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PHP - Moved: How To Assign Textbox Value To Radio Button Value
This topic has been moved to JavaScript Help.
http://www.phpfreaks.com/forums/index.php?topic=350859.0 Similar TutorialsHey Everybody, I am new to PHP coding and have searched tons of forums and still looking... Please help me with the following: I have a MySQL database. There are several fields in the table, among them are Amount_paid and Amount_returned fields. And there are two radio buttons Amount paid and Amount returned and one textBox where I will be entering an amount. What I need is to assign an entered amount to one of those radio buttons (depending which one is selected) and insert the textBox value into the correct field (amount_paid or amount_returned) of the table. I have all other fields coded ok and they work, but have no idea how to make the above stuff work. The code is attached, please let me know if you need more info. Thanks a lot! EDIT: Sorry, now the file is attached This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=321339.0 This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=317717.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=346803.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=350049.0 What am I doing wrong with this selected radio button? <form action="Process/privacy.php" method="post" enctype="multipart/form-data" id="privacy"> <div id="privacy_vis">Your profile is visible to:</div> <div id="privacy_select"> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_0" value="1" <?if($visible=="1")echo 'checked="checked"';?> /> Everyone</label> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_1" value="0"/> Members Only</label> </div> <br /> <div id="privacy_vis">Your Password to view your private pictures is:</div> <div> <input name="pictures_pw" type="text" id="pictures_pw" value="<? echo "$xxx_pw" ?>" size="50" maxlength="20" /> </div> <br /> <div> <input name="submit" type="submit" class="button" id="submit" value="Save Changes" /> </div> </form> </div> I have a function to display some images and allow a user to select a choice via a radio button.The value is then passed to another function. I have 2 problems My selection is not being passed back and I cant assign the value to a query sring in a link to another page. On the form do i need to add checked? Any help appreciated. Code: [Select] function cover() { echo'<h2>Please upload your book cover or choose one from the selection</h2> <p>All book ideas require a cover. Your choice can be changed at a later date.</p>'; //process selection of cover if (isset($_POST['submit'])) { $coverID=$_POST['cover']; echo $coverID; ?>   <ul><li class="demo-menu-link"><a href="?page=submenu7&coverID=$coverID">Finnished Cover</a></li></ul><?php exit(); } else{ echo "not Submitted"; } global $wpdb; $query = "select * from wp_cover"; $result = mysql_query($query) or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error()); echo mysql_error(); if (!$result){ return false; } echo'<div class="wrap"><p>choose from one of the covers below</p></div>'; ?><form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST" id="cover" enctype="multipart/form-data"> <table><tr><?php /* display picture and radio button */ while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $coverID=$row['coverID']; echo"<img src=\"/wordpress_3/wp-content/plugins/Authors2/jackets/{$row['pix']}\" />"; echo"<td>"; echo $coverID; echo "<Input type = 'Radio' Name ='cover' value= '$coverID'/>"; ?> </tr></table> <input type=submit value=submit> </form><?php } } I am trying to have the text alongside the radio button trigger the radio button (cannot use < a href ) e.g. () Trigger with this text The closest I have found is <label for="r1"><input type="radio" name="group1" id="r1" value="1" /> button one</label> But it does not seem to work? Any help greatly appreciated Hello, I had 3 radio buttons with the same name, well, I had created 3 text box that are next to those 3 radio buttons. When I click save to the form, I need to know which radio button had been pressed, so that I can detect & retrieve its value. Any help? Thanks This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=343375.