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PHP - Mysql Query Doesn't Work. [insert Query]
If you also have any feedback on my code, please do tell me. I wish to improve my coding base.
Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> Similar TutorialsI have created a registration page to access my website. After the user registrate himself should appear an alert saying that the registration was OK and a redirect to main.php page... however for some reason if I create an insert statement the alert and the redirect don't appear... If I remove the insert the alert and the redirect works... why? This is part of the code of my 3 files: registration.php (ajax call) $('#submit').click(function() {var username2 = $('#uname2').val(); var password2 = $('#psw2').val(); $.ajax({ url: 'ajax/response.php', type: 'GET', data: {username2 : username2, password2: password2}, success: function(data) { if(data === 'correct') { alert("Username and Password have been created!"); //don' work with the insert location.replace("main.php"); //don' work with the insert } else { alert("Username or password are not correct... please register yourself!"); } } }); }); response.php (answer to ajax call) if(isset($_GET['username2']) && isset($_GET['password2'])) {$username2 = $_GET['username2']; $password2 = $_GET['password2']; if (checkUser($pdo, $username2) === true) { echo 'duplicate'; } else { insertUserPwd($pdo, $username2, $password2); //including this line the redirect and the alert doesn't work... the insert is OK echo 'correct'; } } data_access.php (the function works but doesn't permit alert and redirect to appear) function insertUserPwd(PDO $pdo, $usr, $pwd){ $data = [ 'id' => '', 'user' => $usr, 'password' => $pwd ]; $sql = "INSERT INTO users (id, user, password) VALUES (:id, :user, :password)"; $stmt= $pdo->prepare($sql); $stmt->execute($data); } Can someone help me to fix the code? Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = $_POST['username']; $password = $_POST['password']; $name = $_POST['name']; $server_type = $_POST['type']; $description = $_POST['description']; if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings! All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = $db->prepare("SELECT username,name FROM servers WHERE username = ? OR name = ? LIMIT 1"); $check1->execute(array($username, $name)); if($check1->rowCount() > 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; $insertQuery = $db->prepare("INSERT INTO servers (id, username, password, name, type, description, ip, votes, beta) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)"); $insertQuery->execute(array(null, $username, $password, $name, $server_type, $description, $ip, 0, 1)); if($insertQuery->errorInfo() > 0) { echo "Sorry, there was the following error:"; print_r($insertQuery->errorInfo()); } else { echo "Server has been succesfully created!"; } } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> Whats wrong with that page? :/
Hi, this query runs fine when I run it from PHPMyAdmin: UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1 However, when I run the same query in a PHP file on my server, the page doesn't load at all. The message I get is: www.somesite.com is currently unable to handle this request. HTTP ERROR 500. This is my PHP code:
<?php
include("/database/connection/path/db_connect.php");
$result4 = mysqli_query($GLOBALS["___mysqli_ston"], "UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1");
echo $result4;
?>
So how do I make this query work please? Thanks for your guidance. Another issue with trying to work on somebody else's script (and on no sleep!) I've got this mess of a page I'm trying to manipulate to add a feature to. When somebody goes to this page, it pulls all records. At the top, I added a way to refine the results by dates. That query works fine, I tested it in mysql. To avoid fighting with the original code, I created an if statement to create $query_selectAll. But when I put it in the page, it would just refresh with the same data. I echoed the query to make sure it is correct. Then I realized that there