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PHP - Drop Down Date Don't Connect To Database
hello there.. i have a problem with my php coding where i want to keep date choose by user in the database.
this is the drop down date Code: [Select] <select name="Date_Day"> <option> - Day - </option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <select name="Date_Month"> <option> - Month - </option> <option value="01">January</option> <option value="02">Febuary</option> <option value="03">March</option> <option value="04">April</option> <option value="05">May</option> <option value="06">June</option> <option value="07">July</option> <option value="08">August</option> <option value="09">September</option> <option value="10">October</option> <option value="11">November</option> <option value="12">December</option> </select> <select name="Date_Year"> <option> - Year - </option> <option value="2010">2010</option> <option value="2011">2011</option> <option value="2012">2012</option> <option value="2013">2013</option> <option value="2014">2014</option> <option value="2015">2015</option> <option value="2016">2016</option> <option value="2017">2017</option> <option value="2018">2018</option> <option value="2019">2019</option> <option value="2020">2020</option> <option value="2021">2021</option> <option value="2022">2022</option> <option value="2023">2023</option> <option value="2024">2024</option> <option value="2025">2025</option> <option value="2026">2026</option> </select> the code to connect to the database Code: [Select] $date_year= ($_POST['Date_Year']); $date_month=($_POST['Date_Month']); $date_day=($_POST['Date_Day']); $date=$date_year."-".$date_month."-".$date_day; $query="INSERT INTO aduan (date) VALUES ('date($date)')"; $result=mysql_query($query); if($result){ echo 'Registration success.'; ?><script>window.location ='thanks.php'</script> <?php } else echo 'Registration failed';} when enter a value of date, the database will just show '0000-00-00'.. really hope for your help.. Similar TutorialsHi i have a drop down menu for date which is meant to insert all 3 values into a date column bt is only sending the year how can i fix it <select name="date_of_birth"> <option value="1">January <option value="2">February <option value="3">March <option value="4">April <option value="5">May <option value="6">June <option value="7">July <option value="8">August <option value="9">September <option value="10">October <option value="11">November <option value="12">December </select> <select name="date_of_birth"> <option value="1">1 <option value="2">2 <option value="3">3 <option value="4">4 <option value="5">5 <option value="6">6 <option value="7">7 <option value="8">8 <option value="9">9 <option value="10">10 <option value="11">11 <option value="12">12 <option value="13">13 <option value="14">14 <option value="15">15 <option value="16">16 <option value="17">17 <option value="18">18 <option value="19">19 <option value="20">20 <option value="21">21 <option value="22">22 <option value="23">23 <option value="24">24 <option value="25">25 <option value="26">26 <option value="27">27 <option value="28">28 <option value="29">29 <option value="30">30 <option value="31">31 </select> <select name="date_of_birth" id="year"> <?php $year = date("Y"); for($i=$year;$i>$year-50;$i--) { if($year == $i) echo "<option value='$i' selected>Current Year</option>"; else echo "<option value='$i'>$i</option>"; } ?> for some reason my database will not connect, here's the code: Code: [Select] <?php require("mstr_ref2.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('>','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",'&#39;',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect (localhost, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers WHERE 1"; $result = mysql_query($query); if (!$result) { die('Invalid query: ' . mysql_error()); } header("Content-type: text/xml"); // Start XML file, echo parent node echo '<markers>'; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo '<marker '; echo 'name="' . parseToXML($row['name']) . '" '; echo 'address="' . parseToXML($row['address']) . '" '; echo 'lat="' . $row['lat'] . '" '; echo 'lng="' . $row['lng'] . '" '; echo 'type="' . $row['type'] . '" '; echo '/>'; } // End XML file echo '</markers>'; ?> I think there is something wrong with this line of code. Where it says 'locat host' im not too sure about that because im not connecting to a local host, so what can i put in there instead?i think that is the problem. Code: [Select] $connection=mysql_connect (localhost, $username, $password); This is the error I get: Code: [Select] Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'a2221438'@'localhost' (using password: NO) in /home/a2221438/public_html/map.php on line 44 hey I need this to connect to my database on my sybase sql server, but no matter what i try, it won't populate the plunum field. Any help would be appreciated. Here is my HTML code: Code: [Select] <html> <head> <title>helloscan</title> <meta http-equiv="refresh" content="18"> <meta http-equiv="scanner" content="javascript:doScan('%s');"/> <meta http-equiv="scanner" content="start"/> <META HTTP-Equiv="scanner" Content="enabled" /> <META HTTP-Equiv="scanner" Content="AutoEnter:Enabled"/> <meta http-equiv="keycapture" content="accelerate:all" /> <meta http-equiv="keycapture" content="keyvalue:0x0D; dispatch=true; keyevent:url('javascript:mykeypressed();')" /> <meta