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=329374.0 I am trying to make a set of radio buttons that when you make a selection, it displays a sorted database from MYSQL. I have the MYSQL part figured out but I cannot figure out how to properly display it. I have the following code and I made a select screen just to test: index.html <html> <body> <form action="select.php" method="post"> <input type="radio" name="table" value="table1"> Table 1 <br> <br> <input type="radio" name="table" value="table2">Table 2 <br> <br> <input type="radio" name="table" value="table3">Table 3 <br> <br> <input type="radio" name="table" value="table4">Table 4 <br> <br> <input type="radio" name="table" value="table5">Table 5 <br> <br> <input type="Submit" Name = "submit" value="Submit"> <input type="Reset" value="Reset"> </form> </body></html> select.php <?PHP $selected_radio = $_POST["table"]; if ($selected_radio = = 'table1) { echo "Table 1 Here."; } else if ($selected_radio = = 'table2') { echo "Table 2 Here."; } else if ($selected_radio = = 'table3') { echo "Table 3 Here."; } else if ($selected_radio = = 'table4') { echo "Table 4 Here."; } else if ($selected_radio = = 'table5') { echo "Table 5 Here."; } ?> These are two separate files. When I go to run the code, no matter what I pick, the next page is always blank. Again, the select.php is just suppose to be a check, the real code will display the table instead of echoing a message. i would like to display the value of the selected radio button on the same page... what i want is just reload the page and if there is a radio button selected displays it but i cant display it <?PHP if (isset($_GET["submit"])) { echo $_GET["myradio"]; } ?> <html> <head> </head> <body> <form action="<?PHP $_SERVER["PHP_SELF"]; ?>" method="get"> One <input type="radio" name="myradio" value="one"> Two <input type="radio" name="myradio" value="two"> <a href="<?PHP $_SERVER["PHP_SELF"]; ?>" name="submit">test </a> </form> </body> </html> please help guys...thanks Hi, I have 2 radio button's within a table and need to pass this array. All other rows within my table can be sent as array's and captured using $_POST['field_name'][$ROW 1 value etc]. However for radio buttons this doesn't work. As an example, a standard textbox I can send an array using the following: echo "<td width='33%'><input type='Textbox' width='100%' id='test' name='test[]' value='" .$row['test']. "'></td>"; I can then capture it using: $test = $_POST['test'][$iLine]; This works, no problem, however for radio buttons, I can't use a static array name, as presumably it dumps all rows into the array, if I do this, only the last row has a checked button, hence I need to use the following (where $checked includes the logic to decide whether the button should be checked or not, this works correctly): echo "<input type='radio' name='".$row['venue_id']."[]' value='1'".$checked."/>P1" echo "<input type='radio' name='".$row['venue_id']."[]' value='0'".$checked2." />P2"; I tried using the following: var_dump($_POST[$row]['game_id'][$iLine]); But this just returns a null value. Any ideas? how do you make it so that a radio button is either checked or unchecked based on database? Good Day, I juz like to know if there any other alternative way for the code below, coz i can't update my form when i use this method for radio the button. It's not passing the value. Code: [Select] Edit.php <tr> <td height="36" align="center" valign="middle" bgcolor="#990000"><div align="left" class="style4">Destroy :</div></td> <td align="center" valign="middle" bgcolor="#990000"><div align="left"> <label> <input type=radio name=destroyR value="Yes" <?php echo ($rows['destroy']=='Yes') ?'checked="checked"':''; ?> />Yes</label> <label> <input type=radio name=destroyR value="No" <?php echo ($rows['destroy']=='No') ?'checked="checked"':''; ?> />No</span></label> </div></td> </tr> I have a group of 4 radio buttons. my mysql database knows which one the user selected previously when they stored some information. I now wish to display the same buttons but have radio button checked that the user chose before. I know this can be done but having one of those mind melt moments where I cannot think of the solution so I have 4 buttons that look like this Code: [Select] <input type="radio" name="clarity" id="clarity" value="Opaque"> Opaque<br> <input type="radio" name="clarity" id="clarity" value="Deep"> Deep<br> <input type="radio" name="clarity" id="clarity" value="Mid"> Mid<br> <input type="radio" name="clarity" id="clarity" value="Pale"> Pale<br></td> I just need to attached a checked field to the correct item This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=330523.0 I have page with male female radio button Here's the code Code: [Select] $qry=mysql_query("SELECT * FROM reg_table where id=$id "); $res=mysql_fetch_array($qry); $radio = $res['gender']; switch($radio) { case "male": $mal = "checked"; break; case "female": $fem = "checked"; break; } Code: [Select] Gender: <br /> <input type="radio" name="colour" value="male" checked="<?php $mal; ?>" />Male <input type="radio" name="colour" value="female" checked="<?php $fem; ?>" />Female Whats the use of checked in <input type="radio" name="colour" value="male" checked="<?php $mal; ?>" /> |
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