was another query, $query_selectAllItems, further down the page that was generating the results, and none of what I was doing made a difference. But I'm not sure why it's ignoring my query or how to work around this. I tried deleting the query $query_selectAllItems, thinking it would take mine, because it ends with the same: $result_all $result_all = mysql_query($query_selectall); or $result_all = mysql_query($query_selectAllItems); Code: [Select] <?php require_once('calendar/classes/tc_calendar.php'); include("include/auth.php"); include("include/conn.php"); @$a_row = mysql_fetch_array($result); // I added this if statement in to get my POST results, without having to make changes to the GET results he made. if (isset($_POST['view'])){ $view=$_POST['view']; } else { $view=$_GET['view']; } if ($view=="All") { $query_selectall = 'select * from tbl_registration'; echo $query_selectall; } elseif ($view=="dated") { $mydate = isset($_REQUEST["date5"]) ? $_REQUEST["date5"] : ""; $end_date = isset($_REQUEST["date6"]) ? $_REQUEST["date6"] : ""; $query_selectall = "SELECT * FROM tbl_registration WHERE reg_timestamped BETWEEN STR_TO_DATE('$mydate', '%Y-%m-%d') AND STR_TO_DATE('$end_date' , '%Y-%m-%d')"; echo $query_selectall; } else { $query_selectall = "select * from tbl_registration where category='$view'"; echo $query_selectall; } $result_all = mysql_query($query_selectall); @$numRows_all = mysql_num_rows($result_all); ?> <title>WYF Admin</title> <html> <head> <script language="javascript" src="calendar/calendar.js"></script> <link href="include/styles.css" rel="stylesheet" type="text/css"> <SCRIPT language="JavaScript"> <!-- function confirm_delete(idval) { var verify= confirm("Do you really want to delete this Registration?"); if (verify== true) { window.location="delete_registrations.php?action=delete&did=" + idval; } } //--> </SCRIPT> <script type="text/javascript" src="js/jquery-latest.js"></script> <script type="text/javascript" src="js/jquery.tablesorter.js"></script> <script type="text/javascript"> $(function() { $("table").tablesorter({debug: true}); }); </script> </head> <body leftmargin="0" rightmargin="0" bottommargin="0" topmargin="0" cellspacing="0" cellpadding="0" bgcolor="ffffff"> <table width="100%"><tr><td align="left"><img src="images/logo.jpg"></td></tr> <tr><td><hr></td></tr> </table> <table><tr><td valign="top"> <table cellspacing="1" cellpadding="0" bgcolor="#cccccc" border="0" width="300"> <tr><td> <table cellspacing="0" cellpadding="0" width="300" height="400" bgcolor="#ffffff" border="0"> <tr><td align="left" valign="top"> <table width="250"><tr><td valign="top"> <b>Welcome </b><br><br> <?php //$query_selectAllItems = "SELECT *, DATE_FORMAT(workshop_date, '%e-%m-%Y') as 'my_date' FROM tbl_workshops"; $query_selectAllItems = "SELECT * FROM tbl_registration"; $result_all = mysql_query($query_selectAllItems); $numRows_all = mysql_num_rows($result_all); ?> <? include "include/nav.php"; ?> </td></tr></table></center> </td></tr> <tr><td></td></tr></table></tr></td></table> </td><td valign="top"> <div style="float:left;padding-right:40px;"><a href="getcsv.php">export to csv</a></div><div> <div style="float:right;margin-right:100px;"><form name="form1" method="post" action="viewregistrations2.php"><div style="float:left;overflow:visible;padding-right:10px;">View between</div> <div style="float:left;overflow:visible;padding-right:10px;"> <?php $myCalendar = new tc_calendar("date5", true, false); $myCalendar->setIcon("calendar/images/iconCalendar.gif"); $myCalendar->setDate(date('d'), date('m'), date('Y')); $myCalendar->setPath("calendar/"); $myCalendar->setYearInterval(2000, 2015); $myCalendar->dateAllow('2008-05-13', '2015-03-01'); $myCalendar->setDateFormat('j F Y'); $myCalendar->setAlignment('left', 'bottom'); $myCalendar->setSpecificDate(array("2011-04-01", "2011-04-04", "2011-12-25"), 0, 'year'); $myCalendar->setSpecificDate(array("2011-04-10", "2011-04-14"), 0, 'month'); $myCalendar->setSpecificDate(array("2011-06-01"), 0, ''); $myCalendar->writeScript(); ?