http-equiv="quitbutton" content="visibility: visible;"/> <script language="javascript" type="text/javascript"> function doScan(data){ var divEl = ("%s"); } function enablescanner(enable){ Generic.InvokeMetaFunction('scanner', 'start'); Generic.InvokeMetaFunction('scanner', 'enabled'); Generic.InvokeMetaFunction('scanner', 'autoenter:enabled'); } </script> <script> function get_plunum(){ xmlhttp=ajaxfunction(); if (xmlhttp==null) { alert ("no ajax support"); return; } var ae_xrefnum = document.getelementbyid('ae_xrefnum').value; var ae_plunum = document.getelementbyid('ae_plunum').value; var querystring = "?ae_xrefnum=" + xrefnum + "&ae_plunum="+ plunum"; xmlhttp.onreadystatechange = function (){ if (xmlhttp.readystate == 4 || xmlhttp.readystate=="comlete"){ document.myform.ae_plunum.value = xmlHttp.responseText; } } xmlhttp.open("GET", "helloscan2.php"+querystring, true); xmlhttp.send(null); } function ajaxfunction(){ var xmlhttp=null; try {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } catch (err) {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } return xmlhttp; } </script> </head> <body onload="enablescanner(true)"> <h3 align="center"><center><img src="ac moore" /></center>Please scan a barcode...</h3> <form name="myform"> ItemBarcode: <input type="text" id="ae_xrefnum" name="ae_xrefnum" itembarcode="divE1" oninput="get_plunum()" /> plunum: <input type="text" id="ae_plunum" name"ae_plunum" oninput="get_price()"/> </form> <script language=javascript> { document.myform.ae_xrefnum.focus(); } </script> </body> </html> And Here is my PHP code: Code: [Select] <?php //================================================================ // Configure connection parameters $db_host = "97.0.40.244, 1498"; $db_server_name = "ACMSQL036A"; $db_name = "backoff.db"; $db_file = 'd:\trvbkup\DB'; $db_conn_name = "php_script"; $db_user = "dba"; $db_pass = "sql"; //================================================================ $connect_string = "Driver={Adaptive Server Anywhere 8.0};". "CommLinks=tcpip(Host=$db_host);". "ServerName=$db_server_name;". "DatabaseName=$db_name;". "DatabaseFile=$db_file;". "ConnectionName=$db_conn_name;". "uid=$db_user;pwd=$db_pass"; // Connect to DB $conn = odbc_connect($connect_string,'',''); // Query $qry = "SELECT xrefnum, plunum FROM DBA.PLU_Cross_Ref where xrefnum = '$xrefnum'"; // Get Result $result = odbc_exec($conn,$qry); // Get Data From Result while ($row[] = odbc_fetch_array($result)); // Free Result odbc_free_result($result); // Close Connection odbc_close($conn); // Show data print_r($row[plunum]); //================================================================ ?> your MySQL server version: 5.1.36 Code: [Select] SELECT * FROM game_weapons Table: Picture Attached the EXPLAIN output for your query, if applicable: I wish to connect a drop down menu's selection of weapons with the correlated table information. What do I want to happen: Click on a drop down Menu and have a list of weapons, these weapons are associated with a set number in the database and passed onto the next screen. (The larger number wins, this part I have figured out). <p> <select name="weapon2" style="font-size:20px;font-family:Arial;width:275px"> <option value="power">Power</option> <option value="intelligence">Intelligence</option> <option value="speed">Speed</option> <option value="reserve">Reserve</option> </select> </p> I do have the battle code figured out! (This should be the last step). This is my first post so please correct me if somethings wrong Basically im creating a shopping cart with the help of a guide but there is no database written in the guide so i'm not sure how to proceed. My database wont work... Guide: https://jameshamilto...g-cart-tutorial Error message http://gyazo.com/a20...b096b7727410dfd Index:
<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="description" content="PHP Shopping Cart Using Sessions" />
<meta name="keywords" content="shopping cart tutorial, shopping cart, php, sessions" />
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" media="all" href="/style/style.css" type="text/css" />
<title>Cart</title>
<?php
//connect to your database here
$sql = 'SELECT * FROM books ORDER BY id';
$output[] = '<ul>';
$output[] = '<li>"'.$row['title'].'" by '.$row['author'].': £'.$row['price'].'<br /><a href="cart.php?action=add&id='.$row['id'].'">Add to cart</a></li>';
//connect mysql
mysql_connect($server, $user, $pass) or die ("Sorry, can't conect to mysql.");
//select db
mysql_select_db($db) or die ("Sorry cant select the db.");
?>
</head>
<body>
<?php
$product_id = $_GET[id]; //the product id from the URL
$action = $_GET[action]; //the action from the URL
//if there is an product_id and that product_id doesn't exist display an error message
if($product_id && !productExists($product_id)) {
die("Error. Product Doesn't Exist");
}
switch($action) { //decide what to do
case "add":
$_SESSION['cart'][$product_id]++; //add one to the quantity of the product with id $product_id
break;
case "remove":
$_SESSION['cart'][$product_id]--; //remove one from the quantity of the product with id $product_id
if($_SESSION['cart'][$product_id] == 0) unset($_SESSION['cart'][$product_id]); //if the quantity is zero, remove it completely (using the 'unset' function) - otherwise is will show zero, then -1, -2 etc when the user keeps removing items.
