method="post" > echo" <input style=\"text-align:center\" type=\"text\" name=\"linkorder\" value=\"".$row['order']."\" /> <input type=\"hidden\" name=\"id\" value=\"".$row['id']."\"/> "; <input type="submit" name="updateorder" value="Save Order" /> </form> On Submit: if (isset($_POST['updateorder'])){ connect(); $changeorder = mysql_unbuffered_query("update links set `order` = '".$_POST['linkorder']."' where id = '".$_POST['id']."'") or die(mysql_error()); } I was going put my fist through the monitor but then I remembered I could get help here. Thank you! can anyone see anything wrong here?? it wont update the Ships table.. i should of gone bed hours ago but its bugging me: <?php $sql="SELECT * FROM ships ORDER BY auction='Yes' DESC"; $result=mysql_query($sql); // Count table rows $count=mysql_num_rows($result); ?> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <form name="form1" method="post" action=""> <tr> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td align="center"><strong>Active?</strong></td> <td align="left"><strong>typeID</strong></td> <td align="left"><strong>Item Name</strong></td> <td align="left"><strong>Base Price</strong></td> <td align="left"><strong>Market Price</strong></td> <td align="center"><strong>Auction</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <?php if ($rows['auction'] != "Yes") { ?> <td align="center"><img src="../images/site/delete.png" /></td> <?php } else { ?> <td align="center"><img src="../images/site/accept.png" /></td> <? } ?> <td align="left"><span class="isk"> <? $typeID[]=$rows[typeID]; ?> <? echo $rows['typeID']; ?></span></td> <td align="left"><span class="eveyellow"><? echo $rows['typeName']; ?></span></td> <td align="left"><span class="normal"><?php echo number_format($rows['basePrice'])?> isk</span></td> <td align="left"><input name="marketPrice[]" type="text" size="10" id="marketPrice" value="<? echo $rows['marketPrice']; ?>"> <span class="credits">(<?php echo number_format($rows['marketPrice']/1000000, 2)?> m)</span></td> <td align="center"><input name="auction[]" type="text" size="6" id="auction" value="<? echo $rows['auction']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </td> </tr> </form> </table> <?php // Check if button name "Submit" is active, do this if($Submit){ for($i=0;$i<$count;$i++){ $sql1="UPDATE ships SET marketPrice='$marketPrice[$i]', auction='$auction[$i]' WHERE typeID='$typeID[$i]'"; $result1=mysql_query($sql1); } } if($result1){ header("location:ship.php"); } mysql_close(); ?> typeID is my primary key in the table and i only want to update "marketPrice" and "auction" upon submit. its a update multiple rows form by the way. thank you so much for helping me... again.. would be lost without phpfreaks. hi i was working on a code where i need to use multiple categories for a post, i get help before to add post in multi categories, now i need help on what would be my query to do update for a multiple categories post, to insert a new post with multiple categories i used this $values = array(); foreach($_POST['categories'] as $catID) { $values[] = "($postID, $catID)"; } $sql = "INSERT INTO `relation` (`postid`, `catid`) VALUES " . implode(', ', $values); $query = $db->query($sql); so if a post had 3 categories it will add in relation table, now i wants to update that post and modify the categories, all other part is done only problem is to update this relational category table which have two columns only associated with post. i tried like this but did not work $sql = "UPDATE relation SET `catid` = " . implode(', ', $values) . " WHERE postid ='$id' "; please any help ok, so I have this code: Code: [Select] <?php if (isset($_POST['submitted'])) { include('connect1.php'); $category = $_POST['category']; $criteria = $_POST['criteria'] ; $query = ("SELECT name, badges, rank, userid FROM members WHERE $category LIKE '%".$criteria."