> </div> <div style="float:left;overflow:visible;padding-right:10px;"> and </div> <div style="float:left;overflow:visible;padding-right:10px;"> <?php $myCalendar = new tc_calendar("date6", true, false); $myCalendar->setIcon("calendar/images/iconCalendar.gif"); $myCalendar->setDate(date('d'), date('m'), date('Y')); $myCalendar->setPath("calendar/"); $myCalendar->setYearInterval(2000, 2015); $myCalendar->dateAllow('2008-05-13', '2015-03-01'); $myCalendar->setDateFormat('j F Y'); $myCalendar->setAlignment('left', 'bottom'); $myCalendar->setSpecificDate(array("2011-04-01", "2011-04-04", "2011-12-25"), 0, 'year'); $myCalendar->setSpecificDate(array("2011-04-10", "2011-04-14"), 0, 'month'); $myCalendar->setSpecificDate(array("2011-06-01"), 0, ''); $myCalendar->writeScript(); ?> </div> <div style="float:left;overflow:visible;padding-right:10px;"><input type="hidden" name="view" id="view" value="dated"><input type="submit" value="go!"> </div></form> </div><br><br><br><br> <table width="95%" border="1" cellpadding="3" cellspacing="1" bordercolor="#999999" id="rowspan" class="tablesorter" name="table"><thead> <tr bgcolor="#ffffff"> <th width="125">Name</th> <th width="125">Address</th> <th width="125">Phone</th> <th width="125">Email</th> <th width="125">Workshop</th> <td width="50"> </td> <td width="50"> </td><td> </td> </tr></thead> <tbody> <? //output each row while ($c_row = mysql_fetch_array($result_all)){ ?> <tr> <td><?= $c_row['reg_fname'] ?> <?= $c_row['reg_lname'] ?></td> <td><?= $c_row['reg_address'] ?></td> <td><?= $c_row['reg_phone'] ?></td> <td><?= $c_row['reg_email'] ?></td> <td> <?php $catid = $c_row['reg_workshopid']; $query="SELECT * FROM tbl_workshops where workshop_id = '$catid'"; //Run query; $result=@mysql_query($query); $row=mysql_fetch_array($result); ?> <?php echo($row['workshop_title']); ?> </td> <td width="50" bgcolor="#DEE1EB"><div align="center"><a href="edit_registration.php?id=<? print $c_row['reg_id'] ?>">edit</a></div></td> <td width="50" bgcolor="#DEE1EB"><div align="center"><a href="javascript://" onClick="confirm_delete(<? print $c_row['reg_id'] ?>); return false">delete</a></div></td> <td width="50" bgcolor="#DEE1EB"><div align="center"><a href="printregistration.php?regid=<? print $c_row['reg_id'] ?>">view all / print</a></div></td> </tr> <? } //end while ?> </tbody> </table><br><br> </td></tr></table> Hey, $todo_upgrades_sql = "SELECT * FROM todo_upgrades WHERE time_completion >= $time"; $todo_upgrades_res = mysql_query($todo_upgrades_sql) or die (mysql_error()); results: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 Hi all, Perhaps, let me briefly explain what I would like to achieve. Currently I am using INNER JOIN command to link 4 sql tables 1) tutor_overall_level_subject.sql 2) tutor_subject_level.sql 3) tutor_level.sql 4) tutor_subject.sql In tutor_level.sql, there are 11 'level_id' level id 1 == Pre-School level id 2 == Lower Primary School level id 3 == Upper Primary School level id 4 == Lower Secondary etc.... As you can see from the code below, I am trying to retrieve 'lower primary' records only and place it in a table Subsequently, 'upper primary' records and place it in another table However when I executed the code, I receive a blank page. What could have gone wrong? Thanks if ($row3['level_id'] == 2){} if ($row3['level_id'] == 3){} Code: [Select] <?php //Retrieve Lower Primary if ($row3['level_id'] == 2) { echo'<table><tr>'; echo '<td class="label">Lower Primary</td>'; $count = 0; while($row3 = mysqli_fetch_array($data3)) { if ($count % 5 == 0) { echo "</tr><tr>"; $count = 0; } echo '<td>' . $row3['subject_name'] . '</td>'; $count++; } echo '</tr></table><br/>'; } //Upper Lower Primary if ($row3['level_id'] == 3) { echo'<table><tr>'; echo '<td class="label">Upper Primary</td>'; $count = 0; while($row3 = mysqli_fetch_array($data3)) { if ($count % 5 == 0) { echo "</tr><tr>"; $count = 0; } echo '<td>' . $row3['subject_name'] . '</td>'; $count++; } echo '</tr></table><br/>'; } ?