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PHP - Variables Not Working In .php Echo
Hello all,
I'm passing variables through a URL. This will work: echo $v4; But neither of these will: echo "<a href='test.php?v4=$v4'>Places</a>"; echo "<a href='test.php?v4=".$v4."> Places</a>"; It WILL work if I hardcode v4, like so: echo "<a href='test.php?v4=Utah'>Places</a>"; But that's useless to me, as I don't want to have to write 50 If statements for every database entry. Does anyone know how to fix this? Thanks! Similar TutorialsWhat I would like to find out is how I can echo out all the variables that are in use in the visitors visit. And have these echoed on the page. (for error checking purposes) some of my variables i.e. $username or $email and a few others are being cleared of its content and I can not find any problems searching all the files for the variable name and checking the lines but think that some other variable is in turn causing theproblems. so wanting to find a way to place an echo line that shows all the variables and then have the next line exit; and just move these two new lines around my scripts to find out where the problems might be. Hi, I want to send the following variable using the $_GET function: Hello, I just wanna know if any such commands are available in php for making a variable as such like - $variable = " blah blah .. . . . index.php?X=<?php echo $_GET['x']; ?>..........blah"; thank you I need to echo out some string variables in a form. I also want to add some validation for Name, email etc. I think I have the code right or close, but I can an error on the index.php page which is. "Fatal error: Call to undefined function form_row_class() in index.php on line 14" here is the code for the form <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>String Tester</title> <link rel="stylesheet" type="text/css" href="main.css"/> </head> <body> <div id="content"> <h1>String Tester</h1> <form action="submit.php" method="post"> <table> <tr class="<?php echo form_row_class("name") ?>" > <th><label for="first_name">Name</label></th> <td> <input name="first_name" id="first_name" type="text" value="<?php echo h($_POST['name']); ?>" /> <?php echo error_for('name') ?> </td> </tr> <tr class="<?php echo form_row_class("email") ?>"> <th><label for="email">Email Address</label></th> <td> <input name="email" id="email" type="text" value="<?php echo h($_POST['email']); ?>" /> <?php echo error_for('email') ?> </td> </tr> <tr> <th></th> <td><input type="submit" value="submit" /></td> </tr> </table> </form> <h2>Message:</h2> <?php echo "<table>"; echo "<tr><td>"; echo $name; echo "</td></tr>"; echo "<tr><td>"; echo $email; echo "</td></tr>"; echo "<tr><td>"; echo $phone; echo "</td></tr>"; echo "</table>"; ?> </div> </body> </html> and the submit portion <?php // If request is a form submission if($_SERVER['REQUEST_METHOD'] == 'POST'){ // Validation // Check first_name is non-blank if(0 === preg_match("/\S+/", $_POST['name'])){ $errors['name'] = "Please enter a name."; } // Check email is valid (enough) if(0 === preg_match("/.+@.+\..+/", $_POST['email'])){ $errors['email'] = "Please enter a valid email address."; } // validate a phone number if( !preg_match("/^([1]-)?[0-9]{3}-[0-9]{3}-[0-9]{4}$/i", $phone) ) { echo 'Please enter a valid phone number'; } // If no validation errors if(0 === count($errors)){ // Sanitize first, last, and email $name = mysql_real_escape_string($_POST['name']); $email= mysql_real_escape_string($_POST['email']); $email= mysql_real_escape_string($_POST['phone']); } // Helpers function form_row_class($name){ global $errors; return $errors[$name] ? "form_error_row" : ""; } function error_for($name){ global $errors; if($errors[$name]){ return "<div class='form_error'>" . $errors[$name] . "</div>"; } function h($string){ return htmlspecialchars($string); } ?> probably something simple I am missing. hi there all. hope i can get your help. i am creating a php page that talks to mysql tabes. i want to print query into my html page inside html tags. the first echo in my code works but the one embedded inside the html code prints nothing to the page. look at my code if it helps: <html><body> <?php mysql_connect("localhost", "root", "123456") or die("Connection Failed"); mysql_select_db("man_utd")or die("Connection Failed"); $name = $_POST['members']; $query = "select * from members where username = 'burns'"; $result = mysql_query($query); while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) { echo $line['pass']; } ?> <table border="0" cellspacing="2" cellpadding="2"> <tr> <th><font face="Arial, Helvetica, sans-serif"><?php echo $line['pass']; ?