break;
case "empty":
unset($_SESSION['cart']); //unset the whole cart, i.e. empty the cart.
break;
}
?>
<?php
if($_SESSION['cart']) { //if the cart isn't empty
//show the cart
echo "<table border=\"1\" padding=\"3\" width=\"40%\">"; //format the cart using a HTML table
//iterate through the cart, the $product_id is the key and $quantity is the value
foreach($_SESSION['cart'] as $product_id => $quantity) {
//get the name, description and price from the database - this will depend on your database implementation.
//use sprintf to make sure that $product_id is inserted into the query as a number - to prevent SQL injection
$sql = sprintf("SELECT name, description, price FROM php_shop_products WHERE id = %d;",
$product_id);
$result = mysql_query($sql);
//Only display the row if there is a product (though there should always be as we have already checked)
if(mysql_num_rows($result) > 0) {
list($name, $description, $price) = mysql_fetch_row($result);
$line_cost = $price * $quantity; //work out the line cost
$total = $total + $line_cost; //add to the total cost
echo "<tr>";
//show this information in table cells
echo "<td align=\"center\">$name</td>";
//along with a 'remove' link next to the quantity - which links to this page, but with an action of remove, and the id of the current product
echo "<td align=\"center\">$quantity <a href=\"$_SERVER[PHP_SELF]?action=remove&id=$product_id\">X</a></td>";
echo "<td align=\"center\">$line_cost</td>";
echo "</tr>";
}
}
//show the total
echo "<tr>";
echo "<td colspan=\"2\" align=\"right\">Total</td>";
echo "<td align=\"right\">$total</td>";
echo "</tr>";
//show the empty cart link - which links to this page, but with an action of empty. A simple bit of javascript in the onlick event of the link asks the user for confirmation
echo "<tr>";
echo "<td colspan=\"3\" align=\"right\"><a href=\"$_SERVER[PHP_SELF]?action=empty\" onclick=\"return confirm('Are you sure?');\">Empty Cart</a></td>";
echo "</tr>";
echo "</table>";
}else{
//otherwise tell the user they have no items in their cart
echo "You have no items in your shopping cart.";
}
//function to check if a product exists
function productExists($product_id) {
//use sprintf to make sure that $product_id is inserted into the query as a number - to prevent SQL injection
$sql = sprintf("SELECT * FROM php_shop_products WHERE id = %d;",
$product_id);
return mysql_num_rows(mysql_query($sql)) > 0;
}
?>
<a href="products.php">Continue Shopping</a>
<?php
/*
products table:
CREATE TABLE `products` (
`id` INT NOT NULL AUTO_INCREMENT ,
`name` VARCHAR( 255 ) NOT NULL ,
`description` TEXT,
`price` DOUBLE DEFAULT '0.00' NOT NULL ,
PRIMARY KEY ( `id` )
);
*/
?>
</body>
</html>
products.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="description" content="PHP Shopping Cart Using Sessions" />
<meta name="keywords" content="shopping cart tutorial, shopping cart, php, sessions" />
<link rel="stylesheet" media="all" href="/style/style.css" type="text/css" />
<title>Products</title>
<?php
//connect to your database here
//connect to your database here
$sql = 'SELECT * FROM books ORDER BY id';
$output[] = '<ul>';
$output[] = '<li>"'.$row['title'].'" by '.$row['author'].': £'.$row['price'].'<br /><a href="cart.php?action=add&id='.$row['id'].'">Add to cart</a></li>';
//connect mysql
mysql_connect($server, $user, $pass) or die ("Sorry, can't conect to mysql.");
//select db
mysql_select_db($db) or die ("Sorry cant select the db.");
?>
</head>
<body>
<table border="1">
<?php
$sql = "SELECT id, name, description, price FROM php_shop_products;";
$result = mysql_query($sql);
while(list($id, $name, $description, $price) = mysql_fetch_row($result)) {
echo "<tr>";
echo "<td>$name</td>";
echo "<td>$description</td>";
echo "<td>$price</td>";
echo "<td><a href=\"cart.php?action=add&id=$id\">Add To Cart</a></td>";
echo "</tr>";
}
?>
</table>
<a href="cart.php">View Cart</a>
</body>
</html>