> //This is my complete code Code: [Select] <?php $query3 = "SELECT sl.level_id, sl.subject_id, tl.level_name AS level_name, ts.subject_name AS subject_name " . "FROM tutor_overall_level_subject AS ols " . "INNER JOIN tutor_subject_level AS sl USING (subject_level_id) " . "INNER JOIN tutor_level AS tl USING (level_id) " . "INNER JOIN tutor_subject AS ts USING (subject_id) " . "WHERE ols.tutor_id = '" . $_GET['tutor_id'] . "'"; $data3 = mysqli_query($dbc, $query3) or die(mysqli_error($dbc)); if (mysqli_num_rows($data3) > 0) { echo '<div id="panel4">'; if ($row3['level_id'] == 2) { echo '<td class="label">Lower Primary</td>'; echo'<table><tr>'; $count = 0; while($row3 = mysqli_fetch_array($data3)) { if ($count % 5 == 0) { echo "</tr><tr>"; $count = 0; } echo '<td>' . $row3['subject_name'] . '</td>'; $count++; } echo '</tr></table><br/>'; } echo '</div>'; //End of panel 4 ?> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321864.0 Hello Friends, Now i m stuck with simple insert query . here's the code Code: [Select] <?php include_once("conf.php"); $firstName=$_POST['fname']; $lastName=$_POST['lname']; $email=$_POST['email']; $dob=$_POST['dob']; $password=$_POST['pass']; $fname= stripslashes($firstName); $lname=stripslashes($lastName); $mail= mysql_real_escape_string($email); $password= mysql_real_escape_string($password); mysql_select_db('site'); $statement="Insert into Accounts(Name,lastName,emailId,DOB,password) VALUES($fname,$lname,$mail,$dob,$password)"; $query=mysql_real_escape_string($statement); mysql_query($query) or die("Cannot save data:</br> ".mysql_error()); echo "Data Saved Successfully"; ?> Now please explain me why i m getting the following error Cannot save data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '@gmail.com,1988/12/20,password)' at line 1 Any help will be highly appreciated! Hello every body,, i want to create a new database (auto generate duty assigned using form) in PHP and mysql..
i have four input fields:-
Name, Subject, Class & weekly lectures
now i want to insert name,subject & class into database, when i insert number of weekly lecture in field four..
insert automaticlly in database multiple time which i write in field four (weekly lecture)
database: table structure i have already is:::
id-name-subject-class-period-monday-tuesday-wednesday-thursday-friday-saturday
anybody please help me to create this database or just insert query ....
Hi, Here is an extract of my while loop while ($personquery = mysql_fetch_array($personfetch, MYSQL_ASSOC)) { echo "$personfetch[first_name]"; } This will list each person now I want to do an INSERT to the database on every single member that is being listed I can only get it to INSERT for the one. Thanks I have tried many ways of storing an array of data that comes from a multiple selection form into a mysql table, including serialization. I am currently trying to do it by forming a string, and using the string in the insert query, but keep getting errors, or just nothing happening. I am not sure what I am doing wrong. Code: [Select] $categoryString = array(); if ($categoryArray){ foreach ($categoryArray as $category){ $categoryString[] = $category.'<br />';} } $categoryquery= "INSERT INTO categoryname VALUES('$categoryString')"; mysql_query($categoryquery); Thank you for your time as always. Hello, I am trying to pick up php again and just exercising my skills. So I have it so that it fills my form with the values of what I want to edit, and when I click the edit button, it doesn't edit any of the information. When I echo out $result, I get a MYSQL query string that has the same values as the table, so its not getting the new values that are edited. <?php @mysql_connect('localhost', 'root', '') or die("Could not connect to Mysql Server. " . mysql_error()); @mysql_select_db('tutorials') or die("Could not connect to Database. " . mysql_error()); if(isset($_GET['edit'])) { $id = $_GET['edit']; $query = "SELECT `username`, `password` FROM `users` WHERE `id` = '$id'"; $result = mysql_query($query); $row = mysql_fetch_array($result); $name = $row['username']; $password = $row['password']; } if(isset($_POST['edit'])) { $id = $_GET['edit']; $query = "UPDATE `users` SET `username` = '$name', `password` = '$password' WHERE `id` = '$id'"; $result = mysql_query($query); echo $query; if(!