></font></th> <th><font face="Arial, Helvetica, sans-serif">Value2</font></th> <th><font face="Arial, Helvetica, sans-serif">Value3</font></th> <th><font face="Arial, Helvetica, sans-serif">Value4</font></th> <th><font face="Arial, Helvetica, sans-serif">Value5</font></th> </tr> </body> </html> thanks all for any help echo will not print out a value. I do the simple string " " and it doesn't even do that. It's just blank in my browser. I use netbeans and firefox and chrome. Any idea as to what I'm doing wrong? Simple code snippet: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title>PHP Testing</title> </head> <body> <?php echo "print me"; ?> </body> </html> Thanks for any future help. Please help, when I run this search and enter something in the search thats not in the database, it doesnt reply with "Your query returned 0 results" as it should. I tjust stays blank Here's the section of code in question... if ($search) // perform search only if a string was entered. { mysql_connect($host, $user, $pass) or die ("Problem connecting to Database"); $srch="%".$search."%"; $query = "select * from tvads WHERE advert LIKE '$srch' ORDER BY advert, year DESC, details ASC LIMIT 0,30"; $result = mysql_db_query("cookuk_pn", $query); if ($result) { $count = 1; print "<table border=\"0\" cellpadding=\"0\" cellspacing=\"0\" bordercolor=\"#0000FF\" width=\"900\">"; print "<tr><td width=\"200\" height=\"30\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Advert / Description</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Year</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Artist</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Track</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Buy Album</font></b></u></td>"; print "<td width=\"100\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Download MP3</font></b></u></td></tr>"; while ($row = mysql_fetch_array($result)) { // Begin while $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['advert']. "</font><br>"; $data .= "<font face=\"arial\" size=\"1\" color=\"#000080\"><i>" .$row['details']. "</i></font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['year']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['artist']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['track']. "</font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['asin_ref']. "</font></td>"; $data .= "<td width=\"100\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['mp3_ref']. "</font></td></tr>"; $count++; } // end while $data .="</table>"; echo $data; } else { echo "problems...."; } } else { echo "Your query returned 0 Results"; } ?> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=320829.0 My variable which should be storing XML data and echos it to the screen is echoing the data as a string without the XML structure Below is my code but it is still not working: Code: [Select] $view = $_GET['view']; $xml_data = "http://www.website.com/STRATA/" . $view .".xml"; $handle = fopen($xml_data, 'r'); $Data = fread($handle, 10000); fclose($handle); echo $Data; Hi, Im trying to pull an email from an url, and then echo the email as value into a email form-- under the "from" heading. The echo is not working i get blanks. here is the code: <?php $thisurl='$_SERVER['REQUEST_URI']'; $thepart = explode('/', $thisurl); $themail='$thepart[2]'; ?> <form method="post" action="sendit.php"> To: <br><input type="text" name="to" size="44" value="<?php for($i=1; $i<=$lines; $i=$i+1) { $names[$i] = str_replace("<br>", "", $names[$i]); $names[$i] = str_replace("\n", "", $names[$i]); echo $names[$i].';'; } ?>"><br> From: <br><input type="text" name="email" size="44" value="<?php echo '$themail'; ?>" readonly><br> Subject: <br><input type="text" name="subject" size="44" /><br><br> Hi, This is my first post in this forum and am a PHP beginner. I have written a script in php and need to use echo to see the values of variables etc. However I dont get the output on the screen while using echo . I am using Xampp server with Apache. The startup.html file code is
<!DOCTYPE HTML>
</head>
and the test.php code is <?php
$lat = $_REQUEST['latitude'];
echo 'latitude- '.$lat . ', longitude- ' . $lon; Please help regards
Sanjish Hello All, In below script, I'm using another script called "SimpleImage.php" to upload and resize photos for a news site. The problem comes with renaming the photos. I need to name the photo based off of the story id. I have everything right to get the story id, but saving it as the variable is what's confusing me. Here's what I have: <?php include ("newsconnection.php");?> <?php $picturename = $_POST['newstoryid']; include('SimpleImage.php'); $image = new SimpleImage(); $image->load($_FILES['uploaded_image']['tmp_name']); $image->resizeToWidth(300); $image->save('$picturename'); ?> It's the $image->save('$picturename'); line that's messing me up. Any help would be great!! hi,
I'm new to php. I tried to get sum of two variables using java script. Value of one variable come from a php variable, Other one is a static value. here is the code
$price_per_day=100; it displays correctly. but when i try to add it with another variable it displays nothing. Please help me.