%'"); $result = mysqli_query($dbcon, $query) or die('error getting data'); $num_rows = mysqli_num_rows($result); echo "$num_rows results found"; echo "<table width=\"896\" border=\"0\" cellspacing=\"0\" cellpadding=\"0\">"; echo "<tr bgcolor=\"#F7E496\"><td bgcolor=\"#F7E496\"><strong>name</strong></td><td bgcolor=\"#F7E496\" ><strong>Merit Badges</strong></td><td bgcolor=\"#F7E496\"><strong>Rank</strong></td><td bgclor=\"#F7E496\"></td></tr>"; while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {$color = ($color == 'white')?'#fffccc':'white'; echo "<tr bgcolor='$color'><td> <input type=\"text\" name=\"userid\" id=\"userid\" value='".$row['userid']."'>"; echo $row['name']; echo " </td><td> <form action=\"scout.php\" method=\"post\"> <textarea name=\"badges\" id=\"badges\" cols=\"40\" rows=\"3\" type=\"textarea\">".$row['badges']."</textarea></td><td> <span class=\"adfa\"> </span> <select name=\"rank\" id=\"rank\"> <option value=\"Scout\">Scout</option> <option value=\"Tenderfoot\">Tenderfoot</option> <option value=\"Second Class Scout\">Second Class Scout</option> <option value=\"First Class Scout\">First Class Scout</option> <option value=\"Star Scout\">Star Scout</option> <option value=\"Life Scout\">Life Scout</option> <option value=\"Eagle Scout\">Eagle Scout</option> <option value=\"\" selected=\"selected\">".$row['rank']."</option> </td><td>"; echo "<input type=\"submit\" name=\"submit\" id=\"submit\" value=\"Save\" /> "; echo "</form>"; } echo "</table>"; echo "</td></tr>"; } ?> and this is the code that does the posting: Code: [Select] <?php session_start(); // Must start session first thing /* Created By Adam Khoury @ [URL=http://'http://www.flashbuilding.com/']www.flashbuilding.com[/URL] -----------------------June 20, 2008----------------------- */ // Here we run a login check if (!isset($_SESSION['id'])) { echo 'Please <a href="login.php">log in</a> to access your account'; exit(); } //Connect to the database through our include include_once "connect_to_mysql.php"; // Place Session variable 'id' into local variable $userid = $_SESSION['id']; // Query member data from the database and ready it for display // Process the form if it is submitted if ($_POST['submit']) { $badges = $_POST['badges']; $userid = $_POST['userid']; $rank = $_POST['rank']; $sql = mysql_query("UPDATE members SET badges='$badges', rank='$rank' WHERE userid='".$_GET['userid']."'"); printf("Records updated: %d\n", mysql_affected_rows()) ; exit(); } // close if post ?> So what I need to know is how I can make it so that each result has it's user id associated with it......and I can update multiple rows at once according to each userid that is associated..........right now I can only get it to do one if I add on ?userid=".$row['userid']." in the first piece of code.......how can I make it update lets say 78 as soon as I click submit...... PS I know there will be a submit button with each row right now.......I will move it out of the loop later..... Hi there, Im fairly new at php and mysql but nevertheless im trying to build a web based campaign game for starwars minatures boardgame. Its fairly straightforward and going well.. However ive been thinking about how it will work and have stumbled across a possible problem (because of my limited craft at programming). I want to have a single form that updates all records in the tables, this would simulate an "end of turn" button. Im sure i can do this if doing stuff in the game (e.g. move, create , modify, delete, fleets/ships and auto increment ships hulls simulating repair) if it was done on the same page. However i wanted to to initiate some of these adjustments in their respective pages (fleet.php, planets.php, ships.php etc) and then once the user is happy to click the end turn button somewhere which would update all of these things at the same time.. Is this possible at all??? If anybody could help that would be brilliant. Thank you p.s. if anybody wants a copy of the finished product when its complete, your most welcome. This has been bugging me for quite a while and I've tried so many different things and just run into all kinds of problems... What I'm doing or trying at least is pulling data from a table displaying it into a multiple select box allowing the user the oppertunity