$result) { echo mysql_error(); }else{ echo 'updated post'; } } ?> <form method="POST" action="" > <input type="text" name="name" value="<?php echo $name; ?>" /> First name <br /> <input type="text" name="password" value="<?php echo $password; ?>" /> Last name <br /> <input type="submit" name="edit" value="edit" /> </form> I believe it has something to do with the values of $name and $password in the form conflicting with the first if isset and the second if isset. Thanks for any help possible How can i use single quote for values? $qry='insert into tablename values('a','b');'; I am really just a beginner in PHP but I've got a task to create a simple hotel booking system by using PHP and MySQL. It works in several steps, described in separate .php files. All of them seem to work fine, except the last one. In this last file I want to add all the data into a MySQL database table. I would like to do this by creating a record for each date, a guest is spending in a hotel (so that when booking, another loop checks whether the room is not occupied yet for that date). I decided to use a for-loop for that, but it doesn't seem to be working (the records just don't get inserted into the table). I checked all the variables by echo-ing them and they are all right. I also tried the query without the loop and it works as well. So I guess there is some other problem. This particular .php file looks as follow: <?php session_start(); include('db_config.php'); $name=($_POST['name']); $telephone=addslashes($_POST['telephone']); $email=addslashes($_POST['email']); $code=md5($email.time()); $checkout_date=$_SESSION['checkout']; $checkin_unix=$_SESSION['checkin_unix']; $checkout_unix=$_SESSION['checkout_unix']; $roomtype=$_SESSION['roomtype']; $checkin_date=$_SESSION['checkin']; for ($stay_date=$checkin_unix; ; $stay_date=$stay_date+24*60*60) { if ($stay_date=$checkout_unix){ break; } mysql_query("INSERT INTO reservations VALUES( '', '$roomtype', 'pending', 'date ('d/m/Y', $stay_date)', '$stay_date', '$checkout_date', '$name', '$telephone', '$email', '$code' )"); } ?> I would appreciate any kind of help, any idea. I'm trying to update every record where one field in a row is less than the other. The code gets each row i'm looking for and sets up the query right, I hope I combined the entire query into one string each query seperated by a ; so it's like UPDATE `table` SET field2= '1' WHERE field1= '1';UPDATE `table` SET field2= '1' WHERE field1= '2';UPDATE `table` SET field2= '1' WHERE field1= '3';UPDATE `table` SET field2= '1' WHERE field1= '4';UPDATE `table` SET field2= '1' WHERE field1= '5'; this executes properly if i run the query in phpMyAdmin, however when I run the query in PHP, it does nothing... Any advice? MySQL connection works and it connects to my database but it doesnt insert values into the table that I created. <form action="phplogin2.php" method="post"> Username: <input type="text" name="user" style="color: white; background-color: blue;"/><br/> Password: <input type="password" name="pass" style="color: grey; background-color: black;"/><br/> <button>Login</button> </form> <?php $con = mysql_connect('localhost', 'root', 'eagles1') or die("did not connect"); $dbc = mysql_select_db('mysql') or die("did not connect to database"); $query = mysql_query("INSERT INTO login VALUES('', '$user', '$pass')") or die("query did not work"); $user = $_POST['user']; $pass = $_POST['pass']; if ($con==true){ echo "MySQL Connection Succesful"; } if ($dbc==true){ echo "MySQL Database Connection Succesful"; } if ($query==true){ echo "MySQL Query Succesful"; } ?> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=308528.0 I've got a table with 5 columns that shows appointments for Monday through Friday, but I'm using 5 separate queries, one for each column, for each corresponding day because i cannot figure out how to query the whole week and only put the appointments in the column they belong. Thank you for any help. Here is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 |
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