<!DOCTYPE html> I've got a mailing list (uses DadaMail) which provides a perl script (subscribe_email.pl) so that I can pass subscribers to it thorugh a PHP script. Info he http://dadamailproject.com/support/documentation-5_0_1/COOKBOOK-subscriptions.pod.html#command_line_utility___subscribe_email_pl The trouble is I can get it working when variables are passed to it via URL query strings, but when I try to hard-code variables into it it stops working. I can't see any reason for this, it's got me really confused. This works: - Code: [Select] <?php // example usage: - // http://www.domain.com/ds1.php?sendto=user@domain.com&title=Mr&forename=John&surname=Doe&company=None&country=UK if (isset($_GET['sendto'])) { $email = $_GET['sendto']; } if (isset($_GET['title'])) { $title = preg_replace("/[^A-Za-z ]/", "", $_GET['title']); } if (isset($_GET['forename'])) { $forename = preg_replace("/[^A-Za-z\-. ]/", "", $_GET['forename']); } if (isset($_GET['surname'])) { $surname = preg_replace("/[^A-Za-z\-. ]/", "", $_GET['surname']); } if (isset($_GET['company'])) { $company = preg_replace("/[^A-Za-z()\-.& ]/", "", $_GET['company']); $company = str_replace('&', 'and', $company); } if (isset($_GET['country'])) { $country = preg_replace("/[^A-Za-z\-.& ]/", "", $_GET['country']); $country = str_replace('&', 'and', $country); } if (isset($email)) { $exec_command = 'perl ./subscribe_email.pl --list mylist --email '. $email; if (isset($title)) $exec_command .= ' --fields title '. $title; if (isset($forename)) $exec_command .= ' --fields forename '. $forename; if (isset($surname)) $exec_command .= ' --fields surname '. $surname; if (isset($company)) $exec_command .= ' --fields company '. $company; if (isset($country)) $exec_command .= ' --fields country '. $country; exec(escapeshellcmd($exec_command)); } else { echo 'Nothing to do'; } ?> The mail address and all the parameters are passed to the subscribe_email.pl script. But, this doesn't work: - Code: [Select] <?php $subscriber_email = 'user@domain.com'; $subscriber_title = 'Mr'; $subscriber_forename = 'John'; $subscriber_surname = 'Doe'; $subscriber_company = 'None'; $subscriber_country = 'UK'; if (isset($subscriber_email)) { $email = escapeshellcmd($subscriber_email); } if (isset($subscriber_title)) { $title = preg_replace("/[^A-Za-z ]/", "", $subscriber_title); } if (isset($subscriber_forename)) { $forename = preg_replace("/[^A-Za-z\-. ]/", "", $subscriber_forename); } if (isset($subscriber_surname)) { $surname = preg_replace("/[^A-Za-z\-. ]/", "", $subscriber_surname); } if (isset($subscriber_company)) { $company = preg_replace("/[^A-Za-z()\-. ]/", "", $subscriber_company); $company = str_replace('&', 'and', $company); } if (isset($subscriber_country)) { $country = preg_replace("/[^A-Za-z\-. ]/", "", $subscriber_country); $country = str_replace('&', 'and', $country); } if (isset($email)) { $exec_command = 'perl ./subscribe_email.pl --list mylist --email '. $email; if (isset($title)) $exec_command .= ' --fields title '. $title; if (isset($forename)) $exec_command .= ' --fields forename '. $forename; if (isset($surname)) $exec_command .= ' --fields surname '. $surname; if (isset($company)) $exec_command .= ' --fields company '. $company; if (isset($country)) $exec_command .= ' --fields country '. $country; exec(escapeshellcmd($exec_command)); } else { echo 'Nothing to do'; } ?> In the second example, only the list and email parameters are passed, all the others are lost (or ignored). All that's different between the two is the way the variables are inititally set, I can't for the life of me figure out why the second one isn't working . Even stranger, I tried testing with just: - Code: [Select] <?php exec("perl ./subscribe_email.pl --list mylist --email user@domain.com --fields title Mr --fields forename John--fields surname Doe --fields company None --fields country UK") ?