to remove one or more options. As the code stands now I'm getting no value at all in the post variable, by taking the [] brackets out of the inputs name i was able to get the first selected option but the php code was then unable to remove that value from the database. I hope I'm explaining this well enough but the code follows I'd really appreciate some help or direction on this one. The FORM Code: [Select] <FORM action='' method='post'> <select size='8' multiple name='remove_player[]'> <?php foreach ($members as $key => $mem) { if ($mem != "") { $mem = str_replace("-", " ", $mem); $mem = ucwords($mem); echo ("<option value='" . $mem . "'>" . $mem . "</option>"); } } ?> </select> and then the handler code: Code: [Select] $to_remove = $_POST['remove_player']; $as_team = str_replace(" ", "-", $teamname); $as_team = strtolower($as_team); $for_remove = "SELECT * FROM teams WHERE name = '$as_team'"; $for_query = (mysql_query($for_remove)); foreach ($to_remove as $y => $z) { $z = str_replace(" ", "-", $z); $z = strtolower($z); } while($arr_remove = mysql_fetch_array($for_query)) { foreach ($arr_remove as $a => $b) { foreach ($to_remove as $c => $d) { if ($b == $d) { unset($arr_remove[$a]); } } } foreach ($arr_remove as $e => $f) { $add_replace = (mysql_result($for_query, 0, 'members')); $replace = ($add_replace . "\r\n" . $f . "\r\n"); $replace_mem = "UPDATE teams SET members = '$replace'"; $replace_q = (mysql_query($replace_mem)); } } echo "Member List successfully updated.<br>"; foreach ($to_remove as $h => $g) { echo ($g . " removed from the team.<br>"); } Also any time i try to print any part of the array/s I get no values but the database is being updated with 2 line breaks and a "3" at the end of the table which has me a bit confused as well. Thanks! Hi ive been stuck for a while now and i just cant get my head around it so if you could help i'd be well chuffed. I'm trying to update multple rows in a table depending upon the results of another. I have a form that enables me to update a table called fleet. Another table called ships is realted to the fleet table as each ship is in a fleet: fleet ----- Fleetname* Location Detected ships ------ ShipID* Fleetname * Shipname The particular fleet i am editing is parsed as a url parameter. I made a query to search for all the ships that are in the fleet i am editing: Code: [Select] $colname_ShipsInfleet = "-1"; if (isset($_GET['recordID'])) { $colname_ShipsInfleet = (get_magic_quotes_gpc()) ? $_GET['recordID'] : addslashes($_GET['recordID']); } mysql_select_db($database_swb, $swb); $query_ShipsInfleet = sprintf("SELECT * FROM ships WHERE FleetName = %s", GetSQLValueString($colname_ShipsInfleet, "text")); $ShipsInfleet = mysql_query($query_ShipsInfleet, $swb) or die(mysql_error()); $row_ShipsInfleet = mysql_fetch_assoc($ShipsInfleet); $totalRows_ShipsInfleet = mysql_num_rows($ShipsInfleet); It searched the ships WHERE the FleetName (which is the primary key of the fleet table) is parsed as a url parameter. The appropriate ship records that are generated i want to use so a field can be updated. For example im updating a fleet record and and setting the location (Planet Name) to a different value. I want the Ship records that are of that particular fleet to update a field (PlanetName) in ship table when the fleet table is updated. Code: [Select] if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE ships WHERE ShipID = $row_ShipsInfleet['ShipID'] SET PlanetName=%s", GetSQLValueString($_POST['select'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); $updateSQL = sprintf("UPDATE fleet SET PlanetName=%s, Detected=%s, Faction=%s WHERE FleetName=%s", GetSQLValueString($_POST['select'], "text"), GetSQLValueString(isset($_POST['checkbox']) ? "true" : "", "defined","1","0"), GetSQLValueString($_POST['hiddenField2'], "int"), GetSQLValueString($_POST['hiddenField'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); I'm really not sure how to proceed here so please if you can help me out that would be ace. Thank You |
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