hi i m new to php and i m working on a project in which i m configuring a mail server using Mdeamon 9.5....... In Mdeamon 9.5 users are create by hand but i want to create user online as they sign up and their account will create as abc@mycompany.com and thier inbox created. So i want when user is sign up online and new entries will added to SQL database which trigger the Mdeamon to create a new user is it possible????? If YES then how can i do it..................... Thnx in advance for help.................. Hi, I cant connect to my Mysql database. I get this problem: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'esolarch_databas'@'localhost' (using password: YES) in /home7/esolarch/public_html/new/storescripts/connect_to_mysql.php on line 21 could not connect to mysql Code: [Select] <?php /* 1: "die()" will exit the script and show an error statement if something goes wrong with the "connect" or "select" functions. 2: A "mysql_connect()" error usually means your username/password are wrong 3: A "mysql_select_db()" error usually means the database does not exist. */ // Place db host name. Sometimes "localhost" but // sometimes looks like this: >> ???mysql??.someserver.net $db_host = "localhost"; // Place the username for the MySQL database here $db_username = "esolarch_database"; // Place the password for the MySQL database here $db_pass = "Password"; // Place the name for the MySQL database here $db_name = "esolarch_admin2"; // Run the actual connection here mysql_connect("$db_host","$db_username","$db_pass") or die ("could not connect to mysql"); mysql_select_db("$db_name") or die ("no database"); ?> Hello, I've been having trouble connecting to a MySQL database, I can't find the problem in the code, what am I doing wrong? Getting the database file in the config file : require_once("db_connect.php"); db_connect.php : <?php $db = mysql_connect('83.172.155.14:3306', 'username', 'password') or die(mysql_error()); mysql_select_db('databasename', $db) or die(mysql_error()); ?> I need to connect to a PhpMyAdmin database. I need this fixed asap since I'm doing this for someone and he wants the site done as quickly as possible. P.S: The database used to work in php4 and now I need it to work on php5 Thanks in advance, Hi, When i am trying to run one script on my web server, i get following error Cannot connect to the database using the info you provided Access denied for user 'My_Username'@'localhost' (using password: NO) I filled all info like Host(localhost) Database name(created in cpanel) Username(created in cpanel) Password(i kept blank dont know where to find this) You help will highly appreciate Thanks, Ravindra Hey... I was going through this sample that was given in the class, but got confused at the first point "//change this to include your own database connect script. include "../../dbconnect.php";" and the database connection code is "<?php if ($_POST['submit']) { // connect to your database $connection = pg_connect("port=5432 dbname=rr_ds user=nobody"); if (!$connection) { die("Connection has failed: " . pg_last_error()); }?> " the database connection code is from a previous assignment which i did, but that was for a login page. The current assignment is to connect to the database and have data on it. Here is my code in admin_common.php. This is a website I had over at yahoo that I moved to Godaddy. define("EZSQL_DB_USER", "larryadmin"); // <-- mysql db user define("EZSQL_DB_PASSWORD", "mypassword"); // <-- mysql db password define("EZSQL_DB_NAME", "larryadmin"); // <-- mysql db pname define("EZSQL_DB_HOST", "mysql"); // <-- mysql server host I keep getting this error SQL/DB Error -- [ Error establishing a database connection! Are you sure you have the correct user/password? Are you sure that you have typed the correct hostname? Are you sure that the database server is running? ] SQL/DB Error -- [ Error selecting database larryadmin! Are you sure it exists? Are you sure there is a valid database connection? ] Please help thanks. Hey all, I'm sure this is a really basic question but I'd like a definite answer. I've been watching a tutorial and seeing some site references regarding connecting to a sql database using php. Since it contains a password to the database, my question is, how secure is this page on a webserver, or does it not even matter since the code is so specific to the website and the database it is connecting to.