> and this doesn't work fully either (again just the list and email parameters are passed). Unfortunately, it's the second method I need to use as it's tagged on to the end of a contact form processing script which initiates the subscription if a checkbox is left ticked...and all variables will be coming from this form script. Any help greatly appreciated! I have no idea and there is no reason why this should not be working. im simply trying to add three variables into a database, and only one works. the other two do not work for any reason i can find. can someone point out my error, if any? code: <?php $date = date("Y-m-d"); $dbc = mysqli_connect('localhost', 'root', '', 'timer') or die('Error connecting to DB'); $query = @"INSERT INTO sessions (date, user, sessiontime) VALUES ('$date', '$user', '$sessiontime')"; $user = @$_GET['user']; $sessiontime = @$_GET['clock']; if (@$_GET['addDB'] == "Session Complete") { mysqli_query($dbc, $query) or die( '<br>Query string: ' . $query . '<br>Produced error: ' . mysqli_error($dbc) ); } ?> Form: Code: [Select] <label for="user"><b><em>Your name: </b></em></label><br /><input type="text" name="user" value="Admin/User" /> <input id="clock" name="clock" type="text" value="00:00:0" readonly><br> <input id="startstopbutton" type="button" value="S t a r t" onClick="startstop();" style="font-weight:bold"><br> <input type="submit" name="addDB" value="Session Complete" /> See, all the variables match up!? I dont get what im doing wrong? Hi everyone, I am trying to implement an OAuth system in PHP. I've got the code working but the very first time a fresh, new browser window is opened, the code doesn't work. If I refresh the page and try again, then it works. I have a few suspicions as to where the problem might be but other than that I am stumped. I have two classes: OAuthServer and OAuthClient. I create and store an object of the appropriate class in session variables. I know this is tricky but I am serializing and unserializing properly. To fetch responses from the Server, I am using curl. As curl uses a different session from the browser, I am doing a session_write_close before initializing curl and passing the appropriate parameters to curl. But my code needed to further write session variables even after session_write_close was called and to achieve this, I am calling session_start(), once again, after the curl code is finished. I found that this works but PHP was throwing warnings saying that the header info had already been sent or something like that, but I have suppressed such warnings. I suspect the error has something to do with this but I'm not sure. The part that doesn't work the very first time is that on the server-side, the session variable that is supposed to contain the OAuthServer object is NULL. But if I do a refresh of the page(flow: login_page->error_page), it works. Can anyone tell me why I am encountering the above error and if I am doing things correctly or not. Any help would be greatly appreciated. Thanks & Regards, GarbageGigo I am trying to run a mysql query to get the sum of a column. When I type out the column name it works. When the column name is stored in a variable it does not seem to work. Code: [Select] <?php $total = $_GET['total']; if ($order != "" && $total != ""){ $query2 = "SELECT SUM('.$type2.') FROM customers WHERE sched=1"; $result2 = mysql_query($query2) or die(mysql_error()); while($row = mysql_fetch_array($result2)){ echo "Total ". " = $". $row["SUM('.$type2.')"]; echo "<br />"; } } ?> Any Help would be appreciated. OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu |
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