Thank you in advance. Hi there, I have this connect script I have made. I was wondering if it's secure or not, if not... What would be a good way to do so... Code: [Select] <?php class connect{ public $host = "localhost"; public $dbuser = ""; public $dbpass = ""; public $db = ""; } $connect = new connect(); mysql_connect($connect->host,$connect->dbuser,$connect->dbpass) or die("Could not connect!"); mysql_select_db($connect->db); ?> I know the regular database connection, but this time i am provided with the SSH details. This guy game me the IP address of the database server to connect and 2 login details. SSH: Username and Password DB: Username and Password And i am using XAMPP for trying out the code. Is there any plugin i need to download for SSH connections? Could you please give me the connection snippet for SSH because i don't really know how to do that, i am also searching elsewhere on internet. Thanks in advance for help... Hello I am creating a simple Discussion Forum, and I cant get past my IF Statement to verify topics exist? Please help? <?php //check for required info from the query string if (!$_GET[topic_id]) { header("Location: topiclist.php"); exit; } //connect to server and select database $link = mysql_connect('votpservicescom.ipagemysql.com', 'mantest', 'testman') or die(mysql_error()); mysql_select_db("learn2db",$link) or die(mysql_error()); This topic has been moved to Microsoft SQL - MSSQL. http://www.phpfreaks.com/forums/index.php?topic=319147.0 Okay guys I have finished my db and I want to upload it to a live server but don't know exactly what to change in the code to get the ODBC_connect to open the path at the new server location please help. my database is located in a subfolder called Databases i.e. "www.mydomain.com/Databases/myEvents.mdb" what do i change in the connection string below to get it to open the file on the live server? Thanks in advance. $conn = odbc_connect('myEvents','',''); Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week. Any one know how to write this code? Here is what I have got, but not working. <?php $todays_date = date("Y-m-d"); $result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7"); while($row = mysql_fetch_array($result)) { echo "$todays_date - $row[title]"; } ?> hello fellas, need some help please if possible. i have created a date of birth section in my form where the user selects his/her date of birth from the dropdown menu. they would first select the day then month then year of their birthday. how would i setup the database to get this to work? i currently have: Code: [Select] day VARCHAR( 2 ) NOT NULL , month VARCHAR( 4 ) NOT NULL , year VARCHAR( 4 ) NOT NULL , is this correct? many thanks I am trying to insert a date into a mySQL table from html drop downs with php. Right now when I enter the date it goes into the database as 0000-00-00. Can anybody see why it might be doing this? My html: Code: [Select] <label for='birthdate' >Birthdate (Optional):</label><br/> <select name='month' id='month' value='<?php echo $fgmembersite->SafeDisplay('month') ?>'> <option value="01" selected="January">January</option> <option value="02">February</option> <option value="03">March</option> etc... </select> <select name='day' id='day' value='<?php echo $fgmembersite->SafeDisplay('day') ?>'> <option value="01" selected="1">1</option> <option value="02">2</option> <option value="03">3</option> etc... </select> <select name='year' id='year' value='<?php echo $fgmembersite->SafeDisplay('year') ?>'> <option value="2010" selected="2010">2010</option> <option value="2009">2009</option> <option value="2008">2008</option> etc... </select> And my php to collect info: Code: [Select] $formvars['birthdate'] = $this->Sanitize($_POST['year'], $_POST['month'], $_POST['day']); php where I make table: Code: [Select] "birthdate DATE NOT NULL ,". php to insert into mysql: Code: [Select] $insert_query = 'insert into '.$this->tablename.'( name, address, birthdate, sex, program, guide, email, username, password, confirmcode ) values ( "' . $this->SanitizeForSQL($formvars['name']) . '", "' . $this->SanitizeForSQL($formvars['address']) . '", "' . $this->SanitizeForSQL($formvars['birthdate']) . '", "' . $this->SanitizeForSQL($formvars['sex']) . '", "' . $this->SanitizeForSQL($formvars['program']) . '", "' . $this->SanitizeForSQL($formvars['guide']) . '", "' . $this->SanitizeForSQL($formvars['email']) . '", "' . $this->SanitizeForSQL($formvars['username']) . '", "' . md5($formvars['password']) . '", "' . $confirmcode . '" )'; Thank you! |
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